how many cattle are there on the lazy circle double o bar four square ranch

Answer:

Yes the two figures are congruent. They are the same size and shape they just translated it down the coordinate plane.

Step-by-step explanation:

Answer:

I believe the answer is 42 books.

Step-by-step explanation:

Answe i

Can't see the picture

Step-by-step explanation:

Answer:

sin45°=x/16

or, 1/√2 = x/16

or, x=16/√2

or, x=8√2 or 11.31 #

Answer: (0,3)

Step-by-step explanation:

(x,y) -> (1/2x , 1/2y)

(0,6) -> (1/2 • 0, 1/2 • 6)

=(0,3)

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i hope this helps, brainliest please <3

The number of ways Dr. Orchid can arrange all 9 paintings and 4 paintings is, 362880 and 126 respectively.

Arrangement of the things or object is mean to make the group of them in a systematic order, in all the possible ways.

The number of possible ways to arrange is n!. Here, n is the number of objects.

Dr. Orchid has 9 paintings she wants to hang side by side on her wall.

There are total 9 paintings. So the number of arrangement of these painting is,

[tex]9!=9\times8\times7\times6\times5\times4\times3\times2\times1\\9!=362880[/tex]

There are total 9 paintings, in which Dr. Orchid wants to display 4 of the paintings.  Thus, the number of ways can she choose the paintings she wishes to display is,

[tex]^9C_4=\dfrac{9!}{4!(9-4)!}\\^9C_4=\dfrac{9\times8\times7\times6\times5!}{4!5!}\\^9C_4=126[/tex]

Hence, number of ways Dr. Orchid can arrange all 9 paintings and 4 paintings is, 362880 and 126 respectively.

Learn more about the arrangement here;

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Answer:

5 inches

Step-by-step explanation:

As the height is perpendicular to the base, the radius and the height form a right angle, creating a right triangle where the slant height is the hypotenuse, thus:

[tex](height)^2+(radius)^2=(slant\:height)^2[/tex]

[tex]4^2+(6/2)^2=(slant\:height)^2[/tex]

[tex]16+9=(slant\:height)^2[/tex]

[tex]25=(slant\: height)^2[/tex]

[tex]5=slant\: height[/tex]

In conclusion, the slant height of the cone is 5 inches. See below for a visual.

If a quadrilateral with four congruent sides is not regular. Then the quadrilateral will be a rhombus.

It is a polygon that has four sides. The sum of the internal angle is 360 degrees. In a rhombus, opposite sides are parallel and all sides are equal and each angle is not 90 degrees.

A quadrilateral with four congruent sides is not regular.

If the sides of the quadrilateral are congruent then the quadrilateral must be either square or rhombus.

But if the sides are not regular then it must be a rhombus.

More about the rhombus link is given below.

https://brainly.com/question/22825947

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Answer:

8.

Step-by-step explanation:

I think that's the right answer. Please let me know if it isn't

8 is the correct answer the lovely person who owns this question corrected my mistake. Thank You by the way.

The correct answer is A.

Answer:

80

Step-by-step explanation:

25/120 ( since you are trying to find probability of a situation)=.2083

.2083*380=79.167 (just round it off to the nearest 1 which is 80).

Answer:

1435

Step-by-step explanation:

makatulong ba itong anser ko

You can arrange them in 120 different ways

The easiest way to do this is using factorials!

We are given 5 CDs

We are able to the factorial of 5

It would look like this 5!

5! = 5x4x3x2x1

This equals 120

well, if it was 300 and now is 350, it went up by 50 bucks, that's the inflation amount.

if we take 300 to be the 100%, what is 50 bucks off of it in percentage?

[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} 300 & 100\\ 50& x \end{array} \implies \cfrac{300}{50}=\cfrac{100}{x}\implies 6=\cfrac{100}{x} \\\\\\ 6x=100\implies x=\cfrac{100}{6}\implies x=\cfrac{50}{3}\implies x\approx 16.7[/tex]

The possible coordinates that could be the other endpoints of a line that has a length of 4 units are: (6, 2),  (10, -2), (2, -2), and (6, -6).

On a coordinate plane, the distance between two points is the number of units in between the two points lying on the same axis.

Let's find the distance between (6, -2) and eaxh of the given endpoints tro know which gives us a length of 4 units.

(6, -2) and (6, 2) = |-2 - 2| = 4 units

(6, -2) and (6, 6) = |-2 - 6| = 8 units

(6, -2) and (10, -2) = |10 - 6| = 4 units

(6, -2) and (2, -2) = |6 - 2| = 4 units

(6, -2) and (6, -6) = |-2 - (-6)| = 4 units

(6, -2) and (-2, -2) = |6 - (-2)| = 8 units

(6, -2) and (-10, -2) = |6 - (-10)| = 16 units

Therefore, the possible coordinates of the other endpoint of the line are: (6, 2),  (10, -2), (2, -2), and (6, -6).

Learn more about distance between two points on:

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Answer:

~Senpi boi here~

Step-by-step explanation:

I belive this is your exlpained answer for this qestion, As figure given in the question. Hers it is step by step:

Hypotenuse = 16 in

Base = 9 in

Putting the values in the formula

Hypotenuse² = Perpendicular² + Base²

16² = 9² + Base²

324 - 81 = Base²

243 = Base²

Base = 13.59 in (Approx)

Therefore the length of the base of the moniter be 15.59 in .

Answer: THIS IS THE CORRECT ANSWER

20"

Step-by-step explanation:

Length = 16" = L

Width = 12" = W

Diagonal   =  [tex]\sqrt{L^{2}+W^{2} }[/tex]

= [tex]\sqrt{16^{2}+12^{2} } = \sqrt{256+144\\\\[/tex]

=  [tex]\sqrt{400} = 20"[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's evaluate ~

[tex]\qquad \sf  \dashrightarrow \: \sqrt{{x}^{2} - 6x + 9 }[/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{{x}^{2} - 3x - 3x+ 9 }[/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{{x(}^{} x- 3) - 3(x - 3) }[/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{( x- 3) (x - 3) }[/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{( x- 3) {}^{2} }[/tex]

[tex]\qquad \sf  \dashrightarrow \: {( x- 3) {}^{} }[/tex]

I hope you understood the procedure ~ let me know if you have doubts ~

Answered by James ~ ( Teeny fr )

Answer:

[tex]f(x) = \frac{4}{3} (x - 2) ^{2} + 7[/tex]

Step-by-step explanation:

the answer is :- .

[tex]f(x) = \frac{4}{3} (x - 2) ^{2} + 7[/tex]

Answer:

y=-4(x+2)^2+7

Step-by-step explanation:

Answer:

y=12x - 192

Step-by-step explanation:

Hi there!

We are given the points (16,0) and (17, 12)

We want to write the equation of the line that contains these points in slope-intercept form

Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept

First, we need to find the slope

The slope (m) can be found using the formula [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are points

We have 2 points, which is what we need to find the slope, but let's label their values to help avoid confusion and mistakes

[tex]x_1=16\\y_1=0\\x_2=17\\y_2=12[/tex]

Now let's plug these values into the formula to find the slope

m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

m=[tex]\frac{12-0}{17-16}[/tex]

Subtract

m=[tex]\frac{12}{1}[/tex]

Divide

m = 12

The slope of the line is 12.

Let's substitute that as m in y=mx+b.

Here is our equation so far:

y=12x + b

Now we need to find b

As the equation passes through the points (16,0) and (17, 12), we can use either one of them to solve for b.
Using (16,0) for example:

Substitute 16 as x and 0 as y.

0 = 12(16) + b

Multiply

0 = 192 + b

Subtract 192 from both sides

-192 = b

Substitute -192 as b in the equation

y = 12x - 192

Hope this helps!

Topic: finding the equation of the line

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Step-by-step explanation:

choice 2 ..............

Answer:

True, True, False

Step-by-step explanation:

16.284 to whole is 16

16.284 to tenth is 16.3

16.284 to hundredth is 16.28

Answer:

88189987766.9087 because x stands for 1000

Answer:

option B is correct.

Option A                                                 Option B                                                    

6x = 66                                                    5x = 30  

x = 66/6                                                    x = 30/5

x = 11                                                         x = 6

Option C                                                 Option D

6x = 1                                                       7x + 2 = 15

x = 1/6                                                      7x = 15 - 2

x = [tex]\sf \sf \frac{1}{6}[/tex]                                                          x = [tex]\sf \frac{13}{7}[/tex]

Differentiate x and y with respect to t :

[tex]x = e^{\sec(2t)} \implies \dfrac{dx}{dt} = e^{\sec(2t)} \dfrac{d(\sec(2t))}{dx} = 2\sec(2t)\tan(2t) e^{\sec(2t)}[/tex]

[tex]y = e^{\tan(2t)} \implies \dfrac{dy}{dt} = e^{\tan(2t)} \dfrac{d(\tan(2t))}{dx} = 2\sec^2(2t) e^{\tan(2t)}[/tex]

By the chain rule,

[tex]\dfrac{dy}{dx} = \dfrac{dy}{dt} \times \dfrac{dt}{dx} = \dfrac{\frac{dy}{dt}}{\frac{dx}{dt}}[/tex]

Then

[tex]\dfrac{dy}{dx} = \dfrac{2\sec^2(2t) e^{\tan(2t)}}{2\sec(2t)\tan(2t) e^{\sec(2t)}} = \dfrac{\sec(2t) e^{\tan(2t)}}{\tan(2t) e^{\sec(2t)}} =\dfrac{y \sec(2t)}{x\tan(2t)}[/tex]

and we have

[tex]\log(x) = \sec(2t)[/tex]

[tex]\log(y) = \tan(2t)[/tex]

and the claim follows.