The direction of the bird's velocity can be adjusted so that the wind and the resulting bird velocity will both be in the southerly direction.
(a) The bird should fly at an angle of roughly South 23.58° East if it wants to move directly southward in relation to the earth.
(b) The bird would need around 5.46 hours to fly 500 kilometres from North to South.
The components of the velocity are v(x) and v(y).
The magnitude of the velocity of the bird is 100 km/h
The orientation of the bird corresponds to that of North and South.
The magnitude of the velocity of the wind is 40 km/h
East-west is the direction of the wind.
(a) The component vector of the two velocities are;
The velocity of the bird, v(y) = -100(j)
The velocity of wind, v(x) = 40(i)
If the bird has a component of velocity to accommodate the wind velocity, the direction of its movement will be southerly.
Let θ be the angle of the direction of the bird relative to the negative x-axis, therefore:
-100(j) × cos(θ) = -40·i
θ = cos⁻¹(40/100)
θ ≈ 66.42° in the third quadrat, given that both the y, and x, values are negative.
In the South-West direction, the angle is:
90 - 66.42 ≈ 23.58°
Therefore, to fly directly southward relative to the ground, the bird should fly in the direction of south 23.58° east.
(b) The following is given as the component of the bird's southerly velocity when traveling in the new direction:
v(s) = 100 × sin(θ)
Hence,
Southward velocity, v(s) = 100 × sin(66.42°)
The time t it takes to travel 500 km, is given as:
d = v(s)t
500 = 100 × sin(66.42°)(t)
t = 5.46 hrs
The bird would need 5.46 hours to fly 500 kilometres from North to South.
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The complete question is mentioned below:
Canada geese migrate essentially along a north–south direction for well over a thousand kilometres in some cases, traveling at speeds up to about 100 km/h. If one goose is flying at 100 km/h relative to the air but a 40-km/h wind is blowing from west to east,
(a) at what angle relative to the north–south direction should this bird head to travel directly southward relative to the ground?
(b) How long will it take the goose to cover a ground distance of 500 km from north to south? (Even on cloudy nights, many birds can navigate by using the earth’s magnetic field to fix the north–south direction.)
what is the total capacitance of a certain circuit containing three capacitors with capacitances of .25 microfarad, .03 microfarad, and .12 microfarad, respectively? (note: c(t)
The total capacitance of the capacitor circuit is 40 μF.
We need to know about capacitor circuits to solve this problem. The capacitance will be summed up when the capacitor is combined in parallel. The total capacitance can be determined as
Ct = C1 + C2 + C3
From the question above, we know that:
C1 = 25 μF
C2 = 3 μF
C3 = 12 μF
By substituting the parameters, we can get
Ct = C1 + C2 + C3
Ct = 25 μF + 3 μF + 12 μF
Ct = 40 μF
Hence, the total capacitance of the circuit is 40 μF.
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Two spheres are made of the same metal and have the same radius, but one is hollow and the other is solid. The spheres are taken through the same temperature increase. Which sphere expands more?.
The ideal selection is C. The spheres will each grow evenly.
What is the coefficient of expansion?The coefficient of expansion of any material is the property of the material which defines the expansion or contraction of the material with the variation of the temperature.
The ratio of a body's length, area, or volume at a given temperature, usually 0° C, to its length, area, or volume at that temperature, respectively, while maintaining constant pressure.
Given that two spheres with the same radius and formed of the same metal are hollow and solid, respectively. The same temperature rise is applied to the spheres.
Since both bodies in this instance are formed of the same substance, their orientation has no bearing on how much it expands. Because the materials used to create both spheres were the same, we can thus conclude that they will expand equally.
Therefore, both materials will expand equally.
The complete options are given below:-
A Hollow sphere will expand more than the solid one.
B Solid sphere will expand more than the hollow one.
C Both spheres will expand equally.
D None of these
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the gauge pressure at the bottom of a cylinder of liquid is 0.40 atm . the liquid is poured into another cylinder with twice the radius of the first cylinder. part a what is the gauge pressure at the bottom of the second cylinder?
The gauge pressure at the bottom of the second cylinder is 0.10 atm.
What do you mean by gauge pressure?The pressure of a system above the atmospheric pressure is known as gauge pressure, commonly referred to as overpressure. The pressure from the weight of the atmosphere is included in gauge pressure readings because gauge pressure is zero-referenced against ambient air (or atmospheric) pressure. This indicates that gauge pressure varies in response to both weather and height above sea level. Gauge pressure measurement is adequate for the majority of industrial applications because every operation in a refinery or manufacturing facility operates at the same air pressure. Absolute pressure is a measurement of pressure that is based on a reference pressure of zero or absolutely no pressure. The only place where this happens naturally is in a perfect vacuum, which can only be found in space.
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Construct Explanations Flora is a pilot. She knows that it is very dangerous to put an airplane into a dive that is too steep. Explain what the danger is, in terms of potential and Kinetic energy.
One of the main causes of fatalities in the commercial aviation sector is loss of airplane control while in flight. There are numerous causes of upsets in airplanes, but none of them are statistically significant.
Eliminating one cause of upsets won't definitely result in fewer fatalities and accidents involving loss of control. Reducing the number of upset causes requires ongoing training. Additionally, many environmental factors that cause upsets can't always be avoided, which makes avoidance the best course of action. Therefore, in order to recover an upset airplane, pilots must possess the requisite knowledge and abilities.
All makers of big, swept-wing commercial jet aircraft use the same aerodynamic concepts.
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22. сс Peter exerts a horizontal force of 500 N on a box of mass 2.0 kg which also experiences a friction force of 200 N. If it takes 4.0 s to move the box 3.0 m, what is the efficiency in moving the box? Efficiency 2 Energy coming in energy going X 100 %. (c) ABUD 29% 40% 60% 71% FH301/P1/19 ont.
The efficiency of moving the box is 60%.
Given in the question
Force exerted by peter = 500 N
Force due to friction on box = 200 N
Distance Traveled by box = 3 meters
Now work done by the force is given by
Work Done = (Magnitude of Force) × (Distance traveled)
Let us find work done by each force,
Work done by peter
Work Done = (Magnitude of Force) × (Distance traveled)
Put in the value, we get
Work Done =500 × 3
Work Done by peter = 1500 J
Similarly, Work done by friction
Work Done = (Magnitude of Force) × (Distance traveled)
Put in the value, we get
Work Done =200 × 3
Work Done by Friction = 600 J
As we know the work done by friction force is always negative,
Work Done by Friction = -600 J
So, net Work done = Work Done by peter + Work Done by Friction
net Work done = 1500 - 600
Net Work done = 900 J
Now Efficiency = (Net work done/work done by peter) × 100
Put in the values, we get
Efficiency = (900/1500) × 100
Efficiency = (3/5) × 100
Efficiency = 300/5
Efficiency = 60 %
So, the efficiency of moving the box is 60%.
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i go 540km at a speed of 100 km per hour how long does it take?
Answer: 5.4 hours.
Explanation:
So, this would simply be divison. So, we can take 540 km, and seperate it into 500 km, and 40 km.
That being said, we can divide 500 km by 100, so we can see how many hours it takes for 500 km, which is 5.
Now, we divide 40/100, which gives us 0.4.
Add the two together, and it takes 5.4 hours to reach 540 km at a speed of 100 km/hr
What does a radio wave do to the charges in the receiving antenna to provide a signal for your car radio?
Radio waves allows the charges in the receiving antenna to respond to the electric field portion of the carrier wave.
What is a wave?This refers to a type of disturbance which transports energy from one place to another without the actual movement of the particles and of various types such as microwaves, radio waves etc.
The radio wave allows the electrons in the rod to vibrate with amplitudes which emulates those of the carrier wave and in this case, it is the antenna thereby resulting in the signals in the car radio being provided as a result of these type of interactions.
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Which of the following pairs can be the components of a velocity of 30 m s¹ (east)? (a) 20 m s' (east), 10 m s' (east)
(b) 35 m s¹ (east), 5 m s¹ (west)
(c) 20 m s¹ (east). 15 m s¹ (west)
A and B. The pairs that can be the components of a velocity of 30 m s¹ (east) are 20 m s' (east), 10 m s' (east) and 35 m s¹ (east), 5 m s¹ (west).
What is resultant velocity?
The resultant velocity of an object is the sum of its individual vector velocities.
For a resultant velocity of 30 m/s east, the component velocities that can equal the resultant velocity is calculated as follows;
35 m/s east and 5 m/s west
let the east direction be positive
let the west direction be negative
R = 35 m/s - 5 m/s
R = 30 m/s east
Another pair20 m/s east and 10 m/s east
R = 20 m/s + 10 m/s
R = 30 m/s
Thus, the pairs that can be the components of a velocity of 30 m s¹ (east) are (a) 20 m s' (east), 10 m s' (east) and (b) 35 m s¹ (east), 5 m s¹ (west).
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a 2-kg mass attached to the end of a spring with a spring constant of 200 n/m moves in simple harmonic motion. find the period of the oscillations.
By angular speed, the period of oscillation is 0.63 second.
We need to know about the angular speed of harmonic oscillation. the angular speed can be determined as
ω² = k / m
where ω is angular speed, k is spring constant, and m is the mass.
The angular speed can be calculated by
ω = 2π/T
Hence,
ω² = k / m
(2π/T)² = k / m
where T is period.
From the question above, we know that:
m = 2 kg
k = 200 N/m
By substituting to the equation, we get
(2π/T)² = k / m
(2π/T)² = 200 / 2
(2π/T)² = 100
square root
2π/T = √100
T = 2π / √100
T = 0.63 second
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in 7 seconds, a projectile goes from 0 to 181m/s. What is the acceleration l? (round to the nearest whole number)
Answer:
84.83 ft/s^2 or 85 ft/s^2
Explanation:
A = Δ v Δ t
Acceleration is the rate of change of an objects speed; in other words, it's how fast velocity changes. According to Newton's second law, acceleration is directly proportional to the summation of all forces that act on an object and inversely proportional to its mass. It's all common sense - if several different forces are pushing an object, you need to work out what they add up to (they may be working in different directions), and then divide the resulting net force by your object's mass.
This acceleration definition says that acceleration and force are, in fact, the same thing. When the force changes, acceleration changes too, but the magnitude of its change depends on the mass of an object. This is not true in a situation when the mass also changes, e.g., in rocket thrust, where burnt propellants exit from the rocket's nozzle.
In the 17th century, Sir Isaac Newton, one of the most influential scientists of all time, published his famous book Principia. In it, he formulated the law of universal gravitation which states that any two objects with mass will attract each other with a force exponentially dependent on distance between these objects (specifically, it is inversely proportional to the distance squared). The heavier the objects are, the greater is gravitational force. It explains, for example, why planets orbit around the very dense Sun.
In Principia, Newton also includes three laws of motion which are central to understanding the physics of our world. The acceleration calculator is based on three various acceleration equations, where the third is derived from Newton's work:
a = (v_f - v_i) / Δt,
a = 2 * (Δd - v_i * Δt) / Δt²,
a = F / m,
where:
a is the acceleration,
v_i and v_f are respectively the initial and final velocities,
Δt is the acceleration time,
Δd is the distance traveled during acceleration,
F is the net force acting on an object that accelerates,
m is the mass of this object.
If you already know how to calculate acceleration let's focus on the units of acceleration. You can derive them from the equations we listed above. All you need to know is that speed is expressed in feet per second (imperial/US system) or in meters per second (SI system) and time in seconds. Therefore, if you divide speed by time (as we do in the first acceleration formula), you'll get acceleration unit ft/s² or m/s² depending on which system you use.
Alternatively, you can use the third equation. In this case, you need to divide force (poundals in US and newtons in SI) by mass (pounds in US and kilograms in SI) obtaining pdl/lb or N/kg. They both represent the same thing, as poundal is pdl = lb * ft/s² and the newton is N = kg * m/s². When you substitute it and reduce the units, you'll get (lb * ft/s²) / lb = ft/s² or (kg * m/s²) / kg = m/s².
There is also a third option that is, in fact, widely used. You can express acceleration by standard acceleration, due to gravity near the surface of the Earth which is defined as g = 31.17405 ft/s² = 9.80665 m/s². For example, if you say that an elevator is moving upwards with the acceleration of 0.2g, it means that it accelerates with about 6.2 ft/s² or 2 m/s² (i.e., 0.2*g).
What is the mass of an object that requires 100N (kg-m/s2) of force in order to accelerate it at 10m/s2 (Please use G-R-E-S-A) pls pasagot
The calculated mass is 10 kg.
Mass (kg) times acceleration (m/s2) equals force (N). A constant mass item will therefore accelerate in direct proportion to the force exerted. When two objects of differing masses are subjected to the same force, the heavier object accelerates more slowly than the lighter object. Mass times acceleration, or F=m x a, equals force. This means that in order to move an object at the same speed as an object with smaller mass, a stronger force is required.
So, Mass times acceleration equals force
100=Mass×10
To calculate mass on its own, divide 100 by 10 on both sides.
Mass = 10 kg
Because this formula was developed using kg rather than another unit of mass like the slug, the mass is expressed in kg.
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What was the control group for the Michelson-Morley experiment?
The control group for the Michelson-Morley experiment was Interferometer.
The Michelson Morley Experiment was one of the unsuccessful tests that proved the luminiferous ether idea did not exist.
Michelson and Morley attempted to explain how the Earth orbited the sun and how the passage of substances such as ether over the Earth's surface might cause measurable "ether wind."
They attempted to show the idea that the speed of light depends on the size of the ether wind as well as the direction of the beam in relation to it when the light is emitted from an Earthly source. It was supposed that ether was immobile.
The experiment's goal was to measure the speed of light in different directions in order to determine the speed of the ether relative to Earth, so proving its existence.
The theorized material Luminiferous Ether serves as a medium for the transmission of electromagnetic waves such as light rays and X-rays. Ether was thought to be a transmission medium for light propagation.
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Q|C Spherical waves of wavelength 45.0 cm propagate outward from a point source. (c) Explain how the phase of the wave at a distance of 240 cm compares with the phase at 60.0cm at the same moment.
We are given distance of the center of the source for two waves:
[tex]D_{1} =240 cm[/tex]
[tex]D_{2} =60 cm[/tex]
C) Calculating how their phases compares:
ΔФ240[tex]=\frac{D_{2} }{D_{1} } .[/tex]ΔФ60
[tex]\frac{240}{60} .[/tex]ΔФ60 = 4.ΔФ60
How can you determine a wave's phase?
The period, or length of each cycle, is determined by dividing the frequency by 1, so 1/100 corresponds to a period of 0.01 seconds. The phase shift equation is given by ps = 360 * td / p, where td is the time interval between waves, p is the wave period, and ps is the phase shift in degrees.Phase: The "Phase" of a waveform refers to the location of the moving particle and is expressed in "Radians or degrees."
Phase difference, also known as "Phase angle," is the amount of time that one wave precedes or follows another.
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What is the potential difference across a hand-held fan that has a resistance of. 120 ohms and a current of 0,005A flowing through it?
Answer: The answer is 0.6 volts
Explanation:
As the formula of Resistance says that
Resistance= Voltage÷ Current
Where its going to be
Voltage= Resistance÷ Current
Resistance= 120 ohms
Current= 0.005A
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What weight of the ore in lb would contain exactly 1lb of copper
The density of crushed iron ore is equivalent to 2 500 kg/m3, or 2.5 grams per cubic centimeter, which is the weight of the material. The density is equal to 156.07 pounds per cubic foot in either the Imperial or US customary measuring systems.
When weights are expressed in kilograms of air, the air gives buoyancy, and because a kilogram of copper has a larger volume than a kilogram of lead, it displaces more air and hence receives more support. As a result, on a scale in the air, a kilogram of lead will weigh more than a kilogram of copper. Copper has a density of 8.94 grams per cubic centimeter, or 8 940 kilograms per cubic meter, or 20°C (68°F or 293.15K), at ordinary atmospheric pressure.
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The micrometer 1 is often called the micron , a) how many microns make up 1.8km ? b) how many centimeters equal 1.8 ? c) how many microns are in 1.8 yd ?
By unit conversion, the converted unit is
a. 1.8 km = 1.8 x 10⁹ μm
b. 1.8 μm = 1.8 x 10¯⁴ cm
c. 1.8 yard = 1645920 μm
We need to know about unit conversion to solve this problem. The unit conversion can be used to convert a unit to another unit. It can be defined as
a = xb
where a is unit a, b is unit b and x is the constant of conversion.
From the question above, we know that
a. 1.8 km = .... μm
b. 1.8 μm = .... cm
c. 1.8 yard = .... μm
Find the microns (1 km = 10⁹ μm)
1.8 km = 1.8 x 10⁹ μm
Find the centimeter (1 cm = 10⁴ μm)
1cm = 10⁴ μm
1/10⁴ cm = 1 μm
Hence,
1.8 μm = 1.8/10⁴ cm
1.8 μm = 1.8 x 10¯⁴ cm
Find the microns (1 yd = 914400 μm)
1.8 yard = 1.8 x 914400 μm
1.8 yard = 1645920 μm
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1. Two point charges, q1 and q2, of 4.00 μC each, are placed at x1=-16.0 cm and x2 = 16.0 cm away from the origin on the x-axis. A charge q3 of 1.00 μC is placed 12.0 cm away from the origin on the y-axis.
a. Find the distance from q3 to q1 and from q3 to q2.
b. Find the magnitude and the direction of the force F13 exerted by q1 on q3.
c. Find the magnitude and the direction of the force F23 exerted by q2 on q3.
d. Find the magnitude and the direction of the force F12 exerted by q1 on q2.
The distance between charge 1 and 3 is equal to 20 cm and the force between charge 1 and 3 is equal to force between charge 1 and 3 that is 0.9 Newton and the force between charge 2 and 3 is equal to 1.41 Newton.
What are charges?Electric charges are basic property of matter carried by some elementary particles that governs how the particles are affected by an electric or magnetic field. Electric charge, which can be positive or negative, occurs in discrete natural units and is neither created nor destroyed.
What is coulomb's law?Coulomb's law states that like charges repel and opposite charges attract, with a force proportional to the product of the charges and inversely proportional to the square of the distance between them.
Given:
Magnitude on charge 1 = 4 μC
Magnitude on charge 2 = 4 μC
Magnitude on charge 3 = 1 μC
Distance between charge 1 and 2 = 32 cm
Distance of charge 3 from center of charge 1 and 2 = 12 cm
Distance between charge 1 and 3 can be find using Pythagoras theorem.
Distance between charge 1 and 3 = √(256 + 144)
Distance between charge 1 and 3 = 20cm
Similarly Distance between charge 2 and 3 = 20cm
Force between charge 1 and 3 can be found using coulomb law.
Force between charge 1 and 3 = (9 × 4 × 1)/40
Force between charge 1 and 3 = 36/40
Force between charge 1 and 3 = 0.9 Newton
Similarly using symmetry, force between charge 2 and 3 = 0.9 Newton
Force between charge 1 and 2 =(9 × 4 × 4)/102
Force between charge 1 and 2 = 1.41 newton
Therefore the distance between charge 1 and 3 is equal to 20 cm and the force between charge 1 and 3 is equal to force between charge 1 and 3 that is 0.9 Newton and the force between charge 2 and 3 is equal to 1.41 Newton.
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A spaceship of mass 2.40x10⁶kg is to be accelerated to a speed of 0.700 c. (b) How much fuel would it take to provide this much energy if all the rest energy of the fuel could be transformed to kinetic energy of the spaceship?
The fuel required to gain minimum energy is (3.02 x 10²³ / ΔH) kg.
We need to know about relativistic energy to solve this problem. The rest energy of the object can be determined by
Eo = m₀ . c²
where Eo is rest energy, m₀ is rest mass and c is the speed of light (3 x 10⁸ m/s).
The total energy of object can be described as
E = Eo / √(1 - v²/c²)
where E is total energy, v is the object speed.
From the question above, we know that :
m₀ = 2.4 x 10⁶ kg
c = 3 x 10⁸ m/s
v = 0.7c
Find the rest energy
Eo = m₀ . c²
Eo = 2.4 x 10⁶ . (3 x 10⁸)²
Eo = 2.16 x 10²³ joule
Determine the total energy
E = Eo / √(1 - v²/c²)
E = 2.16 x 10²³ / √(1 - (0.7c)²/c²)
E = 2.16 x 10²³ / 0.71
E = 3.02 x 10²³ joule
Assume that the Heat of Combustion for Space fuel = ΔH J/kg
m = E / ΔH
m = 3.02 x 10²³ / ΔH kg
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A⁵⁷ Fe Fe nucleus at rest emits a 14.0keV photon. Use conservation of energy and momentum to find the kinetic energy of the recoiling nucleus in electron volts. Use M c² = 8.60 × 10⁻⁹J for the final state of the ⁵⁷Fe nucleus.
Kinetic energy is K = 1.82 × 10⁻³ eV.
⁵⁷Fe nucleus emits 14 keV photons at rest.
We have, Mc² = 8.6 × 10⁻⁹ J in the final state of the nucleus.
Let p(nucleus) be the moment of the nucleus and p(photon) be the momentum of the photon.
Then, by conservation of momentum since the total moment is zero.
p(nucleus) = p(photon) = E(γ) / c = 140 keV / c
The energy for the recoiling nucleus is given as:
E² = p²c² + (mc²)²
Now, Mc² = 8.60 × 10⁻⁹J =5.38 × 10¹⁰ eV = 5.38 × 10⁷ keV
Therefore,
(Mc² + K²) ² = (14 keV)² + (Mc²)²
(1 + K²/Mc²)² =(14/Mc²)² +1
The term (1 + K²/Mc²)² is less than 1 therefore, (14/Mc²)² + 1 is equal to 1 by clacualtor.
Now using binomial theorem,
(1 + K²/Mc²)² = √[1 + ((14/Mc²)²] = 1 + (1/2)(14/Mc²)²
K = 1.82 × 10⁻³ eV
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Plane used to remove the tip of your nose
A. Transverse (top/bottom)
B. Sagittal (sides)
C. Frontal (front/back)
Plane used to remove the tip of your nose is known to be called option C. Frontal (front/back).
What is another name for the coronal plane?In regards to biology, If a person were to cut their nose off, it is one that is known to be called coronal.
The coronal plane is said to be a term that is often referred to as the frontal plane and it is seen as any vertical plane that shares the body into ventral as well as dorsal (belly and back) parts.
Therefore one can say that the coronal Plane (Frontal plane) used to remove the tip of your nose.
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In a certain experiment, a filament in an evacuated lightbulb carries a current I₁ and you measure the spectrum of light emitted by the filament, which behaves as a black body at temperature T₁ . The wavelength emitted with highest intensity (symbolized by λmax) has the value λ₁ . You then increase the potential difference across the filament by a factor of 8 , and the current increases by a factor of 2 .(i) After this change, what is the new value of the tempera-ture of the filament? (a) 16 T₁ (b) 8 T₁ (c) 4 T₁ (d) 2 T₁ (e) still T₁
Using Stefan's equation, which states that the power of the emitted radiation will be proportional to the fourth power of the absolute temperature, we treat the filament of the evacuated light bulb as a black body.
P = σ AeT⁴
Where A is the surface area of the emitter, σ is Stefan's constant, and e is the emissivity of the surface.
Now, from Stefan's Law, the radiated power is proportional to the fourth power of temperature.
P =IV
IV ∝ T⁴
Therefore,
I₁ V₁ / (I₂ V₂) = (T₁ / T₂)⁴
T₁ / T₂ = (I₁ V₁ / I₂ V₂)^{1/4}
T₂ = T₂ [ (I₁ V₁ / I₂ V₂)^{1/4} ]
Now we have,
I₂ = 2I₁ and
V₂ = 8V₁
Therefore,
T₂ = T₁ [ (2I₁ )(8V₁)/(I₁ V₁) ]^{1/4}
T₂ = T₁ (16)^{1/4}
T₂ = 2T₁
The correct option is (d).
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Switch on your light source and make sure it's shining onto a wall.hold your largest cardboard square between the light source and the wall.wha do you observe?
Light source will pass through and form a shadow, when I hold the largest cardboard between the light source and the wall. Since, the cardboard is not so thick it will allow rays to pass through it.
Light rays always travel in a straight line. A shadow is formed when the light rays hit an opaque object. Sun is a natural source of light. The rays from the sun fall on objects on earth and forms shadows. Light rays do not interfere with each other if they come cross each other. Light rays travel from the direction of source to the direction of eye. They show property of reflection wherein after colliding a surface they trace their path back.
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An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When the engineer first sees the car, the locomotive is 350 m from the crossing and its speed is 12 m/s. If the engineer’s reaction time is 0.56 s, what should be the magnitude of the minimum deceleration to avoid an accident? Answer in units of m/s^2.
The magnitude of the minimum deceleration to avoid an accident is 2,186.5 m/s².
Minimum acceleration to avoid accidentThe minimum acceleration to avoid accident is calculated as follows;
s = ut + ¹/₂at²
where;
u is the initial velocitya is the minimum accelerationt is time of motionSubstitute the given parameters and solve for the acceleration as follows;
350 = 12(0.56) + ¹/₂(0.56²)a
350 = 6.72 + 0.157a
0.157a = 350 - 6.72
0.157a = 343.28
a = 343.28/0.157
a = 2,186.5 m/s²
Thus, the magnitude of the minimum deceleration to avoid an accident is 2,186.5 m/s².
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Two long, parallel conductors, separated by 10.0cm, carry currents in the same direction. The first wire carries a current I₁ = 5.00A, and the second carries I₂ = 8.00 A. (b) What is the force per unit length exerted by I₁ on I₂ ?
The force per unit length exerted by I₁ on I₂ is [tex]8\times10^-^5 \ N/m[/tex] .
Two long parallel conductors separated by a distance 'r' having current [tex]I_1[/tex] and [tex]I_2[/tex] have force per unit length which is given by [tex]f=\frac{u_0I_1I_2}{2\pi r}[/tex] .....(1) where [tex]u_0[/tex] is permittivity of free space whose value is [tex]4\pi \times10^-^7Tm/A[/tex]
It is given that two long, parallel conductors, separated by 10.0cm having current I₁ = 5.00A and I₂ = 8.00 A.
If the current flowing through the wire are in same direction then they the wire attract each other and if the current flowing through the wire are opposite in direction then they the wire repel each other
Putting r = 10.0cm [tex]=10\times10^{-2}m[/tex] , I₁ = 5.00A and I₂ = 8.00 A in equation (1) , we get
[tex]f=\frac{4\pi \times10^-^7\times5.00\times8.00}{2\times\pi\times10.00\times10^{-2}}\\\\f=\frac{2\times40\times10^-^5}{10} \\\\f=8\times10^{-5}N/m[/tex]
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What is the difference between a testing and outcome variable??
Answer:
The independent variable is the cause. Its value is independent of other variables in your study. The dependent variable is the effect. Its value depends on changes in the independent variable.
Explanation:
Hope this helps!
A straight wire carrying a 3.00-A current is placed in a uniform magnetic field of magnitude 0.280 T directed perpendicular to the wire. (b) Explain why you can't determine the direction of the magnetic force from the information given in the problem.
The reasons are discussed below -
We have a straight current carrying wire placed in a uniform magnetic field.
We have to explain why we can't determine the direction of the magnetic force from the information given in the problem.
What is the magnitude of force acting on a current (I) carrying wire of length (L) placed in a Magnetic field (B)?The force on the current carrying wire will be -
F = IBL sinθ
According to the question -
It is impossible to determine the direction of magnetic force because of the following reasons -
Firstly, the length of the wire present in the region of magnetic field is given. If we assume it to be ∞, then -
F = IB sin(θ) x ∞ = ∞ (which is not a valid result)
Secondly, Although it is mentioned that a straight current carrying wire is placed perpendicular to the uniform magnetic field, there is no mention about the exact orientation of the magnetic field direction. For example, if we consider the wire along +x axis then perpendicular could be any of the four directions -
+k, -k, +j, -j
Hence, these are the reasons why we can't determine the direction of the magnetic force from the information given in the problem.
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20 POINTSSS PLS HELP
Imagine if the Earth suddenly sped up. What do you think would happen to its orbit?
Answer:
down below
Explanation:
I assume you're asking about it's orbit around the sun. I believe the Earth's orbit around the sun would be shorter. If the Earth sped up, one can assume that means the days are shorter and the rate at which the Earth orbits the sun would also speed up.
This sounds like an open ended question, so I don't think there can be a wrong answer.
Hope this helps! :)
Using the graph provided, determine the velocity in meters per second of the object at t = 2 seconds.
+/-
The velocity in meters per second of the object at t = 2 seconds is 2.5 m/s
What is velocity?Velocity is simply defined as the rate of change of displacement with time. Mathematically, it can be expressed as:
Velocity = displacement / time
How to determine the velocity of the object at t = 2 sFrom the question given above, the following data were obtained:
Time = 2 sDisplacement = (3.33 + 6.67) / 2 = 5 mVelocity =?Velocity = displacement / time
Velocity = 5 / 2
Velocity = 2.5 m/s
Thus, the velocity is 2.5 m/s
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Suppose you have found a piece of material. You are not sure what the material is. You want to find out if it is a good conductor or a good insulator. Describe in words what you would do to determine if the material is an electrical conductor.
Answer:
Touch the open ends of the two wires to each other to form a circuit and test the bulb. Touch the two open ends of the wire to each material you are testing, one at a time. If the bulb lights up, it is a good conductor. If it doesn't, it is a good insulator.How do you know if an object is a good conductor and poor conductor of electricity?
Image result for Suppose you have found a piece of material. You are not sure what the material is. You want to find out if it is a good conductor or a good insulator. Describe in words what you would do to determine if the material is an electrical conductor.
Difference between Good Conductor and Bad Conductor of Electricity. Good conductors are those materials which allow electricity to pass through them easily. Bad conductors are those materials which do not allow electricity to pass through them easily.
a 1250 kg car traveling at a speed of 25.0 m/s rounds a 175 m radius curve. assuming the road is level, determine the coefficient of static friction between the car’s tires and the road.
Coefficient of static friction between the car’s tires and the road is 0.3
What is static friction ?
A force that holds an object at rest is called static friction. The definition of static friction is: The resistance people feel when they attempt to move a stationary object across a surface without actually causing any relative motion between their body and the surface they are moving the object across.
Give an illustration of static friction.
When something is sitting on a surface, static friction affects it. For instance, every time you place your foot on the trail when trekking in the woods, there is static friction between your shoes and the surface.
Assume that road is level
Friction force provides centripetal force to the car
The weight of the car is = 1250 kg
speed of the car is = 25 m/s
curve radius =r= 175m
we know the formula of centripetal force is given by
[tex]f_{s} =\frac{mv^{2} }{r}[/tex] where m = mass of the object
v= velocity
r= curve radius
and we know the static force is given by f= μN
here, N= mg
so now,
μmg=[tex]\frac{mv^{2} }{r}\\[/tex]
now put the all give values then we get,
[tex]$$\mu_r=\frac{v^2}{r g}=\frac{(25 \mathrm{~m} / \mathrm{sec})^2}{(175 \mathrm{~m})\left(9.8 \mathrm{~m} / \mathrm{sec}^2\right)}$$[/tex]
μ=[tex]\frac{625}{1715}[/tex]
μ= 0.3 , This is the coefficient of friction between the car tire and the rode
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