How is it possible for a tree to survive if the inner part is missing?

Answer:19.42 degree

Explanation:

using Snell's law, sin(I)/sin(r) = n2 / n1 we will get the answer of angle of refraction of light.

Answer: 900 m

Explanation: If you walk at a speed of 5 meters per second for 3 minutes, or 180 seconds, then you will have walked 900 meters. This can be seen in the equation [tex]x=x_{0}+v_{x0}t+\frac{1}{2} a_{x}t^2[/tex]. As the velocity is constant (no acceleration) and the initial position is zero, plugging in known values for v and t, you can solve for x of 900 m.

The location at the point where electric field becomes zero is at 3.6m, when a positive point charge Q1= 2.6×10−5 C is fixed at the origin and a negative point charge Q2= −5.1×10−6 C is fixed at 2.0m.

Electric field is field around electrically charged particle where columbic force of attraction or repulsion can be experienced by other charged particles. It is denoted by letter E and it's SI unit is V/m Volt per meter or N/C newton per coulomb.

Electric field comes inward to the center of the negative charge and it is going outward for positive charge.

Given,

Q₁= 2.6×10⁻⁵ C

Q₂= −5.1×10⁻⁶ C

x = 2.0m,

In this case there are two charges, one at the origin and other is at 2m distance from origin. Both these charges are kept along positive x axis. looking at the situation there are 2 cases

Case 1 ( electric field in between two charges)

in this case direction of the resultant electric field in between two charges is along positive x direction (direction of electric field of positive charge is outward along x axis which is along positive x direction and direction of electric field of negative charge is inward along x axis which is also in positive x direction).

Case 2 ( right side of the negative charge)

In this case direction of electric field of positive charge is outward along x axis which is along positive x direction and direction of electric field of negative charge is inward along x axis but which is in opposite direction of electric field due to positive charge.

Hence our electric field is zero at right side of the negative charge.

on right side, electric fields due to both charges are opposite to each other then we can write mathematically E₁ - E₂ = 0 at the point where resultant electric field is zero. Where E₁ is elctric field due to positive charge and E₂ is electric field due to negative charge.

E₁ - E₂ = 0

E₁ = E₂

[tex]\frac{kQ_{1}}{x^{2}} = \frac{kQ_{2} }{(x+2)^{2}}[/tex]

[tex]\frac{Q_{1}}{x^{2}} = \frac{Q_{2} }{(x+2)^{2}}[/tex]

[tex]\frac{Q_{1}}{Q_{2} }} = \frac{x^{2} }{(x+2)^{2}}[/tex]

(2.6×10⁻⁵ C ÷ -5.1×10⁻⁶ C)  [tex]= \frac{x^{2} }{(x+2)^{2}}[/tex]

[tex]\frac{x^{2} }{(x+2)^{2}}[/tex] = 5.098 ≅ -5.1

x² = 5.1 (x+2)²

x = 2.25(x+2)

x=2.25x + 4.5

x(1-2.25) = 4.5

x(-1.25) = 4.5

x = 3.6m

Hence Electric field is zero at 3.6m from origin.

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If you drive to the north with a velocity of 88km/hr and in the other lane  A truck approaches you at a constant velocity of 104km/h, (A) the truck's velocity relative to you (Vty) is -192km/h.(B) your velocity relative to the truck (Vyt) is 192km/h. (C) The relative velocities do not change after you and the truck pass each other.

The relative velocity of body B(say) w.r.t. body A(say) is defined as the velocity with which B appears to move to A when both are in motion.

we know that,

When two body A and B, is in relative motion to one another body C, Then the relative velocity of A w.r.t B is (Vab) given by.

Vab=Vac+Vca

Here in the question Given that,

The relative velocity of you with respect to earth (Vye)=88km/h

The relative velocity of the truck w.r.t earth (Vte)= -104km/h ( it is approaching you i.e south direction)

(A) The relative velocity of Truck w.r.t you is given by,

Vte=Vty+Vye

Vty=-Vte-Vye

Vty=-104-88=  -192km/h

Vty=-192km/h towards the negative direction I.e south.

(B) Your velocity relative to the truck (Vyt) is given by,

Vyt= -Vty

Vyt=   -(-192)km/h

Vyt=192km/h towards the positive direction I.e north.

(C) The relative velocity does not change after you and the truck pass each other.

Hence, the relative velocity of the truck w.r.t you is -192km/h the relative velocity you w.r.t truck is 192km/h.

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The 35m would the Roche limit be for an earth-orbiting body with the same density as iron(8.0g/cm ^3).

What is density ?

How much material an object contains per unit volume is determined by the density of the substance. It is symbolized by the letter D, however it can also be represented by the symbol.  The density of a substance reveals how dense it is in a certain space. The definition of density is the mass of a substance per unit volume.

It is measured in meters per second in the SI (ms -1 ). A body is considered to be accelerating if there is a change in the magnitude or direction of its velocity.

Therefore, The 35m would the Roche limit be for an earth-orbiting body with the same density as iron(8.0g/cm ^3).

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The kinetic energy (KE) of an object is given by the formula:

KE = (1/2) * m * v^2

where m is the mass of the object and v is its velocity.

Plugging in the given values, we get:

KE = (1/2) * 60 kg * (20 m/s)^2

KE = 12,000 joules

Therefore, the kinetic energy of the car is 12,000 joules.

Answer:

750m/s

Explanation:

v = fλ = (1500 Hz)(0.5 m) = 750m/s

Answer:

0.5 m and 1500 Hz divided by 750 m/s equals 750 m/s.

Explanation:

Brainliest pls!

At wavelengths [tex]$644.44 \mathrm{~nm}$[/tex] and[tex]$483.33 \mathrm{~nm}$[/tex], the stars [tex]$\mathrm{A}$[/tex] and B have maximum intensities. temperature of most intense star is 6,502.242K

Temperature of star [tex]$\mathrm{A}$[/tex] is [tex]$\mathrm{TA}[/tex]=4,500 [tex]\mathrm{~K}$.[/tex]

Temperature of star $B$ is TB $=6,000 [tex]\mathrm{~K}$.[/tex]

Wavelength of most intense star is [tex]$\lambda_0=446[/tex]

We have to find wavelengths corresponding to maximum intensity of stars at temperatures [tex]$T \wedge$[/tex]and TB and wavelength of most intense star.

From Wein's law, we have

[tex]$\lambda_{\mathrm{nm}}=\frac{2.90 \times 106}{\mathrm{Tk}_{\mathrm{k}}}$[/tex]

Where [tex]$\lambda_{\mathrm{nm}}$[/tex] is in nanometers and [tex]$\mathrm{T} k$[/tex] is in Kelvin.

For Star A, equation (1) becomes

[tex]$\lambda_{\mathrm{A}}=\frac{2.90 \times 106}{\mathrm{TA}}$[/tex]

Using values in (2), we get

[tex]\lambda_{\mathrm{A}}[/tex] & =[tex]\frac{2.90 \times 106}{4,500 \mathrm{~K}} \\[/tex]& =644.44 [tex]\mathrm{~nm}[/tex]

For Star B equation (1) becomes

[tex]$$\lambda_{\mathrm{B}}=\frac{2.90 \times 106}{\mathrm{Tr}}$$[/tex]

Let the temperature of the most intense star is[tex]$\mathrm{T} 0$.[/tex] Now, equation (1) for most intense star becomes [tex]$\lambda_0=\frac{2.90 \times 106}{T_0}$[/tex]

From above equation, we have

[tex]$\mathrm{T}_0=\frac{2.90 \times 106}{\lambda_0}$[/tex]

Using values in (3), we get

[tex]$$\begin{aligned}\lambda_{\mathrm{B}} & =\frac{2.90 \times 106}{6,000 \mathrm{~K}} \\& =483.33 \mathrm{~nm}\end{aligned}$$[/tex]

Using vales in (4), we get

[tex]\begin{aligned}\mathrm{T}_0 & =\frac{2.90 \times 10_6}{446 \mathrm{~nm}} \\= & 6,502.242 \mathrm{~K}\end{aligned}[/tex]

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If object 1 and 2 attracts each other with an electrostatic force of 18N and is separated by some distance, Then if that distance will be halved then the electrostatic force will be = 18×4=72N.

It states that" The force between two charges is directly proportional to the product of their magnitude and inversely proportional to the square of the distance between the charges and acts along the line joining the two charges."

Mathematically,

F∝q1×q2

F∝1/[tex]r^{2}[/tex]

i.e

F= k [tex]\frac{q1 *q2}{ r^{2} }[/tex]

Where q1, q2= magnitude of the charge in C.

and r = the distance between them in m.

k= constant of proportionality.

Question given data,

F1=18N

let r=x (say)

then F1=18=k [tex]\frac{q1 *q2}{ x^{2} }[/tex].....................(1)

if r is halved i.e r=x/2

now new force

F2=k[tex]\frac{q1 *q2}{ (x/2)^{2} }[/tex]

F2=4×k[tex]\frac{q1 *q2}{ x^{2} }[/tex]

F2=4×F1....................(∵F1=k [tex]\frac{q1 *q2}{ x^{2} }[/tex])

=4×18..............................(∵F1=18)

F2=72N

Hence The force between two charged particles when the distance between them is halved is 72N.

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Answer:

3

Explanation:

Newton's Law of Cooling states that the rate of cooling of an object is proportional to the temperature difference between the object and its surroundings.

dQ/dt = -k(T - Troom)

where Q is the amount of heat in the water, t is time, k is a constant, T is the temperature of the water, and Troom is the room temperature.

Using the given information, we can set up the following system of equations:

100 = k(100 - 21) (at t = 0) 65 = k(100 - 21) e⁽⁻¹⁰⁾k (at t = 10)

Solving for k in the first equation gives k = 1/79. Plugging this value into the second equation and solving for T gives T = 36.1 degrees Celsius.

Now, to find the temperature after an additional 5 minutes, we can use the same equation with a new time value:

T = (65 - Troom) e^(-k(10+5)) + Troom

Plugging in the values we know gives T = 30.4 degrees Celsius.

Therefore, the temperature of the water after an additional 5 minutes of cooling is approximately 30.4 degrees Celsius

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You would see blue-violet hue if you peered throughout a spectroscope and observed light that had a wavelength of 450 nm.

Wavelength or frequency are connected to energy in the same way as they are to light. More energy is correlated with shorter wavelengths and higher frequencies. Hence, lower energy is produced by longer wavelengths and lower frequencies.

By measuring overall distances between two identical locations on adjacent waves, the duration can always be found. For determining the wavelength of a waveguide, the distance from one compress to the next or from one rarefaction to another is measured.

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Sound waves can travel through a medium (such as air, water, or solid objects) and can reflect or diffract around obstacles, allowing them to be heard even when there is no direct path to the source of the sound.

When sound waves encounter an obstacle, they can either reflect or diffract. Reflection occurs when sound waves bounce off a surface and return in the direction they came from. Diffracton occurs when sound waves bend around an obstacle and continue in a different direction. This allows sound waves to travel around corners and through small openings.

For example, if someone is talking behind a wall, the sound waves they produce can diffract around the wall and reach your ears, allowing you to hear them. Similarly, when you hear an echo, it is because sound waves have reflected off a surface and reached your ears.

In some cases, sound waves can even travel through solid objects. This is known as vibration or bone conduction. For example, when you hear your own voice or a piece of music through a set of headphones, the sound waves are transmitted through the headphones and vibrate the bones in your ear, which sends signals to your brain that you perceive as sound.

In summary, sound waves can travel through a medium and reflect or diffract around obstacles, allowing them to be heard even when there is no direct path to the source of the sound.

Answer:

The moon does not have an atmosphere because it does not have enough gravity to hold onto the gases that make up an atmosphere. The moon also does not have plate tectonic activity because it does not have enough internal heat to drive the movement of the plates.

Explanation:

Answer & Explanation:

Friction is useful in the following situations:

The brakes on a bike: Friction is necessary in the brakes of a bike as it allows the brake pads to grip onto the rim or disc, which helps to slow down or stop the bike.

Inside the hub of the wheel on a bike: Friction is necessary to prevent the wheel from spinning too freely, which could lead to loss of control or accidents. The hub's bearings require just the right amount of friction to keep the wheel spinning freely but not too fast.

Friction is a nuisance in the following situation:

The moving parts of the chain and gears: Friction between the moving parts of the chain and gears can cause the bike to lose efficiency and require more effort from the rider. This can cause wear and tear on the bike and make it harder to ride.

Kinship charts, often known as kinship diagrams, show relationships. Similar to a family tree chart or a pedigree chart, you can use a kinship diagram to display your genealogy.

An illustration of relationships in a family, community, or culture is called a kinship diagram. Kinship charts resemble family trees in many ways. Therefore, kinship diagrams are used more broadly to comprehend how most families in a culture function rather than identifying individual names or modeling the diagram after one family.

Kinship diagrams enable cultural anthropologists to swiftly sketch out relationships between people throughout the interview process. Also, it offers a way to represent kinship patterns visually in cultures without the use of names, which can be confusing, and it protects people's privacy.

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Mission control is an exciting career that involves managing space missions from the ground.

Mission control is an exciting career that involves managing space missions from the ground. I chose this career because of my interest in space exploration and the opportunity to contribute to the advancement of space technology.

Some questions that could be asked about this career include:

What qualifications are required to become a mission control specialist?

What kind of training do mission control specialists undergo?

What are the typical responsibilities of a mission control specialist during a space mission?

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Two points in the xy plane have Cartesian coordinates (5.00, −5.50) m and (−7.00, 7.00) m.So,  the distance between two points in the xy-plane is 17.32 m.

What is Distance?

Distance is a measurement in numbers of the area between two locations or objects. It is a scalar quantity that symbolises the distance between two places in space or the length of a path taken by an object. Depending on the situation and the scale of the items being measured, distance can be expressed in a variety of ways, including metres, kilometres, miles, feet, and so forth.

Displacement, a vector number that denotes the shift in an object's location with respect to a reference point, is frequently distinguished from distance in physics. Displacement, as opposed to distance, which only analyses the size of the path travelled, considers both the distance travelled by an object and its direction of motion.

To find the distance between two points in the xy-plane, we use the distance formula:

d = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]

where (x1, y1) and (x2, y2) are the coordinates of the two points.

Using the given coordinates, we have:

x1 = 5.00 m, y1 = -5.50 m

x2 = -7.00 m, y2 = 7.00 m

Substituting these values into the formula, we get:

d = [tex]\sqrt{(-7.00 - 5.00)^2 + (7.00 - (-5.50))^2}[/tex]

d= [tex]\sqrt{(-12.00)^2 + (12.50)^2}[/tex]

d= [tex]\sqrt{(144.00 + 156.25)}[/tex]

d= [tex]\sqrt{(300.25)}[/tex]

d=17.32 m

Therefore, the distance between the two points is approximately:

d = 17.32 m (rounded to two decimal places)

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Answer:

475 J

Explanation:

At the top of the feature, Robert has 475 J of kinetic energy and 2240 J of gravitational potential energy. According to the law of conservation of energy, the total energy of a system is constant, so the sum of the kinetic energy and gravitational potential energy at the top of the feature is equal to the sum of the kinetic energy and gravitational potential energy at the bottom of the feature.

Since Robert is at the bottom of the feature, he has lost all of his gravitational potential energy. Therefore, the total energy he has at the bottom of the feature is equal to his kinetic energy at the top of the feature:

Total energy = Kinetic energy at top = 475 J

Therefore, the answer is 475 J, which is option D.

Answer:

h(t) = -16t^2 + 1000

Explanation:

The quadratic function that represents the motion of a freely falling ballast bag that starts from a resting position on a balloon 1000 feet above the ground is given by the equation h(t) = -16t^2 + 1000, where h(t) is the height of the ballast bag in feet at time t seconds after it is released, and -16t^2 represents the effect of gravity on the ballast bag as it falls.

Answer:

-16t^2 + 1000

Explanation:

The change in momentum of the ball is 1.0 kg m/s [E].

The change in momentum of the ball can be calculated using the formula:

Δp = p₂ - p₁

where Δp is the change in momentum, p₂ is the final momentum, and p₁ is the initial momentum.

The momentum of an object is defined as the product of its mass and velocity, so we can calculate the initial and final momenta of the ball as follows:

p₁ = m₁v₁ = (0.1 kg)(5 m/s [W]) = -0.5 kg m/s

p₂ = m₁v₂ = (0.1 kg)(5 m/s [E]) = 0.5 kg m/s

Substituting these values into the formula for Δp, we get:

Δp = p₂ - p₁ = (0.5 kg m/s) - (-0.5 kg m/s) = 1.0 kg m/s [E]

Therefore, the change in momentum of the ball is 1.0 kg m/s [E] using Δp = p₂ - p₁.

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The initial rotational kinetic energy of the yo-yo is equal to ½ × 3.5 ×10-5 kg×m2 ×(0.70m/ 0.008m)2 = 0.000912 Joules.

Kinetic energy is the energy of motion. It is the energy an object has due to its motion. Kinetic energy can be calculated by multiplying the mass of an object with the square of its velocity. Kinetic energy is a form of energy that is associated with the movement of objects. It is released when objects collide or when objects are deformed. Kinetic energy can also be converted into other forms of energy, such as thermal energy, sound energy and electrical energy.

The initial gravitational potential energy of the yo-yo is equal to the change in height multiplied by the weight of the yo-yo. The weight of the yo-yo can be calculated using the equation W = m × g, where m is the mass and g is the acceleration due to gravity. Therefore, the initial gravitational potential energy of the yo-yo is equal to 0.05 kg ×9.8 m/s2 ×0.70 m = 0.343 Joules.

b. Calculate the initial rotational kinetic energy of the yo-yo.

The initial rotational kinetic energy of the yo-yo is equal to ½Iω2, where I is the rotational inertia and ω is the angular velocity. The angular velocity can be calculated using the equation ω = v/r, where v is the linear velocity and r is the radius of the yo-yo. Therefore, the initial rotational kinetic energy of the yo-yo is equal to ½ × 3.5 ×10-5 kg×m2 ×(0.70m/ 0.008m)2 = 0.000912 Joules.

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Answer:

2025 J

Explanation:

The work done by gravity on Logan can be calculated using the formula W = mgh, where W is the work done by gravity, m is the mass of Logan, g is the acceleration due to gravity and h is the change in height.

First we need to calculate the change in height. The initial height of Logan can be calculated using trigonometry. The vertical component of the rope length when it makes a 30 degree angle with the vertical is 4.10m * cos(30) = 3.55m.

Similarly, when Logan releases the rope at an angle of 13.1 degrees with the perpendicular (or 90-13.1=76.9 degrees with the vertical), his height above water level will be 4.10m * cos(76.9) = 0.93m.

So his change in height will be 3.55m - 0.93m = 2.62m.

Now we can calculate how much work gravity does on him: W = mgh = (79kg)(9.8 m/s^2)(2.62m) ≈ 2025 J.

So gravity does about 2025 J of work on Logan up to the point where he releases the rope.

Explanation:

When you exercise the muscles in your body must contract, in order to do that they need oxygen, glucose, a molecule called ATP, and amino acids. As your muscles use these compounds and contract themselves, they will create waste products like carbon dioxide, and lactic acid that must be carried away from the muscles. When exercising many muscles will all require nutrients and elimination of waste products constantly at the same time. To meet this demand the heart must rapidly increase the rate at which it beats and pushes blood through the body. This is why the heart beats significantly faster during exercise.

The bike is going at a speed of 7.76 m/s (or about 28 km/h) while you are pushing it with a force of 190 N over a distance of 2.0 m.

We can use the work-energy principle to determine the final velocity of the bike. The work-energy principle states that the net work done on an object is equal to its change in kinetic energy. In this case, the net work is done by the force that you apply to the bike over a distance of 2.0 m:

Net work = force x distance x cos(theta) = 190 N x 2.0 m x cos(0) = 380 J

The change in kinetic energy of the bike is given by:

[tex]Delta K = 1/2 mv^2 - 0[/tex]

where m is the mass of the bike and v is its final velocity.

Setting the net work equal to the change in kinetic energy, we have:

[tex]380 J = 1/2 (22 kg) v^2[/tex]

Solving for v, we get:

[tex]v = sqrt(2 x 380 J / 22 kg) = 7.76 m/s[/tex]

Therefore, the bike is going at a speed of 7.76 m/s (or about 28 km/h) while you are pushing it with a force of 190 N over a distance of 2.0 m.

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Self-care can be demonstrated in a healthy way by recalling a happy memory.

The first step toward self-care is allowing yourself to be honest and vulnerable. Through self-reflection, you can at last let out all that you've been keeping down. Your journal is your very own private platform on which you can record your successes, anxieties, and worries.

Taking care of oneself exercises can go from proactive tasks, for example, practicing and practicing good eating habits, to mental exercises like perusing a book or rehearsing care, to otherworldly or social exercises, for example, imploring or getting lunch with a companion.

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The terminal velocity of the block is approximately 2.08 m/s when it is traveling downward with a drag coefficient of 0.822.

How to calculate terminal velocity?

To calculate the terminal velocity of the block, we need to use the equation for terminal velocity which is:

v_terminal = sqrt((2mg)/(ρAC_d))

where:

First, let's convert the dimensions of the block from centimeters to meters:

width = 16.0 cm = 0.16 m

length = 19.0 cm = 0.19 m

height = 25.0 cm = 0.25 m

Next, let's calculate the cross-sectional area of the block:

A = width * length = 0.16 m * 0.19 m = 0.0304 m^2

Now we can substitute the values into the equation for terminal velocity:

v_terminal = sqrt((24.55 kg9.81 m/s^2)/(1.43 kg/m^30.0304 m^20.822))

v_terminal = 2.08 m/s

Therefore, the terminal velocity of the block is approximately 2.08 m/s when it is traveling downward with a drag coefficient of 0.822.

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The modern and old cars are fantastic. But however they are different from one another. The vintage cars cannot compete with today's cars. The car engines are significantly advanced over the years.

The deceleration refers to the acceleration in the direction opposite to the direction of the velocity. It always reduces the speed of the objects. The slowing down of a bike in a traffic is an example of deceleration.

The modern cars have smaller deceleration, because the engines in today's cars are more powerful and reliable. They provide greater safety, stability and efficiency. The fuel tank in the modern cars are also greater than the old cars.

Thus the Passengers experience a much smaller deceleration in modern cars.

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Explanation:

E1 = k Q1 / (0.075 m)^2

= 9 x 10^9 Nm^2/C^2 * 10 x 10^-9 C / 0.075^2 m^2

= 400 N/C

E2 = k Q2 / (0.075 m)^2

= 9 x 10^9 Nm^2/C^2 * (-3 x 10^-9 C) / 0.075^2 m^2

= -120 N/C

Since the electric fields due to the two charges are in opposite directions, we can find the net electric field at the midway point by taking the difference between the two:

E = E1 - E2

= 400 N/C - (-120 N/C)

= 520 N/C

Answer:

To calculate the work being done by Sally, we need to use the formula:

Work = Force x Distance x cos(theta)

where:

Force = 10 N (the force required to lift the paintbrush)

Distance = 10 m (the distance Sally lifts the paintbrush)

theta = 0 degrees (since Sally is lifting the paintbrush straight up, the angle between the force and the direction of motion is 0 degrees)

So, the work done by Sally is:

Work = 10 N x 10 m x cos(0)

Work = 100 joules

Therefore, the joules of work being put out by Sally when she lifts the 10 N paintbrush at a distance of 10 meters is 100 joules.

Explanation: