how high is a tree that cast a 23ft shadow at the same time

a 9ft post casts a shadow which is 11ft long ​

Answers

Answer 1

Answer:

tree is about 18.82 ft high

Step-by-step explanation:

The triangles (that are formed by the tree and the poll with their shadows and the line from top to the end of the shadow) are in proportion because they cast the shadow at the same time.

x/9 = 23/11 , we write the proportions

x = 23*9 / 11, multiply both sides by 9

x ≈ 18.82 ft.

How High Is A Tree That Cast A 23ft Shadow At The Same Time A 9ft Post Casts A Shadow Which Is 11ft Long

Related Questions

PLZ HELP ME I NEED HELP PLZZZ!!!!!
Select all that apply.

Given the points (-6, 8) and (-3, 4), which of the following are true about the line passing through these points?

The line represents a direct variation function.
The line has a slope of -3/4 .
The point (9, -12) is also on the line.
The line has a slope of 3/4 .

Answers

Answer:

the point (9,-12) is also on the line

Step-by-step explanation:

by using the 2 points the equation is y=-4/3x

use x of 9

y = -12

it will also represent a direct variation function

so two of the 4 will be correct

Answer:

The point (9,-12) is also on the line

Step-by-step explanation:

Please give brainliest

4. In a class of 35 students, 20 offer Physics,
18 offer Chemistry and 2 offer neither
Physics nor Chemistry
1) Illustrate the information on a Venn
diagram
il) How many students offer all the two
subjects?
1) How many students offer Physics!
1) How many students offer only one
subject

Answers

5 students offers all the two subjects.

Student that offers Physic only = 15 students

Student that offers chemistry only  = 13 students

Students that offers only one subject = 28 students

How to solve a Venn diagram?

Total student in the class = 35

20 offer physics.

18 offer chemistry

2 offer neither physics nor chemistry.

Therefore,

x = student that offer both subject

35 = 20 + 18 - x + 2

35 - 2 - 20 - 18 = -x

-5 = -x

x = 5

Therefore, 5 students offers all the two subjects.

Student that offers Physic only = 20 - 5 = 15

Student that offers chemistry only = 18 - 5 = 13

Students that offers only one subject = 13 + 15 = 28

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Danny got a raise and now makes $58,965.95 a year. Round this number to the
nearest:
a) dollar
b) thousand dollars
c) ten thousand dollars

Answers

Answer:

c) ten thousand dollars

Step-by-step explanation:

Can anyone help? Most brainiest for the correct answer!!

Answers

Answer:  25

Explanation:

The "large cars" pie slice takes up 7% of a full circle. This means that the degree measure of this slice takes up 7% of a full 360 revolution.

7% of 360 = 0.07*360 = 25.2 degrees

This then rounds to 25 degrees

25

If you like, I can put on the solution.

Find the AREA of the shape​

Answers

Step-by-step explanation:

LxB

8x7

equals :56

Area equals to 56cm

in a class of 80 students in Debre Berhan university,45 good in mathematics,15 are good in both Mathematics and English,13 are good in both Mathematics and Psychology, 16 are good in both in English and psychology,20 are good in Psychology and 9 are good in both of the three courses A,how many students are good in mathematics only? B,how many students are not good in any of three courses?

Answers

The relationship between the number of students that are good at a given subject is an illustration of sets.

26 students are good at Mathematics only.28 students are not good at all.

We use the following representations:

[tex]M \to[/tex] Mathematics

[tex]E \to[/tex] English

[tex]P \to[/tex] Psychology

From the question, we have the following parameters

[tex]M = 45[/tex] -- Mathematics

[tex]M\ n\ E =15[/tex] -- Mathematics and English

[tex]M\ n\ P =13[/tex] -- Mathematics and Psychology

[tex]E\ n\ P =16[/tex] -- English and Psychology

[tex]P=20[/tex] -- Psychology

[tex]All = 9[/tex] -- All 3 subjects

[tex]Total = 80[/tex] -- All students

The number of students that are good at mathematics only is as follows:

First, we calculate those that are good at mathematics and English only

[tex](M\ n\ E)' = M\ n\ E - All[/tex]

[tex](M\ n\ E)' = 15 - 9 = 6[/tex]

Then those that are good at mathematics and psychology only

[tex](M\ n\ P)' = M\ n\ P - All[/tex]

[tex](M\ n\ P)' = 13 - 9 = 4[/tex]

So, the students that are good at mathematics only are:

[tex]M' = M - (M\ n\ E)' -(M\ n\ P)' - All[/tex]

[tex]M' = 45 - 6 -4 -9[/tex]

[tex]M' = 26[/tex]

Hence, 26 students are good at Mathematics only.

To calculate the number of students that are not good in any of the subjects, we make use of the complement rule

[tex]A + A' = Total[/tex]

Where:

[tex]A \to[/tex] Students that are not good in any

[tex]A' \to[/tex] Students that are good in at least one

So, we have:

[tex]A' =M' + (M\ n\ E)' + (M\ n\ P)' + (E\ n\ P)' + All[/tex]

Where:

[tex](E\ n\ P) = (E\ n\ P)' - All[/tex]

[tex](E\ n\ P) = 16-9 = 7[/tex]

The equation becomes:

[tex]A' =26 + 6 + 4+7+9[/tex]

[tex]A' =52[/tex]

Recall that:

[tex]A + A' = Total[/tex]

[tex]A = Total - A'[/tex]

[tex]A = 80 - 52[/tex]

[tex]A = 28[/tex]

Hence, 28 students are not good at all.

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I need some help with the homework problem. I have a list of formulas, but can't seem to get it done.

[tex]\int\frac{9}{\sqrt{1+e^{2x}}} \, dx[/tex]

I started by taking the constant out and setting u = [tex]\sqrt{1+e^{2x\\}}[/tex]
After this I can't seem to progress.

Answers

After setting [tex]u=\sqrt{1+e^{2x}}[/tex], partially solving for x in terms of u gives

[tex]u = sqrt{1+e^{2x}} \implies u^2 = 1 + e^{2x} \implies e^{2x} = u^2 - 1[/tex]

Then taking differentials, you get

[tex]2 e^{2x} \,\mathrm dx = 2u \, \mathrm du \implies \mathrm dx = \dfrac{u}{u^2-1}\,\mathrm du[/tex]

Replacing everything in the original integral then gives

[tex]\displaystyle \int \frac9{\sqrt{1+e^{2x}}}\,\mathrm dx = \int \frac9u \times \frac u{u^2-1}\,\mathrm du = 9 \int \frac{\mathrm du}{u^2-1}[/tex]

Split up the integrand into partial fractions:

[tex]\dfrac1{u^2-1} = \dfrac a{u-1} + \dfrac b{u+1} \\\\ 1 = a(u+1) + b(u-1) = (a+b)u + a-b \\\\ \implies \begin{cases}a+b=0\\a-b=1\end{cases} \implies a=\dfrac12,b=-\dfrac12[/tex]

so that

[tex]\displaystyle 9 \int \frac{\mathrm du}{u^2-1} = \frac92 \int \left(\frac1{u-1} - \frac1{u+1}\right) \,\mathrm du \\\\ = \frac92 \left(\ln|u-1| - \ln|u+1|\right) + C \\\\ = \frac92 \ln\left|\frac{u-1}{u+1}\right| + C \\\\ = \frac92 \ln\left(\frac{\sqrt{1+e^{2x}}-1}{\sqrt{1+e^{2x}}+1}\right) + C[/tex]

Jace recorded the grade-level and instrument of everyone in the middle school School of Rock below.
Seventh Grade Students
Instrument # of Students
Guitar 11
Bass 14
Drums 11
Keyboard 14
Eighth Grade Students
Instrument # of Students
Guitar 13
Bass 13
Drums 8
Keyboard 3

Based on these results, express the probability that a seventh grader chosen at random will play an instrument other than bass as a percent to the nearest whole number.

Answers

The probability that a seventh grader chosen at random will play an instrument other than bass is 72%.

Homework pikcuts
Pleas

Answers

Answer:

[tex] \frac{12 - 23 \sqrt{2} }{46} [/tex]

Step-by-step explanation:

you find the LCM

I|I is an integer between 11 and 17

Answers

Yes, there is. It's 14. Hope this helps.

2. 3.6 x 5.5? Explain your answer. (Make sure you include how you knew where to
place the decimal point.)

Answers

Answer:

19.80 or 19.8

Step-by-step explanation:

When multiplying decimal numbers we forget the decimal points and multiply normally; like, 3.6 x 5.5 = 1980, then we count how many decimal numbers(numbers after the decimal point) there are in the factors(In 3.6 we have the decimal number 6. And in 5.5 we have the decimal number 5 ). So here we have 2 decimal numbers resulting in our answer being, 19.80 or 19.8 since the 0 is unnecessary.

Let A={5,8}, B={p,q}, C={r,v} How many elements are in A×B?

Answers

There are 4 elements in the set A* B

How to determine the number of elements in A * B?

The sets are given as:

A={5,8}

B={p,q}

C={r,v}

The expression A * B implies that:

A * B = n(A) * n(B)

Where n( ) implies that the number of elements in......

So, we have

A * B = 2 * 2

This is so because sets A and B have 2 elements each

Evaluate the product

A * B = 4

Hence, there are 4 elements in the set A* B

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8th grade math
5. What is the probability of rolling a 3 on a 6-sided number cube and then NOT rolling 2 or 4 on a 6-sided number cube?

Answers

Answer:

5 in 12 chance or 42% probability of happening

Probably of rolling 3 is 1/6
Probably not rolling 2 or 4 is 4/6
Independent event so:
P(a)*P(b)= 1/6*4/6 = 4/36 =0.111

Please give this in steps

Answers

Answer:

(x - y)²

Step-by-step explanation:

Given

(x + y)² - 4xy

= x² + 2xy + y² - 4xy

= x² - 2xy + y²

= (x - y)²

Answer:

[tex] {(x + y)}^{2} - 4xy = {x}^{2} + 2xy + {y}^{2} - 4xy \\ = {x}^{2} - 2xy + {y}^{2} \\ = {(x - y)}^{2} \\ thank \: you[/tex]

Hours worked in a week - 32; Total Pay - $160.00; What is the hourly rate?

Answers

Answer:

$5

Step-by-step explanation:

Number of hours worked = 32

Total pay = $160

So, hourly rate

= Total pay/number of hours worked

= $160/32

= $5

A room has to be painted and worker A does 1/3 of the work then leaves. Next worker B does 1/4 of the remaining work and then leaves and finally worker C does 1/5 of the remaining work and then leaves.
What fraction of the room still needs to be painted?
a)3/5
b)2/5
c)13/60
d)7/15

Answers

The Answer is C 13/60
S O L U T I O N :

Here, we are given that a room is painted by A, B and C so here three of them have done the work. So, we'll add all these fractions and assume the total work as 1 after that we will substract all the added ones from 1

Let us assume the room completely painted be 1

Now,

A has done 1/3, B has done 1/4 and C has done 1/5 work of the remaining

So, let us add them

A + B + C

⅓ + ¼ + ⅕

Getting the L.C.M. The L.C.M of 3,4,5 is 60

20/60 + 15/60 + 12/60

47/60

Hence, 47/60 room has been painted

Remaining to paint

Total is assumed as 1

Work done = 47/60

Fraction of room needs to painted = 1 - 47/60

(60 - 47)/60

13/60

13/60 of the room needs to be painted, OPTION C IS CORRECT

PLZ HELP ASAP I NEED PLZZZ!!!!!!
Fill in the blank with the correct response. The slope of the graph of y = -2/3x is __.

Answers

Answer:

Solution given:

Equation of line is:

y=-⅔x

comparing above equation with

y=mx+c

we get

m=-⅔

So

slope is -⅔

Answer:

slope is -2/3

Step-by-step explanation:

I. It's linear equation

    y = mx + b

when y is output, x is input, m is slope and b is addition.

The statment above is y = -2/3x + 0

So -2/3 is slope or m.value

Hope that help :D

The cube of an integer is called a __________ ?

Answers

Answer:

a perfect cube

Step-by-step explanation:

Answer:

It is called a perfect cube .

Step-by-step explanation:

1. If a = -1 , the value of3a + 1 is ​

Answers

Answer:

[tex]f(a) = 3a + 1 \\ Now,\: a = - 1 \\ f( - 1) = 3( - 1) + 1 \\ f( - 1) = - 3 + 1 \\ \boxed{ f( - 1) = - 2}[/tex]

Therefore, -2 is the right answer.

SOMER HELP ON GIS ONEEEE

Answers

Answer:

2 one

Step-by-step explanation:

well if u go the other way for it to go right it is mf

It is the 2nd one to the right mf

Two cylinders are similar the volume of one is 27cm^3 the volume of the other cylinder is 1331cm^3 what is the scale factor between them

Answers

Answer:

scale factor = 3 : 11

Step-by-step explanation:

Given 2 similar figures with scale factor a : b , then

ratio of volumes = a³ : b³

Here

ratio of volumes = 27 : 1331 . so

scale factor = [tex]\sqrt[3]{27}[/tex] : [tex]\sqrt[3]{1331}[/tex] = 3 : 11

Answer:

3:11

Step-by-step explanation:

NJ Transit raises its train fees. Snooki wants to visit her parents which used to cost $28 but they increased the fares by 15%. What will the ticket cost now?

Answers

Answer: 32.20$ Train Fee

Step-by-step explanation:

15% of 28 is 4.20... 4.20 will be added to the current Train Fee

   28.00$

 +   4.20$

    32.20$

Final result: The Train Fee will be 32.20$

X¹² - 1 แยกตัวประกอบของพหูนาม

Answers

Answer:

[tex]\left(x^2+1\right)\left(x+1\right)\left(x-1\right)\left(x^2+x+1\right)\left(x^2-x+1\right)\left(x^4-x^2+1\right)[/tex]

Step-by-step explanation:

Factor of [tex]x^{12}-1[/tex] is

[tex]\left(x^2+1\right)\left(x+1\right)\left(x-1\right)\left(x^2+x+1\right)\left(x^2-x+1\right)\left(x^4-x^2+1\right)[/tex]

Q16. If the perimeter of a rectangular house is 25 1/3 yards, and the length is 22 feet. What is the
width?
16 feet
O 35 feet
O 37 feet
0 40 feet
42 feet

Answers

Answer:

OPTION A :16 FEET

PERIMETER =26 1/3=76/3yard=76/3×3=76 feet

LENGTH=22feet

Width=76/2-22

WIDTH=38-22=16 FEET

(5pg)3=125pg. Is wrong or correct

Answers

Answer:

125 p^3 g^3

Step-by-step explanation:

(5pg)^3

We know that (ab)^c = a^c * b^c

5^3 p^3 g^3

125 p^3 g^3

If X= 9 and Y = 3, what is XY

Answers

Answer:

The most basic question I have ever seen lol

XY = 9*3 = 27

It is 27

XY means X*Y
3*9=27

In a mathematics class , half of the students scored 84 on an achievement test. With the exception of a few students who scored 50 , the remaining students scored 76. Which of the following statements is true about the distribution of scores ?


A. The mean is greater than the mode.
B. The mean and the median are the same.
C. The mean is less than the median.
D. The mean is greater than the median.

Answers

Answer: B. The mean is less than the median

Step-by-step explanation:

there are some that scored 51 which means - mean<median

Find - 36
.
Ο +6
-6

Ο 18

Answers

Answer:

+or-6

Step-by-step explanation:

This is a trick question. The answer would be the first choice since you're multiplying -6 by +or-6, meaning that it could still end up as a negative or a positive.

Answer:

Step-by-step explanation:

a person runs at a constant speed of 9.2 miles per hour for 6 minutes and 30 seconds. How far did they travel in yards.

Answers

Given:

Speed[tex]= \bold{9.2 \ \frac{miles}{hour}}[/tex]  

[tex]\therefore \\\\[/tex]

1-hour= 60 minutes

1-minutes=60 second

So

1-hour= 3600 second

Converting the given time into seconds:

Time= 6 minutes and 30 second

       [tex]=\bold{6\times 60 \ second + 30 \ second }\\\\=\bold{360\ second+30\ second}\\\\=\bold{390\ second}\\\\[/tex]

When 3600 seconds covers=9.2 miles

Then equation:

[tex]=\bold{\frac{9.2}{3600}}\\\\[/tex]

390 seconds covers:

[tex]=\bold{\frac{9.2}{3600}\times 390 \ miles} \\\\[/tex]  

Let

[tex]\bold{1 \ miles= 1760\ yard}\\\\[/tex]

Convert the traveling value into yards:

[tex]=\bold{ \frac{9.2}{3600}\times 390\times 1760}\\\\=\bold{ \frac{9.2}{36}\times 39\times 176}\\\\=\bold{ \frac{9.2}{12}\times 13\times 176}\\\\=\bold{ \frac{9.2}{12}\times 2288}\\\\=\bold{ 9.2\times 190.66}\\\\=\bold{ 1754.072\ yards}\\\\[/tex]

Therefore, total traveling yards are"1754.072".  

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Speed of the person has been given as 9.2 miles per hour.

Therefore, speed of the person in miles per minute = [tex]\frac{9.2}{60}[/tex]

Duration for which the person is running = 6 minutes and 30 seconds

                                                                    = 6 minutes and [tex]\frac{30}{60}[/tex] minutes

                                                                    = 6.5 minutes

Since, Distance = Speed × Time

By substituting the values in the expression we can get the distance traveled.

Distance = [tex]\frac{9.2}{60}\times 6.5[/tex]

               = 0.9967 miles

Since, 1 mile = 1760 yards

Therefore, 0.99667 miles = 1760 × 0.99667

                                           = 1754.13 yards

Total distance traveled by the person is 1754.13 yards.

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A total of 574 tickets were sold for the school play. They were either adult tickets or student tickets. There were 74 more student tickets sold than adult tickets. How many adult tickets were sold?

411 is not correct

Answers

The answer is: 250 adult tickets were sold.

To be safe, prove that your answer is correct.

If there are 74 more student tickets than adult tickets, the amount of adult tickets must obviously be less.

Explanation:

74 more than 250, or 250+74 is 324.

250+324=574.

Now, you know the answer is correct. It satisfies all of the given conditions.

Also, note that the difference between the number of student tickets and adult tickets is 74.

So, there are 250 adult tickets and 324 student tickets.

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