How far up a wall will a 25 ft ladder reach if the base of the ladder is 7 feet from the wall?

Answers

Answer 1

The height formed by this 25-foot ladder that leans against a wall is 24 feet.

To find out how far up a wall a ladder will reach, you can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In this case, the ladder forms one side of the triangle, the wall forms another side, and the distance between the base of the ladder and the wall forms the hypotenuse.

Let's call the height of the wall h. Using the Pythagorean theorem, we can set up the following equation:

(25 ft)^2 = h^2 + (7 ft)^2

625 = h^2 + 49

576 = h^2

h = sqrt(576) = 24 ft

Therefore, a 25 ft ladder that is 7 feet from the wall will reach 24 feet up the wall.

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Related Questions

Electric potential energy can be maximized when

Answers

Answer:

d and f

Explanation:

According to table 1, which of the following materials is the poorest electrical conductor?
(A) Copper
(B) Aluminum
(C) Graphite
(D) Brass

Answers

Graphite: according to table 1, which of the following materials is the poorest electrical conductor.

What is conductor?

Conductor is an electrical device or material that is capable of allowing electric current to flow through it. It is used in a variety of applications ranging from wiring in buildings to the transmission of electricity over large distances.

Conductors are typically made from metals, such as copper and aluminum, but certain types of materials, such as semiconductors, can also act as conductors.

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A man is standing on the shore of a beach, up to his knees in water. Every second two waves hit him. What is the frequency of the wave?

Answers

Answer:

f = 2 Hz

Explanation:

The frequency of a wave is defined as the no. of waves passing per unit of time. Therefore, the frequency of a wave can be calculated by the following formula:

[tex]f = \frac{n}{t}[/tex]

where,

f = frequency of the wave = ?

t = time passed = 1 s

n = no. of waves passing in time t = 2

Therefore,

[tex]f = \frac{2}{1\ s}[/tex]

f = 2 Hz

A camera draws 0. 25 amps and with 72 ohms. What voltage supply does this camera need?​

Answers

A camera that draws certain current with specified resistance needs a voltage supply which is calculated to be 18 V.

Given that,

Current i = 0.25 A

Resistance r = 72 ohms

Voltage supply v = ?

From Ohm's law, it is defined that, voltage across the conductor is directly proportional to the current flowing through it. Mathematically, it is represented as v = i r

where,

v is the voltage

i is the current

r is the resistance

Putting in the values, we have,

v = i r

v = 0.25 × 72 = 18 V

Thus, the required voltage supply by the camera is calculated to be 18 V.

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Which statement best describes what waves are? 1. Wavy lines on graph paper | 2. Circles that move out from a central place | 3. Disturbances that transfer energy | 4. Light energy that changes particles of matter

Answers

3. Disturbances that transfer energy

A coil of wire with a current is called a(n)
a.
insulator.
b.
solenoid.
c.
electromagnet.
d.
galvanometer.

Answers

Answer:

Hello There!!

Explanation:

The answer is b. solenoid.

Mechanics sometimes use a piece of pipe to lengthen the handle of a wrench when trying to remove a very tight bolt. How does this make it easier for the mechanic to remove the bolt

Answers

Answer:

increase the length of the handle from the bolt, the torque will increase even if you have the same force

Explanation:

It allows them to apply more torque to the bolt. Torque is the turning or twisting force that causes rotation, in this case, it's applied to the bolt in an effort to loosen it. By lengthening the handle of the wrench, the mechanic is able to leverage more of their body weight and strength behind the wrench, increasing the torque they are able to apply to the bolt.

When a bolt is very tight, it can be difficult to turn it with a standard wrench. The increased torque provided by the longer handle allows the mechanic to apply more force to the bolt, which can help to loosen it. This can be particularly useful in situations where the bolt is corroded, rusted, or otherwise stuck due to a buildup of debris or other factors.

A flashlight bulb is connected to two dry cells with an equivalent voltage of 4.50 V. If the bulb draws a current of 12.0 mA (1000mA = 1A), its resistance is (2 points) a 540. Ohms b 375 Ohms c 266 Ohms d 2.66 Ohms e 145 Ohms

Answers

Answer:

b. 375 Ohms

Explanation:

Given the following data;

Voltage = 4.5 V

Current = 12 mA

To find the resistance;

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

[tex] V = IR[/tex]

Where;

V represents voltage measured in voltage. I represents current measured in amperes. R represents resistance measured in ohms.

Conversion:

1000 mA = 1 A

12 mA = 12/1000 = 0.012 A

[tex] R = \frac {V}{I} [/tex]

Substituting into the formula, we have;

[tex] R = \frac {4.5}{0.012} [/tex]  

Resistance, R = 375 ohms

please help me and give an explanation

Answers

Explanation:

The moon orbits the Earth once every 27.322 days. It also takes approximately 27 days for the moon to rotate once on its axis. As a result, the moon does not seem to be spinning but appears to observers from Earth to be keeping almost perfectly still. Scientists call this synchronous rotation

A mass of 1.5 kg moves in a circle of radius 25 cm at 2.0 Hz. Calculate:
a) the velocity. b) the acceleration. c) the centripetal force acting on the mass.

Answers

Answer:

To solve this problem, you can use the following formulas:

Velocity (v) = 2πr * f

Acceleration (a) = v^2 / r

Centripetal force (F) = ma

In these formulas, r is the radius of the circle, f is the frequency of the circular motion, and m is the mass of the object.

a) To find the velocity of the mass, you can substitute the values given into the formula for velocity:

v = 2πr * f

= 2π(0.25 m) * 2.0 Hz

= 1.57 m/s

So, the velocity of the mass is approximately 1.57 m/s.

b) To find the acceleration of the mass, you can substitute the values given into the formula for acceleration:

a = v^2 / r

= (1.57 m/s)^2 / 0.25 m

= 4.45 m/s^2

So, the acceleration of the mass is approximately 4.45 m/s^2.

c) To find the centripetal force acting on the mass, you can substitute the values given into the formula for centripetal force:

F = ma

= 1.5 kg * 4.45 m/s^2

= 6.68 N

So, the centripetal force acting on the mass is approximately 6.68 newtons.

great players like LeBron James and Michael Jordan, due to their muscular bodies and athletic talent, defy against the law of physics true or false

Answers

The given statement is false. Due of their athleticism and muscular bodies, exceptional athletes like LeBron James or Michael Jordan transcend the laws of physics.

What is law of physics ?

Laws of Physics are by their very nature statements of facts that have been inferred and developed from empirical data. Simply said, physical laws are a technique of categorizing how the world behaves when it comes to "functioning."

What is force?

When an object interacts with another object, it experiences a push or pull known as a force. Every time two objects come into contact, a force is applied to each one of them.  Actual forces can only be created by interaction.

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A ____ exerted by an object on another is a force​

Answers

Answer:

A gravitational force exerted by an object on another is a force.

Explanation:

hope it helps

A gravitational force

Help me with these questions please asap

Answers

the answer for question 22 is C
im not 100% sure about the rest tho

A RL circuit is driven by an AC generator as shown in the figure. sin(ot) The voltages across the resistor and generator are ??.
O always out of phase O always in phase sometimes in phase and O sometimes out of phase Submit

Answers

Sometimes in phase and sometimes out of phase.The voltage across the resistor and generator will depend on the phase difference between the current and voltage in the circuit.

The voltage across the resistor and generator will depend on the phase difference between the current and voltage in the circuit. If the phase difference is 0°, then the voltage across the resistor and generator will be in phase. If the phase difference is 180°, then the voltage across the resistor and generator will be out of phase. In any other scenario, the voltage across the resistor and generator will be somewhere in between in phase and out of phase.

Sometimes in phase and sometimes out of phase.

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Q. Diagram shows a sound wave as being displayed on an oscilloscope screen. Draw the waveform of another sound wave on the same diagram which has twice the pitch and is half as loud.

Answers

Answer:

i want points

Explanation:

difference between reflection of sound, echo and reverberation

Answers

Reflection of sound is the bouncing of sound waves off a surface. Echo is the repetition of sound due to reflection of sound waves off a surface. Reverberation is the persistence of sound in a particular space after the original sound has stopped.

Hope that helps!


The half life of a radioactive substance is the time taken for the activity to halve. Use the graph to calculate the half life of the radioactive isotope.

Answers

Radioactive element  which keeps on decaying over the time. Decay of radioactive element always comes under first order kinetics. Therefore the half life time of  radioactive substance is 2seconds.

What is half life?

Half life tells about the time at which the radioactive material decays to half of its initial concentration.

Mathematically,

half life time=0.693/  rate constant of the decay

The half life of a radioactive substance is the time taken for the activity to halve. Using the graph to calculate the half life of the radioactive isotope, we find that activity that is 3500 so, half of this activity is 17500 which is corresponding to time 2 seconds.

Therefore the half life time of  radioactive substance is 2seconds.

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A car drives up a straight hill at a constant speed of 50 kilometers per hour. A truck drives over the crest of the hill at a constant speed of 50 miles per hour. What is the net force on the car and on the truck

Answers

As a result, the net pressures on the automobile and truck are zero.

what is pressure ?

If you tried to smash a bowling pin into the wall, nothing would happen except that people would stop lending you bowling pins. If you used the same force to hammer a nail, the nail would be far more likely to pierce the wall. This demonstrates that knowing the quantity of the force isn't always enough: you also need to know how that force is distributed over the impact surface. The nail condensed all of the power between the wall and the nail into a relatively tiny region on the pointed tip of the nail. However, because the area of the bowling pin that touched the wall was significantly bigger, the force was much less focused.

Newton's Second Law states that the net Force acting on an object is given by

MA Fnet = MA

The acceleration is given by the ratio of the change in velocity of an object and the time it takes to change velocity.

(Vf - Vi)/T = a

If the vehicles are driving at constant speeds, their velocity change is zero (0).

If the velocity change is zero, the acceleration is also zero (0).

As a result, Fnet = M(0) = 0.

As a result, the net pressures on the automobile and truck are zero.

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the first artificial satellite to orbit the earth was sputnik 1, launched october 4, 1957. the mass of sputnik 1 was 83.5 kg, and its distances from the center of the earth at apogee and perigee were 7300 km and 6610 km, respectively. find the difference in gravitational potential energy for sputnik 1 as it moved from apogee to perigee

Answers

The difference in gravitational potential energy for sputnik 1 as it moved from apogee to perigee is 193 kJ.

The gravitational potential energy of an object in orbit around the Earth can be calculated using the equation:

U = -GMm/r

where U is the gravitational potential energy, G is the gravitational constant, M is the mass of the Earth, m is the mass of the object.

The difference in gravitational potential energy as the satellite moves from apogee to perigee can be found by calculating the potential energy at each point and subtracting the two values:

U(apogee) = -(6.67 x 10^-11 N*(m^2)/(kg^2)) * (5.972 x 10^24 kg) * (83.5 kg) / (7300 x 10^3 m)

U(perigee) = -(6.67 x 10^-11 N*(m^2)/(kg^2)) * (5.972 x 10^24 kg) * (83.5 kg) / (6610 x 10^3 m)

U(apogee) = -1.865 x 10^5 J

U(perigee) = -2.058 x 10^5 J

The difference in gravitational potential energy is:

= U(perigee) - U(apogee)

= -2.058 x 10^5 J - (-1.865 x 10^5 J)

= 193 x 10^3 J

So, the difference in gravitational potential energy for Sputnik 1 as it moved from apogee to perigee is 193 kJ.

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a girl who has a mass of 45kg slides down a slide that is inclined at an angle of 45° with the horizontal if the coefficient of kinetic friction between the girl and the slide is 0.25 what is the magnitude of her acceleration?

Plz if Somone can write the steps thanks ​

Answers

Answer:

Explanation:

This is one-dimensional motion on an incline, which is always tons of fun :/

The equation you need for this is

w*sinθ - f = ma where w is the weight of the girl (NOT the mass), theta is the angle of inclination, f is the frictional force pulling back on the girl, m is the mass of the girl, and a is the acceleration she experiences under these conditions. We have the mass but we need the weight, and weight has its own equation:

[tex]F_n=w=mg[/tex] where Fn is the normal force of the girl (which is the same as weight). Her normal force/weight is

w = 45(9.8) and we need 2 sig fig's for the answer so her weight is

w = 440N

f = μ[tex]F_n[/tex] which is the coefficient of kinetic friction times the normal force/weight of the girl:

f = (.25)(440) and we need 2 sig fig's for this as well so the frictional force is

f = 110

Putting it all together in the main equation looks like this:

440sin45 - 110 = 45a

Multiplication/division rules for sig fig's are different so we have to do them individually.

440sin45 will have 2 sig fig's in the answer:

440sin45 = 310; therefore:

310 - 110 = 45a. Again, because we have subtraction on the left and we will divide eventually, and the rules for both are different, we will subtract first, get that answer in the correct number of sig fig's and then divide that result by 45:

2.0 × 10² = 45a so

a = 4.4 m/s/s

A mosquito runs head-on into a truck. Splat! Which is true during the collision? A. The mosquito exerts more force on the truck than the truck exerts on the mosquito. B. The truck exerts more force on the mosquito than the mosquito exerts on the truck. C. The mosquito exerts the same force on the truck as the truck exerts on the mosquito. D. The truck exerts a force on the mosquito but the mosquito does not exert a force on the truck. E. The mosquito exerts a force on the truck but the truck does not exert a force on the mosquito.

Answers

The truck exerts more force on the mosquito than the mosquito exerts on the truck is true during the collision.

What is the exerts?
Exerts
is a term used to describe a passage or an extract taken from a larger piece of writing. Exerts are often used to showcase a specific part of a work and can be used to highlight the most important or influential passages. Exerts can be used to support or illustrate an argument, and can be used to provide evidence for a point that is being made. Exerts are often found in essays, scholarly articles, and other forms of writing, and are a useful tool for authors to draw attention to certain points or ideas.

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उत्तोलक हुन् ?
Calculate the load arm and effort arm from the following figure if the lever is in
balanced condition. In which class of lever do spoon and scissor belong to.(Ans: 3m, 15 m)2+1

Answers

Answer:

The length of the load arm is 3 m

The length of the effort arm is 15 m

Spoons and scissors are class 1 levers

Explanation:

The data given in the force diagram of the lever (machine) are;

The length of the lever = 18 m = (Length of effort arm) + (Length of load arm)

The force applied at the effort = 100 N

The load lifted by the lever = 500 N

The mechanical advantage, MA is given as follows;

MA = Load/Effort = (Length of effort arm)/(Length of load arm)

∴ MA = 500 N/(100 N) = 5

Let 'x' represent the length of the effort arm, and let 'y', represent the length of the load arm, we have;

x + y = 18...(1) (given)

MA = 5 = x/y

∴ x = 5·y...(2)

Substituting the value of 'x' in equation (1) with x = 5·y gives;

x + y = 5·y + y = 6·y = 18

∴ y = 18/6 = 3

y = 3

The length of the load arm, y = 3 m

x = 5·y = 5 × 3 = 15

x = 15

The length of the effort arm, x = 15 m

When lifting food with a spoon, the fulcrum, which can be taken as the edge of the plate or the supporting finger, is in between bowl of the spoon and the point of application of the thumb towards the extremities of the spoon handle

Therefore a spoon is a class 1 lever

The pivot of a scissors is in between the item being cut (the load) and the holes where the finger applies an effort

Therefore, a scissors is a class 1 lever.

Why is dynamic stretching recommended before activity?

Answers

Dynamic stretching is recommended before activity because it helps to prepare the muscles for the upcoming activity.

It increases range of motion, flexibility, and muscular coordination, and also helps to increase blood flow to the muscles. This helps to improve the performance of the muscles and reduce the risk of injury. Additionally, dynamic stretching helps to improve the overall physical conditioning of an individual, which is beneficial for any type of physical activity.

Dynamic stretching is typically recommended for individuals preparing for physical activity. Dynamic stretching involves movements that gradually increase in range of motion and muscle length, such as arm swings, leg swings, and torso twists.

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hello please help i’ll give brainliest

Answers

The correct answer is B.Antartica and Australia were one landmass millions of years ago.

Find the magnitude of the electric force between the charges 0.12 C and 0.33 C at a separation of 2.5 m. k=8.99×109N⋅m2/C2.

Answers

Answer:

F= k Q1 Q2 / r^2

plug in the numbers

A car drives to the right. There is a large amount of air resistance, and the car's engine provides the car's forward motion. Which force on the free-body diagram below represents the normal force acting on the car?

Answers

A force on the free-body diagram above which represents the normal force acting on the car include the following: D. Force A.

What is a free-body diagram?

In Science, a free-body diagram can be defined as a graphical illustration which is typically used in the field of science to visualize moments, tension, and applied forces that are acting on an isolated or rigid object (body), while using arrows to point in the direction of these forces.

Since this car was driven to the right, with a large amount of air resistance acting on it, and its engine provides the forward motion, we can reasonably infer and logically deduce that the normal force which is acting on the car is represented by Force A as illustrated by the free-body diagram shown in the image attached above.

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An object has a density of 3.25 kg/m?. If it has a total volume of 12.65m?. What is the object's mass?

Answers

Answer:

The object's mass is 41.1125 kilograms.

Explanation:

We can use the general density equation to determine the mass.

Density Equation

[tex]p=\frac{m}{V}[/tex]

[tex]p[/tex] is the density

[tex]m[/tex] is the mass

[tex]V[/tex] is the volume

Lets solve for [tex]V[/tex].

Multiply both sides of the equation by [tex]V[/tex].

[tex]p*V=\frac{m}{V}*V[/tex]

Cancel out the common factor of [tex]V[/tex] on the right side.

[tex]pV=m\\m=pV[/tex]

Now we have an equation for mass.

We are given

[tex]p=3.25[/tex]

[tex]V=12.65[/tex]

Substituting our values into our equation gives us

[tex]m=3.25*12.65\\m=41.1125[/tex]

Notice the unit of the given density

[tex]kg/m[/tex]

Our answer will be in kilograms

If I raise the temperature of a material by 5 K, what is the corresponding change in temperature on the Fahrenheit scale?

Answers

The corresponding change in temperature on the Fahrenheit scale More than 5°F.

In the Celsius scale, a temperature change of 5 degrees K corresponds to a shift of 50 degrees C. This is due to the fact that a temperature change of one degree Celsius is equivalent to a temperature change of one degree Kelvin. Tk = TC +273.15. We can observe that the relationship between the two temperature scales is linear and that its slope is the same for each.

The degree Celsius, denoted by the symbol °C, is the unit of temperature in Celsius and is by definition equal in magnitude to the kelvin unit. A temperature difference or interval can be stated in either kelvin or degrees Celsius, and in both cases the numerical value of the temperature difference is the same. However, the relationship between the numerical value of a thermodynamic temperature represented in kelvin and a Celsius temperature expressed in degrees Celsius exists.

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A student heats 3.55 g of copper and 4.60 g of iodine for 6.25 g of a new compound. All of the iodine reacted, but there is some copper left over unused. How much copper is left?

Answers

The mass of copper that is left unreacted at the end of the chemical reaction is 1.90 g

What mass of copper is left unreacted at the end of the reaction?

The mass of copper that is left untreated at the end of the chemical reaction is determined as follows:

Mass of copper before the reaction = 3.55 g

Mass of iodine before the reaction = 4.60 g

Mass of product = 6.25 g

According to the law of conservation of mass;

Mass of reactant = mass of product + mass of unreacted copper

Mass of reactants = 3.55 + 4.60

Mass of reactants = 8.15 g

The difference in the mass of the product obtained and the mass of the unreacted copper

Mass of unreacted copper = 8.15 g - 6.25 g

Mass of unreacted copper = 1.90 g

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An object falling from 50m will have
potential than an object falling from 30m
:Equal
:Lower
:Greater
:Less

Answers

Answer:

Greater

Explanation:

Distance (height) and mass determine the amount of Potential energy in an object.

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