Answer:
25,300,000,000,000 miles away
How far has a object fallen that is traveling 98 m/s In 10 seconds
Answer:
The distance is, y = 489.5 [m/s]
Explanation:
To solve this problem we can use the following equation of kinematics.
[tex]v_{f}^{2}= v_{i}^{2}+(2*g*y)[/tex]
where:
Vf = final velocity = 98 [m/s]
Vi = initial velocity = 0
g = gravity acceleration = 9.81 [m/s^2]
y = distance [m]
(98^2) = 0 + (2*9.81*y)
Note: the positive sign of the equation means that the acceleration of gravity acts in the direction of the movement of the object.
9604 = 19.62*y
y = 489.5 [m/s]
Sugar is made of carbon, hydrogen, and oxygen atoms. Sugar is
A a compound because its parts cannot be separated through physical mea
B
an element because it is a pure substance whose parts cannot be separat
С
a mixture because it is made of different kinds of atoms.
D
a solution because it dissolves when mixed with water.
25
60
20
1. How many servings can be made with 25 cups of pasta, 30 cups of marinara, and 5
cups of parmesan?
Answer:
60
Explanation:
i think it 60 because u plus 25 +30=55+5=60
what would happen to the gravitational force between earth and the moon if the distance between them increased?
Answer:
The gravitation force would weaken.
Explanation:
It would weaken as they would have less of a effect on eachother. Additionally, the sun would most likely grab the moon and catapult it.. but we dont talk about it.
a) Show that the surface temperature of a star can be inferred from measurements of blackbodyfluxes at two different frequencies, even if the stellar radius and distance are unknown.
b) Explain why in practice this method does not work well if both frequencies are on theRayleigh-Jeans side of the spectrum,hνkT.
c) Derive a simple, approximate expression for the temperature when both measurements areon the Wien tail,hνkT.
d) Derive an expression for the star’s radius if a distance measurement is also available (e.g.,from parallax).
Answer:
The answers to the questions have been solved in the attachment.
Explanation:
The answers to part a to e are all contained in the attachment. For answer part b, temperature and frequency were assumed to be fixed or constant. V² is directly proportional to T telling us that variation in T gives us a square in the frequency variation. This tells us why it is difficult when both frequencies are on this side of the black body.
Jafar's pretty practical, and the physics teacher seems to talk a lot about unreal things such as frictionless surfaces, point particles that represent whole objects (like his car), and ropes that do not stretch when they are used. Scott, one of Jafar's classmates, says that there's the world and then there's physics class and it's not real; Jafar should just memorize the unreal things, give the teacher what she wants, and forget them after the final examination, but Jafar is not comfortable with that. He wants to be an engineer like his older sister, and she told him that what they learned in physics does relate to her job. So giving the teacher what she wants and forgetting does not seem like a good option to him. Which, if any, of the following possible statements Jafar makes to Scott in response to his suggestion could be correct and may be able to persuade Scott to change his mind?
A. "Physics uses unreal situations as starting points because they are easy to visualize and do calculations with, then it adds reality little by little on to the simplified foundations; so points that represent objects aren't lies, they are just simplifications that give us a foothold onto the ideas that are important to consider."
B. "Physics gave the world the transistor and other devices that work in the computers in my car. Physicists have been able to land objects from Earth on Mars and have invented lasers and holograms. Something they are doing as scientists leads to these results, so we should both work to really understand how physics works."
C. "Engineers who built bathyscaphes to investigate the ocean depths use physics principles to keep occupants alive. Engineers who build bridges use physics so the cars do not plunge through even in heavy traffic. Engineers can create integrated circuits that do huge numbers of calculations each second. I think it must be important to understand how the basic physics leads to these useful results."
D. "My sister is an engineer, and she says learning physics is important. If she says so, we should learn O it."
Answer:
Statements A,B,C are correct
Explanation:
For the first statement Jafar is trying to explain the reasons behind the use of unreal/ideal situations by the physics teacher while teaching in classrooms and that can make Scott change his mind about physics
The second statement shows the real applications of physics in every day Devices like the transistor and other devices seen in the world today
The third statement shows to Scott the application of physics in ensuring the safety of lives and property of people around the world
while statement D is not a correct statement to persuade Scott
Answer:
yes A,B,C
Explanation:
Two planes are about to drop an empty fuel tank. At the moment of release each plane has the same speed of 195 m/s, and each tank is at the same height of around 1.10 km above the ground. Although the speeds are the same, the velocities are different at the instant of release, because one plane is flying at an angle of 15° above the horizontal (Plane A) and the other is flying at an angle of 15° below the horizontal (Plane B).
1. Find the:
a. magnitude.
b. direction of the velocity with which the fuel tank hits the ground if it is from plane A.
2. Find the:
a. magnitude
b. direction of the velocity with which the fuel tank hits the ground if it is from plane B.
In each part, give the direction as a positive angle with respect to the horizontal.
Answer:
376.71
Explanation:
1.a
To find the angle between them we add 15 +15=30°
Since they aren't perpendicular we use cosine law
[tex] \alpha = 180 - 30[/tex]
[tex] \sqrt{ {a}^{2} + {b}^{2} - 2ab \cos( \alpha ) } [/tex]
[tex] \sqrt{ {195}^{2} + {195}^{2} - 2 \times 195 \times 195 \times \cos(150) } [/tex]
=376.711
a 100 foot cliff drops vertically to a lake if the angle of elevation from a swimmer to the top of the cliff is 54.6 how far is the swimmer from the clif
Answer:
Explanation:
Please see attached photo for explanation.
In the attached photo, X is the distance of the swimmer from the cliff.
Thus, we can obtain the value of x by using Tan ratio as illustrated below:
θ = 54.6°
Opposite = 100 foot
Adjacent = x =.?
Tan θ = Opposite /Adjacent
Tan 54.6 = 100/x
Cross multiply
x × Tan 54.6 = 100
Divide both side by Tan 54.6
x = 100 / Tan 54.6
x = 71.07 foot
Therefore, the swimmer is 71.07 foot from the cliff.
A jumper in the long-jump goes into the jump with a speed of 12 m/s at an angle of 20 degree above the horizontal. How long will it take the jumper to reach the highest point
Answer:
ffffffffffffffffffffffffffffffffffffffff
Explanation:
The jumper will take 0.419 seconds to reach the highest point.
What is Projectile Motion?A projectile can be described as an object that is thrown obliquely near the surface, it moves along a curved path with constant acceleration directed toward the center of the earth.
In a Projectile Motion, along the x-axis, there is uniform velocity, responsible for the horizontal motion, and along the y-axis, there is uniform acceleration, responsible for the vertical motion of the particle.
The time required to attain the maximum height of the jumper will be given by:
[tex]t =\frac{usin\theta}{g}[/tex]
Given, the velocity of the jumper, u = 12 m/s
The angle of the jumper with the horizontal, θ = 20°
The time taken by the jumper to achieve maximum height:
[tex]t = \frac{12\times sin 20}{9.8}[/tex]
t = 0.419 sec
Therefore, the jumper will achieve maximum height in 0.419 seconds.
Learn more about projectile motion, here:
https://brainly.com/question/11049671
#SPJ2
illustrated map can you guys answer this pls. i will
give you 20 points
A test driver at Incredible Motors, Inc., is testing a new model car having a speedometer calibrated to read rather than . The following series of speedometer readings was obtained during a test run:
Time () 0 2.0 4.0 6.0 8.0 10 12 14 16
Velocity () 0 0 2.0 5.0 10 15 20 22 22
(a) Compute the average acceleration duringeach 2-s interval. Is the acceleration constant?A. Yes
B. No (b) Is it constant during any part of the test run?A. Yes
B. No
Answer:
(a) No, the acceleration is not constant
(b) Yes, it is constant between 6 s and 12 s
Explanation:
Given;
time of motion; t(s) = 0 2 4 6 8 10 12 14 16
velocity (m/s); v = 0 0 2 5 10 15 20 22 22
Average acceleration for t= (2,0) and v = (0,0)
[tex]a = \frac{v_2-v_1}{t_2-t_1} \\\\a = \frac{0-0}{2-0} = 0 \ m/s^2[/tex]
Average acceleration for t = (4, 2) and v = (2,0)
[tex]a = \frac{v_2-v_1}{t_2-t_1} \\\\a = \frac{2-0}{4-2} = 1.0 \ m/s^2[/tex]
Average acceleration for t = (6, 4) and v = (5,2)
[tex]a = \frac{v_2-v_1}{t_2-t_1} \\\\a = \frac{5-2}{6-4} = 1.5 \ m/s^2[/tex]
Average acceleration for t = (8, 6) and v = (10,5)
[tex]a = \frac{v_2-v_1}{t_2-t_1} \\\\a = \frac{10-5}{8-6} = 2.5 \ m/s^2[/tex]
Average acceleration for t = (10, 8) and v = (15,10)
[tex]a = \frac{v_2-v_1}{t_2-t_1} \\\\a = \frac{15-10}{10-8} = 2.5 \ m/s^2[/tex]
Average acceleration for t = (12,10) and v = (20,15)
[tex]a = \frac{v_2-v_1}{t_2-t_1} \\\\a = \frac{20-15}{12-10} = 2.5 \ m/s^2[/tex]
Average acceleration for t = (14,12) and v = (22,20)
[tex]a = \frac{v_2-v_1}{t_2-t_1} \\\\a = \frac{22-20}{14-12} = 1.0 \ m/s^2[/tex]
Average acceleration for t = (22, 22) and v = (16,14)
[tex]a = \frac{v_2-v_1}{t_2-t_1} \\\\a = \frac{22-22}{16-14} = 0 \ m/s^2[/tex]
(a) B. No (The acceleration is not constant)
(b) A. Yes (it is constant between 6 s and 12 s)
Tyler throws a baseball, which accidentally breaks a window in his neighbor's house. Which of the following represents the action force?
1.The window breaking.
2.The baseball accelerating.
3.Tyler's arm throwing the ball.
Answer: Tyler’s arm throwing the ball
Explanation:
Answer:
tyler's arm throwing the ball
Explanation:
i did this assignment
A motorcycle is driven horizontally straight off a 22-m tall cliff with a speed of 65
m/s. How far from the base of the cliff will the motorcycle land?
Answer:
137.8 m
Explanation:
The following data were obtained from the question:
Height (h) = 22 m
Initial velocity (u) = 65 m/s
Horizontal distance (s) =.?
Next, we shall determine the time taken for the motorcycle to get to the ground. This can be obtained as follow:
Height (h) = 22 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
22 = ½ × 9.8 × t²
22 = 4.9 × t²
Divide both side by 4.9
t² = 22/4.9
Take the square root of both side.
t = √(22/4.9)
t = 2.12 s
Finally, we shall determine the horizontal distance travelled by the motorcycle. This is illustrated below:
Initial velocity (u) = 65 m/s
Time (t) = 2.12 s
Horizontal distance (s) =.?
s = ut
s = 65 × 2.12
s = 137.8 m
Thus, the motorcycle will land at 137.8 m away from the cliff
Find the maximum frequency for a non distorted sine-wave output voltage of 12-V peak with an Op-Amp that has a slew rate of 1.5 V/micro seconds
Answer:
The maximum frequency is approximately 20,000 Hz
Explanation:
Given;
peak output voltage, V = 12 V
slew rate, = 1.5 V/μs
The slew rate is given by;
slew rate = 2πfV
where;
f is the maximum frequency given by;
[tex]f = \frac{slew \ rate}{2\pi V}\\\\ f = \frac{1.5 }{\mu*2\pi *12}\\\\ f = \frac{1.5 }{10^{-6}*2\pi *12}\\\\f = 19891.79\\\\f = 20,000 \ Hz\\\\f = 20 \ kHz[/tex]
Therefore, the maximum frequency is approximately 20,000 Hz
An object is dropped from rest.
What is the acceleration after 9 s? The
acceleration of gravity is 9.8 m/s
2
.
Taha xain malai ..........hhdd
A straight line is drawn on the surface of a 18-cm-radius turntable from the center to the perimeter. A bug crawls along this line from the center outward as the turntable spins counterclockwise at a constant 45 rpm. Its walking speed relative to the turntable is a steady 3.4 cm/s. Let its initial heading be in the positive x-direction, where the x- and y-directions are fixed relative to the laboratory. As the bug reaches the edge of the turntable (still traveling at 3.4 cm/s radially, relative to the turntable) what are the x and y components of the velocity of the bug?
Answer:
v_r = 3.4 cm / s , v_t = 84.82 cm / s
Explanation:
The speed of the insect has two components, one radial and the other tangential,
The radial component is the speed with which the insect moves with respect to the plate
v_r = 3.4 cm / s
The tangential component is given by
v = w r
Let's reduce the angular velocity to the SI system
w = 45 rpm (2π rad / 1 rev) (1 min / 60 s) = 4.712 rav / s
let's calculate
v = 4.712 18
v_t = 84.82 cm / s
Running late to work, Mr. Linares drops his keys from the top of the second floor stairwell and they fall straight down to the ground level. It takes about 1.8 s for the keys to hit the floor. How high did the keys fall from?
Answer:
about 1.8 s high
Explanation:
my plan for increasing my participation includes the following strategies
Answer:
Find the explanation below.
Explanation:
I agree to increase my participation in active recreational activities particularly jumping and running for 5 days per week. I will begin my program next month and plan to reach my final goal by entering SPORTS.
My plan for increasing my participation includes the following strategies
1. I must have a positive mind and participate in activities so I can get good grades.
2. I would prepare a schedule for my activities so that they do not encroach on the time for sports.
3. I must dedicate hours to practice the skills that I am not very good at
4. I must listen attentively to the instructions from my coach and apply them diligently.
5. I must develop the spirit of sportsmanship with my peers and playmates so that I can learn from their skills.
My plan for increasing my participation include:
Listen carefully.Foster friendships.Engage the help of volunteers.Promote exercise.Initiate regular meetings for special interest groups.In order to increase participation in activities, it's important to be patient and take time to listen. There should be undivided attention.
Encourage friendships by identifying the residents that have identical character traits and personalities. One can also initiate a volunteers program. They can assist by supervising groups and leading discussion groups.
There should be a promotion of exercise. Residents should be aware of the benefits of exercise for their minds and body. There should also be regular meetings for special interest groups.
Read related link on:
https://brainly.com/question/22697935
A toy car is given an initial velocity of 5.0 m/s and experiences a constant acceleration of 2.0 m/s.
What is the final velocity after 8.0
{Earth science} I give brainly!*
Please select the word from the list that best fits the definition
used as evidence for sea-floor spreading
Options~
Magma
Seismograph
Global positioning system
Fossils
Rift zones
Magnetic reversal'
*I only give brainly if you are right lol
Answer:
The answer is magma
Explanation:
I'm 99.99% this is right
Answer: its magnetic reversal
Explanation: jus took the test make brainly
How does the amount of work done on an object to make it move in the horizontal direction compare to the amount of kinetic energy gained by the object
Answer:
when compared, they are equal
Explanation:
the quantity of work done on object to get it to move in the horizontal direction as well as amount of kinetic energy gained by this object have a direct relationship.
this is true because we are going by the work-energy theory.
"the net work done on any object is equal to the change in the kinetic energy of that object".
therefore amount of kinetic energy gained = work done to make it go in an horizontal direction.
Vectors A and B lie in the xy ‑plane. Vector A has a magnitude of 17.1 and is at an angle of 150.5∘ counterclockwise from the +x ‑axis. Vector B has a magnitude of 28.1 and is 205.3∘ from the +x ‑axis. Resolve A and B into components, and express using ???????????? unit vectors,
A =Ax????+Ay????+Az????
B =Bx????+By????+Bz????
where Ax, Ay, Az and Bx, By, and Bz are the calculated values of the x ‑, y ‑, and z ‑components of vectors A and B , respectively.
Answer:
A = -14.87 i ^ + 8.42 j ^ + 0 k ^
B = -25.41 i ^ -12.0 j ^ + 0 k ^
Explanation:
For this exercise let's use trigonometry by decomposing to vectors
vector A
module 17.1 with an angle of 150.5 counterclockwise.
Sin 150.5 = [tex]A_{y}[/tex] / A
cos 150.5 = Ax / A
A_{y} = A sin 150.5 = 17.1 sin 150.5
Aₓ = A cos 1505 = 172 cos 150.5
A_{y} = 8,420
Aₓ = -14.870
the vector is
A = -14.87 i ^ + 8.42 j ^ + 0 k ^
Vector B
[tex]B_{y}[/tex] = 28.1 sin 205.3
Bₓ = 28.1 cos 205.3
B_{y} = -12.009
Bₓ = -25.405
the vector is
B = -25.41 i ^ -12.0 j ^ + 0 k ^
An unbalanced force of 15 N is applied to a 13 kg mass. What is the acceleration of the mass?
Answer:
the acceleration of an object equals the net force acting on it divided by its mass, or a = F m .
Explanation:
When practicing reading skills, you should focus on _______.
content recall
comprehension
speed
all of the above
Answer:
I would say the answer is All the above.
Explanation:
If this wasn't what you were looking for please don't hesitate to comment again! Have a nice day/night! :)
Answer:
all the above
Explanation:
2. How far can a dog travel if he can travel at 2.5 m/s for 5 seconds?
Answer:
[tex]\boxed {\tt 12.5 \ meters}[/tex]
Explanation:
We want to find how far the dog can travel, or the distance.
Distance can be found by multiplying the speed and the time.
[tex]d=s*t[/tex]
The dog travels 2.5 meters per second and travels for 5 seconds. Therefore,
[tex]s=2.5 \ m/s\\t= 5 \ s[/tex]
Substitute the values into the formula.
[tex]d=2.5 \ m/s \ * 5 \ s[/tex]
Multiply. Note that the seconds, or "s" will cancel each other out when multiplying.
[tex]d= 2.5 \ m * 5[/tex]
[tex]d=12.5 \ m[/tex]
The dog can travel 12.5 meters at 2.5 m/s for 5 seconds.
A soccer player heads the ball and sends it flying vertically upwards at a speed of 18.0 m/s . How high above the players ' head does the ball travel ?
Answer:
16.53 m
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 18.0 m/s.
Final velocity (v) = 0 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) =.?
The maximum height reached by the ball can be obtained as follow:
v² = u² – 2gh (since the ball is going against gravity)
0² = 18² – (2 × 9.8 × h)
0 = 324 – 19.6h
Rearrange
19.6h = 324
Divide both side by 19.6
h = 324 / 19.6
h = 16.53 m
Therefore, the maximum height reached by the ball is 16.53 m
The amount of force a muscle can produce is known as
An object has a mass of 4kg. What is its weight (in Newton) on Earth?
Answer:
mass of an object = 4kg
acceleration due to gravity on earth = 9.8 m/s²
therefore , weight of an object on earth = Mass × gravity
=> weight = 4×9.8 => 39.2 N
since , weight is a force we measure it in newtons
You are playing right field for the baseball team. Your team is up by one run in the botton of the last inning of the game when a ground ball slips through the infield and comes straight toward you. As you pick up the ball 65m from home plate, you see a runner rounding third base and heading for home with the tying run. ou throw the ball at an angle of 30 degrees above the horizontal with just the right speed so that the ball is caught by the catcher, standing on home plate, at the same height as you threw it. As you release the ball, the runner is 20 meters from home plate and running full speed at 8.0 m/s. Will the ball arrive in time for your team's catcher?
Answer:
The correct response is "No". The further explanation is given below.
Explanation:
The given values are:
Angle
[tex]\theta = 30^{\circ}[/tex]
Distance
d = 20 m
Speed
s = 8.0 m/s
Now,
⇒ [tex]y(t) = \frac{1}{2}\times a\times t^2 + v0\times t\times (sin \theta)[/tex]
[tex]0 = -4.9t^2 + v0\times t\times (sin 30)[/tex]
[tex]x = v0\times (cos \theta)\times t[/tex]
[tex]65 = v0\times (cos 30)\times t[/tex]
[tex]v0\times t = \frac{65}{Cos30}[/tex]
[tex]0 = -4.9t^2 + 65\times \frac{sin30}{cos30}[/tex]
[tex]t = 2.767 \ sec[/tex]
So,
⇒ [tex]d = r\times t[/tex]
[tex]20 = 8\times t[/tex]
[tex]t=2.5 \ sec[/tex]
Therefore, 2.5 < 2.767, so it won't get there.
Select the only incorrect statement from the following:
a. When resistors are connected in parallel, the voltage across each resistor is the same
b. When resistors are connected in series, the potential difference across each resistor is the same
c. When resistors are connected in parallel, the total current from the voltage source is the sum of the currents in the individual resistors
d. The current flowing in all resistors in series across a battery is the same as the current from the battery
e. The voltage across all the resistors in series is the sum of the individual voltages across each resistor
Answer: b. When resistors are connected in series, the potential difference across each resistor is the same.
Explanation: When resistors are in series, current is the same in all of rhe them. According to the First Law of Ohm,
voltage (potential difference) = resistance * current.
Resistance is the proportionality constant between voltage and current.
If current is the same, to "keep" resistance constant, voltage has to vary.
So, when resistors are in series, current is the same and potential difference or voltage varies.