A balanced chemical equation demonstrates the Law of Conservation of Mass because it shows that the same amount of mass is present on both sides of the equation. This means that the total mass of the reactants is equal to the total mass of the products.
the specific gravity of ice is 0.917, whereas that of seawater is 1.025. what percent of an iceberg is above the surface of the water?
The percentage of the iceberg that is above the surface of the water is 10.73%.
The buoyancy force that acts on the iceberg is equal to the weight of the seawater displaced by the iceberg.
Buoyancy force = weight of the displaced seawater
The buoyancy force experienced by the iceberg keeps it afloat. Therefore, the volume of the ice submerged in water must be equal to the volume of the displaced water, which is given asρ = m/vρi = 0.917ρw = 1.025
The buoyancy force on the iceberg can be calculated as ρwater * g * V = mgg = 9.8 m/s²V = m/ρwater
We have,ρwater = 1.025ρice = 0.917
∴ The fraction of the iceberg submerged in water can be calculated as:
f = 1 - ρice/ρwater = 1 - 0.917/1.025= 0.1073
Thus, 10.73% of the iceberg is above the surface of the water.
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A 500kg box slides down a frictionless plane at an angle of 60.0°. What is the magnitude of the box's acceleration and the normal force on the box?
-i think i know the answer but it wouldn't hurt to be sure.
500kg box slides down a frictionless plane at an angle of 60.0° the normal force on the box is approximately 2450 N.
The acceleration of the box down the plane is determined by the force of gravity pulling the box down the slope. To determine the magnitude of the acceleration, we first need to resolve the gravitational force into its component vectors parallel and perpendicular to the slope.
The force of gravity on the box is given by:
Fg = m*g
where m is the mass of the box and g is the acceleration due to gravity (9.8 m/[tex]s^2[/tex]).
The component of the force of gravity parallel to the slope is given by:
Fpar = Fg*sin(60.0°)
Fpar = 500 kg * 9.8 m/[tex]s^2[/tex] * sin(60.0°) ≈ 4286 N
The component of the force of gravity perpendicular to the slope is given by:
Fperp = Fg*cos(60.0°)
Fperp = 500 kg * 9.8 m/[tex]s^2[/tex] * cos(60.0°) ≈ 2450 N
The net force down the slope is given by:
Fnet = Fpar
Fnet = 4286 N
The magnitude of the acceleration down the slope is given by:
a = Fnet/m
a = 4286 N / 500 kg ≈ 8.57 m/[tex]s^2[/tex]
Therefore, the magnitude of the box's acceleration down the slope is approximately 8.57 m/[tex]s^2[/tex].
The normal force on the box is equal in magnitude and opposite in direction to the component of the force of gravity perpendicular to the slope, i.e.,
Fn = Fperp
Fn = 2450 N
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a very long wire has radius 6 cm has current 6 amps is directed out of the page. the current is distributed uniformly over its cross-sectional area. point p is 2 cm from the center of the wire. an amperian loop is drawn through point p concentric to the wire. what is the current going through the amperian loop?
The current going through the Amperian loop is approximately 0.67 A.
We have to Compute the cross-sectional area of the whole wire to determine the current flowing through the Amperian loop:
Since the radius of the wire is 6 cm, the area A_total is given by the formula
A_total = πr² = π(6 cm)² ≈ 113.1 cm².
The current is distributed uniformly over the wire's cross-sectional area. The total current is 6 A, so the current density J is given by
J = I_total / A_total = 6 A / 113.1 cm² ≈ 0.053 A/cm².
The Amperian loop is concentric to the wire and passes through point P, which is 2 cm from the center. The area A_loop is given by
A_loop = πr² = π(2 cm)² ≈ 12.57 cm².
The current density J is constant across the wire's cross-sectional area, so the current I_loop through the Amperian loop is given by
I_loop = J × A_loop = 0.053 A/cm² × 12.57 cm² ≈ 0.67 A.
So, 0.67 A is The current flowing through the Amperian loop.
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a 1100 kg car travels at 25 m/s and then quickly stops in 4.2 s to avoid an obstacle. what is the initial momentum of the car?
The initial momentum of the car is 27500 kg m/s.
In the case of the car traveling at a velocity of 25 m/s, it has a certain momentum. When the car comes to a stop, its momentum changes to zero, since the velocity becomes zero. This change in momentum occurs due to a force that acts on the car to bring it to a stop. The initial momentum of the car can be calculated using the formula:
p = m*v
where p is the momentum, m is the mass, and v is the velocity.
Given that the mass of the car is 1100 kg and its velocity is 25 m/s, we have:
p = 1100 kg * 25 m/s = 27500 kg m/s
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Solve for the missing value (only enter the number)
Force (N):?
Mass (kg): 2
Acceleration (m/s^2): 2
The following formula encapsulates it: force (N) Equals mass (kg) x acceleration (m/s2). A mass item will therefore accelerate in direct force exerted. Mass (kg): 2 Force (N): 1 (2). acceleration (m/s2).
What is the unit of force formula?The Newton is the SI unit for force (N). kg*m*s-2 is equivalent to one Newton. F=ma is the fundamental formula for force, where F represents force, m is mass in kilogrammes, and an is acceleration in m*s2. Newton Newton's second motion law is this.
What does one unit of force weigh?An International System of Units' (Symbol: N) unit of force is the newton (SI). The force that causes a mass of one kilogramme to accelerate by one metre / second per second is known as 1 kgm/s2.
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a hummingbird moves its wings at a rate of wingbeats a minute. write this rate in wingbeats per second.
The rate of wingbeats per minute for hummingbirds can be converted to wingbeats per second by dividing the number of wingbeats per minute by 60.
This is because there are 60 seconds in a minute, meaning that if the wings are moving at a rate of x wingbeats per minute, they are moving at a rate of x/60 wingbeats per second.
This conversion is often necessary when calculating the speed of a hummingbird, as it is easier to measure the rate of wingbeats than it is to measure the bird's speed directly. In addition, since hummingbirds are capable of flying incredibly quickly, it is often more precise to measure the rate of their wingbeats instead of their speed.
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A car traveling 127 m/s is 7895 meters away from Bojangles. How long will it take the car to reach Bojangles
Answer:
10s
Explanation:
11. What kind of force did the levitating rings display? What does this say
about the magnetic domains of these objects? Record your evidence.
answer :
force is called the magnetic force of repulsion, and it happens when two magnets have the same poles (either both north or both south) and they push away from each other.
When all the domains in a material are aligned in the same direction, the material becomes strongly magnetized.
explanation :
magnetic domains in the rings were stable and strong enough to resist the force of gravity.
In the case of the levitating rings, the magnetic domains were aligned in such a way that they created a strong magnetic field, which allowed the rings to levitate in mid-air.
tiny regions within ferro magnetic material that have their own magnetic fields are called magnetic domains.
Magnetic domains in the rings refer to the tiny regions within the ring's ferro magnetic material that have their own magnetic fields.
Help asap 50 points!! What form of energy is stored in a battery?
O chemical
O sound
O light
O heat
Answer:
The answer to your question is O chemical
Explanation:
Chemical potential energy
Batteries store energy in the form of chemical potential energy. This energy is converted into electrical energy when the battery is connected to an electrical circuit.
I hope this helps and have a wonderful day!
Hello pls help me if possible
Answer: The x-component of the acceleration is [tex]-0.45m/s^{2}[/tex]
There u go (:
the position of a spring/mass system is described by the following expression: , where a is the amplitude and t is measured in seconds. what is the period of oscillation?
The period of oscillation for the spring/mass system described by the equation x(t) = a sin(ωt) is 2π seconds, which is the time taken for the system to complete one full cycle of oscillation.
The position of a spring/mass system is given by the equation:
x(t) = a sin(ωt)
where x is the displacement of the mass from its equilibrium position, a is the amplitude of the oscillation, ω is the angular frequency, and t is time in seconds.
The period of oscillation, T, is defined as the time taken for the system to complete one full cycle of oscillation, i.e., for the mass to move from its initial position, through its maximum displacement, back to its initial position. Mathematically, we can express the period as:
T = 2π / ω
where ω is the angular frequency of the oscillation.
To find the period of the spring/mass system described by the equation x(t) = a sin(ωt), we need to determine the value of ω. Comparing this equation to the standard form of a sinusoidal wave, y = A sin(ωt + φ), we can see that ω is the coefficient of t inside the sine function, i.e., ω = 2π / T.
In our equation x(t) = a sin(ωt), ω is the coefficient of t, which is just ω = 1. Therefore, we can determine the period of oscillation as:
T = 2π / ω
= 2π / 1
= 2π seconds
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How long is a wire in a 0.86 T field that carries a current of 1.4A and experiences a force of
13 N?
A 14.2-m
The length of a wire in a 0.86 T field that carries a current of 1.4A and experiences a force of 13 N is 14.2-m.
What is the force experienced by a wire when it is placed in a magnetic field and carries an electric current? When a wire is placed in a magnetic field and carries an electric current, it experiences a force known as magnetic force. The formula for magnetic force on a wire is given by:F = BILsinθWhere:F = Magnetic forceB = Magnetic field strength I = Electric currentL = Length of wire in the magnetic fieldθ = Angle between the wire and the magnetic field directionIf we substitute the given values into the above equation, we have:F = (0.86 T)(1.4 A)(L)sin90° = 1.204L NSince F = 13 N, then:13 N = 1.204L NL = 13/1.204L = 10.7981-m≈14.2-mTherefore, the length of the wire in a 0.86 T field that carries a current of 1.4A and experiences a force of 13 N is 14.2-m.
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an aerobatic airplane flying at a constant 60.0 m/s makes a horizontal turn of radius 255 m . the pilot has mass 80.0 kg . what is the bank angle of the airplane?
The bank angle of the airplane is approximately 75.9°.
The bank angle of the aerobatic airplane can be found using the centripetal force equation and the weight of the pilot. The equation is:
tan(θ) = ([tex]V^{2}[/tex]) / (r * g)
where θ is the bank angle, v is the velocity (60.0 m/s), r is the radius (255 m), and g is the acceleration due to gravity (9.81 m/s²).
Solving for θ, we get:
tan(θ) = (60.[tex]0^{2}[/tex]) / (255 * 9.81)
θ = arctan(3.926)
θ ≈ 75.9°
The bank angle of the airplane is approximately 75.9°.
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the plates of an empty parallel-plate capacitor of capacitance 6.0 pf are 8.0 mm apart. what is the area of each plate (in m2)?
The area of each plate is approximately 5.39 × 10⁻⁶m².
The capacitance C of a parallel-plate capacitor is given by:
C = ε₀ * A / d
where ε₀ is the permittivity of free space (8.85 x 10⁻¹²F/m), A is the area of each plate, and d is the distance between the plates.
It is given that the capacitance C is 6.0 pF and the distance between the plates d is 8.0 mm.
First, need to convert the capacitance to Farads (F) from picofarads (pF):
6.0 pF = 6.0 × 10⁻¹²F
Substituting the given values into the capacitance equation, can get:
6.0 × 10⁻¹²F = (8.85 × 10⁻¹²F/m) * A / (8.0 × 10⁻³ m)
Solving for A, we get:
A = C * d / ε₀
A = (6.0 × 10⁻¹² F) * (8.0 × 10⁻³m) / (8.85 × 10⁻¹²F/m)
A ≈ 5.39 × 10⁻⁶m²
Therefore, the area of each plate would be approximately 5.39 × 10⁶m².
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how many 23- w w lightbulbs can be connected in parallel across a potential difference of 85 v v before the total current in the circuit exceeds 3.0 a a ?
A maximum of 11 23 W lightbulbs can be connected in parallel across a potential difference of 85 V before the total current in the circuit exceeds 3.0 A.
We can use Ohm's law to find the current drawn by a single 23 W lightbulb:
P = VI
23 W = V x I
I = 23 W / V
Substituting the given values, we get:
I = 23 W / 85 V
I = 0.27 A
To find the maximum number of lightbulbs that can be connected in parallel without exceeding a total current of 3.0 A, we divide the total current by the current drawn by a single lightbulb:
N = 3.0 A / 0.27 A
N ≈ 11
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How many joules of energy is required to heat 145.0-g of water from 14°C to boiling (100°C)?
Joules of energy required to heat 145.0 g of water from 14°C to boiling (100°C) is : 53,972.48 Joules of energy
What is heat energy?Amount of energy that is transferred from one system to surroundings because of temperature difference is called heat.
A we know : Q = m c ΔT
Q is amount of heat energy required (in joules) ; m is mass of the water (in grams) ; c is specific heat capacity of water (4.184 J/g°C) ; ΔT is change in temperature (in °C)
ΔT = final temperature - initial temperature
= 100°C - 14°C
ΔT = 86°C
As Q = m c ΔT
= 145.0 g * 4.184 J/g°C * 86°C
Q = 53,972.48 J
Therefore, approximately 53,972.48 joules of energy are required to heat 145.0 g of water from 14°C to boiling (100°C).
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in panoramic imaging, the pivotal point, or axis, around which the cassette carrier and x-ray tubehead rotate is termed a
In panoramic imaging, the pivotal point or axis around which the cassette carrier and x-ray tubehead rotate is termed a rotational center .
The panoramic X-ray machine's tubehead and film carrier move around the patient's head, generating a curved or panoramic image of the patient's entire mouth and teeth.In the United States, the most common form of dental radiograph is the panoramic radiograph. A panoramic radiograph is an extraoral, non-invasive X-ray test that displays a panoramic view of the teeth, jaws, and surrounding structures. It is one of the most often used imaging tests in dental clinics because it provides a comprehensive view of the teeth and oral cavity.
In panoramic imaging, the pivotal point, or axis, around which the cassette carrier and x-ray tubehead rotate is termed a "rotation center."
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eight 7.0-w christmas tree lights are connected in series to each other and to a 120-v source. what is the resistance of each bulb?
When eight 7.0 W Christmas tree lights are connected in series to each other and to a 120 V source, the resistance of each bulb is 240 Ω.
What is a series circuit?A circuit that has only one pathway for the flow of electric current is called a series circuit. It means that in a series circuit, all the electrical elements are connected one after the other, and the current flows through each component in turn.
As a result, the current is equal throughout the circuit, and the sum of the voltages across each element equals the total voltage of the circuit.The current is the same in all resistors in a series circuit. The voltage is different across each resistor, but the sum of the voltage drops across all of the resistors in the circuit is equal to the applied voltage.
Voltage across each bulb:The voltage across each bulb is not the same in a series circuit. However, the sum of all the voltages across each bulb adds up to the total voltage of the circuit. Here, the total voltage of the circuit is 120 V. Therefore, the voltage across each bulb is 15 V (120/8=15).Resistance of each bulb:
We use Ohm's law, which states that resistance is equal to voltage divided by current, to calculate the resistance of each bulb. In this example, we have the voltage across each bulb, which is 15 V. We can calculate the current flowing through the circuit by dividing the total voltage by the total resistance, which is the resistance of a single bulb multiplied by the total number of bulbs.
The current flowing through the circuit is 0.5 A (120/240=0.5).We can now determine the resistance of each bulb by dividing the voltage across each bulb by the current flowing through it. Resistance of each bulb is 30 Ω (15/0.5=30).Answer: 30 Ω
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jet fighter planes are launched from aircraft carriers with the aid of their own engines and a catapult. if in the process of being launched from rest, the thrust of a jet's engines is 2.30 105 n and after moving through a distance of 90.0 m the plane lifts off with a kinetic energy of 5.40 107 j, what is the work done on the jet by the catapult?
Work done on the jet by the catapult is 5.40x10^7 J, and Force exerted by the catapult is 6.00x10^5 N.
By using the work-energy principle, we can calculate the work done on the jet and the force exerted by the catapult, given information about initial and final kinetic energies and distance traveled. In this case, initial kinetic energy of the jet is zero, and final kinetic energy is 5.40x10^7 J.
[tex]Work = Kinetic\ Energy\ final - Kinetic\ Energy\ initial\\Work = 5.40 * 10^7 J - 0 J\\Work = 5.40 * 10^7 J[/tex]
Since the work done on the jet is equal to the force exerted by the catapult times the distance it moves, we can find the force:
[tex]Work = Force * Distance\\5.40 * 10^7 J = Force * 90.0 m\\Force = 6.00 * 10^5 N\[/tex]
Therefore, the work done on the jet by the catapult is 5.40x10^7 J, and the force exerted by the catapult is 6.00x10^5 N.
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a force probe is used to push a box across a smooth surface, as shown in the figure. frictional forces are considered to be negligible. the force probe collects data about the force exerted on the box as a function of time. the data are used to create the graph that is shown. during which time interval does the box experience the greatest change in its momentum?
The box experiences the greatest change in its momentum during this time interval of 1.5 s to 3.5 s.
To determine when the box experiences the greatest change in its momentum, we need to consider Newton's second law of motion, which states that the force exerted on an object is equal to the rate of change of its momentum. Mathematically, this is represented as:
F = Δp / Δt
Where F is the force exerted, Δp is the change in momentum, and Δt is the time interval.
Since frictional forces are negligible in this case, the force exerted by the force probe is the only force acting on the box. Therefore, to find the greatest change in momentum, we need to look for the time interval during which the force is at its maximum.
Based on the graph provided (which you need to observe), identify the time interval during which the force exerted on the box is at its highest. This time interval corresponds to the greatest change in the box's momentum. The slope of the line is steeper between 1.5 seconds to 3.5 seconds. This means that the box experiences the greatest change in its momentum during this time interval.So, the correct answer is 1.5 s to 3.5 s.
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which second law expression describes a simple harmonic oscillator? take b to be a positive nonzero constant
Second law expression that describes a simple harmonic oscillator is F= -mbω²x
When it comes to simple harmonic oscillators, the expression of the second law that applies is given by:
F= -mbω²x
Here, F is the force of the oscillator, x is the displacement of the oscillator from its equilibrium position, m is the mass of the oscillator, b is a positive nonzero constant (which represents the friction force), and ω is the angular frequency of the oscillator (which depends on the mass and the spring constant).
This expression is derived from the second law of motion, which states that the force applied to an object is proportional to the acceleration of the object (F = ma).
In the case of a simple harmonic oscillator, the force acting on the oscillator is given by the Hooke's law force, which is proportional to the displacement of the oscillator from its equilibrium position.
Therefore, we can substitute this force into the second law of motion equation to get the expression above.
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a 4.0 kg particle is moving horizontally with a speed of 5.0 m/s when it strikes a vertical wall. the particle rebounds with a speed of 3.0 m/s. what is the magnitude of the impulse delivered to the particle?
The magnitude of the impulse delivered to the particle is 32 kg m/s when its mass is 4 kg, horizontal speed is 5.0 m/s and the rebound speed is 3.0 m/s.
First, let's find the initial momentum of the particle:
Initial momentum (p_initial) = mass × initial velocity
p_initial = 4.0 kg × 5.0 m/s
p_initial = 20 kg m/s
Next, let's find the final momentum of the particle after it rebounds. Since the particle moves in the opposite direction after rebounding, its final velocity will be negative:
Final momentum (p_final) = mass × final velocity
p_final = 4.0 kg × (-3.0 m/s)
p_final = -12 kg m/s
Now, we can find the change in momentum, which is the impulse delivered to the particle:
Impulse = p_final - p_initial
Impulse = (-12 kg m/s) - (20 kg m/s)
Impulse = -32 kg m/s
The magnitude of the impulse is the absolute value of the impulse, so:
Magnitude of impulse = |-32 kg m/s|
Magnitude of impulse = 32 kg m/s
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suppose two worlds, each having mass M and radius R, coalesce into a single world. Due to gravitational contraction, the combined world has a radius of only 3 4R. what is the average density of the combined world as a multiple of r0, the average density of the original two worlds
Answer: the average density of the combined world is 256/81 times the average density of the original two worlds.
Explanation:
The total mass of the two original worlds is 2M, and their average density is given by:
ρ0 = 2M/(4/3 πR^3) = 3M/(2πR^3)
The final radius of the combined world is 3/4R, so its volume is:
V = 4/3 π(3/4R)^3 = 27/64 πR^3
The mass of the combined world is still 2M, so its density is:
ρ = 2M/V = 128M/(27πR^3)
The ratio of the average density of the combined world to that of the original worlds is:
ρ/ρ0 = (128M/(27πR^3)) / (3M/(2πR^3)) = 256/81
a particular balloon is designed by its manufacturer to be inflated to a volume of no more than l. if the balloon is filled with l helium at sea level, is released, and rises to an altitude at which the atmospheric pressure is only mm hg, will the balloon burst? (assume temperature is constant.)
The external pressure at the altitude is only 1474 mmHg.
To determine if the balloon will burst, need to compare the pressure inside the balloon to the external pressure at the altitude where it reaches, can use the ideal gas law to relate the pressure, volume, and temperature of a gas:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the absolute temperature.
Since the balloon is filled with helium, we can assume that the gas behaves ideally. If the balloon is filled to a volume of l at sea level, then find the initial pressure of the helium using the ideal gas law and the conditions at sea level (assuming standard atmospheric conditions):
P₁V = nRT
P₁ = nRT / V = (1 mol * 8.31 J/(mol*K) * 293 K) / l
P₁ ≈ 2.42 atm = 1847 mmHg
Therefore, the initial pressure inside the balloon is approximately 2.42 atm or 1847 mmHg.
As the balloon rises to an altitude where the atmospheric pressure is only P2 mmHg, the pressure inside the balloon decreases due to the decreasing external pressure. If the external pressure drops below the pressure inside the balloon, the balloon will expand and eventually burst.
To find the pressure inside the balloon at the higher altitude, use the ideal gas law again and assume that the volume of the helium remains constant (since the balloon is designed not to exceed a volume of l):
P₂V = nRT
P₂ = nRT / V = (1 mol * 8.31 J/(mol*K) * 293 K) / l
P₂ ≈ 2.42 atm * (760 mmHg / 1 atm) * (P2 / 760 mmHg)
Solving for P2, we get:
P₂ ≈ 1474 mmHg
Since the external pressure at the altitude would be only 1474 mmHg, which is less than the pressure inside the balloon of 1847 mmHg, the balloon will not burst. However, the balloon will expand due to the decreasing external pressure, and the volume of helium inside the balloon will increase.
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what happens to the number of air molecules inside the balloon when the air is heated? (assume v remains constant)
When the air inside a balloon is heated and its volume is held constant, the pressure increases, causing an increase in the number of air molecules inside the balloon.
When the air inside a balloon is heated, the temperature of the air increases, causing the air molecules to gain kinetic energy and move faster. As the molecules move faster, they collide with each other and the walls of the balloon more frequently, exerting a greater force on the walls.
If the volume of the balloon remains constant, the pressure inside the balloon will increase as a result of the increase in temperature. This increase in pressure causes the air molecules to move more vigorously and spread out. However, if we assume that the volume of the balloon remains constant, the air molecules do not have any extra space to move into. Therefore, the pressure increase will lead to an increase in the number of air molecules inside the balloon.
This can be explained by the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature. Assuming that the volume of the balloon is constant and the amount of air (moles of gas) inside the balloon remains the same, an increase in temperature will lead to an increase in pressure. Therefore, to satisfy the ideal gas law, the number of air molecules inside the balloon must increase.
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A submarine is a boat that can travel below the surface of the sea.
A submarine is 20m below the surface of the sea. The pressure due to the sea water at this
depth is P.
On another day, the submarine is 26 m below the surface of fresh water. The density of sea water is 1.3 times the density of fresh water.
What is the pressure due to the fresh water at a depth of 26 m?
The submarine is 26 m below the surface of fresh water. The density of sea water is 1.3 times the density of fresh water. The pressure due to fresh water at a depth of 26 m is 255660 Pa.
The pressure due to the sea water at a depth of 20 m can be calculated using the formula:
P = ρgh
where ρ is the density of the sea water, g is the acceleration due to gravity, and h is the depth of the submarine.
Assuming a density of sea water to be 1030 kg/m³ and g to be 9.81 m/s², we get:
P = 1030 x 9.81 x 20 = 202086 Pa
Now, to calculate the pressure due to fresh water at a depth of 26 m, we can use the same formula with the density of fresh water and the given depth:
P = ρgh
Assuming a density of fresh water to be 1000 kg/m³, and g to be 9.81 m/s², we get:
P = 1000 x 9.81 x 26 = 255660 Pa
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what type of equipment has a grinding head on wheels or tracks that moves through brush and grinds it up?
The equipment that has a grinding head on wheels or tracks that moves through brush and grinds it up is called a forestry mulcher.
A forestry mulcher is an essential tool used in forestry management, land clearing, and other activities that involve clearing trees and vegetation. It is a powerful machine designed to handle tough brush, shrubs, trees, and other vegetation.
The equipment is commonly used in forest management activities such as clearing woodlands, parkland, pastureland, and other large areas. Forestry mulchers are used to grind and mulch trees, bushes, and shrubs into small pieces that can be spread on the ground as a layer of mulch.
The mulch can help control soil erosion and retain moisture in the soil.The forestry mulcher is equipped with a grinding head that contains cutting teeth or blades. The grinding head is attached to a hydraulic arm that can be raised and lowered to adjust the cutting depth.
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1. how can you describe our atmosphere?
2. what are the different gases that can be found in our atmosphere?
3. what is the role of the atmosphere?
(science)
PAKI ANSWER PO PLEASE THANK YOU
Explanation:
Atmosphere is the thin layer of air that surrounds the Earth´s surface . Atmosphere is hold by the gravity exerted by the Earth . There are different layers of atmosphere :
Troposhere
Hydtosphere
Mesosphere
Thermosphere
Exosphere
There are various gases present in the atmosphere ( oxygen , nitrogen , carbon dioxide , sulphur oxide , etc. )
Atmosphere possess the great role as it consists of the Oxygen gas which is the transcendenatl element for the existence of living beings .
Atmosphere provides the shield against the UV. rays
the period t (in seconds) of a pendulum is given by , where l stands for the length (in feet) of the pendulum. if , and the period is seconds, what is the length?
72 feet is the length of pendulum if π = 3.14 and the period is 9.42 seconds.
In the example question, the pendulum's period T (in seconds) is calculated as T = 2(L/32), where L is the pendulum's length (in feet).
The length must be determined if = 3.14 and the period is 9.42 seconds.
T = 9.42 seconds
Adding the values to the formula now:
9.42 = 2*3.14*√(L/32)
9.42 = 6.28*√(L/32)
6.28 divided on both sides gives us
√(L/32) = 1.5
square on both sides, we obtain
(L/32) = 2.25
32 multiplied on both sides gives us
L = 72
The length is therefore 72 feet if = 3.14 and the time period is 9.42 seconds.
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if the neutral of an unbalanced three-wire system is opened, the circuit becomes a 240 v ? circuit. since the line with the smaller load has a ? resistance, more than half the total voltage drops across it. that is, voltage rises above 120 volts.
If the neutral of an unbalanced three-wire system is opened, the circuit becomes a 240 V open circuit. Since the line with the smaller load has a lower resistance, more than half the total voltage drops across it. That is, voltage rises above 120 volts.
When a neutral of an unbalanced three-wire system is opened, the circuit becomes a 240 V open circuit. This means that the voltage between the two hot wires (or line wires) in the circuit becomes 240 V.
In an unbalanced three-wire system, the current flows through both line wires and the neutral wire. The neutral wire carries the unbalanced current, which means it carries the difference between the current flowing through the two line wires. If the neutral wire is opened, the circuit becomes unbalanced because the current flowing through the two line wires is no longer equal. This causes the voltage between the two line wires to increase to 240 V.
Since the line with the smaller load has a lower resistance, it offers less opposition to the flow of current. This means that more current flows through this line, causing the voltage across this line to increase. The voltage across the other line decreases accordingly. If the load on one line is much greater than the load on the other line, then more than half the total voltage drops across the line with the smaller load. This causes the voltage on this line to rise above 120 volts.
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