How do I solve this?

The class boundaries are 0.5 - 3.5, 3.5 - 6.5, 6.5 - 9.5, 9.5 - 12.5, 12.5 - 15.5.

To find the class boundaries, we need to add and subtract 0.5 from the upper and lower limits of each class interval, respectively.

Using this formula, we get the following class boundaries:

Class Boundaries:

0.5 - 3.5, 3.5 - 6.5, 6.5 - 9.5, 9.5 - 12.5, 12.5 - 15.5

To construct the less than cumulative frequency table, we need to add up the frequencies of all the classes up to each class. For example:

Less than Cumulative Frequency Table:

Ages No. of Children Cumulative Frequency

1-3 10 10

4-6 12 22

7-9 15 37

10-12 13 50

13-15 9 59

To construct the greater than cumulative frequency table, we need to subtract the frequency of each class from the total frequency and then add the resulting values up to obtain the cumulative frequency. For example:

Greater than Cumulative Frequency Table:

Ages No. of Children Cumulative Frequency

13-15 9 59

10-12 13 50

7-9 15 37

4-6 12 22

1-3 10 10

Note that the last value of the greater than cumulative frequency table is always equal to the total frequency, which in this case is 59.

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The solution to the system of equations is x=2 and y=-2.

To solve the system of simultaneous equations graphically, we need to graph both equations on the same coordinate plane and find their point of intersection.

First, we'll rearrange both equations to be in the form y=mx+b, where m is the slope and b is the y-intercept.

y = 2 - 2x can be rewritten as y = -2x + 2

y = 2x - 6 can be rewritten as y = 2x - 6

Now, we'll plot both equations on the same coordinate plane. To do this, we'll create a table of values for each equation and plot the points.

For y = -2x + 2: (0,2), (1,0), (2,-2)

For y = 2x - 6:(0,-6), (1,-4), (2,-2)

Next, we'll plot these points on the same graph and draw the lines connecting them.

The point where the lines intersect is the solution to the system of equations. From the graph, we can see that the point of intersection is (2,-2).

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Answer:

[tex]y = 2x + 9[/tex]

Step-by-step explanation:

It is given that the slope of the line is 2, and it passes through (-3 , 3). The equation of straight lines is y = mx + b, in which:

y = (x , y) = 3

m = slope (gradient) = 2

x = (x , y) = -3

b = y-intercept

~

Plug in the corresponding numbers to the corresponding variables:

y = mx + b

3 = (2)(-3) + b

First, multiply -3 with 2:

[tex]3 = (2)(-3) + b\\3 = (2 * -3) + b\\3 = -6 + b[/tex]

Next, isolate the variable, b. Note the equal sign, what you do to one side, you do to the other. Add 6 to both sides of the equation:

[tex]3 = b - 6\\3 (+6) = b - 6 (+6)\\b = 3 + 6\\b = 9[/tex]

Plug in 2 for slope, and 9 for y-intercept, in the given equation:

[tex]y = mx + b\\m = 2\\b = 9\\[/tex]

[tex]y = 2x + 9[/tex] is your answer.

~

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Answer:

499

Step-by-step explanation:

Answer:

33

Step-by-step explanation:

Pythagorean theorem:

6,5^ - 2.5^2= 36

✓36=6 second leg

3×6=18 square area

0,5×6×2,5=7,5 area of a triangle

2×7,5 + 18= 33

From the above information we get:

Absolute maximum: 850
Absolute minimum: 800

To find the absolute maximum and minimum values of the function f(x) = 2x² - 16x + 850 on the given interval (0,4), we will follow these steps:

1. Find the critical points by taking the first derivative of f(x) and setting it equal to zero.
2. Determine if the critical points are within the interval (0,4).
3. Evaluate f(x) at the critical points and endpoints of the interval.
4. Identify the absolute maximum and minimum values based on the results.

Step 1: Find the critical points
f'(x) = 4x - 16
Setting f'(x) equal to zero:
4x - 16 = 0
4x = 16
x = 4

Step 2: Determine if the critical point is within the interval (0,4)
The critical point x = 4 is within the interval (0,4).

Step 3: Evaluate f(x) at the critical points and endpoints of the interval
f(0) = 2(0)² - 16(0) + 850 = 850
f(4) = 2(4)² - 16(4) + 850 = 850 - 64 + 850 = 800

Step 4: Identify the absolute maximum and minimum values based on the results
Absolute maximum: f(0) = 850
Absolute minimum: f(4) = 800

To answer the question:
(a) Interval (0,4)
Absolute maximum: 850
Absolute minimum: 800

(b) It seems you have repeated the interval (0,4), so the answer remains the same.
Absolute maximum: 850
Absolute minimum: 800

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Ishaan's current age is 84.

Let Ishaan's current age be I and Christopher's current age be C.

Given, I = 2C ...........(1) (Ishaan is twice the age of Christopher)

35 years ago, I - 35 = 7(C - 35) (Ishaan was 7 times the age of Christopher 35 years ago)

Simplifying the above equation, we get:

I - 35 = 7C - 245

I = 7C - 210 ...........(2)

Substituting equation (1) in equation (2), we get:

2C = 7C - 210

5C = 210

C = 42

Therefore, Christopher's current age is 42.

Substituting C = 42 in equation (1), we get:

I = 2C = 2(42) = 84

Therefore, Ishaan's current age is 84.

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The question is translated to English as

Ishaan is twice the age of Christopher. 35 years ago Ishaan was 7 times the age of Christopher. How old is Ishaan now?

The mean score of all the students together is 83.1 (rounded to one decimal place).

The mean score of all the students together can be calculated using the formula:

(mean score of first group * number of students in first group + mean score of second group * number of students in second group) / (total number of students)

Substituting the values, we get:

(86.9 * 37 + 74.4 * 22) / (37 + 22)

= (3215.3 + 1636.8) / 59

= 4852.1 / 59

= 82.3

Therefore, the mean score of all the students together is 82.3, rounded to one decimal place.

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In factorization the needed observations and steps before you can factor a difference of two squares are binomial, two positive/negative, prime, multiply factors, and look for a GCF.

Finding the factors of a given number or statement is the process of factorization. Factorization is the process of taking a larger number or expression and turning it into a product of smaller numbers or expressions, or factors. The factors may be polynomials, integers, or other mathematical constructs.

Therefore, the needed observations and steps before you can factor a difference between two squares are:

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The trigonometric ratios of angle C are sin C = 15/17, cos C = 8/17, and tan C = 15/8.

Since triangle ABC is a right triangle with a right angle at B, and we know AC = 17 units (hypotenuse) and BC = 8 units (adjacent side to angle C), we can use the Pythagorean theorem to find the length of the remaining side, AB (opposite side to angle C).

The Pythagorean theorem states: AB² + BC² = AC²

Plugging in the values we know:
AB² + 8² = 17²
AB² + 64 = 289

To find AB:
AB² = 289 - 64 = 225
AB = √225 = 15 units

Now we can determine the trigonometric ratios of angle C:

1. sine (sin C) = opposite/hypotenuse = AB/AC = 15/17
2. cosine (cos C) = adjacent/hypotenuse = BC/AC = 8/17
3. tangent (tan C) = opposite/adjacent = AB/BC = 15/8

So the trigonometric ratios of angle C are:
sin C = 15/17, cos C = 8/17, and tan C = 15/8.

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Step-by-step explanation:

we only need to calculate directly the work hours needed for 10 child bikes and 12 adult bikes.

as a child bikes needs 4 hours to build and 4 hours to test, for 10 child bikes that means 10×4 = 40 hours to build and 40 hours to test

an adult bike needs 6 hours to build and 4 his to test.

so, for 12 bikes that are 12×6 = 72 hours to build and 12×4 = 48 hours to test.

together that means we need

40 + 72 = 112 hours to build

40 + 48 = 88 hours to test

the limits of the company are 120 build hours and 100 test hours per week.

as 112 < 120 and 88 < 100, yes, the company can build 10 child bikes and 12 adult bikes in one week.

in fact, with that they still have 8 work hours (120 - 112) and 12 test hours (100 - 88) left and could therefore build either 2 additional child bikes (8 build hours, 8 test hours) or one additional adult bike (6 build hours, 4 test hours).

Answer:

65 mph

Step-by-step explanation:
To calculate the average speed of Niamh's car, we need to use the formula:

Average speed = Total distance ÷ Total time

First, we need to calculate the total time elapsed from 17:30 to 19:42:

Total time = 19:42 - 17:30 = 2 hours and 12 minutes

To convert the minutes to decimal form, we divide by 60:

2 hours and 12 minutes = 2 + (12 ÷ 60) = 2.2 hours

Now we can calculate the average speed:

Average speed = Total distance ÷ Total time

Average speed = 143 miles ÷ 2.2 hours

Average speed = 65 mph

Therefore, the average speed of Niamh's car from 17:30 to 19:42 was 65 mph.

The ball will rebound to maximum height of 25 centimetres or 0.25 meters after 7 bounces.

Firstly perform the unit conversion. As known, 1 meter is 100 cm. So, 25 centimetres is 0.25 meters.

Now, the formula to be used to find the number of bounces is -

New height × [tex] {2}^{n} [/tex] = old height, where n refers to number of bounces.

Keeping the values in formula

0.25 × [tex] {2}^{n} [/tex] = 32

Rearranging the equation

[tex] {2}^{n} [/tex] = 32/0.25

Divide the values

[tex] {2}^{n} [/tex] = 128

Converting the result into exponent form

[tex] {2}^{n} [/tex] = 2⁷

Thus, n will be 7 bounces.

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Answer:

  (A)  alternate interior angles

Step-by-step explanation:

You want the missing statement in the proof that opposite angles of a parallelogram are congruent.

The proof here shows angles A and C are congruent because they are corresponding parts of congruent triangles. To get there, the triangles must be shown to be congruent.

In statement 5, the triangles area claimed congruent by the ASA theorem, which requires two corresponding pairs of angles and congruent sides.

In statement 4, the relevant sides are shown congruent, so it is left to statement 3 to show two pairs of angles are congruent.

Of the offered answer choices, only one of them deals with two pairs of angles. Answer choice A is the correct one.

Answer:

Step-by-step explanation

Domain :

x

>

4

, in interval notation :

(

4

,

∞

)

Range:

g

(

x

)

∈

R

, in interval notation :

(

−

∞

,

∞

)

Explanation:

g

(

x

)

=

ln

(

x

−

4

)

;

(

x

−

4

)

>

0

or

x

>

4

Domain :

x

>

4

, in interval notation :

(

4

,

∞

)

Range: Output may be any real number.

Range:

g

(

x

)

∈

R

, in interval notation :

(

−

∞

,

∞

)

graph{ln(x-4) [-20, 20, -10, 10]} [Ans]  x>4

Answer:

Step-by-step explanation:

The Domain of g(x) = -|x| is all real numbers (no restrictions on what values x can take).

The Range of g(x) = -|x| is all real numbers less than or equal to zero. Absolute value of any real number is always greater than or equal to zero, and multiplying by a negative sign, that flips the sign of the result. So, g(x) will always be less than or equal to zero.

Domain:  (-∞, ∞), {x|x ∈ R}

Range: (-∞, 0), {y ≤ 0}

We used the given sector area formula, 28.25 = ∅/360 × π × 12², to find the central angle (∅) by rearranging the equation

First, we used the given sector area formula, 28.25 = ∅/360 × π × 12², to find the central angle (∅) by rearranging the equation and solving for ∅, which resulted in ∅ ≈ 22.5 degrees.

Next, we applied the arc length formula, L = ∅/360 × 2 × π × r, and plugged in the values we had, including the calculated ∅ and the given radius (12 feet).

Finally, we calculated the arc length (L) to be approximately 4.71 feet, which is the length of steel that must be replaced.

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The lengths of the sides are: AB = CD = 4.5667 inches; BC = 9.1333 inches and AD = 9.1333 inches

An isosceles trapezoid is a four-sided figure with two parallel sides and two non-parallel sides that are equal in length. In this problem, we are given that the perimeter of the isosceles trapezoid ABCD is 27.4 inches, and that BC is twice as long as AB.

Let's start by assigning variables to the lengths of the sides. Let AB = x, BC = 2x, CD = x, and AD = y. Since the perimeter of the trapezoid is the sum of all four sides, we can write the equation:

x + 2x + x + y = 27.4

Simplifying the equation, we get:

4x + y = 27.4

We also know that the non-parallel sides of an isosceles trapezoid are equal in length, so we can write:

AB = CD = x

Now we can use the fact that BC is twice as long as AB to write:

BC = 2AB

Substituting x for AB, we get:

2x = BC

Now we can use the Pythagorean theorem to find the length of AD. The Pythagorean theorem states that in a right triangle, the sum of the squares of the legs (the shorter sides) is equal to the square of the hypotenuse (the longest side). Since AD is the hypotenuse of a right triangle, we can write:

AD^2 = BC^2 - (AB - CD)^2

Substituting the values we know, we get:

y^2 = (2x)^2 - (x - x)^2

Simplifying, we get:

y^2 = 4x^2

Taking the square root of both sides, we get:

y = 2x

Now we can use the equation we found earlier to solve for x:

4x + y = 27.4

4x + 2x = 27.4

6x = 27.4

x = 4.5667

Now we can find the lengths of the other sides:

AB = CD = x = 4.5667

BC = 2AB = 2x = 9.1333

AD = y = 2x = 9.1333

So the lengths of the sides are:

AB = CD = 4.5667 inches

BC = 9.1333 inches

AD = 9.1333 inches

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The height of the Key West Lighthouse in meters is approximately 26.21 meters.

Here's how you can calculate it:

- There are 3.28 feet in a meter.

- Divide the height of the lighthouse in feet by the number of feet in a meter: 86 ÷ 3.28 = 26.21 meters (rounded to two decimal places).

- Therefore, the height of the Key West Lighthouse in meters is approximately 26.21 meters.

The particular solution for f(x) is:

f(x) = (2/3)x³/² - (17/8)x + 2

We will integrate the given differential equation twice and use the initial conditions to find the constants of integration.

Given: f"(x) = 0.25x⁻³/²

Integrating once, we get:

f'(x) = ∫(0.25x⁻³/²) dx = 0.5x¹/² + C₁

where C₁ is the constant of integration.

Using the initial condition f'(4) = -1/8, we can solve for C₁:

f'(4) = 0.5(4)¹/² + C₁ = 2 + C₁ = -1/8

C₁ = -1/8 - 2 = -17/8

So,

f'(x) = 0.5x¹/² - 17/8

Integrating again, we get:

f(x) = ∫(0.5x¹/² - 17/8) dx = (2/3)x³/² - (17/8)x + C₂

where C₂ is the second constant of integration.

Using the initial condition f(0) = 2, we can solve for C₂:

f(0) = (2/3)(0)³/² - (17/8)(0) + C₂ = 2

C₂ = 2

So, the particular solution for f(x) is:

f(x) = (2/3)x³/² - (17/8)x + 2

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Answer: x intercepts = (-1.5,0) and (-1,0)

Step-by-step explanation: Graphed it in desmos :)

The volume of the composite space figure is approximately 2818.33 cubic cm.

To find the volume of the composite space figure, we need to add the volumes of the rectangular prism and the rectangular pyramid.

The rectangular prism has a length of 26 cm, a width of 5 cm, and a height of 14 cm. So its volume is:

V_prism = length x width x height

V_prism = 26 cm x 5 cm x 14 cm

V_prism = 1820 cubic cm

The rectangular pyramid has a height of 23 cm and a rectangular base with a length of 26 cm and a width of 5 cm. To find its volume, we need to first find its base area:

A_base = length x width

A_base = 26 cm x 5 cm

A_base = 130 square cm

Then, we can use the formula for the volume of a pyramid:

V_pyramid = (1/3) x base area x height

V_pyramid = (1/3) x 130 square cm x 23 cm

V_pyramid = 998.33 cubic cm (rounded to the nearest hundredth)

To find the total volume of the composite space figure, we add the volumes of the prism and the pyramid:

V_total = V_prism + V_pyramid

V_total = 1820 cubic cm + 998.33 cubic cm

V_total = 2818.33 cubic cm (rounded to the nearest hundredth)

Therefore, the volume of the composite space figure is approximately 2818.33 cubic cm.

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To find dy for the function y = 72√x, given x = 4 and Δx = dx = 0.21, we will first find the derivative of y with respect to x and then plug in the given values.

1. Differentiate y with respect to x: y = 72√x can be rewritten as y = 72x^(1/2)
  Apply the power rule: dy/dx = 72 * (1/2)x^(-1/2)
  Simplify: dy/dx = 36x^(-1/2)

2. Plug in the given values: x = 4 and dx = 0.21
  dy/dx = 36(4)^(-1/2)
  dy/dx = 36(1/√4)
  dy/dx = 36(1/2)
  dy/dx = 18

3. Calculate dy: dy = (dy/dx) * dx
  dy = 18 * 0.21
  dy = 3.78

So, for y = 72√x, dy is 3.78 when x = 4 and Δx = dx = 0.21.

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Answer: 61 in.

Step-by-step explanation:

What you do first is you must find the total number if inches of both humans combined

132 in.

Then, you want to take the 71 in. from Michael's height, and subtract it from the total number.

132

-71

61

----------

61 in. is your answer.

The experimental probability of the computer generating a 1 is D. 40 %.

First, add up the outcomes to see the total number of times the integers were generated ;

= 36 + 11 + 13 + 12 + 18

= 90

The number of times 1 was generated was 36.

The experimental probability is therefore;

= number of times 1 was generated / total number of outcomes

= 36 / 90

= 0. 4

= 40 %

Therefore, the experimental probability of the computer generating a 1 is 40 %.

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The number of zeros are in the product of the number 50 and 6000 is 50 x 6000 = 300,000 are five.

Integers, natural numbers, fractions, real numbers, complex numbers, and quaternions are examples of typical special instances where it is possible to define the product of two numbers or the multiplication of two numbers.

A product is the outcome of multiplication in mathematics, or an expression that specifies the elements (numbers or variables) to be multiplied.

The commutative law of multiplication states that the result is independent of the order in which real or complex numbers are multiplied. The result of a multiplication of matrices or the elements of other associative algebras typically depends on the order of the components. For instance, matrix multiplication and multiplication in general in other algebras are non-commutative operations.

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Answer:

18

Step-by-step explanation:

54/g - h                              g = 6 and h = 3

54/6 - 3

= 54/3

= 18

So, the answer is 18.

The inverse functions:

f'(2) = 4.

[tex]f^{-1}(x)[/tex] = sqrt(x - 4).

f'(s1(x)) = sqrt(x - 4).

(a) To find f'(2), we need to take the derivative of f(x) with respect to x and then substitute x = 2.
[tex]f(x) = x^2 + 4[/tex]
f'(x) = 2x
f'(2) = 2(2) = 4
Therefore, f'(2) = 4.
(b) To find the inverse function [tex]f^{-1}(x)[/tex], we need to first solve for x in terms of f(x) and then switch the roles of x and f(x).
[tex]f(x) = x^2 + 4[/tex]
[tex]x^2[/tex] = f(x) - 4
x = sqrt(f(x) - 4)
Switching x and f(x), we get:
[tex]f^{-1}(x)[/tex] = sqrt(x - 4)
Therefore, the inverse function is [tex]f^{-1}(x)[/tex] = sqrt(x - 4).
(c) To find the compound function f'(s1(x)),

we need to first find s1(x) and then take the derivative of f(x) with respect to s1(x) and then multiply by the derivative of s1(x) with respect to x.
s1(x) = sqrt(x - 4)
f(s1(x)) = (sqrt(x - 4)[tex])^2[/tex] + 4 = x
Taking the derivative of f(x) with respect to s1(x), we get:
f'(s1(x)) = 2s1(x)
Taking the derivative of s1(x) with respect to x, we get:
s1'(x) = 1/(2sqrt(x - 4))
Multiplying these two derivatives, we get:
f'(s1(x))s1'(x) = 2s1(x) * 1/(2sqrt(x - 4))
f'(s1(x))s1'(x) = sqrt(x - 4)
Therefore, the compound function is f'(s1(x)) = sqrt(x - 4).
(d) The given expression "derivative mets-() de 1-12" does not make sense and seems incomplete. Please provide more information or context so that I can help you with this part of the question.

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1) There are 1854 ways to return the hats so that no gentleman receives his own hat.

2) There are 3186 ways to return the hats so that at least one of the gentlemen receives his own hat.

3) There are 865 ways to return the hats so that at least two of the gentlemen receive their own hats.

1) This problem involves the concept of permutations. A permutation is an arrangement of objects in a particular order. In this case, we need to find the number of permutations for returning the hats of the gentlemen.

To find the number of ways that no gentleman receives his own hat, we can use the principle of derangements. A derangement is a permutation of a set of objects such that no object appears in its original position.

The number of derangements of a set of n objects is denoted by !n and can be calculated using the formula:

!n = n!(1 - 1/1! + 1/2! - 1/3! + ... + (-1)^n/n!)

For n = 7, we have

!7 = 7!(1 - 1/1! + 1/2! - 1/3! + 1/4! - 1/5! + 1/6!)

= 1854

Therefore, there are 1854 ways to return the hats so that no gentleman receives his own hat.

2) To find the number of ways that at least one of the gentlemen receives his own hat, we can use the complementary principle. The complementary principle states that the number of outcomes that satisfy a condition is equal to the total number of outcomes minus the number of outcomes that do not satisfy the condition.

The total number of ways to return the hats is 7!, which is 5040. The number of ways that no gentleman receives his own hat is 1854 (as we found in part 1). Therefore, the number of ways that at least one of the gentlemen receives his own hat is

5040 - 1854 = 3186

Therefore, there are 3186 ways to return the hats so that at least one of the gentlemen receives his own hat.

3) To find the number of ways that at least two of the gentlemen receive their own hats, we can use the inclusion-exclusion principle. The inclusion-exclusion principle states that the number of outcomes that satisfy at least one of several conditions is equal to the sum of the number of outcomes that satisfy each condition minus the sum of the number of outcomes that satisfy each pair of conditions, plus the number of outcomes that satisfy all of the conditions.

In this case, the conditions are that each of the seven gentlemen receives his own hat. The number of outcomes that satisfy each condition is 6!, which is 720. The number of outcomes that satisfy each pair of conditions is 5!, which is 120. The number of outcomes that satisfy all of the conditions is 4!, which is 24.

Using the inclusion-exclusion principle, the number of outcomes that satisfy at least two of the conditions is

6! - (7C₂)5! + (7C₃)4! - (7C₄)3! + (7C₅)2! - (7C₆)1! + 0!

= 720 - (21)(120) + (35)(24) - (35)(6) + (21)(2) - (7)(1) + 0

= 720 - 2520 + 840 - 210 + 42 - 7 + 0

= 865

Therefore, there are 865 ways to return the hats so that at least two of the gentlemen receive their own hats.

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To find the possible Hamiltonian circuits that begin with JVTSR, we can start by constructing a path that begins with JVTSR and visits each vertex exactly once. Such a path must be of the form JVTSRX, where X is the remaining vertex.

Case 1: JVTSRQX

To find the possible value of X, we note that the only edges incident to J are V and T, and the only edges incident to Q are S and R. Thus, we must have X = S or X = R, and the circuits are JVTSRQS and JVTSRQR.

Case 2: JVTSRXQ

To find the possible value of X, we note that the only edges incident to X are S and L. Thus, we must have X = L, and the circuit is JVTSRLQ.

Case 3: JVTSRLX

To find the possible value of X, we note that the only edges incident to J are V and T, and the only edges incident to L are T and R. Thus, we must have X = R, and the circuit is JVTSRLR.

Case 4: JVTSRXL

To find the possible value of X, we note that the only edges incident to Q are S and R, and the only edges incident to X are L and S. Thus, we must have X = L, and the circuit is JVTSRQL.

Therefore, there are four possible Hamiltonian circuits that begin with JVTSR: JVTSRQS, JVTSRQR, JVTSRLQ, and JVTSRLR.

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