how do i change a mixed number to a improper fraction and simplify

Answer:

[tex]3\sqrt{5}[/tex]

Step-by-step explanation:

Use the distance formula to determine the distance between the two points.

Distance = [tex]\sqrt{(1-4)^{2} + (4-(-2))^{2} }[/tex]

Simplify, and you get the answer.

[tex]3\sqrt{5}[/tex]

The area enclosed by the circle is given as 7494.12 m² and the mistake Frank have made is he subtracted the area of the square and the area of 4 semi-circles.

We are given that the figure is made by attaching semicircles to each side of a 54 dash m​-by-54 dash m square. Frank says the area is 1 comma 662.12 m squared.

We have to find the error made by Frank,

Area of the square = Side of the square x Side of the square

In the question; the side of the square given is 54 m and this would also be the diameter of the semicircle attached to each side of a square.

So, the radius of the semicircle = diameter /2  = 54/2 = 27 m

Now, the area of the square = 54 x 54 = 2916 m².

Also, the area of the semi-circle = [tex]\frac{\pi r^2}{2}[/tex] = [tex]\frac{3.14*27^2}{2}[/tex] = 1144.53 m² .

As there are a total of 4 semi-circles attached to the square, so the area of all the 4 semi-circles = 4 x 1144.53  = 4578.12

Now, the total area of the figure = Area of the square + Area of 4 semi-circles

                = 2916 + 4578.12

                = 7494.12 m².

The error made by Frank was that he subtracted the area of the square and the area of 4 semi-circles to find the area of the whole figure as (4578.12  - 2916  = 1662.12 ).

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Complete question:

Frank needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 54 m​-by-54 m square. Frank says the area is 1662.12 meter squared. Find the area enclosed by the figure. Use 3.14 for pi. What error might Frank have​ made?

The average rate of change of the function f(x) in the interval [tex]-3 \leq x\leq -2[/tex] is -15.

We are given an interval in which we have to find the average rate of change of the function f(x) based on the graph given in the question. The interval given is -3 [tex]\leq[/tex] x [tex]\leq[/tex] -2. We are going to apply the formula for an average rate of change to find the rate of change of the given function in the given interval.

The formula we will use is

The average rate of change = [tex]\frac{f(b) - f(a) }{b - a}[/tex]

Identifying the points in the graph,

a = 3, f(a) = -10

b = -2, f(b) = -25

We will substitute these values in the formula for the average rate of change.

The average rate of change = [tex]\frac{-25-(-10)}{-2-(-3)}[/tex]

The average rate of change = ( -25 + 10)/(-2 +3)

= -15/1

= -15.

Therefore, the average rate of change of the function in the interval [tex]-3 \leq x \leq -2[/tex] is -15.

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The complete question is "The function y=f(x)y=f(x) is graphed below. What is the average rate of change of the function f(x)f(x) on the interval -3\le x \le -2 −3≤x≤−2? "

The population density of manatees within a radius of 5 miles of a half circle off of Crystal Bay is approximately 14 manatees per square mile

The population density of manatees within a radius of 5 miles of a half circle off of Crystal Bay is approximately 70 manatees per square mile. To calculate this, we first need to find the area of the half circle. Using the formula for the area of a circle, A=πr^2, where r is the radius, we can find the area of the full circle with a radius of 5 miles:

A = 3.14 x 5^2
A = 78.5 square miles

Since we only want to consider the area of the half circle, we divide this by 2:

A = 78.5 / 2
A = 39.25 square miles

Now we can calculate the population density by dividing the number of manatees by the area:

Density = 550 / 39.25
Density ≈ 14

Therefore, the population density of manatees within a radius of 5 miles of a half circle off of Crystal Bay is approximately 14 manatees per square mile. Rounded to the nearest whole number, this is 14.

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The ∠EBC and ∠FCD are corresponding angles.Option(C) is Crrect.

Corresponding angles are angles that are in matching or corresponding positions when two parallel lines are intersected by a transversal. In other words, corresponding angles are pairs of angles that occupy the same relative position at each intersection of a transversal and parallel lines.

More specifically, if two parallel lines, line AB and line CD, are intersected by a transversal, line EF, at point G, then the angles that are opposite each other (one on each line) are corresponding angles. The corresponding angles are denoted by the same letter or symbol.

So, ∠EBC and ∠FCD are corresponding angles.Option(C) is Correct.

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The function rule for the statement "the output is eight less than the input" is a simple mathematical expression that represents a relationship between the input and output values.

In this case, it can be expressed as Output = Input - 8. The function takes the input value, subtracts 8 from it, and returns the result as the output value. This rule ensures that the output will always be eight units smaller than the input. For example, if the input is 15, the output will be 7. This function rule can be used to perform calculations or model various scenarios where the output is consistently eight units less than the input.

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The directional derivative of the function f(x, y) = 3x^2 - y^2 + 4 at P(3, 1) in the direction of PQ is -24/sqrt(10).

To find the directional derivative of the function f(x, y) = 3x^2 - y^2 + 4 at point P(3, 1) in the direction of PQ, follow these steps:

Step 1: Compute the gradient of the function. The gradient of f(x, y) is given by the partial derivatives with respect to x and y: ∇f(x, y) = (df/dx, df/dy) = (6x, -2y)

Step 2: Calculate the gradient at point P(3, 1). ∇f(3, 1) = (6(3), -2(1)) = (18, -2)

Step 3: Calculate the unit vector in the direction of PQ. First, find the difference vector PQ = Q - P = (2-3, 4-1) = (-1, 3). Next, find the magnitude of PQ: |PQ| = sqrt((-1)^2 + (3)^2) = sqrt(10). Then, calculate the unit vector uPQ = PQ / |PQ| = (-1/sqrt(10), 3/sqrt(10)).

Step 4: Compute the directional derivative of f at P in the direction of PQ. The directional derivative, D_uPQ f(P), is given by the dot product of the gradient at P and the unit vector uPQ: D_uPQ f(P) = ∇f(P) • uPQ = (18, -2) • (-1/sqrt(10), 3/sqrt(10)) = 18(-1/sqrt(10)) - 2(3/sqrt(10)) = -18/sqrt(10) - 6/sqrt(10) = -24/sqrt(10)

So the directional derivative of the function f(x, y) = 3x^2 - y^2 + 4 at P(3, 1) in the direction of PQ is -24/sqrt(10).

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To find dx dy, we need to take the derivative of y with respect to x. Using the chain rule, we have:

dy/dx = d(Vx)/dx = V * d(x)/dx + x * d(V)/dx

Since we are given y = Vx, we can substitute and simplify:

dy/dx = y/x * d(V)/dx + V

Now we can plug in the given values: y = 8, dt/dx = 1.75. We also need to find V:

y = Vx, so V = y/x = 8/x

Now we can substitute and simplify again:

dy/dx = 8/x * d(V)/dx + 8/x

We need to find d(V)/dx. We know that t = f(x,V), so we can use the chain rule again:

dt/dx = df/dx + df/dV * dV/dx

Since t and V are independent, df/dV = 0. So we have:

dt/dx = df/dx + 0 * dV/dx

dt/dx = df/dx

We also know that dt/dx = 1.75. Therefore:

1.75 = df/dx

Now we can find d(V)/dx:

d(V)/dx = d/dx (y/x) = (dy/dx * x - y * dx/dx) / x^2

Since y = 8, we have:

d(V)/dx = (dy/dx * x - 8) / x^2

Substituting what we know, we get:

d(V)/dx = (8/x * 1.75 - 8) / x^2 = 8(1.75 - x) / x^3

Now we can substitute everything into the formula we derived earlier:

dy/dx = 8/x * d(V)/dx + 8/x

dy/dx = 8/x * (8(1.75 - x) / x^3) + 8/x

Simplifying, we get:

dy/dx = 14/x^2 - 1.75

Therefore, when y = 8 and dt/dx = 1.75, dx/dy = 1/(dy/dx) is:

dx/dy = 1 / (14/x^2 - 1.75) = x^2 / (14 - 1.75x^2)
Given y = √x, we first need to find dy/dx, the derivative of y with respect to x. Using the power rule, we can rewrite y = x^(1/2), and the derivative will be:

dy/dx = (1/2)x^(-1/2)

Now, we are given that y = 8, so we need to find the corresponding value of x:

8 = √x
64 = x

Next, we are given dt/dx = 1.75. We need to find dt/dy, which can be calculated by taking the reciprocal of dy/dx:

dt/dy = 1 / (dy/dx)

Now, we substitute x = 64 into the derivative:

dy/dx = (1/2)(64)^(-1/2) = (1/2)(8)^(-1) = 1/16

Finally, we can find dt/dy by taking the reciprocal of dy/dx:

dt/dy = 1 / (1/16) = 16

So, the value of dt/dy when y = 8 and dt/dx = 1.75 is 16.

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Answer:

Set your calculator to degree mode.

tan(37°) = x/8

x = 8tan(37°) = 6.03

For the given triangle the required value of the x is approximately 6.02 units.

Use the concept of triangle defined as:

A triangle is a three-sided polygon, which has three vertices and three angles which has a sum of 180 degrees.

In the given triangle:

One angle is 37°

Adjacent side = 8 cm

Perpendicular = x

Since we know that,

Tan θ = opposite/adjacent

Therefore,

Tan 37° = x/8

Since Tan 37° ≈ 0.753

Then, 0.753  ≈  x/8

x ≈ 6.02 units

Hence,

The required value of x is approximately 60.2 units.

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Tank B fills faster than Tank A, taking approximately 1.75 minutes to fill while Tank A takes approximately 1.14 minutes.

The problem presents two aquarium tanks, A and B, which are of the same size but have different water levels and fill rates. Tank A has 2 feet of water and is being filled at a rate of 2.2 inches per minute, while Tank B has 8 feet of water and is being filled at a faster rate of 5 inches per minute. The goal is to determine how long it will take to fill each tank.

To solve this problem, we need to use the formula: Time = Volume / Rate. We know that the volume of each tank is the same, so we can set up two equations:

For Tank A: Time = (2 feet * 12 inches/foot) / 2.2 inches/minute = 10.91 minutes or approximately 1.14 minutes.

For Tank B: Time = (8 feet * 12 inches/foot) / 5 inches/minute = 19.2 minutes or approximately 1.75 minutes.

Therefore, Tank A will take approximately 1.14 minutes to fill, while Tank B will take approximately 1.75 minutes to fill. It is important to note that Tank B is being filled at a faster rate than Tank A, despite having a greater volume of water.

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Answer:

B. ∠FBG

Step-by-step explanation:

When an angle is in the three letter form, the first letter is the first line that forms the angle, the second letter is where the angle is located, and third letter is the line that forms the angle with the first line.

Thus, we can see that line E combines with line F, and the actual angle is located at point B.

The two angles adjacent to ∠EBF are ∠DBE and ∠FBG.  Only ∠FBG is one of the answer choices so this is our final answer.

The transformation that  verify that the two triangles f and c are similar are

Rotation: The first procedure is rotating triangle C with center art vertex (-9, 2) counterclockwise 90 degrees

Translation: In this case, the triangle is to the right 1 unit and 2 units up

Dilation: The dilation factor here is 2. Using the vertex of of the point which is (-8, 0) as the center, dilate with a scale factor of two

The transformations described moves triangle F to triangle C

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Out of the 150 new couples, we can expect about:

45 * (150/240) = 28.125 couples where the husband prefers action but the wife does not.

30 * (150/240) = 18.75 couples where the wife prefers action but the husband does not.

What is probability?

Probability is a measure of the likelihood of an event occurring.

Based on the given data from the survey of 225 couples, we can construct a contingency table as follows:

                      Husband   Wife   Total

Action                45          30        75

Comedy            30          45        75

Drama               45          45        90

Total                 120        120       240

From the contingency table, we can see that:

Out of 240 respondents, 75 (45 from husbands and 30 from wives) preferred action movies.

Out of 240 respondents, 60 (30 from husbands and 30 from wives) preferred comedy movies.

Out of 240 respondents, 90 (45 from husbands and 45 from wives) preferred drama movies.

To answer the question of how many of the 150 couples will have exactly one spouse who prefers action movie, we can use the information that:

Out of 240 respondents, 45 husbands preferred action movies but their wives did not.

Out of 240 respondents, 30 wives preferred action movies but their husbands did not.

Therefore, out of the 150 new couples, we can expect about:

45 * (150/240) = 28.125 couples where the husband prefers action but the wife does not.

30 * (150/240) = 18.75 couples where the wife prefers action but the husband does not.

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To find the probability of scoring at least 700 points on the Algebra EOC, we calculate the z-score, which is -0.122, and then find the area under the standard normal curve using a z-table. The probability is 54.98%. Since this is higher than the significance level of 0.05, we can conclude that the student has met the requirement to earn 3 points on the EOC.

Identify the mean, standard deviation, and score needed to earn 3 points

Mean (μ) = 704.39

Standard deviation (σ) = 36.18

Score needed for 3 points = 700

Calculate the z-score for the score needed to earn 3 points

z = (score - μ) / σ

= (700 - 704.39) / 36.18

= -0.122

Look up the area to the left of the z-score in the standard normal distribution table

The area to the left of -0.122 is 0.4502.

Subtract the area found in step 3 from 1 to find the area to the right of the z-score

Area to the right = 1 - 0.4502 = 0.5498

Convert the area to the right into a percentage

Percentage = 0.5498 x 100% = 54.98%

Interpret the percentage as the probability of earning 3 points or more on the Algebra EOC exam:

The probability of earning 3 points or more on the Algebra EOC exam is 54.98%.

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--The given question is incomplete, the complete question is given

" In order to graduate from Ohio, you need to earn 3 points on an Algebra EOC or score remediation

free scores on the ACT and SAT math exams. The EOC exams are normally distributed with a mean of 704.39

and a standard deviation of 36.18. A score of 700 is needed to earn 3 points.

a. Fill in the values of each standard deviation above and below the mean, and make sure to add in the value

of the mean. Answers only are fine. "--

The sequence of transformations the triangle XYZ have gone through to produce figure X'Y'Z' is: D. Rotation 90° counterclockwise, reflection across the y-axis.

Transformation is a method required to change the orientation, or resize a given object to produce its image. Some of the types of transformation are: rotation, reflection, dilation, and translation.

Rotation requires turning a given object about a point at a certain angle.

Reflection implies flipping an object over a line as a reference point.

Dilation deals with either increasing or decreasing the dimensions of a given object.

Translation involves moving an object in a specific direction and given number of units.

Considering triangle XYZ and the figure produced, we can conclude that:

The sequence of transformations the triangle XYZ have gone through to produce figure X'Y'Z' is: D. Rotation 90° counterclockwise, reflection across the y-axis.

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Following an exponential distribution with a mean of 15 seconds, the 60th percentile for the amount of time between customers entering Clay's store is approximately 13.74 seconds.

Based on the information provided, Clay's grocery store experiences customer arrivals following an exponential distribution with a mean of 15 seconds. To find the 60th percentile for the amount of time between customers entering the store, we can use the following formula:

Percentile = Mean * ln(1 / (1 - Percentile in Decimal Form))

In this case, the 60th percentile in decimal form is 0.6. Plugging the values into the formula, we get:

60th Percentile = 15 * ln(1 / (1 - 0.6))

60th Percentile ≈ 15 * ln(1 / 0.4)

60th Percentile ≈ 15 * ln(2.5)

60th Percentile ≈ 15 * 0.9163

60th Percentile ≈ 13.74 seconds

Thus, the 60th percentile for the amount of time between customers entering Clay's store is approximately 13.74 seconds.

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If A large moving box has a volume of 45 cubic meters then two possible sets of dimensions for the box are: 1.5 m x 5 m x 9 m, and 1.5 m x 3 m x 15 m.

One possible way to approach this problem is to use trial and error. Therefore, two possible sets of dimensions for the box are 1.5 m x 5 m x 9 m, and 1.5 m x 3 m x 15 m.

We know that the volume of the box is 45 cubic meters and that the width is 1.5 meters. We want to find two whole numbers for the length and height that work.

We can start by listing the factors of 45: 1, 3, 5, 9, 15, and 45. We can then try each of these factors as the length or height, and see if the other dimension is a whole number greater than 2.

For example, if we try length = 5, then the height would need to be 9 to get a volume of 45. However, the width would be 1.5, which is already less than 2, so this doesn't work. These are the dimensions.

Trying again, if we try length = 9, then the height would need to be 5 to get a volume of 45. In this case, the width would be height = 5, which is greater than 2, so this is a possible answer.

Continuing, if we try length = 3, then the height would need to be 15 to get a volume of 45. This gives us a width of 1.5, which is less than 2, so this doesn't work.

Finally, if we try length = 15, then the height would need to be 3 to get a volume of 45. This gives us a width of height = 3, which is greater than 2, so this is another possible answer.

Therefore, two possible sets of dimensions for the box are: 1.5 m x 5 m x 9 m, and 1.5 m x 3 m x 15 m.

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The expression to show the total volume of the two boxes is:

100 + [tex]s^3[/tex] ([tex]in^3[/tex])

We can start by finding the volume of the smaller box using the formula for the volume of a cube:

Volume of smaller box = (length of one side)^3 = 100 in^3

Taking the cube root of both sides, we get:

Length of one side = ∛100 in ≈ 4.64 in

Now, we can use this value to find the volume of the larger box:

Volume of larger box = (length of one side)[tex]^3 = s^3[/tex]

The total volume of both boxes is the sum of the volume of the smaller box and the volume of the larger box:

Total volume = Volume of smaller box + Volume of larger box

Total volume = 100 in [tex]^3 + s^3[/tex]

Therefore, the expression to show the total volume of the two boxes is:

100 + [tex]s^3[/tex] (in[tex]^3[/tex])

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The volume of the solid obtained by rotating the region about the line x=9 is approximately 201.06 cubic units.

To find the volume of the solid obtained by rotating the region bounded by 2 =8 32? and 2 = -2y about the line x= 9, we can use the cylindrical shell method.

First, we need to sketch the region and the line of rotation:

  |         +---------+

8 |         |         |

  |         |         |

  |         +---------+ x=9

  |              

0 +---------------+

  0      4      8

The region is a rectangle with height 4 and width 8, centered at the origin. The line of rotation is x=9.

Now, we can express the volume of the solid as a sum of cylindrical shells:

V = ∫[0,4] 2πr h dx

where r is the distance between x=9 and the boundary of the region at height x, and h is the thickness of the shell.

Since the region is symmetric about the y-axis, we can consider only the right half of the region and multiply the result by 2 to get the total volume.

The equation of the boundary at height x is:

2 = -2y

y = -x/2

The distance between x=9 and this line is:

r = 9 - (-x/2) = 9 + x/2

The thickness of the shell is dx.

Substituting these values into the integral, we get:

V = 2 ∫[0,4] 2π(9 + x/2) dx

V = 2π ∫[0,4] (18 + x) dx

V = 2π [18x + (1/2)[tex]x^2[/tex]] from x=0 to x=4

V = 2π [(18*4 + (1/2)[tex]4^2[/tex]) - (180 + (1/2)*[tex]0^2[/tex])]

V = 64π ≈ 201.06

Therefore, the volume of the solid obtained by rotating the region about the line x=9 is approximately 201.06 cubic units.

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The general solution is then [tex]y(x) = y_c(x) + yp(x) = c1 e^√2x + c2 e^-√2x - 3/2 cot^3 x.[/tex]

To find the general solution for the nonhomogeneous equation [tex]y'' = 2y + 12 cot^3x[/tex] with particular solution

yp(x) = 6 cotx, we can use the method of undetermined coefficients.

First, we need to find the complementary function, which is the general solution to the homogeneous equation y'' = 2y. The characteristic equation is r² - 2 = 0, which has roots r = ±√2.

Therefore, the complementary function is[tex]y_c(x) = c1 e^√2x + c2 e^-√2x.[/tex]

Next, we need to find a particular solution yp(x) to the nonhomogeneous equation. Since the right-hand side is 12 cot^3 x, we can guess a solution of the form [tex]yp(x) = a cot^3 x.[/tex] Taking the first and second derivatives of this, we get

[tex]yp''(x) = -6 cotx - 18 cot^3 x and yp'''(x) = 54 cot^3 x + 54 cotx.[/tex]

Substituting these into the original equation, we get:

[tex](-6 cotx - 18 cot^3 x) = 2(a cot^3 x) + 12 cot^3 x-6 cotx = 2a cot^3 x[/tex]
a = -3/2

Therefore, the particular solution is[tex]yp(x) = -3/2 cot^3 x.[/tex]

The general solution is then [tex]y(x) = y_c(x) + yp(x) = c1 e^√2x + c2 e^-√2x - 3/2 cot^3 x.[/tex]

So the final answer is [tex]y(x) = y_c(x) + yp(x) = c1 e^√2x + c2 e^-√2x - 3/2 cot^3 x.[/tex]

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Therefore, the probability of the curious pattern occurring is 1/36.

Probability theory is an important branch of mathematics that is used to model and analyze random phenomena, such as the outcomes of games of chance, the behavior of particles in physics, or the performance of complex systems in engineering. It has many practical applications in fields such as statistics, finance, economics, and computer science.

Here,

The probability of rolling a number greater than 3 on a fair die is 3/6 = 1/2, since there are three numbers (4, 5, 6) that satisfy this condition out of the six possible outcomes.

Similarly, the probability of rolling a number greater than 4 on a fair die is 2/6 = 1/3, and the probability of rolling a number greater than 5 is 1/6.

Since each roll is independent, we can multiply these probabilities together to get the probability that all three conditions are satisfied:

P = (1/2) × (1/3) × (1/6)

= 1/36

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There are 5 combinations with one flavor, 10 combinations with two flavors, and 10 combinations with three flavors, resulting in 25 possible combinations in total.

a. Only one flavor is there.

b. Buko can be paired with 4 other flavors and Ube can be paired with 3 remaining flavors.

c. 10 combinations of three flavors.

a. There is only one flavor: Since the box contains only one flavor, there are 5 possible combinations (Buko, Ube, Pineapple, Yema, and Mango).

b. There are two flavors:
- Buko can be paired with 4 other flavors (Ube, Pineapple, Yema, Mango).
- Ube can be paired with 3 remaining flavors (Pineapple, Yema, Mango).
- Pineapple can be paired with 2 remaining flavors (Yema, Mango).
- Yema can be paired with 1 remaining flavor (Mango).
In total, there are 10 combinations of two flavors.

c. There are three flavors:
- There are 5 flavors in total, and we want to choose 3. We can use the formula for combinations: C(n, k) = n! / (k!(n-k)!), where n is the total number of flavors and k is the number of flavors to choose.
- C(5, 3) = 5! / (3!(5-3)!) = 10 combinations of three flavors.

So, there are 5 combinations with one flavor, 10 combinations with two flavors, and 10 combinations with three flavors, resulting in 25 possible combinations in total.

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Answer:

91%

Step-by-step explanation:

The ratio expressing the slope of line k is -2/3.

The ratio expressing the slope of k can be found by using the slope formula, which is: slope = (y₂ - y₁) / (x₂ - x₁), where (x₁, y₁) and (x₂, y₂) are the two given points on the line.

Plugging in the given values, we get:

slope = (-1 - 3) / (2 - (-4))

slope = -4 / 6

slope = -2/3

Therefore, the slope of the line passing through the two given points is -2/3.

To express this slope as a ratio, we can write it as:

-2:3

which means that for every decrease of 2 units in the y-coordinate, there is a corresponding decrease of 3 units in the x-coordinate.

This ratio can also be written as 2: -3 to indicate that for every increase of 2 units in the y-coordinate, there is a corresponding decrease of 3 units in the x-coordinate.

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The correct answer is option 2. Yes, the mean of the sample proportions is 0.6, which is the same as the population proportion.

To determine if the sample proportion is an unbiased estimator, we need to check if the mean of the sample proportions equals the population proportion. In this case, the population proportion of officers who are younger than 18 is given as 0.6. The sample proportions for all possible samples of size 2 are calculated and given in the table.
To calculate the mean of the sample proportions, we add up all the proportions in the table and divide by the total number of samples, which is 9.
Mean of sample proportions = (0 + 0.5 + 0.5 + 0.5 + 0.5 + 0.5 + 1 + 1 + 1) / 9 = 0.6
Since the mean of the sample proportions equals the population proportion, we can say that the sample proportion is an unbiased estimator.

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1) The maximum amount you should spend on rent is $840.

2) The maximum amount you should spend on rent is $570.

3) Your monthly income must be at least $2,733.33 to afford this apartment.

4) Your monthly income must be at least $3,000 to afford this apartment.

5) You need $1,980 to start renting the apartment.

1) With a monthly income of $2,800, the maximum amount you should spend on rent can be calculated using the 30% rule.
$2,800 x 0.30 = $840
So, the maximum amount you should spend on rent is $840.

2) With a monthly income of $1,900, the maximum amount you should spend on rent can be calculated using the 30% rule.
$1,900 x 0.30 = $570
So, the maximum amount you should spend on rent is $570.

3) To afford an apartment that rents for $820, your monthly income should be:
$820 ÷ 0.30 = $2,733.33
So, your monthly income must be at least $2,733.33 to afford this apartment.

4) To afford an apartment that rents for $900, your monthly income should be:
$900 ÷ 0.30 = $3,000
So, your monthly income must be at least $3,000 to afford this apartment.

5) To start renting an apartment that costs $665/month, you need the first and last month's rent, and a $650 security deposit.
First and last month's rent: $665 x 2 = $1,330
Total amount needed: $1,330 + $650 = $1,980
So, you need $1,980 to start renting the apartment.

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The value of x such that fg(x) = 20 is 6.5.

To find the composite function fg(x), we need to substitute the expression for g(x) into f(x), as follows:

fg(x) = f(g(x)) = f(x + 4) = 2(x + 4) - 1 = 2x + 7

So, fg(x) = 2x + 7

ii) To find the value of x such that fg(x) = 20, we can substitute fg(x) into the equation and solve for x, as follows:

fg(x) = 2x + 7 = 20

2x = 13

x = 6.5

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The point estimate for μ is 15.3 years, based on the sample of 60 Grade 9 students.

Based on the statistical techniques given information, the point estimate for the population mean age of all Grade 9 students is 15.3 years. This means that if we assume that the sample is representative of the entire population of Grade 9 students, then we estimate that the average age of all Grade 9 students is 15.3 years.

To estimate the precision of this point estimate, we can calculate confidence intervals. For a 95% confidence interval, we can use the formula:

CI = X ± (Zα/2) * (σ/√n)

where X is the point estimate, Zα/2 is the critical value of the standard normal distribution for a 95% confidence level (1.96), σ is the population standard deviation (which we assume to be known as 4), and n is the sample size (which is 60).

Substituting the values, we get the 95% confidence interval as:

CI = 15.3 ± (1.96) * (4/√60) = (14.33, 16.27)

This means that we can be 95% confident that the true population mean age of Grade 9 students lies between 14.33 and 16.27 years.

For a 99% confidence interval, we can use the same formula with a different value of Zα/2 (2.58 for a 99% confidence level). Substituting the values, we get the 99% confidence interval as:

CI = 15.3 ± (2.58) * (4/√60) = (13.94, 16.66)

This means that we can be 99% confident that the true population mean age of Grade 9 students lies between 13.94 and 16.66 years.

Based on the confidence intervals, we can conclude that the sample provides evidence that the true mean age of all Grade 9 students is likely to be between 14.33 and 16.27 years with a 95% confidence level, and between 13.94 and 16.66 years with a 99% confidence level. However, we cannot be completely certain that the true population mean falls within these intervals as there is always some level of uncertainty associated with sample-based estimates.

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Given that 0 < p < 1 for X~B(5,p) and P(X=3) = P(X=4), so the value of p is 2/3.

We know that X~B(5,p) and P(X=3) = P(X=4).

Using the probability mass function of a binomial distribution, we can write:
P(X=3) = (5 choose 3) * p³ * (1-p)²
P(X=4) = (5 choose 4) * p⁴ * (1-p)¹

Since P(X=3) = P(X=4), we can set these two expressions equal to each other and simplify:
(5 choose 3) * p^3 * (1-p)² = (5 choose 4) * p⁴ * (1-p)¹
10p^3(1-p)^2 = 5p^4(1-p)

Dividing both sides by [tex]p^{3(1-p)[/tex] and simplifying, we get:
10(1-p) = 5p
10 - 10p = 5p
10 = 15p
p = 2/3

Therefore, the value of p is 2/3, given that 0 < p < 1.

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Answer:

5x-9

Step-by-step explanation:

Distribute: 3x-(2x+9) + 4x

3x - 2x - 9 + 4x

Combine Like Terms: 3x - 2x - 9 + 4x

5x-9