How can a water molecule from an apple eventually make its way inside a cloud and then back to Earth?

Answers

Answer 1
the molecule can evaporate into a cloud and then be rained back down
Answer 2

When an apple tree takes up water from the soil, it moves up through the roots, stems, and into the leaves. In the leaves, water is combined with carbon dioxide during photosynthesis to create glucose (sugar) and oxygen. Through transpiration, water is released from the leaves back into the atmosphere. This water vapor can then rise and eventually form clouds through a process called condensation, in which the water vapor cools and changes into liquid droplets or ice crystals. When the clouds become heavy with moisture, precipitation occurs, such as rain or snow, and the water droplets or ice crystals fall back to Earth. Therefore, a water molecule from an apple can eventually end up in a cloud and back to Earth through the natural water cycle.


Related Questions

The map shows Earth's ntinent
reached from the information on the map?
Volcanoes are scattered randomly across Earth.
Volcanoes are only located along edges of continents.
Volcanoes are mostly located along boundaries between
plates.
Volcanoes are distributed equally in the Northern and
Southern Hemispheres.
K
SUBMIT
1:44/26:58 Earths continents >
World Map of Continents
HutH
Continents, Plates, and Volcanoes on Earth
Source: United States Geological Survey
HALL
Expand+
-active volcano
plate boundary line
-equator
8
CC

Answers

Answer:

1:44/26:58 earths continents>would Map of continent

A physics professor is pushed up a ramp inclined upward at an angle 29.0 ∘
above the horizontal as he sits in his desk chair that slides on frictionless rollers. The combined mass of the professor and chair is 90.0 kg. He is pushed a distance 2.55 m
along the incline by a group of students who together exert a constant horizontal force of 610 N. The professor's speed at the bottom of the ramp is 2.15 m/s. Use the work-energy theorem to find his speed at the top of the ramp.

Answers

The speed of the professor and his chair at the top of the ramp is 3.47 m/s.

What is work energy theorem?

The work-energy theorem states that the net work done on an object is equal to the change in its kinetic energy. In this problem, we can use this theorem to relate the work done by the students to the change in the kinetic energy of the professor and his chair.

We can start by finding the gravitational potential energy of the professor and his chair at the top and bottom of the ramp. At the top of the ramp, the gravitational potential energy is:

U_top = mgh_top

= (90.0 kg)(9.81 m/s^2)(2.55 m)sin(29.0∘)

= 985.2 J

where;

g is the acceleration due to gravity and h_top is the height of the top of the ramp relative to some reference level (we assume that the reference level has zero potential energy).

At the bottom of the ramp, the gravitational potential energy is:

U_bottom = mgh_bottom

= (90.0 kg)(9.81 m/s^2)(0 m)sin(29.0∘)

= 0 J

since the bottom of the ramp is the reference level.

The initial kinetic energy of the professor and his chair is:

K_i = (1/2)mv_i^2

= (1/2)(90.0 kg)(2.15 m/s)^2

= 214.84 J

where;

v_i is the initial speed of the professor and his chair at the bottom of the ramp.

The final kinetic energy of the professor and his chair at the top of the ramp is:

K_f = (1/2)mv_f^2

where;

v_f is the speed we want to find.

Since the rollers are frictionless, the only work done on the professor and his chair is the work done by the students. Therefore, the net work done on the professor and his chair is:

W_net = F_horizontal*d

= (610 N)(2.55 m)

= 1555.5 J

According to the work-energy theorem, the net work done on the professor and his chair is equal to the change in their kinetic energy:

W_net = K_f - K_i

Substituting the expressions for W_net, K_f, and K_i, we get:

1555.5 J = (1/2)(90.0 kg)(v_f^2) - 214.84 J

Solving for v_f, we get:

v_f = √[(2(1555.5 J + 214.84 J))/(90.0 kg)]

= 3.47 m/s

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The table below shows data of sprints of animals that traveled 75 meters. At each distance marker, the animals' times were recorded.

Which animal moves with accelerated motion?

Animal 1
Animal 2
Animal 3
Animal 4

Answers

Animal 1 moves with accelerated motionnnn hope that helped<3

Answer: Animal 1

Explanation: animal 1 has the shortest seconds of running fast dunununun

Hang the block of mass 50 g to the spring on the left and measure the period of oscillation T using the stop watch located on the right of the screen (drag the stop watch outside its box). It might be easier if Slow speed is selected. Repeat ten times your measurements of the period and record your data.
What is average value of T? What is the standard deviation of T? Use your average value of T and Eq to find the sprint constant k (N/m)

Answers

Once the average value of T and its standard deviation are determined, the spring constant k can be calculated using the equation k = 4π^2m/T^2, where m is the mass of the block.

To find the average value of T, the ten measurements of T are added together and divided by ten. The standard deviation of T is calculated using the formula that involves finding the square root of the variance.

This experiment aims to demonstrate the relationship between the period of oscillation and the spring constant of the spring. By measuring the period of oscillation of the spring with a known mass hanging from it, the spring constant can be determined, which is a fundamental property of the spring.

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define polarization
how can we remove it​

Answers

Answer:

Polarization is a defect which is caused due to the formation of a hydrogen layer on the copper plate in a simple cell

Explanation:

we can remove it by using the polarizer like potassium dichromate, copper sulphate etc

Answer:

In physics, polarization refers to the orientation of electric field vectors in an electromagnetic wave. When an electromagnetic wave passes through a transparent material such as glass, some of the light waves may be polarized, meaning their electric field vectors vibrate in only one plane or direction.

Polarization can be removed by certain methods such as by using a polarizing filter. A polarizing filter works by allowing only light waves of a particular orientation to pass through along its axis. Any other polarized light waves that are not aligned with the filter axis will be blocked, effectively removing their polarization. Another method involves changing the angle of incident light to a certain degree called Brewster's angle, which causes the reflected light to become polarized.

A 5.0 g mouse races around a 65-cm-diameter horizontal tack. What is the minimum coefficient of static friction between the track and the mouse’s feet that allows the mouse to run at 1.4 m/s without slipping?

Answers

Answer:0.62

Explanation:

mv*2/rg
(1.4)*2*2/65*10*-2 *9.8

=0.615

This impossible, since the coefficient of static friction cannot be greater than 1.0 and therefore, the mouse cannot run at 1.4 m/s without slipping on this track.

What is static friction?

The Force that keeps any object at the rest is called as static friction.

As, Fc = mv² / r

m is the mass of the mouse, v is its velocity, and r is the radius of the track (not the diameter).  r = 0.5 * 65 cm = 32.5 cm = 0.325 m.

Fc = (5.0 g) x (1.4 m/s)²  / 0.325 m

= 31.96 g m/s²

= 0.313 N

Ff = μs * N

Here, μs is coefficient of static friction and N is normal force acting on mouse.

N = mg

= (5.0 g) x (9.81 m/s² )

= 0.049 N

μs = Ff / N

= (0.313 N) / (0.049 N)

= 6.39

This is impossible, since the coefficient of static friction cannot be greater than 1.0 Therefore, the mouse cannot run at 1.4 m/s without slipping on this track.

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6.4 A pebble of mass, m is attached to one end of a high inelastic string of length, L. The other end of the string is fixed. The string is initially held taut to the horizontal and the pepple is then released. Find the values of the following quantities when the string reaches the vertical position: (I)The kinetic energy of the pepple (ii)The velocity of the pepple (III)The acceleration of the pepple and (iv) The tension in the string​

Answers

(I) The kinetic energy of the pebble when the string reaches the vertical position is mgL.

When the pebble is released, it will start to fall towards the ground due to gravity, and the string will become slack. When the string reaches the vertical position, the pebble will have lost all its potential energy, which will be converted into kinetic energy.

What is kinetic energy?

At the vertical position, all the potential energy of the pebble is converted into kinetic energy. The potential energy of the pebble is given by:

PE = mgh

where m is the mass of the pebble, g is the acceleration due to gravity, and h is the height from which the pebble was released. Initially, the height of the pebble is L, so the potential energy is:

PE = mgh = mgL

When the string reaches the vertical position, the height of the pebble is zero. Therefore, all the potential energy is converted into kinetic energy, which is given by:

KE = PE = mgh = mgL

Therefore, the kinetic energy of the pebble when the string reaches the vertical position is mgL.

(ii) The velocity of the pebble when the string reaches the vertical position is sqrt(2gL).

What is velocity of pebble ?

The kinetic energy of the pebble is also given by:

KE = (1/2)mv²

where v is the velocity of the pebble. Equating this expression with the kinetic energy we found above, we get:

mgh = (1/2)mv²

Simplifying and solving for v, we get:

v = √2gh

where h is the initial height of the pebble, which is L. Substituting the given values, we get:

v = √2gL

Therefore, the velocity of the pebble when the string reaches the vertical position is √2gL.

(III) The acceleration of the pebble:

At the vertical position, the tension in the string will be equal to the weight of the pebble. Therefore, the net force acting on the pebble will be zero, and its acceleration will be zero. Therefore, the acceleration of the pebble when the string reaches the vertical position is zero.

(iv) The tension in the string when it reaches the vertical position is mg.

What is tension of spring?

At the vertical position, the tension in the string will be equal to the weight of the pebble. Therefore, the tension in the string is:

T = mg

where m is the mass of the pebble and g is the acceleration due to gravity.

Therefore, the tension in the string when it reaches the vertical position is mg.

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Devices in our homes need to have a steady amount of electric energy to work correctly. Based on your observations, do you think our homes mainly have series circuits or parallel circuits? Explain.

Answers

Answer:Here’s one possible answer:

The brightness of the bulbs in the parallel circuit stayed the same even when there were multiple bulbs on the circuit. Adding a second bulb to the series circuit dimmed each bulb. Homes must have mainly parallel circuits, because the brightness of the bulbs stays the same.

Explanation: edmentum answer

What does "resistance" refer to in terms of electron flow?

Answers

Answer:

In terms of electron flow, "resistance" refers to the opposition that a material or device offers to the flow of electric current through it.

Explanation:

When electrons flow through a conductor, they encounter resistance due to collisions with the atoms of the material, which cause them to lose energy and slow down. This resistance to electron flow causes a drop in voltage and generates heat, which is dissipated by the conductor.

Resistance is measured in ohms (Ω), and it is influenced by various factors such as the size, shape, and material of the conductor, as well as the temperature and the current flow. Materials that have a high resistance are known as insulators, while materials that have low resistance are known as conductors.

without adding more source of light, how can a barber enhance the lighting in his salon?

Answers

Answer:

1. Change or upgrade existing light fixtures to more energy-efficient options such as LED bulbs, for better illumination.

2. Make use of natural light by installing higher windows or skylights, to let in additional sunlight during daytime.

3. Paint walls and ceilings in bright colors, to reflect light and make the room brighter.

4. Rearrange furniture and accessories in the salon to maximize the use of available light.

5. Utilize wall-mounted mirrors for reflection, to increase the brightness in the room.

You make a guitar body from a cigar box that can vibrate with an oscillation frequency of 300 Hz and has a damping timr of 0.005 seconds. The guitar had a string on it that is tuned to C2 = 66 Hz.

(a) Draw the resonance curve of the cigar box.

(b) Draw the Fourier spectra of the string if plucked close to one end, without considering the role of the cogar box.

(c) Now draw what the Fourier spectra of the string will look like if it is attached to the cigar box, which amplifies certain frequencies more than others. Assume the string is plucked close to one end.

Answers

(a) The resonance curve of cigar box would be a plot of  vibration amplitude versus frequency; (b) The Fourier spectra of string without considering role of cigar box would show the various harmonic frequencies ; (c) The Fourier spectra of string will show stronger peak at  resonant frequency of cigar box (300 Hz).

What is resonance curve?

Resonance curve is the curve whose abscissas are frequencies lying near to and on both sides of natural frequency of vibrating system and whose ordinates are corresponding amplitudes of near-resonant vibrations.

(a) The resonance curve of cigar box would be a plot of the vibration amplitude versus frequency. It would show that cigar box has resonant frequency of 300 Hz, which means that it will vibrate more easily at this frequency than at others.

(b) The Fourier spectra of the string without considering the role of the cigar box would show the various harmonic frequencies that the string can produce when plucked. It would be a series of peaks at integer multiples of fundamental frequency (C2 = 66 Hz), with decreasing amplitude as frequency increases.

(c) When the string is attached to cigar box, resonance curve of the cigar box will affect the frequencies that are amplified more than others. The Fourier spectra of string will show a stronger peak at the resonant frequency of the cigar box (300 Hz), and possibly some harmonics that are also amplified by the cigar box. The amplitudes of other harmonics may be reduced due to damping, so the overall spectra will be modified by resonant properties of cigar box.

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