The balanced chemical equation for the reaction between HI and RbOH is:
HI + RbOH → RbI + H2O
From the equation, we can see that 1 mole of HI reacts with 1 mole of RbOH to produce 1 mole of RbI and 1 mole of H2O.
To determine the molarity of the initial RbOH, we can use the following formula:
Molarity of RbOH = (moles of RbOH) / (volume of RbOH solution in liters)
First, let's calculate the number of moles of HI in the 300 mL sample:
moles of HI = Molarity x volume in liters
moles of HI = 2.15 mol/L x 0.3 L
moles of HI = 0.645 mol
Since 1 mole of HI reacts with 1 mole of RbOH, the number of moles of RbOH used in the titration is also 0.645 mol.
Now, we can use the volume and concentration of the RbOH solution to calculate its molarity:
Molarity of RbOH = (moles of RbOH) / (volume of RbOH solution in liters)
Molarity of RbOH = 0.645 mol / 0.212 L
Molarity of RbOH = 3.04 M
Therefore, the molarity of the initial RbOH solution was 3.04 M, which corresponds to the aqua green option.
Answer:
The balanced chemical equation for the reaction between hydriodic acid (HI) and rubidium hydroxide (RbOH) is:
HI + RbOH → RbI + H2O
From the balanced equation, we can see that the stoichiometry of the reaction is 1:1, which means that 1 mole of HI reacts with 1 mole of RbOH.
Given that a 300 mL sample of HI with a concentration of 2.15 M is completely neutralized by 212 mL of RbOH, we can use the following equation to determine the molarity of RbOH:
Molarity of HI x Volume of HI = Molarity of RbOH x Volume of RbOH
2.15 M x 0.300 L = Molarity of RbOH x 0.212 L
Molarity of RbOH = (2.15 M x 0.300 L) / 0.212 L = 3.04 M
Therefore, the molarity of the initial RbOH solution was 3.04 M, option (aqua green).
An aqueous potassium iodate ( KIO3
) solution is made by dissolving 531 g
of KIO3
in sufficient water so that the final volume of the solution is 4.30 L.
Calculate the molarity of the KIO3
solution.
[ KIO3
KIO
3
]=
The molarity of the KIO3 solution is 0.576 M.
KIO3 Molarity CalculationTo calculate the molarity of the KIO3 solution, we need to know the number of moles of KIO3 in the solution and the volume of the solution.
First, let's calculate the number of moles of KIO3:
Number of moles of KIO3 = Mass of KIO3 / Molar mass of KIO3
The molar mass of KIO3 is 214.00 g/mol (1 potassium atom with a molar mass of 39.10 g/mol, 1 iodine atom with a molar mass of 126.90 g/mol, and 3 oxygen atoms with a molar mass of 16.00 g/mol each).
Number of moles of KIO3 = 531 g / 214.00 g/mol
Number of moles of KIO3 = 2.48 mol
Now, we can calculate the molarity of the KIO3 solution:
Molarity = Number of moles of solute / Volume of solution in liters
Molarity = 2.48 mol / 4.30 L
Molarity = 0.576 M
Therefore, the molarity of the KIO3 solution is 0.576 M.
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which of the following substance is a non electrolytes ?
(a)H2SO4
(b)CH3COOH
(c)C6H12O6
(d)NH4Cl
Answer:
C
Explanation:
Glucose (sugar) readily dissolves in water, but because it does not dissociate into ions in solution, it is considered a nonelectrolyte; solutions containing glucose do not, therefore, conduct electricity.
After two emissions an isotope of oxygen-17 becomes a isotope of nitrogen-13. What are the two emissions
The two emissions required for oxygen-17 to become nitrogen-13 are a positron emission and a neutrino emission.
What is neutrino and a positron?A neutrino is a subatomic particle that is similar to an electron in many ways but differs in that it lacks an electrical charge and has a very small mass that might potentially be zero.
Positron is a particle with the same mass as an electron but has a positive charge.
The transformation of oxygen-17 to nitrogen-13 requires the emission of two particles: a positron (also called a positive beta particle) and a neutrino.
The first emission is the positron, which is a particle with the same mass as an electron but with a positive charge. During the emission, a proton in the oxygen-17 nucleus converts into a neutron, and the positron and a neutrino are produced. The positron quickly annihilates with an electron, releasing two gamma rays.
The second emission is the neutrino, which is a subatomic particle with a very small mass and no electrical charge. The neutrino is emitted during the decay of the nitrogen-13 nucleus as it transitions to its ground state.
Therefore, the two emissions required for oxygen-17 to become nitrogen-13 are a positron emission and a neutrino emission.
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Work out what the substances are and which one was used? I know what the first one is and I know what other chromatography one is used i just don't know how to identify it.
d (i) Rf of 0.54 could be substance B or substance D.
d (ii) It would eliminate any potential errors or uncertainties from the first experiment.
Describe Chromatography?Chromatography is a laboratory technique used for separating and analyzing mixtures of substances. It involves passing a mixture through a stationary phase, which is typically a solid or liquid, and a mobile phase, which is a gas or liquid. The different components of the mixture will interact differently with the stationary and mobile phases, causing them to move at different rates and ultimately separate from each other.
1 (d) (i) Based on the Rf values given in the table, two possible identities for the substance that caused the spot with an Rf of 0.54 could be substance B or substance D.
1 (d) (ii) To confirm which one of the substances (B or D) caused the spot, a chromatography experiment with a different solvent could be carried out. This would involve using a solvent that has a different polarity than water, such as hexane or chloroform, and running a new paper chromatography of the mixture. If the same spot appears at the same Rf value as in the previous experiment, then it is likely that the substance causing the spot is substance B. However, if a different spot appears at a different Rf value, then the substance causing the original spot is likely to be substance D. This experiment would help to confirm the identity of the substance causing the spot and would eliminate any potential errors or uncertainties from the first experiment.
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How many moles of CaC2 are needed to react with 49.0 grams H2O
In order to react with 45 g of water 1.25 moles of CaC₂ are required. Explanation: Given data: Moles of CaC₂ needed = ? Mass of water = 45.0 g.
[tex] \: [/tex]
Ba(NO3)2(aq)+CuSO4(aq) complete and balance the precipitation reaction.
Explained answer:
Ba(NO3)2(aq) + CuSO4(aq) -> BaSO4(s) + Cu(NO3)2(aq)
This is a precipitation reaction where barium nitrate and copper sulfate react to form barium sulfate , which is insoluble in water and therefore precipitates out of solution, and copper nitrate.
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. First, we balance the sulfate ions:
Ba(NO3)2(aq) + CuSO4(aq) -> BaSO4(s) + Cu(NO3)2(aq)
Next, we balance the barium and copper ions:
Ba(NO3)2(aq) + CuSO4(aq) -> BaSO4(s) + Cu(NO3)2(aq)
Finally, we balance the nitrate ions:
Ba(NO3)2(aq) + CuSO4(aq) -> BaSO4(s) + 2Cu(NO3)2(aq)
Therefore, the balanced precipitation reaction is: Ba(NO3)2(aq) + CuSO4(aq) -> BaSO4(s) + 2Cu(NO3)2(aq).
At the equivalence point of a strong acid string base titration, all of the acid and base have reacted producing water and a salt
Yes, that is correct. At the equivalence point of a strong acid-strong base titration, all the acid and base have reacted completely to form water and a salt. The solution is neutral as the pH is 7. This is because the strong acid and strong base react completely in a 1:1 ratio to form the salt and water. The salt formed depends on the specific acid and base used in the reaction. For example, if hydrochloric acid (HCl) and sodium hydroxide (NaOH) are used, the salt formed would be sodium chloride (NaCl).
Light can bounce off objects. This is called reflection, and it's what allows us to see objects. This drawing shows a light ray reflecting from the blue construction paper. Although many light waves are hitting the paper and reflecting from it, showing just one ray helps us follow the path of a single wave. white light from flashlight blue light ray seen For each color of paper, which part of white light is reflected?
For each color of paper, the part of white light that is reflected depends on the color of the paper. When white light strikes an object, some of the light is absorbed by the object, some of it is transmitted through the object, and some of it is reflected.
The color of the object that we see is the color of the light that is reflected by the object.
For example, when white light strikes blue paper, the blue color of the paper absorbs all the other colors of the spectrum except blue, which is reflected back to our eyes. This is why we see the paper as blue. Similarly, when white light strikes red paper, the red color of the paper absorbs all the other colors except red, which is reflected back to our eyes. This is why we see the paper as red.
In summary, the color of an object is determined by the color of the light that is reflected by the object, and the color of the light that is reflected depends on the color of the object and the colors of the spectrum that are absorbed or transmitted by the object.
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What quantity in moles of precipitate are formed when 52.9 mL of 0.400 M Ca(NO₃)₂ is mixed with excess K₃PO₄ in the following chemical reaction?
3 Ca(NO₃)₂(aq) + 2 K₃PO₄(aq) → Ca₃(PO₄)₂(s) + 6 KNO₃(aq)
Answer:
To determine the number of moles of precipitate formed in the reaction, we first need to find the limiting reagent.
From the balanced chemical equation, we know that 3 moles of Ca(NO₃)₂ react with 2 moles of K₃PO₄ to produce 1 mole of Ca₃(PO₄)₂.
Let's first calculate the number of moles of Ca(NO₃)₂ present in 52.9 mL of 0.400 M solution:
moles of Ca(NO₃)₂ = concentration × volume
= 0.400 mol/L × 0.0529 L
= 0.02116 mol
Since the stoichiometric ratio of Ca(NO₃)₂ to K₃PO₄ is 3:2, we would need 3/2 times the number of moles of K₃PO₄ to react completely with the given amount of Ca(NO₃)₂. However, the problem states that we have an excess of K₃PO₄, which means that all of the Ca(NO₃)₂ will react with the available K₃PO₄.
Therefore, the number of moles of Ca₃(PO₄)₂ that will be formed is equal to the number of moles of Ca(NO₃)₂ used in the reaction, which is 0.02116 mol.
Hence, 0.02116 moles of Ca₃(PO₄)₂ precipitate will be formed when 52.9 mL of 0.400 M Ca(NO₃)₂ is mixed with excess K₃PO₄ in the given chemical reaction.
Which gas is a greenhouse gas?
Oxygen
ammonia
Nitrogen gas
Water vapor
Answer:Nitrogen gas
Explanation:
I believe it is nitrogen correct me if i am wrong.
H₂PO₂ +3 NaOH →
0.08 M NaOH
(green)
Na PO + 3 H₂O
If 25.0 mL of H₂PO, 0.16 M are required to titrate 150.0 mL of NaOH to the equivalence point, what is the molarity
of the NaOH?
0.16 M NaOH
(sky blue)
0.02 M NaOH
(yellow)
Answer:
The balanced chemical equation for the reaction between H₂PO₂ and NaOH is:
H₂PO₂ + 3 NaOH → Na₃PO₄ + 3 H₂O
Explanation:
From the equation, we can see that 1 mole of H₂PO₂ reacts with 3 moles of NaOH to produce 1 mole of Na₃PO₄ and 3 moles of H₂O.
The volume of NaOH used in the titration is 150.0 mL, which is equivalent to 0.150 L. The molarity of the H₂PO₂ solution used is 0.16 M, which means that 0.16 moles of H₂PO₂ were used in the titration.
According to the balanced equation, 1 mole of H₂PO₂ reacts with 3 moles of NaOH. Therefore, the number of moles of NaOH used in the titration is three times the number of moles of H₂PO₂ used:
Number of moles of NaOH = 3 × 0.16 = 0.48 moles
The volume of NaOH used is 0.150 L, so the molarity of NaOH can be calculated as follows:
Molarity of NaOH = Number of moles of NaOH / Volume of NaOH used
Molarity of NaOH = 0.48 moles / 0.150 L
Molarity of NaOH = 3.2 M
Therefore, the molarity of NaOH is 3.2 M, which is represented by the sky blue color.
determine the mole fraction of each component in a solution in which 3.57 g of sodium chloride (NaCI) is dissolved in 25.0 g of water. Show the steps of the calculation.
The mole fractions of water and sodium chloride in the solution are 0.9578 and 0.0422, respectively.
What is the NaCl mole fraction?If 0.010 moles of sodium chloride dissolve in 100 grammes of purified water, the mole fraction of sodium chloride and water. Water has a mole fraction of 0.982 and NaCl has a mole fraction of 0.018.
1: Determine the sodium chloride moles (NaCl)
NaCl has a molar mass of 58.44 g/mol. As a result, 3.57 g of NaCl has the following number of moles in it:
moles of NaCl = mass of NaCl / molar mass of NaCl
moles of NaCl = 3.57 g / 58.44 g/mol
moles of NaCl = 0.0612 mol
2: Determine the water moles (H2O)
Water has a molar mass of 18.02 g/mol. As a result, 25.0 g of water contains the following number of moles of water:
moles of H2O = mass of H2O / molar mass of H2O
moles of H2O = 25.0 g / 18.02 g/mol
moles of H2O = 1.388 mol
3: Determine the total moles of the solution.
The moles of NaCl and water together make up the total amount of moles in the solution.
total moles = moles of NaCl + moles of H2O
total moles = 0.0612 mol + 1.388 mol
total moles = 1.4492 mol
4: Determine the mole fraction for each element.
NaCl's mole fraction is:
mole fraction of NaCl = moles of NaCl / total moles
mole fraction of NaCl = 0.0612 mol / 1.4492 mol
mole fraction of NaCl = 0.0422
Water's mole fraction is:
mole fraction of H2O = moles of H2O / total moles
mole fraction of H2O = 1.388 mol / 1.4492 mol
mole fraction of H2O = 0.9578
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How many grams of butanethiol can be deodorized by reaction with 4.50 mL of 9.70×10−2 M NaOCl
The mass of butanethiol that can be deodorized by reaction with 4.50 mL of [tex]9.70*10^{-2[/tex] M [tex]NaOCl[/tex] is 46.356g.
Given the volume of butanethiol = 4.50mL
The concentration of [tex]NaOCl[/tex] = [tex]9.70 * 10^{-2[/tex]M
The mass of butanethiol that can be deodorized = m
Butanethiol ([tex]C4H10S[/tex]) has a molar mass of 106.2 g/mol.
Therefore, the amount of butanethiol that can be deodorized by reaction with 4.50 mL of [tex]9.70 * 10^{-2} M[/tex] [tex]NaOCl[/tex] is calculated as follows:
molarity is calculated as number of moles/volume such that:
Moles of [tex]NaOCl[/tex] =[tex](4.50 mL) * (9.70 * 10^{-2} M) = 0.4365 mol[/tex]
We know that mass of substance = moles*molar mass of substance
mass of butanethiol = (0.4365 mol [tex]C4H10S[/tex])*(106.2 g/mol [tex]C4H10S[/tex]) = 46.356 g [tex]C4H10S[/tex]
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Write the equilibrium constant expression, K, for the following reaction: If either the numerator or denominator is blank,
please enter 1.)
N 2 (g)+3H 2 (g) 2NH 3 (g)
The molar concentrations of nitrogen gas, hydrogen gas, and ammonia gas at equilibrium are [N2], [H2], and [NH3], respectively. The equilibrium constant expression, K, for the above reaction is K = [NH3]2 / ([N2] * [H2]3).
How much is K's equilibrium constant?Equilibrium constant (K) is a mathematical ratio that displays the product concentrations subtracted from the reactant concentrations.
What is the expression for the K equilibrium?The expression for the equilibrium constant is expressed as. K=adD·aeEabB·acC. The number of moles of each substance is represented by the lower case letters in the balanced equation, while the substance itself is represented by the upper case letters. Equilibrium favours products if K>1. Equilibrium favours the reactants if K 1.
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C2H6O + 3 O2 → 2 CO2 + 3 H2O
How many moles of CO2 is produced with 8.5 g of O2
0.32 mol
5.7 mol
0.53 mol
0.18 mol
The number of moles of CO₂ produced from the reaction of 8.5 g of oxygen gas, O₂ is 0.18 mole (last option)
How do i determine the number of mole of CO₂ produced?We shall begin by obtaining the mole in 8.5 g of oxygen gas, O₂. Details below:
Mass of oxygen gas, O₂ = 8.5 grams Molar mass of oxygen gas, O₂ = 32 g/mol Mole of oxygen gas, O₂ =?Mole = mass / molar mass
Mole of oxygen gas, O₂ = 8.5 / 32
Mole of oxygen gas, O₂ = 0.266 mole
Finally, we shall determine the number of mole of CO₂ produced. Details below:
C₂H₆O + 3O₂ -> 2CO₂ + 3H₂O
From the balanced equation above,
3 moles of O₂ reacted to produce 2 moles of CO₂
Therefore,
0.266 mole of O₂ will react to produce = (0.266 × 2) / 3 = 0.18 mole of CO₂
Thus, the number of mole of CO₂ produced is 0.18 mole (last option)
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If you mastered this assignment, you will do exactly as it states
1. Do you think a chemical reaction took place in Part 1 when you added the galvanized nail to the acid and water, and in Part 2 when the yeast was added to the hydrogen peroxide? Explain your answer
2. Did the same result occur in both parts when you held up a lighted splint to the jar’s mouth?
What can you conclude from this about the identity of the gas(es) in Parts 1 and 2?
3. In both parts of the activity, you conducted a second trial without having to remix the chemicals. How was this possible?
4. In 1937, a large passenger airship called the Hindenburg mysteriously caught fire. Because
the airship was filled with hydrogen gas, it immediately exploded once the fire reached the gas.
Given this information, do you think one of the reactions above may have produced hydrogen?
Use your data to explain your answer.
Conclusions
Keeping the goal in mind, write a one- or two-sentence conclusion that summarizes the results of
this activity and how they met the established goal.
Answer:
1: Yes I do believe it was a chemical reaction because gas and bubbles were created which can only happen during a chemical reaction also temperature change is another reason for a chemical change.
2: No on the second try I heard fizzing and type of popping concluding that its oxygen gas that was formed from the mixture since oxygen gas could re ignite the flame.
3: The trials all used gasses so there is no need to remix when its still creating gas and keeping the lid on keeps the gas in.
4: Yes the muriatic acid when mixed with the water and galvanised nail form hydrogen gas the popping and fizzing are indictors that it is indeed hydrogen
Explanation:
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Which compound would undergo nucleophilic addition? A ethene, C₂H4 B bromoethane, C₂H,Br Cethanal, CH₂CHO D ethane, C₂H6
Out of the given compounds, the one that would undergo nucleophilic addition is ethanal, CH₂CHO (option C).
What is nucleophilic addition?Nucleophilic addition is a type of chemical reaction in which a nucleophile (an electron-rich species, such as a negatively charged ion or a molecule with a lone pair of electrons) attacks an electrophilic center (an electron-poor atom or group) and forms a new covalent bond.
In this type of reaction, the nucleophile donates a pair of electrons to the electrophilic center, resulting in the formation of a new bond and the creation of a new compound.
This process can occur in various types of molecules and functional groups, but is particularly common in compounds with polar double or triple bonds, such as alkenes and alkynes, or in compounds with polar functional groups, such as carbonyl groups (C=O) and imines (C=N).
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How many grams are there in 5.47 x 1021 molecules of SO2?
O.33 grams of SO2
O.58 grams of SO2
O.72 grams of SO₂
O.49 grams of SO₂
Answer:
The correct answer is option (B) 0.58 grams of SO2.
How many different mRNA sequences could encode the amino acid sequence Met–Leu–Val–His?
Answer:
Therefore, the number of potential sequences is the product of the number of different potential codons for this tripeptide, which gives us a total of (1 × 6 × 6 × 3) = 108 different mRNA sequences that can code for the tripeptide Met-Leu-Arg.
A solid chloride sample weighing 0.3147 g required 43.75 mL of 0.05273 M AgNO, to reach the Ag,CrO, end point.
a. How many moles Cl ion were present in the sample? (Use Eqs. 2 and 3.)
b. How many grams Cl- ion were present? (Use Eq. 4.)
c. What was the mass percent C ion in the sample? (Use Eq. 5.) moles Cr g Cr % Cr
Answer:its a
Explanation: i juts know it is hope it helps
1. Element X and element Y have a difference in electronegativity of 0.7; Will the bond XY be covalent or ionic? explain using electronegativity difference.
2. Which two substances would have a higher melting point. O2 or quatz (SiO2)? Explain your answer.
3. write the name of the covalent compound
Cl2O6
Several weather variables are used to measure weather conditions. Identify 3 weather variables and their instruments that you would use to observe and collect data to determine the relationship between air mass movements and changes in weather.
The following are three weather variables and the tools that can be used to observe and gather data on them to ascertain how air mass movements and weather changes are related:
Temperature is a crucial factor in comprehending weather conditions and is measured using a thermometer.The quantity of water vapor in the air is known as humidity, and it is measured with a hygrometer. An anemometer and a wind vane are used to measure the speed and direction of the wind, respectively. Temperature: For instance, a high temperature means the air is warm and light, and it will rise. Conversely, if the temperature is low, the air will sink since it is heavy and chilly.Air pressure: High-pressure regions are known for having calm, sunny skies, whereas low-pressure regions are known for having gloomy, stormy skies.Wind speed: The direction of the wind can be used to determine the nature and movement of an air mass. The air mass is traveling from the north to the south, for instance, if the wind is blowing from the north.Scientists can discover patterns and connections between changes in weather and changes in air mass movement by observing and recording data on these meteorological variables.
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In which two phase changes does energy decrease?
Answer: potential energy
Explanation: During a phase change, the heat added (PE increases) or released (PE decreases) will allow the molecules to move apart or come together. Heat absorbed causes the molecules to move farther apart by overcoming the intermolecular forces of attraction.
2 HC₂H₂O₂ + Ba(OH)₂
Ba(C₂H₂O₂)₂
+ 2 H₂O
A sample of barium hydroxide (Ba(OH)₂) 0.67 M is titrated with acetic acid (HC₂H₂O₂) 1.2 M. If 55.00 mL of acetic
acid were required, what was the volume of the sample of barium hydroxide?
153.54 mL Ba(OH)₂
(magenta)
98.51 mL Ba(OH)2
(red)
49.25 mL Ba(OH)₂
(blue)
The balanced chemical equation for the reaction between acetic acid and barium hydroxide is:
2 HC₂H₂O₂ + Ba(OH)₂ → Ba(C₂H₂O₂)₂ + 2 H₂O
From the balanced equation, we can see that 2 moles of acetic acid react with 1 mole of barium hydroxide to produce 1 mole of barium acetate and 2 moles of water.
The number of moles of acetic acid used in the titration can be calculated as follows:
moles of HC₂H₂O₂ = Molarity × volume in liters
moles of HC₂H₂O₂ = 1.2 M × (55.00 mL / 1000 mL/ L)
moles of HC₂H₂O₂ = 0.066 moles
From the balanced equation, we know that 2 moles of acetic acid react with 1 mole of barium hydroxide. Therefore, the number of moles of barium hydroxide present in the titration can be calculated as:
moles of Ba(OH)₂ = 0.066 moles / 2
moles of Ba(OH)₂ = 0.033 moles
The molarity of the barium hydroxide solution can be calculated as:
Molarity = moles / volume in liters
We rearrange this equation to solve for the volume:
volume in liters = moles / Molarity
volume in liters = 0.033 moles / 0.67 M
volume in liters = 0.04925 L
Finally, we convert the volume to milliliters:
volume in mL = 0.04925 L × 1000 mL/L
volume in mL = 49.25 mL
Therefore, the volume of the sample of barium hydroxide used in the titration is 49.25 mL. The answer is blue.
For the compound Rbl what are the formulas of all the species you expect to be present in aqueous solution? If there are significant differences in the amounts of species present, use the designations major and minor to distinguish those species present in greater amounts (major species) from those present in lesser amounts (minor species). A. Major species: Rb∗: Minor species: 1 :
B. Major species: I. Minor species: Rb∗: C. Major species: Rb∗ and K, Minor species: NA. D. Major species: NA. Minor species: Rb∗ and I.
The compound RbI is a salt that dissociates in an aqueous solution, producing Rb+ and I- ions.
Major species: Rb+, Minor species: I-Major species: I-, Minor species: Rb+Major species: Rb+ and I-, Minor species: none (since K is not part of the compound)Major species: H2O and I-, Minor species: Rb+ (since RbI is not very soluble, and therefore only a small amount of Rb+ ions will be present in solution)An aqueous solution is a mixture of a substance in water, where the water is the solvent. Water is a versatile solvent, which can dissolve a wide range of compounds due to its polar nature. The concentration of a solute in an aqueous solution is usually expressed in terms of molarity or molality, which indicate the number of moles of solute per liter or kilogram of solvent, respectively.
In an aqueous solution, water molecules surround the dissolved solute particles and separate them from one another. This process is called hydration. When a substance dissolves in water, it can undergo a chemical change, such as ionization or hydrolysis, that affects its properties. Aqueous solutions play a critical role in many chemical reactions and biological processes. The pH of an aqueous solution, which measures the acidity or basicity, is also an essential property that affects its chemical behavior.
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4.8g of salt(z) dissolved in 250cm³ of distilled water give a concentration of 0.80m/dm³. Calculate the molar mass of the salt(z)
Answer:
24 g/mol.
Explanation:
To calculate the molar mass of the salt (z), we need to use the formula:
concentration = number of moles / volume of solution
We know that the concentration is 0.80 mol/dm^3, and the volume of the solution is 250 cm^3, which is equivalent to 0.25 dm^3. Therefore, we can rearrange the formula to solve for the number of moles of salt (z):
number of moles = concentration x volume of solution
number of moles = 0.80 mol/dm^3 x 0.25 dm^3
number of moles = 0.20 mol
Next, we can calculate the mass of salt (z) in the solution using the formula:
mass = number of moles x molar mass
We know that the mass of salt (z) is 4.8 g, and we just calculated that the number of moles is 0.20 mol. Therefore, we can rearrange the formula to solve for the molar mass:
molar mass = mass / number of moles
molar mass = 4.8 g / 0.20 mol
molar mass = 24 g/mol
Therefore, the molar mass of the salt (z) is 24 g/mol.
Answer:24 g/mo
Explanation:
In a common medical laboratory determination of the concentration of free chloride ion
in blood serum, a 'serum sample is titrated with a Hg(NO3)2 solution.
2Cl(aq) +Hg(NO3)2(aq) → 2NO3(aq) + HgCl₂(s)
What is the C1 concentration in a 0.25-mL sample of normal serum that requires 1.46
mL of 8.25 × 10-4 M Hg(NO3)2 (aq) to reach the end point?
The concentration of Cl- in the serum sample is 4.82 x 10-3 M.
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The principle of the titration is based on the following equation:
2Cl(aq) +Hg(NO3)2(aq) → 2NO3(aq) + HgCl₂(s)
Given the data, we can calculate the concentration of Cl- in the serum sample:
1. Calculate the moles of Hg(NO3)2 (aq) used in the titration:
Moles = (concentration of Hg(NO3)2) x (volume of Hg(NO3)2)
= (8.25 x 10-4 M) x (1.46 mL)
= 0.001205 mol
2. Calculate the moles of Cl- in the sample:
Moles = (concentration of Cl-) x (volume of Cl-)
= (C1) x (0.25 mL)
= 0.001205 mol
3. Calculate the concentration of Cl- in the serum sample:
Concentration of Cl- = (moles of Cl-) / (volume of serum sample)
= 0.001205 / 0.25 mL
= 4.82 x 10-3 M
Therefore, the concentration of Cl- in the serum sample is 4.82 x 10-3 M.
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Fluoride, a very stable form of fluorine, is often added to toothpaste and drinking water to prevent
tooth decay. What is the formula of this species?
a. F
b. Fl-
C. Fl+
d. F²-
Answer:
B
Explanation:
The Fluoride ion is a part of the diatomic molecule [tex]F_{2}[/tex] which has two [tex]F^{-}[/tex] molecules that are paired together and share electrons in order to gain a full octet of electrons, which is why [tex]F_{2}[/tex] is the most stable form of fluorine and why it is the way natural fluorine is found. Fluoride refers to half of this diatomic molecule which is [tex]F^{-}[/tex].
Note: Diatomic simply means a molecule that contains two atoms.
1. Billy Beaker is reacting 7.98 mL of 2.50 M HCl with excess NaOH. How many grams of water will be produced by this neutralization reaction?
2. Emily Erlenmeyer is reacting 2.43 mL of 2.50 M H2SO4 with 2.51 mL of 3.00 M NaOH. How many grams of water will be produced by this neutralization reaction?
Use molarity and stoichiometry
1. The amount of water produced by the reaction is 0.359 g.
2. The amount of water produced by the reaction is 0.219 g.
How do you calculate the number of moles neutralized in a titration?To calculate the number of moles of acid neutralized by the tablet, subtract the number of moles of acid neutralized in the titration from the initial solution's moles of acid. Understand and explain standardization in the context of acidic and basic solutions used as reagents in experiments.
1. The neutralization reaction,
HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)
we have to calculate the number of moles of HCl that react,
moles of HCl = volume of HCl x concentration of HCl
= 7.98 mL x 2.50 mol/L / 1000 mL/L
= 0.01995 mol
Since NaOH is in excess,
As a result, the amount of water produced will be equal to the amount of HCl that reacts:
moles of water = moles of HCl = 0.01995 mol
we can use the molar mass of water (18.015 g/mol)
mass of water = moles of water x molar mass of water
= 0.01995 mol x 18.015 g/mol
= 0.359 g
2. The neutralization reaction between H2SO4 and NaOH is:
H2SO4 (aq) + 2 NaOH (aq) → Na2SO4 (aq) + 2 H2O (l)
we have to calculate the number of moles of H2SO4 that react,
moles of H2SO4 = volume of H2SO4 x concentration of H2SO4
= 2.43 mL x 2.50 mol/L / 1000 mL/L
= 0.00608 mol
Now, we have to calculate the number of moles of NaOH that react:
moles of NaOH = volume of NaOH x concentration of NaOH
= 2.51 mL x 3.00 mol/L / 1000 mL/L
= 0.00753 mol
we need to use the stoichiometry of the balanced equation,
moles of water = moles of H2SO4 x (2 moles of water / 1 mole of H2SO4)
= 0.00608 mol x 2
= 0.01216 mol
we can use the molar mass of water (18.015 g/mol)
mass of water = moles of water x molar mass of water
= 0.01216 mol x 18.015 g/mol
= 0.219 g
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K
Beaction
H₂SO4+Za=26804+H₂
of paper. Then complete the
for you.
Reactants
Reactants Products
Fes
Products
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Explanation:
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