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Answer:

28/51

Step-by-step explanation:

First you add up all the values: 28 + 15 + 8 = 51. That is your denominator because the total is the denominator. Then you put 28 as your numerator because that's how many off all the people that only like pizza.

Answer:

9, 10, 3y, 5, 3y, 5

Step-by-step explanation:

First look at the second row

_(2y+3)+_(2y+3)

We know that if we multiply the first blank time 2y is should equal 6y^2, so the answer for the first one is 3y. The third blank times 3 should be 15, so the answer for the third one is 5. Therefore, 3y(2y+3)+5(2y+3).

Now if we distribute, we get the answer for the first part: 6y^2+9y+10y+15.

In the second line we got, 3y(2y+3)+5(2y+3), we can factor out the 2y+3 and end up with (2y+3)(2y+5).

Answer: 30

180 - x = 180 - 2x + 30

x = 30

Answer:

The measure of the unknown angle is 30°.

Step-by-step explanation:

Let the measure of the unknown angle be x°.

Supplementary angles are two angles whose measures sum to 180°.

Complementary angles are two angles whose measures sum to 90°.

Therefore, the supplement of x° is (180 - x)°, and its complement is (90 - x)°.

Given that the supplement is 30° more than twice its complement:

(180 - x)° = 2(90 - x)° + 30°

To find the measure of the angle, solve the equation:

⇒ (180 - x)° = (180 - 2x)° + 30°

⇒ 180° - x° = 180° - 2x° + 30°

⇒ 180° - x° = 210° - 2x°

⇒ 180° - x° + 2x° = 210° - 2x° + 2x°

⇒ 180° + x° = 210°

⇒ 180° + x° - 180° = 210° - 180°

⇒ x° = 30°

Therefore, the measure of the unknown angle is 30°.

Answer:

5) 59.7 in

6) 39.0 mi

7)

8) 50.3 mi

Step-by-step explanation:

5) C = [tex]\pi (19)[/tex]

C = 59.7 in

6) C = [tex]2\pi (6.2)[/tex]

C = 39.0 mi

7) RADIUS IS CUT OFF

use C = [tex]2\pi r[/tex]

8) C = [tex]2\pi (8)[/tex]

C = 50.3 mi

According to the given information, the equation is [tex]V = 15,000(1-0.12)^t[/tex], the car is worth $7,156.67 in 5 years and will be worth $1000 in 24 years.

What is the depreciation rate?

Depreciation rate is a mathematical process in which a quantity decreases over time in a manner proportional to its current value. This means that the rate of decay is proportional to the amount of the substance remaining, and as the amount of the substance decreases, the rate of decline also decreases

a) V = P(1-r)^t, where V is the value of the car, P is the initial price ($15,000), r is the depreciation rate (0.12), and t is the time in years.

[tex]V = 15,000(1-0.12)^t[/tex]

b) To find the value of the car in 5 years, substitute t = 5 into the equation:

[tex]V = 15,000(1-0.12)^5[/tex]

V = 7,156.67

The car is worth approximately $7,156.67 in 5 years.

c) To find when the car will be worth $1000, we need to solve for t in the equation:

[tex]1000 = 15,000(1-0.12)^t[/tex]

[tex]0.067 = (1-0.12)^t[/tex]

Take the natural logarithm of both sides:

ln(0.067) = t ln(0.88)

t = ln(0.067) / ln(0.88)

t ≈ 23.7

Therefore, the car will be worth $1000 in approximately 24 years.

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Answer is in the photo attached. Hope this helped!

The number of orange skittles in the bag is 32.

Ratio is described as the comparison of two quantities to determine how many times one obtains the other. The proportion can be expressed as a fraction or as a sign: between two integers.

We are given that;

The ratio of purple skittles to orange skittles= 5:2

Total skittles= 112

Now,

Let's call the number of purple skittles in the bag "5x" and the number of orange skittles in the bag "2x", where x is a common factor.

We know that the total number of skittles in the bag is 112. So we can write:

5x + 2x = 112

Simplifying, we get:

7x = 112

Dividing both sides by 7, we get:

x = 16

Now we can find the number of orange skittles by substituting x = 16 into our expression for the number of orange skittles:

2x = 2(16) = 32

Therefore, by the given ratio answer will be 32 orange skittles in the bag.

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Answer:

m<NPQ= 82°

Step-by-step explanation:

Below is the explanation for the answer to the assignment.

There are 2 x 120 = 240 possible arrangements in which Maria and Olivia are adjacent.

An order of award presentations has been devised for seven people, including Jeff, Karen, Lyle, Maria, Norm, Olivia, and Paul. We must find out how many different orders the awards can be presented in if Maria and Olivia will be one after the other.There are six possible pairs:

{M, O}, {O, M}, {J, M}, {M, K}, {L, M}, and {M, N}.

In the total number of arrangements, these pairs can occur in two different ways. They are:-

The pair can come first, and the remaining people can be arranged in the rest of the arrangement- The pair can come last, and the remaining people can be arranged in the rest of the arrangement.That is, each pair may appear at the beginning or end of the arrangement, and the remaining persons may be arranged in the remaining positions in any order.

The arrangements would be the same for all six pairs, so we can choose any pair and multiply the outcome by 6.Choose the pair {M, O}. The pair may appear at the start or end of the sequence. There are 2 ways to pick which pair appears first or second.There are 5 individuals left to be arranged. The remaining 5 people can be arranged in 5! = 120 ways.

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Neil will be able to receive Olga's weather updates for a distance of 10 miles on the road.

Equation is a mathematical statement that expresses the equality of two expressions. It is usually written using symbols, such as '=', '<', '>', '+', and '-'. Equations can be used to describe, model, and solve real-world problems. They can also be used to predict the behavior of a system or to find unknown values.

To calculate the approximate number of miles Neil will be able to receive Olga's weather updates, a quadratic equation can be used. The equation is as follows:

A = (x - 15)²+ (y - 15)² <= 100

where A is the area of a circle with a radius of 10 miles, centered at the ranger station, and (x,y) is the position of Neil's car on the road. The equation represents the area that is within the range of Olga's walkie-talkie, which is the area where Neil's car can receive Olga's weather updates.

To solve for x and y, we can use the distance formula, which states that the distance between two points (x1, y1) and (x2, y2) is equal to the square root of (x2 - x1)² + (y2 - y1)². Since we know the starting and ending points of Neil's road, we can use this formula to solve for x and y:

x = Square root of [ (10 - 15)² + (20 - 15)² ] = 10
y = Square root of [ (10 - 15)² + (10 - 15)² ] = 5

Substituting these values into the equation above, we get A = (10 - 15)² + (5 - 15)²= 100, which is Olga's walkie-talkie range. Therefore, Neil will be able to receive Olga's weather updates for a distance of 10 miles on the road.

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2t

Question:

If the coconut from the shorter tree takes time t to reach the ground, how long (in terms of t) will it take the other coconut to reach the ground?

Solution:

We know that the time taken by the coconut to reach the ground is given by the formula:

t = √(2h/g)

Where,
t = time taken to reach the ground
h = height of the tree
g = acceleration due to gravity

If the height of the coconut from the shorter tree is h, then the time taken by it to reach the ground is t.

Now, the coconut from the taller tree has a height of 2h. Therefore, its time taken to reach the ground can be calculated as follows:

t_1 = √(2(2h)/g)
t_1 = √(4h/g)
t_1 = 2√(h/g)

Therefore, the time taken by the coconut from the taller tree to reach the ground is 2 times the time taken by the coconut from the shorter tree to reach the ground.

Hence, the answer is, the time taken by the other coconut to reach the ground is 2t.

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The probability that a randomly selected cap had a strength greater than 11 inch-pounds is approximately 0.2033 or 20.33% (rounded to two decimal places).

We know that cap strength, C, follows a normal distribution with mean μ = 10 inch-pounds and standard deviation σ = 1.2 inch-pounds. Therefore, we can standardize the variable C using the z-score formula:

z = (x - μ) / σ

where x is the value of cap strength we are interested in. In this case, we want to find the probability that a randomly selected cap had a strength greater than 11 inch-pounds, so x = 11. Plugging in the values for μ and σ, we get:

z = (11 - 10) / 1.2 = 0.83

Next, we need to find the probability that a standard normal random variable Z is greater than 0.83. This can be looked up in a standard normal distribution table or calculated using software. Using a standard normal distribution table, we find that the probability of Z being greater than 0.83 is approximately 0.2033.

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To determine the most likely distribution of the colors of candies in the bag before it was opened, we can analyze the data from the table and try to find a distribution that would result in the observed frequencies.

If we add up the number of candies of each color that were pulled out by the four students, we get:

Red: 75 + 80 + 85 + 90 = 330

Blue: 45 + 55 + 60 + 50 = 210

Green: 50 + 45 + 40 + 55 = 190

Yellow: 20 + 20 + 30 + 25 = 95

Orange: 10 + 5 + 25 + 30 = 70

We can see that the most frequently pulled color was red, followed by blue and then green. This suggests that the bag may have had more red candies than the other colors before it was opened.

Looking at the answer choices, the distribution in option B (300 red, 250 blue, 200 green, 100 yellow, and 150 orange) seems to match the observed frequencies the closest, as it has the highest number of red candies. Therefore, option B is the most likely distribution of the colors of candies in the bag before it was opened.

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Correct question:

A bag of candy contained a total of 1,000 candies before it was opened. Four students each pulled out 20 candies at random and recorded the color of the candies in this table.

According to this data, which was the most likely distribution of the colors of candies in the bag before it was opened?

A. 250 red, 250 blue, 250 green, 125 yellow, and 125 orange

B. 300 red, 250 blue, 200 green, 100 yellow, and 150 orange

C. 200 red, 200 blue, 200 green, 200 yellow, and 200 orange

D. 200 red, 200 blue, 200 green, 100 yellow, and 100 orange

Answer:180

Step-by-step explanation:

Answer:

20÷100×4.75=0.95

4.75-0.95=$3.8

Answer:

i got 4.55$

Step-by-step explanation:

i just converted the percentage (20%) and then subtracted that number (0.2) from the original price (4.75$)

The price per foot of the 2-yard rope is $6.36.

To find the price per foot of the 2-yard rope, we need to first convert the length to feet. Since there are 3 feet in a yard, a 2-yard rope is equal to 6 feet.

Next, we divide the total cost of the rope ($22.86) by the length of the rope in feet (6 feet) to get the price per foot:

$22.86 ÷ 6 = $3.81 per yard

To convert this to the price per foot, we divide $3.81 by 3 (since there are 3 feet in a yard):

$3.81 ÷ 3 = $1.27 per foot

Therefore, the price per foot of the 2-yard rope is $1.27 x 5 = $6.36.

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Answer:

The length of the segment is 8 units.

We can use the formula for the volume of a cone to calculate the height of the cone:

V = (1/3)πr^2h

320 = (1/3)π(8^2)h

h = 320/(1/3)(π)(64)

h = 8 units

For x = -2, g(-2) = 2(-2)^3 - 5(-2)^2 + 4(-2) - 1 = 0, so there is a value of x such that g(x) = 0 for -3 ≤ x ≤ 2.

The absolute minimum value of g on the interval -7 ≤ x ≤ 9 is -765, and the absolute maximum value of g on the interval is 1720.

a. To determine if there is a value of x such that g(x) = 0 for -3 ≤ x ≤ 2, we can plug in each value of x in the interval into the equation and see if we get 0.

g(x) = 2x^3 - 5x^2 + 4x - 1

For x = -3, g(-3) = 2(-3)^3 - 5(-3)^2 + 4(-3) - 1 = -55, which is not 0.

For x = -2, g(-2) = 2(-2)^3 - 5(-2)^2 + 4(-2) - 1 = 0, so there is a value of x such that g(x) = 0 for -3 ≤ x ≤ 2.

b. To find the absolute minimum and maximum values of g on the interval -7 ≤ x ≤ 9, we can use the Extreme Value Theorem, which states that a continuous function on a closed interval will have both an absolute minimum and maximum value on that interval.

To find these values, we can take the derivative of g(x) and set it equal to 0 to find critical points, and then evaluate g(x) at those critical points as well as at the endpoints of the interval.

g(x) = 2x^3 - 5x^2 + 4x - 1

g'(x) = 6x^2 - 10x + 4 = 2(3x-2)(x-1)

Setting g'(x) = 0, we get critical points x = 2/3 and x = 1.

g(-7) = -765, g(2/3) = -23/27, g(1) = 0, and g(9) = 1720.

Therefore, the absolute minimum value of g on the interval -7 ≤ x ≤ 9 is -765, and the absolute maximum value of g on the interval is 1720.

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Answer:

5.40

Step-by-step explanation:

let X represent the price of a 18 minute phone call

X=18 ×1.80

6

= 5.40

a) There are three values of x, namely -3, -2, and -1, for which g(x) = 0.

b) The absolute minimum value of g on the interval -7 ≤ x ≤ 9 is 20, and the absolute maximum value of g is 90

a. To check if there is a value of x for -3 ≤ x ≤ 2 such that g(x) = 0, we can plug in each value in the interval and see if any of them make g(x) equal to 0:

g(-3) = -3² + 5(-3) + 6 = 0

g(-2) = -2² + 5(-2) + 6 = 0

g(-1) = -1² + 5(-1) + 6 = 0

g(0) = 0² + 5(0) + 6 = 6

g(1) = 1² + 5(1) + 6 = 12

g(2) = 2² + 5(2) + 6 = 20

So, we can see that there are three values of x, namely -3, -2, and -1, for which g(x) = 0.

b. To find the absolute minimum and maximum values of g on the interval -7 ≤ x ≤ 9, we can first find the critical points of g by taking its derivative:

g'(x) = -2x + 5

Setting g'(x) = 0, we get:

-2x + 5 = 0

-2x = -5

x = 5/2

So, the only critical point of g is x = 5/2.

We can now check the values of g at the endpoints of the interval and the critical point:

g(-7) = -7² + 5(-7) + 6 = 20

g(9) = 9² + 5(9) + 6 = 90

g(5/2) = (5/2)² + 5(5/2) + 6 = 43.25

Therefore, the absolute minimum value of g on the interval -7 ≤ x ≤ 9 is 20, which occurs at x = -7, and the absolute maximum value of g is 90, which occurs at x = 9.

We can justify this by noting that g is a quadratic function with a negative leading coefficient, which means that it opens downward and has a maximum value at its vertex (which occurs at x = 5/2). Since the vertex is within the given interval, and the function is decreasing on the left and increasing on the right of the vertex, the maximum and minimum values of g must occur at the endpoints of the interval.

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The probability that the first arrival will not occur until at least the fifth one-second interval is 1/32.

This is calculated by the following equation:
P(First arrival in at least the fifth one-second interval) = 1 - P(First arrival in first 4 one-second intervals)
P(First arrival in first 4 one-second intervals) = 4/32
Therefore, P(First arrival in at least the fifth one-second interval) = 1 - 4/32 = 1/32

Therefore, the probability that the first arrival will not occur until at least the fifth one-second interval is 1/32.

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The variance is 7.2.

We can use the binomial distribution formula to calculate the variance. The formula for the variance of a binomial distribution is

Variance = n × p × (1 - p)

where n is the number of trials, p is the probability of success on each trial, and (1 - p) is the probability of failure on each trial.

In this case, n = 30 (the number of homes on the route), p = 0.48 (the probability of a home having a dog), and (1 - p) = 0.52 (the probability of a home not having a dog).

The postal employee encountered 12 dogs, which means there were 18 homes without dogs. So, the actual probability of success in this case is

P(dogs) = 12/30 = 0.4

Using the formula above, we can calculate the variance

Variance = n × p × (1 - p)

= 30 × 0.4 × 0.6

= 7.2

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The steps that she could use to solve the quadratic equation is determined as 2(x² + 6x + 9) = 18 + 3.

The solution to the quadratic equation is determined as follows;

2x² + 12x - 3 = 0

2x² + 12x = 3

divide through by 2

x² + 6x = ³/₂

take half of coefficient of x, square it and add it both sides of the equation

(x + 3)² = ³/₂ + 3²

x² + 6x + 9 = 9 + ³/₂

2(x² + 6x + 9) = 18 + 3

Thus, the steps that she could use to solve the quadratic equation is determined as 2(x² + 6x + 9) = 18 + 3.

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The roots of the given quadratic functions are -

x = (- 6 ± √42)/2.

A function is a relation between a dependent and independent variable. We can write the examples of functions as -

y = f(x) = ax + b

y = f(x, y, z) = ax + by + cz

Given is that Inga is solving the quadratic equation -

2x² + 12x - 3 = 0

The quadratic equation is given as -

2x² + 12x - 3 = 0

We can writ its solution as -

x = {- 12 ± √(144 + 24)}/4

x = (- 12 ± √168)/4

x = (- 12 ± 2√42)/4

x = (- 6 ± √42)/2

Therefore, the roots of the given quadratic functions are -

x = (- 6 ± √42)/2.

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Answer:

The angles are 60° and 120°.

Step-by-step explanation:

"supplementary" means that the two angles add up to 180°.

One angle can be x.

The other angle can be x+60° bc its 60° more.

Write an equation.

x + x + 60 = 180

combine like terms.

2x + 60 = 180

subtract 60

2x = 120

divide by 2

x = 60.

Since x = 60, one angle is 60° and the other is 120° (that's 60° more) and they are supplementary.

60° + 120° = 180°

The angles are 60° and 120°.

To perform the opposite translation, we add the opposite of the translation vector to the image point A': the coordinates of point A are (16, 5).

what is a vector?

In mathematics, a vector is an object that represents a quantity having both magnitude (or length) and direction. Vectors can be represented geometrically as arrows, where the length of the arrow represents the magnitude of the vector and the direction of the arrow represents the direction of the vector.

To find the coordinates of point A, we need to perform the opposite translation of moving along the vector 〈−6, 0〉 from the image point A'(10, 5). This is because a translation is a rigid motion that preserves the distance between points, so the distance between A and A' is the same as the distance between their respective translations.

To perform the opposite translation, we add the opposite of the translation vector to the image point A':

A = A' - 〈-6, 0〉 = (10, 5) - (-6, 0) = (16, 5)

Therefore, the coordinates of point A are (16, 5).

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After dividing and simplifying we get (x-3)/(x+3)

One of the four fundamental operations of arithmetic, or how numbers are combined to create new numbers, is division. The additional operations are addition, subtraction, and multiplication.

At a fundamental level, counting the instances in which one number is contained within another is one interpretation of the division of two natural numbers. There is no requirement that this quantity be an integer. For instance, if there are 20 apples and they are divided equally among four people, each person will get 5 apples (see picture).

The integer quotient, which is the quantity of times the second number is entirely contained in the first number, and the remainder are both produced by the division with remainder or Euclidean division of two natural numbers.

1/(x+4) divide by  [tex](x-3)/(x^2 + 7x +12)[/tex]

Simplify : [tex]x^2 +7x +12[/tex]

[tex]x^2 + (3+4)x + 12[/tex]

[tex]x^2 + 3x +4x + 12[/tex]

[tex]x(x + 3) + 4(x + 3)[/tex]

[tex](x+3)(x+4)[/tex]

[tex]1/(x + 4) x (x-3)/(x+3)(x-4)[/tex]

After dividing and simplifying we get the following answer;

[tex]= (x-3)/(x+3)[/tex]

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Answer: 163.36 in

Step-by-step explanation: Using the formula C=2πr you can plug in the radius and get your answer.

C=2 x pi x 26

C = 163.362817987

round as needed

Answer: 163.36

Im pretty sure all you have to do is use the formula

C=2πr

Step-by-step explanation:

C=2π(26)

163.36

Answer:

Step-by-step explanation:

312/520 equals 60%

other people 40%

Answer:

\

Step-by-step explanation:

Given expression: 3x+9

Take 3 outside from the expression, we get,

= 3(x+3), which is called the equivalent expresion

The value of the cube root [tex]343x^9y^{12}z^6[/tex] is [tex]7x^3y^4z^2[/tex]

A number's cube root is a quantity that when multiplied by itself three or more times, returns the original quantity. The cube root of 27, represented as 327, for instance, is 3 because 3 x 3 x 3 = 27 = 33 when we multiply 3 by itself three times. As a result, we can state that the cube root yields a value that is essentially cubed. Thus, 27 is referred to as the ideal cube. We may deduce what the cube's root is from the word "cube root." It denotes the integer that brought about the cube under the root.

The cube root 0f  [tex]343x^9y^{12}z^6[/tex]

[tex]\sqrt[3]{343x^9y^{12}z^6} \\\sqrt[3]{(7x^3y^4z^2)^3} \\\\\\7x^3y^4z^2[/tex]

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