Hey everyone,


right now

I want you to stop

stop whatever you are doing

walk to a mirror

look in it

look at your face

your gorgeous face

look at your eyes

how they shine

look at your hair

it's perfect

you are beautiful

I hope you realize

you are pretty freakin amazing <3

Answer:

Ek = Ekv + Ekh = 4.101 + 0.914 = 5.015J

Explanation:

A 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. What is its potential energy (PE) when it lands

The potential energy PE, relative to the ground, will be zero, because the lemming is at the ground level.

HOWEVER, a much better question would be:

A 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. What is its kinetic energy (KE) when it lands?

Let’s review the 4 basic kinematic equations of motion for constant acceleration (this is a lesson – suggest you commit these to memory):

s = ut + ½at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, u = 0, a = 9.81m/s^2, s = 5.36m

So we find v using equation (2)

v^2 = u^2 + 2as

v^2 = 0 + 2(9.81)(5.36) = 105.1632

So the kinetic energy resulting from the vertical drop is Ekv = ½mv^2

Ekv = ½(0.078)(105.16) = 4.101J

BUT we need to add in the kinetic energy resulting from the horizontal velocity, which did not change during the vertical drop.

Ekh = ½(0.078)(4.84^2) = 0.914J

So the total kinetic energy is Ek = Ekv + Ekh = 4.101 + 0.914 = 5.015J

The potential energy of the object with a mass of 0.0780 kg  moving from a height of 5.36 m is 4.09 J.

Potential energy of an object is generated by virtue of its position at a height from the ground. It is stored in the object when it is at rest, Whereas,  kinetic energy is generated by virtue of the motion of the body.  These energies are together called mechanical energy of the object.

When the object starts moving from rest, its potential energy starts to convert into kinetic energy and when it stops the reverse occurs . The potential energy of  a body is dependant on its mass and height by the equation:

p = mgh

Given that, mass of the object = 0.078 kg

height  h = 5.36 m

acceleration due to gravity g = 9.8 m/s²

then potential energy p = 0.078 × 9.8 m/s² ×5.36 m = 4.09 J

Therefore, the potential energy of the lemming is 4.09 J.

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

m is the mass

f is the force

From the question we have

[tex]a = \frac{56}{7} \\ [/tex]

We have the final answer as

Hope this helps you

Considering a scenario in which the Sun is going to explode.

In order to escape the explosion, we depart in a spacecraft with a speed of v = 0.8c.

The star Tau Ceti is 12 life years away.

At the midpoint of the journey, the Sun as well as Tau Cetik explode. at the same instant.

Imagine a hermit who is immobile with respect to both the Sun and Tau Ceti and resides on an asteroid that is midway between both. He observes the blast waves of both explosions as our spaceship passes him. This observer concludes that the two stars blew up simultaneously because he believes both stars to remain stationary.

In the frame of reference, the Sun and Tau Ceti explode at the same time and will remain stationary.

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Answer:

B. Applied

Explanation:

Applied means that somethings is pushing directly into it like a person to a box. and well the reasons why the others are not contact force are because gravity its cause to an attraction to the planet and no matter where you are it will still attract you, electric is not because it can flow through air, magnetic it affects to an invisible field that even if its not torching the marital you can still feel the magnetic push or pull

So applied

Answer:

C.

Explanation:

kilograms and m/s^2

The three different paper airplane designs were created by Ricardo. In an effort to determine which design flies the farthest, Ricardo intends to fly each paper airplane five times. Following each flight, Ricardo should measure the distance flown by the aircraft and note it.

Two of the most frequent techniques used in agricultural surveying involve measuring angles and distances with basic tools. even when the tools are basic. With diligence and practice, a great degree of precision can be attained.

The (1) pace is the main technique for gauging distance. 2) The odometer. (3) chaining or taping. four stages. optical range finder, number 5. and (6) techniques for electronic distance measurement (EDM).

It will be beneficial to review the standard units of distance first (displacement). The following are the standard English units:

12 inches make up one foot (in)

Yd (yard) = 3 feet (ft)

1 rod is equal to 16.5 feet and 5.5 yards (yd)

A mile is equal to 5280 feet, 1760 yards, and 320 rods.

When converting between different units of measurement, the units cancellation approach comes in quite handy.

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Adding the rise time and fall time then the package to reach the ground in 3.647 second.

Time can be defined in the sence as,that it is a continued sequence of existence and events that occurs in an apparently irreversible succession from the past, through the present, into the future.

We are given that ,

The packege 's trajectory into a rise to maximum height and fall from there to the ground .Rise to maximum height begins at vertical position is  given as,

Vertical position of the helicopter = H₀ = 20 m,

Initial velocityof helicopter = u = 14 m/s upward

Covered time of the helicopter =t₁ = 0,

Acceleration under gravity of helicoper=(- a) = -9.81 m/s²

Rise ends when instantaneous velocity v = 0,

Therefore, from the equation of motion for velocity as a function of time is  written as ,

v = a + at

0 = 14 m/s - (9.81 )m/s² t₁

t₁ = 1.427sec

Thus , the velocity changes linearly over time t₁ sec from u = 0 m/s then the averaging velocity can be given by w i.e.

w = u /2 = (14m/s)/2

w = 7 m/s

Therefore, maximum height of packege is given as,

H₁ = H₀ + w × t₁

H₁ =20m + 9.81m/s (1.427)s

H₁ = 33. 998 m

Therefore, when the packege fall from maximum height begins at ,

Time= t₁ = 0,

Position= h = H₁

Velocity= u = 0, and

Acceleration due to gravity downward=(-a) = -9.81 m/s²

Thus the  equation of motion for position (s) as a function of initial position (h) is can be written as,

s = h + ut₁ + (1/2) at₂²

0 = H₁ + 0 + (1/2) (-9.81)t₂²

t₂² = 4. 890 s

t₂ = 2.21 s

Hence , on adding the rise time t₁ and fall time t₂

Total time T = t₁ + t₂

T = 1.427 s + 2.21s = 3.647 s

Thus, then the package to reach the ground in 3.647 second.

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Answer:

[tex]v_x=34 m/s[/tex]

[tex]v_y=53.9\ m/s[/tex]

Explanation:

Horizontal Launch

When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it eventually hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

vx=v

The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:

[tex]v_y=g.t[/tex]

The horizontal component of the velocity is always the same:

[tex]v_x=34 m/s[/tex]

The vertical component at t=5.5 s is:

[tex]v_y=9.8*5.5=53.9[/tex]

[tex]v_y=53.9\ m/s[/tex]

Answer:

ewwwwwwwwwwww

get it out!

Answer:

  0.6 seconds

Explanation:

The time to fall from height h is ...

  t = √(2h/g)

  t = √(2(1.86 m)/(9.8 m/s^2)) ≈ √0.3796 s ≈ 0.616 s

It would take about 0.6 seconds for the projectile to hit the ground.

Answer:

0.6 seconds

is ur answer :)

✌❤

Answer:

The net force acting on the mass is 16.523 N

Explanation:

The given mass of the object, m = 1.3 kg

The length of the inclined plane over which the mass slides = 8.7 × 10⁻¹ m

The time it takes the mass to slide = 0.37 s

Therefore, we apply the following kinematic equation of motion;

s = u·t + 1/2·a·t²

Where;

u = The initial velocity of the mass = 0 m/s

t = The time taken for the motion = 0.37 s

a = The acceleration

s = The distance moved in the motion = 8.7 × 10⁻¹ m = 0.87 m

Plugging in the values gives;

0.87 = 0 × t + 1/2 × a × 0.37²

∴ 0.87 = 1/2 × a × 0.37²

a = 0.87/(1/2 × 0.37²) ≈ 12.71 m/s²

The net force acting on the mass is F = Mass, m × Acceleration, a force = m × a

Therefore, the net force acting on the mass is F = 1.3 × 12.71 = 16.523

The net force acting on the mass, F = 16.523 N.

The net force acting on the mass along the incline is 16.523 N

From the information given:

According to the second equation of motion;

[tex]\mathbf{S = ut + \dfrac{1}{2}at^2}[/tex]

the initial velocity u = 0 m/s since the mass starts from the rest

∴

[tex]\mathbf{S =0(t) + \dfrac{1}{2}at^2}[/tex]

[tex]\mathbf{S = \dfrac{1}{2}at^2}[/tex]

2S = at²

[tex]\mathbf{a = \dfrac{2S}{t^2}}[/tex]

[tex]\mathbf{a = \dfrac{2\times 0.87 \ m}{0.37^2}}[/tex]

acceleration (a) = 12.71 m/s²

The net force now acting on the mass along the incline can now be estimated as:

[tex]\mathbf{F_{net} = ma}[/tex]

[tex]\mathbf{F_{net} = 1.3 \ kg \times 12.71 \ m/s^2}[/tex]

[tex]\mathbf{F_{net} = 16.523 \ N}[/tex]

Therefore, we can conclude that the net force acting on the mass along the incline is 16.523 N

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In other words, it would take Deep Space 1 more than 81,000 years to travel the 4.24 light-years between Earth and Proxima Centauri at its top speed of 56,000 km/h. In relation to human history, that would be more than 2,700 generations.

Nearly 40 trillion kilometers, or 4.4 light-years, separate us from Alpha Centauri. The NASA-Germany Helios probes, the fastest spacecraft to date to be launched into orbit, flew at a speed of 250,000 kilometers per hour. The probes would need 18,000 years to travel at such pace to arrive at the sun's nearest neighbor. The calculations reveal that it is almost impossible to reach the nearest star in a human lifetime, even with the most futuristic technologies.

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Answer:

70.4%

Explanation:

Step one:

given data

input energy= 2280J

output energy=  1,606 Joules  of useful kinetic and 55joules waste

hence the useful out put= 1606J

Required

The efficiency of the motor

Step two:

what is the efficiency of a motor?

efficiency is the ratio of mechanical power delivered by the motor (output) to the electrical power supplied to the motor (input)

Efficiency= 1606/2280*100

Efficiency=0.704*100

Efficiency=70.4%

They are maintaining their body temperature by cooling down, like dogs do, as they don't have enough sweat glands to keep them cool without panting.

Brown bears maintain body temperature by cooling as a result of panting. So, the correct option is D.

Normal human body-temperature is defined as the typical temperature range found in humans which is commonly referred to as 36.5–37.5 °C. The human body temperature varies. Temperature is known as the degree of hotness or coldness of an area or object.

When we are very hot, the blood vessels of the skin dilate to carry the excess heat to the surface of the skin. Brown bear panting ensures that cool air circulates over the moist surfaces in the mouth which helps maintain body temperature by cooling the body.

Therefore, the correct option is D.

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The ranking of the measurement from the largest to the smallest is 11.6 mg > 0.000006 kg > 1021 µg > 0.31 mg.

Ranking of measurement is a classification that describes the nature of information within the values assigned to variables.

This is usually done based on the size of each item in the list of measurement.

11.6 mg = 0.0116 g

1021 µg = 0.001021 g

0.000006 kg = 0.006 g

0.31 mg = 0.00031 g

Thus, the ranking of the measurement from the largest to the smallest is 11.6 mg > 0.000006 kg > 1021 µg > 0.31 mg.

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The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C

R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m

[tex]Q\;(\text{total charge of the solid sphere})=(26\;\mathrm{\mu C})\left(\dfrac{1\;\mathrm{C}}{10^6\;\mathrm{\mu C}} \right)={26\times 10^{-6}\;\mathrm{C}}[/tex]

Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:

[tex]E=\dfrac{Q}{4\pi\epsilon_0 r^2}[/tex]

Substitute numerical values:

[tex]E&=\dfrac{24\times 10^{-6}}{4\pi (8.8542\times 10^{-12})(0.6)}\\ &={6.49\times 10^5\;\mathrm{N/C}\;\text{directed radially outward}}}[/tex]

The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.

As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).

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The amplitude of the resultant wave in terms of the common amplitude [tex]y_m[/tex] of the two combining waves which are out of phase by [tex]\frac{\pi}{2} \ \text{rad}[/tex] is [tex]\sqrt{2} y_m[/tex].

The amplitude of two waves interfering with each other depends on the principle of superposition.

Since, the waves are out of phase by [tex]\frac{\pi}{2} \ \text{rad}[/tex] so we can write the waves to be:

[tex]y_1=Asin(kx-\omega t)[/tex]

[tex]y_2=Asin(kx-\omega t+\frac{\pi}{2})\\ \therefore y_2=Acos(kx-\omega t)[/tex]

According to the principle of superposition, the resultant wave is written as:

[tex]y=y_1+y_2[/tex]

[tex]\Rightarrow y=A[sin(kx-\omega t)+cos(kx-\omega t)]\\\Rightarrow y=\sqrt{2}A[\frac{1}{\sqrt{2}}sin(kx-\omega t)+\frac{1}{\sqrt{2}}cos(kx-\omega t)]\\y=\sqrt{2}Asin(kx-\omega t+ \frac{\pi}{4})[/tex]

So from the above relation, we have the amplitude to be:

New Amplitude = [tex]\sqrt{2}A[/tex]

Hence, the amplitude of the combined waves is [tex]\sqrt{2}A[/tex].

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Answer:

U^U

Explanation:

Two-dimensional vectors have two components: an x vector and a y vector. Each of these vector components is a vector in the direction of one axis. The sum of the components of vectors is the original vector. Three-dimensional vectors have a z component as well.

The aircraft takes 25s to become airborne and will cover a distance of 1.0417km.

Distance, s = [tex]\frac{300km}{1 h}[/tex]

                s = [tex]\frac{300 }{1}[/tex] × [tex]\frac{1000m}{3600s}[/tex]

                s = [tex]\frac{250}{3}[/tex] m/s

Velocity is the time derivative of the displacement, [tex]v(t)=\frac{d}{dt}(\frac{5}{3}t^{2})[/tex]

                                                                                      [tex]v(t)=\frac{10}{3}t^{2}[/tex]

The time required to reach [tex]v=\frac{500}{3}[/tex] m/s,

                                              [tex]\frac{10}{3}t=\frac{250}{3}[/tex]

                                              [tex]t=25s[/tex]

Now, during this time, the aircraft travels a distance, [tex]D= \frac{5}{3} (25)^{2}[/tex]

                                                                                       [tex]D= 1041.667m[/tex]

                                                                                      [tex]D= 1.0417km[/tex]

Therefore, the aircraft takes 25s to become airborne and will cover a distance of 1.0417km.

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The nfl caliber wide receiver that can reach a top speed of 10.0 m/s in only 2.4 s has an acceleration during this time of: 4.16 m/s²

The formula and procedure we will use to solve this exercise is:

a = (vf - vi) /t

Where:

Information about the problem:

Applying the acceleration formula we have:

a = (vf - vi) /t

a = (10.0 m/s - 0 m/s) /2.4 s

a = (10.0 m/s) /2.4 s

a = 4.16 m/s²

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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Answer:

the circles are called Sun spots.  they are colder than the surrounding area.

Explanation:

Answer:

The circled areas are called__Sunspots___. They are___colder____ the surrounding area.

Explanation:

i just took the test it is correst plz give me a thanks or a brainiest and ill give 1 back :D

The negative acceleration of the truck is -2 m/s.

Acceleration of the body is the rate of change of speed with respect to time. The acceleration of the body is calculated by dividing the change in speed during a particular interval of time, by the time taken to change the speed.

According to the question, the initial speed of the truck is 40 m/s and it decreases to 20 m/s after 10 seconds. As the speed of the truck is decreasing, its sign is negative.

So given in the question

Initial Speed= u = 40 m/s

Final Speed= v = 20 m/s

Change in velocity = v - u

                               = 20 - 40

                               = -20 m/s

Time interval = 10 seconds

Acceleration = Change in Velocity/Time interval

                     = -20/10

                     = -2 m/s

So the acceleration of the truck is equal to -2 m/s. The negative sign indicates the speed is decreasing.

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Answer:

It takes 0.416 seconds to hit the ground.

Explanation:

speed = distance/ time

12 = 5/ x (multiply both with x)

12x = 5 (÷ 12)

x = 0.416 s

The force is attractive.

The force between two parallel currents I₁ and I₂ that are spaced apart by r is measured as the ratio F/L. If the currents are flowing in the same direction, the force is attracting; if not, it is repulsive.

Each parallel wire carries 3.00 A of current in the same direction and is spaced apart by 6.00 cm.

Think of these two wires as being placed side by side on a table, with currents flowing in opposite directions toward you—wire 1 to the left and wire 2 to the right. The magnetic field produced by wire 1 at the location of wire 2 is directed vertically upward, according to the right-hand rule that links current to field direction. The force experienced by wire 2 as a result of its current flowing through this field is therefore determined by the right-hand rule, which links current and field to force, to be to the left, back toward wire 1. The force that one wire applies to another is therefore an attractive force.

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Therefore, Mc² = 2mc²[ 1 + (K/mc²)] where K s the kinetic energy of each of the two identical colliding particles.

Consider a collision between two protons that is perfectly inelastic: an incident proton with mass m(p), kinetic energy K, and momentum magnitude p combines with a target proton that was initially stationary to form a single product particle with mass M.

Now,

In this case, the problem is alleviated by using colliding beams.

A pair of interacting particles' combined momentum may be zero.

After the collision, the center of mass is at rest.

Therefore, all the initial kinetic energy can be used to create particles.

Let K be the kinetic energy of each of the two identical colliding particles.

Therefore, the energy released by the two colliding beams are:

E₁ = K + mc² and E₂ = K + mc²

In the final state,

E(f) = Mc² where M is the new mass of the single product after the collision.

By conservation of energy,

E₁ + E₂ =E(f)

K + mc² + K + mc² = Mc²

2K + 2mc² = Mc²

Taking 2mc² common, we get

Mc² = 2mc²[ 1 + (K/mc²)]

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Answer: True

Explanation:

Answer:

false

Explanation:

hope this help (brainlist plz)

Time taken to reach height is 4 seconds.

Given that;

Velocity of cannon ball = 80 m/s

Height taken = 320 meter

Find:

Time taken to reach height

Computation:

S = ut + (1/2)gt²

320 = (80)(t) + (1/2)(10)(t²)

320 = 80t + 5t²

t² + 16t + 64

So,

t = 4

Time taken = 4 seconds

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He should repeat the test with three additional batteries of varying voltages to demonstrate the reproducibility of results. he should use only one battery but do several trials, using different circuit designs to ensure he has appropriate test groups - this can improve the student's experiment.

Reproducibility, otherwise called replicability and repeatability, is a significant rule supporting the logical technique. For the discoveries of a review to be reproducible implies that results got by an examination or an observational review or in a factual investigation of an informational index. Albeit numerous organic researchers instinctively accept that the reproducibility of a trial implies that it tends to be repeated, Drummond makes a differentiation between these two terms. Informational indexes are huge and calculations are more refined. This requests reproducibility to decrease the mistake and predisposition when people are added to the course of information investigation.

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Answer:

-49.49

Explanation:

If there’s no air resistance then the only thing acting on the object is the force of gravity which is mass times gravity. And to get mass all we have to do is divide 50.5/10 then times that by -9.8 since that’s the force of gravity.

Answer: The answer would be 50.5 N.

Explanation: It’s because there’s no air resistance.