HELPPPPPPPPPP... please help i don't get this whatsoever and my teacher doesn't really help. i dont get none of it at all. please help asap !

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Answer:

X       H(x)=2x+3

-4       -5

0        3

1         5

2        7

3        9

Starting at vertex A and using the nearest neighbor algorithm, the path is: A-C-B-D-A, with a total distance of 95. This means visiting vertices in the order A, C, B, D, and back to A, and the total distance traveled is 95 units.

The nearest neighbor algorithm is used to find the shortest path between a set of points. Here are the steps to apply the algorithm in this case

Start at vertex A. Look for the closest neighboring vertex to A. In this case, the closest vertex is B, which is 7 units away from A. Move to vertex B and mark it as visited. Look for the closest neighboring vertex to B that has not been visited. In this case, the closest vertex is C, which is 11 units away from B.

Move to vertex C and mark it as visited. Look for the closest neighboring vertex to C that has not been visited. In this case, the closest vertex is D, which is 18 units away from C. Move to vertex D and mark it as visited.

Look for the closest neighboring vertex to D that has not been visited. In this case, the closest vertex is B, which is 15 units away from D. Move to vertex B and mark it as visited.

Look for the closest neighboring vertex to B that has not been visited. In this case, the closest vertex is E, which is 20 units away from B. Move to vertex E and mark it as visited.

Look for the closest neighboring vertex to E that has not been visited. In this case, the closest vertex is A, which is 24 units away from E. Move to vertex A and mark it as visited. All vertices have been visited, so the algorithm is complete.

The list of vertices visited, starting and ending at A, is A, B, C, D, B, E, A and the distance is 95.

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Answer: y = -|x + 1| + 1

Step-by-step explanation:

Since this is a "V" shaped graph, we know it uses the absolute value function. This is the parent function:

    y = |x|

This represents the transformations:

➜ a is amplitude

➜ h is horizontal shift

➜ k is vertical shift

    f(x) = a | x - h | + k

Next, we see it is shifted one unit upwards.

    y = |x| + 1

Then, we see it is also shifted one unit left.

➜ Note that this shift is -h units, so we will use positive for moving left.

    y = |x + 1| + 1

Lastly, we see this graph is flipped and has a negative slope, or amplitude.

    y = -|x + 1| + 1

The constant of proportionality of the line is slope m = 2/3

Given data ,

Let the line be represented as A

Now , the value of A is

Let the point on the straight line be P ( 2 , 3 )

Now , from the proportionality , we get

y = kx

Divide by x on both sides , we get

k = y/x

So , the slope of the line is k

k = 2/3

Hence , the proportion is y = ( 2/3 )x

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Answer:

We can use Bayes' theorem to calculate P(R), which states that the probability of an event A given event B is equal to the probability of B given A multiplied by the probability of A, divided by the probability of B:

P(R|T) = P(T|R) * P(R) / P(T)

We can rearrange this equation to solve for P(R):

P(R) = P(R|T) * P(T) / P(T|R)

We are given that P(RI-T) = 0.25, which can be written as:

P(R∩T) = P(R|T) * P(T) = 0.25

We are also given that P(-R|T) = 0.2, which can be written as:

P(-R∩T) = P(-R|T) * P(T) = 0.2 * 0.1 = 0.02

We can use the law of total probability to find P(T|R):

P(T|R) = P(RI-T) / P(R) = 0.25 / P(R)

We can substitute these values into the equation for P(R) to get:

P(R) = P(R|T) * P(T) / P(T|R)

= 0.25 / [P(T|R) * P(T) + P(-R|T) * P(T)]

= 0.25 / [0.25 + 0.02]

= 0.1060

Therefore, the answer is option C: 0.1060.

Let's start by setting up a proportion to represent the ratio of Illinois students to Michigan students:

Illinois students / Michigan students = 6/5

We can simplify this proportion by multiplying both sides by 5:

Illinois students = 6/5 * Michigan students

Next, we can use the information in the table to set up an equation that relates the number of Illinois students, Michigan students, and Indiana students:

Illinois students + Michigan students + Indiana students = 175

We can substitute the expression we obtained for the number of Illinois students into this equation:

6/5 * Michigan students + Michigan students + Indiana students = 175

Multiplying both sides by 5 to eliminate the fraction, we get:

6 * Michigan students + 5 * Michigan students + 5 * Indiana students = 875

Combining like terms, we get:

11 * Michigan students + 5 * Indiana students = 875

Now we can use the fact that the ratio of Illinois students to Michigan students is 6:5 to set up another equation:

Illinois students / Michigan students = 6/5

Substituting the values from the table, we get:

Illinois students / Michigan students = 24/20

Cross-multiplying, we get:

Illinois students * 20 = Michigan students * 24

Simplifying, we get:

Illinois students = 6/5 * Michigan students = 24/20 * Michigan students = 6/5 * 24 Michigan students = 28.8 Michigan students

Since the number of students must be a whole number, we can round 28.8 up to 29. This means that there were 29 Michigan students.

Substituting this into the equation we obtained earlier, we get:

11 * 29 + 5 * Indiana students = 875

Solving for Indiana students, we get:

5 * Indiana students = 875 - 11 * 29 = 546

Dividing both sides by 5, we get:

Indiana students = 546/5 = 109.2

Since the number of students must be a whole number, we can round 109.2 up to 110. This means that there were 110 Indiana students.

Therefore, the answer is 110 students from Indiana.

Answer:

Step-by-step explanation:

it should be shaded at the 76

The finance charge for Sandra Lazzaro, using the average daily balance method, is $13.63.

The average daily balance is one of the methods for computing the finance charges (interest and other fees).

The average daily balance method uses the balance owed at the end of each day of the billing period, and not the balance owed at the end of the week, month, or year.

Billing period for the credit card = 31 days

Unpaid credit card balance = $750

Payment made three days before month-end = $600

Finance charge rate per month = 2.2%

Method = Average daily balance

Day        Description    Amount    Average Balance

1 - 28     Balance           $750       $21,000 ($750 x 28 days)

29 - 31   Payment        -$600       $-1,800 ($600 x 3 days)

31           Total                              $19,200

Average daily balance = $619.35 ($19,200 ÷ 31)

Finance charge = $13.63 ($619.35 x 2.2%)

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Answer: 55

Step-by-step explanation:

The expanded form of log y^10 is either 10 log y or 10 ln y

Assuming that the base of the logarithm is not specified, we can use the change of base formula to expand the logarithm:

log y^10 = log (y^10) / log (base)

Using base 10:

log y^10 = log (y^10) / log 10

= 10 log y / 1

= 10 log y

Using natural logarithm:

log y^10 = log (y^10) / log e

= 10 log y / 1

= 10 ln y

Therefore, the expanded form of log y^10 is either 10 log y or 10 ln y, depending on the base used.

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Answer:

B

D

E

( all of the answers (E, D, B) have no real solutions)

Answer:

x^3-18x^2+108x-216

There is a formula for this simplification, and you can write the answer directly if you remember the formula.

The general formula for f'(x) would be f' (x) = - 8 sin (x) + C.

The most general formula based on the first would be f(x) = 8 cos ( x ) + Cx + D.

To find the most general formula for f ' ( x ), we need to integrate f'' ( x ) with respect to x:

f'' ( x ) = - 8 cos (x)

f' (x) = ∫ ( -8cos(x)) dx

f ' (x) = - 8 sin(x) + C, where C is an arbitrary constant.

We need to integrate f'( x ) with respect to x to find the most general formula for f ( x ):

f'(x) = - 8 sin(x) + C

f(x) = ∫ ( - 8sin ( x ) + C) dx

f(x) = 8 cos ( x ) + Cx + D, where D is another arbitrary constant.

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Answer:

angle 5 is 120 since there is Z shape with angle 3

Answer:

  (x -6)² +(y +2)² = 128

Step-by-step explanation:

You want the equation of the circle centered at (6, -2) through point (14, 6).

The equation of a circle with center (h, k) and radius r is ...

  (x -h)² +(y -k)² = r²

For center (h, k) = (6, -2), we can find the value of r² knowing that it will be the value that lets the point (14, 6) satisfy the equation.

  (14 -6)² +(6 -(-2))² = r² = 8² +8² = 128

The circle equation is ...

  (x -6)² +(y +2)² = 128

Answer: To factorize 3h² + 12h, we can first find the greatest common factor (GCF) of the two terms, which is 3h:

3h(h + 4)

This is the fully factorized form of 3h² + 12h.

The accrued value of the account in 10 years is $641.75

From the question, we have the following parameters that can be used in our computation:

Using the above as a guide, we have the following:

Amount = P * (1 + 0.25r)ᵗ

Where

P = Principal = 600

r = Rate = 2.7% = 0.27

t = time = 10

Substitute the known values in the above equation, so, we have the following representation

Amount = 600 * (1 + 0.25 * 0.27)¹⁰

Evaluate

Amount = 641.75

Hence, the amount is 641.75

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The circled portion in the confidence interval formula p ± z represents the Margin of Error, which plays a crucial role in interpreting the range of plausible values for the population parameter.

In the confidence interval formula p ± z, the circled portion represents the Margin of Error.

The Margin of Error is a critical component of a confidence interval and quantifies the level of uncertainty in the estimate.

It indicates the range within which the true population parameter is likely to fall based on the sample data.

The Margin of Error is calculated by multiplying the critical value (z) by the standard deviation of the sampling distribution.

The critical value is determined based on the desired level of confidence, often denoted as (1 - α), where α is the significance level or the probability of making a Type I error.

The Margin of Error accounts for the variability in the sample and provides a measure of the precision of the estimate.

It reflects the trade-off between the desired level of confidence and the width of the interval.

A larger Margin of Error indicates a wider confidence interval, implying less precision and more uncertainty in the estimate.

Conversely, a smaller Margin of Error leads to a narrower confidence interval, indicating higher precision and greater certainty in the estimate.

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The area between the curves is 61.5 square units.

To compute the area between the curves y = 9x and y = x^2 - 10, find the points of intersection between the curves.

Setting the two equations equal to each other:

x^2 - 10 = 9x

Move all to one side:

x^2 - 9x - 10 = 0

Factor the quadratics:

(x - 10)(x + 1) = 0

So, the points of intersection are x = -1 and x = 10.

Now, determine which curve is above the other in the interval between -5 and 3. Evaluating the y-coordinates of each curve at a point in this interval, say x = 0.

y = 9x, y = 0 at x = 0, so the curve passes across the origin.

y = x^2 - 10, y = -10 at x = 0.

Therefore, the curve y = 9x is above y = x^2 - 10 in the interval [-5, 3].

To compute the area between the curves, take the integral of the top curve minus the integral of the bottom curve over the interval of intersection:

∫(-1 to 3) [9x - (x^2 - 10)] dx

Simplify:

∫(-1 to 3) [ -x^2 + 9x + 10] dx

Then, integrate each term of the polynomial:

[ (-1/3) x^3 + (9/2) x^2 + 10x ] evaluated from x = -1 to x = 3

Plug into the limits of integration and then simplify:

= [ (81/2) - (19/3) ] - [ (-1/3) - (17/2) ]

= 61.5

Therefore, the area between the curves is 61.5 square units.

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The total amount of water that flows from the storage tank between the 7 minute mark and the 37 minute mark is 720 liters.  

The amount of fluid that moves through a pipe or other container over a given amount of time.

The amount of water that flows from the storage tank between the 7 minute mark and the 37 minute mark can be calculated using the equation for the rate at which the water is flowing.

Given that the rate at which the water is flowing at time t is r(t)=200-4t liters per minute and that 0≤t<50, the total amount of water that flows from the storage tank between the 7 minute mark and the 37 minute mark can be calculated as follows:

Total amount of water = ∫r(t)dt  

                   = ∫(200 - 4t)dt  

                   = (200t - 4t²)  

                   = (200(37) - 4(37²)) - (200(7) - 4(7²))  

                   = 1924 - 1204  

                   = 720 liters

The rate of flow decreases linearly with time, which means that the total amount of water flowing from the tank at any given time is equal to the area under the graph of the rate of flow.

This means that the total amount of water that flows from the tank between the 7 minute mark and the 37 minute mark can be calculated by integrating the rate of flow function over the given time interval.

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T(-1, 7)

→

T′(-1, -7)

U(-1, 8)

→

U′(-1, -8)

V(9, 6)

→

V′(9, -6)

The triangle has one solution. The remaining side c ≈ 4 and remaining angles B = 30°; C = 31°.

Option D is correct.

if angle A is obtuse and if a > b then the triangle has one solution

We are given ∠ = 119° which is obtuse and side a= 7 and side b - 4 i.e 7>4 so, the triangle has one solution.

Finding remaining sides c and ∠B and ∠C

Using the Law of sines to find ∠B

a/sin A = b/sin B

7/sin 119° = 4/sin B

7 * sin B = 4 * sin 119

7*sin B = 4(0.874)

sin B = 3.496/7

B = sin^-1(0.4994)

B = 29.96 = 30°

We know that sum of angles of triangle = 180°

So, 180° = 119° + 30° +∠C

180° = 149° + ∠C

=> ∠C = 180° - 149°

∠C = 31°

Now finding c

b/sin B = c /sin C

4/Sin 30 = c/sin 31

4* sin 31 = c*sin 30

4*0.515 = c* 0.5

=> c =  4*0.515/0.5

c = 4.12 ≈ 4

So, Option D one solution; c ≈ 4; B = 30°; C = 31° is correct.

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Determine whether the given triangle has no solution, one solution or two solutions. Then solve the triangle. Round measures of sides to the nearest tenth and measures of angles to the nearest degree

A = 119°, a=7, b=4

Question 7 options:

one solution; c ≈ 7; B = 30°; C = 119°

no solution

one solution; c ≈ 4; B = 31°; C = 30°

one solution; c ≈ 4; B = 30°; C = 31°

The null and the alternate hypothesis are:

In hypothesis testing, we take the null hypothesis (H₀) and the alternative hypothesis (H₁). The null hypothesis is the opposite of the claim , while the alternative hypothesis states  the claim.

In this case, the null hypothesis is that a majority of adults would not erase their personal information online if they could (i.e., 50% or less of them would do so). The alternative hypothesis is that a majority of adults would erase their personal information online if they could (i.e., more than 50% of them would do so). In symbolic form:

H₀: p ≤ 0.5

H₁: p > 0.5

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The simplified polynomial for the area and perimeter of the rectangles are:

13). Area = 5x² + 40, Perimeter = 12x + 16

14). Area = x² + 10x + 12, Perimeter = 4x + 20

Area of rectangle = Length × Width

Perimeter of rectangle = 2(Length + Width)

13). Area of the rectangle = 5x × (x + 8)

Area of the rectangle = 5x² + 40

Perimeter of the rectangle = 2[5x + (x + 8)]

Perimeter of the rectangle = 2(6x + 8)

Perimeter of the rectangle = 12x + 16

12). Area of the rectangle = (x + 3)(x + 7)

Area of the rectangle = x² + 7x + 3x + 21

Area of the rectangle = x² + 10x + 21

Perimeter of the rectangle = 2[(x + 3) + (x + 7)]

Perimeter of the rectangle = 2(2x + 10)

Perimeter of the rectangle = 4x + 20.

Therefore, the simplified polynomial for the area and perimeter of the rectangles are:

13). Area = 5x² + 40, Perimeter = 12x + 16

14). Area = x² + 10x + 12, Perimeter = 4x + 20

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Answer:

x^3 + x^2 - 5x + 3

In 12 days, both Eve and Jenna will work out on the same day again.

To find the number of days until Eve and Jenna work out on the same day again, we need to find the least common multiple (LCM) of 6 and 4.

One way to find the LCM is to list the multiples of each number until we find a multiple that they have in common:

Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, ...

Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, ...

From this list, we see that the least common multiple of 6 and 4 is 12.

This means that in 12 days, both Eve and Jenna will work out on the same day again.

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[tex][D]= \begin{bmatrix} 5&0&-8\\ 10&-2&7\\ -3&-9&6 \end{bmatrix}\implies 2[D] \stackrel{ \textit{scalar multiplication} }{\begin{bmatrix} (2)5&(2)0&(2)-8\\ (2)10&(2)-2&(2)7\\ (2)-3&(2)-9&(2)6 \end{bmatrix}} \\\\\\ ~\hspace{12.5em} 2[D]= \begin{bmatrix} 10&0&-16\\ 20&-4&14\\ -6&-18&12 \end{bmatrix}[/tex]

The best estimate of 7,625,750,263 is 7x10⁹. So the correct option is B.

The given number is 7,625,750,263.

To express the above number in words, it is "seven billion six hundred twenty-five million seven hundred fifty thousand two hundred sixty-three". So, the given value ultimately has a billion value.

To find the correct answer let's see the given options and eliminate each one to find the correct answer. Option A is 7 x 1010 = 7070 which is not even coming to a close, so option A is eliminated.

Let's see the second option which is 7x10⁹ which is 7000000000, which is 7 billion. So, option B is very near to the answer.

Let's see the third option which is 8x10¹⁰ which is 80 billion, it is not an estimated value. So, it is also eliminated and the final option is 8x10⁹ which is 8 billion which is also high value So, it is also eliminated.

From the above analysis, we can conclude that the best estimated value for 7,625,750,263 is 7x10⁹ which is option B.

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a) Null: Mean = 20 days; Alt: Mean > 20 days. b) supported by t-value 6.708 > critical value at α=0.05. c) 95% confidence interval for mean patient discharge time is between 20.528 and 23.472 days, d) 99% confidence, a minimum sample size of 67 patients is required.

a) The null hypothesis is that the mean days for a patient to discharge is still 20 days, while the alternative hypothesis is that the mean days for a patient to discharge has increased and is now greater than 20 days.

Null hypothesis: 0:  = 20

Alternative hypothesis: 1:  > 20

b) We can use a one-sample t-test to test the hypothesis. We will use a significance level of 0.05.

The test statistic is given by:

t = (x - ) / (s / √n)

where x is the sample mean,  is the hypothesized population mean, s is the sample standard deviation, and n is the sample size.

Here, x = 25,  = 20, s = 5, and n = 30. Plugging these values into the formula, we get:

t = (25 - 20) / (5 / √30) = 6.708

The degrees of freedom (df) for the t-distribution is n - 1 = 29. Using a t-table or calculator, the p-value for a one-tailed test with df = 29 and t = 6.708 is < 0.0001.

Since the p-value is less than the significance level of 0.05, we reject the null hypothesis. There is sufficient evidence to conclude that the mean days for a patient to discharge has increased.

c) To construct a 95% confidence interval for the mean days for a patient to discharge, we use the formula:

CI = x ± tα/2 * (s/√n)

where x is the sample mean, s is the sample standard deviation, n is the sample size, and tα/2 is the critical value for a t-distribution with df = n-1 and α = 0.05/2 = 0.025.

Here, x = 22, s = 5, and n = 40 (30 from the first sample + 10 from the second sample). The critical value for tα/2 with df = 39 is 2.022.

Plugging these values into the formula, we get:

CI = 22 ± 2.022 * (5/√40) = (20.528, 23.472)

Therefore, we can be 95% confident that the true mean days for a patient to discharge is between 20.528 and 23.472 days.

d) To find the minimum sample size required to estimate the mean days for a patient to discharge to within 2 days of error with a 99% confidence, we use the formula:

n = (zα/2 * s / E)²

where zα/2 is the critical value for a z-distribution with α = 0.01/2 = 0.005, s is the sample standard deviation (which we assume is the same as before, i.e., s = 5), and E is the desired margin of error (which is 2 days).

Plugging in the values, we get:

n = (2.576 * 5 / 2)² = 66.18

Therefore, the minimum sample size required is 67 patients.

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