help pls
evaluate
m -[(m-n) + (-2)](-5)
if m = -4 and n = -6

Answer:

If 2.5 gallons of paint are needed for the entire fence, then for 1/5 of the fence we need:

2.5 gallons / 5 = 0.5 gallons

To find how much paint is needed for 3/5 of the fence, we can multiply 0.5 gallons by 3:

0.5 gallons * 3 = 1.5 gallons

Therefore, 1.5 gallons of paint are needed for 3/5 of the fence.

Answer:

15 gallons

Step-by-step explanation:

1/5 of the fence would be 5 gallons, because 25/5 is 5, so to find how much paint for 3/5, we have to multiply 3 and 5 which gives us 15. We need 15 gallons of paint to paint 3/5 of the fence

Hope it helped!

The integers are 16.8 and 26.8. To find the integers, we need to use a system of equations. Let's call the first integer x and the second integer y. We know that one integer is 10 more than another, so we can write the first equation as: x = y + 10. We also know that their product is 375, so we can write the second equation as: xy = 375.

Now we can substitute the first equation into the second equation to solve for one of the integers.

y(y + 10) = 375

y^2 + 10y - 375 = 0

Using the quadratic formula, we can find the value of y:

y = (-10 ± √(10^2 - 4(1)(-375)))/2(1)

y = (-10 ± √1900)/2

y = (-10 ± 43.6)/2

y = 16.8 or y = -26.8

Since y has to be an integer, we can only use the value of 16.8.

So, y = 16.8 and x = 16.8 + 10 = 26.8.

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The sοlutiοn tο the inequality is all values οf x greater than -10. This can be represented οn a number line as shοwn in the figure attached.

A cοnnectiοn between twο expressiοns οr values that is nοt equal in mathematics is referred tο as inequality. Hence, inequity results frοm imbalance. In mathematics, an inequality establishes the cοnnectiοn between twο nοn-equal numbers. Equality and inequality are nοt the same.

Use the nοt equal symbοl mοst frequently when twο values are nοt equal (). Values οf any size can be cοntrasted using a variety οf inequalities.

By changing the twο sides until just the variables are left, many straightfοrward inequalities may be sοlved.

Nοnetheless, a variety οf factοrs suppοrt inequality: Bοth sides' negative values are split οr added. Exchange the left and the right.

5x - 15 + 15 > -65 + 15

5x > -50

5x/5 > -50/5

x > -10

Because the inequality is severe, the οpen circle at -10 shοws that it is nοt part οf the sοlutiοn set (i.e., x must be greater than -10, nοt greater than οr equal tο -10).

The right arrοw shοws that the sοlutiοn set gοes οn fοrever in that directiοn.

Hence, the sοlutiοn tο the inequality is all values οf x greater than -10. This can be represented οn a number line as shοwn in the figure attached.

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Knowing the functions f(x) and g(x) we have:

To find the sum, difference, product, and quotient of two functions, we simply perform the corresponding operations on the expressions for each function.

For (f+g)(x), we add the expressions for f(x) and g(x):

(f+g)(x) = (x² + 3x + 1) + (x^2) = 2x² + 3x + 1

For (f-g)(x), we subtract the expression for g(x) from the expression for f(x):

(f-g)(x) = (x² + 3x + 1) - (x²) = 3x + 1

For (f·g)(x), we multiply the expressions for f(x) and g(x):

(f·g)(x) = (x² + 3x + 1) · (x²) = x⁴ + 3x³ + x²

For (f/g)(x), we divide the expression for f(x) by the expression for g(x):

(f/g)(x) = (x² + 3x + 1) / (x²) = 1 + 3x/x² + 1/x² = 1 + 3/x + 1/x²

So, the final answers are:

(f+g)(x) = 2x² + 3x + 1

(f-g)(x) = 3x + 1

(f·g)(x) = x⁴ + 3x³ + x²

(f/g)(x) = 1 + 3/x + 1/x²

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First step is wrong (x-2) × 3x³ should be 3x⁴ - 6x³

not 6x²

Answer: 50in^2

Remember the formula for finding the area of a rectangle is:

A = (base)(height)

In this problem you find the area like so:

A = (12[tex]\frac{1}{2}[/tex])(4)

= ([tex]\frac{25}{2}[/tex])([tex]\frac{4}{1}[/tex])

= ([tex]\frac{25}{1}[/tex])([tex]\frac{2}{1}[/tex])

= 50in^2

Answer: 4 bracelets per hour

Step-by-step explanation:

You're basically finding the amount made in one hour instead of 5, so we just use an equation:

20 = 5x

x = 4

4 are made in an hour. Hope this helps!

a) sin B = y/r = -1/5sqrt(2) and cos B = x/r = 7/5sqrt(2) (b) Since sin B is positive and cos B is negative, we found that angle B belongs in Quadrant II.

Given that cot a = 7, we know that tan a = 1/7. Since tan a = y/x, we can let x = 7 and y = -1 (since a is in Quadrant III and both x and y values are negative in this quadrant).

Using the Pythagorean Theorem, we can find r:
r = sqrt(x^2 + y^2) = sqrt(7^2 + (-1)^2) = sqrt(50) = 5sqrt(2)
Now we can find sin B and cos B:
sin B = y/r = -1/5sqrt(2)
cos B = x/r = 7/5sqrt(2)

We can use the double angle formulas for sine and cosine, sin B and cos B: sin B = sin(Phi - a) = sin Phi cos a - cos Phi sin a = (0)(-7/25) - (1)(-24/25) = 24/25 cos B = cos(Phi - a) = cos Phi cos a + sin Phi sin a = (1)(-7/25) + (0)(-24/25) = -7/25.

Since sin B is positive and cos B is negative, we know that angle B is in Quadrant II.

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Thus, 2002 + 23 = 2025 is the year at which the populace hits 7 million.

The meaning of an equation in algebra is a mathematical assertion that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two expressions 3x + 5 and 14, which are split by the 'equal' symbol.

To find the year when the population reaches 7 million people, we need to solve the equation:

f(x) = 7

where f(x) represents the population, in millions of x years after 2002, and x is the number of years after 2002.

Substituting the given function f(x) = 6.7(1.0032)x into this equation, we get:

6.7(1.0032)x = 7

Dividing both sides by 6.7, we get:

1.0032x = 1.0448

When we take the natural log of both parts, we obtain:

ln(1.0032)x = ln(1.0448)

Using the logarithmic identity ln(aᵇ) = b ln(a), we can simplify this to:

x ln(1.0032) = ln(1.0448)

Dividing both sides by ln(1.0032), we get:

x = ln(1.0448) / ln(1.0032)

Using a calculator, we find:

x ≈ 22.6

Therefore, the population will reach 7 million people approximately 22.6 years after 2002. Rounding this to the nearest whole number, we get:

x ≈ 23

So the year when the population reaches 7 million people is 2002 + 23 = 2025.

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The value of 'x' and 'y' in the given circle and triangle are 30 and 12 respectively.

A triangle is a three-sided closed-plane figure formed by joining three noncolinear points.

Based on the side property triangles are of three types they are Equilateral triangle, Scalene triangle, and Isosceles triangle.

In a right-angled triangle, the sum of the squares of the smaller two sides of a right-angle triangle is equal to the square of the largest side.

From the given information we can form,

x² = 18² + 24². (As tangent is always perpendicular to the radius).

x² = 900.

x = 30.

Now, y = x - radius.

y = 30 - 18.

y = 12.

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Answer:

4700=πr²×31

4700/31=πr²

151.6.../π=r²

√151.6.../π=

6.946933566=r

r=6.95mm

Explain:

Volume of cylinder=

πr²×height

Answer:

x = -2.

Step-by-step explanation:

9.9 = 3.1 - 3.4x

9.9 - 3.1 = -3.4x

6.8 = -3.4

6.8 /-3.4 = -3.4/-3.4

-2 = x

Answer:

Please review the trigonometric proof below

Step-by-step explanation:

Given

[tex]\csc x -\sin x=\cos x \cot x[/tex]

Apply the reciprocal identity to [tex]\csc x[/tex].

[tex]\frac{1}{\sin x} -\sin x=\cos x \cot x[/tex]

Write [tex]-\sin x[/tex] as a fraction then multiply by [tex]\frac{\sin x}{\sin x}[/tex].

[tex]\frac{1}{\sin x} + \frac{-\sin x}{1} =\cos x \cot x[/tex]

[tex]\frac{1}{\sin x} + \frac{-\sin x}{1} *\frac{\sin x}{\sin x}=\cos x \cot x[/tex]

[tex]\frac{1}{\sin x} + \frac{-\sin x\sin x}{\sin x}=\cos x \cot x[/tex]

Combine the numerators over the common denominator.

[tex]\frac{1-\sin x\sin x}{\sin x}=\cos x \cot x[/tex]

Multiply [tex]\sin x[/tex] by [tex]\sin x[/tex].

[tex]\frac{1-\sin^2 x}{\sin x}=\cos x \cot x[/tex]

Apply the Pythagorean identity [tex]1-\sin^2 x=\cos^2 x[/tex]

[tex]\frac{\cos^2 x}{\sin x}=\cos x \cot x[/tex]

Factor [tex]\cos x[/tex] out of [tex]\cos^2 x[/tex].

[tex]\frac{\cos x\cos x}{\sin x}=\cos x \cot x[/tex]

Separate into two fractions.

[tex]\frac{\cos x}{1} *\frac{\cos x}{\sin x}=\cos x \cot x[/tex]

Apply the quotient identity [tex]\frac{\cos x}{\sin x}=\cot x[/tex].

[tex]\frac{\cos x}{1} *\cot x=\cos x \cot x[/tex]

Anything over 1 is just itself.

[tex]\cos x\cot x=\cos x \cot x[/tex]

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, = space

Answer:

csc x − sin x

= [tex]\frac{1}{sin, x}[/tex] - sin x

= [tex]\frac{1 - sin^{2}, x }{sin, x}[/tex]

= [tex]\frac{cos^{2}, x }{sin, x}[/tex]

= [tex]\frac{cos, x}{sin, x}[/tex] * cos x

= cot x cos x

∴csc x - sin x - cot x cos xQED

It is the most " explanation " I can think of.

Thus the answer is shown above..

Answer:

Step-by-step explanation:

Kelsie has written checks for a total of $46 + $82 + $264 + $127 = $519.

Since she only has $370 in her account, this means she has overdraft by $519 - $370 = $149.

Therefore, the bank will charge her $22 for each overdraft, which gives a total of $22 * 7 = $154.

Thus, Kelsie owes the bank a total of $519 + $154 = $673. Answer: \boxed{673}.

Based on the sample of the 48 South African households collected from the Census At School survey project, the mean number of people living in a household will be 6.208, and the standard deviation is 2.576.

However, it is important to note that this sample only represents a small fraction of the total number of the households in South Africa, so we cannot make definitive conclusions about the entire population based on this sample alone.

To get a more accurate estimate of the number of people living in the South African households, a larger and the more representative sample would need to be collected.

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The area of a cross section that passes through the center of a sphere with a diameter of 7 centimeters will be 12.25π cm².

Three-dimensional objects with a sphere-like shape exist in all three dimensions. Three axes, the x-axis, y-axis, and z-axis, are used to define the sphere. The key distinction between a circle and a sphere is this. In contrast to other 3D shapes, a sphere lacks any vertices or edges.

The sphere's points are evenly spaced apart from one another on its surface. In light of this, the sphere's surface and core are always equally separated from one another. The sphere's radius is the measurement between these points. Ball, globe, planets, and other objects are all examples of spheres.

Given : Diameter of Sphere = 7 cm

∴ Radius = 7/2 = 3.5 cm.

Since It is a cross section in a sphere, so, it would be circle.

So, Area of the cross section = Area of circle

Hence, Area of Cross section = πr²

                                                 = π (3.5)²

                                                 =  12.25π cm²

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Answer:

Step-by-step explanation:

lol sorry I know it but don’t know how up to right it sorry

slope of HI = 6, slope of IJ = -1/6, slope of HJ = 5/7, length of HI = √37, length of IJ = √37, length of HJ = √74, Triangle HIJ is isosceles

The slope of a line is found by the formula (y2-y1)/(x2-x1). The length of a line is found by the formula √((x2-x1)²+(y2-y1)²).

Slope of HI = (1-(-5))/(8-7) = 6/1 = 6
Slope of IJ = (-5-(-4))/(7-1) = -1/6
Slope of HJ = (1-(-4))/(8-1) = 5/7

Length of HI = √((8-7)²+(1-(-5))²) = √(1²+6²) = √(1+36) = √37
Length of IJ = √((7-1)²+(-5-(-4))²) = √(6²+(-1)²) = √(36+1) = √37
Length of HJ = √((8-1)²+(1-(-4))²) = √(7²+5²) = √(49+25) = √74

Triangle HIJ is isosceles because it has two sides with the same length (HI and IJ).

- slope of HI = 6
- slope of IJ = -1/6
- slope of HJ = 5/7
- length of HI = √37
- length of IJ = √37
- length of HJ = √74
Triangle HIJ is isosceles

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The cost of backpack is $38.97. The markup amount is $13.64. The regular unit selling price for the backpack is $52.61
Mountain Equipment Co-op will be $19.02.The profit will be $19.02, which is higher than the profit of $6.63 when selling at the regular unit selling price.

To find the cost, markup amount, regular unit selling price, and profit for the backpack, we need to use the following formulas:

1. Cost = List Price - Trade Discount - Quantity Discount
2. Markup Amount = Cost × Markup Percentage
3. Regular Unit Selling Price = Cost + Markup Amount
4. Profit = Regular Unit Selling Price - Cost - Expenses

Let's plug in the given values and calculate each of these:

1. Cost = $59.95 - ($59.95 × 0.25) - ($59.95 × 0.10) = $59.95 - $14.99 - $5.99 = $38.97
2. Markup Amount = $38.97 × 0.35 = $13.64
3. Regular Unit Selling Price = $38.97 + $13.64 = $52.61
4. Profit = $52.61 - $38.97 - ($38.97 × 0.18) = $52.61 - $38.97 - $7.01 = $6.63

Now, if MEC sells the backpack at the MSRP (Manufacturer's Suggested Retail Price), the profit will be different. The MSRP is typically higher than the regular unit selling price, so the profit will be higher as well. Let's say the MSRP is $65. The profit would be:

Profit = MSRP - Cost - Expenses = $65 - $38.97 - ($38.97 × 0.18) = $65 - $38.97 - $7.01 = $19.02

So, if MEC sells the backpack at the MSRP, the profit will be $19.02, which is higher than the profit of $6.63 when selling at the regular unit selling price.

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The solution to the compound inequality 4v + 3 <= 23 and 3v + 4 < 1 is v in the interval (-1, 5].

To solve the compound inequality, we need to solve each inequality separately and then find the intersection of the two solutions.

First, let's solve the inequality 4v+3<=23:
4v+3<=23
4v<=20
v<=5

Next, let's solve the inequality 3v+4<1:
3v+4<1
3v<-3
v<-1

Now, we need to find the intersection of the two solutions, which is the solution that satisfies both inequalities. The intersection of v<=5 and v<-1 is the interval (-1, 5].

So, the solution to the compound inequality is v in the interval (-1, 5]. In interval notation, this is written as (-1, 5].

Therefore, the solution to the compound inequality 4v+3<=23 and 3v+4<1 is v in the interval (-1, 5].

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The quotient is -6x^2-2x-2 and the remainder is -4.

To find the quotient and remainder for the given expression, we can use long division.

First, we divide the first term of the dividend (-6x^3) by the first term of the divisor (x) to get -6x^2. This is the first term of the quotient.

Next, we multiply the first term of the quotient (-6x^2) by the divisor (x-1) to get -6x^3+6x^2. We subtract this from the dividend to get -2x^2-2.

We repeat this process with the new dividend (-2x^2-2) and the same divisor (x-1). We divide the first term of the new dividend (-2x^2) by the first term of the divisor (x) to get -2x. This is the second term of the quotient.

We multiply the second term of the quotient (-2x) by the divisor (x-1) to get -2x^2+2x. We subtract this from the new dividend to get -2x-2.

We repeat this process one more time with the new dividend (-2x-2) and the same divisor (x-1). We divide the first term of the new dividend (-2x) by the first term of the divisor (x) to get -2. This is the third term of the quotient.

We multiply the third term of the quotient (-2) by the divisor (x-1) to get -2x+2. We subtract this from the new dividend to get -4. This is the remainder.

So, the quotient is -6x^2-2x-2 and the remainder is -4.

We can check our work by verifying that

(Quotient)(Divisor) + Remainder = Dividend:

(-6x^2-2x-2)(x-1) + (-4) = -6x^3+6x^2-2x^2+2x+2x-2-4 = -6x^3+4x^2-2

Therefore, our answer is correct.

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We are given the expression √4x^2+100 and the substitution x/5=tan(θ). Our goal is to use the substitution to write the expression as a trigonometric expression and simplify as much as possible.

First, let's substitute x/5=tan(θ) into the expression:

√4(tan(θ)*5)^2+100

Next, let's simplify the expression:

√4(25tan^2(θ))+100

√100tan^2(θ)+100

Now, let's factor out 100 from the expression:

√100(tan^2(θ)+1)

10√tan^2(θ)+1

Finally, let's use the trigonometric identity 1+tan^2(θ)=sec^2(θ) to simplify the expression further:

10√sec^2(θ)

10sec(θ)

Therefore, the expression √4x^2+100 can be written as 10sec(θ) using the substitution x/5=tan(θ).

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The solution to the compound inequality 3u-2<=-14 or 4u+4<28 is u<=-4 or u<6.

A compound inequality is an equation that combines two inequalities with the word "and" or "or".

To solve a compound inequality, we need to solve each inequality separately and then combine the solutions.

For the compound inequality 3u-2<=-14 or 4u+4<28, we will solve each inequality separately.

First, we will solve 3u-2<=-14: 3u-2<=-14 3u<=-14+2 3u<=-12 u<=-4

Next, we will solve 4u+4<28:

4u+4<28 4u<28-4 4u<24 u<6

Now, we will combine the solutions.

Since the word "or" is used in the compound inequality, the solution is the union of the two solutions. This means that the solution is any value of u that satisfies either inequality.

The solution is u<=-4 or u<6. This can also be written in interval notation as (-∞,-4] U (-∞,6).

So, the solution to the compound inequality 3u-2<=-14 or 4u+4<28 is u<=-4 or u<6.

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In a triangle EAC, F is the centroid and two medians, then the required expressions are 10x² + 2y , 5x² +y respectively.

The centroid is the centre point of the object. It is a point at which three medians of a triangle meet. Properties :

We have a triangle AEC, with centroid point F. Here, two medians of triangle AEC. Here, AD = 15x² + 3y, we have to determine the expression for bigger and smaller parts of median. As we know, centroid point F, divides median into ratio, 2: 1, i.e., bigger divided part/smaller divided part = 2/1

First expression for bigger divided part of median = (2/3) (15x² + 3y)

= 10x² + 2y

second expression for smaller divided part of median = (1/3) ( 15x² + 3y)

= 5x² + y

Hence, required expression are 10x² + 2y and 5x² + y.

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There does not exist a group homomorphism φ : D2n → G′ such that ker(φ) = {1, s}.

(a) To show that NG(H) = G, we need to show that every element of G normalizes H. Let g ∈ G, and let h ∈ H. Since H = ker(φ), we know that φ(h) = 1. Now, we need to show that ghg⁻¹ ∈ H. Using the properties of a homomorphism, we can write:

φ(ghg⁻¹) = φ(g)φ(h)φ(g⁻¹) = φ(g)1φ(g⁻¹) = φ(g)φ(g⁻¹) = φ(gg⁻¹) = φ(1) = 1

Therefore, ghg⁻¹ ∈ H, and so g normalizes H. Since this is true for any g ∈ G, we can conclude that NG(H) = G.

(b) Suppose there exists a group homomorphism φ : D2n → G′ such that ker(φ) = {1, s}. Since s ∈ ker(φ), we know that φ(s) = 1. However, we also know that rs = sr⁻¹, and so φ(rs) = φ(sr⁻¹). Using the properties of a homomorphism, we can write:

φ(r)φ(s) = φ(s)φ(r⁻¹) = φ(s)φ(r)⁻¹

Since φ(s) = 1, this simplifies to:

φ(r) = φ(r)⁻¹

But this means that φ(r) is its own inverse, and so φ(r)² = 1. However, we also know that rn = 1, and so φ(rn) = 1. Using the properties of a homomorphism, we can write:

φ(rn) = φ(r)ⁿ = (φ(r)²)ⁿ/2 = 1ⁿ/2 = 1

But this means that n/2 must be an integer, which contradicts the fact that n > 2. Therefore, there does not exist a group homomorphism φ : D2n → G′ such that ker(φ) = {1, s}.

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Answer: 134 tickets.

Step-by-step explanation:

Since we have 14 packs of 9 tickets, we can say it is 14 groups of 9. Which means we multiply. So 9 times 14 equals 126. But Ivan found 8 more tickets on the groud which means we add. so 126 plus 8 equals 134. The answer is 134 tickets.

Answer:

Step-by-step explanation:

multiply # of packs by # of tickets in each pack then add 8

14 x 9 = 126 + 8 = 134

Therefore, the jar can hold 75.36 cubic inches of peanut butter.

The answer is B) 75.36 in3.

An inch is a unit of measurement that is commonly used in the United States, United Kingdom, and other countries that follow the Imperial system of measurement. It is defined as 1/12th of a foot or 2.54 centimeters. In other words, there are 12 inches in a foot. The inch is often used to measure the length or width of small objects or to express the size of computer screens, TVs, and other electronic displays.

Given by the question.

The volume of a cylinder can be calculated using the formula: V = πr^2h, where r is the radius of the base of the cylinder and h is its height.

In this case, the jar has a diameter of 4 inches, which means the radius is 2 inches (diameter = 2 × radius). The height is given as 6 inches. So, we can calculate the volume of peanut butter that the jar can hold as follows:

V = π[tex]r^{2}[/tex]h

V = 3.14 × [tex]2^{2}[/tex] × 6

V = 3.14 × 4 × 6

V = 75.36 cubic inches

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The length of Diagonal is 14.73 unit.

A three-dimensional solid object called a prism has two identical ends. It consists of equal cross-sections, flat faces, and identical bases. Without bases, the prism's faces are parallelograms or rectangles.

Given:

l = 9, w= 10 and h= 6

The Formula for Diagonal length of Prism is:

d =√l² + w² + h²

Here, d = length of the diagonal, l = length of the rectangular base of the prism, w = width of the rectangular base of the prism, and h = height of the prism.

Substitute the value in the equation,

d =√9² + 10² + 6²

d =√81+ 100 + 36

d = √217

d =  14.73 units

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The set of all first components of the ordered pairs of a function are called the Independent Variable.

In a function, the first component of the ordered pairs is known as the independent variable, which is the input value of the function. The second component of the ordered pairs is known as the dependent variable, which is the output value of the function. The set of all first components is also called the domain of the function, while the set of all second components is called the range of the function.

Therefore, the correct term to complete the statement is the Independent Variable.

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The total amount of merchandise that stores A and B sold is 21x²+5x+8

An equation is a mathematical statement with an 'equal to' symbol between two expressions that have equal values.

For example, 3x + 5 = 15.

Given that, are two stores selling merchandise given by equation,

A = 13x²+8x-3 and B = 8x²-3x+11, we need to find the total amount of merchandise that stores A and B sold.

We add both the equations to find the same,

Total merchandise sold = 13x²+8x-3 + 8x²-3x+11

= 21x²+5x+8

Hence, the total amount of merchandise that stores A and B sold is 21x²+5x+8

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