HELP PLEASE I WILL MARK BRAINLIEST

The car will continue at half speed and slow down due to friction after the brakes are released.

The given situation is that the car's motor is stopped and brakes are applied until the car reaches its half speed and the brakes are released. So after the brakes are released, the car will not gain any speed, since there is no force applied. Then it will gradually slow down due to friction.

According to the law of inertia ( i.e., Newton's first law of motion ), an object will tend to stay at rest or motion until an external force is applied. So based on this law, the car will continue at the speed the brakes were released and eventually slow down.

Therefore, the car will continue at half speed and slow down due to friction after the brakes are released.

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density of object is 6.7g/cm³  and volume is 30cm³.

First, air has a low density, so the mass in air is very close to the true mass (mass in a vacuum). Let's say the true mass is 200g.

Then we can use the following formula to find the volume:

AM=TM-V•D where AM is the apparent mass (in water) and TM is the true mass (mass in vacuum which approximates mass in air). , V is the volume of water displaced by the object (which is also the volume of the object) and D is the density of the water, i.e.

170g=200g-V*(1,000g/cm3)

V=30cm³

Therefore The density of is approximately 200g÷30cm³=6.7g/cm³

If you want an exact answer, you can find the density of air under laboratory conditions. For example,

1.20g/L or 0.00120g/cm³. Then, using the above equations, we can set up a system of two equations with two unknowns.

200g=TM-V*(0.00120 g/cm³)

170g=TM-V*(1.000 g/cm³)

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Answer:

c.) 10 to 15 minutes

Explanation:

yw :)

Answer:

c.) 10 to 15 minutes

Explanation:

Answer:

no

gravitational force between them is far smaller than the frictional force between the guy and the bench

velocity of the train is same so acceleration of the train is zero.

Acceleration of an object is known as change in velocity of the object. For a given interval of time.

Distance travelled by the train in first second is, d₁ = 6m

Distance travelled by the train in the 2nd second is, d₂ = 6m

Distance traveled by the train in 3rd second, d₃ = 6m

Formula for the velocity of the train.

v= d/t

where v is velocity

d is distance travelled

t is time taken

For first second velocity is

v₁ = d₁/t₁

v1 = 6/1s = 6m/s

for 2nd second velocity is

v₂= d₂/t₂

v₂ = 6/1 = 6m/s

for 3rd second velocity is

v₃ = d₃/t₃

v₃ = 6/1 = 6m/s

here we saw that the speed of train remains constant for each interval of time. So change of velocity is zero.

velocity of the train is same so acceleration of the train is zero.

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Answer:

The second drop is 3.75 m above the ground

Explanation:

Free Fall Motion

A free-falling object falls under the sole influence of gravity without air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2[/tex].

The distance traveled by a dropped object is:

[tex]\displaystyle y=\frac{gt^2}{2}[/tex]

If we know the height h from which the object was dropped, we can find the time it takes fo hit the ground:

[tex]\displaystyle t=\sqrt{\frac{2y}{g}}[/tex]

When the first drop touches the ground there are two more drops in the air: the second drop still traveling, and the third drop just released from the tap.

The total time taken for the first drop to reach the ground is:

[tex]\displaystyle t_1=\sqrt{\frac{2*5}{g}}[/tex]

[tex]t_1 = 1.01\ s[/tex]

Half of this time has taken the second drop to fall:

[tex]t_2 = 1.01\ s/2=0.505\ s[/tex]

It has fallen a distance of:

[tex]\displaystyle y_2=\frac{9.8(0.505)^2}{2}[/tex]

[tex]y_2 = 1.25\ m[/tex]

Thus its height is:

h = 5 - 1.25 = 3.75

The second drop is 3.75 m above the ground

The horizontal distance of the penny from the base of the table is v(2y/g)^1/2.

The distance the coin lands from the base of the table is 1.0 m

The time of motion of the penny is calculated as follows;

y = vt + ¹/₂gt²

where;

y = ¹/₂gt²

2y = gt²

t² = 2y/g

t = √(2y/g)

The horizontal distance of the penny is calculated as;

X = Vₓt -----(1)

where;

Substitute the value of "t" into equation (1)

X = v(√(2y/g)),

X = v(2y/g)^1/2, shown

Use the formula above to determine the distance the coin lands from the base of the table.

X = v(√(2y/g)),

X = 3.5[√(2x0.4/9.8)]

X = 3.5(0.2857)

X = 1.0 m, shown

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Answer: The acceleration is roughly 9.3 m/s^2

The acceleration is positive.

=====================================================

Work Shown:

Using Newton's Second Law, we get,

F = m*a

52 = 5.6a

5.6a = 52

a = 52/5.6

a = 9.28571428571429 which is approximate

a = 9.3

I rounded to 2 significant figures because both 52 and 5.6 are to 2 sig figs.

The acceleration is positive because the student applied an upward force.

The units for the acceleration are in meters per second squared, abbreviated as m/s^2.

An acceleration of 9.3 m/s^2 means that after every second, the velocity has increased by 9.3 m/s.

Answer:

T = 10 s

Explanation:

First, we need to find the frequency of the object as follows:

[tex]Frequency = f = \frac{Speed\ in\ rpm}{60}[/tex]

where,

Speed = Angular Speed = 6 rpm

Therefore,

[tex]f = \frac{6\ rpm}{60}\\\\f = 0.1\ Hz[/tex]

Now, for time period (T):

[tex]Time\ Period = T = \frac{1}{f}\\\\T = \frac{1}{0.1\ Hz}\\\\[/tex]

T = 10 s

Answer:

2700

Explanation:

because calculate the minute1=60×45=2700

Answer:

[tex]v \approx 30.67\,\,\frac{m}{s}[/tex]

Explanation:

We use the kinematic formula for constantly accelerated motion given below:

[tex]v^2=v_0^2+2\,a\Delta x\\v^2=0+2\,g\,(48)\\v^2=940.8\\v \approx 30.67\,\,\frac{m}{s}[/tex]

1 x 10⁻¹² C are stored in the system.

The power required to move a charge in opposition to an electric field is known as electric potential energy. A charge must be moved through a stronger electric field with more energy, but it also must be moved through a weaker electric field with more energy.

Electric potential at a place in an electric field is the amount of work done to move the unit positive charge from infinity to that point, and electric potential energy is fundamentally different.

Given are the following values: Stored charge, Q= 1x 10⁻¹⁰ C Voltage, V=100 v

We are aware that the formula for a system's capacitance is C=Q/V

= 1 x 10⁻¹⁰ / 100.

=1 x 10⁻¹² C

As a result, it is the necessary remedy.

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Answer:

Electromagnetic waves carry energy.

Explanation:

The waves consist of transverse vibrations in electrical and magnetic fields, not vibrating particles.

Answer:

The value is  [tex]f = 0.36 \ m[/tex]

Explanation:

From the question we are told that

  The radius of curvature is  [tex]R = 0.72 \ m[/tex]

Generally the radius of curvature is mathematically represented as

        [tex]R = 2f[/tex]

Here [tex]f[/tex] is the focal length hence

       [tex]f = \frac{R}{2}[/tex]

=>     [tex]f = \frac{0.72}{2}[/tex]

=>     [tex]f = 0.36 \ m[/tex]

Answer:

a) [tex]F_{x} = 58.2 N[/tex]

[tex] F_{y} = 48.9 N [/tex]

b) a = 1.5 m/s²

Explanation:

a) The horizontal and vertical components of Emily's force can be found knowing the angle and the exerted force.

Since the handle is inclined at 40.0° below the horizontal we have:

[tex] F_{x} = |F|*cos(\theta) = 76.0 N*cos(40) = 58.2 N [/tex]

[tex] F_{y} = |F|*sin(\theta) = 76.0 N*sin(40) = 48.9 N [/tex]

b) The acceleration of the car can be calculated as follows:

[tex] F_{x} = ma [/tex]        

We used the horizontal component of the force because the cart is moving in that direction.

[tex] a = \frac{F_{x}}{m} = \frac{58.2 N}{38.8 kg} = 1.5 m/s^{2} [/tex]

Hence, the acceleration of the car is 1.5 m/s².    

I hope it helps you!

Given that,

Mass of a girl, m  = 50 kg

Mass of the boat, m' = 300 kg

Speed of girl, v = 3 m/s

To find,

The velocity with which the boat begin to move backwards.

Solution,

Let the velocity be v'. Using the conservation of momentum to find it. It is given by :

[tex]mv=m'v'\\\\v'=\dfrac{mv}{m'}\\\\v'=\dfrac{50\times 3}{300}\\\\v'=0.5\ m/s[/tex]

So, the velocity moves backward with a speed of 0.5 m/s.

Answer:

Explanation:

4 is right

The amount of work required to slide the 3 Kg box 6.90 m along (up) the frictionless incline plane is 183.85 J

Work is defined as the product of force and distance moved in the direction of the force. mathematically it is expressed as:

Work done (Wd) = force (F) × distance (d)

Wd = fd

Where height is involved, the workdone is given as as:

Work done (Wd) = mass (m) × acceleration due to graity (g) × height (h)

Wd = mgh

Considering angle projection,

Wd = mghCosθ

Thus, we can detertmine the work done as follow:

Wd = mghCosθ

Wd = 3 × 9.8 × 6.9 × Cos 25

Wd = 183.85 J

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The average velocity during the time interval is (V)=4m/s.

Velocity is a expression of the displacement that an object or particle undergoes with respect to time. Velocity is a vector quantity. The average velocity means total distance divided by total time.

To calculate the average velocity we are using the formula,

Vₙ = (v₁+v₂)/2

Here we are known,

v₁= The position of a particle moving along the x-axis with the average velocity during the time interval from t = 1.0 s

v₂= The position of a particle moving along the same x-axis with the average velocity during the time interval from t = 4.0 s

We have to calculate, the average velocity during the time interval= Vₙ

To calculate the velocities we are using the formula,

v = dx/dt

Here, x=11+14t-2t²

v=dx/dt=14-4t

At, t=1.0s, v₁=14-4*1=10m/s

At, t=4.0s, v₂= 14-4*4=-2m/s

Now, the average velocity is,

Vₙ =(v₁+v₂)/2

Or, Vₙ =(10-2)/2

Or, Vₙ =4m/s

Thus from the above calculation we can conclude that, the average velocity during the time interval from t = 1.0 s to t=4.0 s is (V)=4m/s.

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The position of a particle moving along the x-axis is given by x = (11 + 14t – 2.0t²), where t is in seconds and x is in meters. What is the average velocity during the time interval from t = 1.0 s to t = 4.0 s

Answer:

a = 0.16 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}=v_{o}+a*t\\[/tex]

where:

Vf = final velocity = 3.2 [m/s]

Vo = initial velocity = 1.1 [m/s]

t = time = 13 [s]

a = acceleration [m/s²]

Now replacing:

[tex]3.2=1.1+a*13\\2.1=13*a\\a=0.16[m/s^{2} ][/tex]

A crow flies forward and backward. Its motion is shown on the following graph of horizontal position x vs. time t.

What is the instantaneous velocity of the crow at t = 9 s?

Answer: -0.50 m/s

A crow flies forward and backward. Its motion is shown in the following graph and the instantaneous velocity of the crow at t = 9 s is -0.5 m/s.

From the figure, it shows that from t = 8sec to t = 12 sec the displacement is decreasing, so velocity will be the slope of the straight line.

The velocity is given by:

velocity = -Δx ÷ Δt

velocity = (-2) ÷ (12-8)

velocity = -2 ÷ 4

velocity = -0.5 m/s

Therefore, A crow flies forward and backward. Its motion is shown in the following graph and the instantaneous velocity of the crow at t = 9 s is -0.5 m/s.

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Answer:

i believe that they are or there's something out there

Explanation:

:)

Answer:

hiiiiiiiiiiiii baby.........

Answer: c. 1.89 x 10^14 J

Explanation:

By Einstein's equation, we know that:

E = m*c^2

Where m is the mass-consumed in this case:

m = 2.10g

And we must rewrite this in Kg, knowing that:

1kg = 1000g

Then:

m = 2.10g = (2.10/1000) kg = 0.0021 kg

And c is the speed of light:

c = 3*10^8 m/s.

Then the energy will be:

E = 0.0021 kg*(3*10^8 m/s)^2 = 1.89*10^14 Joules.

The correct option is:

c. 1.89 x 10^14J

Answer:

When these waves reach our ears, they make our eardrums vibrate, and we hear the sound of the bell ringing.

Explanation:

Answer: When a bell is pounded, the metal vibrates. The vibrations travel through the air as sound waves. When these waves reach our ears, they make our eardrums vibrate.

Explanation:

We hear the sound of the bell ringing. Sound always needs to travel through some kind of medium, such as air, water, or metal.

Sorry if this is not the answer you are looking for

Answer:The direction a wave propagates is perpendicular to the direction it oscillates for transverse waves. A wave does not move mass in the direction of propagation; it transfers energy.

Explanation:

The magnitude of the velocity of the truck relative to the car is 183.9 km/h

The direction of the velocity of the truck relative to the car is 67 ⁰ north of west.

The velocity of the truck relative to the car is the resultant velocity of the vehicles.

The resultant velocity of the car is calculated as follows;

Vyi = 119 km/h

Vy2 = 87.7 km/h x sin(35) = 50.3 km/h

Vy(total) = 119 km/h + 50.3 km/h = 169.3 km/h

Vx = -87.7 x cos(35) = -71.84 km

v = √Vy² + Vx²

v = √[(169.3²) + (-71.84)²]

v = 183.9 km/h

θ = arc tan(Vy/Vx)

θ = arc tan(169.3 / -71.84)

θ = -67 ⁰

θ = 67 ⁰ north of west.

Thus, the magnitude of the velocity of the truck relative to the car is 183.9 km/h and the direction of the velocity of the truck relative to the car is 67 ⁰ north of west.

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Answer:

resultant increases by factor of 1.12

Explanation:

EDITED :

Assume force = 1  for simplicity and one vector is on the x axis

at 55 degrees

   horizontal components = 1 + cos 55 = 1.574

   vertical component = sin 55 = .8192

         resultant = 1.77

at 15 degrees

    horizontal components = 1 + cos 15 = 1.966

    vertical component  = sin 15 = .2588

         resultant = 1.98

resultant increases by  1.98 / 1.77 = 1.12 original

The statements that are true are

A satellite is a moon, planet of machine that orbits a planet or a star.

From the diagram, we see that X is a planet, Y is a planet and also a moon to X and z is amoon to Y and Z

Since X does not orbit Y but Y orbits X.

So, the statement is false.

Since Y does not orbit Z but Z orbits Y.

So, the statement is false.

Since X does not orbit Y but Y orbits X, and Z orbits Y.

Since only Z orbits Y, then the statement is false.

Since Z orbits Y and Y orbits X and invariably, Z also orbits X. So, Y and Z orbit X.

So, the statement is true

Since Y orbits X but Z orbits Y, Y is a satellite for X but not Z, since Z orbits Y and is a satellite for Y.

Since Y is only a satellite for X and not Z,

So, the statement is false.

Since Y orbits X, so Y is a satellite for X.

So, the statement is true.

Since Z orbits Y, so Z is a satellite for Y.

So, the statement is true

So, the statements that are true are

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Answer:

The last one

Explanation:

on the exam

Among the following the derived demands are options 1 and 3 only. Because in each case, the demand for one thing is originated  by the demand for another.

The phrase derived demand in economics refers to the demand for a factor of production or intermediate good that results from the demand for another intermediate or final good. In essence, consumer demand for the firm's product determines how much a firm will need.

Additionally, if activity in one area rises, any sector that contributed to the success of the first sector may also experience growth. Here, the school is hiring more teachers because enrollment is increased. Thus, enrolling more teachers satisfies the demand by greater enrollments.

Similarly by recruiting more construction workers the increased demand for new house by people can be solved. However, the second case for filling the attendance is a necessary and not a derived demand.

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Given that,

Mass of the object, m = 1 kg

It moves in a circle of radius 0.5 m with a speed of 5 m/s

To find,

The direction of the acceleration.

Solution,

Whenever an object moves in a circular path, the only force that acts on its is centripetal force which is given by the formula as follows :

[tex]F=\dfrac{mv^2}{r}[/tex]

The centripetal acceleration acts in the direction of force. It acts along the radius of the circular path. In this figure, the direction of the acceleration is shown at point d.

Answer:

D!

Explanation:

took the test