HELP MEEEEEE 25 POINTS

Step-by-step explanation:

Rearrange the terms by writing

3y = -2x + 6 ---> y = (-2/3)x + 2

The slope of this equation is m = -2/3

On solving the provided question, we can say that  on matching the expressions are 100X 14 = 1400 and 14(10) = 140 and 361 . 100 = 36100 and 100(361) = 36100

In mathematics, it is possible to multiply, divide, add, or remove. The construction of an expression is as follows: Expression, number, and mathematical operator Numbers, variables, and functions are the building blocks of a mathematical expression (such as addition, subtraction, multiplication or division etc.) Expressions and phrases can be contrasted. Any mathematical statement with variables, numbers, and an arithmetic operation between them is called an expression or an algebraic expression. For instance, the expression 4m + 5 has the terms 4m and 5 as well as the variable m of the supplied expression, all of which are separated by the arithmetic sign +.

so, on matching the expressions are

100X 14 = 1400

14(10) = 140

361 . 100 = 36100

100(361) = 36100

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Answer: P (T< 685) ≈ 0.31

Step-by-step explanation:

Answer:

[tex]x=(x-3)(x+6)[/tex]

Answer:

Subtract 7.4 – 3.6

Answer:

Subtract 7.4-3.6

Step-by-step explanation:

Pemdas

Answer:

he is not correct

correct answer is -5.61

Step-by-step explanation:

he added them together but did not account for the negative in the second term

Answer:

they are not correct because 7.15 + (-12.76) equals −5.61 not 19.91

Step-by-step explanation:

hope this helps

Answer: 0.023 is twenty-three thousandths written in standard form!

Answer: 0.023

Step-by-step explanation:

Answer:

it is an infinite discontinuity.

Step-by-step explanation:

Removable type of discontinuity does the function have at x = -4. Option  4 is correct.

If the limit of the function at the place of discontinuity exists and the value of the function exists, but they are not equal to each other, the discontinuity is removable.

We may eliminate the discontinuity by making the function's value equal to the function's limiting value at that time.

The given function is;

G(x)=x²+ 7x – (18/x)²+2x-8

G(-4)=(-4)²+7×(-4)- (18/-4)²+2(-4)-8

G(-4)=16-28-20.25-8-8

G(-4)=16-64.25

G(-4)=- -48.25

The given data on putting the value gives the negative values.

Hence, the removable type of discontinuity does the function have at x = -4

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Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point  A(3, 2) with respect to the line 2x + y - 12 = 0.​

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

[tex]C( \dfrac{x+3}{2}, \dfrac{y+2}{2})[/tex]

Also, product of slope will be -1 .( Since, they are parallel )

[tex]\dfrac{y-2}{x-3} \times -2 = -1\\\\2y - 4 = x - 3\\\\2y - x = 1[/tex]

x = 2y - 1

So, [tex]C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})[/tex]

Also, C satisfy given line :

[tex]2\times ( \dfrac{2y + 2}{2}) + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}[/tex]

Also,

[tex]x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}[/tex]

Therefore, the symmetric points is[tex]A'(\dfrac{31}{5}, \dfrac{18}{5})[/tex] .

Answer:

At simple interest it will be 939+939×6×0.08=$1389.72.

Step-by-step explanation:

The bridge opening times when there are 60 minutes in an hour will be 45/60 and 10/60.

From the information, a boat will pass the Colby drawbridge and then the Wave drawbridge and then the Wave drawbridge.

From the table, Colby is on the 3/4 hour. This will be:

= 3/4 × 60

= 45

Also, Wave Bridge will be:

= 1/6 × 60

= 10

Therefore, it's 45/60 and 10/60 because we know that the common denominator is 60 then 3/4 of an hour is 45mins then 1/6 of an hour is 10.

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Complete question

On the Dell River, a boat will pass the Colby drawbridge and then the Wave drawbridge and then the Wave drawbridge. Rename each of the two drawbridge opening times. There are 60 minutes in an hour, so use 60 as a common denominator. Then, rename each opening time using another common denominator

Bridge name:

1. Asher Cross

2. Colby

3. Rainbow

4. Red Bank

5. Wave

Time of Opening:

1. On the hour

2. On the 3/4 hour

3. On the 2/3 hour

4. On the 1/4 hour

5. On the 1/6 hour

The value of (2/3 - 5/6) / 3/4 is -2/9.

A fraction is written in the form of a numerator and a denominator where the denominator is greater that the numerator.

Example: 1/2, 1/3 is a fraction.

We have,

(2/3 - 5/6) / 3/4

2/3 - 5/6

= (4 - 5)/6

= -1/6

Now,

(-1/6 )/(3/4)

= -1/6 x 4/3

= -4/18

= -2/9

Thus,

The value is -2/9.

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Answer:

A

Step-by-step explanation:

the sum of the two angles is 90 degrees

x + 52 = 90

x = 38 degrees

Answer

1/3

Step-by-step explanation:

Answer:

2.98

Step-by-step explanation:

Answer:

[tex] m = \boxed{1} \: \: c = \boxed{4}[/tex]

Step-by-step explanation:

[tex]y = x + 4 \\ equating \: it \: with \\ y = mx + c \\ m = \boxed{1} \: \: c = \boxed{4}[/tex]

Answer lol faith

Step-by-step explanation:

Answer: The equation y = 53+2x relates the variables x and y, where x represents the number of days the crew has worked and y represents the total length of the road.

The change per day in the road's length is given by the coefficient of x in the equation, which is 2. Thus, the change per day in the road's length is 2 miles.

The road's length when the crew started working is given by the constant term in the equation, which is 53. Thus, the road's length when the crew started working was 53 miles.

Step-by-step explanation:

Answer:

The [tex]\sqrt{25}[/tex]= 5

Step-by-step explanation:

Answer:

[tex]\theta=102.85^{\circ}[/tex]

Step-by-step explanation:

Given that,

The radius of circle, r = 7 cm

The area of sector, A = 44cm²

We need to find the angle of the sector. The formula for the area of sector is given by :

[tex]A=\dfrac{\theta}{360}\pi r^2[/tex]

Solve for [tex]\theta[/tex].

[tex]\theta=\dfrac{360A}{\pi r^2}\\\\\theta=\dfrac{360\times 44}{\dfrac{22}{7}\times 7^2}\\\\\theta=102.85^{\circ}[/tex]

So, the angle of the sector is equal to [tex]102.85^{\circ}[/tex].

Answer:

145

Step-by-step explanation:

90+55=145

Answer:

The reflection over the x-axis

Answer:

a

Step-by-step explanation:

Answer:

They can make 2592 different burritos.

Step-by-step explanation:

In this question:

We multiply the number of options for each condiment.

1 choice of tortilla from a set of 3.

1 choice of meat from a set of 4.

1 choice of rice from a set of 2

1 choice of beans from a set of 3

1 choice of cheese from a set of 3

1 choice of salsa from a set of 4.

1 extra topping from a set of 3.

So

3*4*2*3*3*4*3 = 2592

They can make 2592 different burritos.

Hi there!

[tex]\large\boxed{x = 26}[/tex]

x + 17 = 43

Isolate for x by subtracting 17 from both sides:

x + 17 - 17 = 43 - 17

x = 26

Answer:

x=26

Step-by-step explanation:

x+17=43

-17. -17

x= 26

[tex]\boxed{\huge\textsf{\boxed{\frak{Hey \ there!}}}}[/tex]

[tex]\bullet\large\textsf{ To find out the range you have to find the difference between the}\\\large\textsf{maximum and the minimum.}[/tex]

[tex]\bullet \large\textsf{ Reminder: the word difference in mathematics simply means subtract.}\\\large\textsf{So, if your teacher/anyone asks you what does it mean in math, tell}\\\large\textsf{them it is another word for subtraction.}[/tex]

[tex]\bullet\large\textsf{ The formula is: \underline{maximum} - \underline{minimum} = \boxed{\bf range}}[/tex]

[tex]\bullet \large\text{ Whereas, the MAXIMUM IS the GREATER/LARGER NUMBER.}\\\large\text{\& MINIMUM IS the LESS/SMALLER NUMBER.}[/tex]

[tex]\boxed{\star}\large\textsf{ Okay now lets answer your question }\boxed{\star}[/tex]

[tex]\square\large\text{\underline{ MAXIMUM}: \boxed{\bf 21}}[/tex]

[tex]\square\large\text{\underline{ MINIMUM:} \boxed{\bf 15}}[/tex]

[tex]\huge\textsf{21 - 15 = \boxed{your \ range}}[/tex]

[tex]\large\text{SIMPLIFY ABOVE \& YOU HAVE YOUR ANSWER}[/tex]

[tex]\huge\textsf{21 - 15}[/tex]

[tex]\huge\textsf{= 6}[/tex]

[tex]\boxed{\boxed{\huge\textsf{Answer: range = \bf 6}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\boxed{\huge\text{\boxed{\frak{Amphitrite1040:)}}}}[/tex]