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D. Two or more of the same type or different types of atoms.

Answer:

The answer is D.

Explanation:

I know because I am currently doing this topic in Chemistry as well. I hope it was enough.

Explanation:

[tex]KOH→K {}^{ + } + OH {}^{ - } \\ [OH {}^{ - } ] = 3.4 \times {10}^{ - 3} \\ k _{w} = [OH {}^{ - } ] [H {}^{ + } ] \\ 1 \times {10}^{ - 14} = 3.4 \times {10}^{ - 3} \times [H {}^{ + } ] \\ [H {}^{ + } ] = 2.94 \times {10}^{ - 12} \: M[/tex]

Answer:

2.9 X 10^-12 M

Explanation:

Answer:

A

smooth muscle is responsible

Answer:

when De molecules are wide open

Explanation:

due to the molecules gas contains

Answer:

Option A. It has stayed the same.

Explanation:

To answer the question given above, we assumed:

Initial volume (V₁) = V

Initial temperature (T₁) = T

Initial pressure (P₁) = P

From the question given above, the following data were:

Final volume (V₂) = 2V

Final temperature (T₂) = 2T

Final pressure (P₂) =?

The final pressure of the gas can be obtained as follow:

P₁V₁/T₁ = P₂V₂/T₂

PV/T = P₂ × 2V / 2T

Cross multiply

P₂ × 2V × T = PV × 2T

Divide both side by 2V × T

P₂ = PV × 2T / 2V × T

P₂ = P

Thus, the final pressure is the same as the initial pressure.

Option A gives the correct answer to the question.

Explanation:

The other half of the equation involves the hydrogen ions (initially bonded to the chloride ion in the hydrochloric acid). The hydrogen ions gain the electrons lost by the zinc atom, and bond together to form hydrogen gas. Since the hydrogen ions gain electrons, it is a reduction reaction.

Answer:

Paraffin Wax

Explanation:

Paraffin wax is one of the most widely used waxes for candle making. A cheaper alternative, it is a derivable from petroleum, coal or oil. This wax is white and odorless and will keep a consistent appearance throughout your candle's life.

Answer:

I think its D. Sorry if I'm wrong

Explanation:

Answer:

he drank milk!!!

Explanation:

1. he told his dad to go get the milk

2. Steve's dad didn't come back until a year!

3. Steve's dad came back and gave him milk!

4. and boom, he grew!!

:)

All living organisms are capable of growing and producing offspring. All eukaryotic organisms including aquatic plants and algae grow through mitosis. Thus the correct option is 2.

The mitosis is defined as the step in the cell cycle where the newly formed DNA is separated and results in the formation of two new cells which have the same number and kind of chromosomes as the parent nucleus.

It is defined as a process of asexual reproduction observed in unicellular organisms. The cell division is regarded as the driving process of reproduction at the cellular level. Mitosis is required for the growth of the cells and for the replacement of worn-out cells.

Mitosis helps organisms to grow in size and repair damaged tissue. The process of mitosis generates new cells which are genetically identical to each other.

Thus the correct option is 2.

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Answer:

SiO2

Explanation:

Si + O2 → SiO2

Answer:

D

Explanation:

cause overall charge is +1 so will attract

Answer:

The sediments were transported and deposited by streams and rivers.

Explanation:

:)

Answer:

.. ..

:O = C - Cl:

.. | ..

:Cl:

..

The molecular formula of the unknown compound, given that it contains carbon, hydrogen, and oxygen is C₆H₁₂O₆

First, we'll begin by obtaining the mass of carbon, hydrogen and oxygen. Details below:

For Carbon

Mass of C = (12 / 44) × 1.649

Mass of C = 0.45 g

For Hydrogen

Mass of H = (2 / 18) × 0.675

Mass of H = 0.075 g

For Oxygen

Mass of O = (mass of compound) - (mass of C + mass of H)

Mass of O = 1.125 - (0.45 + 0.075)

Mass of O = 0.6 g

Next, we shall determine the empirical formula. details below:

Divide by their molar mass

C = 0.45 / 12 = 0.0375

H = 0.075 / 1 = 0.075

O = 0.6 / 16 = 0.0375

Divide by the smallest

C = 0.0375 / 0.0375 = 1

H = 0.075 / 0.0375 = 2

O = 0.0375 / 0.0375 = 1

Thus, the empirical formula of the compound is CH₂O

Finally, we shall determine the molecular formula. Details below:

Molecular formula = empirical × n = mass number

[CH₂O]n = 180

[12 + (2×1) + 16]n = 180

30n = 180

Divide both sides by 30

n = 180 / 30

n = 6

Molecular formula = [CH₂O]n

Molecular formula = [CH₂O]₆

Molecular formula = C₆H₁₂O₆

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Answer:

It's D the number of organisms an ecosystem can support.

Check if it's right first then if it is, happy to help

Answer:

D: The number of organisms an ecosystem can support

Explanation:

D is the correct answer.

The mass of copper nitrate produced in the reaction 3.65g of copper and 5.16g of nitric acid​ is 3.84g.

Nitric acid reacts with copper

4 HNO3(l) + Cu(s) ==> Cu(NO3)2(s and aq) + 2 NO2(g) + 2 H2O(l)

Deep blue colour characterises the copper nitrate salt that develops. Nitrogen dioxide is the gas that is created when strong nitric acid and copper interact. This maroon mist is nitrogen dioxide.

Copper :

=> mass copper nitrate

=> 3.65g Cu x 1mol of Cu/63.546 g Cu x 1 mol copper nitrate / 1 mol cu x 187.56 g/mol copper nitrate

=> 10.77g

HNO3 (Nitric acid):

=> Mass copper nitrate =3.65 g HNO3 X 1 mol HNO3/63.546 g HNO3 x 1mol of copper nitrate /4 mol HNO3 x 187.56 g/mol copper nitrate.

=> 3.84g.

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1. The reaction: 2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g) ΔG = -2,453.1 KJ is spontaneous

2. The reaction: 3H₂(g) + N₂(g) → 2NH₂(g) ΔG = -33.3 KJ is spontaneous

3. The reaction: CO₂(g) + 2H₂O(g) → CH₂(g) + 2O₂(g) ΔG = 800.7 KJ is nonspontaneous

The Gibbs free energy is a core factor in determining whether a reaction is spontaneous or nonspontaneous. Gibbs free energy is given by the following formula:

ΔG = ΔH – TΔS

Where

NOTE

With the above information, we can determine which of the reaction is spontaneous and also the one which is nonspontaneous as shown below:

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Answer:

The number of ATP molecules made per NADH and FADH2 oxidation differ by 1.

The amount of ATP generated per mole of glucose when the glycerol-3-phosphate shuttle would be 30 instead of 32.

Explanation:

The glycerol-3-phosphate shuttle can transport cytosolic NADH equivalents into the mitochondrial matrix. In this shuttle, the protons and electrons are donated to FAD, which is reduced to FADH2. These protons and electrons are subsequently donated to coenzyme Q in the electron transport chain. Given that the number of ATP molecules made per NADH and FADH2 oxidation differ by 1, the amount of ATP generated per mole of glucose when the glycerol-3-phosphate shuttle would be 30 instead of 32.

FADH2 generates 1.5 ATP per molecule unlike NADH which generates 2.5 ATP per molecule. This is because electron transfer via FADH2 is not coupled to proton pumping unlike electron transfer reactions involving NADH. Thus, two moles of NADH from the oxidation of 2 moles of glyceraldehyde-2-phosophate to two moles of 1,3-bisphosphoglycerate will yield 3 moles of ATP rather than 5 moles when shuttled through the glycerol-3-phosphate shuttle. The glycerol-3-phosphate shuttle of cytosolic NADH shuttling occurs mainly in the brain and skeletal muscles and does not involve membrane transporters.

According to the claim, Balloon A, which has more blue and less orange, exhibits accurate effusion at a relative effusion rate of 1.303. (orange is 1.303 times more effused than blue).Relative rate of effusion for the orange to blue spheres = 1.531.

The process of effusion is when a gas escapes from a container through a hole that is significantly smaller in diameter than the molecules' mean free path.

Gas molecules flow through a small opening in one container and into another by effusion. Graham's law allows rates of effusion to be compared at the same temperature. Diffusion is the random molecular motion-based movement of gas molecules through one or more other types of gas.

Rate of effusion of Orange / Rate of effusion of blue

= [Mblue / Morange]^1/2

Vrms = sqrt [(3RT/M)]

Vorange / Vblue = [ Mblue / Morange]^1/2

Rate of effusion of Orange / Rate of effusion of blue

= 565/ 369

= 1.531

Thus,  Balloon A, which has more blue and less orange, exhibits accurate effusion at a relative effusion rate of 1.303.

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Substance R changed phase because the weak attraction between molecules let them move faster.  Option C

We know that a change of phase has to do with the movement of a material from a given state of matter to the other. Net us note that when there is a change of state, we are going to notice that the force of attraction in the molecule would also change.

Since we know that the substance that we have are liquid at room temperature, we know that the supply of some energy may cause to be bale to change its phase.

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Answer:

12.5 L

Explanation:

Part 1 - Finding Number of moles

First thing we need to find out is number of moles of oxygen gas. We can achieve this using the formula: PV=nRT

Pressure (Pa) x Volume (cubic meters) = no. moles x gas constant (8.31 J/K*mol) x Temperature (K)

We can rearrange this formula to solve for no. moles:[tex]n=\frac{PV}{RT}[/tex] and plug in the values to solve.

1 atm = 1.01325 x 10^5 Pa, therefore 1.76atm = [tex]1.76*1.01325*10^{5} =178332Pa[/tex]

1 L = 1 x 10^-3 m^3, therefore 5L = [tex]5*1*10^{-3}=5*10^{-3}m^{3}[/tex]

Finally Kelvin = Celsius + 273.15, therefore 37.0C = [tex]37.0+273.15=310.15K[/tex]

Substituting this all back into the formula we get:

[tex]n=\frac{(178332)(5*10^{-3})}{(8.31)(310.15)}[/tex]

[tex]n=\frac{891.66}{2577.3465}[/tex]

[tex]n=0.346[/tex] moles (3.s.f)

Part 2 - Balancing Equation

The equation given is not balanced so we need to balance it to find the correct molar ratio. We can start by balancing the oxygens as there are less of them. We can see that there are 2 oxygen atoms on the left as denoted by 'O2' but only one on the right in 'H2O', therefore we can add a two in front of the H2O on the right side to balance the oxygen atoms:

[tex]H_{2(g)} +O_{2(g)} - > 2H_{2} O_{(g)}[/tex]

Now we have four hydrogens on the right side so we have a 2 in front of H2 on the left hand side to balance the hydrogens:

[tex]2H_{2(g)} +O_{2(g)} - > 2H_{2} O_{(g)}[/tex]

And voila! The equation is balanced and shows the correct molar ratio.

Part 3 - Calculating moles of water

As we can see from the molar ratio in the balanced equation, every mole of O2 will produce two moles of H2O- the ratio is 1:2. As we have an excess of hydrogen, we only need to worry about the amount of oxygen we have. Therefore to calculate the number of moles of water that can be made we simply need to multiple by the ratio:

[tex]0.346*2=0.692[/tex] moles of water

Part 4 - Converting to Liters

Finally, to convert our amount of moles into volume, we can use water's molecular mass to find the mass and then its density to find its volume. Water's molecular mass is 18.02gmol^-1 (2x1.01+16.00) and its density is 997kg/m^3.

m=nM (mass = no. moles x molecular mass): m=[tex]0.692*18.02=12.46984g[/tex]

rho = m/v (density = mass/volume): [tex]997=12.46984/v[/tex], therefore [tex]v=0.0125m^{3}[/tex]

Finally as mentioned above, 1 L = 1 x 10^-3 m^3, therefore the volume of water that can be made is 12.5 Liters.

Answer:

Dithiosulfatosilver

Explanation:

Answer:

The procedure for calculating the pH of a solution of a weak base is similar to that of the weak acid in the sample problem. However, the variable x will represent the concentration of the hydroxide ion. The pH is found by taking the negative logarithm to get the pOH, followed by subtracting from 14 to get the pH.

Explanation:

Natural vegetative propagation uses bulbils, aerial shoots, roots, underground stems, and subaerial stems. Utilizing unique vegetative components, artificial vegetative propagation is accomplished.

The production and growth of a new plant through asexual means or from a plant fragment is known as vegetative propagation. There is no gamete production or fertilization throughout the process of propagation.

In this procedure, tubers—modified roots—grow into new plants. In some plant species, adventitious buds even grow on the roots. If the correct circumstances are present, these buds develop into new plants or sprouts. Sweet potato and dahlia are two examples.

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Answer:

Number of mole in HCL = 2.56 x 10⁻³ mol HCL

Explanation:

Given:

Volume of HCL = 25.62 ml

Molarity of HCL = 0.1 M

Find;

Number of mole in HCL

Computation:

Volume of HCL = 25.62 ml

Volume of HCL (in liter) = 25.62 / 1000

Volume of HCL (in liter) = 0.02562 L

Number of mole = Molarity x volume in liter

Number of mole in HCL = Volume of HCL (in liter) x Molarity of HCL

Number of mole in HCL = 0.02562 x 0.1

Number of mole in HCL = 0.002562

Number of mole in HCL = 2.56 x 10⁻³ mol HCL