Help me please!!????

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Here we go ~

Let's use the given expression :

[tex]\qquad \tt \dashrightarrow \:a = v \dfrac{dv}{ds} [/tex]

[tex]\qquad \tt \dashrightarrow \:v \:dv= a \: {}{ds} [/tex]

Now, integrate both sides

[tex]\qquad \tt \dashrightarrow \: \int_{u}^v (v )\: dv= {\int _{0 }^{s} }{}^{} (a) \: {}{ds} [/tex]

[tex]\qquad \tt \dashrightarrow \: {\bigg[\dfrac{v {}^{2} }{2} \bigg]}_{u }^{v} \: = {\bigg[{a{s}^{} }{} \bigg]}_{0}^{s}[/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{1}{2} {\bigg[{v {}^{2} - {u}^{2} }{} \bigg]}_{}^{} \: = a{\bigg[{{s - 0}^{} }{} \bigg]}_{}^{}[/tex]

[tex]\qquad \tt \dashrightarrow \: v {}^{2} - {u}^{2} =2 as[/tex]

[tex]\qquad \tt \: \therefore v {}^{2} =u {}^{2} + 2as[/tex]

I hope you understood ~

Answer:

See below ~

Explanation:

Assume the bodies have the same acceleration

Divide the RHS of equation 2 by equation 1.

Therefore, the body of 6 kg accelerates more by 3 times

Answer:

1. A substance that can be separated into two or more substances only by a chemical change is a(n) _____.

solution

element

mixture

compound

2.

Which of the following materials is a substance?

air

gasoline

stainless steel

silver

3.

The first figure in a properly written chemical symbol always is _____.

boldfaced

capitalized

italicized

underlined

4.

Which of the following represents a compound?

H

H-3

H2O

O-16

5. What do chemical symbols and formulas represent, respectively?

elements and compounds

atoms and mixtures

compounds and mixtures

elements and ions

Explanation:

The rocket plane will travel 800 meters before coming to rest.

initial speed= 80 m/s

kinetic friction= 0.6

Net force action on the plane:

  F- kinetic friction = mass * acceleration

 mass*g - 0.6*mass*g=mass*acceleration     (take g=10m/s)

              acceleration=4m/s

calculation of stopping distance:-

   V²=U²-2as

   0+2as=U²

   S=U²/2a

   S=(80*80)2*4

   S=800 meter.

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The actions that would decrease the width of the central bright are decrease in the wavelength of the light and Increase in the width of the slit.

The wavelength of the light is determined using the following formulas;

[tex]\lambda = d(\frac{y}{D} )[/tex]

where;

y = (λD) / (d)

Thus, the actions that would decrease the width of the central bright are decrease in the wavelength of the light and Increase in the width of the slit.

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Given the value of possible error, the relative error of the measurement is 0.0095.

Given the data in the question;

Relative error is simply the ratio of the absolute or possible error of a measurement to the measurement its self.

Relative error is expressed as;

[tex]RE = \frac{e}{m}[/tex]

Where e is the absolute or possible error and m is the measurement being taken.

To determine the relative error, we substitute our given values into the expression above.

[tex]RE = \frac{0.04cm}{4.2cm} \\\\RE = 0.0095[/tex]%

Therefore, given the possible error, the relative error of the measurement is 0.0095.

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Answer:

Explanation:

wo possible outcomes have an identical probability, which is not possible. C. The sum of all possible moves is greater than 1, which is not possible. D. The probability of two possible outcomes sums to the probability of another outcome, which is not possible.

For a 208-volt, 4-wire, 3-phase wye power system feeds a school building, the average daily voltage is mathematically given as

x=206.23v

Generally, the equation for the mean  is mathematically given as

x=total sum/ number

Therefore

ts=05.25 volts, 203.75 volts, 208 volts, 204.35 volts, 206.7 volts, 207 volts, and 208.55 volts.

ts=1433.6

In conclusion

x=1433.6/7

x=206.23v

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Personality test is aimed at being able to decipher the nature of human personality. The opposite of judging in a personality test is prospecting.

The term personality test is aimed at being able to decipher the nature of human personality through a  Personalities Test.

In this personality test different personality types have their respective opposites. The opposite of judging in a personality test is prospecting.

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Answer:

prospecting

Explanation:

Answer:

a first-hand or contemporary account of an event or topic.

Explanation:

Hi there!

Recall that the amplitude of an oscillating system occurs at a point of maximum potential energy.

For a spring system, potential energy is given as:
[tex]U = \frac{1}{2}kx^2[/tex]

U = Potential Energy (J)

k = Spring constant (N/m)
x = amplitude (m)

We can rearrange the equation to solve for amplitude more easily.

[tex]U = \frac{1}{2}kx^2\\\\2U = kx^2\\\\x^2 = \frac{2U}{k}\\\\x = \sqrt{\frac{2U}{k}}[/tex]

If we double 'U':
[tex]x' = \sqrt{\frac{2(2U)}{k}} = \sqrt{2}*\sqrt{\frac{2U}{k}}\\\\x' = \sqrt{2} * x[/tex]

Thus, the new amplitude would be √2 times greater, so:
[tex]20 cm \cdot \sqrt{2} = \boxed{28.284 cm}[/tex]

Charge is neither generated nor destroyed, according to the rule of conservation of charge. Charge is merely transferred from one item to another in the form of electrons.

Answer:

D biomag

Explanation:

Mercury tends to build up in fish tissues and is present in larger quantities in large predatory fish than in small, herbivorous fish. This phenomenon is known as biomagnification. The correct option is D.

Biomagnification is the process by which certain substances, such as heavy metals like mercury, become increasingly concentrated in the tissues of organisms as they move up the food chain. In other words, the higher up an organism is in the food chain, the more likely it is to accumulate higher levels of these substances. This is because predators consume many smaller prey, each of which may have accumulated small amounts of the substance, leading to a build-up of the substance in the predator's tissues over time. This phenomenon has been well-documented in aquatic ecosystems, where mercury and other pollutants can accumulate in large predatory fish.

The other options are not correct:

Option A. Corrosivity refers to the ability of a substance to corrode or eat away at other materials. It is not relevant to the accumulation of mercury in fish tissues.

Option B. Non-persistence refers to the short-term or temporary nature of a substance or effect. It does not describe the long-term accumulation of mercury in fish tissues.

Option C. Bioremediation refers to the use of living organisms, such as bacteria or plants, to help clean up polluted environments. While this process may be used to reduce the levels of mercury in contaminated areas, it does not explain the process of biomagnification in fish.

Therefore, The correct option is D. biomagnification.

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Answer:

The Principle of Moments states that when a body is balanced, the total clockwise moment about a point equals the total anticlockwise moment about the same point.

Explaining with equation

Moment =force F x perpendicular distance from the pivot d. Moment = Fd.

Answer:

B vacuoles

Explanation:

Answer:

(b) from left to right (→)

Explanation:

Frictional Force

When the surface of one object comes into touch with the surface of another, friction is the force that resists motion. Friction reduces a machine’s mechanical advantage, or, to put it another way, friction reduces the output-to-input ratio. Frictional force refers to the force generated by two surfaces that contact and slide against each other.

Friction is caused due to the irregularities on the two surfaces in contact. So, when one object moved over the other, these irregularities on the surface get entangled, giving rise to friction.

The more the roughness, the more irregularities and more significant will be the friction.

Friction always acts in the opposite direction to the motion, hence the force of friction will be from left to right.

Answer:

3.085 [m].

Explanation:

1) The rule:

m₁*g*l₁=m₂*g*l₂, where m₁ and l₁ - the mass and distance for the small child, m₂ and l₂ - for the big child;

2) according to the condigion l₁+l₂=5, then

3) it is possible to make up the system:

[tex]\left \{ {{l_1+l_2=5} \atop {m_1*l_1=m_2*l_2}} \right. \ = > \ \left \{ {{l_1=5-l_2} \atop {18*(5-l_2)=29*l_2}} \right. \ = > \ \left \{ {{l_1=\frac{145}{47}} \atop {l_2=\frac{90}{47}}} \right.[/tex]

4) finally, l₁=145/47≈3.085 [m].

Answer:

you can use this differenation in density to seperate them by extracting the top layer of the water or where the oil is at and sperate it like that, but that is one methond compared to sing a varying amount. but it also depends on the type of oil as well because some oil is denser than water (i belive, do not quote me on this).

Explanation:

Answer:

A. Increases is the answer.

For a velocity selector for ions using perpendicular electric and magnetic fields is mathematically given as

B= 0.225 T

Generally, the equation for the magnetic field is mathematically given as

B = E/v

Therefore

B = 900/4000

B= 0.225 T

In conclusion. the magnetic field is

B= 0.225 T

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For a current loop with a radius 20 cm and current 2 A is in a uniform magnetic field of 0.5 T, largest potential energy difference is mathematically given as

du=0.2512J

Generally, the equation for the initial velocity  is mathematically given as

v0=-iAB

Therefore

-2*\pi(0.2)(0.5))

v0=-0.1256J

for  180

theta=0180=-iABcos180

V180=0.1256J

Therefore

du=v180-v0

0.1258-(-0.1256

du=0.2512J

In conclusion,  potential energy

du=0.2512J

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The current in the series circuit  across a 9.0 V potential difference is determined as 0.333 A.

The current in the series circuit is determined by applying ohms law as shown below;

V = IR

where;

R = 12 Ω  + 15 Ω  = 27 Ω

I = V/R

I = 9/27

I = 0.333 A

Thus, the current in the series circuit  across a 9.0 V potential difference is determined as 0.333 A.

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The velocity of 1kg and 2 kg mass when separation becomes 5m is 1.334 x 10⁻¹¹ m/s and 6.67 x 10⁻¹² m/s respectively.

The gravitational force between the masses is determined as follows;

[tex]F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67 \times 10^{-11}) (1)(2)}{10^2} \\\\F = 1.334 \times 10^{-12} \ N[/tex]

a = F/m

a₁ = (1.334 x 10⁻¹²) / (1)

a₁ = 1.334 x 10⁻¹² m/s²

a₂ = (1.334 x 10⁻¹²) / (2)

a₂ = 6.67 x 10⁻¹³ m/s²

v = u + 2ad

v₁ = u₁ + 2a₁d

v₁ = 0 + 2( 1.334 x 10⁻¹² )(5)

v₁ = 1.334 x 10⁻¹¹ m/s

v₂ = u₂ + 2a₂d

v₂ = (0) + 2(6.67 x 10⁻¹³)(5)

v₂ = 6.67 x 10⁻¹² m/s

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Answer:

0.826

1 S.f.

0.8 m/s

Explanation:

S (speed) = D (Distance) / T (Time)

According to Myers-Briggs, a charcteristic that is common to judging is  liking things settled and organized.

The term judging has to do with the quest for order and organization. It is one of the personality traits as outlined by Myers-Briggs.

The characteristic that is common among the people that exhibit the judging personality trait is liking things settled and organized.

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Answer:likes to have things settled and organized

Explanation:

bc I just took the test so ik it’s right

[tex]\bold{\huge{\underline{ Solution }}}[/tex]

Here,

Here, we have

We have to find the time of flight

We know that,

Time of flight

[tex]\sf{ = }{\sf{\dfrac{ 2uSin{\theta}}{g}}}[/tex]

Subsitute the required values,

[tex]\sf{ = }{\sf{\dfrac{ 2{\times}100{\times}Sin30{\degree}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 200{\times}{\frac{1}{2}}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 100}{9.8}}}[/tex]

[tex]\bold{ = 10.20 \: s }[/tex]

Hence, The time of flight is 10.20 sec .

Here, We have

We have to find the maximum height attained by the body

We know that,

Maximum height

[tex]\sf{ = }{\sf{\dfrac{ u^{2}Sin^{2}{\theta}}{2g}}}[/tex]

Subsitute the required values,

[tex]\sf{ = }{\sf{\dfrac{ (100)^{2}{\times}Sin^{2}30{\degree}}{2{\times} 9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 10000{\times}{\frac{1}{2}}{\times}{\frac{1}{2}}}{19.6}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 5000{\times}{\frac{1}{2}}}{19.6}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 2500}{19.6}}}[/tex]

[tex]\sf{ = 127.5 \: m}[/tex]

Hence, The maximum height attained by the body is 127.5 .

Here, we have

We have to find the horizontal range

We know that,

Horizontal range

[tex]\sf{ = }{\sf{\dfrac{ u^{2}Sin2{\theta}}{g}}}[/tex]

Subsitute the required values,

[tex]\sf{ = }{\sf{\dfrac{ (100)^{2}{\times}Sin2{\times}30{\degree}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 10000{\times}Sin{\times}60{\degree}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 10000{\times}{\frac{\sqrt{3}}{2}}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 5000{\times}\sqrt{3}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 5000{\times}1.732}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 8660}{9.8}}}[/tex]

[tex]\sf{ = 883.67 \: or 883.7 m}[/tex]

Hence, The range of the body is 883.67 or 883.7 m.

Answer:

(a) 10.20 s (nearest hundredth)

(b) 127.55 m (nearest hundredth)

(c) 883.70 m (nearest hundredth)

Explanation:

Part (a)

At the end of the projectile's flight, its vertical displacement will be zero.

Resolving vertically, taking up as positive:

[tex]s=0\quad u=100 \sin30^{\circ} \quad v=v, \quad a=-9.8, \quad t=t[/tex]

[tex]\begin{aligned}\textsf{Using }\:s & =ut+\dfrac12at^2:\\ 0 & =100 \sin 30^{\circ}t+\dfrac12(-9.8)t^2\\ 0 & = 50t-4.9t^2\\ 4.9t^2 & = 50t\\ 4.9t & = 50\\ t & = \dfrac{50}{4.9}\\ t & = 10.20\:\sf s\:(nearest\:hundredth)\end{aligned}[/tex]

Part (b)

At the maximum height, vertical velocity will be zero.

Resolving vertically, taking up as positive:

[tex]s=0\quad u=100 \sin30^{\circ} \quad v=0, \quad a=-9.8, \quad t=t[/tex]

[tex]\begin{aligned}\textsf{Using }\:v^2 & = u^2+2as :\\ 0^2 & = (100 \sin 30^{\circ})^2+2(-9.8)s\\ 0 & = 2500-19.6s\\ 19.6s & = 2500\\ s & = \dfrac{2500}{19.6}\\ s & = 127.55\: \sf m\:(nearest\:hundredth) \end{aligned}[/tex]

Part (c)

The horizontal velocity of a projectile is always constant, so u = v.

The horizontal component of acceleration is zero.

Resolving horizontally, taking right as positive (and using the value for t we found in part a):

[tex]s=s\quad u=100 \cos30^{\circ} \quad v=100 \cos30^{\circ} , \quad a=0, \quad t=\dfrac{50}{4.9}[/tex]

[tex]\begin{aligned}\textsf{Using }\:s & =ut+\dfrac12at^2 : \\ s & =(100 \cos 30^{\circ})\left(\dfrac{50}{4.9}\right)+\dfrac12(0)\left(\dfrac{50}{4.9}\right)^2\\ s & =50\sqrt{3}\left(\dfrac{50}{4.9}\right)+0\\ s & =883.70\: \sf m\:(nearest\:hundredth)\end{aligned}[/tex]

Answer:

18.51 J

Explanation:

First, we need to find the Kinetic energy of the disk. Since the disk travels in a straight line, we can use the formula [tex]K=\frac{1}{2}mv^2[/tex]:

[tex]Kdisk=\frac{1}{2} 0.033*33.5^2\\Kdisk=18.51 J[/tex]

Since no other force is present, no friction, sound, or vibration, energy must be conserved. Therefore, the answer for both is 18.51 J.

Answer:

milligram 1000g

kilogram 1/1000 g

electrons negative particle outside nucleus

speed km/h

potential energy at rest

mixture sawdust + salt + iron filings

Explanation:

:D

1. 1000g -kilogram

2.1/1000 g - milligram

3. negative particle outside nucleus - electrons

4. km/h - speed

5.energy at rest - potential
6.  centimeter - cm

7. Sawdust + salt + iron filings - mixture

The energy by  virtue of its position is called the potential energy.

The km/h is the unit of speed.

Milligram is written as 1/1000 g.

1000 g is equal to 1 kilogram.

Electron are the negatively charged subatomic particles rotating outside the nucleus.

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Answer:

B

Explanation: Carbon is released into the air by dead organisms, animals, and humans.

The most logical explanation is the incandescent bulb produces more forms of energy than just light, like heat.

The principle of conservation of energy can be used to explain to reason behind the more energy required for an incandescent bulb to produce the same light as a fluorescent light bulb.

Some part of the energy required by the incandescent bulb is used to produce light while some is used to generate heat.

For fluorescent light bulb, all the energy are used to produce light, leading to a better efficiency and less energy required to produce same amout light as  incandescent bulb.

Thus, the most logical explanation is the incandescent bulb produces more forms of energy than just light, like heat.

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