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All stars begin their life in a

O black hole

O main sequence

O protostar

O nebula​

In redox reactions, an oxidation half reaction shows the oxusetoon occurring while the reduction half reaction shows the reduction occurring in the overall reaction.

Redox reactions are reactions in which oxidation and reduction reactions occur together to the same extent.

A redox reaction can be split into two half oxidation and reduction reactions.

The half reactions of the given reactions are shown below:

Overall reaction;

[tex]A. Mg(s) + CoBr_2(aq) ⟶ MgBr_2(aq) + Co(s) \\ [/tex]

Oxidation half reaction:

[tex]Mg (s) ---> Mg ^{2+}(aq)[/tex]

Reduction half reaction:

[tex]Co^{2+} (aq) ---> Co (s)[/tex]

B. Overall reaction

[tex]Cu(s) + 2AuCl(aq) ⟶ CuCl_2(aq) + 2Au(s) \\ [/tex]

Oxidation half reaction:

[tex]Cu(s) ---> Cu^{2+}(aq)[/tex]

Reduction half reaction:

[tex]2Au^{+}(aq) ---> 2 Au (s)[/tex]

Therefore, redox equations can be spilt into oxidation and reduction half reactions.

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Answer:

Thick layer of body fat for food storage and insulation

Explanation:

Polar bears store food for themselves and so do camels. Option B is not correct because bears do not definitely have small surface area and even if camels do they do not need to reduce heat loss because they stay in the deserts. For option C polar bears have thick fur and much body fat to protect itself from the cold. Lastly D cannot be true because camels don't normally have large feet they have small padded foot.

Answer:

Can you arrange it? I don't understand

Based on Hess law, the enthalpy change, ΔH of the reaction is +48.9 kJ.

The equation of the reaction of sulfur dioxide (SO2) and hydrogen disulfide (H2S) to produce sulfur and water is given below:

[tex]SO_2 + 2H_2S \rightarrow 3S + 2H_2O[/tex]

The ΔH of the reaction is calculated from the summation of the ΔH of the intermediate reactions according to Hess law.

SO2 (g) → S (s) + O2 (g) ΔH1 = +300.1 kJ

H2 (g) + S (s) → H2S (g) ΔH2 = –19.5 kJ

2H2 (g) + O2 (g) → 2H2O (g) ΔH3 = –290.1 kJ

ΔH of the reaction = ΔH1 + 2(-ΔH2) + ΔH3

ΔH of the reaction = 300 + 2 × -(-19.5) + (-290.1)

ΔH of the reaction = +48.9 kJ

Therefore, the ΔH of the reaction is +48.9 kJ.

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Based on the data provided, the equation of the reaction is:

Enthalpy of neutralization is the heat change when one mole of hydrogen ions from an acid reacts with one mole of hydroxide ions from an alkali to produce one mole of water.

The equation of the reaction of KOH and HNO3 is given below:

[tex]KOH + HNO_3 \rightarrow KCl + H_2O[/tex]

1 mole of KOH reacts with 1 mole of HNO3 to produce 1 mole of water.

Volume of KOH = 30 mL = 0.03 L

moles of KOH = 0.03 × 0.234 = 0.00702 moles

Therefore, 0.00702 moles of water are produced

Heat produce = mass × specific heat × temperature difference

Volume of solution = 60 mL

density of solution = 1.0 g/mL

mass of solution = 60 mL × 1.0 g/mL = 60 g

Heat produced = 60 × 4.18 × 5.6

Heat produced = 1404.48 J

Enthalpy of neutralization = 1404.48 J/0.00702 moles

Enthalpy of neutralization = 200068.37 J/mol

Enthalpy of neutralization = 200 kJ/mol

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Answer:

3

Explanation:

7.02     three sig digits

Answer:

A - Cinder cone

B - Shield

C - Composite

Explanation:

Cinder cone volcanoes are formed when the volcano explodes and all the lava soldifies and falls steeply upon the sides of the mountain and forms cinders.

Shield volcanoes form when a centralized vent produces low-viscosity flows over a long period of time

Composite volcanoes are also called stratovolcanoes. They form when different types of eruptions deposit different materials around the sides of a volcano. Alternating eruptions of volcanic ash and lava cause layers to form. Over time these layers build up.

Answer:

Answer:A - Cinder coneB - Shield C - CompositeExplanation:Cinder cone volcanoes are formed when the volcano explodes and all the lava soldifies and falls steeply upon the sides of the mountain and forms cinders. Shield volcanoes form when a centralized vent produces low-viscosity flows over a long period of time Composite volcanoes are also called stratovolcanoes. They form when different types of eruptions deposit different materials around the sides of a volcano. Alternating eruptions of volcanic ash and lava cause layers to form. Over time these layers build up.:

The solubility (in mol/L) of silver chromate in 1.20 M in potassium chromate,  silver nitrate and in pure water is

This is further explained below

Generally,The Chemical reaction is

Ag2CrO4 <----> 2 Ag+ + CrO42-

Ksp = [Ag+]^2[CrO42-]

1.12×10−12 = [Ag+]^2[CrO42-]

Hence

1.12×10−12.=(2X)^2*(1.2)

X = 5.0*10^-7 M

b)

1.12×10−12=(1.2)^2*(X)

1.12×10−12= 1.44 * 1(X)^1

X'' = 8.333*10^-13 M

In conclusion

1.12×10−12=(2X)^2*(s)

1.12×10−12= 4(X)^3

X'''= 6.694*10^-5 M

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Answer:

the reactants have more potential energy than the products have. The extra energy is released to the surroundings.

Taking into account the reaction stoichiometry, 2.13 grams of magnesium was dissolved in the solution.

In first place, the balanced reaction is:

Mg²⁺(aq) + Na₂CO₃(aq) → MgCO₃(s) + 2 Na⁺(aq)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: If by reaction stoichiometry 1 mole of Na₂CO₃ react with 24.3 grams of magnesium, 0.0877 moles of Na₂CO₃ react with how much mass of magnesium?

[tex]mass of magnesium=\frac{0.0877 moles of Na_{2}C O_{3}x24.3 grams of magnesium }{1 mole of Na_{2}C O_{3}}[/tex]

mass of magnesium= 2.13 grams

Finally, 2.13 grams of magnesium was dissolved in the solution.

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Answer:

O protein

Explanation:

Bee venom (BV) is a complex mixture of proteins and contains proteins such as phospholipase and melittin, which have an effect on blood clotting and blood clots.

HGD

The heat flows from inside to the outside direction because of lowering of temperature inside the thermos.

When a thermometer is suspended in an insulated thermos that contain a block of ice, the temperature recorded on the thermometer drops, the direction of heat flow is from inside to the outside the thermos. This is because of the insulating material in which the ice is kept and the lowering of the temperature.

So we can conclude that the heat flows from inside to the outside direction because of lowering of temperature inside the thermos.

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The following redox reactions are classify as:

(a) 2H₂O₂ ⟶ 2H₂O + O₂: Disproportionation reaction (redox)

(b) Mg + 2AgNO₃ ⟶ Mg(NO₃)₂ + 2Ag: Single displacement reaction (redox)

(c) NH₄NO₂ ⟶ N₂ + 2H₂O: Decomposition reaction (redox)

(d) H₂ + Br₂ ⟶ 2HBr: Combination reaction (redox)

(a) 2H₂O₂ ⟶ 2H₂O + O₂

This reaction involves hydrogen peroxide (H₂O₂) breaking down into water (H₂O) and oxygen gas (O₂). The oxidation state of oxygen in hydrogen peroxide is -1, and in water, it is -2. Oxygen in oxygen gas has an oxidation state of 0. Therefore, oxygen is being reduced from -1 to 0. The oxidation state of hydrogen remains +1 in H₂O₂ and H₂O. Since one element (oxygen) is reduced and the other (hydrogen) remains unchanged, this is a disproportionation reaction (a type of redox reaction).

(b) Mg + 2AgNO₃ ⟶ Mg(NO₃)₂ + 2Ag

In this reaction, magnesium (Mg) reacts with silver nitrate (AgNO₃) to form magnesium nitrate (Mg(NO₃)₂) and silver (Ag). The oxidation state of magnesium changes from 0 to +2 in Mg(NO₃)₂, while the oxidation state of silver changes from +1 in AgNO₃ to 0 in Ag. This is a single displacement reaction (a type of redox reaction) because one element (magnesium) displaces another (silver) in the compound.

(c) NH₄NO₂ ⟶ N₂ + 2H₂O

This reaction involves ammonium nitrite (NH₄NO₂) decomposing into nitrogen gas (N₂) and water (H₂O). The oxidation state of nitrogen in NH₄NO₂ is +3, and in nitrogen gas (N₂), it is 0. The oxidation state of hydrogen changes from +1 in NH₄NO₂ to +1 in H₂O. Since nitrogen is being reduced from +3 to 0, and hydrogen remains unchanged, this is a decomposition redox reaction.

(d) H₂ + Br₂ ⟶ 2HBr

In this reaction, hydrogen gas (H₂) reacts with bromine gas (Br₂) to form hydrogen bromide (HBr). The oxidation state of hydrogen changes from 0 in H₂ to +1 in HBr, while the oxidation state of bromine changes from 0 in Br₂ to -1 in HBr. This is a combination reaction (a type of redox reaction) because two elements (hydrogen and bromine) combine to form a compound (hydrogen bromide), and their oxidation states change during the reaction.

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mass it the  amount of matter present in any object or body. Everything we see around us has mass. For example, a table, a chair, your bed, a football, a glass, and even air has mass.

Alkali metals require least amount of ionization energy.

Peaky Blinder fan? haha

Answer:

1630.2 j

Explanation:

100 gm * 4.18 J/gm-C  * ( 25.9-22 C ) = 1630.2 j

Answer:

130.159

Explanation:

P=0.987

V=66ml =66/1000=0.066 L

n/moles= ?

R=0.08206

T=86.9+273.15=360.5 K

Formula PV=RnT

n =PV/TR

n=(0.987 * 0.066)/(360.05 * 0.08206) = 0.002205

Now to obtain molar mass  you divide grams by mol.

0.287/0.002205 = 130.159

Answer:

0.93 M

Explanation:

Molarity = [tex]\frac{Moles}{Volume}[/tex]

4.0M = [tex]\frac{x}{0.007 L}[/tex]

4.0 M x 0.007 L = Moles = 0.028

Molarity = [tex]\frac{Moles}{Volume}[/tex]

Molarity = [tex]\frac{0.028 moles}{0.03 L}[/tex]

= 0.93 M

The Ksp shows the extent of solubility of a substance in another. The solubility of the compound is 1.2 * 10^-7 M.

The term solubility shows the extent to which a substance dissolve in solution. The solubility of a substance is often typified by the Ksp of the substance.

Now;

ScF3(s) ⇄Sc^+(aq) + 3F^-

Ksp = [Sc^+] [F^-]^3

Ksp = x (3x)^3

Ksp = 27x^4

x = 4√5.81×10^−24/27

x = 1.2 * 10^-7 M

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Answer:

This isn't chemistry but the answer is Force = mass x acceleration

From the total pressure of the gaseous mixture, the partial pressure of xenon is 119.5 kPa

The partial pressure of a gas is the pressure that gas exerts when it is part of a mixture of gases which did not chemically react together.

The sum of the partial pressure of each gas in the mixture gives the total pressure.

In the gaseous mixtures above:

Total pressure = 248.8 kPa

Partial pressure of xenon = Total pressure - (Sum of partial pressure of the other gases)

Partial pressure of xenon = 248.8 - (77.3 + 52.0)

Partial pressure of xenon = 119.5

Therefore, the partial pressure of xenon is 119.5 kPa.

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Answer:

so the answer is A 5.199mol please. rate. me brainliest. if its. correct

Explanation:

N=nL

[tex]3.131 \times {10}^{24} = n \times 6.022 \times {10}^{23} \\n = \frac{3.131 \times {10}^{24} }{6.022 \times {10}^{23} } \\ n = 5.199mol[/tex]

One mole of aluminum  contains 6.02 × 10²³ Al  particles. One mole of Al weighs 27 g. Hence 4.60 × 10²¹ Al particles or 0.007 moles weighs 0.208 g.  

One mole of a substance is its amount containing 6.02 × 10²³  atoms or molecules. This number is called Avogadro number. One mole of every elements contains Avogadro number of atoms.

Similarly one mole of every compound contains 6.02 × 10²³ molecules. The mass of one mole of compound is called its molar mass. Similarly mass of one mole of an element is called its atomic mass.

Al is 13th element in periodic table. Al is a metal.  One mole of Al contains 6.02 × 10²³ Al  atoms . Hence number of moles of   4.60 × 10²¹ Al particles is:

4.60 × 10²¹/ 6.02 × 10²³  = 0.0077 .

atomic mass of Al = 27 g/mol.

Then mass of 0.0077 moles =  0.0077 × 27 = 0.208 g

Therefore, the mass of  4.60 × 10²¹ Al particles is 0.208 g.

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Answer:

A grasping :)

Explanation:

The panda uses the "thumb" to grab onto bamboo to eat! Without this, the panda would not be able to eat the bamboo!

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Answer:

please the answer Is false