Hello people ~
The given figure shows a cone of height "h cm" and base-radius "r cm" that is made from a wooden spherical solid of radius 10 cm. The volume of the cone is cm³.

(a) Show that r² =20h-h²

(b) Express V in terms of h

(c) Hence, find the value of h such that the volume of the cone is a maximum.​

Hello People ~The Given Figure Shows A Cone Of Height "h Cm" And Base-radius "r Cm" That Is Made From

Answers

Answer 1

Cone details:

height: h cmradius: r cm

Sphere details:

radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

Using Pythagoras Theorem

(a)

TO² + TU² = OU²

(h-10)² + r² = 10²                                   [insert values]

r² = 10² - (h-10)²                                     [change sides]

r² = 100 - (h² -20h + 100)                       [expand]

r² = 100 - h² + 20h -100                        [simplify]

r² = 20h - h²                                          [shown]

r = √20h - h²                                       ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

[tex]\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)[/tex]

[tex]\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)[/tex]

[tex]\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)[/tex]

[tex]\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)[/tex]

To find maximum/minimum, we have to find first derivative.

(c)

First derivative

[tex]\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )[/tex]

apply chain rule

[tex]\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}[/tex]

Equate the first derivative to zero, that is V'(x) = 0

[tex]\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0[/tex]

[tex]\Longrightarrow \sf 40h-3h^2=0[/tex]

[tex]\Longrightarrow \sf h(40-3h)=0[/tex]

[tex]\Longrightarrow \sf h=0, \ 40-3h=0[/tex]

[tex]\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}[/tex]

maximum volume:                when h = 40/3

[tex]\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )[/tex]

[tex]\sf \Longrightarrow maximum= 1241.123 \ cm^3[/tex]

minimum volume:                 when h = 0

[tex]\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)[/tex]

[tex]\sf \Longrightarrow minimum=0 \ cm^3[/tex]

Hello People ~The Given Figure Shows A Cone Of Height "h Cm" And Base-radius "r Cm" That Is Made From
Answer 2

Answer:

(a)  see step-by-step

[tex]\textsf{(b)}\quad V=\dfrac{20}{3} \pi h^2-\dfrac13 \pi h^3[/tex]

[tex]\textsf{(c)}\quad h=\dfrac{40}{3}[/tex]

Step-by-step explanation:

Part (a)

A right triangle can be drawn with vertices at the center O, the base angle of the cone and the center of the base of the cone (see annotated image).

Side lengths of the formed right triangle:

Hypotenuse = radius of sphere = 10 cmHeight = height of cone - radius of sphere = (h - 10) cmBase = base radius of cone = r cm

Using Pythagoras' Theorem [tex]a^2+b^2=c^2[/tex]
(where a and b are the legs, and c is the hypotenuse, of a right triangle)

[tex]\implies r^2+(h-10)^2=10^2[/tex]

[tex]\implies r^2+h^2-20h+100=100[/tex]

[tex]\implies r^2+h^2-20h=0[/tex]

[tex]\implies r^2=20h-h^2[/tex]

Part (b)

[tex]\textsf{Volume of a cone}=\dfrac13 \pi r^2h[/tex]
(where r is the radius and h is the height)

Substitute the expression for [tex]r^2[/tex] found in part (a) into the equation so that volume (V) is expressed in terms of h:

[tex]\begin{aligned}V & =\dfrac13 \pi r^2h\\\\ \implies V & =\dfrac13 \pi (20h-h^2)h\\\\ & = \dfrac13 \pi (20h^2-h^3)\\\\ & = \dfrac{20}{3} \pi h^2-\dfrac13 \pi h^3 \end{aligned}[/tex]

Part (c)

To find the value of h such that the volume of the cone is a maximum, differentiate V with respect to h:

[tex]\begin{aligned}V & =\dfrac{20}{3} \pi h^2-\dfrac13 \pi h^3\\\\ \implies \dfrac{dV}{dh} & =2 \cdot \dfrac{20}{3} \pi h-3 \cdot \dfrac13 \pi h^2\\\\ & = \dfrac{40}{3} \pi h- \pi h^2\\\\ & = \pi h\left(\dfrac{40}{3}-h\right)\end{aligned}[/tex]

Set it to zero:

[tex]\begin{aligned}\dfrac{dV}{dh} & =0\\\\ \implies \pi h\left(\dfrac{40}{3}-h\right) & = 0\end{aligned}[/tex]

Solve for h:

[tex]\begin{aligned} \pi h & = 0 \implies h=0\\ \dfrac{40}{3}-h & =0\implies h=\dfrac{40}{3}\end{aligned}[/tex]

Substitute the found values of h into the equation for Volume:

[tex]\begin{aligned}\textsf{when}\:h=0:V &=\dfrac{20}{3} \pi (0)^2-\dfrac13 \pi (0)^3\\\\ \implies V & =0\sf \:cm^3\end{aligned}[/tex]

[tex]\begin{aligned}\textsf{when}\:h=\dfrac{40}{3}:V &=\dfrac{20}{3} \pi \left(\dfrac{40}{3}\right)^2-\dfrac13 \pi \left(\dfrac{40}{3}\right)^3\\\\ \implies V & =\dfrac{32000}{27} \pi -\dfrac{64000}{81} \pi\\\\ & = \dfrac{32000}{81} \pi \\\\ & = 1241.123024..\sf \:cm^3\end{aligned}[/tex]

Therefore, the value of h such that the volume of the cone is a maximum is:

[tex]h=\dfrac{40}{3}[/tex]

Hello People ~The Given Figure Shows A Cone Of Height "h Cm" And Base-radius "r Cm" That Is Made From

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see explanation

Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

The Pythagorean theorem can be used to find the hypotenuse of a right triangle with legs 40 feet and 96 feet. It tells you ...

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______

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Alyssa buys cheese and apples at the store.
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which expression is equivalent to 5(x+7)?

Answers

Answer:

5x +35

Step-by-step explanation:

you woul use the distrubitive property

so multiply  by x and and 7

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Hello people ~
find the area of a circle with radius 13 m .

Answers

Answer:

Area of a circle

=πr^2

therefore...

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but π =22/7

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Answer:

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GIVEN:

[tex]\Longrightarrow: \sf{V=L*W*H}[/tex]

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SOLUTION:

Multiply.

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I hope this helps. Let me know if you have any questions.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

Answer:

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Answers

Answer:

x is 25˚

Step-by-step explanation:

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25 = x

Step-by-step explanation:

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Find the distance between the two points.
(1,1)
√ [?]
Enter the number that
goes beneath the
radical symbol.
(3,-4)

Answers

Answer:

The number inside radical is 29

Step-by-step explanation:

Given:

Points (1,1) & (3,-4)

To find:

Distance between two points

Distance Formula:

[tex]\displaystyle \large{\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}[/tex]

Determine (x2,y2) = (1,1) and (x1,y1) = (3,-4). Therefore:

[tex]\displaystyle \large{\sqrt{(1-3)^2+(1-(-4))^2}}\\\displaystyle \large{\sqrt{(-2)^2+(1+4)^2}}\\\displaystyle \large{\sqrt{4+5^2}}\\\displaystyle \large{\sqrt{4+25}}\\\displaystyle \large{\therefore \sqrt{29}}[/tex]

Therefore, the number inside the radical is 29

Answer:

[tex]\sqrt{29}[/tex]

Step-by-step explanation:

Hi there!

We are given the points (1, 1) and (3, -4)

We want to find the distance between the points

Distance can be found using the formula [tex]\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are points

We can label the values of the points first, before calculating to help avoid confusion and mistakes.

[tex]x_1 = 1\\y_1 = 1\\x_2 = 3 \\y_2 = -4[/tex]

Now substitute these values into the formula

d = [tex]\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]

d = [tex]\sqrt{(3-1)^2 + (-4-1)^2}[/tex]

Now, using order of operations, first simplify what is in the parentheses:

d = [tex]\sqrt{(2)^2 + (-5)^2}[/tex]

Now raise 2 and -5 to the second power.

d = [tex]\sqrt{4 + 25}[/tex]

Add the numbers together under the radical

d = [tex]\sqrt{29}[/tex]

The distance is [tex]\sqrt{29}[/tex]

Hope this helps!

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Find the values of the variables:

Answers

Answer:

x = 150

y = 30

Step-by-step explanation:

x° = 5y° (corresponding angles) (1)

x° + y° = 180° (Linear pair angles) (2)

From equations (1) and (2), we find:

5y° + y° = 180°

-> 6y° = 180°

-> y° = 180°/6

-> y° = 30°

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Answers

Answer:

x = 0.71; y = 2.43

Step-by-step explanation:

y = 2x + 1

y = 9x - 4

9x - 4 = 2x + 1

7x = 5

x = 5/7

y = 2x + 1

y = 2(5/7) + 7/7

y = 10/7 + 7/7

y = 17/7

x = 0.71; y = 2.43

ok, A movie theater has a seating capacity of 277. The theater charges $5.00 for children, $7.00 for students, and $12.00 for adults. There are half as many adults as there are children. If the total ticket sales were $ 2002, How many children, students, and adults attended?
__ children attended.
__ students attended.
__ adults attended. brainliest for it

Answers

Using a system of equations, it is found that:

126 children attended.88 students attended.63 adults attended.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

Variable x: Number of children that attended.Variable y: Number of students that attended.Variable z: Number of adults that attended.

The theater was full, hence:

x + y + z = 277.

There are half as many adults as there are children, hence:

x = 2z.

The theater charges $5.00 for children, $7.00 for students, and $12.00 for adults. The total ticket sales were of $2002, hence:

5x + 7y + 12z = 2002.

Replacing the second equation into the other two:

y + 3z = 277 -> y = 277 - 3z

7y + 22z = 2002.

Then:

7(277 - 3z) + 22z = 2002

z = 63

y = 277 - 3z = 277 - 3 x 63 = 88

x = 2z = 2 x 63 = 126.

Hence:

126 children attended.88 students attended.63 adults attended.

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Permutations and, combinations: problem type 2.

(A) From a collection of 51 store customers, 3 are to be chosen to receive a special gift. How many
groups of 3 customers are possible?

(B) How, many different committees of size 4 can be formed from 14 people ?

Answers

Step-by-step explanation:

Permutations:

nP r = n!/(n + r)!

Combinations:

nCr = n!/(n - r)!r!

c - combination

p - permutations

Since in both the problems they are looking for different groups, it is a combination problem. the order in which the people were selected in each group is not important, what is required are different groups.

A.

n = 51

r = 3

51C 3 = 51! / ((51 - 3) ×3!)

51C3 = 20 825 groups

OR:

[tex]c = \frac{51}{3} \times \frac{50}{2} \times 49[/tex]

[tex]c = 20825[/tex]

B.

[tex]c = \frac{14}{4} \times \frac{13}{3} \times \frac{12}{2} \times 11[/tex]

[tex]c = 1001[/tex]

1)
В
13
C
105°
7
A

a. 36.2
b40.2
c81.6
d43.9

Answers

Answer:

Step-by-step explanation:

Could you update the question? It is not clear enough


Juan earns 20% commission as a salesperson. He sold a trampoline that cost $86.40 How
much commission did Juan earn?

Answers

Answer:

$17.28

Step-by-step explanation:

20% of $86.40

= [tex]\frac{20}{100}[/tex] × $86.40

= 0.2 × $86.40

= $17.28 ← commission

 

The width of a rectangle measures (s+5t) centimeters, and its length measures (s+2t)centimeters. Which expression represents the perimeter, in centimeters, of the rectangle?

Answers

Answer:

4s+14t

Step-by-step explanation:

2*[(s+5t)+(s+2t)]

=2*(2s+7t)

=4s+14t

Answer:

Step-by-step explanation:

Remark

The Perimeter of a rectangle is found using

P = 2L + 2w

Givens

L = s+2t

w = s + 5t

Solution

P = 2(s + 2t) + 2(s + t5)                     Remove the brackets

P = 2s + 4t + 2s + 10t                       Combine

P = 4s + 14t

Answer P = 4s + 14t                         This cannot be reduced any further.

please help!!!!
simplify the rational expression. state any restrictions on the variable.
t^2+2t-24/t^2-36

Answers

Answer: hope this helps! :)

t - 4

—————

t - 6

Step-by-step explanation:

          t2 + 2t - 24

Simplify   ————————————

            t2 - 36    

Trying to factor by splitting the middle term

  Factoring  t2 + 2t - 24  

The first term is,  t2  its coefficient is  1 .

The middle term is,  +2t  its coefficient is  2 .

The last term, "the constant", is  -24  

Multiply the coefficient of the first term by the constant   1 • -24 = -24  

Find two factors of  -24  whose sum equals the coefficient of the middle term, which is   2 .

    -24    +    1    =    -23  

    -12    +    2    =    -10  

    -8    +    3    =    -5  

    -6    +    4    =    -2  

    -4    +    6    =    2    That's it

Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -4  and  6  

                   t2 - 4t + 6t - 24

 Add up the first 2 terms, pulling out like factors :

                  t • (t-4)

            Add up the last 2 terms, pulling out common factors :

                  6 • (t-4)

Step-5 : Add up the four terms of step 4 :

                  (t+6)  •  (t-4)

           Which is the desired factorization

Trying to factor as a Difference of Squares :

1.2      Factoring:  t2-36  

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

       A2 - AB + BA - B2 =

       A2 - AB + AB - B2 =

       A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 36 is the square of 6

Check :  t2  is the square of  t1  

Factorization is :       (t + 6)  •  (t - 6)  

Canceling Out :

  Cancel out  (t + 6)  which appears on both sides of the fraction line.

Answer:

t⁴ + t³ - 36t - 24

Step-by-step explanation:

Given :

t² + 2t - 24/t² - 36

Solving :

Multiply throughout with t² so the polynomial is easier to simplifyt² (t² + 2t - 24/t² - 36)t⁴ + t³ - 24 - 36t²t⁴ + t³ - 36t - 24
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