Hello Calculus!

Find the value

[tex]\\ \rm\Rrightarrow {\displaystyle{\int\limits_3^5}}(e^{3x}+7cosx-3tan^3x)dx[/tex]

Note:-

Answer with proper explanation required and all steps to be mentioned .

Answers

Answer 1

Answer:

[tex]\displaystyle \int\limits^5_3 {\bigg( e^{3x} + 7 \cos x - 3 \tan^3 x \bigg)} \, dx = \frac{e^{15} - e^9}{3} + 7 \bigg( \sin 5 - \sin 3 \bigg) - 3 \bigg( \frac{\sec^2 5 - \sec^2 3}{2} - \ln \bigg| \frac{\cos 3}{\cos 5} \bigg| \bigg)[/tex]

General Formulas and Concepts:
Calculus

Differentiation

DerivativesDerivative Notation

Derivative Property [Multiplied Constant]:
[tex]\displaystyle (cu)' = cu'[/tex]

Derivative Property [Addition/Subtraction]:
[tex]\displaystyle (u + v)' = u' + v'[/tex]

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]:
[tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:
[tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:
[tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:
[tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Method: U-Substitution + U-Solve

Step-by-step explanation:

Step 1: Define

Identify given.

[tex]\displaystyle \int\limits^5_3 {\bigg( e^{3x} + 7 \cos x - 3 \tan^3 x \bigg)} \, dx[/tex]

Step 2: Integrate Pt. 1

[Integral] Rewrite [Integration Rule - Addition/Subtraction]:
[tex]\displaystyle \int\limits^5_3 {\bigg( e^{3x} + 7 \cos x - 3 \tan^3 x \bigg)} \, dx = \int\limits^5_3 {e^{3x}} \, dx + \int\limits^5_3 {7 \cos x} \, dx - \int\limits^5_3 {3 \tan^3 x} \, dx[/tex][Integrals] Rewrite [Integration Property - Multiplied Constant]:
[tex]\displaystyle \int\limits^5_3 {\bigg( e^{3x} + 7 \cos x - 3 \tan^3 x \bigg)} \, dx = \int\limits^5_3 {e^{3x}} \, dx + 7 \int\limits^5_3 {\cos x} \, dx - 3 \int\limits^5_3 {\tan^3 x} \, dx[/tex][3rd Integral] Rewrite:
[tex]\displaystyle \int\limits^5_3 {\bigg( e^{3x} + 7 \cos x - 3 \tan^3 x \bigg)} \, dx = \int\limits^5_3 {e^{3x}} \, dx + 7 \int\limits^5_3 {\cos x} \, dx - 3 \int\limits^5_3 {\tan^2 x \bigg( \sec^2 x - 1 \bigg)} \, dx[/tex]

Step 3: Integrate Pt. 2

Identify variables for u-substitution and u-solve.

1st Integral

Set u:
[tex]\displaystyle u = 3x[/tex][u] Differentiate [Derivative Properties and Rules]:
[tex]\displaystyle du = 3 \, dx[/tex][Bounds] Swap:
[tex]\displaystyle \left \{ {{x = 5 \rightarrow u = 3(5) = 15} \atop {x = 3 \rightarrow u = 3(3) = 9}} \right.[/tex]

3rd Integral

Set v:
[tex]\displaystyle v = \sec x[/tex][v] Differentiate [Trigonometric Differentiation]:
[tex]\displaystyle dv = \sec x \tan x \, dx[/tex][dv] Rewrite:
[tex]\displaystyle dx = \frac{1}{\sec x \tan x} \, dv[/tex]

Step 4: Integrate Pt. 3

Let's focus on the 3rd integral first.

Apply Integration Method [U-Solve]:
[tex]\displaystyle 3 \int\limits^5_3 {\tan^2 x \bigg( \sec^2 x - 1 \bigg)} \, dx = 3 \int\limits^{x = 5}_{x = 3} {\frac{v^2 - 1}{v}} \, dv[/tex][Integral] Rewrite [Integration Property - Addition/Subtraction]:
[tex]\displaystyle 3 \int\limits^5_3 {\tan^2 x \bigg( \sec^2 x - 1 \bigg)} \, dx = 3 \Bigg( \int\limits^{x = 5}_{x = 3} {v} \, dv - \int\limits^{x = 5}_{x = 3} {\frac{1}{v}} \, dv \Bigg)[/tex][Integrals] Apply Integration Rules [Reverse Power Rule and Logarithmic Integration]:
[tex]\displaystyle 3 \int\limits^5_3 {\tan^2 x \bigg( \sec^2 x - 1 \bigg)} \, dx = 3 \Bigg( \frac{v^2}{2} \bigg| \limits^{x = 5}_{x = 3} - \ln | v | \bigg| \limits^{x = 5}_{x = 3} \Bigg)[/tex][v] Back-Substitute:
[tex]\displaystyle 3 \int\limits^5_3 {\tan^2 x \bigg( \sec^2 x - 1 \bigg)} \, dx = 3 \Bigg( \frac{\sec^2 x}{2} \bigg| \limits^{5}_{3} - \ln | \sec x | \bigg| \limits^{5}_{3} \Bigg)[/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:
[tex]\displaystyle 3 \int\limits^5_3 {\tan^2 x \bigg( \sec^2 x - 1 \bigg)} \, dx = 3 \Bigg( \frac{\sec^2 5 - \sec^2 3}{2}- \ln \bigg| \frac{\cos 3}{\cos 5} \bigg| \Bigg)[/tex]

Step 5: Integrate Pt. 4

Focus on the other 2 integrals and solve using integration techniques listed above.

1st Integral:

[tex]\displaystyle\begin{aligned}\int\limits^5_3 {e^{3x}} \, dx & = \frac{1}{3} \int\limits^5_3 {3e^{3x}} \, dx \\& = \frac{1}{3} \int\limits^{15}_9 {e^{u}} \, du \\& = \frac{1}{3} e^u \bigg| \limits^{15}_9 \\& = \frac{1}{3} \bigg( e^{15} - e^9 \bigg)\end{aligned}[/tex]

2nd Integral:
[tex]\displaystyle\begin{aligned}7 \int\limits^5_3 {\cos x} \, dx & = 7 \sin x \bigg| \limits^5_3 \\& = 7 \bigg( \sin 5 - \sin 3 \bigg)\end{aligned}[/tex]

Step 6: Integrate Pt. 5

[Integrals] Substitute in integrals:
[tex]\displaystyle \int\limits^5_3 {\bigg( e^{3x} + 7 \cos x - 3 \tan^3 x \bigg)} \, dx = \frac{e^{15} - e^9}{3} + 7 \bigg( \sin 5 - \sin 3 \bigg) - 3 \bigg( \frac{\sec^2 5 - \sec^2 3}{2} - \ln \bigg| \frac{\cos 3}{\cos 5} \bigg| \bigg)[/tex]

∴ we have evaluated the integral.

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Answer 2

Answer:

1086950.36760

Formula's used:

[tex]\rightarrow \sf \int sin(ax+b)=-\dfrac{1}{a} cos(ax+b)+c[/tex]

[tex]\rightarrow \sf \int cos(ax+b)=\dfrac{1}{a} sin(ax+b)+c[/tex]

[tex]\rightarrow \sf \int \dfrac{1}{ax+b} =\dfrac{1}{a} ln|ax+b|+c[/tex]

[tex]\rightarrow \sf \int e^{ax+b}=\dfrac{1}{a} e^{ax+b} + c[/tex]

[tex]\rightarrow \bold{ ln|a| - ln|b| = ln|\frac{a}{b} | }[/tex]

Explanation:

[tex]\dashrightarrow \sf \int \left(e^{3x}+7cos\left(x\right)-3tan^3\left(x\right)\right)[/tex]

                        apply sum rule: [tex]\bold{\int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx}[/tex]

[tex]\dashrightarrow \sf \int \:e^{3x}dx+\int \:7\cos \left(x\right)dx-\int \:3\tan ^3\left(x\right)dx[/tex]

                Integrate simple followings first, using formula's given above

[tex]\dashrightarrow \sf \dfrac{1}{3}e^{3x}+7\sin \left(x\right)-\int 3tan^3x[/tex]

                        Breakdown the component

[tex]\dashrightarrow \sf \dfrac{1}{3}e^{3x}+7\sin \left(x\right)-3\int tan^2x(tanx)[/tex]

                                                         [ tan²x = sec²x - 1 ]

[tex]\dashrightarrow \sf \dfrac{1}{3}e^{3x}+7\sin \left(x\right)-3\int (sec^2x-1)(tanx)[/tex]

===========================================================

for integration of [tex]\bold{\int (sec^2x-1)(tanx)}[/tex]

                                                  apply substitution ... u

[tex]\dashrightarrow \int \dfrac{-1+u^2}{u}[/tex]

[tex]\dashrightarrow \sf \int \:-\dfrac{1}{u}+udu[/tex]

[tex]\dashrightarrow \sf - \int \dfrac{1}{u}du+\int \:udu[/tex]

[tex]\dashrightarrow -\ln \left|u\right|+\dfrac{u^2}{2}[/tex]

substitute back u = sec(x)

[tex]\dashrightarrow \sf-\ln \left|\sec \left(x\right)\right|+\dfrac{\sec ^2\left(x\right)}{2}[/tex]

================================================= insert back

[tex]\dashrightarrow \sf \dfrac{1}{3}e^{3x}+7\sin \left(x\right)-3\left(-\ln \left|\sec \left(x\right)\right|+\dfrac{\sec ^2\left(x\right)}{2}\right)[/tex]   outcome after integrating

Now apply the given limits

[tex]\sf \hookrightarrow \sf \dfrac{1}{3}e^{3(5)}+7\sin \left(5\right)-3\left(-\ln \left|\sec \left(5\right)\right|+\dfrac{\sec ^2\left(5\right)}{2}\right) - (\sf \dfrac{1}{3}e^{3(3)}+7\sin \left(3\right)-3\left(-\ln \left|\sec \left(3\right)\right|+\dfrac{\sec ^2\left(3\right)}{2}\right))[/tex]

                                                                   simplify

[tex]\sf \hookrightarrow \sf \dfrac{1}{3}e^{15}+7\sin \left(5\right)-3\left(-\ln \left|\sec \left(5\right)\right|+\dfrac{\sec ^2\left(5\right)}{2}\right) - (\sf \dfrac{1}{3}e^{9}+7\sin \left(3\right)-3\left(-\ln \left|\sec \left(3\right)\right|+\dfrac{\sec ^2\left(3\right)}{2}\right))[/tex]

                          and group the variables

[tex]\sf \hookrightarrow \dfrac{e^{15}-e^9}{3}-\dfrac{3}{2\cos ^2\left(5\right)}+\dfrac{3}{2\cos ^2\left(3\right)}+7\sin \left(5\right)-7\sin \left(3\right)+3\ln \left(\dfrac{1}{\cos \left(5\right)}\right)-3\ln \left(-\dfrac{1}{\cos \left(3\right)}\right)[/tex]

value:

[tex]\sf \hookrightarrow 1086950.36760[/tex]


Related Questions

Which situation below has the highest constant of
proportionality?
A) 16 ounces of jasmine rice costs $4.80.
B) 32 ounces of white rice costs $6.40
C) 12 ounces of white rice costs $1.20.
D) 9 ounces of brown rice costs $1.80

Answers

Answer:

A) k = 0.3

Step-by-step explanation:

Find the constant of proportionality k in each case and compare

y = kx

A)

16k = 4.80 ⇒ k = 4.80/16 ⇒ k = 0.3

B)

32k = 6.40 ⇒ k = 6.40/32 ⇒ k = 0.2

C)

12k = 1.20 ⇒ k = 1.20/12 ⇒ k = 0.1

D)

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As we see k = 0.3 is the highest one

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Answers

888 + 88 + 8 + 8 + 8 = 1000

have a nice day!

888 + 88 + 8 + 8 + 8 = 1000

hope this helps....

Which function in vertex form is equivalent to f(x) = x2 8 – 16x? f(x) = (x – 8)2 – 56 f(x) = (x – 4)2 0 f(x) = (x 8)2 – 72 f(x) = (x 4)2 – 32

Answers

The function in vertex form that is equivalent to the equation f(x) = x^2 + 8 - 16x from the given options is given by: Option A: f(x) = (x-8)^2 -56

What is vertex form of a quadratic equation?

If a quadratic equation is written in the form

[tex]y=a(x-h)^2 + k[/tex]

then it is called to be in vertex form. It is called so because when you plot this equation's graph, you will see vertex point(peak point) is on (h,k)

Since it is specified that the options are in vertex form, so let we convert the given equation to vertex form.

The specified equation is: [tex]f(x) = x^2 + 8 - 16x[/tex]

Converting to vertex form:

[tex]f(x) = x^2 + 8 - 16x\\\\f(x) = x^2 -16x + 8\\[/tex]

(let we make terms such that it becomes (a+b)^2 's formula).

[tex]f(x) = x^2 -16x + 8\\f(x) = x^2 -2\times8x + (-8)^2 -(-8)^2 + 8\\f(x) = (x-8)^2 -64 + 8\\f(x) = (x-8)^2 -56[/tex]

Thus, the function in vertex form that is equivalent to the equation f(x) = x^2 + 8 - 16x from the given options is given by: Option A: f(x) = (x-8)^2 -56

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Answer:

A

Step-by-step explanation:

When looking for the range of a graph, what values are you looking for?

Answers

Answer: So Remember that the range is how far the graph goes from down to up. Look at the furthest point down on the graph or the bottom of the graph. The y-value at this point is y = 1 y=1 y=1.

Question
Find the missing dimension of the cylinder. Round your answer to the nearest whole number.

Volume = 250 ft³
h is unknown
8 ft is the diameter

Answers

Answer:

H = 5.0

Step-by-step explanation:

Using the formula

[tex]V=\pi r^{2} h[/tex]

Solving for h

[tex]h =\frac{V}{\pi r^{2} } =\frac{250}{\pi *4^{2} }\neq 4.97359[/tex]

Round to the nearest tenth

[tex]5.0[/tex]

A rectangle has the sum of length and breadth 20 cm. find the perimeter.​

Answers

Answer:

40 cm.

Step-by-step explanation:

[tex]Because=(long+width)\times 2=perimeter[/tex]

[tex]50:the\ perimeter=20\times 2=40\ cm[/tex]

I hope this helps you

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Answers

Answer:

9.) 37.55102% or 37.6 depending on how deep into the question you are required to go.

10.) not sure. someone else will have to help you

Step-by-step explanation:

Does anyone get this?! ISTG IF ONE OF U BOTS DROP A LINK IM GONNA-

Only answer if you know :)

Answers

Answer:

Diagonal : 10.2

Longer side: 6

Shorter side: 4

Step-by-step explanation:

Answer:

The Answers are 10.6 for the first one 6 for the second one and 4 for the third one

Step-by-step explanation:

Hope this helps sry if I'm wrong

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Does the budgeted amount cover the actual amount for expenses,savings,and emergencies? A. No it’s short $207.00 B.No it’s short $227.00 C.Yes,there’s a surplus of $207.00 D yes there’s is a surplus of 227.00

Answers

Considering the differences in the budgeted and used amoints, it is found that the correct option is given by:

A. No it’s short $207.00.

In the graph, what are the differences between the budgeted and used amounts?

In utilities, there was a surplus of $20.In groceries, the budget was $150 short.In clothing, the budget was $75 short.In gas, the budget was $2 short.

Hence, the difference between the budgeted amount and the used amount is given by:

20 - (150 + 75 + 2) = -207.

The budget was $207 short, hence option A is correct.

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Answer:

partA option B is the correct answer

partB option A is the correct answer

Can someone help me with this problem?

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Answer:

3 (4+13)

Step-by-step explanation:

The GCF of 12 and 39 in 3 so then you divide 12 and 39 by 3.

Susan took out a personal loan for $3,500 at an interest rate of 13% compounded monthly. she made arrangements to pay the loan off in 3 years. what will her monthly payment be? a. $99.34 b. $105.32 c. $117.93 d. $156.60

Answers

Susan's monthly payment will be $117.93.

We have Susan take out a personal loan for $3,500 at an interest rate of 13% compounded monthly.

P=3500

r=30%

t=3

What is the amortization formula?

[tex]A = \frac{P(\frac{r}{12} )}{(1 -(1 +r/12)^{(-12t)}}[/tex]

Where A is the payment,

P= principal,

r =the annual interest rate

t is the number of years.

use the given value in the formula we get

[tex]A = \frac{3500(0.13/12)}{(1 -(1 +0.13/12)^{-36} }[/tex]

A=117.9288

A= 117.93

Susan's monthly payment will be $117.93.

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Answer: C $117.93

Step-by-step explanation:

1. X=7 and y=3

A. X+Y=

B. X+X+Y=

C. 2X+5Y=

D. 8(X+Y)=

E. 15(2X+Y+Y)=

Answers

Answer:

A. 10

B. 17

C. 29

D. 80

E. 300

Step-by-step explanation:

A.

x + y

7 + 3

10

B.

x + x + y

7 + 7 + 3

14 + 3

17

C.

2x + 5y

2(7) + 5(3)

14 + 15

29

D.

8(x + y)
8(7 + 3)

8(10)

80

E.

15(2x + y + y)

15(2(7) + 3 + 3)

15(14 + 3 + 3)

15(17 + 3)

15(20)

300

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Answer:

7 hrs 42 mins

SAnswer: 7 hrs 42 mins

Step-by-step explanation:

San Antonio to Houston 3 1/3

Houston to Dallas 4 1/12

3 1/3 + 4 1/12=10/3+48/12=89/12=75/12

7 5/12= 7.4166667

= 7hrs and 42 minstep-by-step explanation:

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Answer:

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Step-by-step explanation:

3x^2+ 14 x+14= 0

-3.22 , -1.45

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Answer:

Step-by-step explanation:

Condos in Padre Island increase in value by 7% each year. If the Garza's family's condo is now worth
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257727 I used this formula y=150000(1+0.07)^8

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The minimum of x is 15, and the most is infinity, which is the same thing as [15, ∞).

We have given inequality is

–3(6 – 2x) ≥ 4x + 12

What is the meaning of inequality?

The statement of an order relationship greater than, greater than or equal to, less than, or less than or equal to between two numbers or algebraic expressions.

[tex]-3(6 - 2x) \geq 4x + 12\\-18 + 6x \geq 4x + 12\\6x - 4x \geq 12 + 18\\2x \geq 30\\x \geq 15[/tex]

This means that the minimum of x is 15, and the most is infinity, which is the same thing as [15, ∞).

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what is the equation to represent these words the product of a number and 5 is 8

Answers

Answer:

let's say the Missing number is called 'y'.

product means multiplication so

y x 5 = 8.

Hope this at least helps.

Step-by-step explanation:

y x 5 =8

5y = 8

y = 8/5

8/5 hope this helps man

100 points and brainliest please help i only got 10 minutes!

Answers

Answer:

Step-by-step explanation:

(a)

Data Set 1

Mean : 70 + 65 + 72 + 80 + 73 / 5Mean = 357/5 = 71.4Deviation from Mean : 1.4 + 6.4 + 0.6 + 8.6 + 1.6 / 5M.A.D = 18.6/5 = 3.72

Data Set 2

Mean : 61 + 47 + 70 + 63 + 54 / 5Mean : 295/5 = 59Deviation from Mean : 2 + 12 + 11 + 4 + 5 / 5M.A.D. = 34/5 = 6.8

Comparison

On comparing the Mean Aboslute Deviation values of the two games, it is seen that that the Leaping Lizards game has a higher MAD than the Jumping Jackrabbits game, which means the scores deviate more in the Leaping Lizards game, whereas in the other game it is consistent

How much will it cost the company to make 600 helmets? $

Answers

Answer:

15,600

Step-by-step explanation:

Answer:

15,600

Step-by-step explanation:

help!!! 25 points !!

Answers

Answer:

plan c. is the answer byebye

What is the measure of z?

Answers

Brainly is backed by Naspers, Kulczyk Investments, General Catalyst Partners, Point Nine Capital, Runa Capital, and Learn Capital. In 2009, Lukasz Haluch, Michał Borkowski, and Tomasz Kraus co-founded the company in Kraków, Malopolskie, Poland and is available in 35 countries.

A spinner is divided into five colored sections that are not of equal size: red,
blue, green, yellow, and purple. The spinner is spun several times, and the
results are recorded below:
Spinner Results
Color Frequency
7
16
Red
Blue
Green
Yellow
Purple
19
8
3
Based on these results, express the probability that the next spin will land on
yellow as a percent to the nearest whole number.

Answers

Answer:

15.09%

Step-by-step explanation:

Sum of frequencies = 53

Probability = 8

53

=0.1509

Expressing as a percentage

>> 15.09%

Which fraction is the smallest?
A. 3/4
B. 3/5
C. 3/7
D. 3/9

Answers

Answer:

D. 3/9

Step-by-step explanation:

Attached below is a picture with each fraction illustrated.


500 Rounded to the ones place. (whole number)


Answers

Answer:

500

Remember the rounding rule for the ones place...

0 to 4? Round down or keep the same.

5 to 9? Round up.

__________________________________________________________

Questions?

Ask in comments.

It would stay 500! Hope this helped

what will happen to the mean and mad of this distribution if i move the clinics graph to the right

Answers

Step-by-step explanation:

Graph to move right

As we can see mad is same (10)

Hence it doesn't affect the mad what we do with base axis

So if we turn mean to right it gets bigger.

Option A is correct

A medium pizza cheese pizza a papa johns costs $6.80 plus $0.90 for each topping. The cost of a medium cheese pizza at pizza hut is $7.30 plus $o.65 for each topping. How many toppings need to be added to a large cheese pizza from papa johns and pizza hut in order for the pizzas to cost the same, not including tax?

Answers

Answer:

I hope I answered your question!

Step-by-step explanation:

6.80+0.90x=7.30+0.65x (multiply by 100 on both sides)

680+90x=730+65x

50=25x

x=2

Therefore you need to add 2 toppings to each pizza to make them cost the same.

In the figure, AD is perpendicular to BD, AC is perpendicular to BC, and AD ≅ BC.

Which of the following congruences is NOT necessarily true?
∠DAB ≅ ∠CBA
AE ≅ BE
AC ≅ BD
AD ≅ AE
∠EAB ≅ ∠EBA

Answers

Answer:

D) AD ≅ AE

Step-by-step explanation:

According to given details the triangles ADB and BCE are congruent as per HL congruence

Lets verify the choices

∠DAB ≅ ∠CBA,

this is true as corresponding angles of congruent triangles

AE ≅ BE,

this is true as AEB is isosceles

AC ≅ BD,

this is true as corresponding sides of congruent triangles

AD ≅ AE,

this is NOT true as AE > AD as hypotenuse of right triangle is greater than legs

∠EAB ≅ ∠EBA,

this is true as AEB is isosceles

Answer:

D) AD ≅ AE

Step-by-step explanation:

Hook me up with a 5 star and a Thanks :)

The numbers of runs scored by a baseball team over nine games is shown below.

Answers

Answer:

C

Step-by-step explanation:

The avg is about 3.6

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