HelapPPPpPPPPpThe three states of matter that may change during a physical change are O atoms, molecules, electrons O color, shape, size O solid, liquid, gas​

The area of the rectangular painting which is 2890 square centimeters is equivalent to 447.95 square inches

Square inch (in²) is a unit of area equal to the area of a square the sides of which are each one inch long.

Square centimeter (cm²) is another unit of area equal to that of a square of sides 1 centimeter.

The conversion factor of square centimeter to square inches is as follows:

1 square centimetre = 0.155 square inch

2890 square centimeters = 447.95 square inches

Therefore, the area of the rectangular painting which is 2890 square centimeters is equivalent to 447.95 square inches.

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Answer: (D) 0.025 mol [tex]O_2[/tex]

Explanation:

The given balanced equation is :

[tex]4NH_3+5O_2\rightarrow 4NO+6H_2O[/tex]

According to stoichiometry :

4 moles of ammonia [tex](NH_3)[/tex] reacts with = 5 moles of oxygen [tex](O_2)[/tex]

Thus 0.30 moles of  ammonia  [tex](NH_3)[/tex]  reacts with = [tex]\frac{5}{4}\times 0.30=0.375[/tex] moles of oxygen [tex](O_2)[/tex]

Now as given moles of oxygen are more than the required amount, oxygen is the excess reagent.

moles of oxygen [tex](O_2)[/tex] left = 0.40 - 0.375 = 0.025

Thus 0.025 mol [tex]O_2[/tex] excess reagent remains.

The amount of excess reagent remaining when 0.30 mole NH3 reacts with 0.40 mole O2  is 0.025 mole of O2

An excess reagent is a reactant which is left and can keep reacting after whole reaction.

A limiting reagent is a reactant that is totally consumed in the whole process of the reaction.

The chemical equation for the reaction is represented as:

[tex]\mathbf{4NH_3 + 5O_2 \to 4NO + 6H_2O}[/tex]

From the above reaction,

4 moles of ammonia reacts with 5 moles of oxygen molecule;

If 0.30 moles of ammonia reacts, then the numbers of moles of oxygen required can be computed as:

[tex]\mathbf{= \dfrac{0.3 \times 5}{4}}[/tex]

= 0.375 moles of oxygen.

But, we are given that 0.40 moles of oxygen is present.

Therefore, the amount of oxygen in excess is

= 0.40 moles - 0.375 moles

= 0.025 moles of O2

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The Molarity of solution if a 2.45M of sulphiric acid solution has a density of 1.15g/ml at 20degree celesius is 2.69M.

Given,

Density of the solution = 1.15 g/mL

Molarity of the sulphiric acid = 2.45M

Molar mass of sulphuric acid = 98 g

Density is given as:

[tex]Molarity(\frac{1}{molarity} +\frac{mol.wt}{1000} )\\\\=2.45(\frac{1}{molarity} + \frac{98}{1000} )\\\\(\frac{1}{molarity} = (\frac{1.15}{2.45} + \frac{98}{1000} \\\\(\frac{1}{molarity} = 0.469 - 0.098\\\\(\frac{1}{molarity} = 0.371\\\\Molarity = 2.69m\\\\[/tex]

The Molarity of solution if a 2.45M of sulphiric acid solution has a density of 1.15g/ml at 20degree celesius is 2.69M.

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When the total number of reactants and products are the same in the reaction it is called a balanced chemical equation. The balanced chemical equation of H2+ Cl2   → 2HCl(g)

When the total number of reactants and products are the same in the reaction it is called a balanced chemical equation. In the given reaction one mole of 70 g of hydrogen reacts with 2 moles of Cl.

100 g of chlorine reacts with 2/ 70 * 100 = 2.86 gram of hydrogen.

70 grams of chlorine will produce 73 g of HCl.

100 gram of chlorine produce 73/ 70 * 100 = 104.28 g of HCl.

Therefore, When the total number of reactants and products are the same in the reaction it is called a balanced chemical equation. The balanced chemical equation of H2+ Cl2   → 2HCl(g).

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Heat absorbed by 50 g of iron is 898 Joule.

Heat transfer between two bodies, which can take place through conduction, convection, or radiation, is referred to as heat absorption.

Specific heat - The amount of heat needed to raise a substance's temperature by one degree Celsius in one gram, also known as specific heat. The units of specific heat are usually expressed in terms of calories or joules per gram per degree Celsius. The specific heat of water, for instance, is 1 calorie (or 4.186 joules) per gram per degree Celsius.

The formula of specific heat-

q = mc ΔT

where Q is heat absorbed, m is mass and ΔT is change in temperature.

m = 50 g

c = 0.449 J/g C

ΔT = 60 - 10

     = 40 °C

∴q = 50 x 0.449 x 40

q = 898 J

Hence, heat absorbed by 50 g of iron is 898 Joule.

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The mass of the solution formed when 20 g of sugar dissolved in 150 g of tea is 170 g.

The net mass of solution is calculated as the algebraic addition of the mass of the solute which is stirred into the mass of the solvent.

During the formation of solution, the sugar molecules are dissolved into tea in which sugar molecules fitted into the intermolecular spaces present between the water molecules of the tea and form a homogenous mixture.

Solvent is the substance or mixture which present in large amount in the solution.

Solute is the substance or mixture which present in small amount in the solution.

Given,

Mass of solute (sugar) = 20g

Mass of solvent (tea) = 150g

Total mass of solution = 20 + 150

= 170g.

Thus we concluded that the mass of the solution formed when 20 g of sugar dissolved in 150 g of tea is 170 g.

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The energy of the radio wave in kilojoules is obtained as 6.2 * 10^-25 J.

The term wave has to do with a disturbance along a medium which transfers energy. There are different kinds of wave. In this case, a radio wave is a type of electromagnetic wave. The electromagnetic waves do not require a medium for their propagation. This implies that they are able to move on their own with no medium.

Thus;

We know that;

Frequency of the wave = 9.3x10^8 Hz

Plank's constant =  6.626 x 10^-34 J.s

E = hf

E = energy of the wave

h = Plank's constant

f = frequency of the waves

E = 9.3x10^8 Hz *  6.626 x 10^-34 J.s

= 6.2 * 10^-25 J

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Given that hydrogen is not able to donate its single electron,  the water molecule forms by the sharing of electrons between two hydrogen atoms and an oxygen atom.

This is the type of bond which occurs when the electrons of an atom are shared unlike electrovalent bond which is formed when the electrons are transferred from one atom to another.

In this case, since hydrogen can't transfer electron and oxygen needs two electrons to achieve its stable configuration then two hydrogen atoms will share one electron each with the oxygen atom which results in the formation of water.

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Answer:

Determining an Empirical Formula from Combustion Data

Explanation:

Step 1: Identify the mass of carbon dioxide and water produced by the combustion.

Step 2: Find how many moles of carbon are in carbon dioxide.

Step 3: Find how many moles of hydrogen are in water.

The empirical formula of the compound that decomposes is [tex]N_{2} O[/tex]

The term decomposition refers to a type of reaction in which a substance is broken down into its components. We know that a compound is composed of atoms. When there is a decomposition reaction, the atoms of the compound break down.

We can see that the products of the decomposition reaction are nitrogen and oxygen. The red spheres represent oxygen atoms, and the smaller, blue spheres represent nitrogen atoms.

We know that nitrous oxide decomposes to give nitrogen and oxygen. Thus the empirical formula of the compound is [tex]N_{2} O[/tex].

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Answer: a

Explanation:

i hope is help

Answer: To Know That They Did Nothing Wrong

Explanation:

For Example, They Maybe Put The Wrong Thing
Or They Made The Different One Instead Of What They Were Supposed To Do

The percent yield of the ether is 66.5% and the mass of ethylene produced is 4.9 g.

We know that in a reaction, we are only able to obtain the parameter of the reactions by the use of stoichiometry. This is the relationship between the reactants and the products in the process.

The reaction is given as shown in the reaction equations in the question above.

Number of moles of ethanol =  54.0 g /46 g/mol = 1.17 moles

Since 2 moles of ethanol yields 1 mole of ether

1.17 moles of ethanol yields 1.17 moles * 1 mole /2 moles

= 0.585 moles

Mass of the ether = 0.585 moles * 74 g/mol = 43.29 g

Percent yield = 28.8 g/ 43.29 g * 100/1

= 66.5 %

Amount of unreacted ethanol = (100 - 66.5)/100 * 1.17 moles = 0.39 moles

Amount that participates in the side reaction  45.0/100 * 0.39 moles = 0.1755 moles

Given that the reaction is 1:1

Mass of ethylene produced = 0.1755 moles * 28 g/mol = 4.9 g of ethylene

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Answer:

b.

i hope is help

The given operations are performed

and the expressions are presented

in scientific notation as follows;

1) (1.2 × 10⁵) + (5.35 × 10⁶) = 5.47 × 10⁶

2) (6.91 × 10^(-2) + (2.4 × 10^(-3)) = 7.15 × 10^(-2)

3) (9.70 × 10⁶) + (8.3 × 10⁶) = 1.053 × 10⁷

1) (1.2 × 10⁵) + (5.35 × 10⁶)

(1.2 × 10⁵) + (5.35 × 10⁶) = (1.2 × 10⁵) + (53.5 × 10⁵)

(1.2 × 10⁵) + (53.5 × 10⁵) = (1.2 + 53.5) × 10⁵

(1.2 + 53.5) × 10⁵ = 54.7 × 10⁵

54.7 × 10⁵ = 5.47 × 10⁶

Therefore;

(1.2 × 10⁵) + (5.35 × 10⁶) = 5.47 × 10⁶

2) (6.91 × 10^(-2) + (2.4 × 10^(-3))

(6.91 × 10^(-2) + (2.4 × 10^(-3)) = (69.1 × 10^(-3) + (2.4 × 10^(-3))

(69.1 × 10^(-3) + (2.4 × 10^(-3)) = (69.1 + 2.4) × 10^(-3)

(69.1 + 2.4) × 10^(-3) = 71.5 × 10^(-3)

71.5 × 10^(-3) = 7.15 × 10^(-2)

Therefore;

(6.91 × 10^(-2) + (2.4 × 10^(-3)) = 7.15 × 10^(-2)

3) (9.70 × 10⁶) + (8.3 × 10⁵)

(9.70 × 10⁶) + (8.3 × 10⁵) = (97.0 × 10⁵) + (8.3 × 10⁵)

(97.0 × 10⁵) + (8.3 × 10⁵) = (97.0 + 8.3) × 10⁵

(97.0 + 8.3) × 10⁵ = 105.3 × 10⁵

105.3 × 10⁵ = 1.053 × 10⁷

Therefore;

(9.70 × 10⁶) + (8.3 × 10⁵) = 1.053 × 10⁷

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The maximum number of moles of [tex]CO_2[/tex] that can be recovered from the reaction vessel would be 0.17 moles.

The reaction vessel contains:

The equation of the reaction would be as follows:

[tex]2CO + O_2 --- > 2CO_2[/tex]

The mole ratios of the reactants to the product are as follows:

4.800 g of CO = 4.8/28

                        = 0.17 moles

4.800 g of [tex]O_2[/tex] = 4.8/32

                      = 0.15 moles

Since the mole ratio of CO to  [tex]O_2[/tex] is 2 to 1, 0.17 of CO is limiting.

The mole ratio of CO to  [tex]CO_2[/tex] is 1 to 1. Thus, the equivalent mole of  [tex]CO_2[/tex] that can be recovered is also 0.17.

In other words, the maximum number of moles of  [tex]CO_2[/tex] that can be recovered from the reaction vessel is 0.17 moles.

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Remember that 1 nanometer is equal to 1 x 109, therefore multiply 6.49 x 10-3 m by 1 x 109 to get the answer. The correct response is 6.49 x 10-3 m = 6.49 x 106 nm.

What are nanometers used for?

The measuring unit known as a nanometer (NM) is one billionth of a meter. It is frequently used as a scale for creating intricate, atomic-scale parts, particularly in nanotechnology.

What dimension does a nanometer have?

How tiny is "nano" exactly? One nanometer is one billionth of a meter since the prefix "nano" in the International System of Units refers to one billionth, or 10-9. Here are some samples to help you visualize how little that is: About 100,000 nanometers make up a sheet of paper.

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The correct answer is option c) Three moles of sodium, Na.

We know that

18g of H₂O = 1 mol

So, no. of atoms in H₂O = 3 x 6.022 x 10²³

                                           = 1.81 x 10²⁴ atoms(both H&O atoms combined)

Now,

No. of atoms in 1 mol of H₂ = 2 x 6.022 x 10²³

                                             = 1.2044 x 10²⁴ atoms.

No. of atoms in 2 mol of NaCl = 2 x 6.022 x 10²³

                                                  = 1.2044 × 10²⁴ atoms.

No. of atoms in 2 mol of O₂ = 2 x 6.022 x 10²³

                                              = 1.2044 × 10²⁴ atoms.

No. of atoms in 3 mol Na  = 3 x 6.022 x 10²³  

                                              = 1.81 x 10²⁴ Na atoms.

Therefore, 3 mol of Na contains as many atoms as 18g of H₂O i.e., 1.81 x 10²⁴ atoms.

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Which Of The Following Contains As Many Atoms As 18 G Of Water, H2O?

a) One mole of hydrogen, H₂

b) Three moles of sodium, Na

c) Two moles of sodium chloride, NaCl

d) Two moles of oxygen, O₂

A piece of magnesium in the shape of cube measuring with height of 5.62 cm, and this magnesium sample having mass of 1.41 g has a density of 1.78 g/cm³.

What is Density?

Density is known as the mass of substance per unit volume. Density is denoted by a Greek symbol ρ. Density is equal to the mass substance divided by its volume. The SI unit of Density is g/cm ³or kg/m³.

                                     ρ = m

                                             v

where,

ρ = density

m = mass

v  = volume

Given :

Height of the cylinder is 5.62 cm ,

Diameter of the cylinder is 1.34 cm

Radius = D/2 = 1.34/2 cm

Radius = 0.67 cm

Volume of cylinder = πr²h

Volume of cylinder = 3.14 × (0.67)² × 5.62

                                = 7.92 cm³

 Density =   Mass  

                 Volume

Density = 14.1

                 7.92

 Density = 1.78 g/cm³

Hence, the density of sample = 1.78 g/cm³ .

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Answer: B

Explanation:

The atomic number of an element is the number of protons in the nucleus of an atom of that element. Changing the number of neutrons means you get an isotope of the same element. Changing the number of electrons does not affect the atom but affects the charge of the atom. So the periodic table is arranged by increasing the number of protons or atomic numbers.

The concentration of this solution in moles is 0.75 M.

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution.

Mathematically. concentration is given as;

C = n/V

where;

At a constant number of moles;

C1V1 = C2V2

When you boil away 2/3 volume, the new volume becomes 1/3

So V1  = V

V2 = 1/3V = 0.3333V

Substitute the given parameters and solve for the new concentration.

C2 = (C1V1)/V2

C2 = (0.25 x V) / (0.3333V)

C2 = 0.75 M

Thus, the concentration of this solution in moles is 0.75 M.

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Answer: The Marshmellow

Explanation

The marshmallow turns from a solid to a gooey texture.

The concentration of the new solution, given that 2/3 of it's initial volume was boiled away is 0.758 M

The following data were obtained from the question:

The molarity of the new solution can be obtained as follow:

M₁V₁ = M₂V₂

0.250 × 1 = M₂ × 0.33

0.250 = M₂ × 0.33

Divide both side by 0.33

M₂ = 0.250 / 0.33

M₂ = 0.758 M

Thus, the concentration of the new solution is 0.758 M

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s block - group 1 and 2 , p block - group 13 to 18 , d block - group 3 to 12, f block - group 3

Thus we can conclude that ,they are names as s,p,d and f blocks because the last electrons enter s, p , d and f orbitals respectively.

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Answer: kinetic or A :)

Explanation: kinetic energy Alpha particles have typical kinetic energy of 5 MeV (or ≈ 0.13% of their total energy 110 TJ/kg) and have a speed of about 15 000 000 m/s or 5% of the speed of light.

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256.73 ft

Convert 7.27 [tex]m^3[/tex] to[tex]ft^3[/tex]

as per above , we have to convert [tex]m^3[/tex] into [tex]ft^3[/tex]

now:

1 [tex]m^3[/tex] = 35.31  [tex]ft^3[/tex]

7.27 [tex]m^3[/tex] = 35.31 [tex]\times[/tex] 7.27 [tex]m^3[/tex]

               = 256.73 ft

meter cubic and feet both are volumetric unit

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The structure of tRNA resembles cloverleaf. 

 tRNA is called transfer RNA, which is a small RNA molecule which plays important role in protein synthesis.-It serves as link between messenger RNA and the growing chain of amino acids that make up protein.

 tRNA molecules fold into structure resembling cloverleaf  with four important sites:-

•The acceptor stem (3’-CCA) have an amino acid

•The anticodon  attaches  with the mRNA codon (via complementary base pairing)

•The T arm attaches  with the ribosome (via the E, P and A binding sites)

•The D arm of tRNA activating enzyme (help in adding the amino acid to the acceptor stem).

CCA is codon codes for  prolein amino acid in polypeptide chain.

AUG is initiator codon codes for methionine.

UAG, UAA and UGA are stop codons.

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