he data represents the daily rainfall​ (in inches) for one month. Construct a frequency distribution beginning with a lower class limit of 0.000.00 and use a class width of 0.200.20. Does the frequency distribution appear to be roughly a normal​ distribution? 0.310.31 0 0 0 0.190.19 0 0.150.15 0 0.010.01 0.190.19 0.530.53 0 0

Answer:

[tex]x = \frac{1}{4}[/tex]

Step-by-step explanation:

[tex]\frac{x}{2} +\frac{3}{4} =\frac{7}{8}[/tex]

→ Find the LCM of the denominators (2,4 and 8)

LCM = 8

→ Multiply the whole equation by 8 to get rid of the fractions

4x + 6 = 7

→ Minus 6 from both sides to isolate 4x

4x = 1

→ Divide both sides by 4 to isolate x

[tex]x = \frac{1}{4}[/tex]

Answer:

Step-by-step explanation:

[tex] \frac{x}{2} + \frac{3}{4} = \frac{7}{8} [/tex]

Multiply both sides of the equation by 8

[tex] \frac{x}{2} \times 8 + \frac{3}{4} \times 8 = \frac{7}{8} [/tex]

[tex]4x + 6 = 7[/tex]

Move constant to R.H.S and change its sign

[tex]4x = 7 - 6[/tex]

Subtract the numbers

[tex]4x = 1[/tex]

Divide both sides of the equation by 4

[tex] \frac{4x}{4} = \frac{1}{4} [/tex]

Calculate

[tex]x = \frac{1}{4} [/tex]

hope this helps..

Best regards!!

Answer:

mosses

Step-by-step explanation:

use socratic

Mosses are also known as the amphibian of the plant kingdom. The mosses were the first plant that can even survive on the land.

Conifers, pines, and flowering plants developed much later after the evolution of bryophytes.

Therefore, the mosses were the first plant that can even survive on the land.

Learn more about Bryophytes:

https://brainly.com/question/841138

Answer:

19/70 of NASA shuttle missions were carried out by Discovery.

9/140 of NASA shuttle missions were carried out by Challenger.

17/70 of NASA shuttle missions were carried out by Endeavour.

Step-by-step explanation:

Adding the number of missions carried out by NASA gives us 140 in total.

Discovery's total amount of missions simplified is 19/70.

Challenger's total amount of missions is already in the simplest form.

Endeavour's total amount of missions simplified is 17/70.

Answer:

81/140

Step-by-step explanation:

Well to find the fraction we first need to total amount of NASA missions.

38 + 32 = 70

70 + 34 = 104

104 + 27 = 131

131 + 9 = 140

Now we need to find out the amount of Discovery, Challenger, and Endeavour missions.

38 + 9 + 34 = 81

Now we can make the following fraction,

81/140

This is already in simplest form.

Thus,

the answer is 81/140.

Hope this helps :)

Answer:

x= 78

Step-by-step explanation:

Focus on the blue traingle:

∠BHI= 180° -47° -31° (∠sum of triangle)

∠BHI= 102°

x°= 180° -102° (adj. ∠s on a str. line)

x°= 78°

x= 78

Alternatively,

x°= 47° +31° (ext. ∠ of triangle)

x°= 78°

x= 78

Answer:

-3

Step-by-step explanation:

-3 is the answer

Answer:

-3

Step-by-step explanation:

Answer: 6 hours

Step-by-step explanation:

Given, Tim and Jim are working on a school project together.

Tim takes 10 hours to complete the school project.

If Jim worked alone, it would take him 15 hours

Let t be the time they both take if they work together.

Then, [tex]\dfrac{1}{t}=\dfrac{1}{\text{Time taken by Tim}}+\dfrac{1}{\text{Time taken by jim}}[/tex]

[tex]\Rightarrow\ \dfrac{1}{t}=\dfrac{1}{10}+\dfrac{1}{15}\\\\\Rightarrow\ \dfrac{1}{t}=\dfrac{3+2}{30}=\dfrac{5}{30}\\\\\Rightarrow\dfrac{1}{t}=\dfrac{1}{6}\\\\\Rightarrow t=6[/tex]

So, it will take 6 hours to complete the school project together .

Answer:

4 plants

Step-by-step explanation:

If betty has $33 dollars and each plant is $8, than 33/8 ≈ 4

(8 * 4 is 32)

She will have one dollar left but she can't buy another plant since that's not enough.

Answer:

4 plants

Step-by-step explanation:

Take the amount of money she has and divide by the cost per plant

33/8

The amount is 4 with 1 dollar left over

4 plants

Option A is the correct answer.

Answer:

SAS

Step-by-step explanation:

According to the given information both the triangles are congruent by SAS postulate.

The given triangles are congruent by SAS rule.

Two triangles are said to be congruent if all three corresponding sides are equal and all the three corresponding angles are equal in measure.

Given are two triangles, ABC and DEF,

They have congruent parts, given;

AB ≅ DE

BC ≅ EF

∠ B ≅ ∠ E

The triangles have two congruent sides and one congruent angle between them.

The Side-Angle-Side theorem of congruency states that, if two sides and the angle formed by these two sides are equal to two sides and the included angle of another triangle, then these triangles are said to be congruent.

Hence, The given triangles are congruent by SAS rule.

For more reference on congruent triangles, click;

https://brainly.com/question/12413243

#SPJ2

Answer:

9 in.

Step-by-step explanation:

Given that the 4 in and 10 in. lines are parallel, the two triangles are similar.

As such, the ratio of the sides would give the same results.

Hence,

4/6 = 10/(6 + x)

cross multiplying

4(6 + x) = 60

Dividing both sides by 4

6 + x = 15

collecting like terms

x = 15 - 6

= 9

Answer:

74w+10

Step-by-step explanation:

That's the answer

Answer:

Sydney's age is 28

Step-by-step explanation:

Let Devaughn be D

And Sydney be S

D=S+8..... equation 1

D+S=64...... equation 2

Substitute equation 1 to equation 2

S+8+S=64

2S+8=64

2S=64-8

2S=56

S=56/2

S=28

Hope it helps

Good luck

Answer:

x ≥ 4

Step-by-step explanation:

Well to find the inequality we need to single out x,

4x - 1 ≥ 15

+1 to both sides

4x ≥ 16

Divide 4 by both sides

x ≥ 4

Thus,

x is greater than or equal to 4.

Hope this helps :)

Answer:8

Step-by-step explanation:

You find the average which is adding them all together then dividing by how many numbers you added.

Answer:

x is all real numbers

Step-by-step explanation:

5(x-7) + 42 = 5x+7

Distribute

5x - 35 +42 = 5x+7

Combine like terms

5x +7 = 5x+7

Subtract 5x from each side

7=7

This is always true, so x can be any number

Answer:

Hey there!

5(x-7)+42=5x+7

5x-35+42=5x+7

7=7

Infinite solutions.

Hope this helps :)

Answer:

It is 96 square units

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

To solve this you do 80/100=.8

You than do .8×60= 48

Step-by-step explanation:

8. As the name implies, a box-and-whisker plot looks like a box with two whiskers.  The box is the middle 50%.  The whiskers are the bottom 25% and the top 25%.

First, we need to sort the numbers from smallest to largest.  Starting with Set A:

Set A = {56, 57, 62, 68, 71, 82, 84, 92, 97, 101, 103, 106}

Now we find the median of the set, or the middle number.  Set A has 12 data points.  Since 12 is an even number, the median will be the average of the 6th and 7th numbers.

M = (82 + 84) / 2 = 83

Next, we find the median of the lower half.  There are 6 numbers in the lower half, so the median is the average of the 3rd and 4th numbers.

Ml = (62 + 68) / 2 = 65

Now we find the median of the upper half.  Again, there are 6 numbers in the upper half, so the median will be the average of the 3rd and 4th numbers.

Mu = (97 + 101) / 2 = 99

So the left whisker is from 56 to 65.

The box is from 65 to 99.

The right whisker is from 99 to 106.

Don't forget to mark the median, 83.

Repeat for Set B.

Set B = {36, 37, 42, 46, 48, 56, 58, 63, 69, 72, 75, 78}

M = (56 + 58) / 2 = 57

Ml = (42 + 46) / 2 = 44

Mu = (69 + 72) / 2 = 70.5

So the left whisker is from 36 to 44.

The box is from 44 to 70.5.

The right whisker is from 70.5 to 78.

The median is 57.

By graphing both on the same number line, we can easily compare them.

9. To make a dot plot, draw a number line starting from the smallest number and ending at the largest number.  For each number, draw a dot every time the number appears in the set.  For example, the number 3 appears twice in Set A, so draw two dots on 3.  You may find it helpful to sort the data first.

10. Draw a dot plot of the set to determine the shape.

Step-by-step explanation:

just substitute the value of g(X) and f(X)

Answer:

x = 0

Step-by-step explanation:

-7(5-3x)=-35

Divide by -7

-7/-7(5-3x)=-35/-7

5 -3x = 5

Subtract 5 from each side

5-3x-5 = 5-5

-3x=0

Divide by -3

x=0

Answer: x = 0

Step-by-step explanation: Start by distributing the -7 through the parenthses on the left side of the equation.

-7(5) is -35 and -7(-3x) is 21x.

So we have -35 + 21x = -35.

Next, isolate the x term by adding 35 to both sides.

When we do this, we get 21x = 0.

Now divide both sides by 21 and x = 0.

Answer:

The answer is 2.15%  

Step-by-step explanatio

Answer:

The last graph (to the far right).

Step-by-step explanation:

As long as each x-value has one y-value, it is a function. However, the last graph has an x-value at -1 where there are two y-values. So, it does not pass the Vertical Line Test, and it is a relation rather than a function.

Hope this helps!

Answer:

its 23

Step-by-step explanation:

Answer:

$18.3236

Step-by-step explanation:

If the employer reimburses $0.17 per mile driven, we just need to multiply $0.17 by the number of miles that Joe drives.

So, the mileage reimbursement for Joe is:

$0.17 * 107.78 = $18.3236

Answer:

We know that for a standard dice the probability of obtain a 6 is:

[tex] P=\frac{1}{6}[/tex]

And for this case our value of x=3 and replacing we got:

[tex] f(x=3) = (1- \frac{1}{6})^{3-1} \frac{1}{6}[/tex]

[tex]f(x=3)=\frac{25}{36} \frac{1}{6}= \frac{25}{216}= 0.116[/tex]

Step-by-step explanation:

For this case we have the following function:

[tex] f(x) = (1-P)^{x-1} P[/tex]

We want to find the approximate probability of rolling a standard die and getting the first 6 on the 3rd try

We know that for a standard dice the probability of obtain a 6 is:

[tex] P=\frac{1}{6}[/tex]

And for this case our value of x=3 and replacing we got:

[tex] f(x=3) = (1- \frac{1}{6})^{3-1} \frac{1}{6}[/tex]

[tex]f(x=3)=\frac{25}{36} \frac{1}{6}= \frac{25}{216}= 0.116[/tex]

Hey there! :)

Answer:

118 children

58 students

59 adults

Step-by-step explanation:

We can solve this problem by setting up a system of equations:

Let a = adults

2a = children (since double the # of adults were children), and

s = students

Set up the equations:

1704 = 5(2a) + 7s + 12(a)

1704 = 10a + 7s + 12a

235 = 2a + a + s

Simplify the equations:

1704 = 22a + 7s

235 = 3a + s

Subtract the bottom equation from the top by multiplying the bottom equation by 7 to eliminate the 's' variable:

1704 = 22a + 7s

7(235 = 3a + s)

1704 = 22a + 7s

1645 = 21a + 7s

---------------------- (Subtract)

59 = a

This is the number of adults. Substitute this number into an equation to solve for the number of students:

235 = 3(59) + s

235 = 177 + s

s = 58.

Since the number of children is equivalent to 2a, solve:

2(59) = 118 children.

Therefore, the values for each group are:

118 children

59 adults

58 students.

Answer:

adults: 59, students:58 and children 118

Step-by-step explanation:

let A for adults, and C = children and S for students

There are half as many adults as there are children=

A=C/2 , C=2A

A+C+S=235 or

A+2A+S=235 first equation

3A+S=235

12A+5C+7S =1704 or

12A+10A+7S=1704

22A + 7S=1704 second equation

3A+S=235 first

solve by addition and elimination

22A+7S=1704

21 A+7S=1645 subtract two equations

A=59 adults

C=2A=2(59)=118

substitute in :A+S+C=235

S=235-(118+59)=58

check: 5C+7S+12A=1704

5(118)+7(58)+12(59)=1704

Answer:

a) The rate of change associated with the volume of the box is 54 cubic meters per second, b) The rate of change associated with the surface area of the box is 18 square meters per second, c) The rate of change of the length of the diagonal is -1 meters per second.

Step-by-step explanation:

a) Given that box is a parallelepiped, the volume of the parallelepiped, measured in cubic meters, is represented by this formula:

[tex]V = w \cdot h \cdot l[/tex]

Where:

[tex]w[/tex] - Width, measured in meters.

[tex]h[/tex] - Height, measured in meters.

[tex]l[/tex] - Length, measured in meters.

The rate of change in the volume of the box, measured in cubic meters per second, is deducted by deriving the volume function in terms of time:

[tex]\dot V = h\cdot l \cdot \dot w + w\cdot l \cdot \dot h + w\cdot h \cdot \dot l[/tex]

Where [tex]\dot w[/tex], [tex]\dot h[/tex] and [tex]\dot l[/tex] are the rates of change related to the width, height and length, measured in meters per second.

Given that [tex]w = 6\,m[/tex], [tex]h = 6\,m[/tex], [tex]l = 3\,m[/tex], [tex]\dot w =3\,\frac{m}{s}[/tex], [tex]\dot h = -6\,\frac{m}{s}[/tex] and [tex]\dot l = 3\,\frac{m}{s}[/tex], the rate of change in the volume of the box is:

[tex]\dot V = (6\,m)\cdot (3\,m)\cdot \left(3\,\frac{m}{s} \right)+(6\,m)\cdot (3\,m)\cdot \left(-6\,\frac{m}{s} \right)+(6\,m)\cdot (6\,m)\cdot \left(3\,\frac{m}{s}\right)[/tex]

[tex]\dot V = 54\,\frac{m^{3}}{s}[/tex]

The rate of change associated with the volume of the box is 54 cubic meters per second.

b) The surface area of the parallelepiped, measured in square meters, is represented by this model:

[tex]A_{s} = 2\cdot (w\cdot l + l\cdot h + w\cdot h)[/tex]

The rate of change in the surface area of the box, measured in square meters per second, is deducted by deriving the surface area function in terms of time:

[tex]\dot A_{s} = 2\cdot (l+h)\cdot \dot w + 2\cdot (w+h)\cdot \dot l + 2\cdot (w+l)\cdot \dot h[/tex]

Given that [tex]w = 6\,m[/tex], [tex]h = 6\,m[/tex], [tex]l = 3\,m[/tex], [tex]\dot w =3\,\frac{m}{s}[/tex], [tex]\dot h = -6\,\frac{m}{s}[/tex] and [tex]\dot l = 3\,\frac{m}{s}[/tex], the rate of change in the surface area of the box is:

[tex]\dot A_{s} = 2\cdot (6\,m + 3\,m)\cdot \left(3\,\frac{m}{s} \right) + 2\cdot (6\,m+6\,m)\cdot \left(3\,\frac{m}{s} \right) + 2\cdot (6\,m + 3\,m)\cdot \left(-6\,\frac{m}{s} \right)[/tex]

[tex]\dot A_{s} = 18\,\frac{m^{2}}{s}[/tex]

The rate of change associated with the surface area of the box is 18 square meters per second.

c) The length of the diagonal, measured in meters, is represented by the following Pythagorean identity:

[tex]r^{2} = w^{2}+h^{2}+l^{2}[/tex]

The rate of change in the surface area of the box, measured in square meters per second, is deducted by deriving the surface area function in terms of time before simplification:

[tex]2\cdot r \cdot \dot r = 2\cdot w \cdot \dot w + 2\cdot h \cdot \dot h + 2\cdot l \cdot \dot l[/tex]

[tex]r\cdot \dot r = w\cdot \dot w + h\cdot \dot h + l\cdot \dot l[/tex]

[tex]\dot r = \frac{w\cdot \dot w + h \cdot \dot h + l \cdot \dot l}{\sqrt{w^{2}+h^{2}+l^{2}}}[/tex]

Given that [tex]w = 6\,m[/tex], [tex]h = 6\,m[/tex], [tex]l = 3\,m[/tex], [tex]\dot w =3\,\frac{m}{s}[/tex], [tex]\dot h = -6\,\frac{m}{s}[/tex] and [tex]\dot l = 3\,\frac{m}{s}[/tex], the rate of change in the length of the diagonal of the box is:

[tex]\dot r = \frac{(6\,m)\cdot \left(3\,\frac{m}{s} \right)+(6\,m)\cdot \left(-6\,\frac{m}{s} \right)+(3\,m)\cdot \left(3\,\frac{m}{s} \right)}{\sqrt{(6\,m)^{2}+(6\,m)^{2}+(3\,m)^{2}}}[/tex]

[tex]\dot r = -1\,\frac{m}{s}[/tex]

The rate of change of the length of the diagonal is -1 meters per second.

Answer:

Total cost = $4,873

Therefore, the booking cost of hotel 5 would be $4,873

Step-by-step explanation:

Please refer to the attached table.  

The total cost includes the cost of the room and the cost of buffet dinner.

From the given table hotel 5,

The cost of the room for 120 people is found to be $166 per hour.

The conference will last for 5 hours so the total cost of the room is

Cost of room = 5*$166 = $830

From the given table hotel 5,

The cost of the buffet dinner per head is found to be $30.

Since there are total 120 people so the total cost of dinner is

Cost of dinner = 120*$30 = $3600

Total cost = $830 + $3600 = $4430

We are given that hotel 5 has recently increased the total chargers by 10%

Total cost = $4430*1.10

Total cost = $4,873

Therefore, the booking cost of hotel 5 would be $4,873.

Answer:

13/40

Step-by-step explanation:

The period they have played can be divided into 3 parts:

● The time Amy wins

● The time Lily wins

● The time they tie

So the sum of them is the total time of playing.

Let A be the time Amy wins, L the tile Lily wins and T the time they tie .

●●●●●●●●●●●●●●●●●●●●●●●

Since we have expressed the times using fractions then the total period of playing is 1 wich is 100%.

So:

A + P + T = 1

3/8 + 3/10 + T = 1

Multiply 8 by 10 and 10 by 8 so that you get a common denominator.

Cross multiply the numerators and the denominators.

(3*10+3*8)/80 + T = 1

(30 + 24)/80 + T =1

54/80 + T = 1

(27*2)/(40*2) + T = 1

Simplify by 2

27/40 + T = 1

T = 1 - 27/40

Multiply one by 40 to get a common denominator

T = (40-27)/40

T = 13/40

So they have tied 13/40 of the time

Answer:

108 m

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

f(x) = 4 ^ ( x-2)

Let x=3

f(3) = 4 ^ ( 3-2)

       = 4 ^ 1

       = 4

Answer:

4

Step-by-step explanation:

4^(x - 2)

Plug x as 3.

4^(3 - 2)

Subtract.

4^(1)

4^1 = 4