Hayami was riding her bike on a loop that is 15/16 mile long. she rode for 3/4 mile and then stopped to rest she rode another 1/8 mile and then has a flat tire. how far does Hayami have to walk her bike to complete the loop?

A.1/16 mile
b.1/32
c. 3/16
d. 1/8

Answers

Answer 1

1/16 mile

3/4 = 12/16

1/8 = 2/16

12/16 + 2/16 = 14/16

1/16 Mile left to walk

Answer 2

Hayami has to walk her bike Option A) 1/16 mile to complete the loop.

Hayami rode a total of 3/4 + 1/8 = 7/8 mile before getting a flat tire. To complete the loop, she needs to cover the remaining distance of the loop, which is

= 15/16 - 7/8

= 15/16 - 14/16

= 1/16 mile.

Thus, Hayami has to walk her bike 1/16 mile to complete the loop. Therefore, the correct answer is 1/16 mile.

To find out how far Hayami has to walk her bike to complete the loop, we need to calculate the remaining distance after she rode her bike before stopping for a rest and getting a flat tire.

1. First, we calculate the distance Hayami rode before stopping for a rest:

  She rode 3/4 mile.

2. Then, we calculate the distance she rode after stopping for a rest but before getting a flat tire:

  She rode 1/8 mile.

3. Now, let's find out the total distance she rode:

  = 3/4 + 1/8

  = 6/8 + 1/8

  = 7/8 mile.

4. The length of the loop is \(15/16\) mile.

5. To find the remaining distance to complete the loop, subtract the distance she rode from the total loop length:

  = 15/16 - 7/8

  = 15/16 - 14/16

  = 1/16 mile.

6. Therefore, Hayami has to walk her bike 1/16 mile to complete the loop.

In conclusion, the correct answer is 1/16 mile (Option A).

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Complete Question

Choose the correct answer from the given options:

Hayami was riding her bike on a loop that is 15/16 mile long. she rode for 3/4 mile and then stopped to rest she rode another 1/8 mile and then has a flat tire. how far does Hayami have to walk her bike to complete the loop?

A.1/16 mile

b.1/32 mile

c. 3/16 mile

d. 1/8 mile


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HERE IS YOUR ANSWER MATE

HOPE ITS HELPFUL

HAVE A GREAT FUTURE

LOVE FROM INDIA

Hello haohaoxNienie!

[tex] \huge \boxed{\mathfrak{Question} \downarrow}[/tex]

Show that p(x) = x³ - 6x² + 11x - 6 is divisible by x - 1.

[tex] \huge \boxed{\mathfrak{Explanation} \downarrow}[/tex]

To show that p(x) = x³ - 6x² + 11x - 6 is divisible by x - 1, we must divide the polynomial by x - 1. If we get the remainder as 0, then we can say that p(x) = x³ - 6x² + 11x - 6 is divisible by x - 1.

__________________

So, let's do the division (steps in the attached picture).

__________________

We got the remainder as 0. So, yes p(x) = x³ - 6x² + 11x - 6 is divisible by x - 1.

__________________

More steps :-

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__________________

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