The given statement is false . Halley's comet takes 5 years to complete an orbit.
A comet that shines especially brightly is a superb comet. Big comets typically arrive once every ten years, at random, erratic periods.
This translates to a circumference of the solar orbit of around 7.6 billion miles. The gravitational pull of the planets causes the period to change from appearance to appearance.
Because Halley was the first comet to show astronomers that comets might return to our night skies repeatedly, it is frequently referred to as the most famous comet. The comet's appearances have now been connected by astronomers to observations made more than 2,000 years ago.
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The complete question is
Halley's comet takes 5 years to complete an orbit. true or false.
If a student measures the density of aluminum as 2. 87 g/mL and the actual value is 2. 69 g/mL, what is the student's % error?
If the student measures the density of the aluminum as 2. 87 g/mL and the actual value is the 2.69 g/mL, the student's % error is 6.6 %.
The measures density of the aluminum = 2.87 g/mL
The actual density of the aluminum = 2.69 g/mL
The expression of the percent error is as follows :
% error = (|actual value - measured value | / actual value ) × 100 %
% error = (|2.87 - 2.69 | / 2.69 ) × 100 %
% error = 0.066 × 100 %
% error = 6.6 %
Thus, the percent error is 6.6 %.
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calculate the mole in 4.5 molecules of carbon dioxide
Explanation:
Refer to pic...........
Alaxin (CH)no, is a newly discovered drug for the treatment of malaria. Determine the molecular formula of Alaxin if its relative atomic mass is 284. (H = 1; C = 12; 0 = 16)
Answer:
Explanation:
Empirical formula:
C=5, H=8, O=5
Total mass = 5(12) + 8(1) + 5(16) = 120 + 8 + 80 = 208
Empirical formula mass = 208
Next, we can calculate the molecular formula using the given relative molecular mass and the empirical formula mass.
Relative molecular mass = 284
Empirical formula mass = 208
n = Relative molecular mass / Empirical formula mass
n = 284 / 208
n = 1.365
We need to round off the value of n to the nearest integer.
n ≈ 1
Therefore, the molecular formula of Alaxin is the same as the empirical formula: C5H8O5.
What percent of CuC12 is copper?
Explanation:
e atoms. Putting values in above equation, we get: Hence, the mass percent of copper in copper chloride is 47.23 %.
If you start with 11.78 moles of H₂ and 3.07 moles of CO how many moles
of CH₂OH can be produced?
3H₂ + 2CO → 2CH₂OH
How many grams of phosphorus trichloride will be formed upon a complete reaction of 28.7 g of chloride gas with excess phosphorus.(P4)
The molar mass of phosphorus trichloride is 137.33 g/mol. 28.7 g of chloride gas corresponds to 0.20882 mol.
What is mol ?Mol is an abbreviation for molarity, which is a measure of concentration in a solution. It is expressed as amount of solute (in moles) per litre of solution. Molarity is used to describe the strength of an acid or base, the concentration of a substance in a solution, and the amount of a given substance in a given volume of solution. Molarity is also used in the context of dilution, where a solution of known molarity is used to make a solution of a desired molarity. In this case, the number of moles of solute per litre of solution is used as a measure of dilution.
Therefore, 28.7 g of chloride gas reacts with excess phosphorus to form 0.20882 mol of phosphorus trichloride, or 28.20 g of phosphorus trichloride.
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-Guys I need help asap pls someone
How can acetaminophen cause liver damage
Dr. Ke-Qin Hu, a well-known expert in liver disease and director of UCI Health Liver and Pancreas Services, warns that taking or more four grams of acetaminophen in a 24-hour period could result in severe harm.
How do I find out if my liver is healthy?Proteins, liver enzymes, & bilirubin are just a few of the things that a liver blood test analyzes in your blood. This can aid in examining the condition of your liver and looking for indications of inflammation of damage. Infections with the liver, such as hepatitis B and C, can have an impact on your liver.
What foods promote the restoration of the liver?There are numerous nutrients that include certain elements or antioxidants that have been demonstrated to support liver function. The following are a few examples: grapefruit, berries, cranberries, fatty salmon, olive oil, even cruciferous vegetables as broccoli or Brussels sprouts.
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1. To determine the total magnification of the microscope as you are the power of the eye piece by the power of the _____
To determine the total magnification of the microscope as you are the power of the eye piece by the power of the objective lens.
What is total magnification of the microscope?
Magnification of a microscope refers to the degree of enlargement of an object or specimen viewed through the microscope. It is expressed as a numerical value and represents the ratio of the size of the image seen through the microscope to the size of the actual object.
The total magnification of a microscope is calculated by multiplying the magnification of the objective lens by the magnification of the eyepiece. The magnification of the objective lens is determined by the lens itself and is usually marked on the lens, whereas the magnification of the eyepiece is typically 10x.
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Which calculation determines power?
f t − l b s/ sec sec/ f t − l b s
f t × l b s × sec
sec − l b s/ f t
PLS someone help me
It's important to note that in the International System of Units (SI), the unit of power is watts (W), which is equivalent to joules per second (J/s).
What is Power?
In physics, power is the rate at which work is done or energy is transferred. It is a scalar quantity that measures how quickly work can be done or how quickly energy can be transferred from one system to another. Power is typically measured in watts (W), which are equivalent to joules per second (J/s).
The equation for power is:
Power = Work / Time
where Power is measured in watts, Work is measured in joules, and Time is measured in seconds.
Alternatively, power can be calculated as the product of force and velocity:
Power = Force x Velocity
None of the options you provided are the correct calculation for determining power.
Power (P) is defined as the rate at which work is done or energy is transferred, and it can be calculated using the following formula:
P = W/t
Alternatively, if the force (F) applied to an object is known and the object moves a distance (d) over a period of time (t), then power can be calculated using the following formula:
P = F × d / t
Where P is power (in watts), F is force (in newtons), d is distance (in meters), and t is time (in seconds).
It's important to note that in the International System of Units (SI), the unit of power is watts (W), which is equivalent to joules per second (J/s).
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EMS 4-Corner: Tonight Moon Phase Sentence
Answer:
Tonight it is a Waxing Gibbous Illumination: 70%. The Waxing Gibbous phase is when the lit-up part of the Moon grows from 50.1% to 99.9%. It starts just after the First Quarter Moon and lasts until the Full Moon.
What best describes the interaction described below:
Dodder and shrub. The Dodder plant grows on the shrub. The dodder takes water from the shrub and the branches of the dodder pierce the tissues of the shrub. Eventually the shrub will die.
Group of answer choices
One method of obtaining these nutrients from the shrub is through the branches of the Dodder plant penetrating the tissues of the shrub. This is an illustration of a partnership in which only one creature benefits.
What really is tissue and what does it do?Tissue is a collection of cells with a common structure and function that work as a single unit. The brain give it shape and help it retain heat and energy. ibrocartilage, epithelial tissue, muscle tissue, and nervous tissue are the four different types of tissues.
What do cells in tissue do?Your organism is made up of cells, and tissues are created when groupings of cells carry out similar tasks. Your body consists mostly of four different tissue types: connective, epithelial, muscular, and nervous tissue. Organs are cushioned and joined together by connective tissue. The skin's outer layer is made up of epithelial tissue.
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Given the stock concentration of h2so4 is 15 m, describe how you would create 100 ml of the 3. 0 m h2s04 needed in this lab
To create 100 ml of 3.0 M H2SO4 solution from 15 M stock solution, measure 20 ml of stock concentration and dilute it with distilled water to reach a final volume of 100 ml.
By using the following formula, we can create 100 ml of 3.0 M H2SO4 from a stock concentration of 15 M H2SO4
C1V1 = C2V2
where C1 is the initial concentration,
V1 is the initial volume,
C2 is the final concentration, and V2 is the final volume.
Using this formula, we can calculate the amount of stock solution needed to prepare the desired solution as follows:
C1V1 = C2V2
15 M x V1 = 3.0 M x 100 ml
V1 = (3.0 M x 100 ml) / 15 M
V1 = 20 ml
Hence, to create 100 ml of 3.0 M H2SO4 from a stock concentration of 15 M H2SO4, you need to measure 20 ml of the stock solution and then add enough water to bring the total volume to 100 ml.
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Phosphorus reacts with chlorine gas to produce phosphorus trichloride:
1. Write the chemical equation and balance
2. How many moles of chlorine gas are required to produce 17 moles of PCI3 ?
Answer:
1. P4 + 6Cl2 → 4PCI3; already balanced
2. 25.5 moles Cl2
Explanation:
1. The chemical equation for the reaction of phosphorus with chlorine gas to produce phosphorus trichloride is:
P4 + 6Cl2 → 4PCI3
The equation is already balanced
2. The equation shows that 6 moles of chlorine gas are required to produce 4 moles of phosphorus trichloride.
set up a proportion:
6 moles Cl2 / 4 moles PCI3 = x moles Cl2 / 17 moles PCI3
solve for x:
x = (6 moles Cl2 / 4 moles PCI3) x 17 moles PCI3
x = 25.5 moles Cl2
Therefore, 25.5 moles of chlorine gas are required to produce 17 moles of phosphorus trichloride.
Answer:
25.5 moles of Cl₂ required
Explanation:
2P + 3Cl₂ --> 2PCl₃
Since, the stoichiometry (molar ratio) of the reaction is 2 : 3 : 2,
thus, number of moles of Cl₂ = 3/2 × number of moles of PCl₃
∴ number of moles of Cl₂ required is 25.5 moles
Identify the statements that accurately describe the structure of the pyruvate dehydrogenase (pdh) complex. Select all that apply.
The PDH complex is composed of five different enzymes and three different cofactors.
The PDH complex is located in the mitochondrial matrix
The PDH complex links the metabolic pathways of glycolysis and the citric acid cycle.
The correct options are a, b and c.
PDH is made up of five separate enzymes and three different cofactors. These enzymes and cofactors collaborate to convert pyruvate into acetyl-CoA, a molecule capable of entering the citric acid cycle.
The PDH complex is found in the mitochondrial matrix, which is the mitochondria's innermost compartment. Here is also where the citric acid cycle occurs.
The PDH complex connects the glycolysis and citric acid cycle metabolic processes. Glycolysis converts glucose to pyruvate, which the PDH complex subsequently converts to acetyl-CoA. The citric acid cycle then uses acetyl-CoA to create energy in the form of ATP.
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The probable question may be:
Identify the statements that accurately describe the structure of the pyruvate dehydrogenase (pdh) complex. Select all that apply.
a) The PDH complex is composed of five different enzymes and three different cofactors.
b) The PDH complex is located in the mitochondrial matrix
c) The PDH complex links the metabolic pathways of glycolysis and the citric acid cycle.
How it is easier to break an N-H bond and N-O bond than it is to break a N2 bond
It is easier to break the N-H bond and the N-O bond than it is to break the N₂ bond as the triple bond is the strongest bond as compared to the single bond.
The Bond length reduces as the bond strength will increases, the single bonds will breaks more quickly than the double and the triple bonds. The triple bond has the stronger bond strength and the shorter bond lengths than the single and the double bonds.
Thus, it is easier to the the N-H bond and the N-O bond as compared to the N₂ bond or the N ≡ N.
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What mass of iron (III) hydroxide precipitate can be produced by reacting 75.0 mL of 0.105 M iron (III) nitrate with 125 mL of 0.150 M sodium hydroxide?
Explanation:
Refer to pic above.........
The amount of iron (III) hydroxide that can be produced by the reaction of 75.0 mL of 0.105 M iron (III) nitrate with 125 mL of 0.150 M sodium hydroxide is 0.841 g.
Explanation:This problem can be solved using stoichiometry. The balanced reaction is: Fe(NO₃)₃ + 3 NaOH -> Fe(OH)₃ + 3 NaNO₃. This tells us that one mole of iron (III) nitrate reacts with three moles of sodium hydroxide to produce one mole of iron (III) hydroxide.
First, we need to convert the volumes of the solutions to moles using their molarities. So, for iron (III) nitrate: (0.105 moles/L) x (0.075 L) = 0.007875 moles, and for sodium hydroxide: (0.150 moles/L) x (0.125 L) = 0.01875 moles.
Iron (III) nitrate and sodium hydroxide react in a 1:3 ratio. Here, sodium hydroxide is in excess and iron (III) nitrate is the limiting reagent, as (0.01875 moles)/(3) > 0.007875 moles. So, the amount of iron (III) hydroxide formed will be equal to the amount of iron (III) nitrate used.
The molar mass of iron (III) hydroxide is 106.87 g/mol. Therefore, the mass of iron (III) hydroxide precipitate is: (0.007875 moles) x (106.87 g/mol) = 0.841 g.
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How much silver phosphate is produced if 15.5 grams of silver acetate are reacted with excess sodium phosphate?
15.5 grams of silver acetate reacted with excess sodium phosphate will produce 39.1 grams of silver phosphate.
What is the balanced chemical equation?The balanced chemical equation for the reaction between silver acetate and sodium phosphate is:
AgC2H3O2 + Na3PO4 → Ag3PO4 + 3NaC2H3O2
From the equation, we can see that one mole of silver acetate (AgC2H3O2) reacts with one mole of sodium phosphate (Na3PO4) to produce one mole of silver phosphate (Ag3PO4).
To calculate the amount of silver phosphate produced, we need to first determine the number of moles of silver acetate present in 15.5 grams of the compound.
We can use the molar mass of silver acetate (calculated as the sum of the atomic masses of its constituent elements) to convert from grams to moles:
Molar mass of AgC2H3O2 = 107.87 + 24.02 + 3(12.01) + 2(1.01) + 2(16.00) = 166.12 g/mol
Number of moles of AgC2H3O2 = 15.5 g / 166.12 g/mol = 0.0934 mol
Since there is excess sodium phosphate in the reaction, all of the silver acetate will react. Therefore, the number of moles of silver phosphate produced will be equal to the number of moles of silver acetate:
Number of moles of Ag3PO4 = 0.0934 mol
Finally, we can use the molar mass of silver phosphate to convert from moles to grams:
Molar mass of Ag3PO4 = 108.00 + 3(31.00) + 4(16.00) = 418.00 g/mol
Mass of Ag3PO4 produced = 0.0934 mol x 418.00 g/mol = 39.1 g
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If the goalkeeper exerts a 20 N force on the puck, what force does the puck exert on the goalkeeper?
The puck exerts an equal force of 20 N back on the goalkeeper.
The puck exerts a force less than 20 N.
The puck exerts a force greater than 20 N.
During every action, there's an opposite and equal response, states Newton's third rule of motion. The goalie experiences a force of 20 N in return from the puck. The best choice is A.
What in science is a force?That term "force" has a specific meaning in science. At this point, describing a force as being pushed or pulled is perfectly appropriate. It is not possible for a force to "be in it" and "be held by" a thing.
What exactly are force as well as its unit?Force is indeed a physical factor that alters or has the potential to alter an object's state of rest and motion as well as its form. Newton is the SI unit of force.
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The Complete Question :
If the goalkeeper exerts a 20 N force on the puck, what force does the puck exert on the goalkeeper?
A. The puck exerts an equal force of 20 N back on the goalkeeper.
B. The puck exerts a force less than 20 N.
C. The puck exerts a force greater than 20 N.
If 2.19 moles of chlorine gas is trapped over water at 754 mmHg and 21°C, calculate the volume of the gas collected.
Answer:
V = 0.0506 m^3
Explanation:
PV = nRT
V = (nRT) / P
V = (2.19 mol * 8.31 J/(mol·K) * 294.15 K) / 100000 Pa
Find and calculate the heat released using the following equation.
Q = (451 g)(4.18 J/(g·°C)(18 degrees)
q = mCΔT
m– mass of water in grams (g)
C– specific heat capacity, in this case of liquid water [4.18 J/(g-°C)]; a subscript may be added to C to note the type of fluid
ΔT– temperature change of the water (°C)
(I've gathered the data for the equation, I just need help solving it if anyone would be nice enough to lend a quick hand with it. Thank you in advance.)
According to the given data, by using formula q = mCΔT, the heat released is approximately 34,534.68 J.
What is a heat?Heat is the interchange of "thermal" energy caused by a temperature difference. Think about an isolated system with two subsystems that are originally operating at two different temperatures. Energy is moved from the subsystem 2 with a greater temperature to the subsystem 1 with a lower temperature.The energy that results to the movement of molecules and atoms in a material is known as thermal energy, also known as heat. These particles get hotter as they travel more quickly. The thermal energy of the ground is known as geothermal energy. Energy that is held in motion is called motion energy.
Using the given formula:
Q = (451 g)(4.18 J/(g·°C)(18 degrees)
Q = (451 g) x (4.18 J/(g·°C)) x (18°C)
Q = 34,534.68 J
Therefore, the heat released is approximately 34,534.68 J.
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HELP WILL GIVE BRAINLIEST
I’m confused pls help mee(solving the water equation)
Answer:
Excess lemon juice: 162.25 - 92.54 = 69.71
Excess water: 910.08 - 169.55 = 740.53
Explanation:
Excess reactant #2: Water
158.32 x 1/215 x 2/2 x 230.25 = 169.55 g water
Excess lemon juice: 162.25 - 92.54 = 69.71
Excess water: 910.08 - 169.55 = 740.53
How could you describe, in three different ways, the reaction that occurs when heating magnesium and oxygen to form magnesium oxide
Answer:
For example, when magnesium reacts with oxygen to form magnesium oxide, the magnesium atom loses two electrons to form the Mg2+ cation, which has electronic configuration 2,8. The oxygen atom gains these electrons to form the O2– anion, with electronic configuration 2,8.
How many grams of phosphorus trichloride will be formed upon a complete reaction of 28.7 g of chloride gas with excess phosphorus.(P4)
According to the stoichiometry of the given chemical equation, 37 grams of phosphorus trichloride will be formed upon a complete reaction of 28.7 g of chloride gas with excess phosphorus.
What is stoichiometry?It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.
426 g chlorine gives 549.32 g PCl₃ thus for 28.7 g chlorine will give 28.7×549.32/426=37 g.
Thus,37 grams of phosphorus trichloride will be formed upon a complete reaction of 28.7 g of chloride gas with excess phosphorus.
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START
What is the
mass of 2.75
moles of CO₂?
The mass of 2.75 moles of CO2 is approximately 121.03 grams.
What is the mass of 2.75 moles of CO₂?To calculate the mass of 2.75 moles of CO2, we need to use the molar mass of CO2.
The molar mass of CO2 is approximately 44.01 g/mol (12.01 g/mol for carbon + 2x 16.00 g/mol for oxygen).
To calculate the mass of 2.75 moles of CO2, we can use the following formula:
mass = moles x molar mass
Substituting the given values, we get:
mass = 2.75 moles x 44.01 g/mol
mass = 121.0275 g
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The frequency of a FM radio station is 96.3 MHz. What is the wavelength (in meters)?
2.90 × 104 m
0.324 m
3.15 × 106 m
3.11 m
The frequency of a FM radio station is 96.3 MHz.The wavelength of the FM radio station is approximately 3.11 meters.
What is wavelength ?
Wavelength is a physical quantity that measures the distance between two successive points on a wave that are in phase with each other. In other words, it is the distance between two identical points on the wave, such as the distance between two peaks or two troughs.Wavelength is usually denoted by the Greek letter lambda (λ) and is typically measured in meters (m) or some multiple or fraction of meters, such as nanometers (nm) or micrometers (μm).Wavelength is an important characteristic of waves, whether they are electromagnetic waves such as light or radio waves, or mechanical waves such as sound waves. It is closely related to other wave properties such as frequency, amplitude, and wave speed, and can be used to describe and analyze many different types of wave phenomena.The formula to calculate the wavelength of a wave is:
wavelength = speed of light / frequency
where the speed of light is approximately 3.00 × 10^8 meters per second.
Using this formula, we can calculate the wavelength of the FM radio station:
wavelength = 3.00 × 10^8 / 96.3 × 10^6
wavelength = 3.11 meters
Therefore, the wavelength of the FM radio station is approximately 3.11 meters. Answer: 3.11 m.
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MgCl2 is electrolyzed to produce Mg and Cl2. 1311 g of MgCl2 decomposed, what is the percent yield for this reaction if 246.43 g of magnesium are recovered ?
PLEASE HELP
***write a balanced equation
The percent yield of MgCl2 is calculated as follows: (35.8 g/45.56 g) * 100% = 78.58% per mass. The actual yield od MgCl2 is 35.8 g.
MgCl2 is it a salt?The chemical formula of magnesium chloride, or MgCl2, is one magnesium & two chloride ions. It is a salt (compound). MgCl2(H2O)x is the formula for its different hydrates. As an alloying agent and for catharsis.
MgCl2 - Is it a gas?MgCl2, a solid white substance. The direct mixing of dry chlorine and magnesium results in the unknown hydrate (hexagon shaped; r.d. 2.32; p.p.m. 714°C; b.p. 1412°C): Mg(s)+Cl2(g) = MgCl2 (s) As a component of carnallite (KCl), the substance also naturally exists.
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4Al + 3O2 -> 2Al203
How many moles of aluminum oxide can be produced from 24 grams of oxygen gas?
Answer: 0.5 moles of aluminum oxide can be produced from 24 grams of oxygen gas.
Explanation:
balanced chemical equation for the reaction between aluminum and oxygen is:
4Al + 3O2 → 2Al2O3
moles of O2 = mass / molar mass = 24 g / 32 g/mol = 0.75 mol
moles of Al2O3 = (2/3) * moles of O2 = (2/3) * 0.75 mol = 0.5 mol
Therefore, 0.5 moles of aluminum oxide can be produced from 24 grams of oxygen gas.
30. 0 ml of pure water at 282 k is mixed with 50. 0 ml of pure water at 306 k. What is the final temperature of the mixture?
The mixture's final temperature is roughly 293.67 K. At this temperature, all of the components in the combination have an equal distribution of the heat energy present in the system.
The temperature that a mixture of two or more substances will achieve once they have been blended and given time to reach thermal equilibrium is known as the "final temperature". At this temperature, all of the components in the combination have an equal distribution of the heat energy present in the system. The principles of thermodynamics, such as the conservation of energy and the specific heat capacities of the constituent substances, can be used to compute the final temperature. For designing heating and cooling systems, processing materials, and studying chemical reactions, among other scientific and engineering applications, the end temperature is a crucial element to consider. Solving for :
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please help me on my research
about of henry moseley (1887-1915
please help me
G). Personal life
- What were his views on politics, religion, education, music, etc.
- Did he live by a certain life philosophy?
- Did he have a motto that he lived by?
Posoned
- From your reading and research, is there anything interesting about what he/she said, did or
wrote that stood out about this person.
H). Academic and Scientific Awards
-Did he receive any awards for any of his work?
I). Scientific Career
-Where did he work?
- How long did he spend working there?
- Did he publish any research work? On what?
J. Contribution to Chemistry
- What were his contributions specifically to the Field of
Answer:
Henry Mosley was an influential figure in the early 20th century, and his life and work had a lasting impact on the world. He was born in 1885 in Manchester, England, and was the son of a cotton mill worker. He attended Manchester Grammar School, where he excelled academically and was awarded a scholarship to study at the University of Manchester. After graduating with a degree in mathematics, he went on to pursue a career in economics.
Mosley was an advocate of free trade and a strong believer in the power of the market to create wealth and prosperity. He was a vocal critic of the British government’s protectionist policies, which he believed were stifling economic growth. He argued that free trade would lead to increased competition, which would in turn lead to lower prices and higher wages for workers. He also argued that free trade would lead to increased investment in industry, which would create more jobs and stimulate economic growth.
Mosley was a strong proponent of the Labour Party, and he was elected to Parliament in 1918. He served as a Member of Parliament for Smethwick from 1918 to 1924, and then again from 1929 to 1931. During his time in Parliament, he was an outspoken critic of the Conservative government’s policies, particularly their protectionist policies. He also advocated for increased social welfare spending and the nationalization of certain industries.
Mosley was a passionate advocate for social justice and economic equality. He was a strong supporter of the Trade Union movement, and he believed that workers should have the right to collective bargaining. He also argued that workers should be given a living wage, and that employers should be held accountable for their actions.
Mosley was also an advocate for international peace and cooperation. He was a founding member of the League of Nations, and he served as its president from 1920 to 1923. During his tenure as president, he worked to promote international cooperation and peace between nations. He also worked to promote disarmament and international arbitration as a means of resolving disputes between nations.
Mosley’s legacy is one of dedication to social justice and economic equality. His work helped to shape the modern world, and his ideas continue to influence policy makers today. His commitment to free trade, social welfare spending, collective bargaining rights, and international peace are all still relevant today. His life and work serve as an example of how one person can make a difference in the world.
Explanation:
3. What will be the final volume of a 3. 50 L sample of nitrogen at 20. 0 °C if it is heated to 200. °C?
4. The volume of a gas decreased from 2. 40 L to 830. ML and the final temperature is set at 40. 0 °C. Assuming a constant pressure, calculate the initial temperature of the gas in kelvins.
5. A sample of helium gas at 1. 40 atm is heated from 23. 0 °C to 400. 0 K. How many atmospheres is the final pressure of the helium gas?
6. A sample of hydrogen gas is added in a 5. 80 L container at 56. 0 °C. How many moles of the gas are present in the container if the pressure is 6. 70 atm?
7. What is the pressure in a 26. 0 L container with 5. 40 moles of nitrogen dioxide if the temperature is 64. 0°C?
8. A 3. 7 L gas sample, initially at STP, is heated to 280. °C at constant volume. Calculate the final pressure of the gas in atm.
9. Use kinetic molecular theory to relate (translational) kinetic energy to temperature.
10. A flask is charged with 0. 100 mol of A and allowed to react to form B according to the hypothetical gas-phase reaction A(g) ¡ B(g). The following data are collected:
Time (s) 0 40 80 120 160 Moles of A 0. 100 0. 067 0. 045 0. 030 0. 020
11. For each of the following gas-phase reactions, indicate how the rate of disappearance of each reactant is related to the rate of appearance of each product:
(a) C2H5NH2 C2H4 + NH3 (b) N2 + 3 H2 2 NH3
12. Consider the combustion of H2(g): 2 H2(g) + O2(g) 2 H2O(g). If hydrogen is burning at the rate of 0. 48 mol. L-1/s, what is the rate of consumption of oxygen? What is the rate of formation of water vapor?
13. Consider the combustion of ethylene, C2H4 + 3 O2(g) 2 H2O(g). If the concentration of C2H4 is decreasing at the rate of 0. 036 M/s, what are the rates of change in the concentrations of CO2 and H2O?
3.The final volume of the nitrogen gas is 5.65 L.
4.The initial temperature of the gas was 319 K.
5.The final pressure of the helium gas is 1.90 atm.
6.There are 1.48 moles of hydrogen gas in the container.
7.we get:P = nRT/V = (5.40 mol * 0.08206 L atm/mol
8.The final pressure of the gas is 2.11 atm.
9.The average velocity and kinetic energy of its molecules also decrease.
10. Rate of reaction t = 160 s: rate = -(0.030-0.020)/40 = 0.0025 mol/s
11.Rate of appearance of NH3 = 2 x Rate of the reaction
12.The rate of formation of H2O is equal to the rate of consumption of H2, which is 0.48 mol/L/s.
13.The rate of change in the concentration of CO2 is 0.108 M/s, and the rate of change in the concentration of H2O is 0.072 M/s.
3.To solve this problem, we can use the Ideal Gas Law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.Therefore, we can use the formula V1/T1=V2/T2, where V1 and T1 are the initial volume and temperature, and V2 is the final volume and T2 is the final temperature.
V2 = V1(T2/T1) = 3.50 L * (473 K / 293 K) = 5.65 L
Therefore, the final volume of the nitrogen gas is 5.65 L.
4.Gas Law, which states that PV/T = constant for a given amount of gas. Since the pressure is constant, we can use the formula V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature. Solving for the initial temperature, we get:
T1 = (V1/T1) * (T2/V2) = (2.40 L / 40.0 °C) * (273.15 + 40.0) K / (830. mL / 1000 mL/L) = 319 K
Therefore, the initial temperature of the gas was 319 K.
5.To solve this problem, we can use the formula for the Ideal Gas Law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.Therefore, we can use the formula P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature. Plugging in the values, we get:
P2 = P1(T2/T1) = 1.40 atm * (400.0 K / 296.15 K) = 1.90 atm
Therefore, the final pressure of the helium gas is 1.90 atm.
6.the Ideal Gas Law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. We can assume that the number of moles of hydrogen gas is constant since there is no indication of a chemical reaction. Plugging in the values, we get:
n = PV/RT = (6.70 atm * 5.80 L) / (0.08206 L atm/mol K * 329.15 K) = 1.48 mol
Therefore, there are 1.48 moles of hydrogen gas in the container.
7.To solve this problem, we can use the formula for the Ideal Gas Law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
P = nRT/V = (5.40 mol * 0.08206 L atm/mol
8. PV/T = constant. Since the gas is kept at constant volume, V is constant. so n is constant. At STP, P = 1 atm and T = 273.15 K. Converting the temperature to Kelvin gives 553.15 K for the final temperature. Using the combined gas law, we get:
P₁/T₁ = P₂/T₂
1 atm/273.15 K = P₂/553.15 K
P₂ = 2.11 atm
Therefore, the final pressure of the gas is 2.11 atm.
9.According to kinetic molecular theory, the temperature of a gas is related to its average translational kinetic energy.
10.The rate of the reaction can be calculated using the formula:
rate = -Δ[A]/Δt = Δ[B]/Δt
where Δ[A] is the change in the concentration of A over time Δt, and Δ[B] is the change in the concentration of B over time Δt. Using the data provided, we can calculate the rate of the reaction at different time intervals:
t = 40 s: rate = -(0.100-0.067)/40 = 0.00825 mol/s
t = 80 s: rate = -(0.067-0.045)/40 = 0.0055 mol/s
t = 120 s: rate = -(0.045-0.030)/40 = 0.00375 mol/s
t = 160 s: rate = -(0.030-0.020)/40 = 0.0025 mol/s
11.In the gas-phase reactions (a) C2H5NH2 C2H4 + NH3 and (b) N2 + 3 H2 2 NH3, the rate of appearance of each product is equal to its stoichiometric coefficient multiplied by the rate of the reaction. Therefore:
(a) Rate of disappearance of C2H5NH2 = -1 x Rate of the reaction
Rate of appearance of C2H4 = 1 x Rate of the reaction
Rate of appearance of NH3 = 1 x Rate of the reaction
(b) Rate of disappearance of N2 = -1 x Rate of the reaction
Rate of disappearance of H2 = -3 x Rate of the reaction
Rate of appearance of NH3 = 2 x Rate of the reaction
12.In the combustion of H2(g), 2 H2(g) + O2(g) 2 H2O(g), the balanced equation shows that for every 2 moles of H2 burned, 1 mole of O2 is consumed and 2 moles of H2O are formed. The rate of formation of H2O is equal to the rate of consumption of H2, which is 0.48 mol/L/s.
13.The rate of change in the concentration of CO2 is 0.108 M/s, and the rate of change in the concentration of H2O is 0.072 M/s.
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