gym lockers are to be numbered from 1 through 99 using metal numbers to be nailed onto each locker. how many 7s are​ needed?

The Lateral surface of the triangular pyramid = 6 cm²

The lateral surface of a triangular pyramid is the area of the three triangular surfaces of the triangular pyramid, which excludes the area of the base.

The area of each triangular face = area of triangle = 1/2(base)(height).

Given the following as shown in the diagram:

Height of the triangular face = 7.2 cm

Base length of the triangular face = 5 cm

Lateral surface of the triangular pyramid = 3(1/2 × base × height)

Plug in the values

Lateral surface of the triangular pyramid = 3(1/2 × 5 × 7.2)

Lateral surface of the triangular pyramid = 3(18)

Lateral surface of the triangular pyramid = 6 cm²

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The value of (gof)(-2) for the given values of f(x) and g(x) is 60.

A Composite function may be defined as a function which is formed from the operation of combination of two functions. If f(x) and g(x) are two functions, then the composite functions of the given functions are fog(x) that is f(g(x)) and gof(x) that is g(f(x)).

It is given in the question that f(x) = -2x + 7 and g(x) = x² - 6x + 5.

Now, gof(x) = g(f(x)) = (-2x + 7)² - 6(-2x + 7) + 5

gof(x) = 4x² + 49 - 28x + 12x - 42 + 5

gof(x) = 4x² - 16x + 12

gof(-2) = 4(-2)² - 16(-2) + 12

gof(-2) = 16 + 32 + 12

=>gof(-2) = 60

Therefore, the value of gof(-2) is equal to 60.

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Answer:

The distance would be 118

Step-by-step explanation:

The easiest way I solve the distance between a negative number and a positive number is by adding the negative (but making it a positive) and the positive together. If you add 55 and 63 you would get 118. And 118 is the distance between -55 and 63.

I hope this helps!! :)

Answer
(-3) - (-10) = 7

|7| = 7

7

The statement is false, a counterexample is given by using the numbers 1 and -1.

Here we have the statement:

"The sum of two numbers is always greater than their difference"

So we just need to find two numbers such that the statement is false.

This is really trivial, for example, we can propose the numbers 0 and 0.

The sum gives 0 + 0 = 0

The difference is 0 - 0 = 0

The sum is not greater than the difference.

Now, I will propose a less trivial counterexample, let's use the numbers 1 and -1.

The sum gives 1 + (-1) = 1 - 1 = 0

The difference gives: 1 - (-1) = 1 + 1 = 2

The difference is larger than the sum, so we found a counterexample for the given statement.

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Answer:

5

Step-by-step explanation:

Every number from the absolute sign will be positive.

Answer:The answer would be 8

Step-by-step explanation:You would have to do 8/-2+2 and that would leave you with 8 because -2+2 is 0.

Calculating the numeric value of the given function, it is found that Rob will have $2,603.16 in his account in one year.

To find the numeric value of a function, we replace each instance of the variable by the desired value.

For this problem, the expression for the amount that he has into his account after w weeks is given by:

A(w) = 0.04w² + 45w + 155.

One year has 52 weeks, hence w = 52, and the amount is given finding the numeric value as follows:

A(52) = 0.04(52)² + 45(52) + 155 = $2,603.16.

Rob will have $2,603.16 in his account in one year.

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Answer:

x = -6

Step-by-step explanation:

Distribute where possible

5x - 30 + 8 = 7x - 10

Combine like terms

5x - 22 = 7x - 10

Subtract 7x from both sides and add 22 to both sides

-2x = 12

x = -6

Answer:3/7

Step-by-step explanation:

Answer:

3/7

Step-by-step explanation:

change all denominators to 21

{21 is the lcd of all the numbers)

17/21 x 1= 17/21

1/3 x 7 = 7/21

5/7 x 3 = 15/21

17/21 + 7/21 - 15/21

24/21-5/21

9/21

reduce by three

9/21÷3

3/7

Answer:

n² p²r³

Step-by-step explanation:

n ⋅ n ⋅ p ⋅ p ⋅ r ⋅ r ⋅ r

Write using exponents

There are 2 n terms

n²⋅ p ⋅ p ⋅ r ⋅ r ⋅ r

There are 2 p terms

n² p²⋅ r ⋅ r ⋅ r

There are 3 r terms

n² p²r³

The area of the circular section is 3.14 square units

The given parameters are:

Radius, r = 1 kilometre

Rewrite the above properly as follows

So, we have

r = 1 kilometre

The area of the circular section is:

A = πr^2

So, we have

A = 3.14 * 1^2

Evaluate the exponent

So, we have

A = 3.14 * 1

Evaluate the product

So, we have

A = 3.14

Hence, the area of the circular section is 3.14 square units

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The interval where the function is nonlinear and decreasing is 0 < x < 4

The straight lines on the graph are the intervals where the graph is linear

This means that the straight lines on the graph will not be considered

Considering the curve, the graph decrease from x = 0 to x = 4

This can be rewritten as:

0 < x < 4

Hence, the interval where the function is nonlinear and decreasing is 0 < x < 4

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7.5% = 0.075

0.075 x 123.28 = 9.246

So, the tax will be $9.20.

Total cost would be $132.48.

The value of the Z - Score is a -1.5.

According to the statement

We have to find that the z-score of the company.

So, For this purpose, we know that the

A Z-score is a numerical measurement that describes a value's relationship to the mean of a group of values.

From the given information:

The annual salaries of all employees at a financial company are normally distributed with a mean Mu = $34,000 and a standard deviation Sigma = $4,000.

Then

Let X = annual salaries of all employees at a financial company

And

The z score probability distribution for the normal distribution is given by:

Z - Score = Annual salary - mean / s.d.

Then substitute the values

Z - Score = 28,000 - 34,000/ 4000

Z -Score = -6/4

Z -Score = -1.5.

So, The value of the Z - Score is a -1.5.

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Answer:its a

Step-by-step explanation:

The expression -6/25: 5 2/5 is simplified to -30/675

Ratio can be defined as the comparison of two numbers or elements indicating their sizes in relation.

It is represented using the symbol ':'

Example;

The ratio of 3: 5 is written as 3/ 5

Given the expression;

-6/25: 5 2/5

Convert 5 2/5 into an improper fraction = 27/5

We have

-6/ 25 : 27/ 5

Take the ratio

- 6/ 25 ÷ 27/ 5

Take the inverse of the divisor and multiply

- 6/ 25 × 5/ 27

-30/675

Thus, the expression -6/25: 5 2/5 is simplified to -30/675

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P = 180 - (125 + 30)

P = 180 - 155

P = 25 degrees

Thus :

P = 25/180 n radian

P = 5/36 n

Which mean the first option is the correct answer.

The dimensions of original lawn are a. 4 feet by 4 feet.

As per the equation and information mentioned in question, x represents the dimension of original lawn. The equation in question represents the relation between area of lawn at side of reduced lawn and it's area. We will solve this equation to find the value of x.

[tex](x - 8)^{2} = 144[/tex]

The expression on Left Hand Side is same as [tex](a - b)^{2}[/tex]. We know, on expansion, we write it as [tex]a^{2} + b^{2} - 2ab[/tex]. Thus, new equation will be -

[tex]x^{2} + 8^{2} - 2*x*8 = 144[/tex]

[tex]x^{2} + 64 + 16x = 144[/tex]

[tex]x^{2} + 16x + 64 - 144 = 0[/tex]

[tex]x^{2} + 16x - 80 = 0[/tex]

[tex]x^{2} + 20x - 4x - 80 = 0[/tex]

x (x + 20) -4 (x + 20) = 0

(x + 20) (x - 4) = 0

So, the two values of x that we get are:

x = 4 and -20.

The dimensions of lawn can not be negative. Hence, the value of x will be x.

Therefore, the dimensions of original lawn are a. 4 feet by 4 feet.

The complete question is -

Jillian is trying to save water, so she reduces the size  of her square grass lawn by 8 feet on each side. The area of the smaller lawn is 144 square feet. In the equation [tex](x - 8)^{2} = 144[/tex], x represents the side measure of the original lawn. What were the dimensions of the original lawn?

a. 4 feet by 4 feet

b. 8 + [tex]6\sqrt{2}[/tex] feet by 8 + [tex]6\sqrt{2}[/tex] feet

c. 8 - [tex]6\sqrt{2}[/tex] feet by 8 + [tex]6\sqrt{2}[/tex] feet

d. 20 feet by 20 feet

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Answer:

2,440 acres of old-growth trees.

Step-by-step explanation:

61,000*0.04=2,440

There are 2,440 acres of old-growth trees.

Hope this helps!

Please mark as brainliest if correct!

The expressions that are equivalent to [tex]-24\frac{1}{2} +16.15-4[/tex] are (B)16.15 - 28.5 , (C)-28.5 + 16.15 and (E)[tex]12.15-24\frac{1}{2}[/tex]  .

In the question,

the given expression is [tex]-24\frac{1}{2} +16.15-4[/tex] , solving further we get

= -49/2 + 16.15 - 4       ...(as [tex]24\frac{1}{2} = \frac{49}{2}[/tex]  )

= -24.5 + 12.15

= -12.35

In option(A) we have ,

=[tex]24\frac{1}{2} -16.15+4[/tex]

= 49/2 -16.15 +4

= 24.5 -16.15 +4

= 8.35 + 4

= 12.35

In option(B) we have ,

= 16.15 - 28.5

= -12.35

In option(C) we have ,

= -28.5 + 16.15

= -12.35

In option(D) we have ,

[tex]=-20\frac{1}{2} +16.5[/tex]

= -41/2 + 16.5     ...( as [tex]20\frac{1}{2} = \frac{41}{2}[/tex] )

= -20.5 + 16.5

= -4

In option(E) we have ,

[tex]=12.15-24\frac{1}{2}[/tex]

= 12.15 - 49/2

= 12.15 - 24.5

= -12.35

As we can see that from all the option , only option(B), option(C) and option(E) matches with the given expression .

Therefore , The expressions that are equivalent to [tex]-24\frac{1}{2} +16.15-4[/tex] are (B)16.15 - 28.5 , (C)-28.5 + 16.15 and (E)[tex]12.15-24\frac{1}{2}[/tex]  .

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Answer:

[tex]\sqrt{3}[/tex]

Step-by-step explanation:

[tex]\frac{\sqrt{15} }{\sqrt{5} }[/tex]

to rationalise the denominator multiply numerator/ denominator by [tex]\sqrt{5}[/tex]

= [tex]\frac{\sqrt{15} }{\sqrt{5} }[/tex] × [tex]\frac{\sqrt{5} }{\sqrt{5} }[/tex]

= [tex]\frac{\sqrt{75} }{5}[/tex]

= [tex]\frac{\sqrt{25(3)} }{5}[/tex]

= [tex]\frac{5\sqrt{3} }{5}[/tex]

= [tex]\sqrt{3}[/tex]

Answer:

x=3

Step-by-step explanation:

3x-7=2

  +7  +7

3x=9

Divide by 3.

3x divided by 3 is x.

9 divided by 3 is 3.

x=3

Hope this helps.

The value of equation for x is x > 0.

In mathematics, an equation is a formula that expresses the equality of two expressions by connecting them with the equal sign = .

Now the given equation is,

|5-2x| > 5

To solve for let us take x on one side.

So, Subtracting 5 both the side we get,

|5 - 2x - 5| > 5 - 5

Simplifying we get,

|-2x| > 0

Extracting mod we get,

2x > 0

Now since 2 > 0 which is true,

Thus, x > 0

So, the value of equation for x is x > 0.

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Answer:

i think the answer is 0.00263157895

The regions is represented as :

   A = p - p ∩ q ,  B = p ∩ q  and   C = q - p ∩ q

According to the question we have been given the Venn diagram with two regions p and q.

We need to find the representation of regions A, B and C.

As we can from the diagram,

  region A is the area where the only p statement is there which exclude the B region . That is A is area of difference.

So it can be represented as

                   A = p - p ∩ q

  region B is the intersection of p and q.

So it can be represented by

                  B = p ∩ q

region C is the area where only q statement is there and excludes the intersection region. That is C is area of difference

So it can be represented as

                  C = q - p ∩ q

Hence the regions is represented as

                  A = p - p ∩ q

                  B = p ∩ q

                  C = q - p ∩ q

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For the given systems of equations, we have that:

1) The infinite solutions have the following format: (3y - 12, y, 10y - 31).

2) There is one solution: (1.58, -3.45, 3.89).

3) There is one solution: (3, 2, 4).

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

For item 1, the system is:

From the first equation, we have that:

z = 3x + y + 5.

Replacing on the second equation, we have that:

-4x + 2y + 3x + y + 5 = 17

-x + 3y = 12

x = 3y - 12.

Replacing on the third equation, we have that:

-2x - 4y + 3x + y + 5 = -7

x - 3y = -12

Since x = 3y - 12:

3y - 12 - 3y = -12

0 = 0.

Free variable, hence:

The infinite solutions have the following format: (3y - 12, y, 10y - 31).

For item 2, the system is:

From the first equation:

x = -4 - 5y - 3z.

Replacing on the second equation:

-4 - 5y - 3z + 2y - 3z = 9.

-3y -6z = 13.

3y + 6z = 13.

Replacing on the third equation:

-3(-4 - 5y - 3z) + 2y + 3z = -12

12 + 15y + 9z + 2y + 3z = -12

17y + 12z = -14.

From the second equation, we have that:

z = (13 - 3y)/6.

Hence, replacing on the third again:

17y + 2(12 - 3y) = -14

11y + 24 = -14.

y = -3.45.

z = (13 - 3 x (-3.45))/6 = 3.89.

x = -4 - 5(-3.45) - 3(3.89) = 1.58.

Hence:

There is one solution: (1.58, -3.45, 3.89).

For item 3, the system is:

From the second equation:

z = 5x + 2y - 15.

Replacing on the first:

-4x - 2y + 5(5x + 2y - 15) = 4

-4x - 2y + 25x + 10y - 75 = 4

21x + 8y = 79.

Replacing on the third:

5x - 2y - 3(5x + 2y - 15) = -1

5x - 2y - 15x - 6y + 45 = -1.

-10x - 8y = -46.

Adding both resulting equations, we have that:

11x = 33.

x = 3.

Then

21x + 8y = 79.

63 + 8y = 79

8y = 16

y = 2.

z = 5x + 2y - 15 = 5(3) + 2(2) - 15 = 4.

There is one solution: (3, 2, 4).

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Answer:

[tex] - 2x - h[/tex]

Step-by-step explanation:

We are given a function [tex]g(x)=2-x^2[/tex]. We want to find [tex](g(x+h)-g(x))/h[/tex] To do so, first we need to work out the numerator

[tex]g(x+h)=2-(x+h)^2[/tex]. Therefore

[tex]g(x+h)-g(x)\implies 2-x^2-2xh-h^2-2x-x^2[/tex]

like terms cancel out leaving us with

So,

[tex] \displaystyle\frac{g(x + h) + g(x)}{h} = \frac{ h( - 2x - h )}{h} = \boxed{ - 2x - h}[/tex]

After using distributive property we find the solution of 5 × 198 is 990.

What is Distributive property?

By the rule of distributive property, multiplying the sum of two or more addends by a number gives the same result as when each addend is multiplied individually by the number and the products are added together.

The expression is given as;

5 × 198

Now, By using distributive property we calculate as;

5 × 198 = 5 × ( 200 - 2 )

           = (5 × 200) - (5 × 2)

           = 1000 - 10

           = 990

Hence, After using distributive property we find the solution of 5 × 198 is 990.

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