position in a gravitation field (c)
Answer:
The answer is C. position in a gravity field
When a projectile reaches the highest point the vertical component of the acceleration is:
(A) Less than g (B) Greater than g (C) Positive g (D) Negative g
Answer:
The acceleration is g.
Taking the upward direction as positive
V = Vy y - 1/2 g t^2
Taking the downward direction as positive
V = -V y + 1/2 g t^2
One can choose either direction as positive, but the acceleration is
the same as g (it is g) while the projectile is in the air.
When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). Thus, the correct option is D.
What is Projectile motion?Projectile motion is the motion of an object which is thrown or projected high into the air. After the initial force applied on the object that launches the object, the object only experiences the gravitational force. The object is called a projectile and the path of the object is called trajectory.
When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). When the object achieves highest point, then the vertical acceleration of a projectile is zero meter per second square when it is at the peak of its trajectory motion.
Therefore, the correct option is D.
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What is the pulling force of this train, if its engine provides 4200 kW power and 90 km/h speed?
Answer:
yes by 30
Explanation:
uhnhuh
answer the question below
Answer:
1. Shield volcano
Runny,basaltic magma with low silica and low gas content. Has a broad,low profile.
2. Cinder cone volcano
Thick viscosity andesitic magma with high silica content and high gas content. Rapidly solidifying lava forms high,steep-sided cones.
3. Composite volcano
Medium viscosity rhyolitic magma with medium silicon content and medium gas content.Have flatter domes called cones.
Explanation:
Hope it helps you..
Your welcome in advance..(◍•ᴗ•◍)
physical science 5.03b worksheet
6. A 0.10-kilogram bird is flying at a constant speed of 8.0 m/s. What is the bird’s kinetic energy?
Answer:what is the problems
Explana:
Book A with a mass of 1.00 kg is placed on a horizontal table. Book B with a mass of 0.500 kg is placed on top of book A. What is the magnitude of the normal force exerted on book A by the table?
Answer:
Explanation:
N = mg = (1.00 + 0.500)(9.81) = 14.7 N
The magnitude of the normal force exerted on book A by the table is 14.7 N
ForcesFrom the question, we are to determine the magnitude of the normal force.
The normal force ca be calculated by using the formula
[tex]F_{n} = mg[/tex]
Where [tex]F_{n}[/tex] is the normal force
m is the mass
and g is the gravitational field strength ( g = 9.8 m/s²)
The mass will be addition of the masses since Book B is placed on top of the book.
Thus,
m = 1.00 kg + 0.500 kg = 1.50 kg
Then,
[tex]F_{n} = 1.5 \times 9.8[/tex]
[tex]F_{n} = 14.7 \ N[/tex]
Hence, the magnitude of the normal force exerted on book A by the table is 14.7 N
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The period of rotation of Mars is 1 day and 37 minutes. Determine its frequency of rotation in Hertz.
The frequency of rotation of Mars is 0.0000113 Hertz.
Given the following data:
Period = 1 day and 37 minutes.To find the frequency of rotation in Hertz:
First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.
Conversion:
1 day = 24 hours
24 hours to minutes = [tex]60[/tex] × [tex]24[/tex] = [tex]1440[/tex] minutes
[tex]1440 + 37 = 1477 \; minutes[/tex]
1 minute = 60 seconds
1477 minute = X seconds
Cross-multiplying, we have:
[tex]X = 60[/tex] × [tex]1477[/tex]
X = 88620 seconds
Now, we can find the frequency of rotation of Mars by using the formula:
[tex]Frequency = \frac{1}{Period}\\\\Frequency = \frac{1}{88620}[/tex]
Frequency of rotation = 0.0000113 Hertz
Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.
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A man walks westward on a ship with a speed of 4 km/hr. The ship's propeller drives it 15 km/hr south. What is the actual speed of the man relative to the earth? What is the direction of his velocity?
The actual speed or velocity of the man relative to the earth is 15.52km/hr.
The direction of the man's velocity relation to earth is 75° South of West.
Given the data in the question;
Velocity of man relative to ship; [tex]v_{mrs} = 4 km/hr[/tex] westVelocity of ship; [tex]v_s = 15 km/hr[/tex] southVelocity of the man relative to the earth; [tex]v_E =\ ?[/tex]Direction of the man's velocity; [tex]\theta = \ ?[/tex]To get the velocity of the man relative to the earth. From Pythagorean theorem
We can simply say
[tex]v_E = \sqrt{(v_{mrs})^2 + (v_s)^2}[/tex]
We substitute in our given values
[tex]v_E = \sqrt{(4km/hr)^2 + (15km/hr)^2}\\\\v_E = \sqrt{(16km^2/hr^2) + (225km^2/hr^2})\\\\v_E = \sqrt{241km^2/hr^2}\\\\v_E = 15.52 km/hr[/tex]
Therefore, the actual speed or velocity of the man relative to the earth is 15.52km/hr
To get the direction of the man's speed. From the three main trigonometric ratios: SOH CAH TOA
[tex]tan\theta = \frac{opposite}{adjacent}[/tex]
[tex]tan\theta = \frac{v_s}{v_{mrs}}[/tex]
We substitute in our values;
[tex]tan\theta = \frac{15km/hr}{4km/hr}\\\\tan\theta = 3.75\\\\\theta = tan^{-1}( 3.75)\\\\\theta = 75^o[/tex]
Therefore, the direction of the man's velocity relation to earth is 75° South of West
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Peering through a telescope could be considered Step 1 of the scientific method.
True
False
Two skaters face one another and stand motionless, then push against each other on the ice. If one's mass is 55 kg and he moves to the left after the push at a velocity of 4.3 m/s, how fast was the other skater traveling after the push if her mass was 48 kg.
4.9 m/s to the right
Explanation:
We are going to use the conservation law of linear momentum to find her velocity. Initially, they are motionless so their initial total momentum is zero. Let's assume that anything moving to the left has a negative velocity and anything moving to the right has a positive velocity. We can write the conservation law of momentum as
[tex]0 = M_mv_m + M_wv_w[/tex]
where
[tex]M_m[/tex] = mass of the man = 55 kg
[tex]v_m[/tex] = velocity of the man = -4.3 m/s
[tex]M_m[/tex] = mass of the woman = 48 kg
[tex]v_w[/tex] = velocity of the woman
[tex]\Rightarrow 0 = (55\:\text{kg})(-4.3\:\text{m/s}) + (48\:\text{kg})v_w[/tex]
Solving for [tex]v_w,[/tex]
[tex]v_w = \left(\dfrac{55\:\text{kg}}{48\:\text{kg}}\right)(4.3\:\text{m/s}) = 4.9\:\text{m/s}[/tex]
going to the right.
In the Freebody diagram the magnitude of the normal force is 40 N, the friction force is 25N, the net force is 80N. what is the magnitude of the applied force?
Answer:
Explanation:
Without the FBD or a good description of the set up, I'd have to say we cannot tell.
If the set up is of the simplest form with a mass on a horizontal surface being acted on by a horizontal force, then that force must be 80 + 25 = 105 N.
As force is a vector, there are an infinite number of other possibilities for force magnitude depending on which direction the force is acting. The mass is also an unknown variable that would affect the applied force magnitude if the direction is not horizontal.
For question 51, do you use a=d/t
No. That won't help. It's not even true.
someone pls helpp meeee
Answer:
the first answer is correct
The neurotransmitter acetylcholine:
A. is chemically identical to heroin.
B. is found in all sensory neurons.
C. can cause hallucinations when present in abnormally excessive amounts.
D. is involved in muscle contractions and memory.
Explanation:
A. is chemically identical to heroin.
Which landform is the farthest north?
Helllppppp pleaseeeeee!!!
Would you expect the spectrum of a blackbody radiator to have peaks and valleys like the spectrum of WF4-358? Why or why not? Define blackbody radiators in your answer.
The Planck model for the black body and the emission spectrum of the atoms allows to find the results for the peaks in the spectrum of stars is:
The general shape is that of a black body and the peaks are due to chemical compounds or elements in the star.
The stars are very hot celestial bodies by nuclear fusion processes, in a good approximation they approximate an ideal body that absorbs or emits all the radiation called black body.
A black body is a cavity in thermal equilibrium at a dated temperature with a small hole, this hole is the so-called black body and its emission spectrum was explained by Planck, with the assumption that the energy is
E = h νν
Where h is Planck's constant and ν is the frequency of the radiation. In the attachment we see the emission spectrum of a black body for various temperatures.
If in the material under study we have in addition the emission characteristics of some elements, it is energy appears as peaks in the emission spectrum and as black bands o valley in an absorption spectrum, therefore the existence of the structure is in a test of the existence of chemical elements within the stars.
In the attachment we can see the spectrum of a dwarf star where we can appreciate the spectrum of the black body and the emission and absorption lines of the chemical elements inside the star.
In conclusion using the Planck model for the black body and the emission spectra of the atoms we can find the results for the peaks in the spectrum of stars is:
The general shape is that of a black body and the peaks are due to chemical compounds or elements in the star.
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please can anybody tell me what are these lab equipments
Answer:
5 is the tripoid stand
Thanks have a bangtastic day
Answer:
hii there
5 ) tripod
6 ) test tube holder
Explanation:
Hope it helps
Have a nice day : )
Two rowboats on a lake are lined up, in contact, front to back in the same direction. A passenger in the rear boat pushes the front boat directly forward with a force of 40 N.
How much force does the front boat exert on the rear boat?
A. 0N
B. 20N
C. 40N
D. 80N
The answer is C. 40N.
Which statements describe elliptical galaxies? *Select the two correct answers.*
A. They include the Milky Way.
B. They are the most common galaxy type.
C. They typically contain very little gas and dust.
D. They include the universe's largest galaxies.
Elliptical galaxies are galaxies that are shaped like an ellipse. An ellipse is oval in shape, which means elliptical galaxies are oval in shape.
The two correct statements that describe elliptical galaxies are:
B. They are the most common galaxy type.
C. They typically contain very little gas and dust.
Elliptical galaxies are galaxies where you will find little or no gas and dust. The galaxies that are numerous in number are the elliptical galaxies. In the elliptical galaxy, you can't find any spiral component in it.Therefore, from the above explanation, we can see that option B and C is the correct option.
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The statements which describes elliptical galaxies are Choice B and Choice C:
They are the most common galaxy type.They typically contain very little gas and dust.Elliptical galaxies are the most abundant type of galaxies found in the universe although because of their age and dim qualities, they're frequently outshone by younger, brighter collections of starsElliptical galaxies are characterized by the presence of less gas and dust and as such, new shiny stars are not born and the dim nature of elliptical galaxies can be attributed to this.Ultimately, elliptical galaxies are the oldest and are the most common galaxy type and they typically contain very little gas and dust.
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How does the current in a resistor change if the voltage across the resistor is
increased by a factor of 2?
If the voltage across a resistor is increased by a factor of two, the current in the resistor doubles.
What is ohm’s law?When all physical parameters and temperature are constant, Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
This current-voltage connection may be expressed mathematically as,
The Equation of Ohm's Law;
V∝I
V'∝I'
Hence, if the voltage across a resistor is increased by a factor of two, the current in the resistor doubles.
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How many significant figures are in the following measurements? a. 3000000000 m/sA bike rider accelerates uniformaly at 2.0m/s^2 in 7.0 s. What was the speed of the object after 2.0 seconds?
Answer: 1 sig fig
Explanation: because 0s aren‘t significant and yes decimal points matter but after the decimal it’s a 0. So it is 1. If it was 0.30 it would be 2 sig figs but 0.03 would be one sig fig.
When developing an experimental design, which action could a scientist take to improve the quality of the result?
Answer: You can Identify any biases about the answer to the scientific question.
Explanation:
_____ is to Alzheimer's disease as _____ is to Parkinson's disease.
A. Dopamine; serotonin
B. Serotonin; norepinephrine
C. Acetylcholine; dopamine
D. Norepinephrine; serotonin
Answer:
C. Acetylcholine; dopamine
Acetylcholine is to Alzheimer's disease dopamine as is to Parkinson's disease. That is option C.
Neurological disordersThe neurological disorders are does diseases that affect the nervous system of an individual.
Examples of the neurological disorder include:
Alzheimer's disease: This occurs in individuals that have low levels of the neurotransmitter, acetylcholine. The acetylcholine activates muscles and help in short-term memory, and learning.Parkinson's disease: This occurs in individuals that have low levels of the neurotransmitter, dopamine. Dopamine plays a role in sending messages to the part of the brain that controls movement and coordination.Therefore, Acetylcholine is to Alzheimer's disease dopamine as is to Parkinson's disease.
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một viên đạn được bắn lên với vận tốc v0=800m/s theo phương hợp với mặt phẳng nằm ngang một góc 30 độ. xác định tầm xa của viên đạn
Step 1 First Draw a Diagram.
Step 2 Identify the givens
g= -9.8 m/sec2
x0 = 0 m
Y-Yo= 80m
V0 = 800m/s -30o inclined from horizontal
Xf= ?
t = ?
Step 3 * A 2 dimensional problem so break it down into x component and y component
Step 4 x component
x= [Vox ][cos 30o][t]
x= [800m/s][cos 30o][tsec]
x=[692.8m/s][tsec] <---------------Need t
Step 5 y component
Y-Yo= Voy - 1/2gt2
80m= -[v][sin30o][t] -1/2gt2
1/2gt2+[v][sin30o][t]+80m=0 <-------Form Quadratic Equation
Solve for t
t= -[v sin 30] +/- [(v sin 30)-(4)(1/2)(9.8)(80)]1/2
(2)(1/2)(9.8)
t= 400+/- 398
9.8
t= 0.2 sec
Step 6 Plug this into initial x component equation
x=[692.8m/s][tsec]
a bean is placed evenly on a pivot point (fulcrum) on one side of 10N weight is placed 2m from the pivot and a 40N weight a further 4m from the pivot point. How far from the pivot point must the centre of gravity of an 80N weight placed to perfectly balance the beam horizontally?
Answer:
hope you will understand
Explanation:
PLEASE HELPPPPPPPPPPPPP
Answer: sliding
Explanation:
A snow skier slowing to a stop after skiing down a mountain is an example of sliding friction
Answer:
static friction
Explanation:
how did the Ojibwe protect walleye populations?
a.) they count the total number of walleye eggs that a female lays each year.
b.) did you Spears to catch walleye.
c.) they only fish for walleye at night.
d.) they said a limit on the number and size of Walleye a spearfisher can catch.
The Ojibwe protected walleye populations as D. They said a limit on the number and size of Walleye a spearfisher can catch.
Wisconsin Walleye War was a series of protests regarding the fishing and hunting rights of the Ojibwes. Wisconsin wanted to regulate the rights of the people whenever they went fishing and hunting.
The protest eventually led to the state speaking to the people. This resulted in a resolution that there should be a limit on the number and size of Walleye a spearfisher can catch.
This was necessary in order to preserve the walleye for future generations.
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A physics teacher walks 4 meters East, 2 meters South, 4 meters West, and finally 2 meters North. What is the distance and displacement of this teacher?
Please help meeeee!!!
Answer:
1. Test tube
2. tongs
3.
4. FUNNEL
5.
6.
7. Flask
8. Beaker
9. Bunsen burner
10. Erlenmeyer Flask
11. Molar and pestle
12. Wire gauze
13. Graduated cylinder
14. Test tube rack
15. Pipet
16. Filo
Explanation:
By the time children are five years old:
A. the typical 90-minute sleep cycles of alternating REM and NREM are established.
B. about 50 percent of sleep time is spent in REM sleep and 50 percent is spent in quiet sleep that is very similar to NREM stages 1 and 2.
C. their sleep pattern is characterized by 60-minute sleep cycles, producing up to 13 cycles per day.
D. they will begin to experience their first dreams and nightmares.
Option D is correct. Around the age of five, children begin to experience their first dreams and nightmares
By the time children are five years old, several developments occur in their sleep patterns.
Option A is incorrect because the typical 90-minute sleep cycles of alternating REM (Rapid Eye Movement) and NREM (Non-Rapid Eye Movement) are not yet established at this age.
Option B is also incorrect as the sleep time distribution between REM sleep and quiet sleep (similar to NREM stages 1 and 2) is not necessarily equal at this stage.
Option C is inaccurate because 60-minute sleep cycles producing up to 13 cycles per day do not align with the typical sleep patterns of five-year-olds.
However, option D is correct. Around the age of five, children begin to experience their first dreams and nightmares.
This is an important milestone in their cognitive and emotional development, as it reflects the maturation of the brain regions involved in dreaming and the processing of emotions during sleep.
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