GP Submarine A travels horizontally at 11.0 m/s through ocean water. It emits a sonar signal of frequency f = 5.27× 10³Hz in the forward direction. Submarine B is in front of submarine A and traveling at 3.00 m/s relative to the water in the same direction as submarine A. A crewman in submarine B uses his equipment to detect the sound waves ("pings") from submarine A. We wish to determine what is heard by the crewman in submarine B. (a) An observer on which submarine detects a frequency f' as described by Equation 17.19 ?

Answer:

See answers below

Explanation:

Rate of runner   7 km/hr

Bird   =  28 km/ hr

  TIME bird flies to finish line     7.6 km / 28 km/hr  

         the runner covers distance in this time :

                    7.6 / 28  * 7   km   = 1.9 km

                        this leaves    7.6 - 1.9 km = 5.7 km   to the finish

           .....  the bird turns around

              now the two have a closing speed of 28 + 7 = 35 km/hr to cover

                 this   5.7 remaining km

                       time to meet =  5.7 km / 35 km/hr = .16285 hr

                         so the bird flies at 28 km/ hr for this remaining time

                                       = 4.56 km     added to the original 7.6 km before turning around = 12.16 km

Total time for the runner to finish   7.6 km / 7 km/hr = 1.086 hr

   the bird is flying at 28 km/hr for this entire time = 30. 4 km

Answer: A room lined with soft materials that absorb sound.

Explanation:

Just did it :))

Answer:

When something is heated, its atoms vibrate. If one end of a metal bar is heated, the atoms at that end vibrate more than the atoms at the cold end. The vibration spreads along the bar from atom to atom. ... Metals are good conductors of heat.

Explanation:

Given that,

Electrical energy of the motor = 2280 J

Kinetic energy = 1606 J

Wasted energy in thermal and sound energy = 550 J

To find,

The efficiency of the motor in percent.

Solution,

Efficiency is defined as the ratio of useful output energy to the total energy.

Total energy = 2280 J

Useful energy = 1606 J

[tex]\eta=\dfrac{1606}{2280}\times 100\\\\=70.43\%[/tex]

So, the efficiency of the motor is 70.43%.

Answer:

C. 2.5 N

Explanation:

The sum of downwards moments equals sum of moments upwards

Downwards moments

Moments= Force*distance

               = [10/100 * 2 ] +[20/100*4]

               =[0.1*2] +[0.2*4]

               =[0.2+0.8]

               = 1.0 N

Equate this answer to upward force ;

1.0 N = 0.4 *U

1/0.4 =U

2.5 N =U

Answer:

Speed = 0

Restoring force = maximum

Explanation:

Suppose this situation as a spring with a mass attached to it, that oscilates.

The force that the spring does (the restoring force in this case)  is something like

F = K*L

where K is the constant of the spring, and L is the difference between the length of the spring (stretched) and the length of the spring at rest.

Then, when the harmonic oscillator is at its maximum displacement, L takes its maximum value, which means that at this point the restoring force must also have a maximum.

And for the velocity, at this point we have the maximum displacement, this means that, if the mass was moving to the right, after this point the mass stops going to the right, and then returns to the equilibrium position to the left.

Then the velocity has a change of sign, (like an object that reached its maximum height) this means that at that exact moment, the velocity must be zero.

Then:

Speed = 0

Restoring force = maximum

Explanation:

If acceleration points in the same direction as the velocity, the object will be speeding up. The acceleration points in the same direction as the velocity if the car is speeding up, and in the opposite direction if the car is slowing down.

The force on the bottom of the beaker is 8.31 N.

To calculate the force on the bottom of the beaker we are using the formula,

F = PA

Here we are given,

A = area of the beaker.

To calculate the force we have to calculate the pressure P first.

To calculate the pressure P we are using the formula,

P= ρgh

ρ=  density of water.

g= the acceleration due to gravity.

h=the height of the water.

Now we put the values in the formula, we get,

P= ρgh

Or, P= (1000)×(9.8)×(0.30)

Or, P= 2940 Pa.

From the above calculation we can say that the pressure P= 2940 Pa.

Now we put the values in the force formula,

F=PA

Or, F=  2940×[tex]\pi r^{2}[/tex]

Or, F = 2940×π×(0.03)²

Or, F= 8.31N

From the above calculation we can conclude that, The force on the bottom of the beaker is 8.31 N.

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The rock's speed just before impact is 49 m/s and it will be the maximum speed of the rock.

The velocity of the rock before the impact is the final velocity of the rock and it depends on the initial velocity of the rock, time of motion and acceleration due to gravity.

The speed of the rock before the impact is calculated as follows;

v = u + at

where;

Substitute the given parameters and solve for the final velocity.

v = 0 + 9.8 m/s² x 5 s

v = 49 m/s

Thus, the rock's speed just before impact is 49 m/s and it will be the maximum speed of the rock.

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What must be known to determine the direction of the magnetic force on a charge? Check all that apply.

B- the amount of the charge

E- the strength of the magnetic field

To determine the direction of the magnetic force :

A) The type of the charge.

C) The direction of the magnetic field.

D) The velocity of the charge.

To determine the direction of the magnetic force on a charge is the type of the charge, the direction of the magnetic field, and the velocity of the charge.

The magnetic force, attraction or repulsion that emerges between electrically charged particles since of their movement.

It is the fundamental constrain dependable for such impacts as the activity of electric engines and the fascination of magnets for press.

Thus, the correct answer is A, C and D.

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The wavelength of the displacement amplitudes is 124cm.

Frequency is the distance between two pinnacles (or box) of a wave and is consequently estimated in meters. Because of waves coming in all shapes and sizes, the prefix related with meters can change decisively from km for radio waves, micrometers for noticeable light (albeit frequently given in nanometers), to picometers for gamma beams. Albeit X-beams have numerous useful applications, utilizing them requires alert since openness can cause visual impairment, disease and different wounds. Frequency and recurrence are conversely related so that more drawn out waves have lower frequencies, and more limited waves have higher frequencies.

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Answer:

F = 9.81 [N]

Explanation:

To solve this problem we must use Newton's third le which tells us that the sum of forces on a body that remains static must be equal to one resulting from these forces in the opposite direction.

Let's perform a summation of forces on the vertical axis-y to determine the normal force N.

∑F = 0 (axis-y)

[tex]N - m*g = 0[/tex]

where:

m = mass = 4 [kg]

g = gravity acceleration = 9.81 [m/s²]

[tex]N - (4*9.81)=0\\N = 39.24 [N][/tex]

Now we know that the frictional force can be calculated using the following equation.

f = μ*N

where:

f = friction force [N]

μ = friction coefficient = 0.25

N = normal force = 39.24 [N]

Now replacing:

[tex]f = 0.25*39.24\\f = 9.81[N][/tex]

Then we perform a sum of forces on the X-axis equal to zero. This sum of forces allows us to determine the minimum force to be able to move the object in a horizontal direction.

∑F = 0 (axis-x)

[tex]F-f=0\\F-9.81=0\\F= 9.81[N][/tex]

If the coefficient was smaller, a smaller force (F) would be needed to start the movement, this can be easily seen by replacing the value of 0.25, by smaller values, such as 0.1 or 0.05.

If the coefficient were larger, a larger force would be needed.

Answer:

The distance is now 4d

Explanation:

Mechanical Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = m.a

Where a is the acceleration of the object.

The acceleration can be calculated by solving for a:

[tex]\displaystyle a=\frac{F}{m}[/tex]

Once we know the acceleration, we can calculate the distance traveled by the block as follows:

[tex]\displaystyle d = vo.t+\frac{at^2}{2}[/tex]

If the block starts from rest, vo=0:

[tex]\displaystyle d = \frac{at^2}{2}[/tex]

Substituting the value of the acceleration:

[tex]\displaystyle d = \frac{\frac{F}{m}t^2}{2}[/tex]

Simplifying:

[tex]\displaystyle d = \frac{Ft^2}{2m}[/tex]

When a force F'=4F is applied and assuming the mass is the same, the new acceleration is:

[tex]\displaystyle a'=\frac{4F}{m}[/tex]

And the distance is now:

[tex]\displaystyle d' = \frac{4Ft^2}{2m}[/tex]

Dividing d'/d:

[tex]\displaystyle \frac{d' }{d}=\frac{\frac{4Ft^2}{2m}}{\frac{Ft^2}{2m}}[/tex]

Simplifying:

[tex]\displaystyle \frac{d' }{d}=4[/tex]

Thus:

d' = 4d

The distance is now 4d

T-Bars outside of major construction projects is as supports for a dropped ceiling.

A flat metal plate at the bottom of a ribbed "T"-shaped bar that is driven into the ground. usually used to identify the locations of a water meter pit and chain link fence posts.

Metal bar stock is the same way. Round bar (also known as rod), rectangular bar (including square bar, the exceptional case with equal sides), and hexagonal bar are the three most used shapes (usually called hex bar for short).

Although it might seem out of place at the bar, this metal rail has a useful purpose. A few Reddit users described the purpose of the service bar rail, which separates clients from the area where drinks and employees enter and exit the establishment.

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The relative humidity is thirty-five percent is the data in which the sling psychrometer will record and is denoted as option C.

This is defined as the amount of water vapor which is present in air and is usually expressed as a percentage of the amount needed for saturation at the same temperature.

The instrument known as psychrometer is commonly used by scientist to measure the relative humidity of a given area and it does this by taking both a wet-bulb and a dry-bulb temperature reading which is then used to calculate the relative humidity of the given area.

Thus is done using computation tools or the use of psychrometric chart in other to read the results for the required accuracy needed which therefore makes it the most appropriate choice in this scenario.

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Answer:

True

Explanation:

I just took the test and got 100

The magnitude of the electric field is 3.65×10^5N/C directed radially outward.

R (radius of the solid sphere) = (10cm)( 1m /100cm) = 0.1m

[tex]Q\;(\text{total charge of the solid sphere})=(26\;\mathrm{\mu C})\left(\dfrac{1\;\mathrm{C}}{10^6\;\mathrm{\mu C}} \right)=\textcolor{#ff9c8c}{26\times 10^{-6}\;\mathrm{C}}[/tex]

Since [tex]{r=0.1\;\mathrm{m} < R}[/tex], we can use Equation [tex]E&=\dfrac{Qr}{4\pi \epsilon_0 R^3}\tag{5}[/tex] to find the magnitude of the electric field:

Substitute numerical values:

[tex]E&=\dfrac{(26\times 10^{-6})(0.1)}{4\pi (8.8542\times 10^{-12})(0.4)^3}\\ &={3.65\times 10^5\;\mathrm{N/C}\;\text{directed radially outward}}}[/tex]

Magnitude generally refers to distance or quantity. In comparison to motion, Magnitude defines the size of an entity or its speed when moving.

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Answer: Wave frequency can be measured by counting the number of crests (high points) of waves that pass the fixed point in 1 second or some other time period. The higher the number is, the greater the frequency of the waves. The SI unit for wave frequency is the hertz ( Hz ), where 1 hertz equals 1 wave passing a fixed point in 1 second.

Explanation:

Answer:

Explanation:

∑Fx = 0

F1 + F2 = 0

-12 + 2 = -10

force acting against the block is Fx = 10N to the right.

Force = mass * acceleration

where acceleration = 2.0 meters per second.

                       force = 10 N

                      mass = ??

plugin values into the formula:

10 = mass * 2.0

mass = 10 / 2.0

mass = 5 kg

mass on the block = 5kg.

Answer:

momentum

Explanation:

The net impulse delivered to an object always causes a change in the object's momentum. Hence, option (B) is correct.

The given problem is based on the concept of net impulse. The magnitude of force acting on any object for very short interval of time is known as impulse. In the given problem, the transfer of impulse can be explained by the impulse - momentum theorem.

[tex]F \times t = \Delta P\\\\I= \Delta P[/tex]

Here, I is the impulse.

Thus, we can conclude that the net impulse delivered to an object always causes a change in the object's momentum. Hence, option (B) is correct.

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The back end of the rod moved [tex]1.90\ \mathrm{mm}$[/tex] in this time interval.

Given:

Young's modulus, Y = [tex]20 \times 10^{10}\;N/m^{2}[/tex]

Steel density, [tex]\rho = 7.86 \times 10^{3}\;kg/m^{3}[/tex]

Length of the rod, L = 80 cm = 0.800m

The speed of the wave in the rod is

[tex]$v = \sqrt{\frac{Y}{\rho}} = \sqrt{\frac{20\times 10^{10}\ \mathrm{N/m^2}}{7.86\times 10^3\ \mathrm{kg/m^3}}} = 5044\ \mathrm{m/s}$[/tex]

Hence the time taken by the wave to travel the end of the rod is,

[tex]$t=\frac{L}{v} = \frac{0.800\ \mathrm{m}}{5044\ \mathrm{m/s}} = 1.58\times 10^{-4}\ \mathrm{s}$[/tex]

The velocity of the rod is [tex]$v_r = 12.0\ \mathrm{m/s}$[/tex]

The other end will keep moving after the front end hits the wall until the wave reaches the other end, given the period determined by the above problem.

As a result, before the wave reaches the end of the rod, it has traveled a distance of

[tex]$\Delta L = v_r t = (12.0\ \mathrm{m/s}) (1.58\times\ \mathrm{s}) = 1.90\times 10^{-3}\ \mathrm{m} = 1.90\ \mathrm{mm}$[/tex]

Hence, the [tex]1.90\ \mathrm{mm}$[/tex] at the back end of the rod moved in this time interval.

Young's Modulus is a measurement of the mechanical characteristics of linear elastic solids like rods, wires, and other similar objects. It is also known as the Elastic Modulus or Tensile Modulus. Young's modulus is the most often used measurement of a material's elastic properties; other measurements include bulk modulus and shear modulus. This is so that it can inform us about a material's tensile elasticity (ability to deform along an axis).

The relationship between stress (force per unit area) and strain is described by Young's modulus (proportional deformation in an object). Thomas Young, a British scientist, is honored with the name of the Young's modulus. When a certain load is applied to a solid object, it deforms.

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Answer: friction has no role to play in this case. because friction usually occurs between to parts which come in contacts. examples (a)our joints in the human body (b)two mechanical parts (shafts).

Explanation:

However what this topic relates to is gravity. The pebble and paper both weigh one gram, but have different density this is the sole reason why if both are drop from same height the pebble would reach the ground faster than the paper because it is more denser. unlike the paper with a lesser density which would take a longer time to reach the ground.

How a Inkjet printer uses electrical charges and tiny particles to print the image is discussed below.

We have a Inkjet printer which uses electrical charges and heat to fuse tiny plastic particles (called toner) to the paper.

The sufficiency or deficiency of electrons in a body leads to the development of electric charge in a body. Its unit is Coulomb. It can be either Positive or Negative in nature.

According to the question -

The statement mentioned in the question is true. The inkjet printers use electrical charges and heat to fuse tiny plastic particles (called toner) to the paper. Printers attract toner particles (with the help of electric charge) to a transfer roller. Toner particles are pressed onto a piece of paper, while heat and pressure from the fuser unit permanently fix the image onto the page.

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