Given below are the names of some objects and materials: Water, basket ball, orange, sugar, globe, apple and earthen pitcher Group them as Eatables and Non eatables.​

Your answer is → Mass number

Answer:

In science

Explanation:

When a teacher tells you so use the appropriate figures. He/she means to use the proper amount of Sig figs or Significant digits.

Example: Is the picture

In the example the answer is 7.31 because you have to take the less number of significant digits

Answer:

figures that are relevant or suitable for the question asked

Answer:

A. scatter plot?

Explanation:

I dont really know if I'm right... sorry.

Answer:

Explanation:

Assuming the ground is level as well.

F = ma

a = F/m

a = (2000 - 350) / 1500

a = 1.1 m/s²

The acceleration of the car is 1.1 m/s².

To calculate the magnitude of the acceleration of the car, we use the formula below.

Where:

Make a the subject of the equation

From the equation,

Given:

Substitute these values into equation 2

Hence, the acceleration of the car is 1.1 m/s².

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Answer:

Table C:

Fan Speed Observations of Position vs. Time Graphs

Low:

The slope is curved and it increases as you go up . The points start off close but they spread out as the time increases.

Medium:

The speed increases quicker than the graph for low speed. The graph is less curved than the one for low speed. Also, the points spread out faster than they did for low speed as the time increases.

High:

The Graph has a smaller curve then the low and medium speed. Also, the points are the furthest apart. The slope is not as spaced out as it was for the rest of the speed graphs.

Explanation:

hope it helps

Variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.

Objective: The goal of this lab experiment was to investigate the motion of an item with constant acceleration and to examine its velocity as a function of time.

Materials:

Smooth, inclined plane

Cart or tiny wheeled object

Stopwatches and timers

Measuring tape or meterstick

Procedure:

Set up the inclined plane at a 45-degree angle () to the horizontal surface. Check that the plane is smooth and clear of obstacles.

Place the cart or small wheeled object at the bottom of the inclined plane.

Using a meterstick or measuring tape, determine the height (h) and length (L) of the inclined plane.

Ascertain that the cart is at rest at the starting point, which is located at the bottom of the inclined plane.

As soon as the cart is freed and begins to move, start the stopwatch or timer.

Calculate the time (t) it takes the cart to reach each place along the inclined plane. To ensure reliable data gathering, repeat the experiment numerous times.

Determine the time intervals (Δt) between each position for velocity analysis

Data:

Position (m) Time (s) Time Interval (Δt) (s)

0.0                   0.00           -

0.5                   0.50        0.50

1.0                   0.75        0.25

1.5                    1.10              0.35

2.0                    1.50        0.40

Analysis:

Calculate the average velocity between each position by dividing the position change by the time interval (x/t).

Create a graph that plots average velocity (V_avg) versus time (t).

Results:

A straight line emerges from the graph of average velocity against time, demonstrating that the cart's motion was subject to continuous acceleration along the inclined plane. The slope of the graph reflects the acceleration (a) of the cart.

Conclusion:

The experiment successfully demonstrated motion along an inclined plane with constant acceleration. The graph of average velocity vs time revealed important information about the cart's speed, with a linear relationship suggesting steady acceleration. This experiment emphasizes kinematic principles and the significance of using velocity-time data to understand the motion of objects under constant acceleration.

Hence, variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.

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Answer:

the cardiovascular system

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

Answer:

Option A

Explanation:

N is Chloroplast, P is a large centralized vacuole and R is the cell wall which are found only in plant cells. Hence, the given cell is a plant cell.

S = Rough Endoplasmic Reticulum

P = Vacuole

O = Nucleus

T = Smooth Endoplasmic Reticulum

U = Golgi Apparatus

N = Chloroplast

U = Cell Membrane

M = Mitochondria

R = Cell wall

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

sorry I don't know the answer

(C)

...........................

Answer:

Hope this helps!

Explanation:

Answer:

would it be 2.66666666667 or 2.7

Explanation:

The projectiles launch allows to find the results for the questions of the launch of the bomb are:

     a) The fall time is: t = 10.1 s

     b) The distance traveled is: x = 2.24 10³ m

Projectile launching is an application of kinematics where the acceleration on the x-axis is zero and the acceleration on the y-axis is gravity acceleration.

a) Let's find the time until we reach the ground.

The initial vertical velocity is zero, the initial height is I = 500 m, when reaching the ground its height y = 0.

        [tex]y = y_o + v_o_y - \frac{1}{2} g t^2[/tex]  

        0 = y₀ + 0 - ½ g t²

        t = [tex]\sqrt{\frac{2y_o}{g}[/tex]  

        t = [tex]\sqrt{\frac{2 \ 500}{9.8} }[/tex]  

        t = 10.1 s

b) We look for the horizontal distance traveled.

Let's reduce to the international measurement system (SI).

       v = 800 km / h ([tex]\frac{1000m}{1km}[/tex]) ([tex]\frac{1h}{3600s}[/tex]) = 222.22 m / s

       x = vₓ t

       x = 22.22 10.1

       x = 2.24 10³ m

In conclusion, using the projectile launch relationships, we can find the results for the questions that are:

     a) The fall time is: t = 10.1 s

     b) The distance traveled is: x = 2.24 10³ m

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Answer:

correct answer is A) the height of a wave

Explanation:

i just did the test:)

The amplitude is used represent the height of the wave.

A wave is a disturbance in a medium that carries energy without a net movement of particles. In general, waves are classified into two types as Longitudinal and Transverse

Given is the amplitude of a wave.

Amplitude of a wave is equal to measure of the length of crest or trough. Crest and trough are the points that represents the maximum and minimum displacement of the wave with respect to the reference axis. The crest and the trough points are both at a equal straight line distance from the reference axis. This distance is also called height of the wave. The amplitude is the distance between the centerline and the Crest or trough. The general equation representing the amplitude of wave is x = A sin (ωt + ϕ) or x = A cos (ωt + ϕ) is the formula.

Therefore, the amplitude represents the height of the wave.

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Answer:

If two masses 5.2 kg and 4.8 kg are attached to the ends of inextensible strings passed over a frictionless pulley then the acceleration of system is 0.4 ms-2.

Explanation:

Answer:

One of the most widespread beliefs about fossil fuels — oil, natural gas and coal — is that these substances started out as dinosaurs. There’s even an oil company, Sinclair, that uses an Apatosaurus as its icon. That dino-source story is, however, a myth. What is true: These fuels got their start long, long ago — at a time when those “terrible lizards” still walked the Earth.

Fossil fuels store energy in the bonds between the atoms that make up their molecules. Burning the fuels breaks apart those bonds. This releases the energy that originally came from the sun. Green plants had locked up that solar energy within their leaves using photosynthesis, millions of years ago. Animals ate some of those plants, moving that energy up the food web. Others plants just died and decayed.

Any of these organisms, when they die, can be turned into fossil fuels, notes Azra Tutuncu. She’s a geoscientist and petroleum engineer at the Colorado School of Mines in Golden. But it takes the right conditions, including an oxygen-free (anoxic) environment. And time. A whole lot of time.

The coal we burn today got its start some 300 million years ago. Back then, dinosaurs roamed the Earth. But they didn’t get incorporated into coal. Instead, plants in bogs and swamps died. As this greenery sunk to the bottom of those wet areas, it partially decayed and turned into peat. Those wetlands dried out. Other materials then settled down and covered the peat. With heat, pressure and time, that peat transformed into coal. To extract coal, people now have to dig deeply into the earth.

Ancient living organisms are buried quickly and altered by intense heat and pressure to form fossil fuels. Fossil fuels include solid coal, liquid petroleum, and liquid natural gas.

Source; Goo_gle

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if i was not helpful then i am very sorry

An Excerpt from “Optimism”

by Helen Keller

1 Could we choose our environment, and were desire in human undertakings synonymous with

endowment, all men would, I suppose, be optimists. Certainly most of us regard happiness as

the proper end of all earthly enterprise. The will to be happy animates alike the philosopher, the

prince and the chimney-sweep. No matter how dull, or how mean, or how wise a man is, he feels

that happiness is his indisputable right.

2 It is curious to observe what different ideals of happiness people cherish, and in what singular

places they look for this well-spring of their life. Many look for it in the hoarding of riches, some

in the pride of power, and others in the achievements of art and literature; a few seek it in the

exploration of their own minds, or in the search for knowledge.

3 Most people measure their happiness in terms of physical pleasure and material possession.

Could they win some visible goal which they have set on the horizon, how happy they would be!

Lacking this gift or that circumstance, they would be miserable. If happiness is to be so

measured, I who cannot hear or see have every reason to sit in a corner with folded hands and

weep. If I am happy in spite of my deprivations, if my happiness is so deep that it is a faith, so

thoughtful that it becomes a philosophy of life,—if, in short, I am an optimist, my testimony to

the creed of optimism is worth hearing....

4 Once I knew the depth where no hope was, and darkness lay on the face of all things. Then

love came and set my soul free. Once I knew only darkness and stillness. Now I know hope and

joy. Once I fretted and beat myself against the wall that shut me in. Now I rejoice in the

consciousness that I can think, act and attain heaven. My life was without past or future; death,

the pessimist would say, “a consummation devoutly to be wished.” But a little word from the

fingers of another fell into my hand that clutched at emptiness, and my heart leaped to the

rapture of living. Night fled before the day of thought, and love and joy and hope came up in a

passion of obedience to knowledge. Can anyone who has escaped such captivity, who has felt

the thrill and glory of freedom, be a pessimist?

5 My early experience was thus a leap from bad to good. If I tried, I could not check the

momentum of my first leap out of the dark; to move breast forward is a habit learned suddenly

at that first moment of release and rush into the light. With the first word I used intelligently, I

learned to live, to think, to hope. Darkness cannot shut me in again. I have had a glimpse of the

shore, and can now live by the hope of reaching it.

6 So my optimism is no mild and unreasoning satisfaction. A poet once said I must be happy

because I did not see the bare, cold present, but lived in a beautiful dream. I do live in a

beautiful dream; but that dream is the actual, the present,—not cold, but warm; not bare, but

furnished with a thousand blessings. The very evil which the poet supposed would be a cruel

6) Read the last sentence from the text.

Only by contact with evil could I have learned to feel by contrast the beauty of truth and love and goodness.

Explain how Helen Keller develops this idea in the text. Use specific details to

support your answer.

Answer:

Water

Explanation:

At 0 degrees it's solid...Then it melts into a liquid and at 100 degrees it's gas Simple

Answer:

1. A. 0.4 kg

2. B. A team of players in tug of war pulling on the rope, each team with equal numbers of people pulling with equal strength

3.  If an object is stationary the net force is zero.

3. B. The force of friction on the object is different if it is stationary or not

Explanation:

2. If two tug of war teams were pulling with the same force, neither team would move the rope would be at a stand still.

Answer:

The above person to the right is correct except for Number 2. The answer for that will be a.

Explanation:

Remember that equal is a big hint that the scenario is balanced forces since all forces are canceling out thus the object doesn't move. In a. two people are pulling a wheel barrel on the same side. This means one side has more force than the other hence the wheel barrel moves.

The definition of average acceleration allows to find the result for the average acceleration in the given time interval is:

          [tex]a_{average}= 1.5 \ \frac{m}{s^2}[/tex]

Instantaneous acceleration is defined as the derivative of velocity with respect to time.

           a =   [tex]\frac{dv}{dt}[/tex]

Where a is the acceleration, v the velocity and t the time.

They indicate that the speed of the car is given by the relation.

          v = α t + β t²

With α = 3 m / s and β = 0.1 m / s³

Let's make  the derivative.

           a = α + 2β t

Let's substitute

            a = 3 + 2 0.1 t

Average acceleration is the change in velocity in the time interval.  

          [tex]a_{average} = \frac{\Delta v}{\Delta t }[/tex]

Let's find the velocity at the indicated time.

For t = 5 s

         v₅ = 3 + 0.1 5²

         v₅ = 5.5 m / s

For t = 10 s

          v₁₀ = 3 + 0.1 10²

          v₁₀ = 13 m / s

Let's calculate the average acceleration.

           [tex]a_{average} = \frac{13 - 5.5 }{ 10 - 5 }\\[/tex]

           [tex]a_{average}= 1.5 \ m/s^2[/tex]

In conclusion using the definition of mean acceleration we can find the result for the mean acceleration in the given time interval is:

           [tex]a_{average} =[/tex]  1.5 m / s²

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Answer:

Explanation:

Use kinematic equation v² = u² + 2as

Rearrange for distance

s = (v² - u²) / 2a

Realize that at the top of its flight, the ball has zero velocity and gravity is acting downward in an assumed upward positive reference frame.

s = (0² - 29²) / (2(-9.8))

s = 42.90816...

s = 43 m

As we know,

F= ma

Here,

applied force(f)= mass × acceleration

=80kg×3m/s2

=240kgm/s2

=240N

Answer:

Explanation:

We are not told what angle the pull rope is to any other reference. That could make a huge difference in the result.

If we ASSUME that the rope pulls parallel to the slope

Then , if T is rope tension

                                  F = ma

T - mgsinθ - μmgcosθ = m(0)

                                 T = mg(sinθ + μcosθ)

                                 T = 40(9.8)(sin14 + 0.15cos14)

                                 T = 151.88677... 150 N

If the rope pulls the sled at a positive angle relative to the slope, As one might expect from an adult holding the rope, then the tension will be increased because only the Tension portion parallel to the slope causes motion in that direction, but will be decreased because the Normal force, and therefore the friction force, of the slope on the sled will be decreased.

Explanation:

Rules

A match consists of the best of three games of 21 points.

The player/pair winning a rally adds a point to its score.

At 20-all, the player/pair which first gains a 2-point lead wins that game.

At 29-all, the side scoring the 30th point wins that game.

The player/pair winning a game serves first in the next game.

A badminton match can be played by two opposing players (singles) or four opposing players (doubles).

A competitive match must be played indoors utilising the official court dimensions.

A point is scored when the shuttlecock lands inside the opponent's court or if a returned shuttlecock hits the net or lands outside of the court the player will lose the point.

At the start of the rally, the server and receiver stand in diagonally opposite service courts.

A legal serve must be hit diagonally over the net and across the court.

A badminton serve must be hit underarm and below the server's waist height with the racquet shaft pointing downwards, the shuttlecock is not allowed to bounce. After a point is won, the players will move to the opposite serving stations for the next point.

The rules do not allow second serves.

During a point a player can return the shuttlecock from inside and outside of the court.

A player is not able to touch the net with any part of their body or racket.

A player must not deliberately distract their opponent.

A player is not able to hit the shuttlecock twice.

A 'let' may be called by the referee if an unforeseen or accidental issue arises.

A game must include two rest periods. These are a 90-second rest after the first game and a 5-minute rest after the second game.

According to the picture, the chess piece is the least dense. The correct option is A.

The amount of mass that a substance has in relation to its volume is referred to as its density. It is a measurement of how closely together the molecules or particles are arranged within a given object or material.

Typically, floating objects are less dense than the liquid they are in. The fact that the chess piece is floating on the water suggests that it is less dense than the liquid.

It might be an alternative, though, if the toy soldier is also floating and not submerged. More visual context is necessary for precise determination.

Thus, the correct option is A.

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A system in equilibrium has a moment sum of zero and the sum of upward

forces equal to the sum of the downward forces.

The correct values are;

The x and y component of the reaction at pin B are;

Bₓ = 1471.5 N

[tex]B_y[/tex] = 1103.625 N

The x and y component of the force at pin C are;

Cₓ = 588.6 N

[tex]C_y[/tex] = 220.725 N

Reasons:

The weight of the cylinder, W = 90 kg × 9.81 m/s² = 882.9 N

Considering member AB, gives;

[tex]\sum M_A[/tex] = [tex]B_y[/tex] × 2 - [tex]B_x[/tex] × 1.5 = 0 ⇒ [tex]B_y[/tex] = 0.75·Bₓ

Considering member CB, gives;

[tex]\mathbf{\sum M_C}[/tex] = -[tex]B_y[/tex] × 2 + 882.9 × 2.5 = 0 ⇒ [tex]B_y = \dfrac{882.9 \times 2.5}{2} = 1103.625[/tex]

[tex]B_y[/tex] = 0.75·Bₓ ⇒  [tex]B_x = \dfrac{B_y}{0.75} = \dfrac{1103.625}{0.75} = 1471.5[/tex]

The x and y component of the reaction at pin B are;

Bₓ  = 1471.5 N, [tex]B_y[/tex] = 1103.625 N

[tex]\mathbf{\sum F_y}[/tex] = 0 ⇒ -[tex]C_y[/tex] + [tex]B_y[/tex] - 882.9 = 0 ⇒ [tex]-C_y[/tex] + 1103.625 - 882.9 = 0

[tex]C_y[/tex] = 1103.625 - 882.9 = 220.725

[tex]\sum F_x[/tex] = 0 ⇒ -Cₓ + Bₓ - 882.9 = 0 ⇒ -Cₓ + 1471.5 - 882.9 = 0

Cₓ = 588.6

The x and y component of the reaction at pin C are;

Cₓ = 588.6 N, and [tex]C_y[/tex] = 220.725 N

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Answer:

The brain is a part of the body that is particularly sensitive to high temperature. Hence some ungulates, like the Thomson's gazelle, use a counter-current heat exchanging structure known as the carotid rete to keep the brain cooler than the body.The cooled arterial blood then continues toward the brain.

Answer:

Explanation:

My perdiction was correct. I predicted in Part A that the Kinetic Energy would increase. In Part B I predicted that the potential energy would decrease due to the kinetic energy increasing.