Given: AB || DC, AB CD
DA
Prove: ABC CDA

Given: AB || DC, AB CDDAProve: ABC CDA

Answers

Answer 1
1. AB II DC (given)
2. 3. 4. AB =~ CD (given)
5. ^ABC =~ ^CDA (ASA)

Related Questions

a measurement that can be repeated is said to be and one that is close to the accepted or actual value is

Answers

A measurement that can be repeated is said to be precise and one that is close to the accepted or actual value is approximate.

Given that,
The incomplete statement is given we have to complete the statement.

What is standard measurement?

All over the world, most things are in use as of common quantity, so people all over the world agree that they have to follow a common system of measurement and that the common system of measurement is called standard measurement.

Here,

A measurement that can be repeated is said to be precise values
A measurement that is close to the accepted or actual value is approximate.

Thus, the required words are precise and approximate.

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Solve the system of equations. -5a + 7b = 2 -15a + 21b = 6

Answers

It should be noted that solving the system of equations. -5a + 7b = 2 -15a + 21b = 6 will give 0 and this implies that it has no solution

How to illustrate the information?

It should be noted that we simply want to solve the equations given:

-5a + 7b = 2 ................ i

-15a + 21b = 6 ............. ii

Divide equation ii through by 3. This will give:

-5a + 7b = 6

Therefore, the equations will be:

5a + 7b = 2 ................ i

5a + 7b = 2 ................ ii

Subtract equation ii from i

This will be (5a + 7b = 2) - (5a + 7b = 2) = 0

Therefore, it should be noted that solving the system of equations. -5a + 7b = 2 -15a + 21b = 6 will give 0 and this implies that it has no solution

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Ashley is constructing CD such that CD intersects AB at C and is the segment bisector of AB. Select the relationship that must be true.

A) Point C is equidistant from A and B.

B) Point D is equidistant from A and B.

C) Point A is equidistant from C and D.

D) Point B is equidistant from C and D

Answers

Answer:

Step-by-step explanation:

a,d

Answer:ad

Step-by-step explanation:

ad

What is the value for
y
in the equation
y
=
x
2
when
x
=
3
?

Answers

y = x² = 9
y = 2x = 6

Un granjero coloco una cerca al rededor de su parcela. La parcela mide 10 m de cada lado ya que es un cuadrado. Si puso los postes cada 3/4 de metro ¿cuantos postres coloco?

Answers

Greetings from Brasil...

The total length will be: 10+10+10+10 = 40

and

(3/4)m = 0.75m

Then, Rule of 3:

QTD             m

  1     ------    3/4

  X     ------   40

X = 53.333

Soon 53 posts will be needed

the volume of right circular cylinder a is 22 cubic centimeters. what is the volume, in cubic centimeters, of a right circular cylinder with twice the radius and half the height of cylinder a?

Answers

The new volume of the right circular cylinder is 44 cubic centimeter.

The formula for the volume of the cylinder is given as

         V = Πr^2h              (1)

We have been given that,   V = 22 cubic centimeters

Now we need to find the volume of the cylinder which is denoted by V’ whose,

                  r = 2r

          and, h = h/2

Now putting the required values in equation (1) we get

 V’ = Π(2r)^2(h/2)

 V’ = Π4r^2(h/2)

V’ = 4/2(Πr^2h)

V’ = 2V   [as V = Πr^2h]

V’ = 2*22 cubic centimeter

V’ = 44 cubic centimeter

Hence the new volume of the right circular cylinder is 44 cubic centimeter

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(2am³n) (-3am⁴)



pa sagot. thanks​

Answers

Answer:

if you just want to simplify, -6a^2 m^7 n

Step-by-step explanation:

the perimeters of two squares are in the ratio 2 : 7. What is the ratio of the area of the smaller square to the area of the larger square

Answers

The ratio of the area of the smaller square to the area of the larger square = 4 : 49

Finding the area of a square from the perimeter

Let the perimeter of the small square be [tex]P_1[/tex]

Lethe the perimeter of the large square be [tex]P_2[/tex]

Perimeter of a square = 4 Length

[tex]P_1=4L_1\\\\P_2=4L_2[/tex]

The ratio of the perimeters = 2:7

[tex]\frac{4L_1}{4L_2} =\frac{2}{7} \\\\\frac{L_1}{L_2} =\frac{2}{7}[/tex]

The area of a square = L^2

[tex](\frac{L_1}{L_2} )^2=(\frac{2}{7} )^2\\\\\frac{L_{1} ^{2} }{L_{2} ^{2}} =\frac{2^2}{7^2} \\\\\frac{L_{1} ^{2} }{L_{2} ^{2}} =\frac{4}{49}[/tex]

Therefore, the ratio of the area of the smaller square to the area of the larger square = 4 : 49

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I dont understand this i pick the right ones but it say im wrong can someone correct me??

Answers

Answer: 3,140, 47,035

That should be it I’m pretty sure

Answer:

The two in the middle?

What is the length of the shorter leg?
____________________________
What is the length of the longer leg?
____________________________

Answers

The shorter leg of the right triangle measures 3 units, while the larger lag measures 11 units.

How to get the length of the legs of the triangle?

Here we know that we have a right triangle, and we know that:The hypotenuse measures √130 units.

The perimeter measures 14 + √130 units.

If we define:

x = shorter leg.

y = larger leg.

Then, using the Pythagorean theorem, we can write:x^2 + y^2 = √130^2 = 130

And for the perimeter equation we know that:

perimeter = x + y + √130 = 14 + √130

We can simplify this equation to:x + y = 14Then we have the system of equations:

x^2 + y^2 = 130

x + y = 14

Isolating one variable in the second equation we get.

x = 14 - y

Replacing that in the other equation we get:

(14 - y)^2 + y^2 = 130

Now we can solve this for y.

196 - 28y + y^2 + y^2 = 130

2y^2 - 28y + 196 - 130 = 0

2y^2 - 28y + 66 = 0

y^2 - 14y + 33 = 0

Using Bhaskara's formula we can get:

y = (14 ± √( 14^2 - 4*1*33))/2*1y = (14 ± 8)/2

Now, remember that y is the larger leg of the triangle, then:y = (14 + 8)/2 = 11For the value of x we use:

x = 14 - y = 14 - 11 = 3x = 3the shorter leg of the right triangle measures 3 units, while the larger lag measures 11 units.

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HELP...........................! !

Answers

Answer:

[tex] \sf \large( \frac{2}{5} ) {}^{14} [/tex]

Step-by-step explanation:

=((2/5)^4(2/5)^3)^2

=((2/5^4+3))^2

=((2/5^7))^2)

=(2/5)^14

Find the quotient of 4 4/5 divided 4/5. Explain how you can use the GCF to write your answer I. Simplest form.

Answers

Answer:

5/4 Quotient[24/5] and 6

Step-by-step explanation:

5/4 Quotient[24/5]

Simplify the following:

(4 + 4/5)/(4/5)

Multiply the numerator of (4 + 4/5)/(4/5) by the reciprocal of the denominator. (4 + 4/5)/(4/5) = ((4 + 4/5)×5)/4:

((4 + 4/5)×5)/4

Put 4 + 4/5 over the common denominator 5. 4 + 4/5 = (5×4)/5 + 4/5:

(((5×4)/5 + 4/5) 5)/4

5×4 = 20:

((20/5 + 4/5)×5)/4

20/5 + 4/5 = (20 + 4)/5:

(((20 + 4)/5)×5)/4

20 + 4 = 24:

(24/5×5)/4

24/5×5 = (24×5)/5:

((24×5)/5)/4

((24×5)/5)/4 = (24×5)/(5×4):

(24×5)/(5×4)

(24×5)/(5×4) = 5/5×24/4 = 24/4:

24/4

The gcd of 24 and 4 is 4, so 24/4 = (4×6)/(4×1) = 4/4×6 = 6:

Answer: 6

can someone please anwser (5z+y)/7 (the number values of z and y are in the picture)

Answers

Answer:

2

Step-by-step explanation:

First substitute the values of z and y in the expression.

Use PEDMAS. We have to multiply 5 and 3, which gives 15. Subtract 1 from 15 and then divide the result by 7.

[tex]\sf \dfrac{5z + y}{7}= \dfrac{5*3 + (-1)}{7}\\\\[/tex]

          [tex]\sf = \dfrac{15 - 1}{7}\\\\ = \dfrac{14}{7}\\\\= 2[/tex]

Jillion exercise 5 times a week. She runs 3 miles each morning and bikes in the evening. If she exercises a total of 30 miles for the week, how many miles does she bike each evening?

Answers

3 miles per evening

If she runs 3 miles each morning, that is 15 miles of running per week. So you subtract that 15 from 30, which means she bikes 15 miles per week. Now divide 15 by 5 and the answer is she bikes 3 miles per evening.

Answer: 3 miles

Step-by-step explanation:

Total = 30 miles per week

Weekly runs in the morning= 3*5 = 15 miles per week

Bikes= 30-15 = 15 miles per week

Bikes each day= 15/5 = 3 miles

Joel, Ben, and Luke are each wearing a hat with a number on it. Each person adds the two numbers on the other two hats, giving totals of 11, 17, and 22. What is the largest number on a hat?

Answers

Solving a system of equations, we conclude that the largest number on a hat is 14.

What is the largest number on a hat?

We have 3 hats, each one with a number that we will define as:

x, y, and z.

We know that by adding pairs of these numbers we get 11, 17 and 22, then we can write a system of equations:

x + y = 11

x + z = 17

y + z = 22

Clearly z is the largest number, so we want to find z.

First, we can isolate x on the first equation so we get:

x = 11 - y

Replacing that in the second equation giveS:

x + z = 17

(11 - y) + z = 17

Now our system is:

y + z = 22

(11 - y) + z = 17

Isolating y in the first one we get:

y = 22 - z

Now we can replace that in the other equation:

(11 - (22 - z)) + z = 17

Now we can solve this for z.

11 - 22 + z + z = 17

-11 + 2z = 17

2z = 17 + 11 = 28

z = 28/2 = 14

z = 14

We conclude that the largest number on a hat is 14.

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Given , find the average rate of change of f(x)=[tex]f(x)=\frac{1}{x+5}[/tex] on the interval
[1,1+h]. Your answer will be an expression involving h.
Pls halp

Answers

The average rate of change of function f(x)= [tex]\frac{1}{x+5}[/tex]  on the interval [1,1+h] is [tex]-\frac{1}{36+6h}[/tex]

Given,

The function = [tex]\frac{1}{x+5}[/tex]

We know the average rate of change of the function is [tex]\frac{f(b)-f(a)}{b-a}[/tex]

Where a and b are the intervals

a= 1

b=1+h

f(a) =f(1)= [tex]\frac{1}{1+5}[/tex]

=[tex]\frac{1}{6}[/tex]

f(b)= f(1+h)

=[tex]\frac{1}{1+h+5}[/tex]

=[tex]\frac{1}{6+h}[/tex]

f(b)-f(a)= [tex]\frac{1}{6+h}-\frac{1}{6}[/tex]

[tex]=\frac{6-(6+h)}{6(6+h)} \\=\frac{6-6-h}{36+6h}\\ =-\frac{h}{36+6h}[/tex]

Then,

[tex]\frac{f(b)-f(a)}{b-a} =\frac{-\frac{h}{36+6h} }{1+h-1}[/tex]

[tex]=\frac{-\frac{h}{36+6h} }{h} \\=-\frac{1}{36+6h}[/tex]

Hence, the average rate of change of function f(x)= [tex]\frac{1}{x+5}[/tex]  on the interval [1,1+h] is [tex]-\frac{1}{36+6h}[/tex]

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HELP ME PLEASE I need this rn!!!!! SOMEONE ANYONE PLEASEEEEE
question 4
Jeremy is 80 ft from a wall. Each time he moves toward the wall he reduces his distance from the wall by half. Which graph best models the situation?
the four photos are to this question



question 5
Which expressions describe the end behavior of the graph?
the 5 photo is to this one
Select EACH correct answer.

Answers

Using a geometric sequence, we have that:

Graph 1 models the situation.

The end behavior of the graph is given as follows:

As x decreases, y approaches the line y = 2.

What is a geometric sequence?

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q, hence the second term is the first multiplied by q, the third is the second multiplied by q, and so on.

For item 4, we have that:

The first term is of 80.The common ratio is of 0.5.Hence when x = 2, y = 40, when x = 3, y = 20, and so on.

This means that the first graph is correct.

What is the end behavior of a function?

The end behavior of a function is given by the limits of the function when x goes to infinity.

Hence, from the final graph, we have that:

As x decreases, y approaches the line y = 2. (lim x -> negative infinity = -2).As x increases, y decreases without bound. (lim x -> infinity = - infinity, not an option but just to explain).

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PLSSS HELP ANSWER, THE QUESTION IS IN THE SCREENSHOT

Answers

Let f(x) be the integrand.

[tex]f(-2)=-8 \\ \\ f(0)=0 \\ \\ f(2)=8 \\ \\ f(4)=64 \\ \\ \implies \int^{4}_{-2} x^3 \text{ dx}=\approx \frac{1}{2}(2)[-8+64+2(0+8)] \\ \\ =\boxed{72}[/tex]

The longest side of a triangle is a cm.
The second side is bcm shorter than the first side.
The third side is half as long as the second side.
Write an expression, in its simplest form, for the perimeter of
the triangle

Answers

Answer:

P = 2.5a - 1.5b

Step-by-step explanation:

The sides of the triangle are:

a cm,a - b cm,(a - b)/2 cm.

Its perimeter is the sum of the three sides:

P = a + a - b + (a - b)/2 = 2a - b + 0.5a - 0.5b = 2.5a - 1.5b

Please help and answer the parts A and B

Answers

A> The equation for the line is y = -0.1x + 2600

B> The value of the car is $16,500

From the table, we know that for every 6000 miles added there is a decrease in the value by $600.

A> So it is the function of one order

y = kx + b

25500 = 5000k + b

24800 = 12000k + b

After equating it we get

b = 26000 and k = -0.1

Now put the value of b and k in the equation, and we get

y = -0.1x + 26000

Therefore the equation is y = -0.1 + 26000

B> When we put the value of x = 95000, we get

y = -0.1 × 95000 + 26000

  = 16500

Therefore the cost of the car is $16,500

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You place the following shapes in a bag 5 circles 3 triangles 7 squares and 5 rectangles if you reach in the bag what is the probability you will grab a shape

Answers

Answer:

theres a 25% you will grab an apple (work shape is suppose to be circle)

Step-by-step explanation:

Hope this helps

Altogether, tom and sarah have 32 baseball cards. if sarah has three times as many baseball cards as tom, how many does each of them have

Answers

tom has 8 cards and sarah has  24 cards .

Explain how many  cards sarah and tom has?

tom and sarah total baseball cards =32

sarah has three times as many baseball cards as tom

The 2 equations are

1. sarah + tom = 32

2. sarah = [tex]3 \times tom[/tex]

substitute equation 2 in 1.

[tex]3\times tom +tom= 32[/tex]

4 tom = 32

tom = 32/4

tom = 8 cards

sarah = [tex]3\times tom[/tex]

         = [tex]3\times 8[/tex]

sarah = 24 cards

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1 < x + 4 ≤ 4
please help me it’s due at 3:30

Answers

Answer:

−3 < x ≤ 0

Step-by-step explanation:

1 < x + 4 ≤ 4

Add -4 to all parts

1 + −4< x + 4 + −4 ≤ 4 + −4

Put pairs in bracket to avoid confusion

(1 + −4) < x (+ 4 + −4) ≤ (4 + −4)

−3 < x ≤ 0

Last saturday 16 people worked the at the theater. four people worked the morning shift and 12 worked the evening shift. they earned a total of $1,080.00. what did they earn each?

Answers

Earning of each = $33.75

Let's take the earnings of each person to be x.

Total person working at the theater = 16 + 4 + 12

                                                          = 32

Now the total earnings of the people = 32x

Which is given = $1080

So we get an equation

              32x = 1080

                 x = $33.75

Hence we get the earnings of each person = $33.75

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can someone help me really quick

Answers

Shawn earn 11 per hour.

Hannah travel 25 miles in one gallon of gas.

What is graph?

A graph can be defined as a pictorial representation or a diagram that represents data or values in an organized manner.

given:

According to the graph the y- axis shows the earnings.

So, we have the coordinates are

(1, 11), (2, 22) and (3, 33)

So, Shawn earn = 22 - 11 / 2 -1 = 11 per hour.

Now, in second case

The coordinates are

(3, 75), (5, 125), (6, 150), (10, 250)

So, m= (125 - 75) / (5-3)

m= 50/2

m=25

So, Hannah travel 25 miles in one gallon of gas.

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If 4 is subtracted from the numerator of a fraction, its value becomes 1/3. If 5 is added to the denominator of the original fraction its value becomes 1/2. What is the original fraction. ​

Answers

Answer:

79

Step-by-step explanation:

Let the numerator of the original fraction be 'x' and the denominator be 'y'. So, the original fraction becomes xy

According to the question,

Condition I,

If 4 is subtracted from the numerator of a fraction, its value becomes 1/3.

or,x−4y=13

or,3(x−4)=y

or,y=3x−12

Condition II,

If 5 is added to the denominator of the original fraction, the value becomes 1/2.

or,xy+5=12

or,2x=y+5

Put value of y from equation (i) in equation (ii), we get,

or,2x=(3x−12)+5

or,2x=3x−12+5

or,3x−2x−7=0

∴x=7

Put value of x in equation (i), we get,

or,y=3×7−12

or,y=21−12

∴y=9

So, (x,y) = (7,9)

Therefore, the required original fraction is 79.

1. At 2 p.m., a car is 100 km east of Toronto, driving eastward at 80 km/h. A truck leaves Toronto at 2 p.m. and is driving eastward at 120 km/h. At what time will the truck pass the car? How far east of Toronto will they be when this occurs?

Answers

The time at which the truck will pass the car is 2.5 hours and the distance at which the car and truck meet is 200km.

What is velocity?

Velocity is defined as the ratio of the distance moved by the object at a particular time. The velocity is a vector quantity so it needs both the magnitude and the direction.

Given that at 2 p.m., a car is 100 km east of Toronto, driving eastward at 80 km/h. A truck leaves Toronto at 2 p.m. and is driving eastward at 120 km/h.

The time will be calculated as:-

Relative velocity = Distance / Time

Time = Distance /  Relative velocity

Time = 100 / 120 - 80

Time = 2.5 Hours

Distance of car = Speed x time = 80 x 2.5

Distance of car = 80 x 2.5

Distance of car = 200 Km

Therefore, the time at which the truck will pass the car is 2.5 hours and the distance at which the car and truck meet is 200km.

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What is the value of the expression below when w=7?
w² +3w - 10

Answers

Answer:

The value of the expression is 60.

Answer is 60

Step by step

Substitute 7 in place of variable “w” in the expression

7^2 + (3)(7) - 10

49 + 21 - 10

Answer is 60

What does pin stand for? a. principal investment number b. permission initiating number c. percent increase number d. personal identification number please select the best answer from the choices provided a b c d

Answers

Answer:

The answer is D.

Step-by-step explanation:

Answer:

in this case the answer is D

Step-by-step explanation:

your welcome

Question 2 (1 point)
Given the following points, are lines CD and EF parallel, perpendicular, or neithe
A(1,2) B(3,4) C(5,2) D(8,3) E(3,8) F(-6,5)
a
b
C
parallel
perpendicular
neither?

Answers

Given lines CD and EF are parallel. Therefore answer is (a)

How to find slope of  two lines and check whether they are parallel or perpendicular

Given are two points P (x₁, y₁) and Q ( x₂, y₂)

Then slope of the line  PQ is given by  (y₂-y₁)/(x₂-x₁)

If two lines have slopes m₁ and m₂ respectively

Then the lines are parallel when their slopes are equal i.e. m₁=m₂

and  the lines are perpendicular when m₁*m₂= -1

Given C(5,2), D(8,3),E(3,8) F(-6,5)

Then,

Slope of CD = (3-2)/(8-5)= 1/3

Slope of EF = (5-8) / (-6-3)  = 1/3

Slope of CD=Slope of EF

Therefore CD and EF are parallel

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