The Two examples of contact forces are:
frictional force Contact force.The two examples of non contact forces are:
Gravitational forcemagnetic force.Contact forces happens due to the contact between two objects
Non Contact forces happens because there is no contact between two objects. There is no attraction.
When converted to a household measurement, 9 kilograms is approximately equal to a
Answer:
D) 19.8 lbs
Explanation:
1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.
1kg is also equal to 2.205 lbs. 9*2.205=19.8416
9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system
a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.
This leaves us with 19.8 lbs
chứng minh mặt trời là nguồn gốc của tất cả nguồn năng lượng
An Excerpt from “Optimism”
by Helen Keller
1 Could we choose our environment, and were desire in human undertakings synonymous with
endowment, all men would, I suppose, be optimists. Certainly most of us regard happiness as
the proper end of all earthly enterprise. The will to be happy animates alike the philosopher, the
prince and the chimney-sweep. No matter how dull, or how mean, or how wise a man is, he feels
that happiness is his indisputable right.
2 It is curious to observe what different ideals of happiness people cherish, and in what singular
places they look for this well-spring of their life. Many look for it in the hoarding of riches, some
in the pride of power, and others in the achievements of art and literature; a few seek it in the
exploration of their own minds, or in the search for knowledge.
3 Most people measure their happiness in terms of physical pleasure and material possession.
Could they win some visible goal which they have set on the horizon, how happy they would be!
Lacking this gift or that circumstance, they would be miserable. If happiness is to be so
measured, I who cannot hear or see have every reason to sit in a corner with folded hands and
weep. If I am happy in spite of my deprivations, if my happiness is so deep that it is a faith, so
thoughtful that it becomes a philosophy of life,—if, in short, I am an optimist, my testimony to
the creed of optimism is worth hearing....
4 Once I knew the depth where no hope was, and darkness lay on the face of all things. Then
love came and set my soul free. Once I knew only darkness and stillness. Now I know hope and
joy. Once I fretted and beat myself against the wall that shut me in. Now I rejoice in the
consciousness that I can think, act and attain heaven. My life was without past or future; death,
the pessimist would say, “a consummation devoutly to be wished.” But a little word from the
fingers of another fell into my hand that clutched at emptiness, and my heart leaped to the
rapture of living. Night fled before the day of thought, and love and joy and hope came up in a
passion of obedience to knowledge. Can anyone who has escaped such captivity, who has felt
the thrill and glory of freedom, be a pessimist?
5 My early experience was thus a leap from bad to good. If I tried, I could not check the
momentum of my first leap out of the dark; to move breast forward is a habit learned suddenly
at that first moment of release and rush into the light. With the first word I used intelligently, I
learned to live, to think, to hope. Darkness cannot shut me in again. I have had a glimpse of the
shore, and can now live by the hope of reaching it.
6 So my optimism is no mild and unreasoning satisfaction. A poet once said I must be happy
because I did not see the bare, cold present, but lived in a beautiful dream. I do live in a
beautiful dream; but that dream is the actual, the present,—not cold, but warm; not bare, but
furnished with a thousand blessings. The very evil which the poet supposed would be a cruel
6) Read the last sentence from the text.
Only by contact with evil could I have learned to feel by contrast the beauty of truth and love and goodness.
Explain how Helen Keller develops this idea in the text. Use specific details to
support your answer.
A baseball is hit so that it travels straight upward after being struck by the bat. If its initial velocity is 29 m/s , then what is the maximum height that it will reach?
Answer:
Explanation:
Use kinematic equation v² = u² + 2as
Rearrange for distance
s = (v² - u²) / 2a
Realize that at the top of its flight, the ball has zero velocity and gravity is acting downward in an assumed upward positive reference frame.
s = (0² - 29²) / (2(-9.8))
s = 42.90816...
s = 43 m
The function of which system is to transport food, oxygen and enzymes, etc. to all cells and to remove carbon dioxide and wastes from cells?
Answer:
the cardiovascular system
PHYSICISTS NEEDED, THANK YOU, (10 POINTS)
Answer:
would it be 2.66666666667 or 2.7
Explanation:
I need HELP! IMMEDIATELY!!!
Answer:
Option A
Explanation:
N is Chloroplast, P is a large centralized vacuole and R is the cell wall which are found only in plant cells. Hence, the given cell is a plant cell.
S = Rough Endoplasmic Reticulum
P = Vacuole
O = Nucleus
T = Smooth Endoplasmic Reticulum
U = Golgi Apparatus
N = Chloroplast
U = Cell Membrane
M = Mitochondria
R = Cell wall
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807name a substance which will undergo change E
Answer:
Water
Explanation:
At 0 degrees it's solid...Then it melts into a liquid and at 100 degrees it's gas Simple
What is the most likely reason for some antelope to employ selective brain cooling
Answer:
The brain is a part of the body that is particularly sensitive to high temperature. Hence some ungulates, like the Thomson's gazelle, use a counter-current heat exchanging structure known as the carotid rete to keep the brain cooler than the body.The cooled arterial blood then continues toward the brain.
How did ancient organisms become fossil fuels?
Answer:
One of the most widespread beliefs about fossil fuels — oil, natural gas and coal — is that these substances started out as dinosaurs. There’s even an oil company, Sinclair, that uses an Apatosaurus as its icon. That dino-source story is, however, a myth. What is true: These fuels got their start long, long ago — at a time when those “terrible lizards” still walked the Earth.
Fossil fuels store energy in the bonds between the atoms that make up their molecules. Burning the fuels breaks apart those bonds. This releases the energy that originally came from the sun. Green plants had locked up that solar energy within their leaves using photosynthesis, millions of years ago. Animals ate some of those plants, moving that energy up the food web. Others plants just died and decayed.
Any of these organisms, when they die, can be turned into fossil fuels, notes Azra Tutuncu. She’s a geoscientist and petroleum engineer at the Colorado School of Mines in Golden. But it takes the right conditions, including an oxygen-free (anoxic) environment. And time. A whole lot of time.
The coal we burn today got its start some 300 million years ago. Back then, dinosaurs roamed the Earth. But they didn’t get incorporated into coal. Instead, plants in bogs and swamps died. As this greenery sunk to the bottom of those wet areas, it partially decayed and turned into peat. Those wetlands dried out. Other materials then settled down and covered the peat. With heat, pressure and time, that peat transformed into coal. To extract coal, people now have to dig deeply into the earth.
Ancient living organisms are buried quickly and altered by intense heat and pressure to form fossil fuels. Fossil fuels include solid coal, liquid petroleum, and liquid natural gas.
Source; Goo_gle
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if two masses 5.2kg and 4.8kg are attached to ends of inextensible string passed over a friction less pulley then acceleration of system
Answer:
If two masses 5.2 kg and 4.8 kg are attached to the ends of inextensible strings passed over a frictionless pulley then the acceleration of system is 0.4 ms-2.
Explanation:
Which graph uses bars to show data that are broken into intervals?
O A. Scatter plot
O B. Bar graph
O C. Box-and-whisker plot
O D. Histogram
Answer:
A. scatter plot?
Explanation:
I dont really know if I'm right... sorry.
A toy car on a string is pulled across a table horizontally. The string is at an
angle of 30°. Which is the correct free-body diagram for this situation?
EN
w
w
w
w
А
B
с
D
A. A
ОВ. В
ОО Ο Ο
O C. C
D. D
(C)
...........................
Answer:
Hope this helps!
Explanation:
a father pulls his young daughter on a sled (where the combined mass of his daughter and the sled are 40 kg) with a constant velocity up a snowy hill that is inclined at 14 to the horizontal. a) if the coefficient of kinetic friction between the sled's runners and the snow is 0.15, what is the tension force of the rope on which the father pulls
Answer:
Explanation:
We are not told what angle the pull rope is to any other reference. That could make a huge difference in the result.
If we ASSUME that the rope pulls parallel to the slope
Then , if T is rope tension
F = ma
T - mgsinθ - μmgcosθ = m(0)
T = mg(sinθ + μcosθ)
T = 40(9.8)(sin14 + 0.15cos14)
T = 151.88677... 150 N
If the rope pulls the sled at a positive angle relative to the slope, As one might expect from an adult holding the rope, then the tension will be increased because only the Tension portion parallel to the slope causes motion in that direction, but will be decreased because the Normal force, and therefore the friction force, of the slope on the sled will be decreased.
Lab: Motion with Constant Acceleration Assignment: Lab Report
Write your lab report
Someone please help me do this, ill give brainliest
Answer:
Table C:
Fan Speed Observations of Position vs. Time Graphs
Low:
The slope is curved and it increases as you go up . The points start off close but they spread out as the time increases.
Medium:
The speed increases quicker than the graph for low speed. The graph is less curved than the one for low speed. Also, the points spread out faster than they did for low speed as the time increases.
High:
The Graph has a smaller curve then the low and medium speed. Also, the points are the furthest apart. The slope is not as spaced out as it was for the rest of the speed graphs.
Explanation:
hope it helps
Variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.
Objective: The goal of this lab experiment was to investigate the motion of an item with constant acceleration and to examine its velocity as a function of time.
Materials:
Smooth, inclined plane
Cart or tiny wheeled object
Stopwatches and timers
Measuring tape or meterstick
Procedure:
Set up the inclined plane at a 45-degree angle () to the horizontal surface. Check that the plane is smooth and clear of obstacles.
Place the cart or small wheeled object at the bottom of the inclined plane.
Using a meterstick or measuring tape, determine the height (h) and length (L) of the inclined plane.
Ascertain that the cart is at rest at the starting point, which is located at the bottom of the inclined plane.
As soon as the cart is freed and begins to move, start the stopwatch or timer.
Calculate the time (t) it takes the cart to reach each place along the inclined plane. To ensure reliable data gathering, repeat the experiment numerous times.
Determine the time intervals (Δt) between each position for velocity analysis
Data:
Position (m) Time (s) Time Interval (Δt) (s)
0.0 0.00 -
0.5 0.50 0.50
1.0 0.75 0.25
1.5 1.10 0.35
2.0 1.50 0.40
Analysis:
Calculate the average velocity between each position by dividing the position change by the time interval (x/t).
Create a graph that plots average velocity (V_avg) versus time (t).
Results:
A straight line emerges from the graph of average velocity against time, demonstrating that the cart's motion was subject to continuous acceleration along the inclined plane. The slope of the graph reflects the acceleration (a) of the cart.
Conclusion:
The experiment successfully demonstrated motion along an inclined plane with constant acceleration. The graph of average velocity vs time revealed important information about the cart's speed, with a linear relationship suggesting steady acceleration. This experiment emphasizes kinematic principles and the significance of using velocity-time data to understand the motion of objects under constant acceleration.
Hence, variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.
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Una masa de aire de 20g absorbe 780 cal. Teniendo en cuenta que su temperatura inicial es de 30°C. Calcular la
temperatura que alcanzo al absorber el calor. Ce:0,24 cal/g °C
Answer:
sorry I don't know the answer
Un avión vuela horizontalmente con una velocidad de 800 km/h y deja caer
un proyectil desde una altura de 500 respecto al suelo. a) ¿Cuánto tiempo
transcurre antes de que el proyectil se impacte en el suelo?; b) ¿Qué distancia
horizontal recorre el proyectil después de iniciar su caída?
The projectiles launch allows to find the results for the questions of the launch of the bomb are:
a) The fall time is: t = 10.1 s
b) The distance traveled is: x = 2.24 10³ m
Projectile launching is an application of kinematics where the acceleration on the x-axis is zero and the acceleration on the y-axis is gravity acceleration.
a) Let's find the time until we reach the ground.
The initial vertical velocity is zero, the initial height is I = 500 m, when reaching the ground its height y = 0.
[tex]y = y_o + v_o_y - \frac{1}{2} g t^2[/tex]
0 = y₀ + 0 - ½ g t²
t = [tex]\sqrt{\frac{2y_o}{g}[/tex]
t = [tex]\sqrt{\frac{2 \ 500}{9.8} }[/tex]
t = 10.1 s
b) We look for the horizontal distance traveled.
Let's reduce to the international measurement system (SI).
v = 800 km / h ([tex]\frac{1000m}{1km}[/tex]) ([tex]\frac{1h}{3600s}[/tex]) = 222.22 m / s
x = vₓ t
x = 22.22 10.1
x = 2.24 10³ m
In conclusion, using the projectile launch relationships, we can find the results for the questions that are:
a) The fall time is: t = 10.1 s
b) The distance traveled is: x = 2.24 10³ m
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1. A rocket has a mass of 0.8 kg and an engine that provides 100 N of force. A second rocket is being designed to use the same engine but accelerate at half the rate of the first rocket. What is the mass of the second rocket?
a. 0.4 kg
b. 1.6 kg
c. 2.4 kg
d. 0.8 kg
2. Which of the following would be a situation with unbalanced forces?
a. Two people pulling on the same side of a wheelbarrow
b. A team of players in tug of war pulling on the rope, each team with equal numbers of people pulling with equal strength
c. Two people of opposite sides of a big tire. One pushes the tire and one pulls it with equal force
d. Two people not touching a crate that is sitting stationary.
3. Why is it generally easier to push a heavy object that is already moving instead of the same heavy object that is stationary
a. The force of gravity on the object is different if it is stationary or not.
b. The force of friction on the object is different if it is stationary or not
c. The force of the push on the object is different if it is stationary or not
d. The normal force on the object is different if it is stationary or not.
Thanks In Advance!! (I will mark brainliest) :)
Answer:
1. A. 0.4 kg
2. B. A team of players in tug of war pulling on the rope, each team with equal numbers of people pulling with equal strength
3. If an object is stationary the net force is zero.
3. B. The force of friction on the object is different if it is stationary or not
Explanation:
2. If two tug of war teams were pulling with the same force, neither team would move the rope would be at a stand still.
Answer:
The above person to the right is correct except for Number 2. The answer for that will be a.
Explanation:
Remember that equal is a big hint that the scenario is balanced forces since all forces are canceling out thus the object doesn't move. In a. two people are pulling a wheel barrel on the same side. This means one side has more force than the other hence the wheel barrel moves.
Technician a says that the piston engine starts and stops several times per 2nd technician B says that with the rotary engine each rotor has 3 working chambers so it acts like a 3 cylinder engine while it is at operating
Answer:
Explanation:
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Computes average speed when a person walk for 1 minute at speed of 1.5 m/s and another 1 minute at speed of 3.5 m/s along a straight road
Answer:
2.5 m/s
Explanation:
(60*1.5+60*3.5)/120=2.5
or
(1.5+3.5)/2=2.5
When converted to a household measurement, 9 kilograms is approximately equal to a
Answer:
D) 19.8 lbs
Explanation:
1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.
1kg is also equal to 2.205 lbs. 9*2.205=19.8416
9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system
a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.
This leaves us with 19.8 lbs
What does it mean when my teacher asks me to "use appropriate figures"?
Answer:
In science
Explanation:
When a teacher tells you so use the appropriate figures. He/she means to use the proper amount of Sig figs or Significant digits.
Example: Is the picture
In the example the answer is 7.31 because you have to take the less number of significant digits
Answer:
figures that are relevant or suitable for the question asked
Based on your observations, what can you say about your prediction in Parts A and B above concerning the potential and kinetic energy?
Answer:
Explanation:
My perdiction was correct. I predicted in Part A that the Kinetic Energy would increase. In Part B I predicted that the potential energy would decrease due to the kinetic energy increasing.
A car with a mass of 1500 kg is pulled by a rope that is horizontal to the ground. The tension in the rope is 2000 N and a friction force of 350 N opposes the car's motion. What is the magnitude of the car's acceleration?
Answer:
Explanation:
Assuming the ground is level as well.
F = ma
a = F/m
a = (2000 - 350) / 1500
a = 1.1 m/s²
The acceleration of the car is 1.1 m/s².
To calculate the magnitude of the acceleration of the car, we use the formula below.
F-F' = ma................ Equation 1Where:
F = Tension in the ropeF' = Friction forcem = mass of the cara = acceleration of the carMake a the subject of the equation
a = (F-F')/m................. Equation 2From the equation,
Given:
F = 2000 NF' = 350 Nm = 1500 kgSubstitute these values into equation 2
a = (2000-350)/1500a = 1650/1500a = 1.1 m/s²Hence, the acceleration of the car is 1.1 m/s².
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1. According to the picture, which is the least dense?
O A. the chess piece
O B. the toy soldier
O C. the liquid in the container
O D. There is no way to tell,
According to the picture, the chess piece is the least dense. The correct option is A.
The amount of mass that a substance has in relation to its volume is referred to as its density. It is a measurement of how closely together the molecules or particles are arranged within a given object or material.
Typically, floating objects are less dense than the liquid they are in. The fact that the chess piece is floating on the water suggests that it is less dense than the liquid.
It might be an alternative, though, if the toy soldier is also floating and not submerged. More visual context is necessary for precise determination.
Thus, the correct option is A.
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A car’s velocity as a function of time is given by Vx (t) = α.t + β.t 2 , where α= 3m/s and β= 0.1m/s 3 . Calculate the average acceleration for the time interval
b) t= 5 to t = 10 s
The definition of average acceleration allows to find the result for the average acceleration in the given time interval is:
[tex]a_{average}= 1.5 \ \frac{m}{s^2}[/tex]
Instantaneous acceleration is defined as the derivative of velocity with respect to time.
a = [tex]\frac{dv}{dt}[/tex]
Where a is the acceleration, v the velocity and t the time.
They indicate that the speed of the car is given by the relation.
v = α t + β t²
With α = 3 m / s and β = 0.1 m / s³
Let's make the derivative.
a = α + 2β t
Let's substitute
a = 3 + 2 0.1 t
Average acceleration is the change in velocity in the time interval.
[tex]a_{average} = \frac{\Delta v}{\Delta t }[/tex]
Let's find the velocity at the indicated time.
For t = 5 s
v₅ = 3 + 0.1 5²
v₅ = 5.5 m / s
For t = 10 s
v₁₀ = 3 + 0.1 10²
v₁₀ = 13 m / s
Let's calculate the average acceleration.
[tex]a_{average} = \frac{13 - 5.5 }{ 10 - 5 }\\[/tex]
[tex]a_{average}= 1.5 \ m/s^2[/tex]
In conclusion using the definition of mean acceleration we can find the result for the mean acceleration in the given time interval is:
[tex]a_{average} =[/tex] 1.5 m / s²
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An 80 kg box is accelerated to the right at a rate of 3 m/s2. What is the applied force?
As we know,
F= ma
Here,
applied force(f)= mass × acceleration
=80kg×3m/s2
=240kgm/s2
=240N
1.Which term describes the sum of the number of protons and neutrons in an atom?
Your answer is → Mass number
HELPPP
Which of the following statements about friction is FALSE .
1 ) Friction involves objects that are in physical contact .
2) Friction is less if surfaces are very smooth .
3 ) Friction is always in the direction of the motion .
4) Friction is caused by the uneven surfaces of touching objects
HELP PLEASE
What is the correct definition of amplitude?
A. the height of a wave
B. the distance between two crests or troughs
C. the number of complete waves that pass a point in a second
D. the time it takes for one complete wave to pass a given point
Answer:
correct answer is A) the height of a wave
Explanation:
i just did the test:)
The amplitude is used represent the height of the wave.
What is wave?A wave is a disturbance in a medium that carries energy without a net movement of particles. In general, waves are classified into two types as Longitudinal and Transverse
Given is the amplitude of a wave.
Amplitude of a wave is equal to measure of the length of crest or trough. Crest and trough are the points that represents the maximum and minimum displacement of the wave with respect to the reference axis. The crest and the trough points are both at a equal straight line distance from the reference axis. This distance is also called height of the wave. The amplitude is the distance between the centerline and the Crest or trough. The general equation representing the amplitude of wave is x = A sin (ωt + ϕ) or x = A cos (ωt + ϕ) is the formula.
Therefore, the amplitude represents the height of the wave.
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I have been stuck for 15 minutes!!
Answer the following questions about Hurricane Harvey:
a. Why did hurricane Harvey travel from the east (Africia) twards the west (Florida) when our weather starts in the west and travels east?
B. why did hurricane harvey rotate counterclockwise? Do all hurricanes rotate counterclockwise?