The IUPAC name of the amine shown is N-ethylbutan-1-amine.
What is the IUPAC name of an organic compound?
The IUPAC name of an organic compound is a systematic way of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).
It is a standard method to ensure that every organic compound has a unique name, which reflects its structure and the functional groups present in the molecule.
The IUPAC name usually consists of several parts, including the parent chain, substituent groups, and functional groups, arranged in a specific order according to a set of rules.
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Select the options that correctly reflect the mass ratios and mass percentages of the elements in SO3
1. The mass ratio of S is .400
2. The mass percentage of O is 60%
The options "The mass ratio of S is .400 and The mass percentage of O is 60%" , Both are correct of the elements in sulfur trioxide ([tex]SO^3[/tex])
The molecular formula of sulfur trioxide ([tex]SO^3[/tex]) contains one sulfur atom and three oxygen atoms. To calculate the mass ratios and mass percentages of each element in [tex]SO^3\\[/tex], we need to know the atomic masses of sulfur and oxygen:
Sulfur (S): 32.06 g/mol
Oxygen (O): 16.00 g/mol
Mass ratio of S:
The mass ratio of sulfur (S) in [tex]SO^3\\[/tex] is the mass of sulfur divided by the total mass of the compound:
Mass ratio of S = mass of S / (mass of S + mass of O)
Mass ratio of S = [tex]32.06 g/mol / (32.06 g/mol + 3(16.00 g/mol))[/tex]
Mass ratio of S =[tex]32.06 g/mol / 80.06 g/mol[/tex]
Mass ratio of S = 0.400
Therefore, option 1 "The mass ratio of S is .400" is correct.
Mass percentage of O:
The mass percentage of oxygen (O) in [tex]SO^3[/tex] is the mass of oxygen divided by the total mass of the compound, multiplied by 100%:
Mass percentage of O = (mass of O / total mass) x 100%
Mass percentage of O = [tex](3(16.00 g/mol) / (32.06 g/mol + 3(16.00 g/mol))) * 100%[/tex]
Mass percentage of O = [tex]48.00 g/mol / 80.06 g/mol * 100%[/tex]
Mass percentage of O = 59.97%
Rounding to one significant figure, the mass percentage of O in [tex]SO^3\\[/tex] is 60%.
Therefore, option 2 "The mass percentage of O is 60%" is also correct.
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0.487 grams of quinine (molar mass = 324 g/mol) is combusted and found to produce
1.321 g CO2, 0.325 g H2O and 0.0421 g nitrogen. Determine the empirical and molecular
formulas.
The empirical and molecular formulas of the quinine would be C40H48N and C23H27N respectively.
Empirical and molecular formulasTo determine the empirical formula, we need to find the mole ratios of each element in the compound.
First, let's calculate the number of moles of each product:
moles of CO2 = 1.321 g / 44.01 g/mol = 0.0300 molmoles of H2O = 0.325 g / 18.015 g/mol = 0.0180 molmoles of N2 = 0.0421 g / 28.01 g/mol = 0.00150 molNext, let's find the number of moles of each element:
moles of C = moles of CO2 = 0.0300 molmoles of H = 2 x moles of H2O = 0.0360 molmoles of N = 0.5 x moles of N2 = 0.00075 molNow, we can find the empirical formula by dividing each mole value by the smallest mole value:
C: 0.0300 mol / 0.00075 mol = 40H: 0.0360 mol / 0.00075 mol = 48N: 0.00075 mol / 0.00075 mol = 1The empirical formula is C40H48N.
To find the molecular formula, we need to determine the molecular mass of the compound. The empirical formula mass is:
Empirical formula mass = (40 x 12.01 g/mol) + (48 x 1.01 g/mol) + (1 x 14.01 g/mol) = 549.88 g/mol
Molecular formula factor = 324 g/mol / 549.88 g/mol = 0.5899
Molecular formula = 0.5899 x (C40H48N) = C23H27N
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Please does anyone know how to answer these questions?
Given that we don't have the equation mentioned in the question, I will assume that the equation is referred to is the following:
2N2(g) + 5O2(g) → 2N2O5(g)
a) If you start with 2 moles of O2, according to the equation, 5 moles of O2 are needed to react with 2 moles of N2. Therefore, the number of moles of N2O5 created would be (2/5) x 2 = 0.8 moles.
b) If you start with 1 mole of O2, according to the equation, 5/2 moles of O2 are needed to react with 2 moles of N2. Therefore, the number of moles of N2O5 created would be (1/(5/2)) x 2 = 0.4 moles.
c) If you start with 1 mole of N2, according to the equation, 5/2 moles of O2 are needed to react with 2 moles of N2. Therefore, the number of moles of N2O5 created would be (5/2) x 1 = 2.5 moles.
d) If you get 6 moles of N2O5 during your reaction, according to the equation, 2 moles of N2O5 are produced for every 5 moles of O2 used. Therefore, the number of moles of O2 needed would be (5/2) x (6/2) = 7.5 moles.
e) If you get 6 moles of N2O5 during your reaction, according to the equation, 2 moles of N2O5 are produced for every 2 moles of N2 used. Therefore, the number of moles of N2 needed would be (2/2) x (6/2) = 3 moles.
Names: The chemical names for the compounds involved in the equation are:
O2: Oxygen gas
N2: Nitrogen gas
N2O5: Dinitrogen pentoxide gas
Steps
A chemical reaction between nitrogen and oxygen is represented by the balanced chemical equation 2N2(g) + 5O2(g) 2N2O5(g). The quantities of the reactants and products used in this reaction were questioned.
We may use stoichiometry to determine the mole ratio of O2 to N2O5, which will allow us to calculate how many moles of N2O5 is generated when 2 moles of O2 are consumed.
The equation shows that in order to produce 2 moles of N2O5, 5 moles of O2 must react with 2 moles of N2. The result is the production of (2/5) x 2 = 0.8 moles of N2O5.
Similar calculations can be used to determine how many moles of N2O5 are created when 1 mole of O2 or 1 mole of N2 is used.
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Define which are endothermic and exothermic
NaOH (s) → NaOH (aq)
NH4Cl (s) → NH4Cl (aq)
CaCl2 (s) → CaCl2 (aq)
HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)
NaCl (s) → NaCl (aq)
Answer: NaOH (s) → NaOH (aq) is an exothermic process because energy is released when solid NaOH dissolves in water to form an aqueous solution.
NH4Cl (s) → NH4Cl (aq) is also an exothermic process for the same reason as NaOH above.
CaCl2 (s) → CaCl2 (aq) is also an exothermic process because energy is released when solid CaCl2 dissolves in water to form an aqueous solution.
HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l) is an exothermic process because energy is released as the acid-base reaction occurs and the products are formed.
NaCl (s) → NaCl (aq) is not an endothermic or exothermic process since there is no change in the state of the substance (solid to aqueous solution) and therefore no energy is either absorbed or released.
Explanation: Endothermic and exothermic refer to processes that either require energy to be absorbed or release energy to the surroundings.
In the given reactions, NaOH, NH4Cl, and CaCl2 dissolve in water to form aqueous solutions, and in doing so, they release energy to the surroundings, making these processes exothermic.
The reaction between HCl and NaOH also releases energy as the products are formed, and so it is also exothermic.
However, in the case of NaCl, there is no change in the state of the substance, and so no energy is either absorbed or released, making it neither endothermic nor exothermic.
A mixture of 7.5 g
CH4
and 7.5 g
Xe
is placed in a container and the total pressure is found to be 0.52 atm
Find the partial pressure of CH4?
.
The partial pressure of CH₄ in the mixture is 0.464 atm.
What is the partial pressure of the CH₄?To find the partial pressure of CH₄ in the mixture, we need to use the following formula:
Partial pressure of CH₄ = Total pressure × mole fraction of CH₄
To calculate the mole fraction of CH₄, we need to first calculate the moles of each gas present in the mixture.
The number of moles can be calculated using the following formula:
moles = mass ÷ molar mass
The molar mass of CH₄ is 16.04 g/mol and the molar mass of Xe is 131.29 g/mol.
Moles of CH₄ = 7.5 g ÷ 16.04 g/mol = 0.467 mol
Moles of Xe = 7.5 g ÷ 131.29 g/mol = 0.057 mol
The total number of moles in the mixture is the sum of the moles of CH₄ and Xe:
Total moles = 0.467 mol + 0.057 mol = 0.524 mol
Now we can calculate the mole fraction of CH₄:
Mole fraction of CH₄ = Moles of CH₄ ÷ Total moles = 0.467 mol ÷ 0.524 mol = 0.891
Finally, we can use the formula for partial pressure to find the partial pressure of CH₄:
Partial pressure of CH₄ = Total pressure × mole fraction of CH₄
Partial pressure of CH₄ = 0.52 atm × 0.891 = 0.464 atm
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20.00 mL of 1.40 M HCl diluted to 0.430 L.
What is the pH?
We calculate the pH using the equation pH = -log(Ka), which informs us that a solution with 1.0 106 hydrogen ions has a pH of -log(1.0 106) = 7.39.
When diluted with water, what pH will HCl have?According to the provided data, the pH of hydrochloric acid is 2, indicating that it has an acidic nature. The pH will rise to 7 on dilution, or when we add water to the solution. If it includes more hydrogen ions than hydroxide ions, the pH will be lower than 7.
Does HCl dilution affect pH?When an acid solution is diluted, the pH rises. As an illustration, dilute 10.0 mL of 0.1 M HCl to 30.0 mL.
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Iron reacts with oxygen gas to form a mixture of FeO and Fe₂O₃ when the supply of oxygen is regulated. A sample of 20.00 g iron metal reacts with oxygen gas to form 27.55 g iron oxide mixture, and all of the iron metal was consumed. What is the mass in g of FeO that were produced in the mixture?
The mass in of [tex]FeO[/tex] that were produced in the mixture is 8.49g when a sample of 20.00 g iron metal reacts with oxygen gas to form 27.55 g iron oxide mixture.
Given the mass of iron metal = 20.00g
The mass of iron oxide = 27.55g
Iron reacts with oxygen gas to form a mixture of [tex]FeO[/tex] and [tex]Fe2O3[/tex].
The reaction is as follows: [tex]3Fe + 2O2 --- > FeO + Fe2O3[/tex]
The mass of [tex]FeO[/tex] produced in the mixture can be determined using the following equation:
Mass of [tex]FeO[/tex] = Mass of Iron Oxide Mixture – Mass of [tex]Fe2O3[/tex]
Mass of [tex]FeO[/tex] = 27.55 g - Mass of [tex]Fe2O3[/tex]
as we can see from reaction that 3 moles of iron react to give 1 mole of [tex]Fe2O3[/tex] and 1 mole of [tex]FeO[/tex].
The molar mass of Fe (iron) is = 55.85g/mole and molar mass of [tex]Fe2O3[/tex] = 159.69g/mole
3 * 55.85g of Fe produces 1 * 159.69g of [tex]Fe2O3[/tex]
Then 20.00g of iron produces = 20 * 159.69/3 * 55.85 = 19.06g of [tex]Fe2O3[/tex]
Hence mass of [tex]FeO[/tex] produced = 27.55 - 19.06 = 8.49g
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of the following two gases which would you predict to diffuse more rapidly CH4 H2
H2
Factors that affect the rate of diffusion of a gas including the density of the gas temperature concentration difference and diffusion distance. The density of the diffusing gas depends on how high light is or how heavy the gas is.
Hydrogen cyanide is a highly poisonous substance that can be prepared by the reaction of methane and ammonia:
CH4 (g) + NH3 (g) → HCN(g) + 3 H2 (g)
What is the heat of reaction at constant pressure? Provide an answer correct to 3 significant figures. Do not use scientific notation or include units to report your answer. You do need to include the sign as a part of your answer.
N2 (g) + 3 H2 (g) → 2 NH3 (g) ΔHrxn = -91.8 kJ;
C(s) + 2 H2 (g) → CH4 (g) ΔHrxn = -74.9 kJ;
2 C(s) + H2 (g) + N2 (g) → 2 HCN(g) ΔHrxn = +270.3 kJ
The heat of reaction at constant pressure when methane is reacted with ammonia to form hydrogen cyanide is 103.6kJ.
Given that Hydrogen cyanide which is a highly poisonous substance can be prepared by the reaction of methane and ammonia as follows:
[tex]CH_4 (g) + NH_3 (g) -- > HCN(g) + 3 H_2 (g)[/tex]
This is obtained through the following steps:
[tex]N_2 (g) + 3 H_2 (g) -- > 2 NH_3 (g)[/tex]; ΔHrxn = -91.8 kJ;
[tex]C(s) + 2 H_2 (g) -- > CH_4 (g)[/tex]; ΔHrxn = -74.9 kJ;
[tex]2 C(s) + H_2 (g) + N_2 (g) -- > 2 HCN(g)[/tex]; ΔHrxn = +270.3 kJ
The heat of reaction at constant pressure is the sum of the individual reactions such that:
[tex]\delta Hrxn = -91.8 kJ + (-74.9 kJ) + (270.3 kJ) = 103.6 kJ[/tex]
The heat of reaction is the total amount of energy released or absorbed when a chemical reaction occurs. It is calculated by adding the enthalpies of the reactants and subtracting the enthalpies of the products. Hence it concludes that when methane and ammonia react to form hydrogen cyanide, 103.6 kJ of energy is released.
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if the [H+] of a solution is 8.4 x 10-3 mol/L the pOH of the solution is
The pOH of the solution is 10.92.
Calculation-Equation: The relationship between a solution's pH and pOH is:
pH + pOH = 14
where pH is equal to the negative logarithm of the concentration of hydrogen ions (H+), and pOH is equal to the negative logarithm of the concentration of hydroxide ions (OH-).
We must first determine the [OH-] concentration to determine the solution's pOH. We can apply the following:
Kw = [H+][OH-] = 1.0 x 10^-14 at 25°C
where Kw is the water-specific ion product constant.
If we rewrite this equation, we obtain:
[OH-] = Kw/[H+] = 1.0 x 10^-14 / 8.4 x 10^-3 = 1.19 x 10^-11 mol/L
We can now calculate pOH's value using the definition of the term:
pOH = -log[OH-] = -log(1.19 x 10^-11) = 10.92
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HELP ASAP PLSSS I don't get it
Answer:
I believe the answer is 120 degrees Celsius.
Explanation:
−15+135=120
Consider the cis and trans structures of 1,5 dimethyl decline.which one will be more stable?..
Explanation:
In the case of trans-decalin, there is no steric interaction between the rings because they are at their maximum distance. As a result, the trans conformation is more stable. Another reason is that trans-decalin does not undergo ring flipping. So, it remains rigid and is more stable.
Stearic interactions between the two rings result in a less stable conformation in case of cis-decalin.It undergoes ring flipping so, unstable conformation. (The First image)
Hence, trans-decalin is more stable than cis-decalin.(The second image)
Hopefully this helps! :)
Question 7 of 10
When naming a molecule, how do you indicate that the carbons on either side
of the double bond are pointing in opposite directions?
OA. Use the prefix cis-.
OB. Use the prefix methyl-.
OC. Use the number 2 as a prefix.
OD. Use the prefix trans-.
Answer:
by using the prefix trans
Explanation:
i hope you find it helpful
Pls help with common naming the benzene aromatic compounds
The name of the substituent is appended as a prefix to the name of the aromatic compound in the IUPAC nomenclature of substituted aromatic compounds. Nitrobenzene is the name given to a benzene ring linked to a one-nitro group.
A level chemistry: how do you name benzene compounds?Aromatic compounds, often known as arenes, are chemicals that include a benzene ring. Arenes can be given two names: Chlorobenzne, benzoic acid (or benzene-carboxylic acid), and 1,3-dimethylbenzene are examples of substituted benzene rings.
Aromatic rings (also known as aromatic compounds or arenes) are hydrocarbons that include benzene or another ring structure similar to benzene.
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When dinitrogen pentoxide, N₂O5, a white solid, is heated, it decomposes to nitrogen dioxide and oxygen. How many grams of oxygen can be formed from the decomposition of 2.3 g of N₂05?
2N₂05 (s)—>4NO₂(g) + O₂(g)
The mass of the oxygen that can be obtained by the use of the stoichiometry of the reaction is 0.35 g.
How is stoichiometry applied?Stoichiometry is applied in chemistry to calculate the quantities of reactants and products involved in a chemical reaction. It involves using the balanced chemical equation of the reaction to determine the mole ratios of reactants and products, and then using these ratios to calculate the amount of one substance that is required to produce a given amount of another substance.
We know that;
Moles of N2O5 = 2.3g/108 g/mol
= 0.021 moles
2 moles of N2O5 would produce 1 moles of O2
0.021 moles would produce 0.021 * 1/2
= 0.011 moles
Mass of O2 = 0.011 moles * 32 g/mol
= 0.35 g
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ingitis, but, it also occurs when bacteria dir eninges. This may be caused by an ear or sinus infection and or s Define the term meningitis. 1 2 Mention SIX typical complications of meningitis. List FOUR signs and symptoms of meningitis. Discuss THREE steps of treating a person with meningitis Mention the TWO types of meningitis. right reserved TO
Meningitis is an inflammation of the meninges, which are the membranes that cover the brain and spinal cord. It can be caused by a bacterial or viral infection, with bacterial meningitis being the most serious and potentially life-threatening form.
What are Some common complications of meningitis?Septicemia: This is a serious bloodstream infection that can occur as a result of meningitis. It can cause organ failure and can be fatal.
Brain swelling: Meningitis can cause the brain to swell, which can lead to increased pressure inside the skull and can cause damage to brain tissue.
Hearing loss: Meningitis can damage the inner ear and cause hearing loss, which can be permanent.
Vision loss: In some cases, meningitis can cause damage to the optic nerve and lead to vision loss.
Cognitive impairment: Meningitis can cause long-term cognitive impairment, including problems with memory, attention, and other cognitive functions.
Seizures: Meningitis can cause seizures, which are sudden and uncontrolled bursts of electrical activity in the brain.
Some common signs and symptoms of meningitis include:
Headache
Stiff neck
Fever
Nausea and vomiting
The treatment of meningitis typically involves three main steps:
Antibiotics or antiviral medications: Depending on the cause of the infection, antibiotics or antiviral medications may be prescribed to fight the infection.
Supportive care: This may include medications to reduce fever and pain, as well as intravenous fluids to prevent dehydration.
Hospitalization: Most cases of meningitis require hospitalization for close monitoring and treatment.
Conclusively, there are two main types of meningitis: bacterial meningitis and viral meningitis. Bacterial meningitis is more severe and can be life-threatening if not treated promptly, while viral meningitis is typically less severe and often resolves on its own without treatment.
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Write the molecular equation and net ionic equation for the reaction of hydroiodic acid and potassium hydroxide. Include phases (states). Enter the formula for water as H2O
find the molar equation and net ionic equation.
The Molecular Equation is : [tex]HI (aq) + KOH (aq) \rightarrow KI (aq) + H_2O (l)[/tex]
The Net Ionic Equation is : [tex]H^+(aq) + OH^-(aq) \rightarrow H_2O(l)[/tex]
This reaction is an acid-base neutralization reaction. Hydroiodic acid (HI) is an acid and potassium hydroxide (KOH) is a base. When the two react, they form water ([tex]H_2O[/tex]) and potassium iodide (KI).[tex]H_2O[/tex] is a chemical formula for water, which consists of two hydrogen atoms and one oxygen atom. Water is a fundamental component of life and is essential for all forms of life on Earth. The reaction is a double displacement reaction, where the positively charged cations, potassium (K⁺) and hydrogen (H⁺), switch places with each other in the reactants to form the products.
It is possible to describe the as:
[tex]HI (aq) + KOH (aq) \rightarrow KI (aq) + H_2O (l)[/tex]
One way to express the net-ionic equation is as follows:
[tex]H^+(aq) + OH^-(aq) \rightarrow H_2O(l)[/tex]
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CH3CHCHCHCH3 with two CH3 groups and an OH group attached IUPAC name
The IUPAC name for the given molecule, which has four carbon atoms, one OH group, and two methyl (CH3) groups attached, is:
4-methyl-2-pentanol
What is IUPAC?
It is an international organization that aims to advance the chemical sciences and to contribute to the application of chemistry in the service of humankind.
Identify the longest carbon chain that contains the functional group (OH). In this case, the longest chain has five carbon atoms.
Number the carbon atoms in the chain, starting from the end that is closest to the functional group (OH). In this case, we can number the chain from left to right, so that the OH group is on carbon atom 2.
Identify and name the substituents (groups) attached to the main chain. In this case, there are two methyl (CH3) groups attached to carbon atoms 4 and 5, respectively.
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What is the Molarity of a 0.5 Liter solution that contains 3.84 moles of NaCI?
SHOW WORK
Answer:
The molarity of a 0.5 L solution that contains 3.84 moles of NaCl is 7.68 M.
Here’s the work: Molarity (M) = moles of solute / liters of solution Substituting the given values into the equation: Molarity (M) = 3.84 moles / 0.5 L = 7.68 M.
At a constant temperature and pressure, there are initially 0.6400 moles in a balloon with a volume of 4.00 L. Gas is removed until there is a total of 0.3500 moles. Calculate the volume of the balloon after this change.
The volume of the balloon after the change is approximately 2.19 L. The gas laws behaviour of gases by providing relationships between the temperature, moles, volume and pressure
What is gas law?We can use the combined gas law to solve this problem: (P1V1)/(n1T1) = (P2V2)/(n2T2) where P is the pressure, V is the volume, n is the number of moles, and T is the temperature.
We can assume that the temperature and pressure remain constant, so T1 = T2 and P1 = P2.
Therefore, we can simplify the equation to: (V1/n1) = (V2/n2)
Substituting the given values, we get: (V1/0.6400) = (V2/0.3500)
Solving for V2, we get: V2 = (0.3500/0.6400) * V1 V2 = 0.5469 * V1
The volume of the balloon after the change is 0.5469 times the original volume, or: V2 = 0.5469 * 4.00 L = 2.1876 L
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At a certain temperature, 0.4011 mol of N2 and 1.501 mol of H2 are placed in a 4.50 L container.
N2(g)+3H2(g)↽−−⇀2NH3(g)
At equilibrium, 0.1401 mol of N2 is present. Calculate the equilibrium constant, c.
Kc=??
The equilibrium constant of the reaction shown by the illustration would be 4.315.
Equilibrium constant calculationThe balanced equation for the reaction is:
N2(g) + 3H2(g) ⇌ 2NH3(g)
The equilibrium constant expression for this reaction is:
Kc = [NH3]^2 / ([N2] * [H2]^3)
We are given the initial and equilibrium concentrations of N2 and H2, and the equilibrium concentration of NH3 can be calculated as follows:
[NH3] = 2 * [N2]initial - [N2]equilibrium
[NH3] = 2 * 0.4011 mol - 0.1401 mol = 0.6621 mol
Substituting the concentrations into the equilibrium constant expression, we get:
Kc = (0.6621 mol)^2 / (0.1401 mol * 1.501 mol^3)
Kc = 4.315
Therefore, the equilibrium constant for this reaction at the given temperature is 4.315.
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HELP
If you measured out 49.93 mL of a 1.000 M sodium hydroxide solution, how many moles of sodium hydroxide would be present?
Answer: 0.0499 moles of sodium hydroxide
Explanation:
We can determine the number of moles by using the Molarity equation:
Molarity = Moles / Volume (volume is always in Liters)
We have 2 out of 3 components of this equation
Molarity = 1.000 M
Volume = 49.93 mL / 1000 = 0.0499 L
So we rearrange the equation like the following:
Moles = Molarity x volume
= 1.000 Mx 0.0499 L
= 0.0499 moles of sodium hydroxide
What variables are plotted on the x and y axes of the graph
Answer:
The Axes. The independent variable belongs on the x-axis (horizontal line) of the graph and the dependent variable belongs on the y-axis (vertical line). The x and y axes cross at a point referred to as the origin, where the coordinates are (0,0).Why are diamonds unevenly distributed on Earth?
Responses
Diamonds are formed in the upper mantle. Only some places on Earth have an upper mantle.
Diamonds are extremely hard. They are formed in rock that is equally as hard and is found only in certain places on Earth because of this.
Diamonds are made from carbon atoms. Carbon is rarely found on Earth’s surface.
Diamonds are carried upward close to the surface through the action of volcanoes. They are found only in areas with current or past volcanic activity.
Only under certain circumstances involving geological processes, such as plate movements and volcanic activity, could diamonds actually originate. Diamonds can only be found in these unique locations.
Are diamonds distributed equally throughout the world?Nonetheless, because of the mantle's comparatively low carbon content, diamonds are extremely rare. Diamonds are also not found in equal amounts around the planet; rather, they are only discovered in significant quantities in very specific geologic settings.
How do diamonds reach the earth's surface?Carbon crystals that develop beneath the Earth's crust are what makeup diamonds. They are exposed to the atmosphere during volcanic eruptions of a unique magma known as kimberlite.
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Add any nonzero formal charges to the atoms as applicable for the lewis structure shown with connectivity c–s–s. all valence electrons have been included, and this structure follows the octet rule. if formal charges are equal to zero, they should not be included.
Carbon would therefore have a formal charge of 0, Sulfur 1 would have a formal charge of 1, and Sulfur 2 would have a formal charge of 1.
How can nonzero formal charge be found?For each atom in a Lewis structure, you should count how many electrons it "owns" in order to get the formal charges. All of its lone pair electrons as well as 50% of its bonding electrons should be counted. The formal charge is the discrepancy between the atom's number of valence electrons and the number it possesses.
Which has an atom's core having no formal charge?For organic chemists, carbon is the most significant element. Four bonds are made to the carbon atom in the structures of methane, methanol, ethane, ethene, and ethyne.
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5. A 1.0 L sample of a pure gas is found to have a lower pressure than that predicted by the ideal gas law. The best explanation for the observation is that the molccules of the gas
(A) have a combined volume that is too large to be considered negligible when compared to the volume of the container
(B) have a low molecular mass and therefore do
no sinkc the container walls with as much force as expected
(C) are attracted to each other and do not exert as much force on the container walls as they would if they had no mutual attractions
(D) are attracted to the sides of the container and strike the container walls with more force
than expected
Molecules of the gas are attracted to each other and do not exert as much force on the container walls as they would if they had no mutual attractions. Option C
Ideal gas problemThe best explanation for a pure gas having a lower pressure than predicted by the ideal gas law is that the molecules of the gas are attracted to each other and do not exert as much force on the container walls as they would if they had no mutual attractions.
The ideal gas law assumes that gas molecules do not interact with each other and have no volume, which is not true for real gases. In real gases, the molecules do interact with each other, and they do have a finite volume.
As a result, the pressure of a real gas can be lower than predicted by the ideal gas law. This effect is more pronounced at high pressures and low temperatures, where the interactions between gas molecules are stronger.
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Match the following phase changes to their energy flow.
Evaporation
Melting
Freezing
Sublimation
Condensation
Deposition
[Choose]
[Choose]
Energy both absorbed and released
Energy absorbed
No energy flow
Energy released
[Choose]
[Choose]
[Choose ]
[Choose
Whereas freezing, condensation, or deposition are exothermic processes, fusion, vaporisation, and were endothermic processes. Changes in a system's energy occur together every phase transition.
During a phase change, what energy is altered?Potential energy is the type of energy that is transforming during a phase change. Either elevated body temperature (PE increases) and released (PE drops) throughout a phase change will permit the molecules either move apart or join together.
What 4 phase modifications are there?Melting is the process of changing from of the solid to liquid state. freezing: the transformation of a liquid into a solid. The process of evaporation is the change from a liquid to a gas. Condensing: The change from a gaseous to a liquid state.
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How many total atoms are there in 62.5 g
of carbon disulfide ( CS2)?
Total atoms:
The answer is [tex]4.94 x 10^23[/tex] atoms.
To determine the total number of atoms in 62.5 g of carbon disulfide (CS2), we need to use Avogadro's number and the molecular weight of CS2.
The molecular weight of CS2 is:
Carbon atomic weight = 12.01 g/mol
Sulfur atomic weight = 32.06 g/mol
2 sulfur atoms x 32.06 g/mol + 1 carbon atom x 12.01 g/mol = 76.13 g/mol
Now, we can use the formula:
Number of moles = mass ÷ molecular weight
Number of moles of CS2 = 62.5 g ÷ 76.13 g/mol = 0.821 mol
Finally, we can use Avogadro's number, which is[tex]6.022 x 10^23[/tex] atoms per mole, to calculate the total number of atoms in 62.5 g of CS2:
Total atoms = Number of moles × Avogadro's number
Total atoms = 0.821 mol ×[tex]6.022 x 10^23[/tex] atoms/mol
Total atoms =[tex]4.94 x 10^23[/tex] atoms
Therefore, there are approximately[tex]4.94 x 10^23[/tex]atoms in 62.5 g of carbon disulfide (CS2).
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Calculate the hydronium ion concentration, [H3O+] , for a solution with a pH of 10.68 . [H3O+]= M
We know that pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance which is defined as the negative base 10 logarithm of the activity of hydrogen ions. Which states -
pH= - log [H⁺]= - log [H₃O⁺]As per question, we are given a pH value which is 10.68 for a solution and have asked to find out the hydronium ion concentration. Since we have the value of pH, so we can put into the formula and solve for [H₃O⁺] -
[tex] \:\:\:\:\:\:\longrightarrow \sf pH = 10.68\\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf - log [H₃O⁺] = 10.68 \\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf [H₃O⁺] = 10^{-10.68}\\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{[H₃O⁺] = 2.0893 \times 10^{-11}\:M} \\[/tex]
Therefore, the hydronium concentration for the solution is [tex]\underline{\: \sf 2.0893 \times 10^{-11}\:M }\\[/tex]
3. A student obtained the following data using the procedure used in this experiment.
BEFORE IGNITION
mass of crucible + crucible cover = 34.12 g
mass of crucible + cover + unknown sample = 36.65 g
AFTER IGNITION
mass of crucible + cover + unknown (1st weighing) = 35.67 g
mass of crucible + cover + unknown (2nd weighing) = 35.23 g
mass of crucible + cover + unknown (3rd weighing) = 35.20 g
Calculate the % water in the unknown sample:_______?
The percent of water in the unknown sample is calculated as 57.3%.
What is ignition?Process of providing energy that is required to initiate a combustion process is called ignition.
mass of crucible + cover + unknown sample = 36.65 g
mass of crucible + cover = 34.12 g
mass of unknown sample = (36.65 g - 34.12 g) = 2.53 g
mass of water lost during ignition:
mass of unknown sample (before ignition) = 2.53 g
mass of unknown sample (after 1st weighing) = 35.67 g - 34.12 g = 1.55 g
mass of unknown sample (after 2nd weighing) = 35.23 g - 34.12 g = 1.11 g
mass of unknown sample (after 3rd weighing) = 35.20 g - 34.12 g = 1.08 g
total mass of water lost during ignition = (2.53 g - 1.08 g) = 1.45 g
As % water in unknown sample = (mass of water lost / mass of unknown sample) x 100%
= (1.45 g / 2.53 g) x 100%
% water in unknown sample = 57.3%
Therefore, percent of water in the unknown sample is 57.3%.
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