Give an example of:
1. A vector space V, and a (non-empty) subset of V that is closed under addition but not under scalar multiplication.
2. A vector space V and a (non-empty) subset of V that is closed under scalar multiplication but not under addition.

Answers

Answer 1

1). W is closed under addition.  

  W is not closed under scalar multiplication

2. W is not closed under addition

   W is closed under scalar multiplication

1. Let V be the vector space of all 2x2 matrices with real entries. Consider the subset W of V consisting of matrices of the form:

| a b |

| 0 c |

where a, b, and c are real numbers. Note that W is non-empty, since the matrix |0 0| is in W.

|0 0|

Now, let A and B be any two matrices in W, so that A has the form:

| a1 b1 |

| 0 c1 |

and B has the form:

| a2 b2 |

| 0 c2 |

Then the sum of A and B has the form:

| a1+a2 b1+b2 |

| 0 c1+c2 |

which is clearly also in W. Therefore, W is closed under addition.

However, W is not closed under scalar multiplication. Let A be any matrix in W, so that A has the form:

| a b |

| 0 c |

where a, b, and c are real numbers. Then, if we multiply A by a non-real scalar k = xi (where x is a real number and i is the imaginary unit), we get:

kA = xi * | a b | = | xia xib |

| 0 c | | 0 xc |

which is not in W, since the entry in the (1,2) position is non-zero. Therefore, W is not closed under scalar multiplication.

2. Let V be the vector space of all polynomials with real coefficients. Consider the subset W of V consisting of all polynomials of degree at most 2.

Note that W is non-empty, since the polynomial p(x) = 0 is in W.

Now, let c be any real scalar, and let p(x) be any polynomial in W.

Then cp(x) is a polynomial of degree at most 2, since multiplying a polynomial of degree at most 2 by a scalar does not change its degree. Therefore, W is closed under scalar multiplication.

However, W is not closed under addition. Let p(x) and q(x) be any two polynomials in W of degree at most 2. Then the sum p(x) + q(x) may have degree greater than 2, and hence may not be in W. For example, if p(x) = x^2 + 2x + 1 and q(x) = -x^2 + x - 1, then p(x) + q(x) = 3x, which is not in W. Therefore, W is not closed under addition.

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Related Questions

What is most likely true about the melting times of these two types of chocolates

Answers

It can be inferred that milk chocolate does have a lower melting point than dark chocolate and that the rate at which chocolate melts is influenced by a number of variables, including composition, temperature, as well as humidity.

According to the facts provided, it is anticipated that within 64 seconds, half of the milk chocolate brands will melt. According to their composition as well as melting point, different milk chocolate brands may melt sooner or later than 64 seconds.

However, it is believed that none of the dark chocolate brands are expected to melt before 64 seconds have passed and that their melting time actually begins after 200 seconds.

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If the values of A and B make the equation 35x – 29/x^2-3x+2 = A/x-1 +b/x-2 true for all values of x for which it is defined, find A+B. (A) 6 (B) 29 (C) 35 (D) 47 (E) None of these

Answers

If the values of A and B make the equation 35x – 29/x²-3x+2 = A/x-1 +b/x-2 true for all values of x for which it is defined, A+B is 35.

The given equation is 35x - 29/(x² - 3x + 2) = A/(x - 1) + B/(x - 2).

We can simplify the denominator of the second term on the left hand side by factoring it:

35x - 29/[(x - 1)(x - 2)] = A/(x - 1) + B/(x - 2)

Now, we can multiply both sides of the equation by (x - 1)(x - 2) to get rid of the fractions:

35x(x - 1)(x - 2) - 29 = A(x - 2) + B(x - 1)

Expanding the left hand side gives us:

35x³ - 70x² + 35x - 29 = A(x - 2) + B(x - 1)

Now, we can compare the coefficients of x on both sides of the equation to find the values of A and B. The coefficient of x on the left hand side is 35, and on the right hand side it is A + B. Therefore, A + B = 35.


Therefore, the values of A and B make the equation 35x – 29/x^2-3x+2 = A/x-1 +b/x-2 true for all values of x for which it is defined is 35.

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A movie sells only adult tickets and child tickets for one movie the theater sells 126 tickets in all the tape diagram shows the ratio of adult tickets to child tickets the theater sells what does each square of the diagram represent?

Answers

Answer:

So each square in the diagram represents approximately 9.69 tickets. However, since we can't sell fractional tickets, we can round this up to 10 tickets per square. Therefore, each square in the diagram represents 10 tickets.

Step-by-step explanation:

Assuming that the tape diagram shows the ratio of adult tickets to child tickets as 3:2, we can represent this as follows:

  AAA

  AAA

  AAA

  CCC

  CCC

In this diagram, each square represents a certain number of tickets. To determine how many tickets each square represents, we need to know the total number of squares in the diagram.

There are a total of 3 + 3 + 3 + 2 + 2 = 13 squares in the diagram. Since the theater sold 126 tickets in total, we can divide 126 by 13 to find out how many tickets each square represents:

126 ÷ 13 ≈ 9.69

So each square in the diagram represents approximately 9.69 tickets. However, since we can't sell fractional tickets, we can round this up to 10 tickets per square. Therefore, each square in the diagram represents 10 tickets.

Consider the polynomial P(x)=kx^(3)-4x^(2)+x+4. Find the value of k such that the remainder is -6 when P(x) is divided by x+1. k

Answers

The value of k that makes the remainder of the polynomial equal to -6 when divided by x + 1 is k = 5.

To find the value of k that makes the remainder of the polynomial P(x) = kx3 - 4x2 + x + 4 equal to -6 when divided by x + 1, we can use the Remainder Theorem. The Remainder Theorem states that if a polynomial P(x) is divided by x - a, the remainder is P(a).

In this case, we are dividing by x + 1, so we can rewrite this as x - (-1). Therefore, a = -1 and we can plug this value into the polynomial to find the remainder:

P(-1) = k(-1)3 - 4(-1)2 + (-1) + 4

Simplifying this equation gives us:

P(-1) = -k - 4 - 1 + 4

P(-1) = -k - 1

Since we want the remainder to be -6, we can set P(-1) equal to -6 and solve for k:

-k - 1 = -6

-k = -5

k = 5

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Find the y intercept and slope of the linear equation x+y=-6 1/2

Answers

The slope of the equation x + y=-6 1/2 is -1, and the y-intercept is -6 1/2.

To find the y-intercept and slope of the linear equation x  +y=-6 1/2, we

need to rewrite it in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

First, let's isolate y by subtracting x from both sides of the equation:

x + y = -6 1/2

y = -x - 6 1/2

Now we can see that the equation is in slope-intercept form, where the slope (m) is -1 and the y-intercept (b) is -6 1/2.

Therefore, the slope of the equation x + y=-6 1/2 is -1, and the y-intercept is -6 1/2.

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Does this equation have a solution?


10x + 12 = 20x - 2

Answers

Answer:

Answer and how to isolate the variablex=1.4

First, subtract 10x on both sides so you get

12=10x-2

Then add 2 odd both sides

14=10x

Then divide both sides by 10

14/10= 10X/10

So you get x=1.4

Watch help video Ise synthetic division to find the result when 2x^(4)+10x^(3)+8x^(2)+x+24 divided by x+2. If there is a remainder, express the result in the form

Answers

Therefore, the result of the division 2x^(4)+10x^(3)+8x^(2)+x+24 divided by x+2 using synthetic division is 2x^(3)+6x^(2)+4x-6+(36)/(x+2).

To use synthetic division to find the result of the given polynomial division, we need to follow these steps:

1. Write the coefficients of the dividend polynomial in a row: 2 10 8 1 24
2. Write the constant term of the divisor with the opposite sign in front of the row: -2 | 2 10 8 1 24
3. Bring down the first coefficient: -2 | 2 10 8 1 24
         -----------
            2
4. Multiply the first coefficient by the divisor's constant term and write the result under the second coefficient: -2 | 2 10 8 1 24
         -----------
            2 -4
5. Add the second coefficient and the result from step 4: -2 | 2 10 8 1 24
         -----------
            2  6
6. Repeat steps 4 and 5 for the remaining coefficients: -2 | 2 10 8 1 24
         -----------
            2  6  4 -6
7. The last number in the row is the remainder. If it is 0, the division is exact. If not, we need to express the result in the form: quotient + (remainder)/(divisor)


In this case, the quotient is 2x^(3)+6x^(2)+4x-6 and the remainder is 36. So the result of the division is:
2x^(3)+6x^(2)+4x-6+(36)/(x+2)

Therefore, the result of the division 2x^(4)+10x^(3)+8x^(2)+x+24 divided by x+2 using synthetic division is 2x^(3)+6x^(2)+4x-6+(36)/(x+2).

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solve the problem with simplex method , and verify using graphical method
Extra Credit Min Z = -X1 + 2X2 St. -X1 + X2 >= -1 4X1 + 3X2 + <= 12
2X1 <= 3
Xi >= 0

Answers

In this case, the point (3/2, 0) is the optimal solution, which matches the solution we found using the simplex method.

To solve the problem using the simplex method, we first need to convert the inequalities to equations by adding slack variables. Then we can set up the initial tableau and use the simplex method to find the optimal solution. Finally, we can verify the solution using the graphical method.

Convert inequalities to equations by adding slack variables
-X1 + X2 >= -1 becomes -X1 + X2 + S1 = -1
4X1 + 3X2 <= 12 becomes 4X1 + 3X2 + S2 = 12
2X1 <= 3 becomes 2X1 + S3 = 3

Set up the initial tableau
| -1 | 2 | 1 | 0 | 0 | 0 |
| -1 | 1 | 1 | 0 | 0 | -1 |
| 4 | 3 | 0 | 1 | 0 | 12 |
| 2 | 0 | 0 | 0 | 1 | 3 |

Use the simplex method to find the optimal solution
We first need to choose the pivot column, which is the one with the most negative coefficient in the objective row. In this case, it is the first column. Then we need to choose the pivot row, which is the one with the smallest positive ratio of the right-hand side to the pivot column coefficient. In this case, it is the third row. We can then use the pivot element to eliminate the other coefficients in the pivot column and repeat the process until we have no negative coefficients in the objective row.

After performing the simplex method, we get the following final tableau:
| 0 | 5/4 | 1 | 1/4 | 0 | 3 |
| 0 | 7/4 | 1 | 1/4 | 0 | 3 |
| 0 | 3/4 | 0 | 1/4 | 0 | 3 |
| 1 | 0 | 0 | 0 | 1/2 | 3/2 |

The optimal solution is X1 = 3/2, X2 = 0, and Z = -3/2.

Verify the solution using the graphical method
We can graph the constraints and find the feasible region. Then we can graph the objective function and find the point where it intersects the feasible region that gives the maximum or minimum value. In this case, the point (3/2, 0) is the optimal solution, which matches the solution we found using the simplex method.

Extra Credit:
To solve the problem using the simplex method, we first need to convert the inequalities to equations by adding slack variables. Then we can set up the initial tableau and use the simplex method to find the optimal solution. Finally, we can verify the solution using the graphical method.

Convert inequalities to equations by adding slack variables
-X1 + X2 >= -1 becomes -X1 + X2 + S1 = -1
4X1 + 3X2 <= 12 becomes 4X1 + 3X2 + S2 = 12
2X1 <= 3 becomes 2X1 + S3 = 3

Set up the initial tableau
| -1 | 2 | 1 | 0 | 0 | 0 |
| -1 | 1 | 1 | 0 | 0 | -1 |
| 4 | 3 | 0 | 1 | 0 | 12 |
| 2 | 0 | 0 | 0 | 1 | 3 |

Use the simplex method to find the optimal solution
We first need to choose the pivot column, which is the one with the most negative coefficient in the objective row. In this case, it is the first column. Then we need to choose the pivot row, which is the one with the smallest positive ratio of the right-hand side to the pivot column coefficient. In this case, it is the third row. We can then use the pivot element to eliminate the other coefficients in the pivot column and repeat the process until we have no negative coefficients in the objective row.

After performing the simplex method, we get the following final tableau:
| 0 | 5/4 | 1 | 1/4 | 0 | 3 |
| 0 | 7/4 | 1 | 1/4 | 0 | 3 |
| 0 | 3/4 | 0 | 1/4 | 0 | 3 |
| 1 | 0 | 0 | 0 | 1/2 | 3/2 |

The optimal solution is X1 = 3/2, X2 = 0, and Z = -3/2.

Verify the solution using the graphical method
We can graph the constraints and find the feasible region. Then we can graph the objective function and find the point where it intersects the feasible region that gives the maximum or minimum value. In this case, the point (3/2, 0) is the optimal solution, which matches the solution we found using the simplex method.

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Liam wants to run 10 more runs what is the equations

Answers

the answer is x+10 i think bye

A piece of timber 0.72 m long is cut evenly into smaller pieces of 0.03 m each. How many of these pieces can be cut?

Answers

Answer:

24

Step-by-step explanation:

This is a division problem.

0.72/0.03 = 7.2/0.3 = 72/3 = 24

A store manager adjusts the price of an item each week that the item goes unsold. The price of the unsold item, in dollars, after x weeks can be modeled by the exponential function f(x)=320(0.90)^x
: The initial price of the store item before the store manager made any price adjustments were: _________

Can someone help me solve this?
Thanks!

Answers

Answer:

The initial price of the store item would be the price before any price adjustments were made, which corresponds to when x=0.

Plugging x=0 into the given function, we get:

f(0) = 320(0.90)^0 = 320(1) = 320

Therefore, the initial price of the store item was $320.

Question 10 of 10 6 st Answer here 5 E Given the two similar triangles above, what is the measure of side DE?​

Answers

Answer:

DE = 3

Step-by-step explanation:

What is a scale factor?

A scale factor consists of two or more shapes who look the same but have different scales or measures. A scale factor of [tex]\frac{1}{2}[/tex] means that the new shape is half the size of the original.

To solve for a missing length, we can use this expression:

[tex]a^{2} +b^{2} =c^{2}[/tex]

Inserting our numbers into the expression:

[tex]8^{2}+ b^{2} =10^{2}[/tex][tex]64 + b^{2} = 100[/tex]

Subtract 64 from each side:

[tex](64 - 64) + b^{2} =(100-64)[/tex][tex]b^{2} =36[/tex][tex]\sqrt{36} =6[/tex]

Therefore, the missing side length is 6.

Looking at the side CB, it is 10 units long. If the new shape is 5 units long, that means that the scale factor from shape 1 to 2 is [tex]\frac{1}{2}[/tex], meaning it is half its size. If the new shape is half its size, we can use this expression to solve for the missing length:

6 × [tex]\frac{1}{2}[/tex] or 6 ÷ 2 = 3

Therefore, the measure of DE is 3.

It takes 4 minutes for the wheel to make one complete rotation. Put a star at Bo’s location after riding the wheel for 21 minutes

Answers

After 21 minutes the location of BO in the wheel is EO

How to find BO after 21 minutes

The location of BO after 21 minutes is solved using the data:

It takes 4 minutes for the wheel to make one complete rotation

hence in 21 minutes the rotation covered is

= 21 / 4

= 5.25

This is 5 complete rotations and 0.25 (a quarter rotation).

0.25 rotation is

=0.25 * 360

= 90

Each gap in the wheel is

360 / 12 = 30 degrees

hence three steps from B which is EO

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I want to be done with this

Answers

The equation which represents exponential growth is y = (1.2)* and equation which represents exponential decay is y = (.71)*,  y = 0(6.3)* represents a constant function.

What is exponential growth or decay function?

Consider the function:

[tex]y = a(1\pm r)^m[/tex]

where m is the number of times this growth/decay occurs, a = initial amount, and r = fraction by which this growth/decay occurs.

If there is plus sign, then there is exponential growth happening by r fraction or 100r %

If there is negative sign, then there is exponential decay happening by r fraction or 100r %

We are given that;

c. y = (1.2)*

d. y = 0(6.3)*

e. y = (.71)*

a.) The equation and graph that show exponential growth is y = (1.2)x. This is because the base of the exponent (1.2) is greater than 1, so as x increases, the value of y increases at an increasing rate. The graph of y = (1.2)x is an upward-curving curve that gets steeper as x increases.

b.) The equation and graph that show exponential decay is y = (0.71)x. This is because the base of the exponent (0.71) is between 0 and 1, so as x increases, the value of y decreases at a decreasing rate. The graph of y = (0.71)x is a downward-curving curve that flattens out as x increases.

Therefore, exponential growth shows y = (1.2)* whereas y = (.71)* show exponential decay.

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Can anybody please help me with this question

Answers

Answer:

  (a)  8 : 3

  (b)  1 7/8 cups

Step-by-step explanation:

Given a recipe that calls for 2 cups of flour and 3/4 cup of water, you want to know the ratio in simplest terms, and the amount of water for 5 cups of flour.

Simplified ratio

The ratio can be written and simplified as a fraction. Fractions are divided in the usual way.

  2/(3/4) = 2 ÷ 3/4 = 2 × 4/3 = 8/3 = 8 : 3

5 cups flour

If we multiply each term in this ratio by 5/8, we can find the recipe that uses 5 cups of flour:

  (5/8)·8 : (5/8)·3 = 5 : 15/8 = 5 : 1 7/8

Naomi uses 1 7/8 cups of water with 5 cups of flour.

Answer:

Step-by-step explanation:

[tex](a)[/tex]

[tex]2:\frac{3}{4}[/tex]

Multiply both sides by 4 to remove fraction:

[tex]2\times4:\frac{3}{4} \times 4[/tex]

[tex]8:3[/tex]     (this is simplest form because no number goes into both 8 and 3)

[tex](b)[/tex]

5 cups of flower:

[tex]8 \times \frac{5}{8} : 3 \times \frac{5}{8}[/tex]   (I chose [tex]\frac{5}{8}[/tex] to turn the 8 into 5)

[tex]5:\frac{15}{8}[/tex]

5 cups flour needs [tex]\frac{15}{8}[/tex] ([tex]=1\frac{7}{8}[/tex]) cups water

Babe and Ruth are 675 miles apart and headed straight toward each
other. If Babe is traveling at 40 mph and Ruth is traveling at 35
mph, how many hours will it be before the two meet?

Answers

Babe and Ruth are 675 miles apart and headed straight toward each

other. If Babe is traveling at 40 mph and Ruth is traveling at 35

mph, it will take 9 hours before they meet.

To determine the time it will take for Babe and Ruth to meet, we need to use the formula:

time = distance / rate

Since they are traveling towards each other, we can add their speeds to get the combined speed at which they are approaching each other.

combined speed = Babe's speed + Ruth's speed

combined speed = 40 mph + 35 mph

combined speed = 75 mph

Now we can plug in the values we have into the formula:

time = distance / combined speed

time = 675 miles / 75 mph

time = 9 hours

Therefore, it will take 9 hours before Babe and Ruth meet.

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Suppose that a line passes through the points (5,1) and (-1.5).
Where will it pass through the x-axis?

Answers

The line passes through the x-axis at the point (13/2, 0).

To find where the line passes through the x-axis, we need to find the x-intercept of the line. The x-intercept is the point where the line crosses the x-axis, so the y-coordinate of this point will be 0.

We can use the slope-intercept form of a line, y = mx + b, to find the x-intercept. First, we need to find the slope of the line, m. The slope is given by the formula:
m = (y2 - y1)/(x2 - x1)

Plugging in the given points, we get:

m = (5 - 1)/(-1 - 5)

m = -2/3

Now we can plug in one of the points and the slope into the equation to solve for the y-intercept, b:
1 = -2/3(5) + b
b = -13/3

So the equation of the line is:
y = -2/3x + 13/3

To find the x-intercept, we set y to 0 and solve for x:
0 = -2/3x + 13/3
x = 13/2


So the line passes through the x-axis at the point (13/2, 0).

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What is the volume of the composite solid?

Answers

The volume of the composite solid is 5104 cubic ft.

What is triangular prism?

A triangular prism's volume is the area that it takes up in all three dimensions. A prism is a solid object that has the same cross-section throughout its entire length, equal bases, and flat, rectangular side faces. Prisms can be divided into many categories and given different names depending on the form of their bases. A triangular prism has three rectangular lateral sides and two identical triangular bases.

The area of a triangular prism is given as:

V = 1/2(bhl)

Here, h = 22 - 12 = 10 ft.

Substituting the values we have:

V = 1/2(13)(10)(32)

V = 2080 cubic ft.

The volume of the rectangular prism is given as:

V = lwh

V = (28)(9)(12)

V = 3024 cubic ft.

The volume of the composite solid is:

V = V1 + V2

V = 2080 + 3024

V = 5104 cubic ft.

Hence, the volume of the composite solid is 5104 cubic ft.

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Numeric For the following exercises, use the given information to find the unknown value. 24.yvaries directly asx. Whenx=3, theny=12. Findywnehx=20. 25.yvaries directly as the square ofx. Whenx=2, theny=16. Findywhenx=8. 26.yvaries directly as the cube ofx. Whenx=3, theny=5. Findywhenx=4

Answers

When x = 4, y = 320/27.

If y varies directly as x, it means that y = kx, where k is a constant. To find k, we can use the given information:

When x = 3, y = 12

12 = k * 3

k = 4

Now that we know k, we can find y when x = 20:

y = k * x

y = 4 * 20

y = 80

Therefore, when x = 20, y = 80.

25. If y varies directly as the square of x, it means that y = k * x^2, where k is a constant. To find k, we can use the given information:

When x = 2, y = 16

16 = k * 2^2

k = 4

Now that we know k, we can find y when x = 8:

y = k * x^2

y = 4 * 8^2

y = 4 * 64

y = 256

Therefore, when x = 8, y = 256.

26. If y varies directly as the cube of x, it means that y = k * x^3, where k is a constant. To find k, we can use the given information:

When x = 3, y = 5

5 = k * 3^3

k = 5/27

Now that we know k, we can find y when x = 4:

y = k * x^3

y = 5/27 * 4^3

y = 5/27 * 64

y = 320/27

Therefore, when x = 4, y = 320/27.

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What is the coordinate point of the red dot on the graph?

(3, 2)

(-2, 3)

(2, -3)

(3, -2)

Answers

Answer:

(2,-3)

Step-by-step explanation:

Given the population growth model 12000/3+e^−.02(t) , what is
the initial population and what is the maximum population?

Answers

The initial population is 4001 and the maximum population is 4000

The given population growth model is [tex]12000/3+e^{-0.02(t)}.[/tex]

To find the initial population, we need to plug in t=0 into the equation.

[tex]12000/3+e^{-0.02(0)}[/tex]

= [tex]12000/3+1[/tex]

= [tex]4000+1[/tex]

= [tex]4001[/tex]

So the initial population is 4001.

To find the maximum population, we need to find the limit of the equation as t approaches infinity.


= [tex]12000/3+0[/tex]

= [tex]4000[/tex]

So the maximum population is 4000.

In conclusion, the initial population is 4001 and the maximum population is 4000.

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Find k so that when x^(3)+kx^(2)+k^(2)x+14 is divided by x+2, the remainder is 0.

Answers

The values of k that make the remainder 0 when x^(3)+kx^(2)+k^(2)x+14 is divided by x+2 are 3 and -1.

To find k so that when x^(3)+kx^(2)+k^(2)x+14 is divided by x+2, the remainder is 0, we can use the Remainder Theorem. The Remainder Theorem states that if a polynomial f(x) is divided by x-a, the remainder is f(a).

So, if we let f(x) = x^(3)+kx^(2)+k^(2)x+14 and a = -2, we can find the value of k that makes the remainder 0.

f(-2) = (-2)^(3)+k(-2)^(2)+k^(2)(-2)+14 = 0

Simplifying the equation, we get:

-8 + 4k - 2k^(2) + 14 = 0

-2k^(2) + 4k + 6 = 0

Dividing by -2, we get:

k^(2) - 2k - 3 = 0

Factoring the equation, we get:

(k-3)(k+1) = 0

So, k = 3 or k = -1.

Therefore, the values of k that make the remainder 0 when x^(3)+kx^(2)+k^(2)x+14 is divided by x+2 are 3 and -1.

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26. G(9, 12), H(−2, −15), J(3, 8) and
G'(9, -2), H'(-2, 25), J'(3, 2)

Answers

The transformation between the points is (x, y) = (x, -y + 10)

How to determine the transformation

From the question, we have the following parameters that can be used in our computation:

G(9, 12), H(−2, −15), J(3, 8) and

G'(9, -2), H'(-2, 25), J'(3, 2)

We can see that the x coordinates of the image and the preimage are equal

However, the relationship between the y-coordinates is

y' = -y + 10

This means that

(x, y) = (x, -y + 10)

The above rule is a translation transformation

Translation transformation is a transformation that moves each point in a figure or object by a fixed distance in a specified direction.

Hence, the transformation is (x, y) = (x, -y + 10)

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Complete question

26. G(9, 12), H(−2, −15), J(3, 8) and G'(9, -2), H'(-2, 25), J'(3, 2)

Write out the transformation rule from GHJ to G'H'J'

4. IQ (intelligence) tests are usually specified so that scores are normally distributed with a mean of 100 over the entire population. Suppose that a certain IQ test is designed to have a mean of 100 and standard deviation of 10. (a) What is the probability that a randomly selected individual from the population will score between 90 and 110 on this test? (b) An employer wishes to identify potential "high flyers" and intends to do this using the outcome of the IQ test. If the employer offers these positions to people with IQs in the top 1% of the population, what is the score the employer will use to decide job offers?

Answers

The probability that a randomly selected individual will score between 90 and 110 on this test is 0.6826. The score the employer will use to decide job offers is 123.3 to decide job offers for potential "high flyers."

The IQ test is designed to have a mean of 100 and a standard deviation of 10. This means that the test follows a normal distribution with a mean of 100 and a standard deviation of 10.

(a) The probability that a randomly selected individual from the population will score between 90 and 110 on this test can be found using the standard normal distribution table. We need to find the z-scores for 90 and 110 and then use the table to find the corresponding probabilities.

The z-score for 90 is (90 - 100) / 10 = -1
The z-score for 110 is (110 - 100) / 10 = 1

Using the standard normal distribution table, we find that the probability for a z-score of -1 is 0.1587 and the probability for a z-score of 1 is 0.8413.

The probability that a randomly selected individual will score between 90 and 110 is the difference between these two probabilities:

0.8413 - 0.1587 = 0.6826

So the probability that a randomly selected individual will score between 90 and 110 on this test is 0.6826.

(b) The employer wants to identify potential "high flyers" and intends to do this using the outcome of the IQ test. If the employer offers these positions to people with IQs in the top 1% of the population, we need to find the z-score that corresponds to the top 1% of the population.

Using the standard normal distribution table, we find that the z-score that corresponds to the top 1% of the population is 2.33.

Now we can use the z-score formula to find the corresponding IQ score:

z = (x - mean) / standard deviation

2.33 = (x - 100) / 10

Solving for x, we get:

x = (2.33 * 10) + 100 = 123.3

So the employer will use a score of 123.3 to decide job offers for potential "high flyers."

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Assume that A is a matrix with three rows. Find the matrix B such that BA gives the matrix resulting from A after the given row operations are performed.3R3​+R1​⇒R1​−7R2​⇒R2​​B=

Answers

The matrix B such that BA gives the matrix resulting from A after the given row operations are performed.3R3​+R1​⇒R1​−7R2​⇒R2​​B= is B = [[1, 0, 3], [0, -7, 0], [0, 0, 1]].

Assuming that A is a matrix with three rows, we can find the matrix B such that BA gives the matrix resulting from A after the given row operations are performed.3R3​+R1​⇒R1​−7R2​⇒R2​​B= by following these steps:

1. Start with the identity matrix, I, which is a matrix with ones along the main diagonal and zeros everywhere else:
I = [[1, 0, 0], [0, 1, 0], [0, 0, 1]]

2. Apply the first row operation, 3R3​+R1​⇒R1​, to the identity matrix by adding three times the third row to the first row:
I = [[1+3(0), 0+3(0), 0+3(1)], [0, 1, 0], [0, 0, 1]]
I = [[1, 0, 3], [0, 1, 0], [0, 0, 1]]

3. Apply the second row operation, −7R2​⇒R2​, to the identity matrix by multiplying the second row by -7:
I = [[1, 0, 3], [0*(-7), 1*(-7), 0*(-7)], [0, 0, 1]]
I = [[1, 0, 3], [0, -7, 0], [0, 0, 1]]

4. The resulting matrix, I, is the matrix B that we are looking for:
B = [[1, 0, 3], [0, -7, 0], [0, 0, 1]]

Therefore, the matrix B such that BA gives the matrix resulting from A after the given row operations are performed.3R3​+R1​⇒R1​−7R2​⇒R2​​B= is B = [[1, 0, 3], [0, -7, 0], [0, 0, 1]].

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Jimmy is paying for a meal with group of friends. They received great service, so he is giving a 20% tip. The meal came to 166.60 before sales tax. How much will he leave as a tip?
Tip=$

Answers

Jimmy will leave a $33.32 tip for the great service.

What is the total of the cost?

Whole cost is the sum of all expenditures made to generate a certain level of production; when this total cost is divided by the amount produced, average or unit cost is discovered.

To calculate the tip, we need to first find 20% of the total cost of the meal (before sales tax):

20% of 166.60 = 0.20 x 166.60 = 33.32

Therefore, Jimmy will leave a $33.32 tip for the great service.

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A spinner is divided into three equal parts A, B, and C. The repeated experiment of spinning the spinner twice is simulated 125 times. A table of outcomes is shown.


Outcome Frequency
A, A 15
A, B 12
A, C 10
B, A 18
B, B 15
B, C 17
C, A 11
C, B 13
C, C 14

Based on the table, for what probability can you expect the spinner to not land on A?
0.66
0.47
0.33
0.10

Answers

The probability of the spinner not landing on A is 0.47.

How to find the probability you can expect the spinner to not land on A?

To find the probability that the spinner does not land on A, we need to add up the frequencies of the outcomes where A does not appear, which are (B,B), (B,C), (C,B), and (C,C):

Frequency of not landing on A = Frequency(B,B) + Frequency(B,C) +  Frequency(C,B) + Frequency(C,C)

Frequency of not landing on A = 15 + 17 + 13 + 14 = 59

The total number of outcomes is 125, so the probability of not landing on A is:

P(not A) = Frequency of not landing on A / Total number of outcomes

P(not A) = 59 / 125 = 0.47

Therefore, the probability of the spinner not landing on A is 0.47.

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Employees frequently need to work in team projects. We examine the difference in the team efficiency, when employees work in teams through distance working (e.g. with online meetings) in relation to teamwork with physical presence. Data are collected from a sample of 87 employees that have worked in a team project through online meetings and 74 employees that have worked in a team with physical presence. The employees filled a questionnaire, where one question was "The teamwork was efficient", on a scale from 1-5, where 1=strongly disagree and 5=strongly agree. The mean score in this question for the team that had used online meetings was 2.63, with a standard deviation of 0.92, while for the team that had worked with physical presence the mean was 2.35, with a standard deviation of 0.81. Test if teamwork with distance meetings appears to be generally more efficient for employees, in relation to teamwork with physical presence. Use a 1% level of significance.

Answers

This hypothesis test indicates that the team efficiency when working through distance working (e.g. with online meetings) is not generally more efficient than when working with physical presence.

The research question being examined is whether teams that work through distance working (e.g. with online meetings) are generally more efficient than those that work with physical presence. To answer this question, a hypothesis test can be used with a 1% level of significance.

The null hypothesis (H0) is that there is no difference in team efficiency between those teams that work through distance working (e.g. with online meetings) and those that work with physical presence. The alternative hypothesis (H1) is that there is a difference in team efficiency between those teams that work through distance working (e.g. with online meetings) and those that work with physical presence.

To test this hypothesis, a two-tailed independent t-test was used. The mean score for the team that had used online meetings was 2.63 with a standard deviation of 0.92 and for the team that had worked with physical presence the mean was 2.35 with a standard deviation of 0.81. The t-statistic obtained was 1.71 and the corresponding p-value was 0.093.

Since the p-value (0.093) is not less than the level of significance (0.01), the null hypothesis cannot be rejected. Therefore, the data suggests that there is not a significant difference in team efficiency between those teams that work through distance working (e.g. with online meetings) and those that work with physical presence.

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Compare the similarities and differences between Binomial and Normal distributions.
.What types of data does each use?
.What kinds of statistical formula and techniques are used with each?
.What similar characteristics do they share in their distributions?

Answers

Binomial and Normal distributions are two different types of probability distributions that are commonly used in statistics. Both distributions involve a set of possible outcomes, and the probability associated with each outcome.

The Binomial Distribution is used for discrete data such as coin flips, the number of defective items in a production run, and the number of wins and losses in a series of games. It is used with the formula P(x;n,p) and the techniques of probability, permutations, and combinations.

The Normal Distribution is used for continuous data such as height, weight, IQ scores, and test scores. It is used with the formula P(x;μ,σ) and the techniques of statistics, standardization, and z-scores.

Both distributions have the same basic shape and the same basic idea of a probability of a certain outcome. The main difference between them is that the Binomial Distribution is discrete and the Normal Distribution is continuous.

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Which of the following proves these triangles as congruent?

Answers

Answer:

AAS

Step-by-step explanation:

Answered this question before on Acellus.

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