Answer:
George must run the last half mile at a speed of 6 miles per hour in order to arrive at school just as school begins today
Step-by-step explanation:
Here, we are interested in calculating the number of hours George must walk to arrive at school the normal time he arrives given that his speed is different from what it used to be.
Let’s first start at looking at how many hours he take per day on a normal day, all things being equal.
Mathematically;
time = distance/speed
He walks 1 mile at 3 miles per hour.
Thus, the total amount of time he spend each normal day would be;
time = 1/3 hour or 20 minutes
Now, let’s look at his split journey today. What we know is that by adding the times taken for each side of the journey, he would arrive at the school the normal time he arrives given that he left home at the time he used to.
Let the unknown speed be x miles/hour
Mathematically;
We shall be using the formula for time by dividing the distance by the speed
1/3 = 1/2/(2) + 1/2/x
1/3 = 1/4 + 1/2x
1/2x = 1/3 - 1/4
1/2x = (4-3)/12
1/2x = 1/12
2x = 12
x = 12/2
x = 6 miles per hour
Which property was used to write the equation in step 2? Step 1: 5 (x minus 7) = 55. Step 2: 5 x minus 35 = 55. Step 3: 5 x = 90. Step 4: x = 18.
Answer:
Distributive Property
Step-by-step explanation:
If we have an equation where we multiply something in parentheses by a certain term, then we can apply the distributive property to simplify it.
In this case: [tex]5(x-7)=55[/tex]
We can multiply [tex]x-7[/tex] by 5 to simplify this equation - this is the distributive property.
[tex]5x - 35 = 55[/tex]
So the property used to write the equation in Step 2 was the distributive property.
Hope this helped!
Answer:
the answer is didrtbutive
Step-by-step explanation:
hope it helps.
have a good day:)
can u solve these asap pls
Step-by-step explanation:
1We will use the Thales theorem since ED and CB are parallel and A,D and B are in the same lign wich is the same for C,E and A
[tex]\frac{x}{12}[/tex] = [tex]\frac{2}{2+4}[/tex] [tex]\frac{x}{12}[/tex] = [tex]\frac{2}{6}[/tex] [tex]\frac{x}{12}[/tex] = [tex]\frac{1}{3}[/tex] x= [tex]\frac{12*1}{3}[/tex] x= 4 2since we have two similar sides and one similar angle between them it will be SAS similarity
Solve the inequality. |2k + 1| ≥ 5
Answer: k ≥ 2 and k ≤ -3
Step-by-step explanation:
When answering a problem like this, normally, you first isolate the absolute value. As it is already isolated, the next thing you do is split the equation into 2k + 1 ≥ 5 and 2k + 1 ≥ -5, because the contents of the absolute value could be negative or positive, and simplifying both into k ≥ 2, and k ≤ -3.
Hope it helps <3
4 lemon are brought for Rs. 10 and sold 3 for Rs. 10 ,what is the profit %
Answer:
The profit is Rs 2.5Step-by-step explanation:
In other to solve for the profit we have to solve for the unit cost of one lemon first
If 4 lemons cost Rs. 10
then 1 lemon will cost= 10/4= Rs 2.5
knowing that one cost Rs 2.5
cost price of three would be 3* Rs 2.5= Rs 7.5
Since three was sold for Rs. 10.
The profit made is
cost of three- selling price of three= Rs. 10- Rs 7.5= Rs 2.5
The mean amount spent by a family of four on food per month is $500 with a standard deviation of $75. Assuming that the food costs are normally distributed, what is the probability that a family spends less than $410 per month?
Answer:
The probability that a family spends less than $410 per month
P( X < 410) = 0.1151
Step-by-step explanation:
Step(i):-
Given mean of the population = 500
Given standard deviation of the Population = 75
Let 'X' be the variable in normal distribution
[tex]Z = \frac{x-mean}{S.D}[/tex]
Given X = $410
[tex]Z = \frac{410-500}{75} = - 1.2[/tex]
Step(ii):-
The probability that a family spends less than $410 per month
P( X < 410) = P( Z < - 1.2 )
= 0.5 - A( -1.2)
= 0.5 - A(1.2)
= 0.5 - 0.3849 ( ∵from normal table)
= 0.1151
Final answer:-
The probability that a family spends less than $410 per month
P( X < 410) = 0.1151
Help ASAP! Will award brianliest!
Answer:
1: yes AB2×4
2:not possible
3:(11,2)
(20,12)
Step-by-step explanation:
1:compare the orders given which is 2×3 and 3×4 so to get if it's possible to multiply you just cancel out the same numbers if present i.e 3
2:so I took the first column of m multiply the first row of n (add values you get i.e -2×1+1×-4+0×2=-6) but on the second value of the first row I got 8 not 3 so I said not possible
3 you multiply row by column
(1×1+0×7+2×5=11. 1×4+0×2+-2×1=2)
(3×1+1×7+2×5=20. 3×4+1×2+2×-1=12)
therefore
(11,2)
(20,12)
The gray figure has been transformed in different ways.
Tell whether each statement is True or False.
Answer:
False ,false,true, true and true
Step-by-step explanation:
An employee is paid a salary of \$73,840 per year, plus benefits and overtime (time and a half) on hours worked over 40 per week, working as a civil servant. What is the regular time hourly rate of pay for this employee, and what is her total income in a month where she works 40 hours, 44 hours, 43.5 hours, and 40 hours, weekly, in the month?
A.$37.00/hr and \$6,336.25 in total income
B. $35.50/hr and \$6,079.38 in total income
C.$37.50/hr and \$6,421.88 in total income
D.$36.00/hr and \$6,165.00 in total income
Answer:
B. $35.50/hr and \$6,079.38 in total income
Step-by-step explanation:
Given the following :
Total regular pay earning for the year = $73,840
Let basic salary = b
Overtime = 1.5b
Regular earning per week :
Regular year earning / number of weeks per year
$73840 / 52 = $1420
Regular hours = 40
Regular earning per week = $1420
Regular earning per hour = $1420 / 40
Regular earning per hour = $35.50
Number of overtime hours :
4 hours + 3.5hours = 7.5hours
Overtime pay per hour = 1.5 * regular earning
Overtime pay per hour = 1.5 * 35.5 = $53.25
Total overtime pay = Overtime pay per hour * Number of overtime hours
Total overtime pay = $53.25 * 7.5
Total overtime pay = 399.375
Total pay for the month :
160 regular hours + 7.5 overtime hours
(160 * 35.5) + $399.375
$5,680 + 399.375 = $6,079.375
= $6,079.38
A large explosion causes wood and metal debris to rise vertically into the air with an initial velocity of 96 feet per second. The quadratic function h(t)=96t−16t2 gives the height h (in feet) of the debris at time t (in seconds) after the explosion. How many seconds will it take before the debris falls back to the ground?
Answer:
6 seconds
Step-by-step explanation:
We have to find the t-intercepts of the function. To do so, let's set h(t) = 0.
0 = 96t - 16t²
0 = 16t(6 - t) -- Factor 96t - 16t²
16t = 0 or 6 - t = 0 -- Use Zero Product Property
t = 0 or t = 6 -- Solve for t
We're not looking for the solution t = 0 because that represents when the debris was launched. Therefore, the answer is 6 seconds.
Answer: 6 seconds
Step-by-step explanation: factor
Eparture time of a car is 0540 hours and it traveled for 45 minutes before it reached its destination. At what time did the car arrived at its destination : *
Answer:
The time at which the car arrives at its destination is 0625 hours or 6: 25 am or 25 minutes past 6.
Step-by-step explanation:
Departure time = 0540 Hours means 5: 40 am or 40 minutes past 5 in the morning.
Now add 45 mins
Hours : Minutes
5: 40
+ 45
5 : 85
But 1 hour contains 60 minutes so 85 - 60 gives 25 minutes . those 60 minutes = 1 hour are carried over the hours and added .
Hours : Minutes
1
5: 40
+ 45
6 : 25
The time at which the car arrives at its destination is 0625 hours or 6: 25 am or 25 minutes past 6 in the morning.
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP(25 points)
Answer: I hope it helps :)
x=6 , y=6√3x =23√3 , y=23u =12 , v= 6a =18√2 , b =18x = 13 , y= 13Step-by-step explanation:
1.
[tex]Hypotenuse =x\\Opposite =y \\Adjacent =6\\\alpha = 6\\Let's\: find\: the \:hypotenuse\: first\\Using SOHCAHTOA\\Cos \alpha = \frac{adj}{hyp} \\Cos 60 = \frac{6}{x} \\\frac{1}{2} =\frac{6}{x} \\Cross\:Multiply\\x = 12\\Let's\: find\: y\\Hyp^2=opp^2+adj^2\\12^2=y^2+6^2\\144=y^2+36\\144-36=y^2\\108=y^2\\\sqrt{108} =\sqrt{y^2} \\y=6\sqrt{3}[/tex]
2.
[tex]Opposite =x\\Hypotenuse = 46\\Adjacent =y \\\alpha =60\\Using \: SOHCAHTOA\\Sin \alpha =\frac{opp}{adj} \\Sin 60=\frac{x}{46}\\\\\frac{\sqrt{3} }{2} =\frac{x}{46} \\2x=46\sqrt{3} \\x = \frac{46\sqrt{3} }{2} \\x =23\sqrt{3} \\\\Hyp^2=opp^2+adj^2\\46^2=(23\sqrt{3} )^2+y^2\\2116=1587+y^2\\2116-1587=y^2\\529=y^2\\\sqrt{529} =\sqrt{y^2} \\y = 23[/tex]
3.
[tex]Hypotenuse = u\\Opposite =6\sqrt{3} \\Adjacent = v\\\alpha =60\\Sin\: 60 = \frac{6\sqrt{3} }{u} \\\frac{\sqrt{3} }{2} =\frac{6\sqrt{3} }{u} \\12\sqrt{3} =u\sqrt{3} \\\\\frac{12\sqrt{3} }{\sqrt{3} } =\frac{u\sqrt{3} }{\sqrt{3} } \\u = 12\\Hyp^2=opp^2+adj^2\\12^2= (6\sqrt{3} )^2+v^2\\144=108+v^2\\144-108=v^2\\36 = v^2\\\sqrt{36} =\sqrt{v^2} \\\\v =6[/tex]
4.
[tex]Hypotenuse = a\\Opposite =18 \\Adjacent = b\\\alpha =45\\Tan \alpha = opp/adj\\Tan \:45 =18/b\\1=\frac{18}{b}\\ b = 18\\\\Hyp^2=Opp^2+Adj^2\\a^2 = 18^2+18^2\\a^2=324+324\\a^2=648\\\sqrt{hyp^2} =\sqrt{648}\\ \\a =18\sqrt{2}[/tex]
5.
[tex]Hypotenuse = 13\sqrt{2}\\ Opposite =x\\Adjacent = y\\\alpha =45\\Sin\:\alpha = opp/hyp\\Sin 45=x/13\sqrt{2}\\ \\\frac{\sqrt{2} }{2} =\frac{x}{13\sqrt{2} } \\2x=26\\2x/2=26/2\\\\x = 13\\\\Hyp^2=opp^2+adj^2\\(13\sqrt{2})^2=13^2+y^2\\ 338=169+y^2\\338-169=y^2\\169=y^2\\\sqrt{169} =\sqrt{y^2} \\13 = y[/tex]
Is 3/4 = 9/12 greater or less than 1/2
Answer:
greater than
Step-by-step explanation:
To compare 3/4 to 1/2, let's convert 1/2 so that it has a denominator of 4. This would then be 2/4. Because 3 > 2, 3/4 > 2/4 which means 3/4 > 1/2.
Answer:
Greater
Step-by-step explanation:
It is greater than 1/2 because when you divide the fractions you get- 1/2 = 0.5, 3/4 = 0.75 And this makes it greater.
Evaluate w+(-x)-2/3 where w= 5/9 and x=4/3
Answer:
-1/24
Step-by-step explanation:
Plug in X and W
5/8 - 4/3 - 2/3.
Combine like terms.
5/8 - 2/3.
Solve.
-1/24
Answer:
- 2 1/10
Step-by-step explanation:
Given the sequence -3, 9, -27, 81, -243, ..., find the recursive formula.
Answer:
[tex]a_{n}[/tex] = - 3[tex]a_{n-1}[/tex]
Step-by-step explanation:
There is a common ratio between consecutive terms of the sequence, that is
r = 9 ÷ - 3 = - 27 ÷ 9 = 81 ÷ - 27 = - 243 ÷ 81 = - 3
The recursive formula is of the form
[tex]a_{n}[/tex] = r[tex]a_{n-1}[/tex] = - 3[tex]a_{n-1}[/tex]
can anyone help me please
Answer:
It is -1
Step-by-step explanation:
You have to use pemdas, so 5 squared is 25. Than 25 times 4 is 100. Than 2-100 is -98. Than -98/7 is -14. Than you have to add 12 and 1 so the answer is -1.
the answer of mine is also 5
Hexagon DEFGHI is translated on the coordinate plane below to create hexagon D'E'F’G’H’I’
Which rule represents the translation of hexagon DEFGHI to hexagon D’E’F’G’H’I’?
(x,y)—> (x-8,y-7)
(x,y) —> (x-7,x-8)
(x,y) —> ( x-4,x-5)
(x,y) —> ( x-5,y-4)
Answer:
The answer is "[tex]\bold{(x,y)\longrightarrow (x-8, y-7)}[/tex]".
Step-by-step explanation:
In the given question some data is missing. so, the correct answer to this can be explained in the following example:
In the given example, point D is also known as the coordinates in the (2, 5), and in the coordination of the D prime (D') and after translation its co-ordinates value is (-6, -2). Since the very first choice is only accurate as:
⇒2-8 = -6
⇒ 5-7 = -2
It can try certain things too and see why this alone is the correct translation.
Kermit's favorite iced tea is made with 15 1515 tea bags in every 2 22 liters of water. Peggy made a 12 1212-liter batch of iced tea with 90 9090 tea bags. What will Kermit think of Peggy's iced tea?
Correct question is;
Kermit's favorite iced tea is made with 15 tea bags in every 2 liters of water. Peggy made a 12-liter batch of iced tea with 90 tea bags. What will Kermit think of Peggy's iced tea? Choose 1 answer: (Choice A) A It is too strong.
(Choice B) B It is too weak.
(Choice C, Checked) C It is just right.
Answer:
C - It is just right
Step-by-step explanation:
We are given that;
The Number of tea bags needed to make every 2 liters of water = 15 tea bags.
Thus,
For each liter of water, the number of tea bags needed = 15/2 = 7.5 tea bags.
Now, kermit needs to make 12 liters of iced tea.
Therefore, total number of tea bags required for 12 liters of iced tea = 12 × 7.5 = 90 tea bags.
Now, Peggy also took 90 tea bags to make a 12-liter batch of iced tea.
Therefore, kermit would think that the mixture of Peggy's tea is just right.
Correct option is C
Yo can someone please help me
Answer:
Addition Property of EqualityStep-by-step explanation:
When doing algebra, you need to reverse operations. When you reverse an operation, you use one of the properties. For example, if you add 3x to undo subtracting 3x, you are using the addition property of equality, because the equation still equal.
I'm always happy to help :)A large company is hosting a conference. So far, a total of 3,922 people have signed up, including 26 from united states. How many people from other countries have signed up?
Answer:
3,896 have signed up from other countries
Step-by-step explanation:
In this problem we are required to calculate the number of signups from other countries.
well, since we know the total sign ups to be 3,922
And also we know that 26 out of the total signed up from the USA
This means that the sign ups from other countries will be
3,922-26=3,896
It takes 32 minutes for 3 people to paint 4 walls. How many minutes does it take 4 people to paint 7 walls?
Answer:
Step-by-step explanation:
Assuming each person gets the same amount of work done, each wall in the first scenario takes 8 minutes to paint. If 3 people paint 4 walls, then each person is painting 1 1/3 of a wall. We can use that to find out how long it takes one person to paint 1 1/3 walls:
[tex]\frac{8min}{wall}*\frac{4}{3}walls=\frac{32}{3}min[/tex]. Interpreting that, it takes each person 10 2/3 minutes to paint 1 1/3 walls.
If 4 people paint 7 walls, that means that each person is painting 7/4 walls, or 1.75 walls each. Using the fact that it takes 10.66666 minutes to paint 1.33333 walls, we can find out how many minutes it will take to paint 1.75 walls:
[tex]\frac{10.6666}{1.33333}=\frac{x}{1.75}[/tex] Cross multiply to get
18.666655 = 1.3333x so
x = 14.000 minutes
Laura collects old foreign coins. She has 83 coins in total. She has 53 lira and drachma coins. She has 51 lira and peseta coins. How many lira coins does she have?
Answer: She has 21 lira coins.
Step-by-step explanation:
Given, Laura collects old foreign coins. She has 83 coins in total. She has 53 lira and drachma coins. She has 51 lira and peseta coins.
Let x = the number of lira coins.
y= the number of drachma coins.
z= the number of peseta coins.
Then, as per given, we have
x+y+z=83 (i)
x+y=53 (ii)
x+z=51 (iii)
From (ii) and (iii)
y=53-x
z=51-x
Put these values in (i) , we get
x+(53-x)+(51-x)=83
⇒ x+53-x+51-x=83
⇒ 104-x=83
⇒104-83=x
⇒x= 21
Hence, she has 21 lira coins.
Kendra rides a bicycle on a path that is 84 miles her average speed is 7 miles per hour to find about how long the trip takes solve the distance formula d = rt for t then substitute to find the time the trip takes
Answer:
Hello There!
~~~~~~~~~~~~~~~~~~
Kendra is planning to ride her bike that is 84 miles long. She plans to average 7 miles per hour. How long will the trip take?
-----
time = distance/rate
-----
t = 84 miles/7 m/hr = (84/7)hrs = 12 hrs.
Cheers,
Stan H.
------
So the answer is 12 hours.
------
Hope this helped you. Brainliest would be nice!
find the value of x. 43°
Answer: x = 137°
Step-by-step explanation:
When a quadrilateral is inscribed in a circle, the opposite angles are supplementary.
x + 43° = 180°
x = 137°
The value of x is 137°.
What is inscribed quadrilateral?The quadrilateral whose all 4 vertices lie on the circumference of the circle is called an inscribed quadrilateral.
In inscribed quadrilateral opposite angles are supplementary i.e. sum of those opposite angles is 180°.
Here given in the picture that the measurements of the two opposite angles in the inscribed quadrilateral in the circle are 43° and x°.
So as we know in the inscribed quadrilateral opposite angles are supplementary.
So sum of those opposite angles in the quadrilateral is 180°.
so we can write x+43°= 180°
⇒ x = 180°- 43°
⇒ x = 137°
Therefore the value of x is 137°.
Learn more about inscribed quadrilateral
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pleaseeeeeeeeee helllllllpppppp pleaseeeeee hellpppp
Answer:
a. u = 19b. t = 6c. a = 2Step-by-step explanation:
a. Given,
v = 34 , a = 5 , t = 3
[tex]v = u + at[/tex]
plugging the values:
[tex]34 = u + 5 \times 3[/tex]
Calculate the product
[tex]34 = u + 15[/tex]
Move 'u' to L.H.S and change its sign
[tex] - u + 34 = 15[/tex]
Move constant to RHS and change its sign
[tex] - u = 15 - 34[/tex]
Calculate
[tex] - u = - 19[/tex]
The difference sign (-) will be cancelled in both sides:
[tex]u = 19[/tex]
b. Given,
v = 50 , u = 20 , a = 5
[tex]v = u + at[/tex]
plugging the values
[tex]50 = 20 + 5 \times t[/tex]
[tex]50 = 20 + 5t[/tex]
Move 5t to L.H.S and change its sign.
Similarly, Move 50 to R.H.S and change its sign
[tex] - 5t = 20 - 50[/tex]
Calculate
[tex] - 5t = - 30[/tex]
The difference sign (-) will be cancelled in both sides
[tex]5t = 30[/tex]
Divide both sides of the equation by 5
[tex] \frac{5t}{5} = \frac{30}{5} [/tex]
Calculate
[tex]t = 6[/tex]
c. Given,
v = 22 , u = 8 , t = 7
[tex]v = u + at[/tex]
plugging the values
[tex]22 = 8 + a \times 7[/tex]
[tex]22 = 8 + 7a[/tex]
Move 7a to LHS and change its sign
Similarly, Move constant to R.H.S and change its sign
[tex] - 7a = 8 - 22[/tex]
Calculate
[tex] - 7a = - 14[/tex]
The difference sign (-) will be cancelled in both sides
[tex]7a = 14[/tex]
Divide both sides of the equation by 7
[tex] \frac{7a}{7} = \frac{14}{7} [/tex]
Calculate
[tex]a = 2[/tex]
Hope this helps...
Good luck on your assignment..
If there we're 25 people in class voting,how many votes does it take to win a majority?
Answer:
it takes 13 votes to win a majority
Step-by-step explanation:
half+1 in the case of 25
it takes 13 votes to win a majority ( because there is nothing called half vote)
The quadratic equation 4x2 + 45x + 24 = 0 was solved using the Quadratic Formula, x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a. One solution is −10.69. What is the other solution? Round to the hundredths place.
Answer:
The other solution is 0.56
Step-by-step explanation:
The quadratic equation is;
4x^2 + 45x + 24
a is the coefficient of x^2 which is 4
b is the coefficient of x which is 45
c is the third number which is 24
Using the quadratic formula, we have
x = {-b ± √(b^2-4ac)}/2a
So inputing the values we have highlighted above, we have
x = {-45 ± √(45^2-4(4)(24)}/2(4)
x = {-45 ± √(2025-4(4)(24)}/2(4)
x = {-45 ± √1641}/2(4)
x = {-45 ± 40.51}/2(4)
x = (-45+40.51)/8 or (-45-40.51)/8
x = 0.56 or -10.69
Answer:
-0.56
Step-by-step explanation:
The guy above was nearly correct, not correct. He said it was positive when it is actually negative.
Hope this helps!
plzzz help class 9 optional math
If tan theta =p show that sec theta*cosec theta =p+1/p
Answer:
[tex]sec(\theta) \times cosec(\theta) = \dfrac{tan^2 (\theta)+ 1}{tan (\theta)} = tan (\theta)+ \dfrac{1}{tan (\theta)} = p + \dfrac{1}{p}[/tex]
Step-by-step explanation:
The given trigonometric relations are
tan(θ) = p
sec(θ)×cosec(θ) = p + 1/p
We note that, when tan(θ) = p, we have;
p + 1/p = tan(θ) + 1/(tan(θ)) = (tan²(θ) + 1)/tan(θ)
By trigonometric ratios, we have;
tan²(θ) + 1 = sec²(θ) =1/cos²(θ) which gives;
(tan²(θ) + 1)/tan(θ) = 1/cos²(θ) × 1/tan(θ) = cos(θ)/sin(θ)×1/cos²(θ)
[tex]\dfrac{1}{cos^2(\theta)} \times \dfrac{cos (\theta)}{sin( \theta)} = \dfrac{1}{cos(\theta)} \times \dfrac{1}{sin( \theta)} = sec(\theta) \times cosec(\theta)[/tex]
Therefore;
[tex]If \ tan (\theta) = p \ then \ sec(\theta) \times cosec(\theta) = p + \dfrac{1}{p}[/tex]
Use the quadratic formula to find the exact solutions of x2 − 5x − 2 = 0. x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a x equals 5 plus or minus the square root of 33, all over 2 x equals negative 5 plus or minus the square root of 33, all over 2 x equals 5 plus or minus the square root of 17, all over 2 x equals negative 5 plus or minus the square root of 17, all over 2
Answer:
x = [ -b +- sqr root (b^2 - 4ac)] / 2a
a = 1
b = -5
c = -2
x = [- - 5 +- sqr root (-5^2 -4 * 1 * -2)] / 2 * 1
x = [5 +- sqr root (25 + 8)] / 2
x1 = 5.3723
x2 =-0.37228
Step-by-step explanation:
Exact solution for the give quadratic equation are
[tex]x=\frac{5+\sqrt{33}}{2},\:x=\frac{5-\sqrt{33}}{2}[/tex]
Quadratic EquationQuadratic equation of the form [tex]ax^2+bx+c=0[/tex]
For any quadratic equation we get two values for x. we can find the values for x by applying quadratic formula .
Quadratic formula
[tex]x=\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]
Given equation is [tex]x^2-5x-2=0[/tex]
The value of a=1, b= -5 and c=-2
Substitute all the values in the formula.
To find out exact solutions , we need to simplify the final answer.
Exact solutions are without any decimals.
[tex]x=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:1\cdot \left(-2\right)}}{2\cdot \:1}\\x=\frac{-\left(-5\right)\pm \sqrt{33}}{2\cdot \:1}\\x=\frac{-\left(-5\right)\p+ \sqrt{33}}{2\cdot \:1}\\\\x=\frac{5+\sqrt{33}}{2}\\\\x=\frac{-\left(-5\right)- \sqrt{33}}{2\cdot \:1}\\\\x=\frac{5-\sqrt{33}}{2}\\[/tex]
Exact solutions are
[tex]x=\frac{5+\sqrt{33}}{2},\:x=\frac{5-\sqrt{33}}{2}[/tex]
Learn more information about 'Quadratic formula ' here
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Graph the data set.
{(-1, 0.5), (0, 1), (1, 2), (3, 8), 5, 32)}
Which kind of model best describes the data?
a. quadratic
b. exponential
c. linear
d. cubic
Answer:
b. Exponential
Step-by-step explanation:
We are given the coordinates as the data set:
[tex]\bold{\{(-1, 0.5), (0, 1), (1, 2), (3, 8), (5, 32)\}}[/tex]
First of all, let us plot the given coordinates on the xy coordinate axis.
Let us have a look at the values of x and y first.
A pair is represented as (x, y) i.e. first value is of 'x' and the second value is of 'y'.
[tex]\begin{center}\begin{tabular}{ c c } x & y\\ -1 & 0.5 \\ 1 & 2 \\ 2 & 4 \\ 3 & 8 \\ 5 & 32\end{tabular}\end{center}[/tex]
If we plot them on the graph, we get the graph as the image attached in the answer area.
Let us join the coordinates using a curve.
If we closely look at the graph, there is a sudden increase with increasing value of 'x'.
Actually the increase is exponential.
Observing the given coordinates, we can see that they are in the form:
[tex](x, 2^x)[/tex]
i.e. [tex]y =2^x[/tex]
So, the exponential model best describes the data.
Correct answer is:
b. exponential
A high school wants to sell postage stamps with the school logo on them. The fundraising group have purchased 500 sheets of stamps at $16/sheet plus $50 to create the image. They plan to sell each sheet for $20. a) Write an equation that represents the cost of obtaining the stamps. b) Write an equation that represents the income from sales. c) For each equation, set up a table of values. d) Graph each equation on the same set of coordinate axis. e) What is the minimum number of sheets the group must sell so they don't lose any money? f) How much profit will they make if they sell 500 sheets?
Answer:
a) Cost
[tex]C(q) = 50+16q\\\\C(500)=50+16(500)=50+8,000=8,050[/tex]
b) Sales income
[tex]S(q)=20q\\\\S(500)=20\cdot 500 = 10,000[/tex]
c) Table of values
[tex]\left[\begin{array}{ccc}q&C(q)&S(q)\\0&50&0\\250&4,050&5,000\\500&8,050&10,000\end{array}\right][/tex]
d) Attached
e) Breakeven point = 12.5 sheets
f) Profit at 550 sheets = $1,950
Step-by-step explanation:
a) We have a fixed cost for the image, at $50.
We also have a variable cost of $16 a sheet.
The purchased quantity is 500 sheets.
Then, the cost function is:
[tex]C(q) = 50+16q\\\\C(500)=50+16(500)=50+8,000=8,050[/tex]
b) The price for each sheet is $20, so the income from sales are:
[tex]S(q)=20q\\\\S(500)=20\cdot 500 = 10,000[/tex]
c) Table of values
[tex]\left[\begin{array}{ccc}q&C(q)&S(q)\\0&50&0\\250&4,050&5,000\\500&8,050&10,000\end{array}\right][/tex]
d) Attached
e) The minimum number of sheets the group must sell so they don't lose any money is the breakeven point (BEP) and can be calculated making the income sales equal to the cost:
[tex]S(q)=C(q)\\\\20q=50+16q\\\\(20-16)q=50\\\\4q=50\\\\q=50/4=12.5[/tex]
f) This profit can be calculated as the difference between the sales income and the cost:
[tex]P(500)=S(500)-C(500)\\\\P(500)=20\cdot 500-(50+16\cdot 500)=10,000-8,050=1,950[/tex]
The given number of 500 sheets of stamps purchased at $16/sheet with
a plan to sell each sheet for $20 gives the following values;
(a) Cost, C = 50 + 16·q
(b) Income, R = 20·q
(c) Please find the included table of values and the attached graph
(e) Approximately 403 sheets
(f) $1,950
Which method can be used to derive the equations?
(a) The cost per sheet of stamp = $16/sheet
The cost to create the image = $50
Amount at which they plan to sell each sheet, P = $20
Therefore
Cost of obtaining the stamps, C = 50 + 16·q(b) The income from sale, R = Number of units sold × P
Which gives;
R = 20·q(c) The table of values are therefore;
C = 50 + 16·q
[tex]\begin{array}{|c|c|c|}q&C=50+16 \times q\\0&50\\1&66\\2&82\\3&98\\4&114\\5&130\\6&146\\7&162\\8&178\\9&194\\10&210\\11&226\\12&242\\13&258\\14&274\end{array}\right][/tex]
R = 20·q
[tex]\begin{array}{|c|c|c|}q&R = 20 \times q\\0&0\\1&20\\2&40\\3&60\\4&80\\5&100\\6&120\\7&140\\8&160\\9&180\\10&200\\11&220\\12&240\\13&260\\14&280\end{array}\right][/tex]
Please find attached the required graph created with MS Excel
e) The minimum number of sheets the group must sell is given as follows;
The cost of the sheets purchased = 50 + 16 × 500
Which gives;
At point of profitability; Income = Cost
50 + 16 × 500 = 20·[tex]q_{min}[/tex]
[tex]q_{min} = \dfrac{50 + 16 \times 500}{20} =402.5 \approx \mathbf{403}[/tex]
The minimum number the sheets they must sell, [tex]q_{min}[/tex] ≈ 403 sheets(f) The profit made by selling 500 sheets is; 20·q - (50 + 16·q)
Where;
q = 500
Which gives;
20 × 500 - (50 + 16 × 500) = 1,950
The profit made from selling 500 sheet = $1,950
Learn more about graphs of functions here:
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