Gas Tank- 11 in , 1.25 ft, 1.75 ft
The gas tank is 20% full. Use the current price of gas in your community to find the cost to fill the tank (1 gal = 231 in^3
Current price = 3.79

Answer:

$45.48

Step-by-step explanation:

Given that:

Gas tank are 11 inches, 1.25 feet and 1.75 feet.

The gas tank is 20% full. Use the current price of gas in your community to find the cost to fill the tank (1 gal = 231 in³)

Current price = 3.79

Solution:

Formula: Volume = LWH

While,

L = Length

W = Width

H = Height

Since we, know that

Gas tank are 11 inches, 1.25 feet and 1.75 feet.

We have to convert either to inches or feet.

Note that: 1 feet = 12 inches

I will convert feet to inches

Thus,

1.25 × 12 = 15

1.75 × 12 = 21

Since 11 is already in inches we don't have to change that.

Now from the formula: LWH

Therefore, we have:

V = 11 × 15 × 21

V = 3465

Now, from the given the gas tank is 20% full

Finding 20%:

3465 × 20 % = 693

Now subtract to find the other 80%

3465 - 693 = 2772

Since 1 gal = 231 in ³

2772/ 231 = 12

Now, 12 mulitply by the current price of gas given:

12 × 3.79 = 45.48

Hence, the cost to fill the tank is $45.48

Kavinsky

Answer:

$45.48

Step-by-step explanation:

Convert to inches

1.25 × 12 = 15

1.75 × 12 = 21

Since 11 is already in inches we don't have to change that.

Now from the formula: LWH

Therefore, we have:

V = 11 × 15 × 21

V = 3465

Now, from the given the gas tank is 20% full

Finding 20%:

3465 × 20 % = 693

Now subtract to find the other 80%

3465 - 693 = 2772

Since 1 gal = 231 in ³

2772/ 231 = 12

Now, 12 mulitply by the current price of gas given:

12 × 3.79 = 45.48

Hence, the cost to fill the tank is $45.48

Select the equivalent expression.
\left(9^{6}\cdot 7^{-9}\right)^{-4}=?(9
6
⋅7
−9
)
−4
=?left parenthesis, 9, start superscript, 6, end superscript, dot, 7, start superscript, minus, 9, end superscript, right parenthesis, start superscript, minus, 4, end superscript, equals, question mark
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
9^{24}\cdot 7^{-36}9
24
⋅7
−36
9, start superscript, 24, end superscript, dot, 7, start superscript, minus, 36, end superscript

(Choice B)
B
\dfrac{9^{24}}{7^{36}}
7
36

9
24

​
start fraction, 9, start superscript, 24, end superscript, divided by, 7, start superscript, 36, end superscript, end fraction

(Choice C)
C
\dfrac{7^{36}}{9^{24}}
9
24

7
36

​
start fraction, 7, start superscript, 36, end superscript, divided by, 9, start superscript, 24, end superscript, end fraction

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