The charge stored in the capacitor is 36 coulombs.
When the voltage across a capacitor is 12 volts and its capacitance is 3 farads, the amount of charge stored in it is 36 coulombs.
What is voltage?
The voltage is the electric potential difference between two points in a circuit, or it may be the driving force that causes current to flow. The charge q stored in a capacitor with a capacitance C when a voltage V is applied is given by: q = CV, where q is the charge stored in the capacitor, C is the capacitance of the capacitor, and V is the voltage applied to the capacitor. A 3-farad capacitor that is charged to 12 volts stores 36 coulombs of charge. Therefore, 36 coulombs of charge is stored in it.
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changing the inner radius automatically changes the angular velocity to 36 degrees / s. why? (make sure to mention moment of inertia and angular momentum in your answer.)
Changing the inner radius automatically changes the angular velocity to maintain the conservation of angular momentum. Changing the inner radius of a rotating object changes its moment of inertia, which is a measure of its resistance to rotational motion.
The moment of inertia depends on the distribution of mass within the object, as well as the shape and size of the object. In this case, since the angular velocity changes to 36 degrees per second, we can conclude that the moment of inertia of the rotating object has increased.
According to the conservation of angular momentum, the product of the moment of inertia and angular velocity remains constant for a rotating object. Mathematically, we can express this principle as:
I1 x ω1 = I2 x ω2
Where I1 and I2 are the initial and final moments of inertia, and ω1 and ω2 are the initial and final angular velocities, respectively.
In this scenario, if we increase the inner radius of the rotating object, its moment of inertia will increase. Since the angular momentum must remain constant, the angular velocity must decrease to compensate for the increase in moment of inertia. Similarly, if we decrease the inner radius, the moment of inertia will decrease, and the angular velocity must increase to conserve angular momentum.
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a car is travelling with a speed of 36km/h,with acceleration of 2.5m/s2.What velocity
does the car gain after 30s.Find the velocity in S.I. unit
Explanation:
first convert the km/hr in m/s and apply the formula:v=u+at
then put all the values given
;here 36km/hr is the initial velocity(u)
acceleration(a)=2.5m/s²
time=30sec.
A car acquires velocity of 72km/h
in 10s starting from start.. Calculate it's average velocity, acceleration and distance travelled during this period.
Answer:
Avg. Velocity = 10 m/s
Acceleration = 2 m/s^2
Distance = 100 m
Explanation:
First, we need to convert the velocity of the car from km/h to m/s, since the standard unit of velocity in SI units is meters per second.
72 km/h = 20 m/s (to 2 significant figures)
We can now calculate the average velocity of the car using the formula:
average velocity = total distance ÷ total time
Since the car starts from rest, its initial velocity is 0 m/s. Therefore, the total distance it travels during the 10 seconds is:
distance = (1/2) × acceleration × time²
where acceleration is the constant acceleration of the car during the 10 seconds, which we do not know yet.
To find the acceleration, we can use the formula:
final velocity = initial velocity + acceleration × time
The final velocity of the car is 20 m/s (which we calculated earlier), the initial velocity is 0 m/s, and the time is 10 seconds. Therefore:
20 m/s = 0 m/s + acceleration × 10 s
Solving for acceleration:
acceleration = 2 m/s²
Substituting this value of acceleration into the formula for distance, we get:
distance = (1/2) × 2 m/s² × (10 s)² = 100 meters
Therefore, the average velocity of the car during the 10 seconds is:
average velocity = total distance ÷ total time = 100 meters ÷ 10 seconds = 10 m/s
The acceleration of the car during the 10 seconds is 2 m/s², and the distance travelled by the car during this period is 100 meters.
a he ion (charge e, mass 4u) with an initial speed of 1.0 * 105 m/s is brought to rest by an electric field. a. did the ion move into a region of higher potential or lower potential?
The He ion moved into a region of higher potential.
When the He ion (charge e, mass 4u) with an initial speed of 1.0 * 10⁵ m/s enters an electric field, it experiences a force due to the electric field. Since the ion is positively charged, it is attracted to the negative plate and repelled by the positive plate.
As it moves towards the negative plate, it moves into a region of higher electric potential. This is because the potential difference between the plates causes the ion to decelerate until it comes to rest.
The work done by the electric field on the ion is equal to the change in kinetic energy, which confirms that the ion moved into a region of higher potential.
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it is the chance high or low that any hazard will actually cause somebody harm
Answer:
So long it's a "hazard" by literal definition, there is a high chance of harm once it touches or interacts with a being.
Someone help me pls!!!
Answer:
Student 2 (B)
Explanation:
ignore the explanation I need 20 characters to add an answer
a ball is attached to the end of a string. it is swung in a vertical circle of radius 1.33 m. what is the minimum velocity that the ball must have to make it around the circle?.
Answer:
v = 3.61210464965 m/s
Explanation:
∑F = ma
Centripetal acceleration is mv^2/r and the ball is under a force of gravity
[tex]F=ma\\\\mg = \frac{mv^2}{r}\\\\v=\sqrt{gr} \\\\v=\sqrt{(9.81m/s^2)(1.33m)} \\\\v=3.61210464965m/s[/tex]
The minimum velocity that the ball must have to make it around the vertical circle is 3.66 m/s.
When the ball is swung in a vertical circle, there are two forces acting on the ball, which are the gravitational force and the tension force in the string. When the velocity of the ball is minimum, the gravitational force will be equal to the tension force in the string.
The centripetal force is also equal to the gravitational force. This can be expressed mathematically as:
[tex]\frac{mv^2}{R} = mg + T[/tex]
Where m is the mass of the ball, v is its velocity, R is the radius of the vertical circle, g is the acceleration due to gravity, and T is the tension force in the string. Rearranging the formula gives:
[tex]v^2 = Rg + R*(\frac{T}{m})[/tex]
We can see that the minimum velocity of the ball is achieved when T is minimum. At the top of the circle, T is minimum, which means:
[tex]v^2 = Rg[/tex]
So, [tex]v = \sqrt{(Rg)} = \sqt{(1.33 * 9.81)} = 3.66[/tex] m/s
Therefore, the minimum velocity that the ball must have to make it around the vertical circle is 3.66 m/s.
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If a truck with a frequency of 85.0 Hz is traveling toward an observer with a speed of 27.0 m/s, what frequency does the observer hear as the truck approaches?
how does the period obtained when the cylinder is suspended by a thread compare with its period when placed in the pan
The period of oscillation of the cylinder in the pan will be affected by the properties of the fluid, such as its density and viscosity, which will not affect the motion of the suspended cylinder.
The formula for the period of oscillation of a cylinder in a fluid is given by:
T = 2π√(I/mgd)
Viscosity describes the internal friction between different layers of a fluid as they move past one another. High-viscosity fluids, such as molasses or honey, flow slowly and require more force to move, while low-viscosity fluids, such as water, flow more easily and quickly.
Viscosity is influenced by several factors, including temperature, pressure, and the size and shape of molecules in the fluid. For example, as the temperature of a fluid increases, its viscosity typically decreases, and as pressure increases, viscosity may increase. Viscosity is important in many areas of science and engineering, such as in the study of fluid dynamics, lubrication, and materials science. It also plays a role in various industrial applications, such as in the production of paints, cosmetics, and food products.
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Suggest a problem concerning an interesting effect observed with specific non-newtonian fluids.Also pls recommend any experiment, explain its results and pls share some pics for a better explanation?
The problem concerning an interesting effect observed with specific non-Newtonian fluids investigating the impact of shear stress on the flow behavior of non-Newtonian fluids.
In this experiment, a non-Newtonian fluid is placed in a cylindrical container and its flow behavior is observed when a shear stress is applied to its surface which is created by a rotating paddle wheel which is placed at the bottom of the container. The paddle wheel is rotated at different speeds to increase the shear stress applied to the non-Newtonian fluid.
The results of this experiment demonstrate that when the shear stress is increased, the viscosity of the non-Newtonian fluid decreases. This decrease in viscosity causes the non-Newtonian fluid to flow more easily and with less resistance. This effect can be seen when the paddle wheel is rotated at higher speeds; the non-Newtonian fluid flows more quickly and with less effort.
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binoculars contain prisms inside that reflect light entering at an angle largerthan the critical angle. if the index of refraction of a glass prism is 1.58, what is the critical angle for light entering the prism?
The critical angle for light to penetrate a glass prism with a 1.58 index of refraction is 40.2 degrees.
The formula for calculating the critical angle is sin(critical angle) = 1/n, where n is the medium's coefficient of refraction.
The critical angle can be determined using the formula sin(critical angle) = 1/1.58 for a glass prism with an index of refraction of 1.58.
Criterion angle sin = 0.6329 When we take the inverse sine of both edges,
Taking the inverse sine of both sides, we get:
critical angle = sin^-1(0.6329)
critical angle = 40.2 degrees
As a result, 40.2 degrees is the critical angle for light to penetrate a glass prism with a 1.58 index of refraction.
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A 0.155 kg arrow is shot from
ground level, upward at 31.4 m/s.
What is its potential energy (PE)
when it is 30.0 m above the
ground?
The potential energy of the arrow when it is 30.0 m above the ground is 45.57 J.
What is the potential energy (PE) of the arrow when it is 30.0 m above the ground?The potential energy (PE) of an object at a height h is given by the formula:
PE = mgh
Where m is the mass of the object, g is the acceleration due to gravity ( 9.8m/s²), and h is the height.
Given that:
m = 0.155 kg
v = 31.4 m/s
h = 30.0 m
g = 9.81 m/s² (acceleration due to gravity)
Use the formula for potential energy to find the potential energy of the arrow at a height of 30.0 m:
PE = mgh
PE = 0.155 × 9.8 × 30.0
PE = 45.57 J
Therefore, the potential energy of the arrow is 45.57 J.
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a horizontal force of 180 n used to push a chair across a room does 520 j of work. how far does the chair move in this process?
According to the work-energy principle, the work done on an item is equal to the change in its kinetic energy. The chair is being pushed horizontally with a force of 180 N, producing 520 J of effort.
To calculate the distance the chair moves, we may apply the formula W = Fd. W = 520 Fd J = 180 N x d When we solve for d, we get: d = 520 J / 180 N d = 2.89 m As a result, the chair moves 2.89 meters across the room while being pushed with a force of 180 N and performing 520 J of effort. The work done on an item is equal to the change in its kinetic energy, according to the work-energy principle. The chair is being pushed horizontally with a force of 180 N, resulting in an effort of 520 J. We may use the formula W = Fd to compute the distance the chair moves.
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with what minimum speed must you toss a 150 g ball straight up to just touch the 14- m -high roof of the gymnasium if you release the ball 1.7 m above the ground? solve this problem using energy.
The minimum speed required to toss the ball straight up to just touch the roof of the gymnasium is 6.35 m/s.
To calculate the minimum speed required to toss a 150 g ball straight up to just touch the 14 m high roof of the gymnasium, we can use energy conservation. The potential energy of the ball when it is at the release point is given by mgh, where m is the mass of the ball, g is the acceleration due to gravity, and h is the height of the release point above the ground. At the release point, the ball has zero kinetic energy.
When the ball just touches the roof, its potential energy is zero, and all its initial potential energy has been converted into kinetic energy. The kinetic energy of the ball can be expressed as (1/2)mv^2, where v is the velocity of the ball at the point of contact with the roof.
Therefore, we can write the equation: mgh = (1/2)mv²
Rearranging the equation, we get: v = sqrt(2gh)
Substituting the given values, we get: v = sqrt(2 x 9.81 m/s^2 x (14 m - 1.7 m)) = 6.35 m/s
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calculate the value of δs when 63.0 g of ga(l) solidifies at 29.8 ∘c .
The value of δs when 63.0 g of gallium solidifies at 29.8 °C is approximately 80.3 J/g·°C.
To calculate the value of δs, we need to use the formula:
δs = Q / m
where Q is the heat absorbed during the solidification of the substance and m is the mass of the substance.
The heat absorbed during the solidification of a substance is given by:
Q = ΔHf * n
where ΔHf is the heat of fusion of the substance and n is the number of moles of the substance.
To find n, we can use the formula:
n = m / M
where M is the molar mass of the substance.
The molar mass of gallium is 69.72 g/mol.
Using the given values, we get:
n = 63.0 g / 69.72 g/mol
n ≈ 0.904 mol
The heat of fusion of gallium is 5.59 kJ/mol.
So, Q = 5.59 kJ/mol * 0.904 mol
Q ≈ 5.06 kJ
Now, we can find the value of δs:
δs = Q / m
δs = 5.06 kJ / 63.0 g
δs ≈ 80.3 J/g·°C
Therefore, the value of δs when 63.0 g of gallium solidifies at 29.8 °C is approximately 80.3 J/g·°C.
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how much energy is consumed by a 1.0 kw hair dryer used for 13 min ? express your answer with the appropriate units.
The hair dryer consumes 0.217 kilowatt-hours (kWh) of energy when used for 13 minutes. This is a common unit of measurement for electrical energy consumption.
To calculate the amount of energy consumed by a 1.0 kW hair dryer used for 13 minutes, we need to use the formula for electrical energy:
Energy (in kWh) = Power (in kW) x Time (in hours)
First, we need to convert the time from minutes to hours by dividing it by 60:
Time (in hours) = 13 min / 60
= 0.217 hours
Then, we can substitute the power and time values into the formula:
Energy (in kWh) = 1.0 kW x 0.217 hours
= 0.217 kWh
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two train tracks are going in opposite directions leave at the same time. one train travels 80km/hr and the other travels 70km/hour. how long after they leave will they me 50km apart
Answer:
20 min
Explanation:
let the time taken be t
s = distance by train 1 + distance by train 2
s= 50 km
by the second equation of motion,
[tex]s=\frac{1}{2} at^2+ut[/tex]
a in both trains is zero.
so,
50= 80t + 70t
50= 150t
t= 1/3 hr = 20 min
The first equation of motion: v = u + at
Second equation of motion: s = ut + 12 at2
Third equation of motion: v2 = u2 + 2as
where,
s = displacement
u = initial velocity
v = final velocity
a = acceleration
t = time of motion
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The two trains will be 50km apart after 1/3 of an hour, which is equivalent to 20 minutes.
Two train tracks are going in opposite directions leave at the same time. One train travels 80km/hr and the other travels 70km/hour.
When two train tracks are going in opposite directions and leave at the same time, they are moving apart from each other. In this case, one train is moving at 80 km/hour, and the other is moving at 70 km/hour. Therefore, the relative speed of the two trains is 80 km/hour + 70 km/hour = 150 km/hour.
To determine the time it takes for the trains to be 50 km apart, we use the formula:
d = rt
Where, d = distance, r = rate (speed), and t = time
So, 50 = 150t (since the distance is 50 km and the relative speed is 150 km/hour). Solving for t, we get:
[tex]t = \frac{50}{150} = \frac{1}{3}[/tex] hours = 20 minutes.
Therefore, the two trains will be 50 km apart after 20 minutes of leaving.
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based on the distance/size ratios for each system, in which system are the objects the most isolated from one another?
Based on the distance/size ratios for each system, the objects that are the most isolated from one another are likely the stars in a galaxy.
This is because stars in a galaxy are typically separated by much larger distances than objects in other systems.
For example, while planets and stars may be relatively close to one another in a solar system, stars in a galaxy can be many light-years apart from each other.
Similarly, moons and planets may be relatively close to one another in a planetary system, but stars in a galaxy are typically much more isolated.
Therefore, based on distance and size ratios, stars in a galaxy are likely to be the most isolated from one another compared to objects in other systems.
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The probable question may be:
based on the distance/size ratios for each system, in which system are the objects the most isolated from one another?
Galaxies, Stars in a Galaxy , Planets and Stars, Moons and Planets
two kids are on a seesaw that is 4m long. if the one boy has a mass of 50kg and the other is 30kg. how far from the center should the bigger boy sit if the smaller one is 3.5 m from the far end of the seesaw?
Two kids are on a seesaw that is 4m long. if the one boy has a mass of 50kg and the other is 30kg. The bigger boy should sit 1.04 meters from the center if the smaller one is 3.5 m from the far end of the seesaw.
Let the bigger boy sit at x meters from the center.
Now, we can say that the smaller boy sits at (4 - 3.5) = 0.5 meters from the center.
The principle of moments states that the sum of moments acting on an object is equal to zero.
Hence, we can say that
(50)(x) = (30)(0.5) (4 - x)
Simplifying the above equation, we get:
50x = 60 - 7.5x
57.5x = 60
x = 60 / 57.5
x ≈ 1.04 meters
Hence, the bigger boy should sit 1.04 meters from the center.
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a 920 kg sports car collides into the rear end of a 2300 kg suv stopped at red light. the bumpers lock, the brakes are locked, and the two cars skid forward 2.8 meters before stopping. coefficient of friction between tires and road is .80. calculate the speed of the sports car at impact?
The speed of the sports car at impact is 9.37 m/s.
The conservation of momentum and the work-energy principle using here . Before the collision, the two cars are not moving, so their initial momentum is zero. Let v be the speed of the sports car after the collision.
Using the conservation of momentum, we have:
(m1 + m2) * v = m1 * v1
where m1 and m2 are the masses of the sports car and the SUV, respectively, and v1 is the initial velocity of the sports car before the collision.
After the collision, the two cars move together and stop after skidding a distance of 2.8 meters. can use the work-energy principle to relate the work done by the frictional force to the change in kinetic energy of the two cars. The work done by the frictional force is given by:
W = F * d = μ * N * d
where μ is the coefficient of friction, N is the normal force, and d is the distance over which the frictional force acts. The normal force is equal to the weight of the two cars, which is:
N = (m₁ + m₂) × g
where g is the acceleration due to gravity.
The change in kinetic energy of the two cars is:
ΔK = (1/2) × (m¹ + m²) × v²
Using the work-energy principle, we have:
W = ΔK
μ × N × d = (1/2) × (m1 + m2) × v²
Substituting the expressions for N and μ, we get:
μ × (m₁+ m₂) × g × d = (1/2) × (m1 + m2) × v²
Simplifying and solving for v, we get:
v = √(2 × μ × g ×d)
Substituting the given values, we get:
v = √(2 × 0.8 × 9.81 m/s² × 2.8 m) = 9.37 m/s
Therefore, the speed of the sports car at impact would be 9.37 m/s.
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the spacecraft that got the closest to the nucleus of halley's comet and sent back dramatic photographs of what the nucleus looked like was:
The spacecraft that got the closest to the nucleus of Halley's Comet and sent back dramatic photographs of what the nucleus looked like was the European Space Agency's (ESA) Giotto spacecraft.
The Giotto spacecraft was launched on July 2, 1985, and on March 13, 1986, it passed within 596 kilometers (370 miles) of Halley's comet's nucleus. It was able to send back spectacular photographs of the comet's nucleus.
The Giotto mission was a joint European Space Agency (ESA) project with contributions from 14 European countries. It was named after the Italian artist Giotto di Bondone because the probe's camera had the same field of view as the artist's sketch of Halley's comet in 1301.
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how does the linear speed of a child sitting near the center of a rotating merry-go-round compare with that of a dog sitting near the edge of the same merry-go-round?
The linear speed of a child sitting near the center of a rotating merry-go-round is less than the linear speed of a dog sitting near the edge of the same merry-go-round.
Speed is a fundamental concept that refers to how fast an object is moving. It is defined as the distance covered by an object in a given amount of time. The concept of speed is important in many areas of physics, including kinematics, dynamics, and thermodynamics. It is often used to describe the motion of objects, such as cars, airplanes, and particles.
In physics, there are two types of speed: scalar speed and vector speed. Scalar speed is the magnitude of the velocity vector and is measured in units of distance per unit of time. Vector speed, on the other hand, is the speed of an object in a specific direction and is measured in units of distance per unit of time in that direction.
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Can you please help me with this question
Impedance is a measure of the opposition to the flow of electrical current in a circuit. It is a complex quantity that includes both resistance and reactance, and is measured in ohms (Ω).
What is the impedance?Impedance is an important concept in electrical engineering and is used to design and analyze electronic circuits, communication systems, and power systems.
We know that the capacitive reactance is;
Xc= 1/2πfC
Xc =1/2* 3.14 * 1 * 10^3 * (0.01 * 10^-6)
Xc = 15924 ohm
Then Z = √R^2 + Xc^2
Z = √(10 * 10^3) + (15924 )^2
Z = 18804 ohm
I = V/Z
I = 10V / 18804 ohm
I = 0.00053 A
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traveling at a speed of 21 m/s, the driver of a car suddenly locks the wheels by slamming on the brakes. the coefficient of kinetic friction between the tires and the road is 0.72. how much time does it take for the car to come to stop?
A vehicle is going at 21 m/s when the driver abruptly slams on the brakes locking the wheels. The tires and the road's kinetic friction coefficients are both 0.72. It takes the car 2.76 seconds to come to a stop.
When a car is moving and the driver slams on the brakes, the kinetic friction between the tires and the road will cause the car to decelerate. The force of friction can be calculated using the equation:
f_k = μ_k × N
where f_k is the force of kinetic friction, μ_k is the coefficient of kinetic friction, and N is the normal force (equal to the weight of the car) acting on the car.
The force of friction is equal and opposite to the force applied by the brakes, so we can write:
f_k = ma
where m is the mass of the car and a is its acceleration.
Combining these equations and solving for a, we get:
a = -μ_k × g
where g is the acceleration due to gravity (9.81 m/s^2) and the negative sign indicates that the car is decelerating.
The time it takes for the car to come to a stop can be found using the equation:
v = u + at
where v is the final velocity (zero in this case), u is the initial velocity (21 m/s), a is the acceleration (-μ_k × g), and t is the time.
Substituting the given values, we get:
0 = 21 m/s + (-μ_k × g) × t
Solving for t, we get:
t = -21 m/s / (-μ_k × g)
= 2.76 s
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the police car has a mass of 2200 kg. assuming that its acceleration is entirely due to the static friction between the tires and the ground, what is the minimum coefficient of static friction between the tires and the ground?
The police car has a mass of 2200 kg. Assuming that its acceleration is entirely due to the static friction between the tires and the ground, the minimum coefficient of static friction between the tires and the ground is 0.191.
There is a minimum amount of friction necessary between the tires of a car and the road so that the car does not slide around or roll over as it drives along. This is referred to as the minimum coefficient of static friction. It's crucial to understand that the value of the coefficient of static friction is unique to each pair of materials interacting. Therefore, using the given values, the minimum coefficient of static friction (μ) between the tires and the ground can be calculated as follows;
F_friction = mass x accelerationF_friction = 2200 x accelerationStatic frictional force is the force that arises between two surfaces when they are in contact with one other and one is not sliding or moving relative to the other.
Hence, the maximum possible static friction (Fmax) can be given by:
F_max = coefficient of static friction (μ) x normal force of contactF_max = μ x FNWhere FN is the normal force exerted by the ground on the car, which is equal to the weight of the car (mg). Therefore, F_max = μmgAs a result, the minimum coefficient of static friction (μ) required can be calculated using the given values as:μmin = Friction/Fmax = Friction/(μmg)
Substitute the given values into the equation:
μmin = Friction/Fmax = Friction/(μmg)μmin = Friction/Fmax = 2200 x acceleration/2200 x gμmin = acceleration/g = 0.191
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the coil is near the ousth pole, which is held in place. does the coil exert an attractive or repulsive force on the magnet
When the coil is located near the south pole, which is held in place, it exerts an attractive force on the magnet.
When a magnet approaches a conducting loop, it induces a current in the coil as the magnetic field changes. When there is a changing magnetic field linked with a loop of wire, an induced electromotive force (emf) is generated in the loop according to Faraday's law of electromagnetic induction.
A current is generated in the loop as a result of the emf, which then produces its own magnetic field. When this field links with the initial magnetic field, it generates a torque that rotates the magnet. This torque is what causes the magnet to be attracted to the coil.
Lenz's law states that the magnetic field produced by the coil opposes the magnetic field that created it. As a result, the direction of the current in the coil is in the opposite direction to the change in magnetic flux passing through it.
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if it gains sufficient mass from a binary companion, a white dwarf can become a if it gains sufficient mass from a binary companion, a white dwarf can become a brown dwarf. type i supernova. black dwarf. planetary nebula. type ii supernova.
If a white dwarf gains sufficient mass , it can undergo a type I supernova. This occurs when the white dwarf reaches Chandrasekhar limit, which is approximately 1.4 times mass of the Sun.
If a white dwarf does not gain sufficient mass to undergo a type I supernova, it will eventually cool down and become a black dwarf. A brown dwarf is a failed star that is not massive enough to undergo nuclear fusion in its core, and so it emits very little light or heat.
A type II supernova occurs when a massive star runs out of fuel and its core collapses, leading to a catastrophic explosion. This is distinct from a type I supernova, which involves a white dwarf.
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you are swinging a yo-yo around in a circle above your head. assume this is a perfect system: the mass of the string is negligible, the yo-yo is a point mass and your arm is a perfectly vertical axis of rotation.given the mass of the yo-yo is m and the length of the string (radius of the circle traced by the yo-yo) is l, you find the moment of inertia to be i. if you double the length of the string, what is the new moment of inertia?
if you double the length of the string, the new moment of inertia is 4 times the initial moment of inertia.
When a yo-yo is swung around in a circle above the head, and it is assumed that it is a perfect system with negligible mass of the string, the yo-yo is a point mass, and the arm is a perfectly vertical axis of rotation, the moment of inertia can be given as `I = ml²`,
where, I is The moment of inertia for a point mass m placed a distance l from the axis of rotation. This formula is based on the assumption that the point mass rotates along an axis perpendicular to the plane of motion.
If the length of the string (radius of the circle traced by the yo-yo) is doubled, the new moment of inertia can be calculated as follows:
I' = m(2l)²
I' = m4l²
Therefore, the new moment of inertia is `4ml²`.
Thus, the new moment of inertia is 4 times the initial moment of inertia.
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when air is inhaled, it quickly becomes saturated with water vapor as it passes through the moist upper airways. when breathing dry air, about 25 mg of water are exhaled with each breath. at 12 breaths per minute, what is the rate of energy loss due to evaporation? at body temperature, the heat of vaporization of water is lv
The rate of energy loss due to evaporation is 6.75 × 104 J/min.
When answering questions on Brainly, it is important to be factually accurate, professional, and friendly. Answers should be concise and relevant to the question asked. Any typos or irrelevant parts of the question should be ignored.
The terms provided in the question should be used in the answer to ensure clarity and accuracy. Here is a possible answer to the question:When air is inhaled, it quickly becomes saturated with water vapor as it passes through the moist upper airways.
When breathing dry air, about 25 mg of water are exhaled with each breath. At 12 breaths per minute, what is the rate of energy loss due to evaporation?At body temperature, the heat of vaporization of water is Lv = 2.25 × 106 J/kg.
To find the rate of energy loss due to evaporation, we need to find the mass of water that is exhaled per minute.Using the given values, the mass of water exhaled in one breath is 25 mg or 0.025 g.
Therefore, the mass of water exhaled per minute is:
0.025 g/breath x 12 breaths/min
= 0.3 g/minThe rate of energy loss due to evaporation can now be calculated using the formula:
q = mLvwhere q is the rate of energy loss,
m is the mass of water per unit time, and Lv is the heat of vaporization of water. Substituting the values obtained above gives:
q = (0.3 g/min) x (2.25 × 106 J/kg) =
6.75 × 104 J/min
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nuclear reactions unit test egenuity
A nuclear reactions unit test in edenuity is a type of assessment used to evaluate students' understanding of nuclear reactions.
It typically involves multiple-choice and fill in the blank questions that test the student's knowledge of different types of nuclear reactions, the equations used to calculate them, and the effects of different types of radiation on different materials. The unit test may also include diagrams or simulations of actual nuclear reactions to further test the student's knowledge. The goal of the unit test is to ensure that the student has a comprehensive understanding of nuclear reactions, and to ensure that they are able to apply this knowledge in the real world. The test may also include open-ended questions that ask students to explain nuclear reactions in their own words.
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