Thin layer chromatography (TLC) is a technique used to separate the components of a mixture based on their different affinities for a stationary phase (usually a thin layer of silica gel or alumina on a glass or plastic plate) and a mobile phase (usually a solvent or a mixture of solvents).
TLC is an analytical tool widely used because of its simplicity, relative low cost, high sensitivity, and speed of separation.
Besides proper balance of polarity, one of the requirements for the pair of solvents used in TLC is that they must be miscible with each other. This means that they can mix together in any proportion without forming two separate layers. For example, water and ethanol are miscible solvents, but water and hexane are not. Using miscible solvents ensures that the mobile phase has a uniform composition and polarity throughout the TLC plate. This helps to achieve better separation and reproducibility of the results.
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If a fossil contains 1 part carbon 14 to 7 parts nitrogen 14, how old is it?
The fossil is approximately 17,100 years old.
The age of a fossil can be estimated by using the half-life of carbon-14. The half-life of carbon-14 is approximately 5,700 years, which means that after this time, half of the carbon-14 in a sample will have decayed into nitrogen-14.
If a fossil contains 1 part carbon-14 to 7 parts nitrogen-14, this means that the carbon-14 has decayed to one-eighth (1/8) of its original amount. Since we know the half-life of carbon-14, we can use this information to estimate the age of the fossil.
If we assume that the fossil originally contained only carbon-14, then the number of half-lives that have passed can be calculated as follows:
1/2n = 1/8
where n is the number of half-lives that have passed.
Simplifying this equation, we get:
2n = 8
n = 3
Therefore, the fossil has undergone 3 half-lives of carbon-14 decay. Since the half-life of carbon-14 is approximately 5,700 years, we can estimate the age of the fossil by multiplying the half-life by the number of half-lives:
age = 5,700 years/half-life * 3 half-lives
age = 17,100 years.
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what is the ph at the equivalence point for the titration of 0.17 m solutions of the following acids and bases, and which of the indicators shown below would be suitable for each titration?
SCUBS
Explanation:
Scubs is the form of pop by nayeon and Liz doesn't get line kitch
someone pls help
For each example, identify whether the property described is chemical or physical.
Justify your answer in each case.
(a) Bronze metal has a shiny lustre.
(b) When silver nitrate is added to calcium
chloride, a cloudy solid (precipitate)
appears.
(c) Mercury is liquid at room temperature.
Answer:
A. Physical B.Chemical C. Physical
Explanation:
Shiny is a physical Mercury is liquid which is physical and sliver added into calcium is a chemical property.
-. Hydrogen bonds help dictate the way that proteins, such as
enzymes fold, and also
sometimes play a significant role
in the way proteins interact with
other substances (e.g. enzymes
with substrates). In the diagram
to the right, what would happen
to the active site of
chymotrypsin if His 57 were
replaced by an amino acid with
a nonpolar amino acid residue?
The replacement of the polar amino acid residue His 57 with a nonpolar residue in the chymotrypsin active site could impair the proper positioning of catalytic residues, potentially reducing or eliminating the enzyme's activity.
What would happen to the active site of chymotrypsin if His 57 were replaced by an amino acid with a nonpolar amino acid residue?His 57 forms a hydrogen bond with Ser 195 in the chymotrypsin active site. His 57 is a polar amino acid residue, and its interaction with Ser 195 contributes to the proper positioning of the catalytic residues in the active site.
If His 57 were replaced by a nonpolar amino acid residue, such as alanine or valine, the hydrogen bond with Ser 195 would be lost. This could result in a change in the positioning of the catalytic residues in the active site, which could impair the ability of chymotrypsin to properly interact with its substrate and perform its enzymatic function. Therefore, the replacement of His 57 with a nonpolar amino acid residue could potentially reduce or eliminate the enzymatic activity of chymotrypsin.
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g when the following equation is balanced properly under acidic conditions, what are the coefficients of the species shown? hno3 fe no fe2 water appears in the balanced equation as a fill in the blank 5 (reactant, product, neither) with a coefficient of . (enter 0 for neither.) how many electrons are transferred in this reaction?
Total 2 electrons are transferred in this reaction.
Balanced chemical equation for the given reaction under acidic conditions is;
8 H⁺ + 2 Fe²+ + 2HNO₂ → 2NO₃⁻ + 2 Fe₃⁺ + 3H₂O
So the coefficients of the species are;
HNO₂⁺ + Fe₂⁺ → NO₃⁻ + Fe₃⁺
1 + 1 → 1 + 1
Water will appear in the balanced chemical equation as a product having a coefficient of 3.
The number of electrons transferred in this reaction can be calculated by examining the oxidation states of the atoms involved. Iron (Fe) goes from a +2 oxidation state to a +3 oxidation state, which means it has lost one electron per Fe atom. Therefore, 2 electrons are transferred in total.
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--The given question is incomplete, the complete question is
"When the following equation is balanced properly under acidic conditions, what are the coefficients of the species shown? HNo2+ + Fe2+ --> NO3- + Fe water appears in the balanced equation as a fill in the blank 5 (reactant, product, neither) with a coefficient of . (enter 0 for neither.) how many electrons are transferred in this reaction?"--
Please help base the answers to the paragraph above CHEMISTRY
Answer: 1. The chemical formula of the negative polyatomic ion present in an aqueous nitric acid solution is nitrate, which has a chemical formula of NO3-.
2. The solubility of sulfur dioxide (SO2) in water is negatively affected by an increase in water temperature. This means that as the temperature of water increases, the solubility of SO2 in water decreases. This is because the solubility of gases in water generally decreases with increasing temperature, due to the decrease in gas molecules' ability to dissolve in water. Therefore, when water temperature increases, the amount of SO2 that can dissolve in the water decreases, resulting in less acidic rainfall.
Explanation:
at higher temperature, will you collect more volume of gas or less volume, with the same amount of reactants?
The higher temperature will witness more volume in gas when the amount of reactants is same.
The Charle's Law states that the volume is directly proportional to the temperature when other parameters are kept constant. Thus, the increase in temperature will accompany increase in volume.
The reason for such phenomenon is expansion of gases on heating due to excess absorption of energy. It is available in the form of kinetic energy which subsequently is evident through square of velocity.
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at 70 oc, the solubility of an unknown solute is 61.8 g/100.0 g of water. what mass of the solute can dissolve in 142.1 g of water at the same temperature? type answer:
Answer:
Explanation:
Use the given solubility to set up a proportion:
61.8 g / 100.0 g water = x g / 142.1 g water
Cross-multiply to solve for x:
x = (61.8 g / 100.0 g water) * 142.1 g water
Simplify and solve:
x = 87.76 g
Round the answer to an appropriate number of significant figures:
The answer should be rounded to three significant figures, since the given solubility has three significant figures. Therefore, the final answer is:
x = 87.8 g
Therefore, 87.8 g of the unknown solute can dissolve in 142.1 g of water at 70 °C.
At 70°C, the solubility of the unknown solute is 61.8 g/100.0 g of water. 87.9 g of the solute can dissolve in 142.1 g of water at 70°C.
(61.8 g solute / 100.0 g water) = (x g solute / 142.1 g water)
To solve for x, cross-multiply:
61.8 * 142.1 = 100 * x
8791.38 = 100x
x = 87.9138
Thus, 87.9 g of the solute can dissolve in 142.1 g of water at 70°C.
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does your synthesis strategy give a substitution reaction with the expected regiochemistry and stereochemistry? draw the expected product of the forward reaction.
Answer:
Yes, the synthesis strategy can give a substitution reaction with the expected regiochemistry and stereochemistry
Explanation:
The expected product of the forward reaction would be a single enantiomer of the substituted product, depending upon the starting materials used. For example, if the starting material is an unsubstituted chiral compound, then the product would be a single enantiomer of the desired product. If the starting material is a racemic mixture, then the product would be a racemic mixture of the desired product. In detail, a substitution reaction involves the replacement of a functional group in a molecule with a different functional group. This process can be catalyzed by a transition metal catalyst, such as a palladium or nickel complex. The reaction is usually carried out in the presence of a base, such as sodium hydroxide or potassium hydroxide, and a nucleophile, such as an alcohol or an amine.
When it comes to synthesis, the goal is to create a compound or molecule from simpler components through chemical reactions. In terms of regiochemistry and stereochemistry, these refer to the specific spatial orientation of atoms or groups in a molecule and the effects this has on reactivity and other properties.
In regards to the question, it is difficult to provide a specific answer without more information about the specific reaction and compounds involved. However, in general, the expected product of a substitution reaction will depend on factors such as the type of substitution reaction (e.g. nucleophilic, electrophilic), the nature of the substituent groups involved, and the reaction conditions. For example, in a nucleophilic substitution reaction, the incoming nucleophile will typically replace a leaving group on the substrate molecule. The regiochemistry and stereochemistry of the product will depend on the location and orientation of the leaving group and the incoming nucleophile, as well as any other factors that may influence the reaction. In summary, the expected product of a forward reaction in a substitution reaction will depend on a variety of factors related to the reaction and the compounds involved.
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BASIC CHEM I DONT THINK ITS THAT HARD IM JUST BAD
PLEASE HELP ME. URGENT
copper (II) sulphate reacts with iron metal
name the;
reactant and the state:
product and the state:
word equation:
balanced formula:
type of reaction:
Agriculture: Copper (II) sulfate is used as a fungicide to control plant diseases, while iron metal is used as a nutrient for plants.
Fe + CuSO4 Reaction.
Reactant and state: Copper (II) sulphate, solid (CuSO4.5H2O)
Product and state: Iron (II) sulphate, solid
(FeSO4) and Copper metal, solid (Cu)
Word equation: Iron metal + Copper (II) sulphate sulphate - Copper metal + Iron (II)
Balanced formula: Fe + CuSO4 Cu + FeSO4
Type of reaction: This is a single displacement or substitution reaction, where iron replaces copper in the copper sulfate compound.
ChatGPT
what relationship there is between salinity and light transmittance.
Answer:
The relationship between salinity and light transmittance is that an increase in salinity leads to a decrease in light transmittance. This is because the dissolved salts in water absorb and scatter light, reducing the amount of light that can pass through.
Explanation:
Would you expect to find large glaciers on all of these landmass today? Explain
Answer:
The main places you would find glaciers on in today's world are places like Alaska, Antarctica, and Greenland. Places that are cold either year-round or most of the year and are in an ocean area are typically where glaciers form.
Explanation:
These places typically are cold year-round and are the perfect area for glaciers to form, but not everywhere forms glaciers as they need certain weather conditions to form.
A polar solvent is prepared by mixing 27.5 mL of propanone with 222.5 mL of water. What is the percentage by volume of propanone in the mixture?
A polar solvent is prepared by mixing 27.5 mL of propanone with 222.5 mL of water the percentage by volume of propanone in the mixture is 11%.
The percentage by volume of propanone in the mixture can be calculated as follows:
Find the total volume of the mixture:
Total volume = volume of propanone + volume of water
Total volume = 27.5 mL + 222.5 mL
Total volume = 250 mL
Calculate the volume fraction of propanone:
Volume fraction of propanone = volume of propanone / total volume
Volume fraction of propanone = 27.5 mL / 250 mL
Volume fraction of propanone = 0.11
Convert the volume fraction to a percentage:
Percentage by volume of propanone = volume fraction of propanone x 100%
Percentage by volume of propanone = 0.11 x 100%
Percentage by volume of propanone = 11%
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the function of a buffer is to . group of answer choices maintain a neutral ph act as a strong acid change color at the end point of a titration be a strong base maintain the ph of a solution
The function of a buffer is to maintain the pH of a solution. The correct answer is maintain the pH of a solution.
Buffers are important in many chemical processes and biological systems, as they help maintain a stable pH environment, allowing for the proper functioning of chemical reactions and enzymes.
A buffer is a solution that resists changes in pH when small amounts of acid or base are added. It does this by absorbing or releasing H+ ions as necessary. The buffering capacity of a solution is determined by the concentrations of the weak acid and its conjugate base, which together form a buffer system.
Buffers are important in many biological processes because they help to maintain the pH of body fluids and prevent them from becoming too acidic or basic. They are also used in many laboratory experiments and industrial processes where pH control is important.
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determine the equilibrium partial pressure of nh3 in a reaction vessel that initially contained 0.900 atm n2 and 0.500 atm h2 at 648 k.
The equilibrium partial pressure of [tex]$NH_3$[/tex] is 0.0106 atm. [tex]$K_c=\frac{[NH_3]^2}{[N_2][H_2]^3},$[/tex] and [tex]$[NH_3]=1.32\times10^{-4}\frac{mol}{L}.$[/tex]
To decide the harmony halfway strain of [tex]$NH_3$[/tex] in the response vessel, we really want to think about the decent condition for the response:
[tex]$N_2(g) + 3H_2(g)[/tex] rightleftharpoons [tex]2NH_3(g)$[/tex].
At harmony, the paces of the forward and invert responses are equivalent, and the centralizations of the reactants and items never again change. The harmony steady articulation for this response is:
[tex]$K_c = \frac{[NH_3]^2}{[N_2][H_2]^3}$[/tex]
We can utilize the underlying tensions of [tex]$N_2$[/tex] and [tex]$H_2$[/tex] to ascertain their fixations utilizing the best gas regulation:
[tex]$[N_2] = \frac{P_{N_2}}{RT} = \frac{0.900 atm}{0.08206 \frac{L\cdot atm}{mol\cdot K} \times 648 K} = 0.0149 \frac{mol}{L}$[/tex]
[tex]$[H_2] = \frac{P_{H_2}}{RT} = \frac{0.500 atm}{0.08206 \frac{L\cdot atm}{mol\cdot K} \times 648 K} = 0.0083 \frac{mol}{L}$[/tex]
Subbing these fixations and the harmony steady articulation into the articulation for [tex]$K_c$[/tex], we get:
[tex]$K_c = \frac{[NH_3]^2}{[N_2][H_2]^3}$[/tex]
[tex]$K_c = \frac{([NH_3]/0.0149 \frac{mol}{L})^2}{0.0149 \frac{mol}{L} \times (0.0083 \frac{mol}{L})^3}$[/tex]
[tex]$K_c = \frac{[NH_3]^2}{1.05\times10^{-10}}$[/tex]
Addressing for [tex]$[NH_3]$[/tex], we get:
[tex]$[NH_3] = \sqrt{K_c \times [N_2] \times [H_2]^3}$[/tex]
[tex]$[NH_3] = \sqrt{1.05\times10^{-10} \times 0.0149 \frac{mol}{L} \times (0.0083 \frac{mol}{L})^3}$[/tex]
[tex]$[NH_3] = 1.32\times10^{-4} \frac{mol}{L}$[/tex]
At long last, we can switch this fixation over completely to a halfway tension utilizing the best gas regulation:
[tex]$P_{NH_3} = [NH_3] \times \frac{RT}{P}$[/tex]
[tex]$P_{NH_3} = (1.32\times10^{-4} \frac{mol}{L}) \times \frac{0.08206 \frac{L\cdot atm}{mol\cdot K} \times 648 K}{1 atm}$[/tex]
[tex]$P_{NH_3} = 0.0106 atm$[/tex]
Consequently, the harmony halfway tension of [tex]$NH_3$[/tex] in the response vessel is 0.0106 atm.
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white solid is observed to be insoluble in water, insoluble in excess ammonia solution and soluble in dilute hcl. which compound is it?
The white solid could be silver chloride (AgCl) which is insoluble in water, insoluble in excess ammonia solution and soluble in dilute HCl.
AgCl is insoluble in water, and when it reacts with excess ammonia solution, it forms a complex with the formula [Ag(NH₃)²⁺]. Therefore, AgCl is insoluble in excess ammonia solution. When AgCl is treated with dilute hydrochloric acid (HCl), it dissolves to form a solution containing silver ions (Ag⁺) and chloride ions (Cl⁻). AgCl is a white crystalline solid with a high melting point (455°C) and boiling point (1,155°C). It is sparingly soluble in water, and its solubility decreases as the temperature decreases. AgCl is also insoluble in organic solvents.
AgCl is used in various applications, such as in the production of silver electrodes, in electroplating, and as a reagent in chemical analysis. AgCl is considered to be relatively non-toxic, but it can be harmful if ingested or inhaled in large quantities. It is also considered an environmental hazard and should be handled and disposed of with care.
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Multiple Choice due tomorrow. Please help double check!
The correct options are AB+CD →AD+CB, Oxygen, HF, Ba(OH)₂, Na₂SO₄+H₂O, They are double displacement reactions.
What are double displacement reactions?When pieces of two ionic compounds are exchanged, two new compounds are created. These reactions are known as double displacement reactions. Chemical reactions known as double displacement reactions occur when the reactant ions move around to create new products. Precipitate production often happens as a result of a double displacement process. Covalent or ionic chemical bonds may be present between the reactants. Iron sulphate is produced as a result of the interaction between iron and copper sulphate. Because iron is more reactive than copper in this situation, copper is replaced. Zinc and iron sulphate react, producing zinc sulphate as a byproduct.
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If 2,035 J of heat is added to a 500.0 g sample of water at 35.0°C, what is the final temperature of the water? Specific heat of water is 4.18 J/g°C. (Find the temperature change then subtract the initial temperature given).
calculate the percent ionization of 0.0075 m butanoic acid in a solution containing 0.075 m sodium butanoate.
The per cent ionization of the solution is 0.017%. The steps involved are;
Write the reaction equation
Setup the ICE table
make the necessary calculation
The equation of the reaction is as follows;
CH₃CH₂CH₂COOH(aq) ⇄ [tex]H^{aq}[/tex] + CH₃CH₂CH₂COO[tex]^{-aq}[/tex]
I 0.0075 0 0.085
C -x +x + x
E 0.0075 - x x 0.085 + x
The Ka of the acid = 1.5 x 10⁻⁵
Hence;
1.5 x 10⁻⁵ = x(0.085 + x)/0.0075 - x
1.5 x 10⁻⁵ (0.0075 - x ) = x(0.085 + x)
1.1 x 10⁻⁷ - 1.5 x 10⁻⁵ˣ = 0.085x + x²
x² + 0.085x - 1.1 x 10⁻⁷ = 0
x = 0.0000013 M
Percent ionization= 0.0000013 M/0.0075 × 100/1
= 0.017%
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based on the solubility rules, which one of these compounds is insoluble in water? group of answer choices rb2so4 na2so4 cuso4 baso4 mgso4
Based on the solubility rules, the compound D. BaSO4 is insoluble in water.
This is because barium sulfate is one of the exceptions to the general solubility rule for sulfates (SO4^2-). While most sulfates are soluble in water, those containing barium (Ba^2+), along with lead (Pb^2+), and calcium (Ca^2+) are not soluble.
In contrast, the other compounds listed are soluble:
A. Rb2SO4 - Rubidium sulfate is soluble because alkali metal salts (like rubidium) are generally soluble in water.
B. Na2SO4 - Sodium sulfate is soluble for the same reason as rubidium sulfate - sodium is an alkali metal.
C. CuSO4 - Copper sulfate is soluble because most sulfate salts are soluble in water.
E. MgSO4 - Magnesium sulfate is soluble, as it is also a sulfate salt.
In summary, BaSO4 is the only compound among the given choices that is insoluble in water due to the specific solubility rules for sulfate compounds. Therefore the correct option is D
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at low temperatures, intermolecular forces become important and the pressure of a gas will be higher than predicted by the ideal gas law. true or false
The given statement "at low temperatures, intermolecular forces become important and pressure of the gas will be higher than predicted by ideal gas law" is false. Because, at low temperatures, intermolecular forces become more significant and cause gas molecules to come closer together, which reduces the volume of the gas.
As a result, the pressure of the gas will be lower than predicted by the ideal gas law, which assumes that gas molecules have no volume and do not interact with each other.
The ideal gas law is only accurate for gases that behave like ideal gases, meaning that they have negligible intermolecular forces and occupy no volume. Real gases, on the other hand, deviate from the ideal gas law at high pressures and low temperatures, where intermolecular forces become more significant.
At these conditions, the volume of the gas becomes significant compared to the volume of the container, and the gas behaves less ideally. In this case, we need to use more complex equations of state to accurately predict the behavior of the gas.
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enter your answer in the provided box. how many seconds does it take to deposit 66.5 g of zn on a steel gate when 21.0 a is passed through a znso4 solution?
It will take approximately 9340 seconds or 2.59 hours to deposit 66.5 g of Zn on the steel gate when 21.0 A of current is passed through the ZnSO₄ solution.
To calculate the time required to deposit 66.5 g of Zn on a steel gate, we can use Faraday's laws of electrolysis, which states that the amount of substance produced (in moles) at an electrode is directly proportional to the amount of electric charge passed through the electrode.
The formula for calculating the amount of substance produced is;
n = Q / (zF)
where; n will be the amount of substance produced (in moles)
Q is the electric charge passed through the electrode (in coulombs)
z is the number of electrons transferred per molecule of Zn (2 for Zn)
F is Faraday's constant (96485 C/mol)
We can first calculate the number of moles of Zn that are deposited on the gate using the given mass and molar mass of Zn
n(Zn) = m(Zn) / M(Zn)
n(Zn) = 66.5 g / 65.38 g/mol
n(Zn) = 1.018 mol
Next, we can calculate the electric charge required to deposit this amount of Zn using the formula;
Q = n × z × F
Q = 1.018 mol × 2 × 96485 C/mol
Q = 196293 C
Finally, we can use the formula for electric current (I = Q / t) to calculate the time required (t) to pass an electric charge of 196293 C through the solution at a current of 21.0 A;
t = Q / I
t = 196293 C / 21.0 A
t = 9340 s or 2.59 hours
Therefore, it will take 9340 seconds.
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what is the partial pressure of carbon dioxide in a container that holds .5 moles of carbon dioxide,.32 moles of nitrogen, .2 moles of hydrogen, and has a total pressure of 1.05 atm?
Answer: 0.5 atm
Explanation: To calculate the partial pressure of carbon dioxide, we need to use the mole fraction of carbon dioxide and the total pressure of the container.
The mole fraction of carbon dioxide is:
X(CO2) = n(CO2) / n(total)
X(CO2) = 0.5 moles / (0.5 moles + 0.32 moles + 0.2 moles)
X(CO2) = 0.4762
The partial pressure of carbon dioxide is:
P(CO2) = X(CO2) * P(total)
P(CO2) = 0.4762 * 1.05 atm
P(CO2) = 0.5 atm (rounded to one decimal place)
Therefore, the partial pressure of carbon dioxide in the container is 0.5 atm.
Answer:
0.58 atm
Explanation:
how many grams of cs2(g) can be prepared by heating 9.80 mol s2(g) with excess carbon in a 5.75 l reaction vessel held at 900 k until equilibrium is attained?
The chemical equation for the reaction between sulfur and carbon to produce carbon disulfide is:
S2(g) + C(s) → CS2(g)
To determine the number of grams of CS2(g) that can be prepared, we need to use the stoichiometry of the reaction and the ideal gas law.
We need to calculate the number of moles of CS2(g) that can be produced by 9.80 mol of S2(g). From the equation, we can see that one mole of S2(g) reacts with one mole of C(s) to produce one mole of CS2(g). Therefore, the number of moles of CS2(g) produced will be equal to 9.80 mol.
We need to use the ideal gas law to calculate the volume of the CS2(g) produced. We know that the reaction vessel has a volume of 5.75 L and is held at 900 K. Assuming the pressure remains constant, we can use the ideal gas law: PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
We can rearrange this equation to solve for n: n = PV/RT
Substituting the values we have:
n = (1 atm)(5.75 L)/(0.08206 L·atm/mol·K)(900 K)
n = 0.318 mol
Therefore, the mass of CS2(g) produced will be:
mass = n × M
where M is the molar mass of CS2(g) which is 76.14 g/mol.
mass = 0.318 mol × 76.14 g/mol
mass = 24.2 g
Therefore, 24.2 grams of CS2(g) can be prepared by heating 9.80 mol S2(g) with excess carbon in a 5.75 L reaction vessel held at 900 K until equilibrium is attained.
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most metals used by society are obtained from . group of answer choices base metals ore minerals precious metals native metals
This is incomplete question, here is the question.
Most metals used by society are obtained from which group of options: base metals, ore minerals, precious metals, or native metals?
Most metals used are obtained from base metals ore minerals due to their abundance and ease of extraction through mining.
Most metals utilized by society are acquired from base metals mineral minerals. These minerals incorporate copper, zinc, lead, nickel, and tin, which are tracked down in enormous amounts in the World's hull. The extraction interaction includes mining these metals from underground or open-pit mines, trailed by pounding and crushing to set the metal free from the mineral grid.
Synthetic or actual division procedures are then used to confine and refine the metal. Valuable metals, like gold and silver, are additionally acquired from metal minerals, however they are somewhat intriguing and more hard to extricate. Local metals, then again, are tracked down in their unadulterated metallic structure and don't need extraction from mineral minerals.
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consider the tittration of 100.0 ml of 0.500 m nh3 with 0.500 m hcl. after 50.0 ml of hcl has been added the [h ] of the solution is:
The pH of the solution after 50.0 mL of 0.500 M HCl has been added is 4.74.
The balanced chemical equation for the reaction between NH₃ and HCl is:
NH₃ + HCl → NH₄Cl
This reaction is a neutralization reaction, in which an acid (HCl) reacts with a base (NH₃) to form a salt (NH₄Cl) and water.
Since NH₃ is a weak base and HCl is a strong acid, the reaction will go to completion, and all of the NH₃ will react with the HCl. Before any HCl is added, the solution contains only NH₃, so its pH is basic. As HCl is added, it reacts with the NH₃ to form NH₄Cl, which is a neutral salt. The pH of the solution will decrease as more HCl is added, until all of the NH₃ has reacted and the solution becomes acidic.
To find the pH of the solution after 50.0 mL of 0.500 M HCl has been added to 100.0 mL of 0.500 M NH₃, we need to calculate the moles of NH₃ and HCl that have reacted.
Moles of NH₃ = (100.0 mL)(0.500 M) = 0.0500 moles
Moles of HCl = (50.0 mL)(0.500 M) = 0.0250 moles
Since NH₃ and HCl react in a 1:1 ratio, all of the HCl has reacted with half of the NH₃, leaving 0.0250 moles of NH₃ unreacted.
To calculate the concentration of NH₄⁺ ions in the solution, we need to consider the equilibrium reaction between NH₃ and NH₄⁺ :
NH₃ + H₂O ⇌ NH₄⁺ + OH⁻
The equilibrium constant for this reaction is:
Kb = [NH₄⁺][OH⁻] / [NH₃]
At equilibrium, the concentration of NH₃ will be 0.0250 moles / 0.150 L = 0.167 M (since the total volume of the solution is 150.0 mL). The concentration of OH- ions can be calculated using the Kb value for NH₃, which is 1.8 × 10⁻⁵:
Kb = [NH₃⁺][OH⁻] / [NH₃]
1.8 × 10⁻⁵ = [NH₄⁺][OH⁻] / 0.167
[NH₄⁺][OH⁻] = 3.006 × 10⁻⁶
Since the solution is neutral at equilibrium, the concentration of H+ ions is equal to the concentration of OH- ions. Therefore, the pH of the solution is:
pH = -㏒[H⁺]
[H⁺] = [OH⁻] = √(Kw / [NH₄⁺])
= √(1.0 × 10⁻¹⁴/ 3.006 × 10⁻⁶) = 1.83 × 10⁻⁵ M
pH = -㏒(1.83 × 10⁻⁵) = 4.74
As a result, the pH of the solution after adding 50.0 mL of 0.500 M HCl is 4.74.
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why is the mixture placed in an ice-bath during the addition of the concentrated sulfuric acid? (check all that apply.)
The mixture is placed in an ice-bath during the addition of the concentrated sulfuric acid for multiple reasons. Firstly, the concentrated sulfuric acid is highly reactive and exothermic.
When added to the mixture, it can cause a sudden rise in temperature, leading to undesired side reactions. Placing the mixture in an ice-bath helps to control the reaction temperature and avoid any unwanted reactions.
Secondly, the ice-bath helps to reduce the sulfonation of the 1,4-dimethoxybenzene. Sulfonation can lead to the formation of undesired products and reduce the yield of the desired product.
Finally, placing the mixture in an ice-bath can also help to reduce the formation of butene, which is an undesired byproduct that can form at higher temperatures. The cooling effect of the ice-bath helps to prevent the formation of butene and favor the formation of the FC alkylation product.
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Full Question ;
Why is the mixture placed in an ice-bath during the addition of the concentrated sulfuric acid? (Check all that apply.) MULTIPLE ANSWER A. To avoid the evaporation of the concentrated sulfuric acid. B. To increase the rate of the reaction. C. To favor the formation of the FC alkylation product. D. To reduce the sulfonation of the 1,4-dimethoxybenzene E. To reduce the formation of butene
a rigid cylinder at that temperature contains 0.127 atm of hydrogen, 0.134 atm of iodine, and 1.055 atm of hydrogen iodide. is the system at equilibrium?
The measured Kc is different from the calculated Kc, the system is not at equilibrium. There is either too much hydrogen iodide and/or too little hydrogen and/or iodine in the cylinder.
To determine whether the system is at equilibrium, we can use the equilibrium constant expression for the reaction;
H₂(g) + I₂(g) ⇌ 2HI(g)
The equilibrium constant expression for this reaction is;
Kc = [HI]² / [H₂] [I₂]
We are given the partial pressures of each component in the cylinder, so we can calculate the concentrations using the ideal gas law.
[P] = n/V = (m/M) / V
where P is the partial pressure, n is the number of moles, V is the volume, m is the mass, M is the molar mass, and the square brackets denote concentration.
For hydrogen (H₂)
[P] = n/V = (m/M) / V
[m/M] = [P] x V
[m/M] = 0.127 atm x V / R x T
For iodine (I₂)
[P] = n/V = (m/M) / V
[m/M] = [P] x V
[m/M] = 0.134 atm x V / R x T
For hydrogen iodide (HI)
[P] = n/V = (m/M) / V
[m/M] = [P] x V
[m/M] = 1.055 atm x V / R x T
Switching these expressions into the equilibrium constant expression, we get;
Kc = ([HI]/V)² / ([H₂]/V) x ([I2]/V)
Kc = ([HI]² / V²) / ([H₂] x [I2] / V²)
Put in the values we get:
Kc = [(1.055 atm / V)² / (0.127 atm / V) x (0.134 atm / V)]
Kc = 8.37 atm² / V²
If the system is at equilibrium, the measured concentrations should give the same value for Kc as calculated above. If the measured Kc is different, then the system is not at equilibrium.
Therefore, we can calculate the measured Kc as;
Kc = ([HI]² / V²) / ([H₂] x [I2] / V²)
Kc = [(1.055 atm / V)² / (0.127 atm / V) x (0.134 atm / V)]
Kc = 8.87 atm² / V²
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which symbol is a measure of the favorability of a reaction, considering both the enthalpy and entropy?
The symbol that is a measure of the favorability of a reaction, considering both the enthalpy and entropy, is Gibbs free energy (ΔG).
The Gibbs free energy change of a reaction takes into account the change in enthalpy (ΔH) and the change in entropy (ΔS) of the system, and is given by the equation:
ΔG = ΔH - TΔS
where T is the temperature in Kelvin.
A negative value of ΔG indicates that the reaction is spontaneous and favors the formation of products, while a positive value of ΔG indicates that the reaction is non-spontaneous and favors the formation of reactants. At equilibrium, ΔG is zero, indicating that the reaction is in a state of balance between the reactants and products.
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as we add more co2 to the atmosphere, it will eventually come back down as: group of answer choices condensation meatballs carbonic acid, and acid rain rain
When we add more carbon in the atmosphere it warms the planet and helps the plants on land grow more. Excess of carbon can makes the water more acidic.
When carbon dioxide is added to atmosphere it reacts with water to form carbonic acid from which hydrogen ions dissociate and results in increasing the acidity of the system. So we can say that in addition to any greenhouse effect the anthropogenic carbon dioxide emissions to the atmosphere can increase the acidity of the atmosphere and precipitation of the atmosphere. Most of the plant species show higher rates of photosynthesis which cause increased growth and the decreased water use and lowered tissue concentrations of nitrogen and protein of the water.
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The correct question is,
What happens when too much CO2 enters the atmosphere?