Frank’s been traveling a lot lately as part of his job. During the past 30 days,he’s been out of town 18 days. What fraction represents the number of the 30 days that frank has been out of town? Explain how you got your answer

Answers

Answer 1

Answer:

[tex]n = \frac{3}{5}[/tex]. Which means that Frank has been travelling out of the town 3 days for each five days.

Step-by-step explanation:

The fraction ([tex]n[/tex]) is obtained by dividing the number of days that Frank has been out of town (18 days) in the given period (30 days). That is to say:

[tex]n = \frac{t}{T}[/tex]

[tex]t[/tex] - Out-of-the-town period, measured in days.

[tex]T[/tex] - Given period, measured in days.

If [tex]t = 18\,days[/tex] and [tex]T = 30\,days[/tex], then:

[tex]n = \frac{18\,days}{30\,days}[/tex]

[tex]n = \frac{3}{5}[/tex]

Which means that Frank has been travelling out of the town 3 days for each five days.


Related Questions

Plzzzzzzzzzzzzzzzzzzzzzz find the hcf of 15a²b² and -24ab

Answers

Let's take a look at each term separately.

15a^2b^2:

15 has factors 1, 3, 5, 15

a x a

b x b

-24ab

-24 has factors 1, 2, 3, 4, 6, 8, 12, 24

a

b

Now, we can see what each of these terms has in common. Both have a 3 in their factor lists, as well as one a and one b.

Therefore, the greatest common factor is 3ab.

Hope this helps!! :)

Answer:

3ab

Step-by-step explanation:

[tex]15a^{2} b^{2} - 24ab[/tex] is divided by 3

[tex]5a^{2} b^{2} - 8ab[/tex] take away a and b once

hope this helped!!!

[tex]5ab - 8[/tex]

= 3ab

Lengths of pregnancies​ (in humans) have a mean of 267.6 days and a standard deviation of 15.4 days. A woman tracked her pregnancy and found it to be 309 days. Find the z score for 309 days. Is such a length​ unusual?

Answers

Answer:

The z-score is  [tex]z = 2.65[/tex]

The length of days is not unusual

Step-by-step explanation:

From the question we are told that

     The population mean is  [tex]\mu = 267.6 \ days[/tex]

     The standard deviation is  [tex]\sigma = 15.4 \ days[/tex]

      The value considered is  [tex]x = 309 \ days[/tex]

The z-score is mathematically represented as

           [tex]z = \frac{x - \mu}{\sigma }[/tex]

            [tex]z = \frac{309 - 267.6}{15.6 }[/tex]

           [tex]z = 2.65[/tex]

Now given that the z-score is not greater than 3  then we can say that the length of days is not unusual

(reference khan academy)

a test consists of 10 true false questions to pass a test a student must answer at least six questions correctly if a student guesses on each question what is the probability that the student will pass the test A. 0.172 B. 0.205 C. 0.828 D. 0.377

Answers

Answer:

[tex] P(X \geq 6) = P(X=6) +P(X=7) +P(X=8) +P(X=9) +P(X=10)[/tex]

And using the probability mass function we got:

[tex]P(X=6)=(10C6)(0.5)^6 (1-0.5)^{10-6}=0.205[/tex]

[tex]P(X=7)=(10C7)(0.5)^7 (1-0.5)^{10-7}=0.117[/tex]

[tex]P(X=8)=(10C8)(0.5)^8 (1-0.5)^{10-8}=0.0439[/tex]

[tex]P(X=9)=(10C9)(0.5)^9 (1-0.5)^{10-9}=0.0098[/tex]

[tex]P(X=10)=(10C10)(0.5)^{10} (1-0.5)^{10-10}=0.000977[/tex]

And adding the values we got:

[tex] P(X\geq 6) = 0.377[/tex]

The best answer would be:

D. 0.377

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:

[tex]X \sim Binom(n=10, p=0.5)[/tex]

The probability mass function for the Binomial distribution is given as:

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]

Where (nCx) means combinatory and it's given by this formula:

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]

For this case in order to pass he needs to answer at leat 6 questions and we can rewrite this:

[tex] P(X \geq 6) = P(X=6) +P(X=7) +P(X=8) +P(X=9) +P(X=10)[/tex]

And using the probability mass function we got:

[tex]P(X=6)=(10C6)(0.5)^6 (1-0.5)^{10-6}=0.205[/tex]

[tex]P(X=7)=(10C7)(0.5)^7 (1-0.5)^{10-7}=0.117[/tex]

[tex]P(X=8)=(10C8)(0.5)^8 (1-0.5)^{10-8}=0.0439[/tex]

[tex]P(X=9)=(10C9)(0.5)^9 (1-0.5)^{10-9}=0.0098[/tex]

[tex]P(X=10)=(10C10)(0.5)^{10} (1-0.5)^{10-10}=0.000977[/tex]

And adding the values we got:

[tex] P(X\geq 6) = 0.377[/tex]

The best answer would be:

D. 0.377

A college administrator predicts that the proportion of students that are nursing majors is greater than 40%. To test this, a group of 400 students are randomly selected and it's determined that 190 are nursing majors. The following is the setup for this hypothesis test:

H0:p=0.40
Ha:p>0.40

In this example, the p-value was determined to be 0.001. Find the conclusion and interpret the results for this hypothesis test for a proportion (use a significance level of 5%)

Answers

Answer:

Step-by-step explanation:

Using the following data:

H0:p=0.40 (null hypothesis)

Ha:p>0.40 (alternative hypothesis)

The p-value was determined to be 0.001.

a significance level of 5%

Since the p value (0.001) is less than the significance level (0.05), we will reject the null hypothesis and then we would conclude that the proportion of students that are nursing majors is greater than 0.4.

Answer:

p value= 0.131

Step-by-step explanation:

Since we have calculated the test statistic, we can now proceed to find the p-value for this hypothesis test.Using the test statistic and since the hypothesis test is a left tailed test, the p-value will then be the area under the standard normal curve to the left of the test statistic of -1.12.Using the Standard Normal table given above, the area under the standard normal curve to the left of the test statistic of -1.12 is 0.131 (rounded to 3 decimal places.Thus the p-value = 0.131.

9. A college financial advisor wants to estimate the mean cost of textbooks per quarter for students at the college. For the estimate to be useful, it should have a margin of error of 20 dollars or less. The standard deviation of prices is estimated to be around 100 dollars. How large of a sample size needs to be used to be 95% confident, with the given margin of error?

Answers

Answer: 97

Step-by-step explanation:

Formula to compute the required sample size :

[tex]n= (\dfrac{\sigma\times z_{\alpha/2}}{E})^2[/tex]

, where [tex]\sigma[/tex] = standard deviation

E= Margin of error

[tex]z_{\alpha/2}[/tex] = Two tailed z-value.

Here, E= 20

[tex]\sigma[/tex] = 100

For 95% confidence level: [tex]z_{\alpha/2}[/tex] =1.96

Required sample size:

[tex]n=(\dfrac{100\times1.96}{20})^2\\\\=(5\times1.96)^2\\\\=96.04\approx97[/tex]

Hence, the required sample size : 97

Assume that IQ scores are normally distributed, with a standard deviation of 16 points and a mean of 100 points. If 60 people are chosen at random, what is the probability that the sample mean of IQ scores will not differ from the population mean by more than 2 points

Answers

Answer:

The probability that the sample mean of IQ scores will not differ from the population mean by more than 2 points is 0.67

Step-by-step explanation:

Please check attachment for complete solution and step by step explanation

Y+15<3 what is the solution

Answers

Answer:

y < -12

Step-by-step explanation:

Step 1: Subtract 15 on both sides

y + 15 - 15 < 3 - 15

y < -12

This inequality means the any number smaller than -12 would work. So:

-123415235 would work

-1234 would work

-46527 would work

2 would NOT work

6 would NOT work

Answer:

[tex]y < - 12[/tex]

Step-by-step explanation:

[tex]y + 15 < 3[/tex]

Move constant to RHS and change its sign:

[tex]y < 3 - 15[/tex]

Calculate the difference

[tex]y < - 12[/tex]

Hope this helps..

Good luck on your assignment..

conditinal probability question. please help! :)​

Answers

Answer:

P(A|B) = 1 / 6

Step-by-step explanation:

Assuming two fair sided dice with faces numbered 1 to 6.

By intuition, there can only be 6 possible outcomes, so probability is 1/6.

Illustration how to use conditional probability.

Given two events A, B, following is the equation of conditional probability

that A happens given B has already happened and observed.

P(A|B) = P( A intersect B ) / P(B)

In the given problem,

A = casting a double-six

B = casting a double

P(A) = (1 / 6) * (1 / 6) = 1/36

P(B) = (6/6) * (1/6) = 1/6

P(A|B) = 1/36 / (1/6) = 1/6

In triangle abc what is the value of cos b A 5/13 B 12/13 C 5/12 D 13/12

Answers

Answer:

[tex]\boxed{Option \ B}[/tex]

Step-by-step explanation:

In the triangle,

Hypotenuse = 13

Opposite = Perpendicular = 5

Adjacent = Base = 12

Now,

Cos B = [tex]\frac{Adjacent}{Hypotenuse}[/tex]

Cos B = 12/13

If the triangle is just like in the attached file!

Answer:

B) 12/13

Step-by-step explanation:

QUESTION 4 (10 MARKS)
A retired couple requires an annual return of $2,000 from investment of $20,000. There are 3
options available:
(A) Treasury Bills yielding 9%;
(B) Corporate bonds 11%;
Junk Bonds. 130%
How much should be invested in each to achieve their goal? Give 3 sets of options that can
achieve their goal.[10 Marks]​

Answers

Answer:

  (T, C, J) = (in dollars)

     (10000, 10000, 0),

     (15000, 4915.97, 84.03),

     (18181.82, 1680.67, 137.51)

Step-by-step explanation:

There are a number of ways to approach this question. We have chosen an approach that determines the investments required to achieve interest rate targets.

__

For an overall interest rate of I, the proportion that must be invested at rate I1 < I < I2 is ...

  proportion at I1 = (I2 -I)/(I2 -I1)

Similarly, the proportion that must be invested at I2 is what's left over. It can be computed similarly:

  proportion at I2 = (I -I1)/(I2 -I1)

__

We want an overall interest rate of $2000/$20000 = 10%.

Given available interest rates of 9%, 11%, and 130%, we need to have investments at a rate lower than 10% and at a rate higher than 10%.

If we use only the options for 9% and 11% (no junk bonds), then we can compute ...

  proportion at 9% = (11 -10)/(11 -9) = 1/2

  proportion at 11% = (10 -9)/(11 -9) = 1/2

1st Option:

  $10,000 in treasury bills; $10,000 in corporate bonds

__

Suppose we want to achieve a 13% return on our investments at 11% and 130%. Then the proportion invested at 9% will use this value for I2:

  proportion at 9% = (13 -10)/(13 -9) = 3/4

Of the remaining 1/4 of the money, we can achieve a 13% return by mixing the investments like this:

  proportion at 11% = (130 -13)/(130 -11) = 117/119

  proportion at 130% = (13 -11)/(130 -11) = 2/119

2nd option:

  $20,000 × 3/4 = $15,000 in treasury bills

  $5000 × 117/119 = $4,915.97 in corporate bonds

  The remaining amount, $84.03 in junk bonds

__

Let's suppose we want a 20% return on our investment in junk bonds and corporate bonds. Then the proportion of the money invested at 9% will be ...

  proportion at 9% = (20 -10)/(20 -9) = 10/11

And the proportion at 11% will be ...

  proportion at 11% = (130 -20)/(130 -11) = 110/119 . . . (of the remaining 1/11 of the funds)

3rd option:

  $20,000 × 10/11 = $18,181.82 in treasury bills

  $1,818.18 × 110/119 = $1,680.67 in corporate bonds

  The remaining amount, $137.51 in junk bonds

_____

Additional comment

The most that could be invested in Junk Bonds is $165.29. If the remainder is invested in Treasury Bills, then the overall return will be $2000. (You could consider this to be a 4th option.)

Compute P7,2. (Enter an exact number.)
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Answers

Answer:

42

Step-by-step explanation:

The permutation formula is P(n, r) = n! / (n - r)!. We know that n = 7 and r = 2 so we can write:

7! / (7 - 2)!

= 7! / 5!

= 7 * 6 * 5 * 4 * 3 * 2 * 1 / 5 * 4 * 3 * 2 * 1

= 7 * 6 (5 * 4 * 3 * 2 * 1 cancels out)

= 42

Answer:

[tex]\boxed{42}[/tex]

Step-by-step explanation:

Apply the permutation formula.

[tex]P(n,r)=\frac{n!}{ (n-r)!}[/tex]

[tex]P=number \: of \: permutations\\n=total \: number \: of \: objects \: in \: the \: set\\r=number \: of \: choosing \: objects \: from \: the \: set\\[/tex]

[tex]n=7\\r=2[/tex]

Plug in the values and evaluate.

[tex]P(7,2)=\frac{7!}{ (7-2)!}[/tex]

[tex]P(7,2)=\frac{7!}{ (5)!}[/tex]

[tex]P(7,2)=\frac{5040}{120}[/tex]

[tex]P(7,2)=42[/tex]

67.805 what is the value of the 0 help please asap!​

Answers

Answer:

hundreths

Step-by-step explanation:

After the decimal there is tenths, hundreths thousandnths, tens of thousands e.t.c

Answer:

Hello! The answer will be hundredths.

Step-by-step explanation:

The 5 means the thousandths.

The 0 means the hundredths.

The 8 means the tenths.

The 7 means the ones

And the 6 means the tens.

Hope this helps! :)

( below I attached a picture, which might be helpful.)

A researcher is interested in determining the mean energy consumption of a new
compact florescent light bulb. She takes a random sample of 41 bulbs and determines
that the mean consumption is 1.3 watts per hour with a standard deviation of 0.7.
When constructing a 97% confidence interval, which would be the most appropriate
value of the critical value?

A) 1.936
B) 2.072
C) 2.250
D) 2.704
E) 2.807


Answers

Answer:

The most appropriate  value of the critical value is 2.289.

Step-by-step explanation:

We are given that a researcher takes a random sample of 41 bulbs and determines  that the mean consumption is 1.3 watts per hour with a standard deviation of 0.7.

We have to find that when constructing a 97% confidence interval, which would be the most appropriate  value of the critical value.

Firstly, as we know that the test statistics that would be used here is t-test statistics because we don't know about the population standard deviation.

So, for finding the critical value we will look for t table at (41 - 1 = 40) degrees of freedom at the level of significance will be [tex]\frac{1 - 0.97}{2} = 0.015[/tex] .

Now, as we can see that in the t table the critical values for P = 1.5% are not given, so we will interpolate between P = 2.5% and P = 1%, i.e;

     [tex]\frac{0.015 - 0.025}{0.025-0.01}= \frac{\text{Critcal value}-2.021}{2.021-2.423}[/tex]

So, the critical value at a 1.5% significance level is 2.289.

A manufacturer claims that the mean tensile strength of thread A exceeds the average tensile strength of thread B. To test his claim, 16 sample pieces of each type of thread are tested under similar conditions. Type A thread had a sample average tensile strength of 185 kg with a standard deviation of 6 kg, while type B thread had a sample average tensile strength of 178 kg with a standard of 9 kg. Assume that both populations are normally distributed and the variances are equal. Test the manufacturers claim using a = 0.05 level of significance.

Answers

The complete part of the first sentence is;

A manufacturer claims that the average tensile strength of thread A exceeds the average tensile strength of thread B by at least 12 kilograms.

Answer:

we fail to reject the null hypothesis and conclude that the difference of the average tensile strength of thread A and thread B is less than 12

Step-by-step explanation:

We are given;

n_A = 16

n_B = 16

x'_A = 185 kg

x'_B = 178 kg

s_A = 6 kg

s_B = 9 kg

Let μ_A denote the population average tensile strength of thread A

Also, Let μ_B represent the population average tensile strength of thread B

Thus;

Null Hypothesis; H0;μ_A - μ_B ≤ 12

Alternative hypothesis;H1; μ_A - μ_B > 12

From the image attached, with a significance level of 0.05, the critical value for right tailed is 1.645. So we will reject the hypothesis is z > 1.645

Formula for z is;

z = (x'_A - x'_B - d_o)/√((s_A²/n_A) + (s_B²/n_B))

Plugging in the relevant values, we have;

z = (185 - 178 - 12)/√((6²/16) + (9²/16))

z = -5/2.7041634566

z = - 1.849

Since the z-value is less than 1.645,we fail to reject the null hypothesis and conclude that the difference of the average tensile strength of thread A and thread B is less than 12

Can two events with nonzero probabilities be both independent and mutually​ exclusive? Choose the correct answer below. A. ​Yes, two events with nonzero probabilities can be both independent and mutually exclusive when their probabilities add up to one. B. ​No, two events with nonzero probabilities cannot be independent and mutually exclusive because if two events are mutually​ exclusive, then when one of them​ occurs, the probability of the other must be zero. C. ​Yes, two events with nonzero probabilities can be both independent and mutually exclusive when their probabilities are equal. D. ​No, two events with nonzero probabilities cannot be independent and mutually exclusive because independence is the complement of being mutually exclusive.

Answers

Answer:

Step-by-step explanation:

B. ​No, two events with nonzero probabilities cannot be independent and mutually exclusive because if two events are mutually​ exclusive, then when one of them​ occurs, the probability of the other must be zero.

For two mutually exclusive events , with non- zero probabilities , when one occurs , the other can not happen . In this way they become dependent events . In this way , for two events to be both independent and mutually exclusive , at least one of the two events must have zero probability .

It should be noted that two events with nonzero probabilities cannot be independent and mutually exclusive because if two events are mutually​ exclusive, then when one of them​ occurs, the probability of the other must be zero.

Mutually exclusive events simply means the events that cannot take place at the same time. The occurrence of one of the events will prevent the other event from occuring.

Therefore, two events with nonzero probabilities cannot be independent and mutually exclusive because if two events are mutually​ exclusive, then when one of them​ occurs, the probability of the other must be zero.

Read related link on:

https://brainly.com/question/15179003

Which of the following functions best describes this graph ?

Answers

Answer:

answer D

Step-by-step explanation:

Lets have a look to the graph and to the  each of given functions.

As we can see in graph it intersects X in points (-3;0) and (-6;0) that means the function has the roots x1=-3 and x2=-6

Function A  has the roots x1=+3 and x2=+6 => doesn' t fit

Function B has only 1 root x=2 , so can be factorized y=(x-2)^2 => doesn' t fit

Function C has 2 roots  x1=4  and x2=-5 => doesn' t fit

Function D can be factotized as y=(x+6)*(x+3) so has 2 roots x1=-6 x2=-3 => exactly what we need!!!

We can also notice that the coefficient near x²  is equal to 1  and is positive.

That means the legs of the graph directed up,- this is exactly like in our graph. It gives us extra argument why we choose D.

If we assume that asset X has an expected return of 10 and a variance of 10, then its coefficient of variation is:

Answers

Answer: Its coefficient of variation = 0.316

Step-by-step explanation:

The formula to find the coefficient of variations:

Coefficient of variation: [tex](\dfrac{\sqrt{\text{variance}}}{\text{return}})[/tex]

Given: Asset X has

Variance = 10

Expected return = 10

then, coefficient of variation [tex]=\dfrac{\sqrt{10}}{10}=\dfrac{1}{\sqrt{10}}\approx0.316[/tex]

Hence, its coefficient of variation = 0.316

Find the solution(s) of the quadratic equation 2x2 – 3x – 35 = 0

Answers

Answer: x = 5, x = -7/2

Step-by-step explanation:

2x² - 3x - 35 = 0

Step 1: Find two values whose product = 2(-35) and sum = -3:  -10 & 7

Step 2: Replace the b-value of -3x with  -10x + 7x:

2x² - 10x   + 7x - 35 = 0

Step 3: Factor the first two terms and the second two terms:

2x(x - 5)  +7(x - 5) = 0

Step 4: Write the factored form:

Notice that the parenthesis are identical.  This is one of the factors. The outside values are the other factor:

Parenthesis: (x - 5)

Outside: (2x + 7)

Factored form: (x - 5)(2x + 7) = 0

Step 5: Set each factor each to zero and solve for x:

x - 5 = 0             2x + 7 = 0

   x - 5                      [tex]x=-\dfrac{7}{2}[/tex]

The solutions of the quadratic equation given as 2x² - 3x - 35 = 0 are x=5 and x =-3.5.

Given that:

2x² - 3x - 35 = 0

This is a quadratic equation.

It is required to find the solutions of this equation.

The solution of the quadratic equation of the form ax² + bx + c = 0 can be found using the quadratic formula:

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

From the given equation:

a = 2

b = -3

c = -35

Substitute to the quadratic formula.

[tex]x=\frac{-(-3)\pm \sqrt{(-3)^2-4(2)(-35)}}{2(2)}[/tex]

  [tex]=\frac{3\pm \sqrt{9+280}}{4}[/tex]

  [tex]=\frac{3\pm \sqrt{289}}{4}[/tex]

  [tex]=\frac{3\pm 17}{4}[/tex]

So, the solutions are:

[tex]x=\frac{3+ 17}{4}=5[/tex], and [tex]x=\frac{3-17}{4}=-3.5[/tex]

Hence, the solutions are x =5, -3.5.

Learn more about Quadratic Formula here :

https://brainly.com/question/22364785

#SPJ6

The coldest temperature ever recorded in New York City was -15F on Feb 9, 1934. The next day, the temperature rose
Write an expression for the temperature on Feb 10

Answers

Answer:

x = -15 + y

Step-by-step explanation:

Let next days temperature be x and the temperature rise be y

=> x = -15 + y

The next day's temperature will be more since it "rose".

Answer:

[tex]\boxed{x=-15+y}[/tex]

Step-by-step explanation:

Let the temperature on Feb 10, 1934 be x.

Let the temperature increase be y.

On Feb 9, the temperature was -15F.

On Feb 10, the temperature increased.

[tex]x=-15+y[/tex]

Find the amount necessary to fund the given withdrawals. Semiannual withdrawals of 850 for 6 years,interest rate is 4.7% compounded semiannually.

Answers

Answer:

The amount necessary to fund the withdrawal is $8798.820

Step-by-step explanation:

Here, we are interested in calculating the necessary amount to fund the withdrawal given in the question.

From the question, we can identify the following;

Principal amount, P= $850

Here, Period rate, i = 0.047/ 2 =0.0235

n = 6*2 = 12

Mathematically;

Present Value of an annuity, Ao=P* [1-(1+i)^{-n}]/i

Ao=850* [1-(1+0.0235)^{-12}] /0.0235

Ao = $8798.820

Find one solution for the equation. Assume that all angles involved are acute angles. tangent (3 Upper B minus 32 degrees )equals cotangent (5 Upper B plus 10 degrees )

Answers

Answer:

Step-by-step explanation:

Equation given

tan(3B-32 ) = cot ( 5B +10 ) = tan [ 90 - ( 5B + 10 ) ]

tan(3B-32 ) = tan  (90 - 5B - 10 )

(3B-32 ) =  (90 - 5B - 10 )

8B = 32 + 80

B = 14° .

Which of the following is an exterior angle of triangle BHE? Yes or no​

Answers

Answer:

Im not 100% sure, but I think it is:

No

No

No

Yes

2.4.6.8. 10.... geometrical,arithmetic or neither?​

Answers

Answer:

This is an arithmetic sequence.

Step-by-step explanation:

The difference between the consecutive terms is constant => sequence is arithmetic.

4-2 = 2

6-4= 2

8-6 = 2

10-8 = 2

Step-by-step explanation:

It's an arithmetic sequences.

Formed by the n th term 2n.

As the difference is 2 between them.

let's find it, by formulae.

n th term = 2n

t1= 2×1=2t2 = 2×2=4t3=2×3=6t4=2×4=8

and so on.....

Therefore, it's an arithmetic sequence.

Hope it helps..

What is the focus of the parabola? y=−1/4x2−x+3

Answers

Answer:  Focus = (-2, 3)

Step-by-step explanation:

[tex]y=-\dfrac{1}{4}x^2-x+3\\\\\rightarrow a=-\dfrac{1}{4},\ b=-1[/tex]

First let's find the vertex. We do that by finding the Axis-Of-Symmetry:

[tex]AOS: x=\dfrac{-b}{2a}\quad =\dfrac{-(-1)}{2(\frac{-1}{4})}=\dfrac{1}{-\frac{1}{2}}=-2[/tex]

Then finding the maximum by inputting x = -2 into the given equation:

[tex]y=-\dfrac{1}{4}(-2)^2-(-2)+3\\\\y=-1+2+3\\\\y=4[/tex]

The vertex is: (-2, 4)

Now let's find p, which is the distance from the vertex to the focus:

[tex]a=\dfrac{1}{4p}\\\\\\-\dfrac{1}{4}=\dfrac{1}{4p}\\\\\\p=-1[/tex]

The vertex is (-2, 4) and p = -1

The focus is (-2, 4 + p) = (-2, 4 - 1) = (-2, 3)

The population density, D, in people/square mile (p/mi²), for the large city Westport is related to the distance x (in miles) from the city’s center by the equation:________.
D=4300x /x^2 + 40.
a. Describe what happens to West-port's population density as the distance from the city’s center changes from one mile to six miles. What may explain this phenomenon?
b. Describe what happens to West-port's population density as the distance from the city’s center changes from ten miles to thirty miles.
c. Describe the end-behavior of this function? What may explain this phenomenon?
d. In what areas of the city is the population density below 200 p/mi²?

Answers

Answer:

Step-by-step explanation:

  D=4300x /x² + 40.

x = 1

D = 4300 / 41 = 104.88 p / mi²

x = 6

D = 25800 / 76

= 339.47  p / mi²

Population density increases as we go away from city's centre .

b )

x = 10

D=4300x /x² + 40.

D = 307.14 p/ mi²

x = 30

D = 137.23 p / mi²

Population decreases .

c )

when x is very high , density will decrease due to squared denominator whose value increases very fast .

d )

D < 200

4300x /x² + 40 < 200

4300 x < 200 x² + 8000

43 x < 2 x² + 80

2 x² - 43 x + 80 > 0

( x - 19.44 ) ( x - 2.05 ) > 0

Range x <  2.05

x > 19.44

Please help, much needed. A lot of points

Answers

Answer:

A. -9

Step-by-step explanation:

If one of the variables were negative than, it would not be able to equal 2/7.

It’s A which is -9, have a good day

What is the inverse of the function

Answers

Answer:

A

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = [tex]\frac{19}{x^3}[/tex] ( multiply both sides by x³ )

x³y = 19 ( divide both sides by y )

x³ = [tex]\frac{19}{y}[/tex] ( take the cube root of both sides )

x = [tex]\sqrt[3]{\frac{19}{y} }[/tex]

Change y back into terms of x, then

[tex]f^{-1}[/tex] (x) = [tex]\sqrt[3]{\frac{19}{x} }[/tex] = [tex]\frac{\sqrt[3]{19} }{\sqrt[3]{x} }[/tex] → A

Suppose taxi fares from Logan Airport to downtown Boston is known to be normally distributed and a sample of seven taxi fares produces a mean fare of $21.51 and a 95% confidence interval of [$20.52, $22.48]. Which of the following statements is a valid interpretation of the confidence interval?
a. 95% of all taxi fares are between $20.52 and $22.48.
b. We are 95% confident that a randomly selected taxi fare will be between $20.52 and $22.48.
c. We can report that the average taxi fare between Logan Airport and downtown Boston will fall between $20.52 and $22.48.
d. With 95% confidence

Answers

Answer:

The correct option is C

Step-by-step explanation:

From the question we are told that

   The  sample mean is  [tex]\= x =[/tex]$21.51

    The 95%  confidence level interval  is  [$ 20.52 , $22.48]

Generally the 95%  confidence level interval is mathematically represented as

      [tex]\= x - MOE < \mu < \= x + MOE[/tex]

Where  MOE  is the margin of error which defines in percentage the amount by which the sample mean taxi fare(for the 7 taxi  ) will differ from the average taxi fare between Logan Airport and downtown Boston will fall between

Also  [tex]\mu[/tex] is the  average taxi fare between Logan Airport and downtown Boston

So we see that the this 95%  confidence level interval tells us  that  the average taxi fare between Logan Airport and downtown Boston will fall between $20.52 and $22.48.

Which statement is true about the function f(x)= -x?
O The domain of the graph is all real numbers.
The range of the graph is all real numbers.
O The domain of the graph is all real numbers less than or equal to 0.
The range of the graph is all real numbers less than or equal to 0.

Answers

Answer:

The domain of the graph is all real numbers less than or equal to 0.

Step-by-step explanation:

Hello,

We know that we cannot take square root of negative numbers, so we must have

[tex]-x\geq 0 \ \text{ ***multiply by -1, it changes the inequality, so*** } \\ \\\large \boxed{\sf \ \ x\leq0 \ \ }[/tex]

So the domain of the graph is all real numbers less than or equal to 0.

For information, I attached the graph so that we can verify it.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Mia agreed to borrow a 3 year loan with 4 percent interest to buy a motorcycle if Mia will pay a total of $444 in interest how much money did she borrow how much interest would Mia pay if the simple interest rate was 5 percent

Answers

Answer:

a) $3700

b) $555

Step-by-step explanation:

The length of the loan is 3 years.

The interest after 3 years is $444.

The rate of the Simple Interest is 4%.

Simple Interest is given as:

I = (P * R * T) / 100

where P = principal (amount borrowed)

R = rate

T = length of years

Therefore:

[tex]444 = (P * 3 * 4) / 100\\\\444 = 12P / 100\\\\12P = 444 * 100\\\\12P = 44400\\\\P = 44400 / 12\\[/tex]

P = $3700

She borrowed $3700

b) If the simple interest was 5%, then:

I = (3700 * 5 * 3) / 100 = $555

The interest would be $555.

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