The position of the center of mass of the system from corner A is 4.3692cm.
To find the position of the center of mass of the system, we need to use the formula:
C.M. = (m1r1 + m2r2 + m3r3 + m4r4)/(m1 + m2 + m3 + m4)
where m1, m2, m3, and m4 are the masses of the four-point masses, and r1, r2, r3, and r4 are the distances of the point masses from the reference point (in this case, corner A).
Let's first find the distances of the four-point masses from corner A. We can see that the distance of the 2kg mass from corner A is 2 cm. The distance of the 4kg mass from corner A is the diagonal of a square of side 2 cm, which is sqrt(22 + 22) = 2.828 cm. Similarly, the distances of the 6kg and 8kg masses from corner A are also 2.828 cm.
Now, let's substitute the values in the formula:
C.M. = (2kg2cm + 4kg2.828cm + 6kg2.828cm + 8kg2.828cm)/(2kg + 4kg + 6kg + 8kg)
C.M. = (4cm + 11.312cm + 16.968cm + 22.624cm)/20kg
C.M. = 1.824cm + 0.5656cm + 0.8484cm + 1.1312cm
C.M. = 4.3692cm
Therefore, the position of the center of mass of the system from corner A is 4.3692cm.
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Which of the following is not considered a bloodborne pathogen
Influenza virus is not considered as a bloodborne pathogen. The correct answer is option D.
Bloodborne pathogens are infectious microorganisms that can cause disease when transmitted through contact with infected human blood or other body fluids.
They can include viruses, bacteria, and other microorganisms that can cause serious illness or even death.
Influenza virus is not considered a bloodborne pathogen because it is primarily a respiratory virus that spreads through droplets when an infected person talks, coughs, or sneezes.
It can also spread through contact with contaminated surfaces or objects, but it is not primarily transmitted through contact with blood or other body fluids.
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The probable question may be:
Which of the following is not considered a bloodborne pathogen
A. Hepatitis B virus
B. Human immunodeficiency virus (HIV)
C. Hepatitis C virus
D. Influenza virus
1) Three masses hang about a 3 meter stick whose fulcrum is at
50cm. A mass of m1=60.0 kg hangs at the 90.0 cm mark, m2= 20.0 kg hangs at the 20.0 cm mark. Find the location of the mass, m3= 10 kg to obtain static equilibrium. If it is not possible to reach equilibrium, then select a new pivot point and draw a new diagram that will allow the system to reach static equilibrium with the same lever arms values as before for all masses.
The mass m3 should be placed 0.8 m away from the fulcrum to achieve static equilibrium.
Static equilibriumTo achieve static equilibrium, the net torque acting on the system must be zero. The torque is given by the product of the force and the lever arm. Taking the fulcrum as the reference point, we can write:
(m1)(g)(0.9 m - 0.5 m) + (m2)(g)(0.2 m - 0.5 m) + (m3)(g)(x - 0.5 m) = 0
where g is the acceleration due to gravity (9.81 m/s^2) and x is the distance of the mass m3 from the fulcrum.
Simplifying and solving for x, we get:
x = [(m1)(0.9 m - 0.5 m) + (m2)(0.2 m - 0.5 m)] / (m3) + 0.5 m
x = [((60.0 kg)(0.4 m) + (20.0 kg)(-0.3 m))] / (10.0 kg) + 0.5 m
x = 0.8 m
Therefore, the mass m3 should be placed 0.8 m away from the fulcrum to achieve static equilibrium.
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During an ultrasound, sound waves are sent by a transducer through muscle tissue at a speed of 1,300 m/s. Some of the sound waves are reflected from a metal fragment 5.0 cm into the muscle tissue. How long did it take the transducer to detect the reflected waves from the metal fragment after they were first emitted?
0.26 seconds
39 seconds
4.6 E−5 seconds
7.7E−5 seconds
Will the placement of the continents on Earth look different in 100 million years than today?
Answer:
Yes
Explanation:
Continents is constantly moving, but at very slow rate.
This is due to the movement of the tectonic plate underneath the earth surface.
On average they move about 10 cm per year.
So in 100 million, they will move 10,000 km.
Of course, how the continents looks 100 million years from now will be very different than today.
The second law of thermodynamics states that
a change in a system's energy is equal to the energy
transferred to the system.
energy cannot be created or destroyed.
energy can flow from a colder object to a warmer object
only if something does work.
the only way to reduce an object's temperature is to
increase the entropy of the environment.
Answer: energy can flow from a colder object to a warmer object
only if something does work.
Explanation: Consider the flow of water from a higher level to a lower level. There is no need to use energy to make this process occur. This type of process which does not need the application of energy to take place is said to be spontaneous. But to make water go up to the water tank, a pump must be used to make the process take place. This type of process which needs the use of energy to make it happen is said to be nonspontaneous.
but why not the only way to reduce an object's temperature is to
increase the entropy of the environment.?
coz the motion of particles decreases and their velocity decreases so they have less entropy at a lower temperature.
hope it helped:)
As clothing tumble in a dryer, they can become charged. If a small piece of lint with a charge of +1.62 E−19 C is attracted to the clothing by a force of 2.0 E−9 N, what is the magnitude of the electric field at this location?
0.38 E10 N/C
1.2 E10 N/C
3.2 E10 N/C
3.6 E10 N/C
Answer:
1.2 E10 N/C
Explanation:
The force between two charged objects can be calculated using Coulomb's law:
F = k * q1 * q2 / r^2
where F is the force, k is Coulomb's constant (k = 8.99 x 10^9 N m^2 / C^2), q1 and q2 are the charges of the two objects, and r is the distance between them.
Rearranging this equation to solve for the electric field at a point, we get:
E = F / q
where E is the electric field strength and q is the charge at that point.
Substituting the given values, we get:
E = (2.0 x 10^-9 N) / (1.62 x 10^-19 C)
E = 12345.68 N/C
Therefore, the magnitude of the electric field at this location is 1.235 x 10^4 N/C.
What is the difference between analog signal and digital signal. Explained in essay form.
A continuous signal that changes in frequency and amplitude over time is referred to as an analogue signal. A digital signal one can only take on a small number of values and is commonly represented by 0s and 1s.
Being able to take on any value within a continuous range of values makes it the perfect choice for simulating physical phenomena like temperature, sound, and light. Analogue signals include things like radio waves, vinyl records, and conventional telephone networks. Modern communication and computing systems use digital signals instead of analogue ones because they can be transferred and processed more effectively and are less prone to noise. Computer networks and digital cameras are few examples of digital signals.
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what is the unit of time not based on a heavenly body
1. Choose one from the following countries:
o United States
o United Kingdom
o Australia
o Nepal
o Russia
o Spain
o India
2. Then make research of some laws supporting sexuality and gender in your
chosen country.
uk
because they have a Sexuality law
calculate the electric field at the centre of a square 60cm on a side if one corneris occupied by a +45uC charge and the other three corners are occupied by -31uC charge
Question 11 of 25
In the circuit below, resistors R₁ and R₂ are in parallel. What is the equivalent
1
1
resistance? (R₁ = 30 22,R₂ = 20 2) (
A
+A)
Ptot R₁
S₁
S₂
R₁
S₂ S
ww
R₂
1
R₂₂k
Answer:
60 ohms
Explanation:
To find the equivalent resistance of two resistors R₁ and R₂ in parallel, we can use the formula:
1/Req = 1/R₁ + 1/R₂
where Req is the equivalent resistance.
Substituting the values given, we get:
1/Req = 1/30 + 1/20
Simplifying, we get:
1/Req = 1/60
Multiplying both sides by Req, we get:
Req = 60 ohms
Therefore, the equivalent resistance of the two resistors R₁ and R₂ in parallel is 60 ohms.
The pressure difference between two locations is 0.005 Torr .Which one of the following barometers is preferred to measure the small pressures accurately? (knowing that: Density of mercury = 13600 kg/m³, density water = 1000 kg/m³, density of oil = 800 kg/m³
A-Mercuric barometer
B-Oil-water barometer
C-Water barometer
D-Oil barometer
Due to its high density, the mercury barometer is the greatest option for precisely measuring minor changes in pressure. The correct option is A.
A barometer is an instrument used to measure atmospheric pressure. It typically consists of a long glass tube filled with a liquid, usually mercury, and inverted in a container of the same liquid.
The preferred barometer to measure small pressures accurately would be the mercury barometer (option A), because it has a higher density compared to the other options and hence it can detect smaller changes in pressure.
To see why the other options are not as good for measuring small pressures accurately, we can compare their densities:
Oil-water barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.
Water barometer: The density of water is much lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.
Oil barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.
Therefore, option A, the mercury barometer, is the best choice for measuring small changes in pressure accurately due to its high density.
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A is a sphere that is traveling with velocity of (3,7)m/s and had a mass of 5 kg .it collide with sphere B and both particle move together with velocity of (1,4)m/s after the collision. Sphere B has a mass of 4 kg . Find the velocity of B before the collision
The velocity of sphere B is -1.475 m/s. Which is in opposite direction to the direction of sphere A.
What is velocity?Velocity is the rate of change of displacement.
To calculate the velocity of sphere B before collision, we use the formula below
Formula:
u = [V(M+m)-Mu']/m................... Equation 1Where:
u = Velocity of sphere B before collisionV = Velocity of both particles after collisionM = Mass of sphere Am = Mass of sphereu' = Velocity of sphere B before collisionFrom the question,
Given:
V = 1.4 m/sM = 5 kgm = 4 kgu' = 3.7 m/sSubstitute these values into equation 1
u = [1.4(5+4)-(5×3.7)]/4u = (12.6-18.5)/4u = -5.9/4u = -1.475Hence, the velocity of sphere B is -1.475 m/s.
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The graph shows how the speed of a car travelling in a straight line changes with time. Which section shows the largest acceleration? speed A B C D time
The section that shows the largest acceleration on the graph would be section B, as it has the steepest slope.
This indicates that the car is increasing in speed at a faster rate during this section compared to the other sections.
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complete question not found in search engine.
A rocket is fired from the earth to the moon at a speed of 0.930c. Let two events be "rocket leaves earth" and "rocket hits moon"
A. In the earth's reference frame, calculate Δx for these events.
B. In the earth's reference frame, calculate Δt for these events.
C. In the earth's reference frame, calculate the spacetime interval s for these events.
D. In the earth's reference frame, calculate Δx' for these events.
E. In the earth's reference frame, calculate Δt' for these events.
F. In the earth's reference frame, calculate the spacetime interval s' for these events.
G. In the earth's reference frame, calculate Δx if a rocket is replaced with a laser beam.
H. In the earth's reference frame, calculate Δt if a rocket is replaced with a laser beam.
I. In the earth's reference frame, calculate the spacetime interval s if a rocket is replaced with a laser beam.
Express ALL parts with appropriate units
A. Δx = 384,400 km (distance between Earth and Moon)
How to solveB. Δt = 384,400 km / (0.930 * 299,792 km/s) ≈ 1.421 s
C. s² ≈ (-2.781 * 10^10) km² (imaginary number, time-like separated events)
D, E, F. Cannot answer without specified primed frame.
G. Δx for laser beam = 384,400 km
H. Δt for laser beam = 384,400 km / 299,792 km/s ≈ 1.282 s
I. s² for laser beam ≈ 0 km² (light-like separated events)
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What is amplitude and phase in electrical and electronics circuit?
In electrical and electronics circuits, amplitude is the maximum value of a signal. This is known as the strength or intensity of the signal. Phase, can be seen as the timing relationship between two signals or waveforms. It tell the time it takes betwen the peaks or zero crossings of two waveforms
What more should you know about phase in electrical and electronics circuits?In electrical and electronics circuits, phase tell us about the the relationship between currents in different parts of the circuit, For example in AC circuits with multiple components.
We the amplitude and phase of signals in electrical and electronics circuits is understood, it becomes easier to design and analyz circuits, and can even be used for troubleshooting and maintaining them.
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Four point masses 2kg, 4kg, 6kg and 8kg are placed at the corners of Square ABCD of 2cm long respectively. Find the Position of centre of mass of the system from the corner A.
please help me I give you 50 coins
I don’t understand this pls help
What is the current theory about the formation of the solar system?
Responses
About 14 billion years ago, several supernova events scattered all the known elements throughout the galaxy. The magnetic elements were attracted to each other and formed the early celestial bodies that eventually became the planets of the solar system.
About 14 billion years ago, several supernova events scattered all the known elements throughout the galaxy. The magnetic elements were attracted to each other and formed the early celestial bodies that eventually became the planets of the solar system.
A big bang occurred in the solar system as a result of a fusion reaction. All the matter in the solar system that had been clumped together was shattered and sent flying. As new pieces of matter connected, all the celestial bodies of the solar system were formed.
A big bang occurred in the solar system as a result of a fusion reaction. All the matter in the solar system that had been clumped together was shattered and sent flying. As new pieces of matter connected, all the celestial bodies of the solar system were formed.
The area of the universe that was to become the solar system went through a period of vast expansion as a result of rapid radioactive decay that left behind clouds of dust and gases. The excess clouds and gases were used to form the various parts of the solar system.
The area of the universe that was to become the solar system went through a period of vast expansion as a result of rapid radioactive decay that left behind clouds of dust and gases. The excess clouds and gases were used to form the various parts of the solar system.
The solar system began as a cloud of dust and gas that condensed, forming a bulging middle and an outer disk. The bulging middle of the cloud became the sun, and the rest of the dust and gas formed the planets, orbiting the sun in the same plane.
The current theory about the formation of the solar system is that it began as a cloud of dust and gas, known as the solar nebula which is the last response.
What happened to the nebula?The nebula collapsed under its own gravity, forming a spinning disk with a bulging middle that became the sun. The remaining dust and gas in the disk coalesced into small bodies, which collided and stuck together, forming the planets.
This process, known as accretion, resulted in the four inner planets, which are small and rocky, and the four outer planets, which are large and gas-rich.
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Which of the following is the dimension of moment of inertia? (a) ML2 (b) MLT-1 (c) L2T 2 (d) L T-1
The dimension of the moment of inertia is [tex]ML^2[/tex]. Option A.
What is the moment of inertia?The moment of inertia represents the resistance of a body to rotational motion. It depends on the body's mass and the distribution of that mass around the axis of rotation.
The formula for the moment of inertia involves mass and distance and is expressed as:
I = mr^2
where
m is the mass of the bodyr is the distance from the axis of rotation.The dimension of mass is represented by M, and the dimension of distance is represented by L. Therefore, the dimension of moment of inertia is:
Moment of inertia = mass x distance^2 = M x L^2 = [tex]ML^2[/tex].
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graph
shows a variety of moving objects and how their distance is related to time what do these objects have in common
What is common among all the graphs is that they all show an object that is moving.
What is a graph?In the distance time graph, we have the distance on the vertical axis and we have the time on the horizontal axis and the shape of the plots may differ depending on the nature of the motion of the objects.
Graphs of distance vs time help us to examine motion by showing how an object has moved over time. All objects shown on a distance vs. time graph are shifting positions over time, regardless of the graph's specific shape or slope, and the graph reveals information about the direction and speed of their motion.
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Which of the following is not among the uses of dimensional analysis? (a) determination of the Numerical constant (b) to convert one system of unit to another (c) to change the units of derived quantities (d) to test the correctness of an equation
To convert one system of unit to another of derived quantities is not a use of dimensional analysis.
What is dimensional analysis?Checking for consistency in the dimensions on both sides of an equation entails looking at the dimensions of the physical quantities involved in a problem, such as length, mass, time, electric charge, and temperature.
The core tenet of dimensional analysis is that physical quantities, such as length, mass, and time, may be described in terms of their basic dimensions.
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All of the options listed are included in the uses of dimensional analysis.
What is dimensional analysis?Dimensional analysis is a powerful tool used in physics to:
check the correctness of equations derive new equationsconvert units from one system to anotherdetermine numerical constants that relate physical quantities.The dimensional analysis involves analyzing the dimensions of physical quantities and using them to establish relationships between them.
By using the principles of dimensional analysis, we can simplify complex physical problems and gain insights into the behavior of physical systems.
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Suppose 10.0 g of ice at -10.0C is placed into 300.0 g of water in a 200.0-g copper calorimeter. The final temperature of the water and copper calorimeter is 18.0C.
1) What was the initial common temperature of the water and copper? (Express your answer to three significant figures.)
The initial common temperature of the water and copper is approximately 2.68°C.
To find the hidden typical temperature of the water and copper, we need to use the norm of protection of energy, which communicates that energy can't be made or obliterated, recently moved or changed beginning with one design then onto the following.
The force lost by the ice as it breaks up is identical to the power obtained by the water and the calorimeter. We can impart this using the recipe:
Q_ice = Q_water + Q_calorimeter
where Q_ice is the force lost by the ice, Q_water is the power procured by the water, and Q_calorimeter is the force gained by the calorimeter.
We can determine the power lost by the ice using the recipe:
Q_ice = m_ice * L_f
where m_ice is the mass of the ice and L_f is the force of blend of water, which is 333 J/g.
Q_ice = (10.0 g) * (333 J/g) = 3330 J
We can sort out the force obtained by the water using the condition:
Q_water = m_water * c * (T_f - T_i)
where m_water is the mass of the water, c is the specific power breaking point of water, which is 4.184 J/g°C, T_f is the last temperature of the water and calorimeter, and T_i is the hidden ordinary temperature of the water and calorimeter.
Q_water = (300.0 g) * (4.184 J/g°C) * (18.0°C - T_i)
We can figure the force obtained by the calorimeter using the recipe:
Q_calorimeter = m_calorimeter * c_calorimeter * (T_f - T_i)
where m_calorimeter is the mass of the calorimeter, which is 200.0 g, c_calorimeter is the specific force breaking point of copper, which is 0.385 J/g°C, T_f is the last temperature of the water and calorimeter, and T_i is the hidden ordinary temperature of the water and calorimeter.
Q_calorimeter = (200.0 g) * (0.385 J/g°C) * (18.0°C - T_i)
Subbing these circumstances into the norm of conservation of energy, we get:
m_ice * L_f = m_water * c * (T_f - T_i) + m_calorimeter * c_calorimeter * (T_f - T_i)
Tending to for T_i, we get:
T_i = T_f - [(m_ice * L_f)/(m_water * c + m_calorimeter * c_calorimeter)]
T_i = 18.0°C - [(10.0 g) * (333 J/g)/(300.0 g * 4.184 J/g°C + 200.0 g * 0.385 J/g°C)]
T_i = 2.68°C
As needs be, the basic ordinary temperature of the water and copper was 2.68°C (conveyed to three immense figures).
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Before taking a personality test, Jackie sets her mind on growth. How might this affect her understanding of the test?
Choose two anSwers-
1.She will score high in the areas she chooses to.
2.She will respond based on what's best in her desired career path.
3. She will think of the results as an opportunity to find joy.
4. She will identify areas for self- development in her results.
Answer:
The two answers that are likely to be true are:
She will think of the results as an opportunity to find joy.
She will identify areas for self-development in her results.
By setting her mind on growth, Jackie is likely to approach the personality test with a positive and open mindset. This can lead to the following outcomes:
She will think of the results as an opportunity to find joy: Jackie may view the test results as a chance to discover aspects of her personality that bring her joy and satisfaction. She might focus on finding strengths and positive qualities that can contribute to her personal and professional growth.
She will identify areas for self-development in her results: Rather than viewing the test results as fixed labels or limitations, Jackie is likely to see them as valuable feedback for self-improvement. She may actively seek out areas where she can further develop her skills, knowledge, and personality traits to enhance her personal and career growth.
It's important to note that the other options listed in the question (1. She will score high in the areas she chooses to and 2. She will respond based on what's best in her desired career path) are not directly related to having a growth mindset. They suggest a more biased or strategic approach to the test, which may not align with the concept of growth and self-improvement.
What is the definition of physical activity?
A.
a movement that stimulates your respiratory system
B.
a movement that causes perspiration
C.
a movement that results in the body’s use of energy
D.
a movement that requires little effort
Answer: The answer is C
Explanation: because I got it correct
C. A movement that results in the body's use of energy.
WHO has defined physical activity as any bodily movement that requires expenditure of energy.
Physical activity includes both exercise as well as integrated activities of one's daily routine.
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Two moles of helium gas initially at 268 K
and 0.51 atm are compressed isothermally to
1.5 atm. Find the final volume of the gas. Assume
that helium behaves as an ideal gas. The
universal gas constant is 8.31451 J/K · mol.
answer in units m^3
The final volume of the gas is 1,515.24 m³.
What is the final volume of the gas?The final volume of the gas is calculated by applying ideal gas law;
PV = nRT
Where;
P is the pressureV is the volumen is the number of molesR is the universal gas constantT is the temperature.At a constant temperature, we will have the following equation;
P₁V₁ = P₂V₂
V₂ = (P₁V₁) / P₂
V₂ = (0.51 atm)(2 mol)(8.31451 J/K·mol)(268 K) / (1.5 atm)
V₂ = 1,515.24 m³
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please help PLEASE NOW
Journal prompt to be answered in 2 fully developed paragraphs
Prompt: What are some products (or programs) that you could purchase to help your performance in your current physical activity? How would the product (or program help)? Do you really think it is effective? Use specific examples from your experience.
You could purchase a fitness tracker to help your performance in your current physical activity.
Fitness tracker would help you in the area of goal setting.
Fitness trackers are effective because they have helped my friends to improve workout routine.
What are some products and programs that do help to physical activity?Wearable fitness trackers can monitor data like heart rate, number of steps taken, distance traveled, and number of calories burned.
Supplements including protein powders, creatine, and beta-alanine can enhance recovery, muscular growth, and endurance.
Working with a coach or personal trainer can help you attain your fitness objectives by offering personalized training regimens, comments on form and technique, and accountability.
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A megaphone amplifies sound by
all the above
increasing the range of frequencies that can be produced.
focusing sound energy into one specific direction.
spreading out the sound waves over a large area.
What pressure does a 500N - pound girl produce while standing on the floor if the area of the sole of one of her shoes is 60 cm²?. pleaaasee guysss help meee
The pressure exerted by the girl is approximately 833,333.33 Pa (Pascals).
Kinetic energy depends only on a system's_
Select all that apply
>
acceleration
height
mass
2
speed
volume
Answer: mass and speed
Explanation: Remember kinetic energy equals 1/2mv^2 so it is dependent on mass and velocity which is speed.