For exercise, a softball player ran around the bases 12 times in 15 minutes. At the same rate, how many times could the bases be circled in 50 minutes?

Answers

Answer 1

The bases could be circled 40 times in 50 minutes at the same rate.

To solve this problem

For this issue's solution, let's use unit rates.

In order to calculate the unit rate,

Considering that the player went 12 times around the bases in 15 minutes, the unit rate is 12/15, =  0.8 times per minute.

In a minute, the player would have circled the bases 0.8 times. By dividing the unit rate by the number of minutes, we can calculate how many times the bases could be circled in 50 minutes:

50 minutes x  0.8 times each minute = 40 times.

Therefore, the bases could be circled 40 times in 50 minutes at the same rate.

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Related Questions

Please Help Fast!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

The number of solutions that are there for the pair of equations for lines Q and S is zero solution (no solution) because the lines are parallel with no point of intersection.

What is no solution?

In Mathematics and Geometry, no solution is sometimes referred to as zero solution, and an equation is said to have no solution when the left hand side and right hand side of the equation are not the same or equal.

This ultimately implies that, a system of equations would have no solution when the line representing each of the equations are parallel lines and have the same slope i.e both sides of the equal sign are the same and the variables cancel out.

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Chase was on his school’s track team and ran the 2400m race. He has been working on his pace and can run 1600m in 5. 5 minutes. If he keeps this pace through the entire race, how long will it take him to finish the 2400m race?

A. 8. 25 minutes

B. 7. 75 minutes

C. 8. 5 minutes

D. 8. 42 minutes

Answers

If Chase can run 1600m in 5.5 minutes, then his pace is:

5.5 minutes / 1600m = 0.0034375 minutes/meter

To find out how long it will take him to run 2400m at this pace, we can multiply the pace by the distance:

0.0034375 minutes/meter * 2400m = 8.25 minutes

Therefore, the answer is A. 8.25 minutes.

Which triangle will always have the same area, no matter how it is drawn? A А a right triangle that has two 45° angles an obtuse triangle that has two 30° angles © a right triangle that has two 5-inch-long sides an obtuse triangle that has two 5-inch-long sides​

Answers

The triangle that will always have the same area, no matter how it is drawn, is a right triangle that has two 45° angles. The correct answer is option A

This is because any right triangle with two 45° angles is a special type of triangle called an isosceles right triangle. In an isosceles right triangle, the two legs are congruent, which means they have the same length. Therefore, no matter how the triangle is drawn, its area will always be the same.

To see why this is true, let's use the formula for the area of a right triangle:

Area = (base x height) / 2

In an isosceles right triangle, the base and height are congruent, so we can write:

Area = (leg x leg) / 2

Simplifying this expression, we get:

Area = (leg^2) / 2

Since the legs of an isosceles right triangle are congruent, we can substitute leg for both legs in the formula:

Area = (leg^2) / 2 = (leg x leg) / 2

No matter how the triangle is drawn, the legs will have the same length, so the area of the triangle will always be the same.

Therefore, the correct answer is option A, a right triangle that has two 45° angles.

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Omar Cuts A Piece of wrapping paper with the shape and dimensions as shown.Find The Area Of The Wrapping Paper.Round Your Answer To The Nearest Tenth Of Needed

Answers

Answer:

72.5 square inches

Step-by-step explanation:

See attachment.

The areas of the 2 shapes are in blue, but when added together:

60+12.5=72.5

Hope this helps!

1. p(x)= f(x)+g(x)
Write the equation of p(x)

Answers

Answer:p(x)=3x+5

Step-by-step explanation:

f(x)=2x+3

g(x)=x+2

p(x)=(2x+2)+(x+2)= 3x+5

 

Answer:

p(x)=ax + b

Step-by-step explanation:

Analyzing Solution Sets to Linear Equations with the Variable on Both Sides

2x + 5 = 3 + 2(x + 1)

Answers

Answer: it will need to be rewritten so that the variable is only on one side of the equation

Step-by-step explanation:f the equation contains fractions, you may elect to multiply both sides of the equation by the least common denominator

You start by distributing from the 2 into the parentheses for x which will become 2x and 2. Next you may start canceling out. get either 2x and cancel it out with the other you should at this point then have X+5=3+1 combine like terms.

Patty and Carol leave their homes in different cities and drive toward each other on the same highway.


• They start driving at the same time.


• The distance between the cities where they live is 300 miles.


• Patty drives an average of 70 miles per hour.
. Carol drives an average of 50 miles per hour.


Enter an equation that can be used to find the number of hours, t, it takes until Patty and Carol are at the same


location.

Answers

The equation to find the number of hours, t, until Patty and Carol are at the same location is: 70t + 50t = 300.


1. Patty and Carol start driving at the same time, towards each other on the same highway.
2. The distance between their cities is 300 miles.
3. Patty drives at an average speed of 70 mph, so in t hours she covers 70t miles.
4. Carol drives at an average speed of 50 mph, so in t hours she covers 50t miles.
5. As they drive towards each other, the sum of the distances they cover should equal the total distance between their cities.
6. Therefore, combining the distances covered by Patty and Carol, we get: 70t (Patty's distance) + 50t (Carol's distance) = 300 (total distance).

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A ball of radius 11 has a round hole of radius 4 drilled through its center.
Find the volume of the resulting solid.

Answers

The volume of the resulting solid is estimated 4,128.38 cubic units.

How do we calculate?

The volume of the ball isgitten as:

V_ball = (4/3)πr^3

r is the radius of the ball. In this scenario

r = 11, so:

V_ball = (4/3)π(11)^3

V_ball = (4/3)π(1331)

V_ball = 4,396.46 cubic units

The volume of the hole is gotten as :

V_hole = (4/3)πr^3

r is the radius of the hole.

In thisscenario, r = 4, so:

V_hole = (4/3)π(4)^3

V_hole = (4/3)π(64)

V_hole = 268.08 cubic units

In conclusion, the volume of the resulting solid is:

V_resulting_solid = V_ball - V_hole

V_resulting_solid = 4,396.46 - 268.08

V_resulting_solid = 4,128.38 cubic units

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Choose the correct answer.
Find the quadratic equation given the points (6,0), (-1,0), and (7,4).

h(x) = 1/2(x + 1)(x − 6)
h(x) = 2(x+6)(x − 1)
h(x) = 2(x + 1)(x - 6)
h(x):1/2(x+6) (x - 1)

Answers

The quadratic equation given the points (6,0), (-1,0), and (7,4).

The correct answer is h(x) = 1/2(x + 1)(x - 6).

To find the quadratic equation given the points (6,0), (-1,0), and (7,4), we can use the general form of a quadratic equation, which is [tex]h(x) = ax^2 + bx + c.[/tex]

First, let's substitute the coordinates of the given points into the equation to create a system of equations:

For the point (6,0):

[tex]0 = a(6)^2 + b(6) + c ---- (1)[/tex]

For the point (-1,0):

[tex]0 = a(-1)^2 + b(-1) + c ---- (2)[/tex]

For the point (7,4):

[tex]4 = a(7)^2 + b(7) + c ---- (3)[/tex]

We now have a system of three equations with three unknowns (a, b, c). We can solve this system to find the values of a, b, and c.

Solving the system of equations (1), (2), and (3), we find:

a = 1/2

b = -3/2

c = 0

Thus, the quadratic equation that satisfies the given points is:

h(x) = 1/2(x + 1)(x - 6).

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A.
kyle swam 4 laps in the pool on monday. he swam
6 times as many laps on tuesday. choose true or false
for each statement.
a. the expression 6 x 4 represents the number of
x
laps kyle swam on tuesday.
b. the words 6 times as many as 4 represents the
number of laps kyle swam on tuesday.
c. the number of laps kyle swam on tuesday can be
found by solving the equation ? = 6 x 4.
d. kyle swam 10 laps on tuesday.

Answers

A. Kyle swam 4 laps in the pool on Monday. He swam 6 times as many laps on Tuesday.

a. The expression 6 x 4 represents the number of laps Kyle swam on Tuesday.


b. The words "6 times as many as 4" represent the number of laps Kyle swam on Tuesday.

c. The number of laps Kyle swam on Tuesday can be found by solving the equation x = 6 x 4.

d. Kyle swam 10 laps on Tuesday.


a) True. Since Kyle swam 6 times as many laps on Tuesday as he did on Monday (4 laps), you would multiply 6 by 4 to find the number of laps he swam on Tuesday.

b) True. This phrase means that Kyle swam 6 times the number of laps he swam on Monday (4 laps), which gives you the number of laps he swam on Tuesday.

c) True. This equation represents the total number of laps Kyle swam on Tuesday. By solving the equation, you can determine that Kyle swam 24 laps on Tuesday.

d) False. Based on the information given and the calculations made, Kyle actually swam 24 laps on Tuesday, not 10.

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Box and whisker plots

Answers

Answer: Box and whisker plots are plots on number lines with a box and two lines off the edges, called whiskers. The box has a line at the upper quartile(1), one at the lower quartile(2), and one in the center of the box at the median(3). The two lines go to the ends of the data, one at the minimum(4) and one at the maximum(5).

  4     2     3       1             5

   |-----[___|____]-----------|

₀__₁__₂__₃__₄__₅__₆__₇__₈

I hope this helps.

Which number sequence follows the rule subtract 15 starting from 105? 15, 30, 45, 60, 75 15, 10, 25, 20, 35 105, 100, 95, 90, 85 105, 90, 75, 60, 45

Answers

The number sequence that follows the rule of subtracting 15 starting from 105 is 105, 90, 75, 60, 45.

To obtain this sequence, we start with 105 and subtract 15 from it to get 90. Then we subtract 15 from 90 to get 75, and so on until we reach 45. Each term in the sequence is obtained by subtracting 15 from the previous term.

It is important to note that this is an arithmetic sequence with a common difference of -15. The formula for finding the nth term of an arithmetic sequence is: an = a1 + (n-1)d, where an is the nth term, a1 is the first term, and d is the common difference. Using this formula, we can find any term in the sequence by plugging in the appropriate values.

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The height of three basketball players is 210 cm, 220 cm and 191 cm.
What is their average height?

Answers

Answer:

Average height = 207 cm

Step-by-step explanation:

It's given that, The height of three basketball players is 210 cm, 220 cm and 191 cm.

h₁ = 210 cm

h₂ = 220 cm

h₃ = 191 cm

Total number of observations = 3.

Average = Sum of all observations/Total number of observations.

Average = h₁ + h₂ + h₃/3

Average = 210 +220 + 191 /3

Average = 430 + 191/3

Average = 621/3

Average = 207

Therefore, The required average height is 207 cm.

consider h(x)= 11x² - 6x calculate H (x) Fx 6.Xr1 유 11 6 3 (22.-6) 3 6 In(3) 11 A) 2 +1 (221 - 6)31 B) - (11r? - br)3*** In(3) 2 (3***") - 6 In(3) (221 - 63#* - (1142 – 63)3 (3***")" 2 +1 4 (221 - 63 - (1122 – 6x)3 In(3) i 1 D)

Answers

The answer is B) - (11x² - 6x)ln(3) + 2ln(3) - 6ln(x) + C, where C is the constant of integration.

To solve this problem, we are given a function h(x) and asked to find its antiderivative or indefinite integral, which is denoted by H(x) and is defined as the function whose derivative is h(x). We are also given a specific value of H(x) at x = 6 and asked to use it to find the constant of integration, denoted by C.

The given function is h(x) = 22x - 3x² - 6/x, and we want to find H(x), which is the antiderivative of h(x). Using the power rule of integration, we can integrate each term of h(x) separately:

∫ (22x - 3x² - 6/x) dx = ∫ 22x dx - ∫ 3x² dx - ∫ 6/x dx= 11x² - x³ - 6ln|x| + C

where C is the constant of integration. Note that we need to include an absolute value sign around x in the natural logarithm term because the function is not defined for x = 0.

Next, we are given that H(6) = 31, which means that when x = 6, the value of H(x) is 31. Substituting x = 6 and H(x) = 31 into the above equation, we get:

31 = 11(6)² - (6)³ - 6ln|6| + C

Simplifying, we get:

31 = 132 - 216 - 6ln(6) + CC = 221/3 - 6ln(6)

Therefore, the antiderivative of h(x) is:

H(x) = 11x² - x³ - 6ln|x| + 221/3 - 6ln(6)

We can simplify the expression by using the identity ln|a/b| = ln|a| - ln|b|:

H(x) = 11x² - x³ - 6ln(3) - 6ln(x) + 2ln(3) + C

where C is the constant of integration. Thus, the final answer is:

B) - (11x² - 6x)ln(3) + 2ln(3) - 6ln(x) + C, where C is the constant of integration.

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Find (A) f'(x). (B) the partition numbers for f', and (C) the critical numbers of f. f(x) = x³ - 75x - 2 (A) f'(x)= (B) Find the partition numbers for f' Select the correct choice below and, if necessary, fill in the answer box to complete your choice A. The partition number(s) is/are x = (Use a comma to separate answers as needed) B. There are no partition numbers (C) Find the critical numbers for f. Select the correct choice below and, if necessary, fill in the answer box to complete your choice A. The critical number(s) is/are x = (Use a comma to separate answers as needed) B. There are no critical numbers

Answers

The critical numbers of f are x = -5 and x = 5.

(A) To find the derivative f'(x), we differentiate f(x) = x³ - 75x - 2 with respect to x:
f'(x) = 3x² - 75

(B) There are no partition numbers for f' as partition numbers are related to integer partitions, which are not applicable in this context.

(C) To find the critical numbers of f, we set f'(x) equal to 0 and solve for x:
3x² - 75 = 0
x² = 25
x = ±5

So the critical numbers of f are x = -5 and x = 5.

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As as you approach zero from the left on a number line the integers ____ , but the absolute values of those integers ___?

Answers

As you approach zero from the left on a number line, the integers become increasingly negative, but the absolute values of those integers remain positive.

A number line is a visual representation of numbers placed in order on a straight line. It is a graphical tool used to represent the real numbers, starting from negative infinity on the left side and extending to positive infinity on the right side. The number line is divided into equal intervals, and each point on the line corresponds to a specific value or number. The distance between any two points on the number line represents the numerical difference between the corresponding numbers. The number line is a fundamental tool in mathematics for understanding the order and magnitude of numbers, as well as for performing operations such as addition, subtraction, and comparison.

As you approach zero from the left on a number line, the integers become increasingly negative, but the absolute values of those integers remain positive.

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You roll a 6-sided die two times.
What is the probability of rolling a number greater than 1 and then rolling a number less than
3?

Answers

Answer:

Step-by-step explanation:

The possible outcomes of rolling a fair six-sided die are the numbers 1, 2, 3, 4, 5, and 6, each of which has an equal probability of $\frac{1}{6}$ of appearing.

The probability of rolling a number greater than 1 is $\frac{5}{6}$, since there are five out of six possible outcomes that satisfy this condition (namely, 2, 3, 4, 5, and 6).

The probability of rolling a number less than 3 is $\frac{2}{6}=\frac{1}{3}$, since there are two out of six possible outcomes that satisfy this condition (namely, 1 and 2).

To find the probability of both events happening (rolling a number greater than 1 and then rolling a number less than 3), we can multiply their respective probabilities:

$\frac{5}{6}\cdot\frac{1}{3}=\frac{5}{18}$

Therefore, the probability of rolling a number greater than 1 and then rolling a number less than 3 is $\boxed{\frac{5}{18}}$.

6. A football player throws a football. The function h given by h(t) = 6 + 75+ - 161
describes the football's height in feet † seconds after it is thrown.

A. The football is thrown from ground level.
B. The football is thrown from 6 feet off the ground.
C. In the function, - 167? represents the effect of gravity.
D. The outputs of h decrease then increase in value.
E. The function h has 2 zeros that make sense in this situation.
F. The vertex of the graph of h gives the maximum height of the foot

Answers

The correct options are:

The football is thrown from 6 feet off the ground. In the function, - 167? represents the effect of gravity.The vertex of the graph of h gives the maximum height of the foot

The description of the football's height

Option B:  The football is thrown from 6 feet off the ground.

when t = 0

h(t) = 6 * 75 * 0 + 16 * 0

= 6 feet

Option C : - 16t² represents the effect of gravity

we have

[tex]h = ut - \frac{1}{2}gt^2[/tex]

[tex]\frac{1}{2}gt^2=-16t^2[/tex]

F. The vertex of the graph of h gives the maximum height of the foot

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Find a quadratic function that models the


number of cases of flu each year, where y is years since 2012. What is the coefficient of x? Round your answer to the nearest hundredth

Answers

Using regression analysis, we get the following quadratic function:

y = 557[tex]x^{2}[/tex] + 1,690x + 60,000

How to explain the function

We can use the data given and fit a quadratic equation in the form of y = a[tex]x^{2}[/tex] + bx + c, where y represents the number of flu cases and x is the number of years since 2012.

x (years since 2012) y (number of flu cases)

0 60,000

1 62,000

2 63,000

3 64,000

4 65,000

5 66,000

6 67,000

7 68,000

8 69,000

9 70,000

10 71,000

11 72,000

12 73,000

13 74,000

14 75,000

15 76,000

Next, we can use this table to find the coefficients a, b, and c that give us the best-fit quadratic function.

Using a regression analysis, we get the following quadratic function:

y = 557[tex]x^{2}[/tex] + 1,690x + 60,000

Here, the coefficient of x is 1,690, which represents the linear term in the quadratic equation. It tells us how much the number of flu cases changes with each year since 2012, assuming a quadratic relationship.

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Year Number of Flu Cases

2000 20,000

2001 22,000

2002 25,000

2003 28,000

2004 32,000

2005 35,000

2006 38,000

2007 42,000

2008 45,000

2009 50,000

2010 55,000

2011 58,000

2012 60,000

2013 62,000

2014 63,000

2015 64,000

Find a quadratic function that models the number of cases of flu each year, where y is years since 2012. What is the coefficient of x?

6.) Marissa's class is having a Read-a-Thon. The 34 students in her class have read a total of 817 books. On average, how many books has each student read? (5th grade answer)​

Answers

Answer:

24 with a remainder of 1 (or Q.24 R.1)

Explanation:
divide the amount of books by the amount of students.

Apply the Distributive Property to the right side.
12
enter your response herex

enter your response here ​(Type integers or​ fractions.)

Answers

The rewritten expression of 12 using the distributive property is 3(2 + 2)

Rewriting the equation using the distributive property.

From the question, we have the following parameters that can be used in our computation:

12 distributive property

This means that

12

Express as 6 + 6

So, we have

12 = 6 + 6

Factor out 3 from the equation

So, we have

12 = 3(2 + 2)

The above equation has been rewritten using the distributive property.

Hence, the rewritten expression using the distributive property is 3(2 + 2)

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2. Mandy is walking in the woods. She completes 70% of her walk in 3 hours. She continues walking at that same rate. How much time, in hours, will Mandy's entire walk take?
A 3 4\5
B. 5
C. 6
D. 6 1\2​

Answers

Answer:

If Mandy completed 70% of her walk in 3 hours, then we can find her walking rate as follows:

Let's assume that the entire walk takes t hours. Then, 70% of the walk would take 0.7t hours. We know that Mandy completes 70% of her walk in 3 hours, so we can set up the following equation:

0.7t = 3

Solving for t, we get:

t = 3 ÷ 0.7 ≈ 4.29

So, the entire walk will take approximately 4.29 hours. Since Mandy has already walked for 3 hours, the remaining time she needs to complete her walk is:

4.29 - 3 = 1.29 hours

Therefore, the answer is closest to option A, 3 4/5 hours.

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A baker has a small and large bag of sugar for making cakes. The large bag contains 30 cups of sugar and is 2. 5 times larger than the small bag. The small bag contains enough sugar to make 9 cakes and has 0. 75 cups of sugar remaining.



how many cakes can be made with a large bag of sugar?

Answers

After solving the word problem, the large bag contains enough sugar to make 40 cakes

Since the large bag is 2.5 times larger than the small bag, and the small bag contains enough sugar to make 9 cakes, the large bag contains enough sugar to make:

2.5 * 9 = 22.5 cakes

However, since there are only 30 cups of sugar in the large bag, and we don't know how much sugar is needed to make a single cake, we cannot determine the exact number of cakes that can be made with a large bag of sugar.

As for the small bag, if it had enough sugar to make 9 cakes and there are 0.75 cups of sugar remaining, then each cake requires:

(sugar in bag - remaining sugar) / number of cakes

= (9 - 0.75) / 9

= 0.75 cups of sugar

Therefore, the large bag contains enough sugar to make:

30 cups / 0.75 cups per cake

= 40 cakes

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Your local dry cleaners is running a special. The dry cleaner is offering a 13% discount for any drop off that is over $40. Also, they are running a neighborhood special of an additional 5% off. Given this information, determine the decay factor corresponding to each percent decrease. A. 34. 8; 33. 06 c. 0. 87; 0. 95 b. 0. 384; 0. 3306 d. 87; 95

Answers

The decay factor corresponding to each percent decrease is 0.87. The correct option is c. The customer would save a total of $17.35, or 17.35% off the original price.

To determine the decay factor corresponding to each percent decrease, we need to use the formula:

decay factor = (100% - percent decrease)/100%

For the first discount of 13%, the decay factor would be:

decay factor = (100% - 13%)/100% = 0.87

For the additional neighborhood discount of 5%, the decay factor would be:

decay factor = (100% - 5%)/100% = 0.95

So the correct answer is option C, with a decay factor of 0.87 for the 13% discount and 0.95 for the neighborhood discount.

These decay factors represent how much of the original price is left after the discount has been applied. For example, if the original price was $100, after the 13% discount, the price would be:

price after first discount = $100 x 0.87 = $87

Then, after the additional 5% discount, the final price would be:

final price = $87 x 0.95 = $82.65

So the customer would save a total of $17.35, or 17.35% off the original price.

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The profit from selling tickets to a musical can be modeled by the function P(x) = -100x2 + 2,400x - 8,000, where x is the price per ticket, in dollars. What ticket price will maximize the profit?

Answers

The profit is maximized at $16,400 when the ticket price is $12.

To find the ticket price that maximizes the profit, we used the fact that the maximum or minimum value of a quadratic function occurs at its vertex. For a quadratic function in the form of P(x) = ax^2 + bx + c, the x-coordinate of the vertex can be found using the formula x = -b / 2a.

In this case, we were given the function [tex]P(x) = -100x^2 + 2400x - 8000,[/tex]where x represents the price per ticket. The coefficient of [tex]x^2[/tex] is negative, which tells us that the graph of this function is a downward-facing parabola. The vertex of this parabola represents the maximum value of the function.

Using the formula x = -b / 2a, we found the x-coordinate of the vertex to be x = -2400 / 2(-100) = 12. This means that a ticket price of $12 will maximize the profit.

To verify that this is indeed the maximum profit, we substituted x = 12 into the profit function P(x):

[tex]P(12) = -100(12)^2 + 2400(12) - 8000 = 16,400[/tex]

We can see that the profit is maximized at $16,400 when the ticket price is $12.

In summary, to find the ticket price that maximizes the profit, we used the formula x = -b / 2a to find the x-coordinate of the vertex of the quadratic function representing the profit from selling tickets to a musical. The maximum profit occurs at the ticket price that corresponds to the x-coordinate of the vertex.

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7) Roy buys pizza for his friends. A whole pizza costs P 190. 00 and P 40. 00 for every
additional topping. If he spent P 1070 for pizza with 3 sets of additional toppings, how
many whole pizzas did he buy?
8) There are 4 large gifts. Inside each large gift are 2 medium-sized gifts and inside each
medium-sized gift are 3 small gifts. How many gifts are there altogether?
9) Mang Cardo has cows and chickens in his farm. If he counted 13 heads and 36 feet,
how many cows and chickens does he have?
10) Alexander travelled at 6:00 a. M. And started driving at an average speed of 70 km per
hour. After two hours of driving, he stopped for 30 minutes for a rest. He continued
driving and reach his hometown at 9:30 a. M. How far did he travel?​

Answers

7) Roy buys 5 whole pizzas.

8) There are 36 gifts altogether.

9) There is 5 cows and 8 chickens.

10) He travel 210 km.

We have the four parts of question:

Now, We have the information:

7) A whole pizza costs P 190.00 and P 40. 00 for every additional topping.

If he spent P 1070 for pizza with 3 sets of additional toppings.

So, The formation of equation is:

=> (1070 - 3 × 40) ÷ 190

=> 5

8) Total gifts are : 4

and Inside each large gift are 2 medium-sized gifts and inside each

medium-sized gift are 3 small gifts.

So, the formation of equation;

=> 4 × 2 = 8

=> 8 × 3 = 24

The total is:

8 + 24 + 4 = 36

9) There are 13 heads and 36 feet .

We know:

Cows have (C) 4 legs

Chickens have (c)  2 legs

So, The equation will be:

C + c=13   ....eq.(1)

Multiply by 4, we get:

4C+2c=36

Then,

4C+4c=52

4C+2c=36

--------------- (-)

2c=16

c = 8 chickens

We put the value of c in eq.(1), we get  

C=13 - 8

C = 5 cows

Hence, There is 5 cows and 8 chickens.

10) Alexander travelled at 6:00 a.m.

and, average speed is 70 km per hour.

So, He travelled 140 km in 2 hours.

After two hours of driving, he stopped for 30 minutes for a rest.

He continued driving and reach his hometown at 9:30 a.m.

So, therefore he continues driving at 8:30

then he arrived at his destination at 9:30

So after his break for driving he travels 1 more hour

So in total he travelled 3 hours to arrive at his destination

3 × 70 = 210.

Learn more about Equation at:

https://brainly.com/question/29657988

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What’s the answer I need help pls?

Answers

Answer:

A, C, F

Step-by-Step:

The amplitude is whatever the coefficient is behind the trig function

Please help. The problem is found in the photo below, just please help.

Answers

Answer:

-4 = 5

0 = -1

2 = -4

4 = -7

(-4, 5)

(0, -1)

(2, -4)

(4, -7)

Step-by-step explanation:

First, let's identify what each term represents.

y-intercept: -1

slope: 3/2

Then, fill out the table.

x = -4

-1 - (3/2 · -4)

-1 - (-12/2)

-1 - (-6)

-1 + 6

y = 5

x = 0

-1 - (3/2 · 0)

-1 - 0

y = -1

x = 2

-1 - (3/2 · 2)

-1 - (6/2)

-1 - (3)

y = -4

x = 4

-1 - (3/2 · 4)

-1 - (12/2)

-1 - (6)

y = -7

Then, plot the points in the function on the graph.

(-4, 5)

(0, -1)

(2, -4)

(4, -7)

Consider the graph of function g
y4
If f(x)=x², which equation represents function g?
OA. g(z) f(27)
OB. g (2) f(42)
M
2
O C. g(z) = 2 f(z)
(2)
D. 9(2) -

Answers

Answer:

D

Step-by-step explanation:

5. A 40-kg ornamental star is suspended by two chains fastened to
horizontal beams at different heights with angles as shown.
Determine the tension in each chain.


The diagram is shown below; I also know we have to split up the triangles to make two right angle triangles but I’m not sure where to go from there

Answers

Answer:We can start by resolving the forces acting on the ornamental star in the vertical direction and in the horizontal direction. Since the star is stationary, these forces must balance each other out.

Let's call the tension in the higher chain T1 and the tension in the lower chain T2. We can use trigonometry to find the vertical and horizontal components of each tension force.

For T1:

The vertical component is T1cos(40°) and the horizontal component is T1sin(40°).

For T2:

The vertical component is T2cos(30°) and the horizontal component is T2sin(30°).

Now, resolving the forces in the vertical direction, we have:

T1cos(40°) + T2cos(30°) - mg = 0

where m is the mass of the star and g is the acceleration due to gravity.

Substituting the values:

T1cos(40°) + T2cos(30°) - (40 kg)(9.81 m/s^2) = 0

T1cos(40°) + T2cos(30°) = 392.4 N

Next, resolving the forces in the horizontal direction, we have:

T1sin(40°) = T2sin(30°)

Now we have two equations with two unknowns:

T1cos(40°) + T2cos(30°) = 392.4 N

T1sin(40°) = T2sin(30°)

Solving these equations simultaneously, we get:

T1 = 266.4 N

T2 = 205.1 N

Therefore, the tension in the higher chain (T1) is 266.4 N and the tension in the lower chain (T2) is 205.1 N.

Step-by-step explanation:

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