The probability that it was an HH coin is [tex]\frac{1}{50}[/tex]
Conditional Probability P(B/A) is defined as probability of occurrence of B given that A has already occurred .
Baye's Theorem describes the probability of an event based on conditions that might be related to event .
P(A/B)={P(B/A)*P(A)}/P(B)
Total number of coins =100
Total number of HH coins = 1
P(HH) =Probability of getting HH=1/100
P(H/HH)=Probability of H knowing that HH has already occurred=1
Next to find Probability Of H
We need to find two thing
(i) Probability H appears and is a fair coin= [tex]\frac{1}{2} *\frac{98}{100} =\frac{98}{200}[/tex]
(ii)Probability H appears and is a HH coin = [tex]\frac{1}{100}[/tex]
P(H)= (i)+(ii) =100/200=1/2
BY Baye's Theorem
P(HH|H)={P(H|HH)∗P(HH)}/P(H)
[tex]=\frac{1*\frac{1}{100} }{\frac{100}{200} }[/tex]
[tex]=\frac{2}{100}[/tex]
[tex]=\frac{1}{50}[/tex]
Therefore , The probability that it was an HH coin is [tex]\frac{1}{50}[/tex]
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help please
just tell the answer get it right for brainliest!
Answer:
pretty sure its 2.9
Step-by-step explanation:
Answer:2.92 or just 3
Step-by-step explanation:
btw read your lesson and pay attentiom
If 4 is subtracted from the numerator of a fraction, its value becomes 1/3. If 5 is added to the denominator of the original fraction its value becomes 1/2. What is the original fraction.
Answer:
79
Step-by-step explanation:
Let the numerator of the original fraction be 'x' and the denominator be 'y'. So, the original fraction becomes xy
According to the question,
Condition I,
If 4 is subtracted from the numerator of a fraction, its value becomes 1/3.
or,x−4y=13
or,3(x−4)=y
or,y=3x−12
Condition II,
If 5 is added to the denominator of the original fraction, the value becomes 1/2.
or,xy+5=12
or,2x=y+5
Put value of y from equation (i) in equation (ii), we get,
or,2x=(3x−12)+5
or,2x=3x−12+5
or,3x−2x−7=0
∴x=7
Put value of x in equation (i), we get,
or,y=3×7−12
or,y=21−12
∴y=9
So, (x,y) = (7,9)
Therefore, the required original fraction is 79.
how many quarts of pure antifreeze must be added to 3 quarts of a 40% antifreeze solution to obtain a 60% antifreeze solution?
1.5 quarts of pure antifreeze must be added to 3 quarts of a 40% antifreeze solution to obtain a 60% antifreeze solution
Given;
Percentage of 3 quarts of antifreeze solution = 40%
We have to find,
Quarts to obtain the antifreeze solution of 60%
Now,
The 3 quarts of 40% antifreeze solution contains 0.4 x 3 = 1.2 quarts of pure antifreeze solute
Let,
x is the number of quarts of pure antifreeze needed to make a 60% solution
The equation to solve becomes, where x is the amount of pure antifreeze to be added is
(1.2 + x )/(3 + x) =0.6
(1.2 + x ) = 0.6 * (3 + x)
(1.2 + x ) = 1.8 + 0.6x
x-0.6x = 1.8 - 1.2
0.4x = 0.6
x = 1.5
Therefore,
1.5 quarts of pure antifreeze to the current solution to make a 60% solution
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a password system uses four digits from 0 to 9. how many different four-digit passwords with no digit repeated are possible?
Total 5040 passwords can be generated when no digits are repeated
• Permutation in mathematics is an arrangement of objects in an definite order. The elements or sets or things are arranged in sequential order or linear order.
• Permutation is classified into four types :
1) where repetition is not allowed
2) where repetition is allowed
3) objects that are non distinct
4) circular permutation
• The formula for calculating permutation is n!/(n-r)!
As we are given that the password uses four digits from 0-9 and repetition is not allowed.
So, n = 10 and r = 4
Using the formula for permutation we get
= 10! / (10-4)!
= 10!/6!
= 10 * 9 * 8 * 7 * 6! / 6!
= 10 * 9 * 8 * 7
= 5040
Therefore, 5040 four digit passwords are possible when no digit is repeated.
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Question 2 (1 point)
Given the following points, are lines CD and EF parallel, perpendicular, or neithe
A(1,2) B(3,4) C(5,2) D(8,3) E(3,8) F(-6,5)
a
b
C
parallel
perpendicular
neither?
Given lines CD and EF are parallel. Therefore answer is (a)
How to find slope of two lines and check whether they are parallel or perpendicular
Given are two points P (x₁, y₁) and Q ( x₂, y₂)
Then slope of the line PQ is given by (y₂-y₁)/(x₂-x₁)
If two lines have slopes m₁ and m₂ respectively
Then the lines are parallel when their slopes are equal i.e. m₁=m₂
and the lines are perpendicular when m₁*m₂= -1
Given C(5,2), D(8,3),E(3,8) F(-6,5)
Then,
Slope of CD = (3-2)/(8-5)= 1/3
Slope of EF = (5-8) / (-6-3) = 1/3
Slope of CD=Slope of EF
Therefore CD and EF are parallel
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please solve u r the best thx
Answer:13
Step-by-step explanation:
Answer:
There are no values of f to make this equation true.
Hope this helps.
Step-by-step explanation:
In the second part of the equation, 6( 1/16f - 3 ), 6 * 1/16f is 3/8f. If both sides subtract a 3/8f and both sides add 18, you get 18.5 = 0 meaning there are no values of f to make this equation true.
What does pin stand for? a. principal investment number b. permission initiating number c. percent increase number d. personal identification number please select the best answer from the choices provided a b c d
Answer:
The answer is D.
Step-by-step explanation:
Answer:
in this case the answer is D
Step-by-step explanation:
your welcome
What is the length of the shorter leg?
____________________________
What is the length of the longer leg?
____________________________
The shorter leg of the right triangle measures 3 units, while the larger lag measures 11 units.
How to get the length of the legs of the triangle?Here we know that we have a right triangle, and we know that:The hypotenuse measures √130 units.
The perimeter measures 14 + √130 units.
If we define:
x = shorter leg.
y = larger leg.
Then, using the Pythagorean theorem, we can write:x^2 + y^2 = √130^2 = 130
And for the perimeter equation we know that:
perimeter = x + y + √130 = 14 + √130
We can simplify this equation to:x + y = 14Then we have the system of equations:
x^2 + y^2 = 130
x + y = 14
Isolating one variable in the second equation we get.
x = 14 - y
Replacing that in the other equation we get:
(14 - y)^2 + y^2 = 130
Now we can solve this for y.
196 - 28y + y^2 + y^2 = 130
2y^2 - 28y + 196 - 130 = 0
2y^2 - 28y + 66 = 0
y^2 - 14y + 33 = 0
Using Bhaskara's formula we can get:
y = (14 ± √( 14^2 - 4*1*33))/2*1y = (14 ± 8)/2
Now, remember that y is the larger leg of the triangle, then:y = (14 + 8)/2 = 11For the value of x we use:
x = 14 - y = 14 - 11 = 3x = 3the shorter leg of the right triangle measures 3 units, while the larger lag measures 11 units.
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What is the value of the expression below when w=7?
w² +3w - 10
Answer:
The value of the expression is 60.
Ashley is constructing CD such that CD intersects AB at C and is the segment bisector of AB. Select the relationship that must be true.
A) Point C is equidistant from A and B.
B) Point D is equidistant from A and B.
C) Point A is equidistant from C and D.
D) Point B is equidistant from C and D
Answer:
Step-by-step explanation:
a,d
Answer:ad
Step-by-step explanation:
ad
Given , find the average rate of change of f(x)=[tex]f(x)=\frac{1}{x+5}[/tex] on the interval
[1,1+h]. Your answer will be an expression involving h.
Pls halp
The average rate of change of function f(x)= [tex]\frac{1}{x+5}[/tex] on the interval [1,1+h] is [tex]-\frac{1}{36+6h}[/tex]
Given,
The function = [tex]\frac{1}{x+5}[/tex]
We know the average rate of change of the function is [tex]\frac{f(b)-f(a)}{b-a}[/tex]
Where a and b are the intervals
a= 1
b=1+h
f(a) =f(1)= [tex]\frac{1}{1+5}[/tex]
=[tex]\frac{1}{6}[/tex]
f(b)= f(1+h)
=[tex]\frac{1}{1+h+5}[/tex]
=[tex]\frac{1}{6+h}[/tex]
f(b)-f(a)= [tex]\frac{1}{6+h}-\frac{1}{6}[/tex]
[tex]=\frac{6-(6+h)}{6(6+h)} \\=\frac{6-6-h}{36+6h}\\ =-\frac{h}{36+6h}[/tex]
Then,
[tex]\frac{f(b)-f(a)}{b-a} =\frac{-\frac{h}{36+6h} }{1+h-1}[/tex]
[tex]=\frac{-\frac{h}{36+6h} }{h} \\=-\frac{1}{36+6h}[/tex]
Hence, the average rate of change of function f(x)= [tex]\frac{1}{x+5}[/tex] on the interval [1,1+h] is [tex]-\frac{1}{36+6h}[/tex]
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Please help and answer the parts A and B
A> The equation for the line is y = -0.1x + 2600
B> The value of the car is $16,500
From the table, we know that for every 6000 miles added there is a decrease in the value by $600.
A> So it is the function of one order
y = kx + b
25500 = 5000k + b
24800 = 12000k + b
After equating it we get
b = 26000 and k = -0.1
Now put the value of b and k in the equation, and we get
y = -0.1x + 26000
Therefore the equation is y = -0.1 + 26000
B> When we put the value of x = 95000, we get
y = -0.1 × 95000 + 26000
= 16500
Therefore the cost of the car is $16,500
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HELP...........................! !
Answer:
[tex] \sf \large( \frac{2}{5} ) {}^{14} [/tex]
Step-by-step explanation:
=((2/5)^4(2/5)^3)^2
=((2/5^4+3))^2
=((2/5^7))^2)
=(2/5)^14
I dont understand this i pick the right ones but it say im wrong can someone correct me??
Answer:
The two in the middle?
Last saturday 16 people worked the at the theater. four people worked the morning shift and 12 worked the evening shift. they earned a total of $1,080.00. what did they earn each?
Earning of each = $33.75
Let's take the earnings of each person to be x.
Total person working at the theater = 16 + 4 + 12
= 32
Now the total earnings of the people = 32x
Which is given = $1080
So we get an equation
32x = 1080
x = $33.75
Hence we get the earnings of each person = $33.75
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Simplify fully
4x^+ 4x/-2x^-2
Answer: -12x
Step-by-step explanation: 4x +4 −2 −2x
Calculate x to the power of 1 and get x.
4x+4×( −2 −2x )
Calculate 2 to the power of −2 and get 41.
4x+4×( − 41x)
Divide x by − 41
by multiplying x by the reciprocal of − 41 .
4x+4×( −1x×4)
Anything divided by -1 gives its opposite.
4x+4(−x×4)
Multiply 4 and −1 to get −4.
4x−4x×4
Multiply −4 and 4 to get −16.
4x−16x
Combine 4x and −16x to get −12x.
−12x
a measurement that can be repeated is said to be and one that is close to the accepted or actual value is
A measurement that can be repeated is said to be precise and one that is close to the accepted or actual value is approximate.
Given that,
The incomplete statement is given we have to complete the statement.
All over the world, most things are in use as of common quantity, so people all over the world agree that they have to follow a common system of measurement and that the common system of measurement is called standard measurement.
Here,
A measurement that can be repeated is said to be precise values
A measurement that is close to the accepted or actual value is approximate.
Thus, the required words are precise and approximate.
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PLSSS HELP ANSWER, THE QUESTION IS IN THE SCREENSHOT
Let f(x) be the integrand.
[tex]f(-2)=-8 \\ \\ f(0)=0 \\ \\ f(2)=8 \\ \\ f(4)=64 \\ \\ \implies \int^{4}_{-2} x^3 \text{ dx}=\approx \frac{1}{2}(2)[-8+64+2(0+8)] \\ \\ =\boxed{72}[/tex]
Un granjero coloco una cerca al rededor de su parcela. La parcela mide 10 m de cada lado ya que es un cuadrado. Si puso los postes cada 3/4 de metro ¿cuantos postres coloco?
Greetings from Brasil...
The total length will be: 10+10+10+10 = 40
and
(3/4)m = 0.75m
Then, Rule of 3:
QTD m
1 ------ 3/4
X ------ 40
X = 53.333
Soon 53 posts will be needed
can someone help me really quick
Shawn earn 11 per hour.
Hannah travel 25 miles in one gallon of gas.
What is graph?A graph can be defined as a pictorial representation or a diagram that represents data or values in an organized manner.
given:
According to the graph the y- axis shows the earnings.
So, we have the coordinates are
(1, 11), (2, 22) and (3, 33)
So, Shawn earn = 22 - 11 / 2 -1 = 11 per hour.
Now, in second case
The coordinates are
(3, 75), (5, 125), (6, 150), (10, 250)
So, m= (125 - 75) / (5-3)
m= 50/2
m=25
So, Hannah travel 25 miles in one gallon of gas.
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I cant find my answer please help!
Answer:
Domain: 1 ≤ x ≤ 6
Range 10 ≤ M(x) ≤ 60
Step-by-step explanation:
M(x) = 10x where x represents the number of tickets bought
Assume nobody goes with Victoria. In that case she will go alone, only 1 ticket is bought and total cost = $10
Maximum 5 friends means total of 6 tickets purchased so total cost is $60
Domain refers to the possible input values ie possible x values. Here the domain is 1 ≤ x ≤ 6 also written as [1, 6]
The range is the total possible set of output values. Here output of the function is cost and cost ranges between 10 and 60 inclusive
So Range = 10 ≤ M(x) ≤60 also written as [10, 60]
two accountants, lee and johnson, went to a business meeting together. lee drove to the meeting and johnson drove back from the meeting. if lee and johnson each drove 140 kilometers, what was the average speed, in kilometers per hour, at which lee drove? 1) the average speed at which johnson drove was 70 kilometers per hour 2) lee drove for exactly 2 hours
The average speed of Lee is 70 km/hr.
To clear up this trouble we want to understand the concept of average speed.
average speed is given while we divide the overall distance blanketed with the aid of the total time taken.
right here, it's miles given that Lee and Johnson each drove a hundred and forty Km. additionally, it's miles given that lee drove for two hours.
So, average speed of Lee = [tex]\frac{140}{2}[/tex]
= 70 km/hr
Here, the average speed at which Lee drove the car and went to business meeting is 70 km/hr.
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The longest side of a triangle is a cm.
The second side is bcm shorter than the first side.
The third side is half as long as the second side.
Write an expression, in its simplest form, for the perimeter of
the triangle
Answer:
P = 2.5a - 1.5bStep-by-step explanation:
The sides of the triangle are:
a cm,a - b cm,(a - b)/2 cm.Its perimeter is the sum of the three sides:
P = a + a - b + (a - b)/2 = 2a - b + 0.5a - 0.5b = 2.5a - 1.5bcan someone please anwser (5z+y)/7 (the number values of z and y are in the picture)
Answer:
2
Step-by-step explanation:
First substitute the values of z and y in the expression.
Use PEDMAS. We have to multiply 5 and 3, which gives 15. Subtract 1 from 15 and then divide the result by 7.
[tex]\sf \dfrac{5z + y}{7}= \dfrac{5*3 + (-1)}{7}\\\\[/tex]
[tex]\sf = \dfrac{15 - 1}{7}\\\\ = \dfrac{14}{7}\\\\= 2[/tex]
You place the following shapes in a bag 5 circles 3 triangles 7 squares and 5 rectangles if you reach in the bag what is the probability you will grab a shape
Answer:
theres a 25% you will grab an apple (work shape is suppose to be circle)
Step-by-step explanation:
Hope this helps
Joel, Ben, and Luke are each wearing a hat with a number on it. Each person adds the two numbers on the other two hats, giving totals of 11, 17, and 22. What is the largest number on a hat?
Solving a system of equations, we conclude that the largest number on a hat is 14.
What is the largest number on a hat?
We have 3 hats, each one with a number that we will define as:
x, y, and z.
We know that by adding pairs of these numbers we get 11, 17 and 22, then we can write a system of equations:
x + y = 11
x + z = 17
y + z = 22
Clearly z is the largest number, so we want to find z.
First, we can isolate x on the first equation so we get:
x = 11 - y
Replacing that in the second equation giveS:
x + z = 17
(11 - y) + z = 17
Now our system is:
y + z = 22
(11 - y) + z = 17
Isolating y in the first one we get:
y = 22 - z
Now we can replace that in the other equation:
(11 - (22 - z)) + z = 17
Now we can solve this for z.
11 - 22 + z + z = 17
-11 + 2z = 17
2z = 17 + 11 = 28
z = 28/2 = 14
z = 14
We conclude that the largest number on a hat is 14.
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Altogether, tom and sarah have 32 baseball cards. if sarah has three times as many baseball cards as tom, how many does each of them have
tom has 8 cards and sarah has 24 cards .
Explain how many cards sarah and tom has?tom and sarah total baseball cards =32
sarah has three times as many baseball cards as tom
The 2 equations are
1. sarah + tom = 32
2. sarah = [tex]3 \times tom[/tex]
substitute equation 2 in 1.
[tex]3\times tom +tom= 32[/tex]
4 tom = 32
tom = 32/4
tom = 8 cards
sarah = [tex]3\times tom[/tex]
= [tex]3\times 8[/tex]
sarah = 24 cards
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HELP ME PLEASE I need this rn!!!!! SOMEONE ANYONE PLEASEEEEE
question 4
Jeremy is 80 ft from a wall. Each time he moves toward the wall he reduces his distance from the wall by half. Which graph best models the situation?
the four photos are to this question
question 5
Which expressions describe the end behavior of the graph?
the 5 photo is to this one
Select EACH correct answer.
Using a geometric sequence, we have that:
Graph 1 models the situation.
The end behavior of the graph is given as follows:
As x decreases, y approaches the line y = 2.
What is a geometric sequence?A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q, hence the second term is the first multiplied by q, the third is the second multiplied by q, and so on.
For item 4, we have that:
The first term is of 80.The common ratio is of 0.5.Hence when x = 2, y = 40, when x = 3, y = 20, and so on.This means that the first graph is correct.
What is the end behavior of a function?The end behavior of a function is given by the limits of the function when x goes to infinity.
Hence, from the final graph, we have that:
As x decreases, y approaches the line y = 2. (lim x -> negative infinity = -2).As x increases, y decreases without bound. (lim x -> infinity = - infinity, not an option but just to explain).More can be learned about geometric sequences at https://brainly.com/question/24643676
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find the slope of the line that goes through the points (4,-6) and (3,7)
Answer:
m=-13
Step-by-step explanation:
the formula for getting the slope is[tex] = \frac{y 2- y1}{x2 - x1} \\ = \frac{7 - ( - 6)}{3 - 4} \\ = \frac{7 + 6}{ - 1} \\ = \frac{13}{ - 1} \\ = - 13[/tex]Hope this helpsthe perimeters of two squares are in the ratio 2 : 7. What is the ratio of the area of the smaller square to the area of the larger square
The ratio of the area of the smaller square to the area of the larger square = 4 : 49
Finding the area of a square from the perimeterLet the perimeter of the small square be [tex]P_1[/tex]
Lethe the perimeter of the large square be [tex]P_2[/tex]
Perimeter of a square = 4 Length
[tex]P_1=4L_1\\\\P_2=4L_2[/tex]
The ratio of the perimeters = 2:7
[tex]\frac{4L_1}{4L_2} =\frac{2}{7} \\\\\frac{L_1}{L_2} =\frac{2}{7}[/tex]
The area of a square = L^2
[tex](\frac{L_1}{L_2} )^2=(\frac{2}{7} )^2\\\\\frac{L_{1} ^{2} }{L_{2} ^{2}} =\frac{2^2}{7^2} \\\\\frac{L_{1} ^{2} }{L_{2} ^{2}} =\frac{4}{49}[/tex]
Therefore, the ratio of the area of the smaller square to the area of the larger square = 4 : 49
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