Find the volume of the solid.
3 cm
2 cm
6 cm
4 cm
4 cm
2 cm
7 cm

Answers

Answer 1

Answer:

8064cm.

Step-by-step explanation:

When trying to find volume,All you have to do is multiply all the numbers.

Answer 2

Answer:

3 x 2=6 x 6 = 36 x 4 = 144 x 4 = 576 x 2 = 1152 x 7 = 8064

Step-by-step explanation:


Related Questions

Which pairs of polygons are similar?

Select each correct answer.

Answers

Answer:

Two polygons are similar if their corresponding angles are congruent and the corresponding sides have a constant ratio (in other words, if they are proportional). Typically, problems with similar polygons ask for missing sides.

Step-by-step explanation:

this is the correct answer

A culture started with 5000 becteria. after 2 hours it grew to 6500 becteria. Predict how many bacteria will be present after 18 hours. Round your answer to the nearest whole number. p=ae^kt

Answers

Answer:

About 53022 bacteria present.

Step-by-step explanation:

We can use the continuous growth formula:

[tex]\displaystyle P = A e^{kt}[/tex]

Where k is some constant.

With an initial population of 5000, it grew to 6500 after two hours.

In other words, P = 6500 when A = 5000 and t = 2:

[tex]\displaystyle (6500) = (5000)e^{k(2)}[/tex]

Solve for k:

[tex]\displaystyle \begin{aligned} 6500 & = 5000e^{2k} \\ \\ e^{2k} & = \frac{6500}{5000} = \frac{13}{10} \\ \\ \ln\left(e^{2k}\right) & = \ln\left(\frac{13}{10}\right) \\ \\ 2k & = \ln\frac{13}{10} \\ \\ k & = \frac{1}{2}\ln\frac{13}{10}\end{aligned}[/tex]

Therefore, our equation is:

[tex]\displaystyle P = \bigg{5000e}^{\dfrac{1}{2}\ln\dfrac{13}{10}t[/tex]

After 18 hours, t = 18. Hence:

[tex]\displaystyle \begin{aligned} P(18) & = \bigg{5000e}^{\dfrac{1}{2}\ln\dfrac{13}{10}(18)} \\ \\ & \approx 53022\end{aligned}[/tex]

Therefore, after 18 hours, there will be about 53022 bacteria present.

A model satellite has a scale of 1 cm : 3 m. If the real satellite is 18 m wide, then how wide is the model satellite?

A. 54 cm
B. 1 cm
C. 6 cm
D. 15 cm

Answers

C

1cm : 3cm
= 1 x 6 cm : 3 x 6 m
= 6cm : 18m

Pls Help Me
Pls show your work pls and thank you

Answers

Answer:

DWest I think

Step-by-step explanation:

Someone else asked this and this is what they think and it seems right

Find the area of this trapezoid. Be sure to include the correct unit in your answer.

Answers

Answer:  [tex]92 \text{ yd}^2[/tex]

=======================================================

Work Shown:

[tex]A = \frac{h(b_1+b_2)}{2}\\\\A = \frac{8(19+4)}{2}\\\\A = \frac{8(23)}{2}\\\\A = \frac{184}{2}\\\\A = 92\\\\[/tex]

The [tex]b_1[/tex] and [tex]b_2[/tex] are the parallel bases, while h is the height perpendicular to each base.

The units are in square yards, abbreviated as [tex]\text{yd}^2[/tex]

Think of a 1 yard by 1 yard square that has an area of [tex](1 \text{ yd})*(1 \text{ yd}) = (1)^2(\text{yd})^2 = 1 \text{ yd}^2[/tex]

The side of 9 yards is never used and put in there as a distraction.

four dice are thrown simultaneously. what will be the probability that all of them have the same face ?​

Answers

Answer:

1/216

Step-by-step explanation:

A dice (assuming it is from 1-6) has 6 faces. There are 4 dices.

equation will be

6*6*6=answer

Multiply 6 three times by itself because there are 4 dices. That is because One die would be 1

Two would be 1/6

Three would be 1/36

And four would be the ...

Asnwer=216

The following data shows the low temperature in Vancouver, in degrees Celsius, for two weeks in January one year.

8.40, 8.35, 8.50, 8.40, 8.90, 8.20, 8.50, 8.30, 8.50, 8.50, 8.75, 8.30, 8.10, 8.55

Which box plot best represents this data?

Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.1 and maximum value is 8.9 and the interquartile ranges approximately between 8.3 and 8.5 and the median falls approximately between 8.4 and 8.5.
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.1 and maximum value is 8.7 and interquartile ranges approximately between 8.3 and 8.6 and median falls approximately between 8.4 and 8.5.
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.2 and maximum value is 8.9 and interquartile ranges approximately between 8.3 and 8.6 and median is approximately at 8.5.
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.1 and maximum value is 8.9 and interquartile ranges approximately between 8.3 and 8.5.

Answers

To create the dot plot you will list the data in order and use the given numbers to create the box plot.

8.10, 8.20, 8.30, 8.32, 8.34, 8.50, 8.50, 8.50, 8.55, 8.60, 8.60, 8.65, 8.65, 8.90

Lower extreme: 8.10

Upper extreme: 8.90

Median: 8.50

1st/lower quartile: 8.32

3rd/upper quartile: 8.60

Please see the attached picture for the boxplot.

Two point particles are attached to each other via a light in-extensible string that passes over a ring hanging from the ceiling via a chain. Find an expres- sion for the tension in the string and the chain.​

Answers

a. The expression for the tension in the string is T = mg

b. The expression for the tension in the chain is T = 2mg

To solve the problem, we need to know what tension is.

What is tension?

This is the opposing force in a stretched material.

a. Tension in the string

The expression for the tension in the string is T = mg

Since the string supports the weight of the object, the tension in the string equals the weight of the particle.

Let

T = tension in sring and W = weight of particle = mg where m = mass of particle and g = acceleration due to gravity

So, T = W

T = mg

So, the expression for the tension in the string is T = mg

b. Tension in chain

The expression for the tension in the chain is T = 2mg

Since the chain supports both strings, the tension in the chain equals the tension in both strings.

Let

T' = tension in chain and T = tension in each string

So, T' = T + T

T' = 2T

T' = 2W

T' = 2mg

So, the expression for the tension in the chain is T = 2mg

Learn more about tension here:

https://brainly.com/question/24994188


Which of the following functions is graphed below?

Answers

Answer:

b

Step-by-step explanation:

Find all zeros of ƒ(x) = 2x^4 – 72x^2. Then determine the multiplicity at each zero. State whether the graph will touch or cross the x-axis at the zero.

Answers

Answer: See below

Step-by-step explanation:

To find the factor,

f(x) = 0

[tex]\begin{aligned}&2 x^{4}-72 x^{2}=0 \\&2 x^{2}\left(x^{2}-36\right)=0 \\&x^{2}\left(x^{2}-36\right)=0 \\&x \times x \times(x-6) \times(x+6)=0 \\&\mathrm{x}=0,0,6,-6\end{aligned}[/tex]

So,

x = 0 multiplicity 2

x = -6 multiplicity 1

x = 6 multiplicity 1

For an even multiplicty, the graph touches the x-axis, and for an odd multiplicty, the graph crosses the x-axis

Therefore,

x = 0 multiplicty 2, Touch

x = -6 multiplicty 1, Cross

x = 6 multiplicty 1, Cross

shannon purchased a quilt at the farmers market. the area of the quilt 9 1/3 meters. the width is 2 4/5. what is the length of the rug in meters​

Answers

length = 3 1/3 m

hope it helps...!!!

Sue has $500 in an account for 9 years at a compound rate of 7.5%. How much does she have?

Answers

Answer:

she has about $3750 in her acount.

Step-by-step explanation:

hope this helps you!

Find the area of the sector.



a. 11.16 in²

b. 44.66 in²

c. 50.24 in²

d. 2.8 in²

Answers

Hi!

Circle Area Formula

[tex]A=\pi r^2[/tex]

We will start by solving for the area of the entire figure.

Plugin the values into the circle area formula. We will use 3.14 for pi:

[tex]A=3.14(4)^2[/tex]

Simplify:

[tex]A=50.24[/tex]

Now, this is the area of the entire circle, but we only want that certain shaded region.

We know that a circle has a total of 360 degrees, and the shaded sector is simply 80 degrees.

We can divide to see how much of the circle is shaded:

80 / 360 = 0.22...

Now, we can take this number and multiply it by 50.24 (our answer from above) to get the area of the shaded sector:

0.22 * 50.24 = 11.16

Therefore, your answer is A.

For a similar problem, see:

https://brainly.com/question/11952845

What are the missing numbers in this series: 10,16,21,26,31,

Answers

Answer:

38

Step-by-step explanation:

16 - 10 = 6

21 - 16 = 5

26 - 21 = 4

31 - 26 = 5

31 + 6 = 38

The next missing number is 38.

From there, continue the pattern.

Solve the equation 25z2 + 140 = −29 by using square roots.
A. z = ±13/5
B. z = ±29/5
C. no real solutions
D. z = ±7/5

Answers

Answer:

Option C, no real solutions

Step-by-step explanation:

Step 1:  Subtract 140 from both sides

[tex]25z^2 + 140 = -29[/tex]

[tex]25z^2 + 140 -140 = -29 -140[/tex]

[tex]25z^2 = -169[/tex]

Step 2:  Divide both sides by 25

[tex]\frac{25z^2}{25} = \frac{-169}{25}[/tex]

[tex]z^2 = -6.76[/tex]

Step 3:  Square root both sides

[tex]\sqrt{z^2} = \sqrt{-6.76}[/tex]

Since we are trying to square root a negative it would cause imaginary solutions so in conclusion we have no real solutions.

Answer:  Option C, no real solutions

MY SISTER NEEDS HELP IN MATH...

Answers

Answer:

[tex]b. \: 16[/tex]

Step-by-step explanation:

Divide the numbers ⬇

16 ÷ 4 = 4

[tex](4 + 2) \times 2 + 4[/tex]

Add the numbers ⬇

4+2=6

[tex]6 \times 2 + 4[/tex]

Multiply the numbers ⬇

6 x 2 = 12

[tex]12 + 4[/tex]

Add the numbers ⬇

[tex]12 + 4 = 16[/tex]

OPTION B IS RIGHT :)

hope this helps!! Mark me brainliest please!

Answer: B. 16

Step-by-step explanation:

Hope this helps!

Evaluate 5(a•4)+ b, 1 when a=-andb=12. 3 O A) 14 3 OB) 17 2 O C) 18 3 OD) 27


HELP ASAP ​

Answers

Evaluate 5(a•4)+ b, when a = 1/3 and b=12

The Answer is

C. 18 2/3

hope it's help hshshs

given function g, which is defined by g(x)=x^3-x, what is the value of g(3)

Answers

Answer:

g(3) = 24

Step-by-step explanation:

The question is essentially asking you, "With an input of 3, what is the output of the function?" To find g(3), plug "3" into the "x" variable. Then, simplify as much as you can.

g(x) = x³ - x

g(3) = (3)³ - (3)

g(3) = 27 - 3

g(3) = 24

Does anyone know how to get free answers? I ran out, I have a lot of points I just need more free answers again

Answers

Answer: I believe that by helping or answering others you can get get questions, but I do know there is a limited amount of questions being able to ask before paying monthly. Hope this helps

Answer:

What you have to do is answer peoples question to gain more

Step-by-step explanation:

Martin orders a pasta dish that is priced at $11.99. He also orders a drink. The total cost for the pasta and drink is $14.48. Which of the following equations can be used to find the cost of the drink?

Answers

Answer:

14.48=11.99+y

or

y=14.48-11.98

Step-by-step explanation:

it should be one of these (the variable might be different)

y is the price of the drink

The half-life of Radium-226 is 1590 years. If a sample contains 400 mg, how many mg will remain after 1000
years?

Answers

Answer:

258.65 mg will be remain after 1000 years

Step-by-step explanation:

This problem can be solved several ways, I prefer the natural log approach for reasons I won’t go into here:

Activity final = Activity initial e^-kt, where

k = the decay constant, = ln2/half life = 0.693/1590, = 0.000436/year

t = the decay time, in the same time base as k

The problem can be worked in units of activity, mass, or number of atoms.

400 x e^-0.000436 x 1000 = 400 x e^-.436 = 258.65 mg

you can check this by estimating. There is about 2/3 of a half life, so there should be more than 200 mg, which would be the value at one half life.

what’s the answer to this

Answers

Let’s first do process of elimination, obviously the numbers are growing, so we can rid of A and C. Linear growth grows by the same number every day, but this graph doesn’t represent that, so your ANSWER IS D!! Hope this helps

Baker, Inc. uses the sum-of-the-years’-digits method to depreciate a $79,600.00 piece of equipment that has an estimated life of 20 years. The salvage value is $4,000.00. The book value at the end of year 2 is

Answers

The book value at the end of year 2 of the equipment depreciated using the sum-of-the-years’-digits method is $65,560.

What is the book value at the end of  year 2?

Depreciation is a method used to expense the cost of an asset. Book value is the cost of the asset less the accumulated depreciation.

Sum-of-the-year digits = (remaining useful life / sum of the years ) x  (Cost of asset - Salvage value)

Depreciation expense in year 1:

Sum of the years = 1 +2 +3 +4 + 5 + 6 + 7 + 8 + 9 + 10+ 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 210

Undepreciated life of the asset = 20

(20 / 210) x ($79,600 - 4,000) = 7200

Depreciation expense in year 2:

19 / 210 x ($79,600 - 4,000) = 6840

Book value = 79600 - 7200 - 6840 = $65,560

To learn more about depreciation, please check: https://brainly.com/question/25552427

1
Select the correct answer.
To solve this system of equations using substitution, what could be substituted in place of y in the first equation
4x=5-2y
y-2x=7
ОА.
7 - 2x
ОВ.
41
5
OC.
5 - 41
2
OD.
2x + 7
Reset
Next

Answers

The expression y = 7 + 2x can be substituted into the first equation to find the variable "x"

System of equation

System of equation are made of two or more equations with unknowns

Given the system of equation

4x=5-2y

y-2x=7

From equation 2:

y = 7 + 2x

The expression y = 7 + 2x can be substituted into the first equation to find the variable "x"

Learn more on system of equation here: https://brainly.com/question/14323743

#SPJ1

Magda and Nicholas each purchase almonds and cashews for their trail mix recipes as shown.


Almonds
(pounds)
Cashews
(pounds)
Total Cost
(dollars)
Magda 6 1 $73.60
Nicholas 4 3 $78.00

Click on each blank to enter the cost per pound of almonds and cashews.

Answers

Answer:

almonds: $10.20

cashews: $12.40

Step-by-step explanation:

Complete the equation of the line through (-10,-7)(-5,−9)

Answers

Slope
-9+7 -2
—— = ——
-5+10 5

Equation of a line
y+7=-2/5(x+10)
y+7=-2/5x-4
y=-2/5x-11

step by step subtraction Mayan: 208 - 75

Answers

Answer:

133

Step-by-step explanation:

Find the following in radians. You
should be able to do this without a
calculator.
cos-1 0
=
TT
?

Answers

By using the definition of the inverse cosine function, we will see that:

[tex]cos^{-1}(0) = pi/2[/tex]

How to complete the expression?

We have the expression:

[tex]cos^{-1}(0) = \frac{pi}{?}[/tex]

Remember that if:

[tex]cos(x) = y\\\\cos^{-1}(y) = x[/tex]

Then, in what do we need to evaluate the cosine function to get an output equal to zero?

[tex]cos( pi/2) = 0[/tex]

Then:

[tex]cos^{-1}(0) = pi/2[/tex]

Then we can replace the question sign with a 2.

If you want to learn more about the cosine function, you can read:

https://brainly.com/question/8120556

What are the vertex, focus, and directrix of the parabola whose equation is y-5= 1/12 (x-3)^2

Answers

Answer:

Vertex: (3,5)

Focus: (3,8)

Directrix: y = 2

Step-by-step explanation:

Get y by itself by adding 5 over to the other side. The equation is now y = 1/12(x-3)^2 + 5.

The value inside of the parentheses is -3. Since it's within the parentheses, switch the signs for the x value of the vertex. The "+ 5" represents the y value. Therefore the vertex is (3,5).

The value "a" on the parabola is 1/12. To find the distance from the vertex to the focus/directrix, use the equation a = 1/4p. 1/12 = 1/4p. p = 3. This parabola opens up, so "p" must be added onto the y value of the vertex for the focus. The focus is therefore (3,8).

For the directrix, subtract "p" from the y value of the vertex. The directrix is a horizontal line at y = 2.

What is the length of the diameter of a circle with a radius that is 13 centimeters? cm

Answers

Answer:

13 this is the ansewer to this

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