Find the slope of the line passing through the points (-5, 3) and (7,9).

Answer:

It's the last one. We know it's to the right because the -8 is in the exponent and also, it's -8 not +8.

Answer:

Step-by-step explanation:

Given,

AD = 38

EB = 7x - 4

FC = 6x - 6

Now, we have to find the value of X

[tex]eb \: = \frac{1}{2} (ad \: + fc \: )[/tex] ( Mid segment Theorem )

Plug the values

[tex]7x - 4 = \frac{1}{2} (38 + 6x - 6)[/tex]

Calculate the difference

[tex]7x - 4 = \frac{1}{2} (32 + 6x)[/tex]

Remove the parentheses

[tex]7x - 4 = \frac{32}{2} + \frac{6x}{2} [/tex]

[tex]7x - 4 = 16 + 3x[/tex]

Move variable to L.H.S and change its sign

Similarly, Move constant to R.H.S and change its sign

[tex]7x - 3x = 16 + 4[/tex]

Collect like terms

[tex]4x = 16 + 4[/tex]

Calculate the sum

[tex]4x = 20[/tex]

Divide both sides of the equation by 4

[tex] \frac{4x}{4} = \frac{20}{4} [/tex]

Calculate

[tex]x = 5[/tex]

The value of X is 5

Now, let's find the value of EB

EB = 7x - 4

Plug the value of X

[tex] = 7 \times 5 - 4[/tex]

Calculate the product

[tex] = 35 - 4[/tex]

Calculate the difference

[tex] = 31[/tex]

The value of EB is 31

Hope this helps..

Best regards!!

Work Shown:

[tex]\sin^2 \theta + \cos^2 \theta = 1\\\\\left(\frac{3}{10}\right)^2 + \cos^2 \theta = 1\\\\\frac{9}{100} + \cos^2 \theta = 1\\\\\cos^2 \theta = 1 - \frac{9}{100}\\\\\cos^2 \theta = \frac{100}{100}-\frac{9}{100}\\\\\cos^2 \theta = \frac{91}{100}\\\\\cos \theta = \sqrt{\frac{91}{100}} \ \text{ cosine positive in Q1}\\\\\cos \theta = \frac{\sqrt{91}}{\sqrt{100}}\\\\\cos \theta = \frac{\sqrt{91}}{10}\\\\[/tex]

Answer:

√91/10

Step-by-step explanation:

sin 0.3 is equal to 18(approximate value)

cos18°=0.951

which is √91/10

Answer:

Original price is $1610

Step-by-step explanation:

2737=1.7*Original price

divide each side by 1.7

Original price=1610

Hope this helps!

Answer:

$432

Step-by-step explanation:

60*6=360

They paid $360 for the first 6 months.

20%*60=.2*60

0.2*60=12

12*6=72

They paid $72 for the last 6 months.

360+72=432

They paid $432

$648 is the total amount the customer will pay for the 1-year plan

percentage, a relative value indicating hundredth parts of any quantity.

Given that a customer enrolled in a 1-year product purchase plan that costs $60 per month.

After 6 months, the customer received a monthly discount of 20%.

We need to find the total amount the customer will pay for the 1-year plan.

Product Plan = $60 per month

Money he pay for 1 month = $ 60

Money He pay for first 6 month = 6 × 60 = $ 360

after 6 month he receives 20% discount monthly,

So, Now he pay for 1 month = 60 - 20% × 60

=60-20/100×60

=60-12=48

Money he pay for last 6 month = 6 × 48 = 288

Total Money he  pay in a year = 360 + 288 = $ 648

Hence, $648 is the total amount the customer will pay for the 1-year plan

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Answer:

Step-by-step explanation:

[tex] \sqrt{ {x}^{2} - 3x - 6} = x - 1[/tex]

Squaring on both sides:

[tex] {x}^{2} - 3x - 6 = {(x - 1)}^{2} [/tex]

Use the formula:[tex] {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} [/tex]

[tex] {x}^{2} - 3x - 6 = {x}^{2} - 2x + 1[/tex]

Combine like terms.

[tex] {x}^{2} - {x}^{2} - 3x + 2x = 1 + 6[/tex]

[tex] - 3x + 2x = 7[/tex]

Calculate

[tex] - x = 7[/tex]

[tex]x = - 7[/tex]

Hope this helps...

Good luck on your assignment..

Answer:

-7

Step-by-step explanation:

Khan academy

Answer:

x=8

Step-by-step explanation:

[tex]\sqrt{x+8}-\sqrt{x-4}=2\\\sqrt{x+8}=2+\sqrt{x-4}\\\left(\sqrt{x+8}\right)^2=\left(2+\sqrt{x-4}\right)^2\\x+8=x+4\sqrt{x-4}\\8=4\sqrt{x-4}\\8^2=\left(4\sqrt{x-4}\right)^2\\64=16x-64\\x=8[/tex]

Answer:

my best answer for this is B. False.

I calculated as fast as i can.

6 1/10

Step-by-step explanation:

4 + 1/2+1+3/5

5+1+1/10=6 1/10

Answer:

  19.9 days

Step-by-step explanation:

The amount remaining after d days is ...

  a = (1/2)^(d/7)

We want to find d when a = 0.14

  log(a) = (d/7)log(1/2)

  d = 7·log(0.14)/log(1/2) ≈ 19.855 ≈ 19.9

The farmers need to wait about 19.9 days for it to be safe.

Answer:

Step-by-step explanation:

[tex] \mathrm{Given}[/tex],

[tex] \mathrm{Discount\% = 20\%}[/tex]

[tex] \mathrm{Marked \: price = 1250}[/tex]

[tex] \mathrm{Now \: let's \: find \: the \: discount \: amount}[/tex]

[tex] \mathrm{discount \: amount = dis\% \: of \: MP}[/tex]

[tex] \mathrm { = 20\% \: of \: 1250}[/tex]

[tex] \mathrm{ = 250}[/tex]

[tex] \mathrm{let's \: find \: the \: selling \: price}[/tex]

[tex] \mathrm{ = MP \: - \: discount \: amount}[/tex]

[tex] \mathrm{ = 1250 - 250}[/tex]

= $ [tex] \mathrm{1000}[/tex]

[tex] \mathrm{lets \: find \: the \: Vat \: amount}[/tex]

[tex] \mathrm{vat \: amount = vat\% \: of \: sp}[/tex]

[tex] \mathrm{ = 12.5\% \: of \: 1000}[/tex]

= $ [tex] \mathrm{ 125}[/tex]

[tex] \mathrm{Now \: finally \: let's \: find \: the \: selling \: price \: with \: vat}[/tex]

[tex] \mathrm{selling \: price \: + \: vat \: amount}[/tex]

[tex] \mathrm{ = 1000 + 125}[/tex]

= $ [tex] \mathrm{1125}[/tex]

Therefore, The final sale of the necklace is $ 1125

Hope I helped

Best regards!

Answer:

variable A and Variable B are more negatively related than variable C and variable D.

Step-by-step explanation:

Variables A and B have a covariance = 45

Variables C and D have a covariance = 627

Comparing the relationship between variable A AND B with the relationship between variable C and D

variable A and Variable B are more negatively related than variable C and variable D. this is because the covariance between variable A and Variable B are less positive

Answer:

The sampling is dependent because an individual selected for one sample does dictate about which individual to be selected in the second sample.

The variable is qualitative because it classifies the individual.

Step-by-step explanation:

The sample is dependent as the second individual selected in the sample is dependent on the first individual selection. The sample selection is not random and is dictated. The variables selected are qualitative in nature because they identify the quality of response variable which is non numerical in nature.

Answer:

Option B

an increasing exponential graph

Answer:

7 children

Step-by-step explanation:

Answer:

7 children is the correct answer

and you follow me if you can't I will unfollow you

Answer:

29.4≤μ≤32.6

Step-by-step explanation:

The datas given from the questions are as shown:

Number of people n = 24

Mean xbar= $31

Standard deviation σ = $6

Confidence Interval formula is expressed as:

CI = xbar ± Z(σ/√n)

Z value for 80% confidence interval is 1.282

Substituting the values into the Confidence Interval formula will give;

CI = 31 ± 1.282{6/√24}

CI = 31 ± 1.282(1.225)

CI = 31 ± 1.57045

CI = 31+1.57045 and 31-1.57045

CI = (29.42955, 32.57045)

CI = (29.4, 32.6) to 1dp

The confidence interval will be within the range 29.4≤μ≤32.6

Answer:

17 lanterns.

Step-by-step explanation:

There are 13 campers with one lantern each, so that will be 13 * 1 = 13 lanterns.

The company supplies 4 extra lanterns for the whole group.

So, they will bring 13 + 4 = 17 lanterns.

Hope this helps!

Answer:

2.25

Step-by-step explanation:

The computation of the number c that satisfied is shown below:

Given that

[tex]f(x) = \sqrt{x}[/tex]

Interval = (0,9)

According to the Rolle's mean value theorem,

If f(x) is continuous in {a,b) and it is distinct also

And, f(a) ≠ f(b) so its existance should be at least one value

i.e

[tex]f^i(c) = \frac{f(b) - f(a)}{b -a }[/tex]

After this,

[tex]f(x) = \sqrt{x} \\\\ f^i(x) = \frac{1}{2}x ^{\frac{1}{2} - 1} \\\\ = \frac{1}{2}x ^{\frac{-1}{2}[/tex]

[tex]f^i(x) = \frac{1}{{2}\sqrt{x} } = f^i(c) = \frac{1}{{2}\sqrt{c} } \\\\\a = 0, f (a) = f(o) = \sqrt{0} = 0 \\\\\ b = 9 , f (b) = f(a) = \sqrt{9} = 3\\[/tex]

After this,

Put the values of a and b to the above equation

[tex]f^i(c) = \frac{f(b) - f(a)}{b - a} \\\\ \frac{1}{{2}\sqrt{c} } = \frac{3 -0}{9-0} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{3}{9} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{1}{3} \\\\ \sqrt[2]{c} = 3\\\\\sqrt{c} = \frac{3}{2} \\\\ c = \frac{9}{4}[/tex]

= 2.25

Answer:

y= -2x +1

Step-by-step explanation:

slope- intercept form:

y= mx +c, where m us the gradient and c is the y-intercept.

Let's find the value of m first using the gradient formula.

Gradient= [tex] \frac{y1 - y2}{x1 - x2} [/tex]

[tex]m = \frac{ - 3 - 3}{2 - ( - 1)} \\ m = \frac{ - 6}{2 + 1} \\ m = \frac{ - 6}{3} \\ m = - 2[/tex]

y= -2x +c

To find the value of c, substitute a pair of coordinates.

When x= -1, y=3,

3= -2(-1) +c

3= 2 +c

c= 3 -2

c= 1

Thus the equation of the line is y= -2x +1.

Answer:  C

Step-by-step explanation:

h · k(x) = 2(3x - 5)(-2x + 1)

           = (6x - 10)(-2x + 1)

           = -12x² + 6x + 20x - 10

           = -12x² + 26x - 10

Answer:

C

Step-by-step explanation:

h(x) × k(x)

= 2(3x - 5)(- 2x + 1) ← expand factors using FOIL

= 2(- 6x² + 3x + 10x - 5)

= 2(- 6x² + 13x - 5) ← distribute parenthesis by 2

= - 12x² + 26x - 10 → C

Answer:

[tex] x^3 - 6x + 2 [/tex]

Step-by-step explanation:

The given polynomials can be added together by adding like terms together as shown below:

=> Add together, the coefficient of all terms that have the power of 3.

[tex] (2x^3) + (x^3) + (-3x^3) [/tex]

[tex] 2x^3 + x^3 - 3x^3 [/tex]

[tex] 3x^3 - 3x^3 [/tex]

[tex] x^3 [/tex]

=> [tex] (-4x^2) + (6x^2) + (2x^2) [/tex]

[tex] -4x^2 + 8x^2 [/tex]

[tex] 4x^2 [/tex]

=> [tex] (6x) + (-8x) + (-4x) [/tex]

[tex] 6x - 8x - 4x [/tex]

[tex] -6x [/tex]

=> [tex] (-3) + (12) +(-7) [/tex]

[tex] -3 + 12 - 7 [/tex]

[tex] 2 [/tex]

The answer = [tex] x^3 - 6x + 2 [/tex]

Answer:

4x^2-6x+2

Step-by-step explanation:

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

   C

b

    C

c

    C

d  

     A

Step-by-step explanation:

From the question we are told that

    The population mean is  [tex]\mu = 0.5 \ in[/tex]

Generally the Null hypothesis is  [tex]H_o : \mu = 0. 5 \ in[/tex]

                The Alternative hypothesis is  [tex]H_a : \mu \ne 0.5 \ in[/tex]

Considering the parameter given for part a  

       The sample size is  n =  15  

        The  test statistics is  t =  1.66

        The level of significance [tex]\alpha = 0.05[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 15- 1[/tex]

           [tex]df = 14[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = 2.145[/tex]

We are making use of this  [tex]t_{\frac{\alpha }{2} }[/tex] because it is a one-tail test

Looking at the value of  t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that  [tex]t < t_{\frac{\alpha }{2} }[/tex] so the null hypothesis would not be rejected

Considering the parameter given for part b  

       The sample size is  n =  15  

        The  test statistics is  t =  -1.66

        The level of significance [tex]\alpha = 0.05[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 15- 1[/tex]

           [tex]df = 14[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = -2.145[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha}{2} ,df }[/tex] the we see that t does not lie in the area covered by  [tex]t_{\frac{\alpha}{2} , df }[/tex] (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part  c

       The sample size is  n =  26  

        The  test statistics is  t =  -2.55

        The level of significance [tex]\alpha = 0.01[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 26- 1[/tex]

           [tex]df = 25[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = 2.787[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that t does not lie in the area covered by  [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part  d

       The sample size is  n =  26  

        The  test statistics is  t =  -3.95

        The level of significance [tex]\alpha = 0.01[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 26- 1[/tex]

           [tex]df = 25[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = -2.787[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha}{2} }[/tex] the we see that  t  lies in the area covered by  [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we  reject the null hypothesis

Answer:

A. The median represents the center.

Step-by-step explanation:

In statistics and probability theory, the median value is the middle value or center value in a group of data values or numbers. To find the median, the values have to be placed in value order, from smallest to largest. The center number would be the median. The number lies between the higher half and the lower half. Therefore the median represents the center of the data values.

Answer:

D. 6

Step-by-step explanation:

here, as given set Q consists { 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36}

and set Z contains {3, 6, 9, 12, 15, 18, 21,24, 27, 30, 33, 36, .... }

so be comparing both, we can see that the numbers 6, 12, 18, 24, 30 and 36 is repeated.

Step-by-step explanation:

[tex]W^m=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{m}\\\\W^n=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{n}\\\\W^mW^n=\underbrace{(W\cdot W\cdot W\cdot...\cdot W)}_{m}\underbrace{(W\cdot W\cdot W\cdot...\cdot W)}_{n}\\\\=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{m+n}=W^{m+n}[/tex]

From the following given equation, the answer to W^mW^n = [tex]\mathbf{W^{m+n}}[/tex]

The laws of indices provide us with the rules and principles for simplifying mathematical computations or algebraic expressions that include powers of the same base.

The example of the question given can be solved by using the multiplication rule. The multiplication rule states that we sum up the power of the integers if they have the same base.

From the given information

W^mW^n = [tex]\mathbf{W^{m+n}}[/tex]

Learn more about indices here:

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Answer:

YTM = 5.45%

Step-by-step explanation:

Here, we are interested in calculating the yield to maturity.

Mathematically;

Annual coupon=1000*4.3%=43

YTM=[Annual coupon+(Face value-Present value)/time to maturity]/(Face value+Present value)/2

=[43+(1000-870)/18]/(1000+870)2

=5.45%

Answer: 4.8mi

Step-by-step explanation:

From Newton, getting to Bloomington takes 10mi, and getting to Arlington takes 5.2mi.  Thus, simply do 10-5.2 to get 4.8mi.

Hope it helps <3

Answer:

9 x 9 x 9 x 9 x 9

Step-by-step explanation:

9^5 = 9 x 9 x 9 x 9 x 9

Answer:

it is C

Step-by-step explanation:

Answer:

Step-by-step explanation:

The square root of 7066 is 84.0595....

Therefore the largest number we must test is 84, seeing as now we have proven we do not need to test any numbers greater than 84.0595...

That means, we only need to test prime numbers smaller than 84 to see if they go into 7066.

84 isn't prime. But 83 is prime.

Therefore, the greatest prime that needs to be considered for divisibility is 83.

Answer:

The numbers 7066 is not prime .

But we easily know when a number is prime when we divide it by the first prime numbers; 2, 3, 5, 7, 11.

Step-by-step explanation:

It is known with certainty that a number is prime when it is only divisible by and by unity.

But in this case, that number, when divided by other numbers less than the one, shows that when dividing into the remainder, it gives zero, which means that it is not only divisible by itself or by the unit, but also by other numbers.

for example; 7066/2=3533 , the remainder is zero;