find the quotient of and express it in the simplest form

Answer:

I guess y=2x+5

Answer: Choice C. No error. Molly is correct

Note how BC is 4 units high while FG is 5 units high. We don't have a match. So there is no way the figures are the same regardless of rigid transformations.

Answer:

Its c

Step-by-step explanation:

I got it right on khan academy

The plus 7 at the end will shift the graph 7 units up. Replace y with f(x).

Then we have g(x) = f(x) + 7. Adding 7 to y = f(x) will increase the y value by 7.

The statement correctly describes the graph of y = x + 7 as choice A.

The graph is moved 7 units up

We have given that,

The graph of y = x.

Each statement describes a transformation of the graph of y = x.

The plus 7 at the end will shift the graph 7 units up.

Replace y with f(x).

Then we have g(x) = f(x) + 7.

Adding 7 to y = f(x) will increase the y value by 7.

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Explanation:

You could use any two points you want. For me, the easiest is when x = 0. Plug this into the equation to get

y = 2x-7

y = 2(0)-7

y = -7

So we have x = 0 and y = -7 pair up to get (0,-7) as our first point. This is the y intercept.

Repeat for x = 1

y = 2x-7

y = 2(1)-7

y = -5

So (1,-5) is another point on this line. You only need two points at minimum to graph a straight line.

Answer:

[tex]\boxed{2x-3}[/tex]

Step-by-step explanation:

[tex]f(x)=3x-1\\ g(x)= x+2[/tex]

[tex](f-g)(x)\\f(x)-g(x)[/tex]

[tex](3x-1)-(x+2)\\ 3x-1-x-2\\2x-3[/tex]

Answer:

[tex]f(x) =\sqrt[3]{x}[/tex]

Step-by-step explanation:

Hello!

Considering the parent function, as the most simple function that preserves the definition. Let's take the function given:

[tex]g(x) = \sqrt[3]{x-5}+7[/tex]

To have the the parent function, we must find the parent one, let's call it by f(x).

[tex]f(x) =\sqrt[3]{x}[/tex]

This function satisfies the Domain of the given one, because the Domain is still [tex](-\infty, \infty)[/tex] and the range as well.

Check below a graphical approach of those. The upper one is g(x) and the lower f(x), its parent one.

Answer:

5 units to the right and 7 units up (B on edge)

Step-by-step explanation:

Answer: $14,950

Step-by-step explanation:

Given: Cost of Direct Materials  =  $3,200

Cost of direct labor = $4,700

Overhead rate = 150%

So, Overhead cost = 150% x (Total  direct labor cost)

= $(150% x 4,700) =$ ( 1.5 x 4,700)                              [150% = 1.5]

= $7,050

Work in Progress  =  Direct Materials  + Direct labor  + Overhead

= $(3,200+4,700+7,050)

=$14,950

Hence, the balance in the Work in Process account at the end of September relative to Job A3B = $14,950

Answer:

x = 74°

Step-by-step explanation:

The diagram shown in this question, is a Quadrilateral inscribed in a circle

It is important to note that

The sum of opposite angles in a Quadrilateral = 180°

93° + z = 180°

z = 180° - 93°

z = 87°

In a cyclic quadrilateral,

Intercepted angle = 1/2(Intercepted arc)

Intercepted angle = 93°

Intercepted arc = x + 112°

Hence,

93° = 1/2(x + 112)°

93° × 2 = x + 112°

186° = x + 112°

x = 186° - 112°

x = 74°

Answer:

It’s 87° for mine

Step-by-step explanation:

7x - 14 = 4x + 19

7x - 4x = 14 + 19

3x = 33

x = 11

Answer:

y= 0.15x - 1, y = x, y = x + 100, y = 15x + 5.

Step-by-step explanation:

When the slope of a line is less than 1 (if the slope is a decimal), the slope will not be steep. But when the slope is more than 1, the slope will be steeper than the average.

According to that rule, the steepest will be y = 15x + 5.

The next steepest equations will be y = x and y = x + 100 (they are both at the same degree of steepness; the intercept does not impact the steepness of the line).

The least steepest will bey = 0.15x - 1.

So, the order, from least steep to most steep, will be y= 0.15x - 1, y = x, y = x + 100, y = 15x + 5.

Hope this helps!

Answer:

Step-by-step explanation:

Given figure : Trapezoid

Base sides,

a = 2.5

b = 7.5

Height ( h ) = 2.5

Now, finding the area:

[tex] \frac{1}{2} (a + b) \times h[/tex]

Plug the values

[tex] = \frac{1}{2 } \times (2.5 + 7.5) \times 2.5[/tex]

Calculate the sum

[tex] = \frac{1}{2} \times 10 \times 2.5[/tex]

Reduce the numbers with G.C.F 2

[tex] = 5 \times 2.5[/tex]

Calculate the product

[tex]12.5 \: \: {units}^{2} [/tex]

Hope this helps...

Best regards!

Answer:

1st one

Step-by-step explanation:

The rational function which is graphed below is  F(x)=-1/x, the correct option is B.

Function is a type of relation, or rule, that maps one input to specific single output;

In mathematics, a function is an expression, rule, or law that describes the relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable). In mathematics and the physical sciences, functions are indispensable for formulating physical relationships;

Linear function is a function whose graph is a straight line;

We are given that;

The graph of the function

Now,

Points on 1/(x + 4);

The function y = 1/(x + 4) is a hyperbola. It has two branches that extend infinitely in opposite directions. The x-axis and y-axis are both asymptotes of the hyperbola.

Points on y= 1/x-4;

The function y = 1/(x - 4) is also a hyperbola. Its asymptotes are the vertical line x = 4 and the horizontal line y = 0;

Points on y = 1/(x-1);

The function y = 1/(x-1) is also a hyperbola. Its asymptotes are the vertical line x = -4 and the horizontal line y = 0.

Therefore, by the given graph function will be F(x)=-1/x;

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Complete question :

∆ABC is similar to ∆PQR. AB¯¯¯¯¯ corresponds to PQ¯¯¯¯¯, and BC¯¯¯¯¯ corresponds to QR¯¯¯¯¯. If the length of AB¯¯¯¯¯ is 9 units, the length of BC¯¯¯¯¯ is 12 units, the length of CA¯¯¯¯¯ is 6 units, and the length of PQ¯¯¯¯¯ is 3 units, then the length of QR¯¯¯¯¯ is ______units and the length of RP¯¯¯¯¯ is ________units.

Answer:

QR = 4 units ; RP = 2 units

Step-by-step explanation:

For similar triangles

Length1 ∆1/length1 ∆2 = Length 2 ∆1 /length 2∆2

AB Corresponds to PQ

BC corresponds to QR

AB = 9 Units, BC = 12 Units

CA = 6 units, PQ = 3 units

Take the ratio of the corresponding sides :

AB/ PQ = BC / QR

9/ 3 = 12 / QR

Cross multiply

9 * QR = 3 * 12

QR = 36 / 9

QR = 4 units

For RP:

AB/PQ = CA/RP

9 / 3 = 6 / RP

9 * RP = 3 * 6

RP = 18 / 9

RP = 2 units

Answer:

rp-2 qr-4

Step-by-step explanation:

Step-by-step explanation:

HL states that a hypotenuse and leg of a right triangle must be congruent, so you would need to know the hypotenuses are congruent and a leg is congruent. For 6, You're only given 2 sides instead of 3, and since this is a Side-Side-Side Postulate, you must have the third sides be congruent. For 7, Angle-Side-Angle requires to known congruent angles and a side in between them, so you would need to know that angle I is congruent to angle L. Lastly, Side-Angle-Side needs two sides and an angle between them, so you would need to know that side JI is congruent to HD. HI is already congruent to itself by the Reflexive Property, so you only need to know JI ≅ HD.

Answer:

28 cm²

Step-by-step explanation:

The area of Δ BDF is the area of the rectangle subtract the area of the 3 white triangles.

Since the area of the rectangle = 80 cm² and

area = length × breadth, then

breadth = 80 ÷ 10 = 8 cm

Thus CE = EF = 8 cm and CD = DE = BC = 4 cm

Area of Δ DEF = 0.5 × 10 × 4 = 20 cm²

Area of Δ ABF = 0.5 × 8 × (10 - 4) = 0.5 × 8 × 6 = 24 cm²

Area of Δ BCD = 0.5 × 4 × 4 = 8 cm²

Thus

area of Δ BDF = 80 - (20 + 24 + 8) = 80 - 52 = 28 cm²

Answer:

The answer is option 2.

The correct answer is C. Four pies

Explanation:

Marginal cost refers to an increase in the cost of production as additional units are made. In the case of apple pies, the graph shows the cost for one is $1.00. Moreover, this decreases when two or three pies are produced because the cost is between $0.60 and $0.30. However, if the producer makes four or more units, the cost increases. For example, at four units the cost per unit is $0.60, while at six units the cost is $1.50. Thus, the marginal cost begins to increase at four pies.

Answer: four pies

Step-by-step explanation:

The graph is a marginal cost curve that compares expenses therefore it would equal four pies because the marginal cost rises on the graph starting at 4.

The required length of the base is 18 units for the square pyramid.

The square pyramid shown below has a slant height of 17 units and a vertical height of 15 units. What is the length of one of the bases of the pyramid to be determined?

In a right-angled triangle, its side, such as hypotenuse, perpendicular, and the base is Pythagorean triplets.

The verticle height = 15
Slant height = 17
Let the base length be a,
For the half slant profile applying the Pythagorean theorem,
slant heigth² = vertical height² +  base length ²
17² = 15² + ( a/2 )²
289 - 225  =  ( a/2 )²
( a/2 )² = 64
a/2 =8
a = 16

Thus, the required length of the base is 18 units for the square pyramid.

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Answer:

iv, ii, i, iii, vi, v

Step-by-step explanation:

First, it is better if you fix all of these into fractions:

2/3--> 0.6666

-4/5--> -0.8

7/4--> 1.75

-21/8--> -2.625

11/4--> 2.75

root 5--> 2.24...

Hope this helps!!

Answer:

[tex]a^2+2ab+b^2[/tex]

Step-by-step explanation:

If we have [tex](a+b)^2[/tex] we can calculate this as:

[tex](a+b)*(a+b)[/tex]

So, applying distribution property, we get:

[tex](a+b)*(a+b)=a*a+a*b+b*a+b*b[/tex]

Where:

[tex]a*a=a^{2}[/tex]

 [tex]b*b=b^2[/tex]

[tex]a*b=b*a=ab[/tex]

so:

[tex](a+b)*(a+b)=a^2-ab+ab+b^2\\(a+b)*(a+b)=a^2+2ab+b^2[/tex]

Answer:

x = -7

Step-by-step explanation:

5x+8=3x-6

Subtract 3x from each side

5x-3x+8=3x-3x-6

2x+8 = -6

Subtract 8 from each side

2x+8-8 = -6-8

2x = -14

Divide by 2

2x/2 = -14/2

x = -7

Answer: x= -7

Step-by-step explanation:

[tex]5x+8=3x-6[/tex]

[tex]\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides}[/tex]

[tex]5x+8-8=3x-6-8[/tex]

[tex]5x=3x-14[/tex]

[tex]\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}[/tex]

[tex]5x-3x=3x-14-3x[/tex]

[tex]2x=-14[/tex]

[tex]\mathrm{Divide\:2\:\:on\:\:both\:sides\:}[/tex]

[tex]-14/2=-7[/tex]

[tex]x=-7[/tex]

Answer:

The answer is 39 kg

Step-by-step explanation:

We are looking for the weight of box A so we will use the number given to use for Box A.

We also have the total which is 194/4 kg

If we divide 195 by 5 we will get 39 kg

But to check if your answer is correct also divide 195 by 41 and that will give us 4.75 kg

And if you add the two answers up your will get 43.75 kg

Now we need to find the weight of Box B to see if our answer is correct

When you subtract 43.75 from 195 you will get 151.25

When we will add 43.75 to 151.25 you will get 195

So the answer is correct, the answer is 39 Kg

Answer:

Hey there!

He can create 7 plates at most, with one carrot cake and one marble cake on each plate.

Hope this helps :)

Answer:

We have an extrema (local minimum) at x = -0.125

An inflection point at x = 0.25

Step-by-step explanation:

The given function is given as follows;

[tex]f(x) = 3x^{1/3} + 6x^{4/3}[/tex]

At the extrema points, f'(x) = 0 which gives;

[tex]0 = \dfrac{\mathrm{d} \left (3x^{1/3} + 6x^{4/3} \right )}{\mathrm{d} x} = \dfrac{(8 \cdot x+1) \times \sqrt[0.3]{x} }{x}[/tex]

(8x + 1) =x- (0/((x)^(1/0.3)) = 0

x = -1/8 = -0.125

f''(x)  gives;

[tex]f''(x) = \dfrac{\mathrm{d} \left (\dfrac{(8 \cdot x+1) \times \sqrt[0.3]{x} }{x} \right )}{\mathrm{d} x} = \dfrac{ \left (\dfrac{8}{3}\cdot x^2 - \dfrac{2}{3} \cdot x \right ) \times \sqrt[0.3]{x} }{x^3}[/tex]

Substituting x = -0.125 gives f''(x) = 32 which is a minimum point

The inflection point is given as follows;

[tex]\dfrac{ \left (\dfrac{8}{3}\cdot x^2 - \dfrac{2}{3} \cdot x \right ) \times \sqrt[0.3]{x} }{x^3} = 0[/tex]

[tex]\dfrac{8}{3}\cdot x^2 - \dfrac{2}{3} \cdot x \right }{} = 0 \times \dfrac{x^3}{ \sqrt[0.3]{x}}[/tex]

[tex]\dfrac{8}{3}\cdot x - \dfrac{2}{3} \right }{} = 0[/tex]

x = 2/3×3/8 = 1/4 = 0.25

We check the value of f''(x) at x = 0.24 and 0.26 to determine if x = 0.25 is an inflection point as follows;

At x = 0.24,   f''(x) = -0.288

At x = 0.26,   f''(x) = 0.252

0.25 is an inflection point

Answer:  1) c    2) a     3) d

Step-by-step explanation:

[tex]\cos \theta = \dfrac{adjacent}{hypotenuse}\quad \\\\\\\cos 42.1=\dfrac{4.7}{x}\\\\\\x=\dfrac{4.7}{\cos 42.1}\\\\\\\large\boxed{x=6.33}\\[/tex]

******************************************************************************************

Reference angle is the angle measurement from the x-axis.  There is no such thing as a negative reference angle.

-183°  is 3° from the x-axis so the reference angle is  [tex]\large\boxed{3^o}[/tex]

*******************************************************************************************

Coterminal means the same angle location after one or more rotations either clockwise or counter-clockwise.

To find these angles, add or subtract 360° from the given angle to find one rotation, add or subtract 2(360°) from the given angle to find two rotations, etc.

To find ALL of the coterminals, add or subtract 360° as many times as the number of rotations.  Rotations can only be integers. In other words, you can only have ± 1, 2, 3, ... rotations. You cannot have a fraction of a rotation.

Given: 203°

Coterminal angles: 203° ± k360°, k ∈ I

Answer:

cos(30)

Step-by-step explanation:

Answer:

sin(15)

Step-by-step explanation:

Answer:

The third option is correct.

The domain of the function is given by

[tex]Domain = 0 \leq t \leq 40[/tex]

The range of the function is given by

[tex]Range = 0 \leq V(t) \leq 200[/tex]

Step-by-step explanation:

Sara bought a cell phone for $200 and its value has decreased at rate of $5 per month.

V(t) is the value of the phone and t is the number of months.

The domain of the function is the possible values of the number of months t.

The domain of the function is given by

[tex]Domain = 0 \leq t \leq 40[/tex]

The range of the function is the values of V(t) that we get after substituting the possible values of the number of months t.

The range of the function is given by

[tex]Range = 0 \leq V(t) \leq 200[/tex]

When the number of months is t = 0 then the value of the function is maximum V(t) = 200

When the number of months is t = 40 then the value of the function is minimum V(t) = 0

Therefore, the third option is correct.

Answer:

Step-by-step explanation:

It is half of equilateral triangle where 2√3 is its hight so:

[tex]2\sqrt3=\frac{k\sqrt3}2\\\\4\sqrt3=k\sqrt3\\\\k=4[/tex]

Answer:

[tex]x=-1,5[/tex]

Step-by-step explanation:

[tex]x^2-4x-5=0[/tex]

In order to solve this quadratic, we have many methods. We can factor, complete the square, or use the quadratic formula. I'm going to factor since it's the easiest method.

To factor, find two numbers that when multiplied equal a(c) and when added equal b.

a=1, b=-4, and c=-5.

So we want two numbers that when multiplied equals 1(-5)=-5 and when added equals -4.

-5 and 1 are the possible numbers. Therefore:

[tex]x^2-4x-5=0\\x^2+x-5x-5=0\\x(x+1)-5(x+1)=0\\(x-5)(x+1)=0\\x=5, -1[/tex]