Find the probability of each event. A class has five boys and nine girls. If the teacher randomly picks six students, what is the probability that he will pick exactly four girls?

Answer:

Step-by-step explanation:

A basketball is basically a sphere, so it suffices to calculate the surface are of the ball to determine the amount of required material. Given a sphere of radius r we have that the surface area is [tex]4\pi r^2[/tex]

In this case, r = 11.14 cm. So the area is aproximately 1159.48 squared cm. (1159.48 = [tex]4\pi (11.14)^2[/tex])

Answer:

  $2192.60

Step-by-step explanation:

March 4 is day 63 of the year. So, the amount of tax that Kelly needs to refund to Mason is the tax for the remaining 365 -63 = 302 days of the year.

Kelly will owe Mason ...

  (302/365)($2650) = $2192.6027 ≈ $2192.60

Answer:

3 is not a solution

Step-by-step explanation:

6x – 7 = 12?

Substitute 3 in for x and see if the equation is true

6*3 - 7 = 12

18-7 = 12

11 =12

This is false so 3 is not a solution

Answer:

y > 2x + 1

Step-by-step explanation:

(1 is the y intercept) 2/1 is the gradient so 2 up and 1 across

Answer:

x = 1/2

Step-by-step explanation:

2(4x+2) = 4x - 12(x-1)

Distribute

8x +4 = 4x - 12x +12

Combine like terms

8x + 4 = -8x +12

Add 8x to each side

8x+4+8x = -8x+12 +8x

16x+4 = 12

Subtract 4 from each side

16x +4-4 = 12-4

16x = 8

Divide by 16

16x/16 =8/16

x = 1/2

Answer:

x = 1/2

Step-by-step explanation:

2(4x+2) = 4x - 12(x-1)

Expand brackets.

8x + 4 = 4x - 12x + 12

Subtract 4 on both sides.

8x = 4x - 12x + 12 - 4

Subtract 4x and add 12x on both sides.

8x - 4x + 12x = 12 - 4

Combine like terms.

16x = 8

Divide both sides by 16.

x = 8/16 = 1/2

Answer:

The probability that the person is between 65 and 69 inches is 0.5403

Step-by-step explanation:

Mean height = [tex]\mu = 66[/tex]

Standard deviation = [tex]\sigma = 2.5[/tex]

We are supposed to find What is the probability that the person is between 65 and 69 inches i.e.P(65<x<69)

[tex]Z=\frac{x-\mu}{\sigma}[/tex]

At x = 65

[tex]Z=\frac{65-66}{2.5}[/tex]

Z=-0.4

Refer the z table for p value

P(x<65)=0.3446

At x = 69

[tex]Z=\frac{69-66}{2.5}[/tex]

Z=1.2

P(x<69)=0.8849

So,P(65<x<69)=P(x<69)-P(x<65)=0.8849-0.3446=0.5403

Hence the probability that the person is between 65 and 69 inches is 0.5403

Answer:

60 cm

Step-by-step explanation:

You need to use ratios to solve.  If the scale is 1:30 then the wheel is 2:(?).  Cross-multiply the fractions and solve for x.

1/30 = 2/x

1x = 30*2

x = 60

The wheel is 60 cm in diameter.

Answer:

60 centimeters

Step-by-step explanation:

The scale is 1:30. The wheel diameter is 2 while the actual size of the wheel is unknown. Therefore, the scale for the wheel is 2:x

Let’s set up a proportion.

1/30=2/x

First, cross multiply. Multiply the numerator of the first fraction by the denominator of the second. Then, multiply the numerator of the second by the denominator of the first.

1*x= 2*30

1x=20*30

x=20*30

x=60

Add appropriate units, in this case centimeters (cm).

x= 60 cm

The actual diameter of the wheel is 60 centimeters.

Answer:

We accept H₀

p-value = 0,1618

Step-by-step explanation:

We are going to solve a one tail proportion-test ( right tail)

We assume Normal distribution

Sample population 1000

Political strategist to test  wants to test:

Null hypothesis                             H₀           p = p₀       or   p = 26 %

Alternate hypothesis                    Hₐ           p > p₀        or  p > 26%

We assume CI  90 % then

α = 10 %     α = 0,1    and  z score for α = 0,1  is critical value

z = 2,32          ( note  2,32 is z score for α = 0,1017 "good approximation")

To compute z(s)

z(s)  =  ( p -p₀ ) / √ p₀q₀/n

z(s)  =  ( 0,29 - 0,26 ) /√ 0,26*0,74/1000

z(s)  = 0,03 / 0,014

z(s) = 2,14

We compare z(s) and z(c)

z(s) < z(c)

2,14 < 2,32

z(s) is in the acceptance region we accept H₀

The p-value for z(s) is from z-table

p-value = 0,1618

Answer:

11 / 12 or 0.9167

Step-by-step explanation:

Given:

3/4 + 1/6

Find:

Value with expression

Computation:

"3/4 added to number 1/6"

3/4 + 1/6

By taking LCM

[9 + 2] / 12

11 / 12 or 0.9167

Answer:

15%

Step-by-step explanation:

To calculate the margin of error, we can adopt this formula

Margin of error = critical value* (standard deviation/sqrt of sample size)

Where critical value is 2.33, sd is 0.78 and sample size is150.

Thus, we have:

Margin of error = 2.33*(0.78/√150)

Margin of error = 2.33*(0.78/12.2474)

Margin of error =2.33*0.06369

Margin of error = 0.1484 which is a 15% margin of error

Answer:

D. ⅔

Step-by-step explanation:

I hope it helps :)

[tex]m = \frac{y_2 - y_1}{x_2 - x_1} \\ m = \frac{3 - 1}{5 - 2} = \frac{2}{3} \\ m = \frac{2}{3} [/tex]

Answer:

0

Step-by-step explanation:

3^2 is 9, and (-3)^2 is 9.

so, 9-9=0

Answer:

2√2−3

Step-by-step explanation:

Simplify each term.

Since there are no imaginary terms, the complex conjugate is the same as the simplified expression.

Hope this can help

Answer:

See below.

Step-by-step explanation:

So, we have the zeros -4 with a multiplicity of 1, zeros 2 with a multiplicity of 3, and f(0)=64.

Recall that if something is a zero, then the equation must contain (x - n), where n is that something. In other words, for a polynomial with a zero of -4 with a multiplicity of 1, then (x+4)^1 must be a factor.

Therefore, (x-2)^3 (multiplicity of 3) must also be a factor.

Lastly, f(0)=64 tells that when x=0, f(x)=64. Don't simply add 64 (like what I did, horribly wrong). Instead, to keep the zeros constant, we need to multiply like this:

In other words, we will have:

[tex]f(x)=(x+4)(x-2)^3\cdot n[/tex], where n is some value.

Let's determine n first. We know that f(0)=64, thus:

[tex]f(0)=64=4(-2)^3\cdot n[/tex]

[tex]64=-32n, n=-2[/tex]

Now, let's expand:

Expand:

[tex]f(x)=(x+4)(x^2-4x+4)(x-2)(-2)[/tex]

[tex]f(x)=(x^2+2x-8)(x^2-4x+4)(-2)[/tex]

[tex]f(x)=(x^4-4x^3+4x^2+2x^3-8x^2+8x-8x^2+32x-32)(-2)[/tex]

[tex]f(x)=-2x^4+4x^3+24x^2-80x+64[/tex]

This is the simplest it can get.

Answer: 12-i

               12-(√-1)

Step-by-step explanation:

[tex]18-\sqrt{-25}[/tex]   Original Question

[tex]18-(\sqrt{25} * \sqrt{-1} )[/tex]   Split

[tex]18-5*(\sqrt{-1} )[/tex]   Solve for square root

[tex]12-\sqrt{-1}[/tex]   Subtract

You can substitute [tex]\sqrt{-1}[/tex] for i

[tex]12-i[/tex]   Substitute

Answer:

18-5i

Step-by-step explanation:

Answer: The concentration will be 8 milligrams per liter at 2 hours and 4 hours.

Step-by-step explanation:

GIven: The concentration of a certain painkiller supplied by serum varies in its effectiveness over time according to the following function, [tex]C (t) = - t^2 + 6t[/tex] where C is the concentration of the painkiller in the serum measured in milligrams per liter so that it takes effect during t hours.

Put C(t)=8, then we get

[tex]8=-t^2+6t\\\\\Rightarrow\ t^2-6t+8=0\\\\\Rightarrow\ t^2-2t-4t+8=0\\\\\Rightarrow\ t(t-2)-4(t-2)=0\\\\\Rightarrow\ (t-2)(t-4)=0\\\\\Rightarrow\ t=2,4[/tex]

At t=2, [tex]C(t)=-(2)^2+6(2)=-4+12=8[/tex]

At t=4, [tex]C(t)=-(4)^2+6(4)=-16+24=8[/tex]

Hence, the concentration will be 8 milligrams per liter at 2 hours and  4 hours.

Answer:

b. the approx time it takes an investment to double in value

Answer:

S = [0.2069,0.7931]

Step-by-step explanation:

Transition Matrix:

[tex]P=\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right][/tex]

Stationary matrix S for the transition matrix P is obtained by computing powers of the transition matrix P ( k powers ) until all the two rows of transition matrix p are equal or identical.

Transition matrix P raised to the power 2 (at k = 2)

[tex]P^{2} =\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right][/tex]

[tex]P^{2} =\left[\begin{array}{ccc}0.2203&0.7797\\0.2034&0.7966\end{array}\right][/tex]

Transition matrix P raised to the power 3 (at k = 3)

[tex]P^{3} =\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]X\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right][/tex]

[tex]P^{3} =\left[\begin{array}{ccc}0.2203&0.7797\\0.2034&0.7966\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right][/tex]

  [tex]P^{3} =\left[\begin{array}{ccc}0.2086&0.7914\\0.2064&0.7936\end{array}\right][/tex]

Transition matrix P raised to the power 4 (at k = 4)

[tex]P^{4} =\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]X\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]X\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right][/tex]

[tex]P^{4} =\left[\begin{array}{ccc}0.2086&0.7914\\0.2064&0.7936\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right][/tex]

[tex]P^{4} =\left[\begin{array}{ccc}0.2071&0.7929\\0.2068&0.7932\end{array}\right][/tex]

Transition matrix P raised to the power 5 (at k = 5)

[tex]P^{5} =\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]X\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]X\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right]X\left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right][/tex]

[tex]P^{5} =\left[\begin{array}{ccc}0.2071&0.7929\\0.2068&0.7932\end{array}\right] X \left[\begin{array}{ccc}0.31&0.69\\0.18&0.82\end{array}\right][/tex]

[tex]P^{5} =\left[\begin{array}{ccc}0.2069&0.7931\\0.2069&0.7931\end{array}\right][/tex]

P⁵ at k = 5 both the rows identical. Hence the stationary matrix S is:

S = [ 0.2069 , 0.7931 ]

Answer:

a. $849.45

Step-by-step explanation:

In the above question, we are given the following information

Coupon rate = 10%

Face value = 1000

Maturity = n = 20 years

t = number of periods = compounded semi annually = 2

Percent yield = 12% = 0.12

Bond Value formula =

C/t × ([1 -( 1/ 1 + r/t)-^nt ÷] r/t) +( F/ (1 + r/t)^nt)

C = coupon rate × face value = 10% × 1000 = 100

Bond value:

= 100/2 × ( [1 - (1 /1 + 0.12/2)^-20×2]÷ 0.12/2)+ (1000/( 1 + 0.12/2)^20×2

= 50 × ( [1 - (1 /1 + 0.06) ^40] ÷ 0.06) + ( 1000/ (1 + 0.06) ^40

= 50 × ( [1 - (1/ (1.06) ^40] ÷ 0.06 ) + (1000/(1.06)^40)

= 50 × 15.046296872 + 97.222187709

= $849.45

Bond value = $849.45

Answer:

Step-by-step explanation:

Given,

Radius ( r ) = 10

Height ( h ) = 6

pi ( π ) = 3.14

now, let's find the volume of given cone:

[tex]\pi {r}^{2} \frac{h}{3} [/tex]

Plug the values

[tex] = 3.14 \times {10}^{2} \times \frac{6}{3} [/tex]

Evaluate the power

[tex] = 3.14 \times 100 \times \frac{6}{3} [/tex]

Calculate

[tex] = 628 \: {units}^{3} [/tex]

Hope this helps..

Best regards!!

Answer:

The answer is 200π units³ .

Step-by-step explanation:

Given that the formula of volume of cone is V = 1/3×π×r²×h where r represents radius and h is height. Then, you have to substitute the value of radius and height into the formula :

[tex]v = \frac{1}{3} \times \pi \times {r}^{2} \times h[/tex]

[tex]let \: r = 10 \: , \: h = 6[/tex]

[tex]v = \frac{1}{3} \times \pi \times {10}^{2} \times 6[/tex]

[tex]v = \frac{1}{3} \times \pi \times 600[/tex]

[tex]v = 200\pi \: {units}^{3} [/tex]

Answer:

15 pt

Step-by-step explanation:

to convert qt to pt you multiply by 2 so 7 and 1/2 times 2 is 15

A - No

B - No

C - Yes

D - Yes

.

C and D are alternate exterior angles

Answer:

35 degree angle a cute angle

Answer:

Step-by-step explanation:

A and B are supplementary angles since the lines are parallel

A + B = 180

6x-18 + 14x+38 = 180

Combine like terms

20x +20 = 180

Subtract 20 from each side

20x+20 -20 =180-20

20x = 160

Divide by 20

20x/20 =160/20

x = 8

Answer:

Look for perpendicular lines or corresponding angles or alternate interior angles.

Step-by-step explanation:

When you want to show that a quadrilateral is a parallelogram you need to show that the oposite sides are parallel. In order to show that two segments are parallel there are various theorems and definitions you can use.

1 -  Remember that two lines perpendicular to the same segment are parallel.

2 - When two lines are cut by a secant and their alternate interior angles are congruent, then the resulting lines are parallel, I will attach a drawing to illustrate what I am saying.

3 - When two lines are cut by a secant and their CORRESPONDING angles are congruent, then the resulting lines are parallel, I will also attach a drawing to illustrate what I am saying.

4x+21+3x-5=121

7x+16=121

x=15

angle ABD =4(15)+21=81

Concepts:

Answer:

First option and fifth option

-2x-1=3^(-x) and 2^(-x)+2= -5^x + 3 don't intersect.

Therefore, the graphs have no solution.

Answer:

3

Step-by-step explanation:

Use this equation

[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] substitute

-6-3/0-3 subtract

-9/-3 simplify

-3/-1 two negitives cansle out

3/1=3

Hope this helpes, if it did, please consider giving me brainliest, it will help me a lot. If you have any questions, feel free to ask.

Have a good day! :)

Answer:

3

Step-by-step explanation:

To find the slope, we use the slope formula

m= ( y2-y1)/(x2-x1)

   = ( -6 -3)/(0 -3)

    = -9/-3

    = 3

Answer:

The answer for dy/dx is 3/4t .

Step-by-step explanation:

First, you have to differentiate x and y expressions in term of t :

[tex]x = a {t}^{4} [/tex]

[tex] \frac{dx}{dt} = 4a {t}^{3} [/tex]

[tex]y = a {t}^{3} [/tex]

[tex] \frac{dy}{dt} = 3a {t}^{2} [/tex]

Next, we can assume that dy/dt ÷ dx/dt = dy/dx. So we have to substitute the expressions :

[tex] \frac{dy}{dt} \div \frac{dx}{dt} = \frac{dy}{dt} \times \frac{dt}{dx} = \frac{dy}{dx} [/tex]

[tex] \frac{dy}{dx} = 3a {t}^{2} \div 4a {t}^{3} [/tex]

[tex] \frac{dy}{dx} = 3a {t}^{2} \times \frac{1}{4a {t}^{3} } [/tex]

[tex] \frac{dy}{dx} = \frac{3}{4t} [/tex]

Answer:

[tex]\boxed{\frac{1}{8} }[/tex]

Step-by-step explanation:

[tex]\frac{5}{4} / 10[/tex]

Changing "division" into multiplication and inverting the term after it:

[tex]\frac{5}{4} * \frac{1}{10}[/tex]

=> [tex]\frac{1*1}{4*2}[/tex]

=> 1/8

Answer:

1/8

Step-by-step explanation:

Well to do 5/4 ÷ 10 let's set up the following.

[tex]\frac{5}{4} / \frac{10}{1}[/tex]

Then we use the keep, change, and flip rule.

So keep 5/4 change the / to a * and flip the 10/1 ro a 1/10.

[tex]\frac{5}{4} * \frac{1}{10}[/tex]

Now we multiply them to get,

5/40

simplified

1/8

Thus,

the answer is 1/8.

Hope this helps :)

If it has a single zero that means it has to be just touching the x-axis with its tip.

We know that if it has only one zero, the discriminant equals 0.

So,

[tex]D=b^2-4ac=0\implies (-k)^2-4(1)(9)=0[/tex]

Solving for k,

[tex]k=\pm\sqrt{36}=\boxed{\pm{6}}[/tex].

Hope this helps.