Answer:
A. 210
Step-by-step explanation:
Consider the three stocks in the following table. Pt represents price at time t, and Qt represents shares outstanding at time t. Stock C splits two-for-one in the last period.
P0 Q0 P1 Q1 P2 Q2
A 90 100 95 100 95 100
B 50 200 45 200 45 200
C 100 200 110 200 55 400
Required:
Calculate the first-period rates of return on the following indexes of the three stocks: (Do not round intermediate calculations. Round answers to 2 decimal places.)
a. A market value–weighted index
b. An equally weighted index
Lily begins soving the equation 4(x -1) -x =3(x + 5) -
11. Her work is shown bekow.
How can her partial solution be interpreted?
O The equation has one solution: x =0.
O The equation has one solution: x=8.
O The equation has no solution.
O The equation has infinite solutions.
4(x-1) -X= 3(x + 5) -11
4x–4-X=3x + 15-11
3x-4= 3x + 4
PLEASE HURRY
Answer:4(x - 1) - x = 3(x + 5) - 11
Step-by-step explanation:
Lily's work:
4(x – 1) – x = 3(x + 5) – 11
4x – 4 – x = 3x + 15 – 11
3x – 4 = 3x + 4
Her partial solution, 3x - 4 = 3x + 4, can be interpreted as a FALSE statement because 3x - 4 does NOT equal 3x + 4.
Since it is a false statement, the equation has no solution.
The number of the solution will be infinity. Then the correct option is D.
What is the solution of the equation?The solution of the equation means the value of the unknown or variable.
The equation is given below.
4(x – 1) – x = 3(x + 5) – 11
Simplify the equation, we have
4x – 4 – x = 3x + 15 – 11
3x - 3x = 8
The variable x is eliminated.
Then the number of the solution will be infinity.
Then the correct option is D.
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-1/2 (8+1/3 )
1. -4-1/6
2.-4-1/3
3.-5+1/3
4. -5+1/6
Answer:4.16667
Step-by-step explanation: 1
Simplify —
3
Equation
0 - (— • (8 + —))
2 3
STEP
2
:
Rewriting the whole as an Equivalent Fraction
2.1 Adding a fraction to a whole
Rewrite the whole as a fraction using 3 as the denominator :
8 8 • 3
8 = — = —————
1 3
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
8 • 3 + 1 25
————————— = ——
3 3
Equation at the end of step
2
:
1 25
0 - (— • ——)
2 3
STEP
3
:
1
Simplify —
2
Equation at the end of step
3
:
1 25
0 - (— • ——)
2 3
STEP
4
:
Final result :
-25
——— = -4.16667
6
Terms and topics
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f(x)=2x+3 find the
x-int:
y-int:
Asymptote:
End behavior:
Also put in a table f(x)=2x+3
Susan has 4 cup of raisins and she is dividing them into 3/8 cup
servings. How many servings will she have?
Answer:
32/3 servings
Step-by-step explanation:
4 / (3/8) =
(4/1) x (8/3) =
32/3
Two dice are rolled; find the probability for total: a) 1, b) 4 or 6; c) <13
Answer:
0 ; 2/9 ; 1
Step-by-step explanation:
In a roll of two dice ;
The sample space = (Number of faces on die)^number of dice rolled = 6^2 = 36
The total possible outcome = sample space = 36
The probability of an event (A) :
P(A) = number of required outcome / number of total possible outcomes
find the probability for total: a) 1,
P(total of 1)
Number of 1 total = 0
Hence, P(total of 1) = 0
b) 4 or 6;
Number of 4 total = 3
Number of 6 total = 5
3 /36 + 5 / 36 = 8/36 = 2/9
c) <13
P(total < 13)
Number of total < 13 = 36
36 / 36 = 1
expand and simplify root5(root10+root2)
convert into power notation 81/49
what is the awnser to y=3/2x-1
Answer:
On a coordinate graph, make a point at (0, -1)
Move the point up 3 units and right 2 units, and make another point. Continue across the plane and draw the line connecting the dots.
Answer:
Step-by-step explanation:
Sophie answered 84% of the questions on her science test correctly. If she answered 21 questions correctly, how many questions were on the test?
Answer:25
Step-by-step explanation:
Suppose a one-year subscription to a magazine costs $12.99 and a three-year subscription costs $25.98. The cost and length of a subscription are related. Write a slope-intercept equation to model the cost of a subscription for any period of time.
Answer:
[tex]y = 6.495x + 6.495[/tex]
Step-by-step explanation:
Represent years with x and cost with y.
So, we have:
[tex](x_1,y_1)=(1,12.99)[/tex]
[tex](x_2,y_2)=(3,25.98)[/tex]
Required
Determine the slope intercept equation
First, we calculate the slope (m)
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex]m = \frac{25.98 - 12.99}{3 - 1}[/tex]
[tex]m = \frac{12.99}{2}[/tex]
[tex]m = 6.495[/tex]
The equation is then calculated as:
[tex]y - y_1 = m(x - x_1)[/tex]
Where
[tex]m = 6.495[/tex]
[tex](x_1,y_1)=(1,12.99)[/tex]
[tex]y - 12.99 = 6.495(x - 1)[/tex]
[tex]y - 12.99 = 6.495x - 6.495[/tex]
Make y the subject
[tex]y = 6.495x - 6.495 + 12.99[/tex]
[tex]y = 6.495x + 6.495[/tex]
Sets B and D are subsets of the universal set U.
These sets are defined as follows.
U= {f, k, q, s, x, y, z)
B={k, q, x, y)
D = {f.q, x, y, z)
Find the following sets.
Write your answer in roster form or as Ø.
(a) BnD' = [
(b) (BUD)' = [
Answer:
(a) B ∩ D' = {k}
(b) (B ∪ D)' = {s}
Step-by-step explanation:
Set Notation
[tex]\begin{array}{|c|c|l|} \cline{1-3} \sf Symbol & \sf N\:\!ame & \sf Meaning \\\cline{1-3} \{ \: \} & \sf Set & \sf A\:collection\:of\:elements\\\cline{1-3} \cup & \sf Union & \sf A \cup B=elements\:in\:A\:or\:B\:(or\:both)}\\\cline{1-3} \cap & \sf Intersection & \sf A \cap B=elements\: in \:both\: A \:and \:B} \\\cline{1-3} \sf ' \:or\: ^c & \sf Complement & \sf A'=elements\: not\: in\: A \\\cline{1-3} \sf - & \sf Difference & \sf A-B=elements \:in \:A \:but\: not\: in \:B}\\\cline{1-3} \end{array}[/tex]
Given sets:
U (universal) = {f, k, q, s, x, y, z}B = {k, q, x, y}D = {f, q, x, y, z}Part (a)
[tex]\begin{aligned}\sf B \cap D' & = \sf B \cap \left( \text{U}-D\right)\\ &= \sf \{k, q, x, y \} \cap \left(\{f, k, q, s, x, y, z \} - \{f, q, x, y, z \}\right)\\& = \sf \{k, q, x, y \} \cap \{ k, s \}\\ & = \sf \{k \}\end{aligned}[/tex]
Part (b)
[tex]\begin{aligned}\sf \left(B \cup D\right)' & = \sf \text{U}-\left(B \cup D\right)\\& = \sf \{f, k, q, s, x, y, z \}-\left(\{k, q, x, y\} \cup \{f, q, x, y, z\}\right)\\& = \sf \{f, k, q, s, x, y, z \}-\{ f, k, q, x, y, z\}\\& = \sf \{s\}\\\end{aligned}[/tex]
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Now we have to find,
→ B ∩ D'
→ (B ∪ D)'
Let's solve for the following sets,
a) B ∩ D' = ?
→ B ∩ D'
→ {k, q, x, y} ∩ ({f, k, q, s, x, y, z} - {f, q, x,y,z})
→ {k, q, x, y} ∩ {k, s} = {k}
Hence, the required set is {k}.
b) (B ∪ D)' = ?
→ B' ∩ D'
→ ({f, k, q, s, x, y, z} - {k, q, x, y}) ∩ ({f, k, q, s, x, y, z} - {f, q, x, y, z})
→ {f, s, z} ∩ {k, s} = {s}
Hence, the required set is {s}.
(7y-8y)2+14=2 solve for x
Answer:
y = 6
Step-by-step explanation:
(7y-8y)2+14=2
First, simplify the left side
7y - 8y = -y
2*-y = -2y
Now solve the equation
-2y + 14 = 2
Subtract 14 from both sides
-2y = -12
Take away the negative signs since both sides are negative
2y = 12
Divide both sides by 2
y = 6
(If the variable was x instead of y the variable would still equal 6)
Question 7 of 10
Describe the nature of the roots for this equation. x²+3x-7=0
A. One real, double root
B. Two real, irrational roots
C. Two real, rational roots
D. Two complex roots
Answer:
B
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0 ( a ≠ 0 )
Then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real irrational roots
• If b² - 4ac > 0 and a perfect square then 2 real rational roots
• If b² - 4ac = 0 then 1 real double root
• If b² - 4ac < 0 then 2 complex roots
Given
x² + 3x - 7 = 0 ← in standard form
with a = 1, b = 3, c = - 7 , then
b² - 4ac
= 3² - (4 × 1 × - 7) = 9 + 28 = 37
Since b² - 4ac > 0 then 2 real irrational roots
how to explain how you know the midpoint of line segment
Answerits the point that divides the segment into two congruent segments
Step-by-step explanation:
ex. D————-o————-G
The midpoint would be the O. Mid:means Middle
hehehe hope this helps
PLEASE IM LITERALLY SO CONFUSED
A ladder is placed 30 inches from a wall. It touches the wall at a height of 50 inches from the ground.
The angle made by the ladder with the ground is
degrees, and the length of the ladder is
inches.
The length of the ladder is 58.31 inches and the angle made by the ladder with the ground is θ = 59.04°.
The distance between the ladder and the wall is 30 inches.
The height at which the ladder touches the wall is 50 inches from the ground.
Let x be the slant height when the ladder touches the wall.
Then, by using a Pythagorean theorem:
(Base)² + (Altitude)² = (Hypotenuse)²
(30)² + (50)² = x²
x² = 900 + 2500
x² = 3400 inches²
x = √[ 3400 inches²]
x = 10√34 inches
x = 58.31 inches
Then the angle made by the ladder with gound is :
tan (θ) = opposite / adjacent
tan (θ) = 50/30
tan (θ) = 5/3
θ = tan⁻¹ ( 5/3 )
θ = 59.04°
Therefore, the ladder is 58.31 inches long and the angle between the ground and the ladder is 59.04°.
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A swimming pool has a volume of 32,100 gal. Use the table of conversion facts to find out how many cubic yards of water it would take to completely fill the swimming pool. Round your answer to two decimal places.
158.93 yd³ water it would take to completely fill the swimming pool.
Given that, a swimming pool has a volume of 32,100 gal and we have to find out that how many cubic yards of water it would take to completely fill the swimming pool.
1 cubic yard (yd³) ≈ 201.97 gallon (gal)
So, by using the conversion given above we can simply find the water in cubic yards that it would take to completely fill the swimming pool.
Volume of the swimming pool = 32,100 gal
and we know that, 1 cubic yard (yd³) ≈ 201.97 gallon (gal)
Now, we get
water needed in cubic yards to completely fill the swimming pool
= 32,100/201.97
= 158.93 yd³
Hence, 158.93 yd³ water it would take to completely fill the swimming pool.
Therefore, 158.93 yd³ is the required answer.
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5x – 24 > 26
what is the solution to the inequality?
Answer:
x > 10
Step-by-step explanation:
5x - 24 > 26
Add 24 on both sides.
5x -24 + 24 > 26 + 24
5x > 50
Divide by 5 on both sides.
x > 50 ÷ 5
Find x.
x > 10
Could y’all PLEASE HELP
Answer:
should be complementary angles
HELP ME OUT PLEASE!!!
Answer:
x=30
Step-by-step explanation:
8x - 3(2x-4) = 3(x-6)
first let's get rid of the brackets:
8x- 3·2x + 3·4 = 3x - 3·6
8x - 6x + 12 = 3x - 18
now group all the x terms and number terms
8x - 6x - 3x = -18 - 12
-x = -30
x = 30
A length of a rope is stretched between the top edge of a building
Answer:
what am i supposed to be answering..?
Step-by-step explanation:
The Awsome Bowl Factory makes two kinds of bowls. they produce a basic bowl every 6 minutes and a gigantic bowl every 15 minutes. They start at 8:00 a.m. how many minutes after they start will both bowls be produced together?
Answer:
21 minutes or 8:21 a.m
Step-by-step explanation:
6+15=21
Larry recorded his time as he ran. What was his average speed from hour 2 to hour 4?
Answer:
4-2=2
Step-by-step explanation:
Answer:
7 mph
Step-by-step explanation:
i took the same test on edg
Solve the system by the elimination method:
-6x + 5y = -11
6x - 11y = -19
A (6,5)
B (-6,-5)
C (5,6)
D (-5, -6)
Answer:
x = 6, y = 5
Step-by-step explanation:
Solve the following system:
{5 y - 6 x = -11 | (equation 1)
{-11 y + 6 x = -19 | (equation 2)
Add equation 1 to equation 2:
{-(6 x) + 5 y = -11 | (equation 1)
{0 x - 6 y = -30 | (equation 2)
Divide equation 2 by -6:
{-(6 x) + 5 y = -11 | (equation 1)
{0 x + y = 5 | (equation 2)
Subtract 5 × (equation 2) from equation 1:
{-(6 x) + 0 y = -36 | (equation 1)
{0 x + y = 5 | (equation 2)
Divide equation 1 by -6:
{x + 0 y = 6 | (equation 1)
{0 x + y = 5 | (equation 2)
Collect results:
Answer: {x = 6, y = 5
help pleasee :)
In the 1936 Olympics, Jesse Owens won a gold medal for running the 100-meter dash in 10.3 seconds. What was Owens' speed in meters per second, rounded to the nearest tenth?
Jesse Owen speed is 9.71 meters per seconds.
How to find speed?Speed is a scalar quantity that refers to "how fast an object is moving.
In other words, speed is the distance travelled per unit of time.
Therefore, it can be represented mathematically as follows:
speed = distance / time
Jesse Owen covers 100 meters dash for 10.3 seconds. Therefore, the speed he used for the race can be calculated as follows:
speed = distance / time
distance = 100 meters
time = 10.3 seconds
Hence,
speed = 100 / 10.3
speed = 9.70873786408
speed = 9.71 meters per seconds
Therefore, Jesse Owen speed is 9.71 meters per seconds.
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Solve the following equation. Express your answer as an integer, simplified fraction, or decimal rounded to two decimal places.
A rectangular-shaped parking lot is to have a perimeter of 546 yards. If the width must be 61 yards because of a building code, what will the length need to be?
The length of the parking lot will be 212 yards
Perimeter of rectangleFrom the question, we are to determine what the length of the parking lot needs to be
From the given information, we have that
"A rectangular-shaped parking lot is to have a perimeter of 546 yards"
and
"the width must be 61 yards"
From the formula for perimeter of a rectangle,
P = 2(l +w)
Where P is the perimeter
l is the length
and w is the width
From the given information,
P = 546 yards
w = 61 yards
Putting the parameters into the equation,
546 = 2(l + 61)
546 = 2l + 122
2l = 546 - 122
2l = 424
l = 424/2
l = 212 yards
Hence, the length of the parking lot will be 212 yards
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One-stray Problem Solving
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POSSIBLE POINTS: 5.88
A population of bacteria is growing at an hourly rate of r so that at the end of each hour the population of the sample is multiplied by the growth factor of
z = 1+r. The beginning population is 800 bacteria, an additional 300 are present after 1 hour, and an additional 400 are present after the following
hour.
Write an expression for the population at the end of three hours in terms of the growth factor.
Answer:
1500z
Step-by-step explanation:
Given a bacteria population that is multiplied by z every hour, and the population after 2 hours is 1500, you want the population after 3 hours in terms of z.
ApplicationThe problem statement tells you the population is multiplied by z every hour. After 2 hours, the population is 800 +300 +400 = 1500. After 3 hours, that value will be multiplied by z:
1500z . . . . . population after 3 hours
__
Additional comment
The given values of population tell us z = 1100/800 = 1.375 for the first hour, and z = 1500/1100 ≈ 1.364 for the second hour. The average value of z for the two-hour period is √(15/8) ≈ 1.369. The desired expression could be any of ...
800z³ . . . . . . . population 3 hours after the beginning1100z² . . . . . . . population 2 hours after the first hour1500z . . . . . . . population 1 hour after the second hourPresumably z would have different values in each case, and we hesitate to predict what those values might be. Perhaps the population is being rounded to the nearest 10 or 100.
An exponential regression calculation models the population as ...
p = 801.945×1.36812^t . . . . . . . z ≈ 1.36812
Using this formula, we get the given population numbers by rounding to the nearest 10.
evaluate the expression when c=2
c^2-8c-3
Answer:
-15
Step-by-step explanation:
Replace c with 2,
(2)^2 -8(2) -3 =
4 - 16 -3 + -12
= -15
Martine wants to open an after-school tutoring service for students in 6th through 9th grade. How can a thorough knowledge of customers' expectations improve the probability of her success?
Answer:
it would help her know how to prepare her teaching to match the students learning and expectations
Step-by-step explanation:
This idea of opening this tutoring service for students in these grades would prove a success if if martine has adequate knowledge of her students/customers. That is the learners requirements, their expectations, their experiences, and their strengths and weaknesses in particular subject areas.
Knowledge of these expectations would help to set Martine on the path of tutoring success and this would attract more students. So for her to have a strong tutoring business she has to know the approaches to use to make students strong academically, and how to match learning ability with her teaching.