Answer:
HGD: 117
FDG: 180
Step-by-step explanation:
Answer:
<HDG = 117 degrees
<FDG = 63 degrees
Step-by-step explanation:
Its a straight line
These are supplementary angles
If its a striaght line its 180 degrees.
We already know theres a 63 degrees so we jsut gotta subtract
180-63=117
So 117 degrees for HDG
[tex]\sqrt3+2\sqrt2 - \sqrt6-4\sqrt2[/tex]
Can someone please help me with number 35?
Answer:
4
Step-by-step explanation:
Two cars start at a given point and travel in the same direction at average speeds of 45 miles per hour and 52 miles per hour (see figure). How far apart will they be in 4 hours?
Answer:
half apart
Step-by-step explanation:
hope it help you
Avery and Carmen both have summer jobs. Avery gets paid $360 every 4 weeks. Carmen gets paid $480 every 6 weeks. summer break lasts a total of 12 weeks. who will earn more money during summer break?
Answer:
Avery
Step-by-step explanation:
12/4=3 so Avery will be paid 3 times
360×3= $1080
12/6=2 Carmen will be paid twice
480×2=$960
Avery earns more
Choose the grid reference number for the mine shown. A. 621333 B. 136233
PLEASE HELP ASAP!!!
Answer:
A.621333
Step-by-step explanation:
◑◑◑◑◑◑◑◑
Answer:
631226
Step-by-step explanation:
Distribute: -(14s+9)-7(s+11)
Answer: -21s-86
Step-by-step explanation:
Distribute the -1 to the 14s+9 (this means multiply-1 and 14s, then multiply -1 and 9) to get -14s-9. Then distribute the -7 to the s+11 (this mean multiply -7 and s, then multiply -7 and 11) to get -7s-77. You will now have the equation -14s-9-7s-77. Simplify this by adding like terms (-14s-7s) and (-9-77) you will get the equation: -21s-86
Distributing -(14s+9)-7(s+11) gives -14s -9 -7s -77; and further simplification results into -21s -86
From the question,
We are to distribute -(14s+9)-7(s+11)
To do this,
We will clear the bracket by distributing the terms outside
That is,
-(14s+9)-7(s+11) becomes
-14s -9 -7s -77
Now, if desired, we can simplify further by collecting like terms
-14s -9 -7s -77
-14s -7s -9 -77
Then, we get
-21s -86
The simplified expression is -21s -86
Hence, distributing -(14s+9)-7(s+11) gives -14s -9 -7s -77; and further simplification results into -21s -86
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Select the shapes that are similar to shape A
Answer:
purple in the top left
Step-by-step explanation:
um I don't know, it looks right, lol I'm sorry I hope this helps you let me know if its right
PLEASE 40 points
What is an equation that has -12 and 15 as it’s only solutions
Answer: x^2+27x+180
Step-by-step explanation: can i pls have brainliest i need it for my goal
find the next two terms of the sequence 1.1 , 2.2 , 3.3, 4.4, ….. A) 4.5, 5.5 B ) 5.6 C) 5.6, 6.7 D) 5.5, 6.6
Answer:
D)
Step-by-step explanation:
the pool at the apartment is 30 feet long 20 feet wide and five feet deep it has been filled to 4 feet how many more cubic inches does it need
Answer:
600 cubic feet
Step-by-step explanation:
IF YOU DONT KNOW THE QUESTION, PLEASE DONT ANSWER IT FOR THE PONIS. I REALLY NEED IT
Answer:
- 3x^2 + 2x - 13
Step-by-step explanation:
f (x) + g (x) = ( - 4x^2+5x-9) + (x^2 - 3x - 4)
= ( - 4x^2 + x^2) + (5x-3x) + (-9-4)
= - 3x^2 + 2x - 13
If you have a collection of 20 items, how many different groups of 8 can you create?
Answer:
you can create 2 groups of 8 and you will have a group of 4 left
Step-by-step explanation:
Heba ate 1/12 of a box of cereal. Now the box is 3/4 full
What fraction of a full box was there before Heba ate?
Answer:
5/6
Step-by-step explanation:
1/12 + 3/4 = 9/12
9/12 + 1/12 = 10/12
simplify 10/12
= 5/6
Here is a linear equation in two variables: 2x+4y−31=123
Answer:
y=−11x+77/2
Step-by-step explanation:
The procedure for solving simultaneous linear equations now called Gaussian elimination appears in the ancient Chinese mathematical text Chapter Eight: Rectangular Arrays of The Nine Chapters on the Mathematical Art. Its use is illustrated in eighteen problems, with two to five equations.[4]
Systems of linear equations arose in Europe with the introduction in 1637 by René Descartes of coordinates in geometry. In fact, in this new geometry, now called Cartesian geometry, lines and planes are represented by linear equations, and computing their intersections amounts to solving systems of linear equations.
The first systematic methods for solving linear systems used determinants, first considered by Leibniz in 1693. In 1750, Gabriel Cramer used them for giving explicit solutions of linear systems, now called Cramer's rule. Later, Gauss further described the method of elimination, which was initially listed as an advancement in geodesy.[5]
In 1844 Hermann Grassmann published his "Theory of Extension" which included foundational new topics of what is today called linear algebra. In 1848, James Joseph Sylvester introduced the term matrix, which is Latin for womb.
Linear algebra grew with ideas noted in the complex plane. For instance, two numbers w and z in {\displaystyle \mathbb {C} }\mathbb {C} have a difference w – z, and the line segments {\displaystyle {\overline {wz}}}{\displaystyle {\overline {wz}}} and {\displaystyle {\overline {0(w-z)}}}{\displaystyle {\overline {0(w-z)}}} are of the same length and direction. The segments are equipollent. The four-dimensional system {\displaystyle \mathbb {H} }\mathbb {H} of quaternions was started in 1843. The term vector was introduced as v = x i + y j + z k representing a point in space. The quaternion difference p – q also produces a segment equipollent to {\displaystyle {\overline {pq}}.}{\displaystyle {\overline {pq}}.} Other hypercomplex number systems also used the idea of a linear space with a basis.
Arthur Cayley introduced matrix multiplication and the inverse matrix in 1856, making possible the general linear group. The mechanism of group representation became available for describing complex and hypercomplex numbers. Crucially, Cayley used a single letter to denote a matrix, thus treating a matrix as an aggregate object. He also realized the connection between matrices and determinants, and wrote "There would be many things to say about this theory of matrices which should, it seems to me, precede the theory of determinants".[5]
Benjamin Peirce published his Linear Associative Algebra (1872), and his son Charles Sanders Peirce extended the work later.[6]
The telegraph required an explanatory system, and the 1873 publication of A Treatise on Electricity and Magnetism instituted a field theory of forces and required differential geometry for expression. Linear algebra is flat differential geometry and serves in tangent spaces to manifolds. Electromagnetic symmetries of spacetime are expressed by the Lorentz transformations, and much of the history of linear algebra is the history of Lorentz transformations.
The first modern and more precise definition of a vector space was introduced by Peano in 1888;[5] by 1900, a theory of linear transformations of finite-dimensional vector spaces had emerged. Linear algebra took its modern form in the first half of the twentieth century, when many ideas and methods of previous centuries were generalized as abstract algebra. The development of computers led to increased research in efficient algorithms for Gaussian elimination and matrix decompositions, and linear algebra became an essential tool for modelling and simulations.[5]
Vector spaces
Main article: Vector space
Until the 19th century, linear algebra was introduced through systems of linear equations and matrices. In modern mathematics, the presentation through vector spaces is generally preferred, since it is more synthetic, more general (not limited to the finite-dimensional case), and conceptually simpler, although more abstract.
A vector space over a field F (often the field of the real numbers) is a set V equipped with two binary operations satisfying the following axioms. Elements of V are called vectors, and elements of F are called scalars. The first operation, vector addition, takes any two vectors v and w and outputs a third vector v + w. The second operation, scalar multiplication, takes any scalar a and any vector v and outputs a new vector av. The axioms that addition and scalar multiplication must satisfy are the following. (In the list below, u, v and w are arbitrary elements of V, and a and b are arbitrary scalars in the field F.)[7]
Find m FGN
See picture and give explanation please! Thank you!
Answer:
m<FGN=(7x+18)º=88º
Step-by-step explanation:
(7x+18)º=(6x-10)º+38º
x=10
so
m<FGN=(7x+18)º=88º
hope this is the answer you're looking for.
I need help asap pleaseeeee
James has a piece of construction paper with a length of 9/10 feet and a width of 2/3 feet.
What is the area of James's piece of construction paper?
Area = length x width
When you multiply fractions, multiply top number by top number and bottom number by bottom number:
9/10 x 2/3 = (9 x 2) / (10 x 3) = 18/30 this can be reduced by dividing both numbers by 6:
18/30 reduces to 3/5
Answer: 3/5 square feet
- Given: C is the midpoint of AE
C is the midpoint of BD
AE = BD
=
Prove: AC = CD
A midpoint is a point that bisects a line into two equal parts.
Given that C is the midpoint of AE, hence;
AC + CE = AE ........ 1
Similarly, if C is the midpoint of BD, then;
BC + CD = BD................... 2
If AE = BD, then we will equate 1 and 2 to have:
AC + CE = BC + CD
Also since CE = BC, the equation becomes
AC + CE = CE + CD
AC = CD (Proved)
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Which of the following relations is a function?
O {(9,0), (10,3), (11, 6), (11, 9)}
O {(1, 1), (1, 2), (1, 3), (1,4)}
O {(1, 3), (2, 10), (6, 24), (24, 6)}
O {(0,6), (-1, 10), (-1, 14), (-3, 18)}
Answer:
O {(1, 3), (2, 10), (6, 24), (24, 6
A formula used for calculating velocity is v=1/2at^2 what is a expressed in terms of v and t
Answer:
[tex]v = \frac{1}{2} a {t}^{2} \\ a = \frac{2v}{ {t}^{2} } [/tex]
'a' can be expressed in terms of 'v' and 't' as -
[tex]$a=\frac{2v}{t^{2} }[/tex]
We have the following expression -
[tex]$v = \frac{1}{2} at^{2}[/tex]
We have to express → a in terms of v and t.
What is the value of x in -Sin([tex]2n\pi x[/tex]) = 0.785?On solving, we get -
Sin([tex]2n\pi x[/tex]) = 0.785
Sin([tex]2n\pi x[/tex]) = Sin ([tex]\frac{\pi }{4}[/tex])
2n[tex]\pi[/tex]x = [tex]\frac{\pi }{4}[/tex]
x = [tex]$\frac{1}{8n}[/tex]
According to the question, we have -
[tex]$v = \frac{1}{2} at^{2}[/tex]
[tex]$a=\frac{2v}{t^{2} }[/tex]
Hence, 'a' can be expressed in terms of 'v' and 't' as -
[tex]$a=\frac{2v}{t^{2} }[/tex]
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A scrapyard had 200 tons of recycled steel. They sold 15 tons per day for several days. If there are 80 tons left at the scrapyard, how many days have passed?
Please explain fully.
Answer:
8 days
Step-by-step explanation:
200-80= 120
120 ÷ 15 = 8 days
Answer:
SAME AS WHAT HE SAYS
Step-by-step explanation:
How much will it cost for him to buy 3 dozen using the rate $12.00 for 20 cookies?
Find the value of each of the variables.
A X = 12, y = 15, z = 20
B. X = 9,7 = 15,2 - 20
C. X = 9,y = 18,2 = 20
D. X = 12, y = 18,2 = 20
Answer:B
Step-by-step explanation:
B
Which of the following numbers can be exposed as repeated decimals? 5/7 4/5 7/9 5/8
A. 7/9 and 5/8
B. 5/7 and 4/5
C. 5/7 and 7/9
D.4/5 and 5/8
Answer:
C.
Step-by-step explanation:
5/7=.714285714 and so on
7/9=.777777778 and so on
What is the Prime factorization of 321411?
Answer:
The determined equation for number 321411 factorisation is 3 * 107137.
1
Mr. Johnson wants to fill up his car's gas tank. The car has a 25 gallon gas tank and there are 4 gallons of gas already in the tank. Gas costs $3.04 for each gallon. Mr. Johnson has $50 to spend on gas. Will he have enough money. Show your work and justify your answer.
Based on the cost of filling of the car, we can infer that Mr. Johnson does not have enough to spend on gas.
The car can take 25 gallons of gas and already has 4 liters inside it. The quantity of gas Mr. Johnson has to buy is:
= 25 - 4
= 21 gallons
The price of a gallon is $3.04. The price of 21 gallons would be:
= Price of gas x Number of gallons
= 3.04 x 21
= $63.84
In conclusion, Mr. Johnson does not have enough to spend on gas because he has only $50 yet the gas will cost $63.84.
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f(x) = -x^2+ 6x -10
write each function in vertex form and give the vertex
Answer:
Vertex form: f(x) = – (x – 3)² – 1
vertex: (3, -1)
Step-by-step explanation:
Given the quadratic function, f(x) = -x²+ 6x -10:
where a = -1, b = 6, and c = -10
The vertex of a parabola is the point at which the parabola intersects the axis of symmetry. The axis of symmtery occurs at x = h. Therefore, the x-coordinate of the vertex is the same as h.
To find the vertex, (h, k), you need to solve for h by using the formula: [tex]h = \frac{-b}{2a}[/tex]
Plug in the values into the formula:
[tex]h = \frac{-b}{2a}[/tex]
[tex]h = \frac{-6}{2(-1)} = 3[/tex]
Therefore, h = 3.
Next, to find the k, plug in the value of h into the original equation:
f(x) = -x²+ 6x -10
f(x) = -(3)²+ 6(3) -10
f(x) = -1
Therefore, the value of h = -1.
The vertex = (3, -1).
Now that you have the value for the vertex, you can plug these values into the vertex form:
f(x) = a(x - h)² + k
a = determines whether the graph opens up or down, and makes the parent function wider or narrower.
If a is positive, the graph opens up.If a is negative, the graph opens down.h = determines how far left or right the parent function is translated.
k = determines how far up or down the parent function is translated.
Plug in the vertex, (3, -1) into the vertex form:
f(x) = – (x – 3)² – 1
This parabola is downward-facing, with its vertex, (3, -1) as its maximum point on the graph.
30 POINTS AND BRAINLEST FOR ANSWER HELP!!!!!
Answer:
a
Step-by-step explanation:
A dresser with the mirror attached is 6.28 feet tall. The difference between their heights is 1.28 feet. What are the heights of the dresser and the mirror by themselves? Let the height of the dresser and the height of the mirror = y. =x
Answer:
Step-by-step explanation:
y = dresser height
x = mirror height
x+y=6.28
x-y = 1.28
x = 1.28+y
x+y=6.28
(1.28+y)+y=6.28
2y = 5
y = 2.5
Dresser = 2.5 ft
Dresser + Mirror = 2.5 + 1.28 = 6.28 ft
Mirror = 1.28 ft
Find the slope of the line
(18, 7) (8, 10)