find the length of x rounded to nearest hundredth please!!

Find The Length Of X Rounded To Nearest Hundredth Please!!

Answers

Answer 1

Answer:

4.00 pls give brainliest

Step-by-step explanation:

Answer 2

Hello turkshcutie11!

[tex] \huge \boxed{\mathfrak{Question} \downarrow}[/tex]

Find the value of x.

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

It's given that the triangle in the figure is a right triangle (a triangle with one angle as 90°). So, we can use the pythagoras property to solve this question.

__________________

Given sides :-

5 units (base)3 units (altitude)x units (hypotenuse)

__________________

Using pythagoras property...

Hypotenuse ² = Base² + Altitude ²

x² = 5² + 3²

x² = 25 + 9

x² = 34

x = √34

x = 5.83 units (1st option).

__________________

Hope it'll help you!

ℓu¢αzz ッ


Related Questions

Aashi buys
2 packets of bread rolls costing £1.40 for each packet
1 bottle of ketchup costing £1.80
3 packets of sausages
Aashi pays with a £10 note.
She gets 45p change.
Work out the price in pounds (£) of one pack of sausages.

(you will get brainliest) !! :D

Answers

Bread rolls = BR
Ketchup = K
Sausages = S

2BR +1K + 3S = £10 - 45p
2BR + 1K + 3S = £9.55

2BR = 1.40 x 2 = £2.80
1K = £1.80

£2.80 + £1.80 + 3S = £9.55
3S = £9.55 - £2.80 - £1.80
3S = £4.95
£4.95 / 3 = BR
S = £1.65

The answer is £1.65 for one pack of sausages

Price of one unit Sausage =  1.65

Sum ( Price x Quantity) = Total Expenditure  

Price of Bread x Quantity of Bread + Price of Ketchup x Quantity of Ketchup + Price of Sausage x Quantity of Sausage

Total Expenditure Value = 10 - 0.45  = 9.55

Let price of sausage = P

Therefore, 2 (1.40) + 1 (1.80) + 3 P = 9.55

2.80 + 1.80 + 3 Ps = 9.55

4.6 + 3 P = 9.55

3P = 9.55 - 4.60 =  4.95

P = 4.95 / 3 = 1.65

To learn more, refer https://brainly.com/question/16910784?referrer=searchResults

help with 14 please!!! please also explain!!

Answers

Answer:

f = ab/(a + b)

Step-by-step explanation:

#14

Given:

1/f = 1/a + 1/b

Solving for f:

1/f = b/ab + a/ab1/f = (a + b)/ab         cross - multiplyf(a + b) = ab             divide by (a + b)f = ab/(a + b)

Please help I’m timed thank you!!!

Answers

Answer:

BAP=12

ABP=32.5

BCP=45.5

please ans very easy question​

Answers

Answer:

what is the question please tell me on comment

Camille is 7 years older than Donny, and Donny is 4 years younger than Tommy.
Write an expression for the total ages of the three people, in simplest form.

Answers

11

Step-by-step explanation:

first you add seven plus four and then you get your answer that is eleven

How to find the Smallest value?
3/8
3/4
1/2
7/8
5/6

Answers

Answer:

Make all fractions have the same common denominator, and you will find that 3/8 is the smallest value.

Step-by-step explanation:

help #2 #4 #6 #8 #10 #12

Answers

FhehsjsudjwbsbzjsuuejZjdjekrndksusjsjenenf

Can someone help me please

Answers

Answer:

The financial aid covers $ 1,875

Student needs to pay out-of-pocket $635

Step-by-step explanation:

(2,500) * (3/4) = 7500/4 = 1,875

2,500 - 1,875 = 635

__% of 4 is 7

Please answer its due today

Answers

Answer:

175%

hope that helps. :)

I think is 3 I don’t know if is right

A ping pong ball has a 75% rebound ratio. When you drop it from a height of k feet, it bounces and bounces endlessly. If the height of the bounce follows geometric progression, find the general term that represent the situation in term of k. [2 marks] Hence, if the ball dropped from a height of 235ft, determine i. the highest height achieved by the ball after six bounces ii. the total distance travelled by the ball when it strikes the ground for 12th time [2 marks] [3 marks b) The number of cell double after each process of cell division every 2 hours. If there are 120 bacteria initially, how many bacteria will be there after one and half day? [4 marks]​

Answers

The movement of the ping pong ball follows a exponential progression.

The expression for the k-th bounce is: [tex]\mathbf{T_k = 235 \times (0.75)^k}[/tex]The height after the 6th bounce is 41.82 ftThe total distance after the 12th bounce is 1584.84ft.There will be 31457280 bacteria after a day and a half.

1. Ping pong ball

The given parameters are:

[tex]\mathbf{a = 235}[/tex] --- the initial height

[tex]\mathbf{r = 75\%}[/tex] --- the common ratio

(a) The expression after bouncing k times

To do this, we make use of

[tex]\mathbf{T_n = a \times r^n}[/tex]

So, we have:

[tex]\mathbf{T_n = 235 \times (0.75)^n}[/tex]

In this case; k = n.

So, the equation becomes

[tex]\mathbf{T_k = 235 \times (0.75)^k}[/tex]

Hence, the expression for the k-th bounce is: [tex]\mathbf{T_k = 235 \times (0.75)^k}[/tex]

(b) The height after bouncing 6 times

This means that k = 6.

So, we have:

[tex]\mathbf{T_k = 235 \times (0.75)^k}[/tex]

[tex]\mathbf{T_6 = 235 \times (0.75)^6}[/tex]

[tex]\mathbf{T_6 = 41.82}[/tex]

Hence, the height after the 6th bounce is 41.82 ft

(c) The total distance after the 12th bounce

First, we calculate the total height after the 12th bounce using:

[tex]\mathbf{S_k = \frac{a(1 - r^k)}{1 - r}}[/tex]

So, we have:

[tex]\mathbf{S_k = \frac{235 \times (1 - 0.75^{12})}{1 - 0.75}}[/tex]

[tex]\mathbf{S_k = \frac{235 \times (0.968)}{0.25}}[/tex]

[tex]\mathbf{S_k = 909.92}[/tex]

So, the total distance is:

[tex]\mathbf{Distance = 2 \times S_k - a}[/tex]

[tex]\mathbf{Distance = 2 \times 909.92 - 235}[/tex]

[tex]\mathbf{Distance = 1584.84}[/tex]

Hence, the total distance after the 12th bounce is 1584.84ft.

(2) Cell division

The given parameters are:

[tex]\mathbf{r = 2/2hr}[/tex] --- rate

[tex]\mathbf{a = 120}[/tex] --- initial number of cells

[tex]\mathbf{t = 18}[/tex] --- number of 2 hours is a day and a half

So, the number of bacteria is:

[tex]\mathbf{T_t = ar^t}[/tex]

This gives

[tex]\mathbf{T_t = 120 \times 2^{18}}[/tex]

[tex]\mathbf{T_t = 31457280}[/tex]

Hence, there will be 31457280 bacteria after a day and a half.

Read more about exponential functions at:

https://brainly.com/question/11487261

(Pre calc) I only need to do part A i would love to have some help I will make it 120 Points

Answers

Answer:

The domain should be X

Step-by-step explanation:

I'm a bit unsure but I think it's correct

What is the largest multiple of 9 whose negation is greater than -100?

Answers

Answer:

99

Step-by-step explanation:

Its negation is greater than -100. Hope this helps!

~Just a joyful teen

[tex]SilentNature[/tex]

Answer:

99

Step-by-step explanation:

See the question



Help


I’ll give a brainliest



1 , 2 , 3 , or 4 ?

Answers

Answer:

the answer is 3 I think if not than 2

pls help meeeee
pls....​

Answers

Answer:

1→10

Step-by-step explanation:

12

27

45

105/4

49/2

2/15

2/9

22/45

7/12

1/3

U just need to multiply both the numerators and both the denominators
And then simplify the final answer
Eg: 3/10 * 4/9 = 12/90 = 2/15

Which problem could the bar diagram represent

Answers

ANSWER: is there a picture for the question?

Step-by-step explanation:

Match the following items.


Determine the functions if θ is a first-quadrant angle, and sin = .


1. cosθ √(15)/5

2. tanθ √(10)/2

3. cscθ √(15)/3

4. secθ √6/3

5. cotθ √6/2

Answers

The functions are illustrations of trigonometry ratios

[tex]\mathbf{(a)\ cos\theta = \frac{\sqrt{15}}{5}}[/tex]

The sine of an angle is calculated as follows

[tex]\mathbf{sin\theta = \sqrt{1 - cos^2\theta}}[/tex]

So, we have:

[tex]\mathbf{sin\theta = \sqrt{1 - (\sqrt{15}/5)}}[/tex]

[tex]\mathbf{sin\theta = \sqrt{1 - (15/25)}}[/tex]

Take LCM

[tex]\mathbf{sin\theta = \sqrt{\frac{10}{25}}}[/tex]

[tex]\mathbf{sin\theta = \frac{\sqrt{10}}{5}}[/tex]

[tex]\mathbf{(b)\ tan\theta = \frac{\sqrt{10}}{2}}[/tex]

The tangent of an angle is:

[tex]\mathbf{\ tan\theta = \frac{Opposite}{Adjacent}}[/tex]

Using Pythagoras theorem, we have:

[tex]\mathbf{Hypotenuse^2 = Opposite^2 + Adjacent^2}[/tex]

So, we have:

[tex]\mathbf{Hypotenuse^2 = (\sqrt{10})^2 + 2^2}[/tex]

[tex]\mathbf{Hypotenuse^2 = 10 + 4}[/tex]

[tex]\mathbf{Hypotenuse^2 = 14}[/tex]

Take square roots

[tex]\mathbf{Hypotenuse = \sqrt{14}}[/tex]

So, the sine of the angle is:

[tex]\mathbf{\ sin\theta = \frac{Opposite}{Hypotenuse}}[/tex]

[tex]\mathbf{\ sin\theta = \frac{\sqrt{10}}{\sqrt{14}}}[/tex]

Rationalize

[tex]\mathbf{\ sin\theta = \frac{\sqrt{140}}{14}}[/tex]

[tex]\mathbf{(c)\ csc\theta = \frac{\sqrt{15}}{3}}[/tex]

The sine of the angles is:

[tex]\mathbf{sin \theta = \frac{1}{csc\theta}}[/tex]

So, we have:

[tex]\mathbf{sin \theta = \frac{1}{\sqrt{15}/3}}[/tex]

[tex]\mathbf{sin \theta = \frac{3}{\sqrt{15}}}[/tex]

Rationalize

[tex]\mathbf{sin \theta = \frac{3\sqrt{15}}{15}}[/tex]

[tex]\mathbf{sin \theta = \frac{\sqrt{15}}{5}}[/tex]

[tex]\mathbf{(d)\ sec\theta =\frac{\sqrt 6}{3}}}[/tex]

The sine of an angle is calculated as follows

[tex]\mathbf{sin\theta = \sqrt{1 - (1/sec\theta)^2}}[/tex]

So, we have:

[tex]\mathbf{sin\theta = \sqrt{1 - (3/\sqrt 6)^2}}[/tex]

[tex]\mathbf{sin\theta = \sqrt{(1 - 9/6)}}[/tex]

[tex]\mathbf{sin\theta = \sqrt{( - 3/6)}}[/tex]

The sine of the angle does not have a real value

[tex]\mathbf{(e)\ cot\theta = \frac{\sqrt 6}{2}}[/tex]

Start by calculating the tangent of the angle

[tex]\mathbf{tan\theta = \frac{1}{cot\theta}}[/tex]

So, we have:

[tex]\mathbf{tan\theta = \frac{1}{\sqrt 6/2}}[/tex]

[tex]\mathbf{tan\theta = \frac{2}{\sqrt 6}}[/tex]

Rationalize

[tex]\mathbf{tan\theta = \frac{2\sqrt 6}{6}}[/tex]

[tex]\mathbf{tan\theta = \frac{\sqrt 6}{3}}[/tex]

The tangent of an angle is:

[tex]\mathbf{\ tan\theta = \frac{Opposite}{Adjacent}}[/tex]

Using Pythagoras theorem, we have:

[tex]\mathbf{Hypotenuse^2 = Opposite^2 + Adjacent^2}[/tex]

So, we have:

[tex]\mathbf{Hypotenuse^2 = (\sqrt{6})^2 + 3^2}[/tex]

[tex]\mathbf{Hypotenuse^2 = 6 + 9}[/tex]

[tex]\mathbf{Hypotenuse^2 = 15}[/tex]

Take square roots

[tex]\mathbf{Hypotenuse = \sqrt{15}}[/tex]

So, the sine of the angle is:

[tex]\mathbf{\ sin\theta = \frac{Opposite}{Hypotenuse}}[/tex]

[tex]\mathbf{\ sin\theta = \frac{\sqrt{6}}{\sqrt{15}}}[/tex]

Rationalize

[tex]\mathbf{\ sin\theta = \frac{\sqrt{90}}{15}}[/tex]

Rewrite as:

[tex]\mathbf{\ sin\theta = \frac{3\sqrt{10}}{15}}[/tex]

[tex]\mathbf{\ sin\theta = \frac{\sqrt{10}}{5}}[/tex]

Read more about trigonometry ratios at:

https://brainly.com/question/24888715

what is the approximate length of segment PR?
25
11
125
18

Answers

Answer:

18

correct me if I'm wrong❌

Show how to use a power of 10 to write 42.66 / 2.97 as an equivalent expression with a whole number divisor

PLEASE HELP DUE TONIGHT!!
WILL MARK BRAINLIEST!!

Answers

Expressing the given equation as a power of 10 with the divisor expressed as an whole number can be written as [tex] \frac{42.66 \times 10^{2}}{297}[/tex]

Given the expression :

42.66/2.97

Expressing the numbers as a power of 10 :

Dividend = 42.66 Divisor = 2.97

To convert the divisor to a whole number :

Multiply both by 100

Dividend = 42.66 × 100Divisor = 2.97 × 100 = 297

Expressing dividend as a power of 10 :

Dividend = 42.66 × 100 = 42.66 × 10²

Hence, the equivalent equation would be : [tex] \frac{42.66 \times 10^{2}}{297}[/tex]

Learn more : https://brainly.com/question/18796573

Pls help can’t figure it out

Answers

X = 30
Y = 20
Let me know if you want me to show my work (:

2. Mack buys a gourmet pizza for $50. The shop increases its purchase price by 50%? What is the new price of the pizza?

Answers

Answer:

$75

Step-by-step explanation:

50% is half of the total, meaning that we can take half of $50, then add it to 50. Half of 50 is 25, so 50 + 25 = 75 dollars.

Write the equation in function form:
8x + 4y = 20

Answers

The answer is f(x) = 5 - 2x

Function form means just replace y with f(x).

So given 8x + 4y = 20:

Subtract 8x
4y = 20 - 8x

Divide both sides by 4
y = 5 - 2x

evaluate f(m-5) and simplify if f(x)=5x-9

Answers

Answer:

f(m-5) = 5m-34

Step-by-step explanation:

f(x)=5x-9

Replace x with m-5

f(m-5) = 5(m-5) -9

Distribute

         = 5m-25 -9

         = 5m-34

Answer:

answer is 5m - 34

Step-by-step explanation:

!!!!!!!!!!!!!!!!!!!!!!!!

Solve pls branliest!

Answers

Answer:

1 23 then 70 .2 corrected

A) is the last choice answer 2+8
B) is the second choice 2+(-8)

I’m doing my math homework and I don’t understand it all. I did most of it in class but I don’t get it still so here’s the question

Question:
-4/3(3q -10)

Answers

Answer:

-4q+ 40/3

Step-by-step explanation:

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Answers

Answer:

should be 40

1.6[3(5(2))-5]

1.6[30-5]

1.6[25]

40

Find the volume of the composite solid.

Answers

Answer:

volume

________

7 ft 8 ft 7.5 ft 7 ft

X-6y=6 find an ordered pair

Answers

Answer:

(6,0) or (0,-1)

Step-by-step explanation:

X-6y=6

X=6+6y

X/6=1+y

X/6-1=y

y=X/6-1

We'll use substitution to solve the ordered pair. Let's say Y = 0. We'll insert it back into our equation.

0=X/6-1

1=X/6

6=X

(6,0)

We can also start with X being = 0.

y=0/6 -1

y=-1

(0,-1)

I've attached what that would look like as a graph.

PLEASE HELP ME ITS ALGEBRA THANK YOUUUU

Answers

900 divided by 20 = 45
unit rate = 45
so $45 per person
85 guests x 45 = 3825

I hope this helps!

if y varies inversely as x, when y=20 and x=2 find the equation for y. then, find y when x=4

Answers

Answer:

the equation for y=20=1/2

Step-by-step explanation:

y=1/4

y=0.25

An academy requires there to be 3 teachers for every 72 students and 5 tutors for every 60 students. How many students does the academy have per teacher? Per tutor? How many tutors does the academy need if it has 132 students?

Answers

For every 24 students there is one teacher. For every 12 students is one tutor. If the Academy had 132 students then you will need 11 tutors.
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