Answers
Answer: the answer is 6
Step-by-step explanation:
Answer:
D. 6
Step-by-step explanation:
GCF means greatest common factor, so if you test out all of the answers, the factors you come up with is 2 and 6. Since 6 is larger, that is your answer.
Related Questions
HELP HELP HELP HELP HELP HELP HELP HELP HELP HELP HELP ASAP ASAP ASAP ASAP ASAP ASAP ASAP ASAP ASAP ASAP ASAP ASAP ASAP ASAP ASAP ASAP HELP
Answers
Answer:
is this in slope intercept form for what kind
Answer:
i just joined and i get points for an answer, im sorry i cant answer te question
NEED WORKOUT WITH ANSWER
Answers
1450➗800
HELP ME AS SOON AS POSSIBLE PLEASE HELP ME
Answers
Plzzzz help like just plzzzzz In Alana's math class, there are 12 boys and 13 girls. What is the ratio of boys to girls?
Answers
Which input value produces the same output value for
the two functions on the graph?
NO
O x=-3
O x= -2
O x= -1
O x=3
1-3 -2 -1
1 2 3 4 5 x
4
Answers
Answer:
x= 3 ; the answer choice D.
Step-by-step explanation:
EDGE 2020, just took the test.
pls help!!! I will make you brainiest!!!!! What is the rate of change?
Answers
Answer:
the rate iof change is 286
Step-by-step explanation:
Answer:
Rate of Change is 65
Step-by-step explanation:
260/4 = 65
585/9 = 65
845/13 = 65
1105/17 = 65
1625/25 = 65
3. Fill in the blank to make this equation true.
- (-20) = -62
Answers
Answer:
-82
Step-by-step explanation:
(-62) - (-20) = -82
Suppose number of hours employees work in a week at a company are normally distributed with an unknown population mean and a population standard deviation of 2 hours. A random sample of 65 employees weekly hours is taken. These gave a sample mean time of 39 hours. Find the error bound (EBM) of the confidence interval with a 95% confidence level. A 2 by 5 z-table.
Answers
Answer:
0.49
Step-by-step explanation:
We can use the formula to find the error bound:
EBM=(zα/2)(σ/√n)
We know that σ=2 and n=65. We are also given that the confidence level (CL) is 95%, or 0.95. So, we can calculate alpha (α).
α=1−CL
=1−0.95
=0.05
Since α=0.05, we know that α2=0.05/2=0.025. The value of z0.025 is 1.960.
Now we can substitute the values into the formula to find the error bound.
EBM=(zα/2)(σ/√n)
=(1.960)(2/√65)
≈(1.960)(0.248)
≈0.49
So, the error bound (EBM) is 0.49.
Simplify
6x2 + 8x + 11 + 4x + 9x2
Answers
Answer:
24x+29
Step-by-step explanation:
Answer:
15x^2+12x+11
Step-by-step explanation:
Hope this helps!
Water is pumped from a tank at constant rate, and no more water enters the tank. If the tank contains 19140 L at 4:47 PM and 8097 L at 5:05 PM the same day, how many liters will the tank contain at 5:11 PM that day?
Answers
Answer:
The liters that the tank will contain at 5:11 PM that day are:
4416 Liters.Step-by-step explanation:
Firstly, you must identify the outlet flow of the water pumped from the tank, for this, you must subtract the last volume given from the first volume:
19,140 L - 8,097 L = 11,043 LAnd the minutes that passed from the first volume until the last volume given (18 minutes from 4:47 PM to 5:05 PM), so, you must divide that two values to obtain the outlet flow:
Outlet flow = [tex]\frac{Volume}{Time}[/tex] Outlet flow = [tex]\frac{11,043 L}{18 min}[/tex] Outlet flow = 613.5 [tex]\frac{L}{min}[/tex]Now, you must see the next hour given (5:11 PM), if you see, from 5:05 PM to 5:11 PM has passed 6 minutes, taking into account this, you replace the equation of outlet flow to clear the volume:
Outlet flow = [tex]\frac{Volume}{Time}[/tex] Volume = Outlet flow * timeAnd replace the values to obtain the new volume pumped:
Volume = 613.5 [tex]\frac{L}{min}[/tex] * 6 minVolume = 3681 L.At last, you must subtract these liters from the last volume identified in the tank:
New Volume in the tank = 8097 L - 3681 LNew Volume in the tank = 4416 LThe volume in the tank at 5:11 PM is 4416 Liters.
The tank will contain 4416 L of water at 5:11 PM .
Rate of discharge of water:Given that, the tank contains 19140 L at 4:47 PM and 8097 L at 5:05 PM
It means that, in 18 minutes the amount of water discharge is,
[tex]=19140-8097=11043L[/tex]
The rate of flow is,
[tex]=\frac{11043}{18}=613.5L/min[/tex]
From 5:05 PM to 5:11 PM , six minutes are passes.
Water discharge in that six minute is ,
[tex]=613.5*6=3681L[/tex]
The tank will contain at 5:11 PM is,
=[tex]8097-3681=4416L[/tex]
Learn more about rate of flow here:
https://brainly.com/question/21630019
Marty ran 2.62 miles four days in a row. How far did he run all four days this week?
Answers
Answer:
10.48
Step-by-step explanation:
Answer:
10.48 mi
Step-by-step explanation:
2.62 times 4= 10.48
Can anybody help me as soon as possible. Model with mathematics. The weight of a pen manufactured at the PEN factory is 8g. The actual weight can vary as much as 2g. Write and solve an inequality to represent all acceptable weights for a pen at this factory.
*25 POINTS*
Answers
Answer:
[6, 10]Step-by-step explanation:
Let the weight of a pen be x
Then its weight can be between
8 - 2 = 6 g and 8 + 2 = 10 gThis can be shown as
8 - 2 ≤ x ≤ 8 + 26 ≤ x ≤ 10x = [6, 10]What value of x makes the equation true? 5x+3x–32+12=180
Answers
Answer:
Step-by-step explanation:
Step 1: Simplify both sides of the equation
(5x+3x)+(-32+12)=180
8x-20=180
Step 2: Add 20 to both sides.
8x-20+20= 180+20
8x= 200
Step 3: Divide both sides by 8
8x/8= 200/8
x= 25
 pi times 1.5 to the second power times eight
Answers
Answer:
56.54866776
Step-by-step explanation:
:) Hope this helps
56.5486677646
or just 56.54 works :)
An oil storage tank is a cylinder with a height of 50 feet and a diameter of 20 feet. What is the volume of the tank? Use 3.14 for Pi.
Answers
Answer:
15707.96ft³
Step-by-step explanation:
Who can possibly beat me?
A. Kakarot
B. Gohan
C. Broly
D. Frieza
Answers
Answer:
C
Step-by-step explanation:
Explanation
Please help me with this question
Answers
Step-by-step explanation:
1. 120+21 =141
2. 21-3=18
3. 7x-21
4. 4x+20
5. 45+100=145
6. 40+5c
7. 20+22r+26s
Im not too sure about the other question
Help. (Math)
1. Using the geometry tools below, construct a bisection of the line segment EF.
2. Using the geometry tools below, construct a copy of the angle ABC below.
Answers
Answer:
...................................
Help if anyone know this
Answers
Answer:
The first one is 0,4 and the other is 5,2
Please help me. ____\\\\\\\\\[]_____
Answers
The management of a supermarket wants to adopt a new promotional policy of giving a free gift to every
customer who spends more than a certain amount per visit at this supermarket. The expectation of the
management is that after this promotional policy is advertised, the expenditures for all customers at this
supermarket will be normally distributed with a mean of $95 and a standard deviation of $16. If the
management wants to give free gifts to at most 13.57% of the customers, what should the amount be
above which a customer would receive a free gift?
Answers
Answer:
X ≥ 112,6 $
Step-by-step explanation:
Normal Distribution N ( 95 , 16 )
μ₀ = 95
σ = 16
We need to get z (score) for area 0,1357; then from z - Table we get
z (score) = 1,1
Now z (score ) = ( X - μ₀ )/σ
1,1 = ( X - 95 ) / 16
17,60 + 95 = X
X = 112,6 $
That means that in order to get a gift customes has to spend at least 112,6 $
A survey was conducted to determine whether hours of sleep per night are independent of age. A sample of individuals was asked to indicate the number of hours of sleep per night with categorical options: fewer than 6 hours, 6 to 6.9 hours, 7 to 7.9 hours, and 8 hours or more. Later in the survey, the individuals were asked to indicate their age with categorical options: age 39 or younger and age 40 or older. Sample data follow.
Hours Of Sleep 39 or Younger 40 or Older
Fewer than 6 38 36
6 to 6.9 60 57
7 to 7.9 77 75
8 or More 65 92
Required:
a. Conduct a test of independence to determine whether hours of sleep are independent of age. Using α= 0.05 level of significance
b. Compute the value of the 2 test statistic.
c. The p-value is:________
d. What is your conclusion?
Answers
Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
________Hours of sleep______
Age ___<6__6-6.9___ 7-7.9 __≥8 ___total
≤ 39___38___60_____77____65____240
≥ 40___36___57_____75____92____260
A.) test of independence for row and column variables :
Null: row and column variables are independent
Alternative : row and column variables are not independent
Expected frequencies :
[(row total) * (column total] / sample size
E1: ((38+60+77+65)*(38+36))/500 = 35.52
E2: ((38+60+77+65)*(60+57))/500 = 56.16
E3: ((38+60+77+65)*(77+75))/500 = 72.96
E4: ((38+60+77+65)*(65+92))/500 = 75.36
E5: ((36+57+75+92)*(38+36))/500 = 38.48
E6: ((36+57+75+92)*(60+57))/500 = 60.84
E7: ((36+57+75+92)*(77+75))/500 = 79.04
E8: ((36+57+75+92)*(65+92))/500 = 81.64
Then performing the Chisquare independence test X²
X² = Σ[(f1-e1)²/e1 + (f2-e2)²/e2... (fn - en)²/en]
F1 to f8 = 38,60,77,65,36,57,75,92
X² = ((38-49.92)^2)/35.52 + ((60-56.16)^2)/56.16 + ((77-72.96)^2)/72.96 + ((65-75.36)^2)/75.36 + ((36-38.48)^2)/38.48 + ((57-60.84)^2)/60.84 + ((75-79.04)^2)/79.04 + ((92-81.64)^2)/81.64
= 4.0070162
X² = 4.00
α = 0.05
Reject Null if p < α
df = (row - 1)*( column - 1)
df = (2 - 1)*(4-1) = 1*3 = 3
To obtain the p value, we can use an online calculator to compute the P-value from the X² square score at α = 0.05 and 3 degree of freedom
p = 0.261
Since ; p > α ; 0.261 > 0.05 ; The result is not significant at α 0.05 ; Hence we fail to reject the Null.
an airplane was at 34500 feet in the air
Answers
Answer:
And....? Is there anything else to it?
Solve for X then find the measure of DEF. Write your answers in decimal form.
Answers
Answer:
Since EF bisects ∠DEF, we know that EF splits ∠DEF in 2 halves from the word 'bisects', which can be written as 'bi- sects' , where bi means 2 and sects means sections
Hence, ∠DEG = ∠GEF --------------(1)
We are given the measure of these angles:
∠DEG = 3x - 4
∠GEF = x + 13
Now, replacing the values in (1):
3x - 4 = x + 13
2x = 17
x = 17/2
Now, finding the measure of ∠DEF:
∠DEF = ∠DEG + ∠GEF
∠DEF = 3x - 4 + x + 13
∠DEF = (51 / 2) - 4 + (17/2) + 13 (x = 17/2)
∠DEF = 34 - 4 + 13
∠DEF = 43°
3/12 + -1 2/3 as a improper fraction
Answers
Answer:-17/12
Step-by-step explanation:
convert fractions, subtract
1. How did Muhammad’s death in 632 affect the Muslim state he had established?
Why were the Muslims able to conquer the powerful Byzantine and Persian Empires in just 20 years??
Why did many Jews, Christians, and other non-Muslims convert to Islam in the growing Muslim empire?
Why was Abu Bakr important to the survival of the Muslim state??
How did the conquering caliphs treat their non-Muslim subjects??
Answers
Answer:
tbh not sure sorry hope somebody anwsers
Step-by-step explanation:
Which ordered pairs are solutions to the equation 6x + 7y = 6?
Answers
Answer:
(2,−6/7), (3,−12/7), and (6,−30/7)
Step-by-step explanation:
3 friends split $55.00 evenly
Answers
Answer:
18.
Step-by-step explanation:
Answer:
We divide right? if yes then great!
18 remainder 3 so 18.3
list the angles in order from smallest to largest.
Answers
Answer:
What are the angles
Step-by-step explanation:
List all the angles
A product can be made in sizes huge, average and tiny which yield a net unit profit of $14, $10, and$5, respectively. Three centers manufacture these products. The centers respectively have a capacity ofturning out 550, 750, and 275 units of the product per day, no matter what sizes are involved. The manufacturing process necessitates cooling water and each unit of huge, average, and tiny sizesproduced require 22, 16, and 9 gallons of water, respectively. Center 1 has 11,000 gallons of coolingwater available per day, Center 2, 7000, and Center 3, 4000 gallons. The daily demand is of 710, 900,and 350 units of the huge, average, and tiny siz. By company policy, the fraction (scheduled production)(center's capacity) must be the same at all the centers. The company wishes to maximize its profits.
Required:
Model this problem as a linear program
Answers
Answer:
The model is:
z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃ to maximize
Subject to:
First center X₁₁ + X₂₁ + X₃₁ ≤ 550
Second center X₁₂ + X₂₂ + X₃₂ ≤ 750
Third center X₁₃ + X₂₃ + X₃₃ ≤ 275
22* X₁₁ + 16* X₂₁ + 9*X₃₁ ≤ 11000
22* X₁₂ + 16* X₂₂ + 9*X₃₂ ≤ 2700
22*X₁₃ + 16* X₂₃ + 9*X₃₃ ≤ 3400
X₁₁ + X₁₂ + X₁₃ ≤ 710
X₂₁ + X₂₂ + X₂₃ ≤ 900
X₃₁ + X₃₂ + X₃₃ ≤ 350
2700*(X₁₁ + X ₂₁ + X₃₁) - 11000*(X₁₂ + X₂₂ + X₃₂) = 0
3400*(X₁₁ + X ₂₁ + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0
Xij >= 0
Step-by-step explanation:
Let´s call Xij product size i produced in center j
According to this, we get the following set of variable
X₁₁ product size huge produced in center 1
X₁₂ product size huge produced in center 2
X₁₃ product size huge produced in center 3
X₂₁ product size average produced in center 1
X₂₂ product size average produced in center 2
X₂₃ product size average produced in center 3
X₃₁ product size-tiny produced in center 1
X₃₂ product size-tiny produced in center 2
X₃₃ product size-tiny produced in center 3
Then Objective function is
z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃
Constrains
Center capacity
1.- First center X₁₁ + X₂₁ + X₃₁ ≤ 550
2.- Second center X₁₂ + X₂₂ + X₃₂ ≤ 750
3.- Third center X₁₃ + X₂₃ + X₃₃ ≤ 275
Water available
1.- 22* X₁₁ + 16* X₂₁ + 9*X₃₁ ≤ 11000
2.- 22* X₁₂ + 16* X₂₂ + 9*X₃₂ ≤ 2700
3.- 22*X₁₃ + 16* X₂₃ + 9*X₃₃ ≤ 3400
Demand constrain
Product huge
X₁₁ + X₁₂ + X₁₃ ≤ 710
Product average
X₂₁ + X₂₂ + X₂₃ ≤ 900
Product tiny
X₃₁ + X₃₂ + X₃₃ ≤ 350
Fraction SP/CC must be the same
First and second centers fraction SP/CC
(X₁₁ + X ₂₁ + X₃₁)/ 11000 = (X₁₂ + X₂₂ + X₃₂)/ 2700
2700*(X₁₁ + X ₂₁ + X₃₁) - 11000*(X₁₂ + X₂₂ + X₃₂) = 0
First and third centers fraction SP/CC
(X₁₁ + X ₂₁ + X₃₁)/ 11000 = ( X₁₃ + X₂₃ + X₃₃)/ 3400
3400*(X₁₁ + X ₂₁ + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0
The model is:
z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃
Subject to:
First center X₁₁ + X₂₁ + X₃₁ ≤ 550
Second center X₁₂ + X₂₂ + X₃₂ ≤ 750
Third center X₁₃ + X₂₃ + X₃₃ ≤ 275
22* X₁₁ + 16* X₂₁ + 9*X₃₁ ≤ 11000
22* X₁₂ + 16* X₂₂ + 9*X₃₂ ≤ 2700
22*X₁₃ + 16* X₂₃ + 9*X₃₃ ≤ 3400
X₁₁ + X₁₂ + X₁₃ ≤ 710
X₂₁ + X₂₂ + X₂₃ ≤ 900
X₃₁ + X₃₂ + X₃₃ ≤ 350
2700*(X₁₁ + X ₂₁ + X₃₁) - 11000*(X₁₂ + X₂₂ + X₃₂) = 0
3400*(X₁₁ + X ₂₁ + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0
Xij >= 0